In the first 120 miles over 240 mile journey a truck driver maintained an average speed of 50 mph what was his average featuring the next 120 miles if the average speed of the entire trip with 60 mph

Answers

Answer 1
The correct answer is 70 MPH because when 50 and 70 are added together and divided by 2, you get 60.
Answer 2
The average speed over the entire trip was 60 mph, which must equal the distance traveled (240 miles) times the elapsed time.  Dividing  60 mph into 240 miles gives us the elapsed time:  (240 miles) / (60 mph) = 4 hours total.

Next:  determine the length of time required to drive the first 120 miles at 50 mph.  It is (120 miles) / (50 mph), or 2.4 hours.

Next, find the length of time required to drive the second 120 miles.  It is 4 hours less 2.4 hours, or 1.6 hours.

Lastly, find the average speed over which the second 120 miles were covered in 1.6 hours:

average speed (2nd 120 miles) = (120 miles) / (1.6 hours) = 75 mph.

Related Questions

If 2(x -1) = 14, then x =

Answers

remember you can do anything to an equestion as long as you do it to both sides


2(x-1)=14
divide both sides by 2
x-1=7
add 1 to both sides
x=8

If the given equation is represented as "2(x - 1) = 14", then the value of the variable "x" is 8.

To solve the equation 2(x - 1) = 14 for x, we use algebraic techniques to separate x.

First, we distribute the 2 to both terms inside the brackets;

2x - 2 = 14,

Next, we separate the variable x by adding 2 to both sides of the equation:

2x - 2 + 2 = 14 + 2,

Simplifying the equation:

2x = 16,

At last , to solve for x, we divide both sides of the equation by 2:

We get,

(2x) / 2 = 16 / 2,

x = 8,

Therefore, the solution to the equation 2(x - 1) = 14 is x = 8.

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What is the inverse of y equals x squared + 2

Answers

to get the inverse relation of any expression, simply start off by doing a switcharoo on the variables, and then solve or "y".

[tex]\bf \boxed{y}=\boxed{x^2}+2\qquad inverse\implies \boxed{x}=\boxed{y^2}+2 \\\\\\ x-2=y^2\implies \sqrt{x-2}=y\impliedby f^{-1}(x)[/tex]

Which ratio is equivalent to 7 : 8?
A) 28 : 40
B) 21 : 24
C) 49 : 64

Answers

B!!!!! 21/3=7 and 24/3=8 there for 21:24=7:8

A local hamburger shop sold a combined total of 693 hamburgers and cheeseburgers on Wednesday. There were 57 fewer fewer cheeseburgers sold than hamburgers. How many hamburgers were sold on Wednesday

Answers

693-57 = 636

636/2 = 318

cheeseburgers sold = 318

 hamburgers sold = 318 + 57 = 375


To determine the number of hamburgers sold on a specific day, an equation is set up and solved to find the value of hamburgers. In this scenario, 375 hamburgers were sold on Wednesday.

The question is asking how many hamburgers were sold on a specific Wednesday given the total combined sales of hamburgers and cheeseburgers and that fewer cheeseburgers were sold than hamburgers. To find the number of hamburgers sold, we can set up a system of equations. Let's define H as the number of hamburgers and C as the number of cheeseburgers. From the information provided, we have the following equations:

H + C = 693 (Total sales of both types of burgers)C = H - 57 (There were 57 fewer cheeseburgers sold than hamburgers)

Substituting the second equation into the first gives us:

H + (H - 57) = 693

2H - 57 = 693

Adding 57 to both sides, we get:

2H = 693 + 57

2H = 750

Now divide both sides by 2:

H = 375

Therefore, 375 hamburgers were sold on Wednesday.

