In Part A, you found the amount of product (1.80 mol P2O5 ) formed from the given amount of phosphorus and excess oxygen. In Part B, you found the amount of product (1.40 mol P2O5 ) formed from the given amount of oxygen and excess phosphorus. Now, determine how many moles of P2O5 are produced from the given amounts of phosphorus and oxygen.

I believe that the balanced chemical equation is:

3H2(g)+N2(g)→2NH3(g), ΔH = -21.9 kcal

We can see that 21.9 kcal of heat is released for every 2 moles of NH3.

The molar mass of NH3 is 17 g/mol, hence:

moles NH3 = 33.68 g / (17 g/mol)

moles NH3 = 1.98 mol

The total energy released is:

total heat = (-21.9 kcal / 2 mol) * 1.98 mol

total heat = -21.70 kcal

Answer:

The answer is the Third sublevel. Hope this helps

Explanation:

Tungsten contains 74  electrons in total. The electronic configuration of tungsten can be written as [Xe] 4F¹⁴ 5d⁴ 6s².

What is tungsten?

Tungsten is 74th element in periodic table. It is a d -block element and is classified as a transition metal. Tungsten have potential application in electronic devices. The filaments of electric bulb are made by tungsten.The latin name of tungsten is wolfram. That's why it has the symbol W.

Noble gases have completely filled orbitals and their electronic configuration is fully filled in all orbitals. Therefore, using the noble gas notation we can represent the configuration of other elements.

Tungsten have 74 electrons. Xenon a noble gas have 54 electrons . Thus all the orbitals are completely filled. W can be written using Xe. Thus remaining 20 electrons have to specified in corresponding orbitals. Hence, the configuration of W is [Xe] 4F¹⁴ 5d⁴ 6s².

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Answer:

for identifying elements in a sample

for determining the distance and velocity of galaxies

for producing neon lights

for determining types of chemical bonds

for use in medical imaging devices

Explanation:

Hello,

Field spectroscopy, is a technique used to measure the reflectance properties of  vegetation, soils, rocks, and water bodies in the natural environment, generally under  solar illumination. Some disciplines are interested in the measurement of light reflected  off objects in the natural environment. Natural targets are usually illuminated by the  whole hemisphere of the sky, and thus receive direct solar flux and scattered sky light, thus, it can be applied for determine elements in a sample as each one reflects the light differently, for determining the distance and velocity of galaxies  as one could measure the light velocity, for producing neon lights , for determining types of chemical bonds  as they have measurable energies related with the reflected light and for use in medical imaging devices to determine patrons in the obtained results.

Best regards.

Considering the structure of the atom, The subatomic particle that has a negative charge is the electron (option B)

All atoms are made up of subatomic particles: protons and neutrons, which are part of their nucleus, and electrons, which revolve around them.

Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged (electrons).

In other words, every atom consists of:

Finally, an electron has a negative charge.

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The subatomic particle that has a negative charge is the electron.

The subatomic particle that has a negative charge is the electron.

Electrons are tiny particles found outside the nucleus of an atom. They have a negative charge and are responsible for the flow of electricity. Protons, on the other hand, have a positive charge, and neutrons have no charge.

In summary, the answer to your question is the electron.

A chemical property and a physical property are related to chemical and physical changes of matter.

Answer: A physical property is an aspect of the matter that can be observed or measured without changing it. Examples of physical properties include color, molecular weight, and volume.

A chemical property may only be observed by changing the chemical identity of a substance.

This property measures the potential for undergoing a chemical change. Examples of chemical properties include reactivity, flammability and oxidation states.

Answer:

A chemical property and a physical property are related to chemical and physical changes of matter.

Answer: A physical property is an aspect of the matter that can be observed or measured without changing it. Examples of physical properties include color, molecular weight, and volume.

A chemical property may only be observed by changing the chemical identity of a substance.

This property measures the potential for undergoing a chemical change. Examples of chemical properties include reactivity, flammability and oxidation states.

Explanation:

The complete balanced chemical reaction for this would be:

NaOH  +  C3H6O3  -->  NaC3H5O3  +  H2O

So we see that exactly 1 mole of NaOH reacts with 1 mole of lactic acid.

Calculate moles of NaOH.

moles NaOH = 0.07 moles/L * 0.0268 L

moles NaOH = 1.876 x 10^-3 mol

So,

moles C3H6O3 = 1.876 x 10^-3 mol

The molar mass of lactic acid is 90.08 g/mol so the mass is:

mass C3H6O3 = (1.876 x 10^-3 mol) * 90.08 g/mol

mass C3H6O3 = 0.169 g

When a diver enters the water, they experience both water pressure and air pressure. As the diver descends, the pressure exerted by the water increases because water is denser than air. The pressure is measured in atmospheres, with one atmosphere being equal to 760 millimeters of mercury or the normal atmospheric pressure at sea level.