I need to simplify this equation and don't know how, please help!
[tex] \frac{ \frac{y}{x} - \frac{x}{y}}{ \frac{1}{y}-\frac{1}{x}} [/tex]

Answers

[tex]\bf \textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\\\ -------------------------------\\\\[/tex]

[tex]\bf \cfrac{\frac{y}{x}-\frac{x}{y}}{\frac{1}{y}-\frac{1}{x}}\implies \cfrac{\textit{LCD of \underline{xy}}}{\textit{LCD of \underline{xy} also}}\implies \cfrac{\frac{y^2-x^2}{xy}}{\frac{x-y}{xy}}\implies \cfrac{y^2-x^2}{\stackrel{ }{xy}}\cdot \cfrac{\stackrel{ }{xy}}{x-y} \\\\\\ \cfrac{y^2-x^2}{x-y}\implies \cfrac{(y-x)(y+x)}{x-y}\implies \cfrac{\stackrel{ }{(y-x)}(y+x)}{-\stackrel{ }{(y-x)}}\implies \cfrac{y+x}{-1} \\\\\\ -(y+x)\implies -y-x[/tex]

he IQ scores of 500 college football players are randomly selected. Which graph would be most appropriate for these data: histogram, bar chart, pie chart, multiple bar graph, or slack plot?

Answers

A histogram allows you to plug in data such as the occurrences of score frequencies in a continuous data set that has been equally divided into classes such as bins. Bar charts allows you to use numerous types of variables including nominal an ordinal data sets. Pie chart is a circle chart that allows you to see the numerical proportions of each data set. The chart that would be most appropriate in the IQ scores of 500 college football players that are randomly selected is the histogram. This is because the data is to be classified according to their IQ scores and it requires a distribution of sample from 500 college football players.


What are the next two numbers in the pattern 3.1, 3.11, 3.11, 33.11

Answers

33.11, 311 im pretty sure this is right, if it is not can you please correct me?

Rachel pays $15.20 for a pack of 8 towels. Find the unit price in dollars per towel .

Answers

15.20 / 8 = 1.90 per towel <==
Final answer:

The unit price of a towel is calculated by dividing the total cost of the pack ($15.20) by the number of towels in the pack (8), which equals $1.90 per towel.

Explanation:

In order to find the unit price in dollars per towel, we simply divide the total cost of the pack by the number of towels in the pack. So for Rachel who paid $15.20 for a pack of 8 towels, to find the cost per towel, you'd divide $15.20 by 8.

To calculate:

Divide the total cost by the number of items: $15.20 / 8

This equals $1.90. So, the cost per towel, or unit price, is $1.90.

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A number is K units to the left of 0 on the number line. Describe the location of its opposite

Answers



------------------------(- K)-------------0-------------(+K)-----------------

K unit to the left of 0, means K is negative.
The opposite of (-K) is (+K), both are symmetric vs. the origin "0", then its location will be +K

In a study conducted for the state department of education, 30% of the teachers who left teaching did so because they were laid off. assume that we randomly select 16 teachers who have recently left their profession. find the probability that at least 7 of them were laid off.

Answers

This problem can be solved by using the binomial distribution.

p = 30% = 0.3 is the probability that a teacher was laid off.
q = 1 -p = 0.7 is the probability that a teacher was not laid off.
n = 16 is the sample size.
r = 7 is the expected number of teachers who were laid off

The probability that 7 out of 16 teachers were laid off is
₁₆C₇ p⁷q⁽¹⁶⁻⁷⁾ = 11440*(0.3⁷)*(0.7⁹) = 0.101 =10.1%

Answer:
The probability is 0.101 or 10.1%

at the end of the month, a medical office has 86 envelopes remaining. if the office uses 7 envelopes per day, on which day will the office likely run out of envelopes?

Answers

86/7 = 12.28 days worth

 so they will run out on the 13th day of the next month

in a right triangle, what is the product of sin b and tan c and product of sin c and tan b

Answers

check the picture below.

Two examples where the law of detachment does not apply.

Answers

If the following statements are true, use the Law of Detachment to derive a new true statement.

1) If you are a penguin, then you live in the Southern Hemisphere.

2) You are a penguin.

Remember if p then q

The law of detachment, or modus ponens, doesn't apply when the antecedent is false or when premises lack conditional statements, making deductions invalid in these cases.

The law of detachment, also known as modus ponens, is a fundamental principle in classical logic that allows us to make valid deductions. However, there are situations where it does not apply:

Invalid Antecedent: In modus ponens, we start with a conditional statement (if-then statement) as our premise and then affirm the consequent. If the antecedent (the "if" part) of the conditional statement is false, the law of detachment cannot be applied. For example, if we have the statement "If it is raining, then the ground is wet" and we know that the ground is not wet, we cannot conclude anything about whether it's raining or not, as the antecedent is false.

Lack of a Conditional Statement: Modus ponens requires a conditional statement as its premise. If we are given unrelated or non-conditional premises, we cannot apply this rule. For instance, if we know that "John is a doctor" and "The sun is shining," we cannot use modus ponens to deduce anything because there is no conditional relationship between the statements.

In summary, while modus ponens is a valid and powerful inference rule in classical logic, it cannot be applied when the antecedent is false or when the premises do not involve conditional statements.

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Complete question below:

Could you provide two examples where the law of detachment does not apply in logic?

Choose the correct description of the graph of the inequality x − 3greater than or equal to 5

Answers

not sure what the correct description is but the answer is:
x ≥ 8

Answer:

Move all terms not containing x to the right side of the inequality. x≥8

Closed circle on 8, shading to the right.

At what points does the helix r(t) = sin t, cos t, t intersect the sphere x2 + y2 + z2 = 65? (round your answers to three decimal places. if an answer does not exist, enter dne.)

Answers

Final answer:

To determine the intersection points of the helix and the sphere, we substitute the helix's parametric expressions into the sphere's equation, simplify, and solve for t, resulting in two points of intersection upon further substitution back into the helix's equation.

Explanation:

The question asks at what points the helix r(t) = (sin t, cos t, t) intersects the sphere x2 + y2 + z2 = 65. To find the intersections, we substitute the parametric equations of the helix into the equation of the sphere. Thus, we get (sin2t) + (cos2t) + t2 = 65. Using the Pythagorean identity sin2t + cos2t = 1, the equation simplifies to 1 + t2 = 65, which further simplifies to t2 = 64. Solving for t, we find t = ±8. Thus, the helix intersects the sphere at the points generated by these t values, which can be found by substituting t back into the helix equations, resulting in (sin(8), cos(8), 8) and (sin(-8), cos(-8), -8), with approximate numerical values after calculations.

What is 24/126 simplified

Answers

Hello there!

24/126.

First, let's try to divide both numbers by 2, as the numbers in the ones place are even.

24 / 2 = 12
126 / 2 = 63

12/63

Divide both numbers by 3.

12 / 3 = 4
63 / 3 = 21

4/21. This is your simplified fraction.

I hope this helps!
24= 2*2*2*3
126= 2*3*3*7

The GCF= 2*3 or 6

Divide the numerator and denominator by the GCF
24/6=4
126/6=21

Final answer: 4/21

Analyzing the graphs of a periodic functions (need help)

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\ % function transformations for trigonometric functions \begin{array}{rllll} % left side templates f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}} \\\\ f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\ f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}} \end{array} \\\\ -------------------\\\\[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks}\\ \left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\[/tex]

[tex]\bf \bullet \textit{function period or frequency}\\ \left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ \left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)[/tex]

now, with that template above in mind, let's see.

reflected over the x-axis, that means A is negative.

vertically shrunk by 0.25 or 1/4, that means A is negative 4, or -4.

shifted to the left, that means C/B  is positive

shifted by 65°, that means, we could use the default B = 1, and C = 65°, that way we end with C/B = 65/1 or just +65

and shifted downwards by 1 unit, that means D = -1.