At a depth of 34 feet in fresh water, the diver experiences 2 atmospheres of pressure. This includes one atmosphere from the air pressure above the water's surface and an additional atmosphere from the 34 feet of water. For every additional 34 feet the diver descends, they will encounter an extra atmosphere of pressure.

To calculate the pressure at 102 feet, we can divide the depth by 34 (since each 34 feet corresponds to one additional atmosphere of pressure).

102 feet / 34 feet = 3 atmospheres of pressure

Therefore, at a depth of 102 feet, a diver would experience 3 atmospheres of pressure.

Now, you might wonder why this pressure doesn't squash the diver. The reason is similar to why a person on land is not squashed by one atmosphere of pressure. Our bodies are made up of fluids and tissues that can withstand and equalize the pressure. When a person is at sea level, the air pressure around them is balanced by the air pressure within their body. Similarly, when a diver descends into the water, the increased water pressure is balanced by the internal pressure within their body. This balance prevents the diver from being squashed by the external pressure. However, it is important for divers to follow safety guidelines and gradually ascend to allow their bodies to adjust to changes in pressure and avoid decompression sickness.  

    AI(NO3)3 + 3H20 -----> AI(OH)3 + 3H + 3N03-

The change in heat is simply equal to:

change in heat ΔH = final enthalpy – initial enthalpy

ΔH = [280.25 g * 4.18J/gC * (17.5°C)] – [280 g * 4.18J/gC * 13.5°C]

ΔH = 4,699.89 J = 4.7 kJ

Hence heat released is about 4.7 kJ

Answer:

Significant figures in number '0.070' is 2.

Explanation:

Significant figures : The figures are the numerals which express the value of magnitude of a quantity to a specific degree of accuracy also called significant digits.

0.070 = [tex] 7.0\times 10^{-2][/tex]

Significant figures in number '0.070' is 2.

Answer:

The element is Carbon. Atomic number = 6

Explanation:

The electron configuration distributes electrons into levels or sub-levels, Each of these levels has a determined capacity of electrons that can contain and you always follow an specific order given to you by the Linus Diagram.

Sub Level s--> 2 electrones

Sub level p --> 6 electrons

Sub level d --> 10 electrons

Sub level f --> 14 electrons

Sub level g --> 18 electrons.

Considering this you must follow the arrows of the Linus Diagram and distribute all the electrons acording to the atomic number of the element.

The complete balanced chemical reactions are:

HNO3 =>          CaCO3 + 2HNO3 → Ca(NO3)2 + H2O + CO2(g)

H2SO4 =>         CaCO3 + H2SO4 → CaSO4 + H2O + CO2(g)

So we see that 1 mole of CaCO3 is needed for 2 moles of HNO3 and similarly to 1 mole of H2SO4.
The number of moles can be calculated as the product of volume and molarity, so:

moles H2SO4 = 1.7×10^−5 M * (15.5 x 10^9 L) = 263,500 mol H2SO4

moles HNO3 = 8.9×10^−6 M * (15.5 x 10^9 L) = 137,950 mol HNO3

So the total moles of CaCO3 required is:

moles CaCO3 = 263,500 mol * 1 + 137,950 mol * (1/2)

moles CaCO3 = 332,475 mol

The molar mass of CaCO3 is 100.086 g/mol, so the mass is:

mass CaCO3 = 332,475 mol * 100.086 g/mol

mass CaCO3 = 33,276,092.85 g = 33.3 x 10^3 kg

Mass of limestone required for complete neutralization is 3,336.64 [tex]\rm \times\;10^4[/tex] grams.

Limestone is [tex]\rm CaCO_3[/tex]. The neutralization reaction for limestone will be:

[tex]\rm CaCO_3\;+\;2\;HNO_3\;\rightarrow\;Ca(NO_3)_2\;+\;H_2O\;+\;CO_2[/tex]

[tex]\rm CaCO_3\;+\;H_2SO_4\;\rightarrow\;CaSO_4\;+\;H_2O\;+\;CO_2[/tex]

The balanced equation states that for neutralization of 1 mole of limestone, 2 moles [tex]\rm HNO_3[/tex] and 1 mole of [tex]\rm H_2SO_4[/tex] is required.