[tex]\bf f(x)=-4sin(1x+65^o)-1\implies f(x)=-4sin(x+65^o)-1[/tex]

and looks more or less like the picture below.

If the measures of the angles of a triangle are in the ratio of 19:13:4, then the expressions 19x, 13x, and 4xrepresent the measures of these angles. Find these angle measures.

Answers

Well this isn't college math lol

You do 19x + 13x + 4x = 26x

180 divided by 26x =        x = 6.92307...

plug in x then  round to tenth

6.9 x 19 = 131.1 degrees

6.9 x 13 = 89.7 degrees

6.9 x 4 = 27.6 degrees
interior angles of a triangle add up to 180

19x + 13x + 4x = 180
36x = 180
x = 180/36
x = 5

19x = 19(5) = 95 <== heres one
13x = 13(5) = 65 <== and another
4x = 4(5) = 20 <==and another

19:13:4 = 95:65:20

20. Archetypes are a type of _______ that appear throughout history.
A. motif
B. prototype
C. foreshadowing
D. subgenre
Student Answer: A
Answer: Incorrect
Answer is B Prototype

Answers

An archetype appears repeatedly throughout history. Its' a  B. Prototype-an original idea that has come to be used over and over again. 

For Penn Foster the answer you find the answer to this qrestion In the section called Analysis of “ Paul’s Case” 4 th paragraph an Archetype appears repeatedly throughout history -It’s a prototype . So the qrestion people are asking is. Archetypes are a type of _______ that appear throughout history? A. foreshadowing B. prototype C. subgenre D. motif

Answer true and correct B. PROTOTYPE

I made a hundred on this test for pf

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What is the diameter of a circle with a circumference of 4pi?

Answers

C = πD     [C=circumference, D=diameter]

4π = πD     ⇒ D = 4π/π = 4 units
What is the diameter of a circle with a circumference of 4pi? = 2x radius = 8 Inches.

What is the area of parallelogram ABDC?

Answers

You can split it into two triangles and find the area of both triangles and later add them up.

A = bh/2

Triangle 1:
3*3 = 9
9/2 = 4.5

Triangle 2:
3*3 = 9
9/2 = 4.5

4.5 + 4.5 = 9

Answer: The area of the parallelogram is 9 cm^2

Hope this helps :)
Please give brainliest

Answer:

9cm

Step-by-step explanation:

Find the area of the equilateral triangle if a side is 14√3 ft. Round to the nearest whole number.

Answers

Answer:

Answer is C

Step-by-step explanation:

Area of an equilateral triangle can be found by the following formula,

A=[tex]\frac{\sqrt{3}} {4} a^{2}[/tex]

Where "a" is the length of one side of the triangle.

Now we can substitute the value given to the equation above and find the area of the given equilateral triangle.

A=[tex]\frac{\sqrt{3}} {4}(14\sqrt{3})^ {2}[/tex]

=[tex]\frac{\sqrt{3}} {4} 196*3[/tex]

=[tex]\frac{\sqrt{3}*196*3} {4}[/tex]

=[tex]254.611[/tex]

A=[tex]255[/tex] square feet.

Answer is C

What is the number of square units in the area of the triangle whose vertices are points (2,0), (6,0), (8,5)

Answers

check the picture below

you can pretty much just count how many units for the base, and height.

Answer: 10 square units.

Step-by-step explanation:

The area of triangle with vertices [tex](x_1,y_1),(x_2,y_2)\text{ and }(x_3,y_3)[/tex] is given by :-

[tex]A=\dfrac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)][/tex]

Given : The vertices of triangle : (2,0), (6,0), (8,5)

Then , the area of the triangle will be :_

[tex]A=\dfrac{1}{2}[(2)((0)-(5))+(6)((5)-(0))+(8)((0)-(0))\\\\\Rightarrow A=\dfrac{1}{2}[20]\\\\\Rightarrow A=10\text{ square units}[/tex]

Hence, the number of square units in the area of the triangle whose vertices are points (2,0), (6,0), (8,5) = 10

help me? idk the answer :P

Answers

[tex]\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\ a^{-{ n}} \implies \cfrac{1}{a^{ n}} \qquad \qquad \cfrac{1}{a^{ n}}\implies a^{-{ n}} \qquad \qquad a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\ -------------------------------\\\\ \left( 2^8\cdot 3^{-5}\cdot 6^0 \right)^{-2}\left( \cfrac{3^{-2}}{2^3} \right)^4\cdot 2^{28}\impliedby \textit{let's do the first group} \\\\ -------------------------------\\\\ [/tex]

[tex]\bf \left( 2^8\cdot \cfrac{1}{3^5}\cdot 1 \right)^{-2}\implies \left( \cfrac{2^8}{3^5} \right)^{-2}\implies \left( \cfrac{3^5}{2^8} \right)^{2}\implies \cfrac{3^{2\cdot 5}}{2^{2\cdot 8}}\implies \boxed{\cfrac{3^{10}}{2^{16}}}\\\\ -------------------------------\\\\ \textit{now the second group}\qquad \left( \cfrac{3^{-2}}{2^3} \right)^4\implies \left( \cfrac{\frac{1}{3^2}}{2^3} \right)^4\implies \left( \cfrac{1}{2^3\cdot 3^2} \right)^4[/tex]

[tex]\bf \cfrac{1^4}{2^{4\cdot 3}\cdot 3^{4\cdot 2}}\implies \boxed{\cfrac{1}{2^{12}\cdot 3^8}}\\\\ -------------------------------\\\\ \textit{so we end up with\qquad }\cfrac{3^{10}}{2^{16}}\cdot \cfrac{1}{2^{12}\cdot 3^8}\cdot 2^{28}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{16}\cdot 2^{12}\cdot 3^8} \\\\\\ \cfrac{3^{10}\cdot 2^{28}}{2^{16+12}\cdot 3^8}\implies \cfrac{3^{10}\cdot 2^{28}}{2^{28}\cdot 3^8}\implies 3^{10}\cdot 2^{28}\cdot 2^{-28}\cdot 3^{-8}[/tex]

[tex]\bf 3^{10-8}\cdot 2^{28-28}\implies 3^2\cdot 1\implies 3^2\implies 9[/tex]

EASY 5 POINTS!!! You want to help build an awards podium for a track meet. If the podium has the dimensions shown, what is its volume?

Answers

Answer:

The volume is equal to [tex]18\ cm^{3}[/tex]

Step-by-step explanation:

we know that

The volume of each figure is equal to

[tex]V=LWH[/tex]

where

L is the length

W is the width

H is the height

Step 1

Find the volume of figure N 1

[tex]V1=1.5*2*3=9\ cm^{3}[/tex]

Step 2

Find the volume of figure N 2

[tex]V2=1.5*2*2=6\ cm^{3}[/tex]

Step 3

Find the volume of figure N 3

[tex]V3=1.5*2*1=3\ cm^{3}[/tex]

Step 4

Find the total volume

[tex]V=V1+V2+V3=9+6+3=18\ cm^{3}[/tex]

Answer:

[tex]\text{Volume of podium}=18\text{ ft}^3[/tex]

Step-by-step explanation:

We have been given a graph of podium for a track meet and we are asked to find the volume of our given podium.

To find the volume of podium we will find volume of each podium using volume of cuboid formula.

[tex]\text{Volume of cuboid}=l*b*h[/tex], where,

[tex]l=\text{ Length of cuboid}[/tex],

[tex]b=\text{ Breadth of cuboid}[/tex],

[tex]h=\text{ Height of cuboid}[/tex].