The moles of [tex]\rm HNO_3[/tex] and [tex]\rm H_2SO_4[/tex] available are:

Moles of [tex]\rm HNO_3[/tex] = molarity [tex]\times[/tex] volume (L)

Moles of [tex]\rm HNO_3[/tex] = 8.9 [tex]\rm \times\;10^-^6[/tex] [tex]\times[/tex] 15.5 [tex]\rm \times\;10^9[/tex] L

Moles of [tex]\rm HNO_3[/tex] = 13.975 [tex]\rm \times\;10^4[/tex] moles

Moles of [tex]\rm H_2SO_4[/tex] = 1.7 [tex]\rm \times\;10^-^5[/tex]  [tex]\times[/tex] 15.5 [tex]\rm \times\;10^9[/tex] L

Moles of [tex]\rm H_2SO_4[/tex] = 26.35  [tex]\rm \times\;10^4[/tex] moles

Moles of [tex]\rm CaCO_3[/tex] required = 1 mole of [tex]\rm H_2SO_4[/tex] + [tex]\rm \dfrac{1}{2}[/tex] moles of [tex]\rm HNO_3[/tex]

Moles of [tex]\rm CaCO_3[/tex] required = 26.35  [tex]\rm \times\;10^4[/tex] moles [tex]\rm H_2SO_4[/tex] + [tex]\rm \dfrac{1}{2}[/tex] (13.975 [tex]\rm \times\;10^4[/tex] moles) [tex]\rm HNO_3[/tex]

Moles of [tex]\rm CaCO_3[/tex] required = 26.35  [tex]\rm \times\;10^4[/tex] + 6.9875  [tex]\rm \times\;10^4[/tex]

Moles of [tex]\rm CaCO_3[/tex] required = 33.3375  [tex]\rm \times\;10^4[/tex] moles

Mass of limestone = moles of limestone [tex]\times[/tex] molecular weight of limestone

Mass of limestone =  33.3375  [tex]\rm \times\;10^4[/tex] moles [tex]\times[/tex] 100.0869 grams

Mass of limestone = 3,336.64 [tex]\rm \times\;10^4[/tex] grams.

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 So the total moles of CaCO3 required is:

moles CaCO3 = 263,500 mol * 1 + 137,950 mol * (1/2)

moles CaCO3 = 332,475 mol

The molar mass of CaCO3 is 100.086 g/mol, so the mass is:

mass CaCO3 = 332,475 mol * 100.086 g/mol

mass CaCO3 = 33,276,092.85 g = 33.3 x 10^3 kg

To find the number of moles of nitrogen, N, in 88.0 g of nitrous oxide, N2O, we can use the molar mass of N2O. The molar mass of N2O is calculated by adding the atomic masses of nitrogen and oxygen. Using the equation number of moles = mass (g) / molar mass (g/mol), we can calculate that there are 2.0 moles of nitrogen, N, in 88.0 g of N2O.

To find the number of moles of nitrogen, N, in 88.0 g of nitrous oxide, N2O, we need to use the molar mass of N2O. The molar mass of N2O is calculated by adding the atomic masses of nitrogen and oxygen: 2(14.01 g) + 16.00 g = 44.02 g/mol. Now, we can use the molar mass to calculate the number of moles:

Number of moles = Mass (g) / Molar mass (g/mol)

Number of moles = 88.0 g / 44.02 g/mol = 2.0 mol of nitrogen, N.

Final answer:

Zinc (Zn) does not react with magnesium chloride (MgCl₂) because Zn is less reactive than Mg and cannot displace Mg from its compound. The answer to the student's query is - no reaction (N.R).

Explanation:

When considering the reactivity of zinc (Zn) relative to magnesium (Mg), we refer to the activity series of metals. According to the activity series, Mg is more reactive than Zn, which means that Mg is more likely to lose electrons compared to Zn. When mixing Zn metal with a solution of magnesium chloride (MgCl₂), we are essentially testing whether Zn can replace Mg in MgCl₂. However, since Zn is less reactive than Mg, it cannot displace Mg from its compound. The reaction we're investigating would be:

Zn (s) + MgCl₂ (0.5 M) → N.R (no reaction)

No reaction will occur in this case, so we denote this by writing 'N.R' to signify that a reaction does not take place.

The type of hybridization a central atom exhibits is determined by the number of regions of electron density around it. For example, molecules with a lone pair on the central atom or those with two single bonds and a double bond to the central atom display sp² hybridization. Central atoms surrounded by two regions of valence electron density depict sp hybridization.

The type of hybridization a molecule exhibits depends on the number of regions of electron density that surround its central atom. Molecules with a lone pair on the central atom or those with two single bonds and a double bond to the central atom, show sp² hybridization. Examples of such molecules include CINO, formaldehyde (CH₂O), and ethene (H₂CCH₂). Furthermore, central atoms surrounded by just two regions of valence electron density present sp hybridization, found in molecules like HgCl₂, Zn(CH3)2, HCCH, and CO₂. The geometry of these regions of electron density mirrors the shapes of molecules predicted by the VSEPR theory, further indicating how hybrid orbital theory provides an explanation for these molecular shapes.

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The most stable Lewis structure of acrolein is attached in image below.

Lewis dot structures are also called as electron dot structures and can be drawn if the molecular formula of a compound is known. It provides information regarding the nature of bond and the position of atoms .

They are also capable of exhibiting the lone pair if any present in a molecule or compound.Lewis defined a base to be an electron pair donor and an acid to be an electron pair acceptor.

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