Upon substituting our given values in cuboid formula we will get,

[tex]\text{Volume of cuboid 1}=\text{3 ft*2 ft*1.5 ft}[/tex]    

[tex]\text{Volume of cuboid 1}=9\text{ ft}^3[/tex]    

[tex]\text{Volume of cuboid 2}=\text{2 ft*2 ft *1.5 ft}[/tex]

[tex]\text{Volume of cuboid 2}=6\text{ ft}^3[/tex]

[tex]\text{Volume of cuboid 3}=\text{1 ft*2 ft *1.5 ft}[/tex]

[tex]\text{Volume of cuboid 3}=6\text{ ft}^3[/tex]

Let us add volume of each cuboid to find the volume of our given podium.

[tex]\text{Volume of podium}=9\text{ ft}^3+6\text{ ft}^3+3\text{ ft}^3[/tex]

[tex]\text{Volume of podium}=18\text{ ft}^3[/tex]

Therefore, volume of our given podium is 18 cubic feet.

Sal bought three CDs for 1598 each a computer cable for 3995 and a case for his MP3 player for 2499 sales tax is 7% to the nearest cent what is the total cost of his purchases




Pleaseee helppppppp

Answers

15.98*3 + 39.95 + 24.99 = 112.88

7% taxes (always taxes!): 112.88 * 1.07= 120.7816

Rounded to cents: 120.78
3(15.98) + 39.95 + 24.99 = 112.88
112.88(1.07) = 120.78 <=

In Ellen's math class, there are 2 boys for every 3 girls . What is the the following ratio of boys to girls in the class ?
A . 17/21
B . 14/21
C . 7/14
D. 11/17

Answers

Based on the ratio of boys/girls We can infer that the only possibility for Ellen's math class would be answer B. 14/21

The Jurassic Zoo charges ​$14 for each adult admission and ​$9 for each child. The total bill for the 214 people from a school trip was ​$2081. How many adults and how many children went to the​ zoo?  

Answers

a=adult

c=child

a+c=214

c=214-a

9c+14a=2081

9(214-a)+14a=2081

1926-9a+14a=2081

5a=155

a=155/5=31

31 adults

183 children


check

31*14 = 434

183*9=1647

1647+434=2081

The perimeter of a triangle is 133 inches. If one side of the triangle is five more than the shortest side, and the longest side is 14 more than the shortest side, find the lengths of the three sides?

Answers

side 1 = x

side 2 = x+5

side 3 = x+14

perimeter = side 1 + side 2 + side 3

133 = x + (x+5) + (x +14)

133=3x + 19

114=3x

x=114/3 = 38

side 1 = 38

side 2 = x+5 = 38+5 = 43

side 3 = x+14 = 38+14 = 52


38+43+52 = 133

side lengths are 38, 43 & 52

Find the indicated probabilities using the geometric​ distribution, the Poisson​ distribution, or the binomial distribution. Then determine if the events are unusual. If​ convenient, use the appropriate probability table or technology to find the probabilities.

A newspaper finds that the mean number of typographical errors per page is
six
six. Find the probability that​ (a) exactly
four
four typographical errors are found on a​ page, (b) at most
four
four typographical errors are found on a​ page, and​ (c) more than
four
four typographical errors are found on a page.

Answers

The applicable distribution is Poisson, since it relates to the number of successes/occurrences within a specified interval.

The probability of a given number, x, of occurrences is given by
P(x)=m^x*e^(-m)/x!
where m is the mean number of occurrences.

In the case of mean, m=6, the probability reduces to
P(x)=6^x*e^(-6)/x!

(a) x=4
P(4)=6^4*e^(-6)/4!=0.13385

(b) x<=4
P(X<=4)=P(X=0)+P(X=1)+P(X=2)+P(X=3)+P(X=4)
=0.00248+0.01487+0.04462+0.08924+0.13385+0.28506
=0.28506

(c) x>4
P(X>4)=1-P(X<=4)
=1-0.28506
=0.71494
Other Questions
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