In the reaction of 1.23 g of salicylic acid, molar mass 138.12 g/mol, with 2.85 g of acetic anhydride, molar mass 102.10 g/mol, a student obtained 1.39 g of acetylsalicylic acid, molar mass 180.17 g/mol. What is the percent yield?


I found that salicylic acid was the limiting reactant so do I just find the mass from there?

Answer: Option (a) is the correct answer.

Explanation:

Atomic number means the sum of total number of protons acquired by an atom.

So, when atomic number of nitrogen is 7 then it means there are 7 protons present.

Whereas atomic mass means the sum of total number of protons and neutrons present in an atom.

Therefore, nitrogen-15 is an isotope of nitrogen that will always have 7 protons when it is neutral in nature. Hence, in nitrogen-15 the number of protons and neutrons are calculated as follows.

                   Atomic mass = no. of protons + no. of neutrons

                             15 = 7 + no. of neutrons

                    no. of neutrons = 15 - 7

                                               = 8

Thus, we can conclude that the atomic nucleus of nitrogen-15 contains 8 neutrons.

Atomic number is the number of protons in an element. Mass number is the total number of protons and neutrons in an element. Thus, to get the number of neutrons in an element, one can subtract the atomic number of an element from the mass number.

Since Nitrogen has an atomic number of 7, the number of neutrons in nitrogen with a mass number of 14 is 14 - 7 = 7 neutrons

The number of neutrons in nitrogen with a mass number of 15 is 15 -7 = 8 neutrons

Thus, the answer to the question is 8 neutrons.

Note: Nitrogen-14 means nitrogen with a mass number of 14 while nitrogen-15 means nitrogen with a mass number of 15

Answer: No, the oxidation state of hydrogen does not change in the given chemical reaction.

Explanation: Balancing the given chemical equation, we get:

[tex]2HBr+H_2SO_4\rightarrow SO_2+Br_2+2H_2O[/tex]

Reactant side:

In HBr, the oxidation state of bromine is -1, so to form a neutral compound, hydrogen should have an oxidation state of +1.

In [tex]H_2SO_4[/tex] , the oxidation state of sulfate is -2, so to form a neutral atom, two hydrogen atoms having +1 oxidation state should combine with it.

Product side:

In [tex]H_2O[/tex], the oxidation state of hydroxide ion is -1, so to form a neutral water molecule, hydrogen should have an oxidation state of +1.

From above, we can say that the oxidation states of hydrogen atom did not change for the following chemical reaction.

The substances listed as HBr, CH3COOH and H3PO4 are acids. Acids are substances that donate protons or H+ ions in solution while bases accept these ions. NaCl is a salt.

The substances listed as HBr (hydrobromic acid), CH3COOH (acetic acid), and H3PO4 (phosphoric acid) are all types of acid. These are known as acids because they donate protons, or hydrogen ions (H+) in solution, which is the defining property of an acid based on the Bronsted-Lowry definition of acids and bases. In contrast, substances like LiOH and Mg(OH)2 are bases because they accept H+ ions, and NaCl is a salt, which is typically the product of an acid-base neutralisation reaction.

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Simple distillation is most effective for separating two liquids when their boiling points differ by more than 100°C. For closer boiling points, fractional distillation is recommended.

Simple distillation is best used to separate two liquids that have boiling points that differ by more than 100°C. This method works well to purify mixtures by separating a liquid from non-volatile impurities or from components with significantly greater or lesser boiling points. When the difference in boiling points of the components is less than 100°C, simple distillation cannot achieve significant purification. In such cases, fractional distillation, which involves a fractionating column, is used to enhance purification.

For instance, the distillation of crude oil or the production of alcoholic spirits like brandy and whiskey are applications of distillation that exploit the differences in boiling points to separate mixtures into their components.

The metal fittings on boats where ropes can be fastened are called cleats. Cleats are typically made of metal or plastic and are used to secure ropes by wrapping them around the fitting. Cam cleats are a specific type that use cams to grip and release the rope easily.

The metal fittings on boats where ropes can be fastened are called cleats. Cleats come in various shapes and materials, including metal and plastic, and are designed to secure ropes by wrapping them around the fitting. A specific type of cleat often used in sailing is the cam cleat, which uses cams to grip the rope when pulled upward and allows easy release when pulled downward.

In addition to cleats, there are other fittings like bitts and bollards that also serve the purpose of securing ropes on boats. However, cleats are the most commonly used and recognized for this function.

Answer:

The correct answer is 7.

Explanation:

Given :  3-ethyl-2-pentene (Alkene)

The longest chain in the molecule is of 5 carbon atom. And on second carbon ethyl group is present.In ethyl group there re 2 carbon atoms. So, the total carbon atom in 3-ethyl-2-pentene are 7 carbon atoms.

[tex]CH_2=C(C_2H_5)-CH_2-CH_2-CH_3[/tex]

Answer:

5.12 moles of NaCl are required to prepare 0.80 L of 6.4 M NaCl.

Explanation:

Molarity (M) is a concentration measure that indicates the number of moles of solute that are dissolved in a given volume.

The Molarity is then determined by:

[tex]Molarity (M)=\frac{number of moles of solute}{volume}[/tex]

Molarity is expressed in units[tex]\frac{moles}{liter}[/tex].

6.4 M NaCl indicates that 1 liter of solution there are 6.4 moles of NaCl.

You can apply a rule of three as follows: if in 1 liter of solution there are 6.4 moles of NaCl, in 0.8 L how many moles are there?

[tex]moles=\frac{0.8 L*6.4 moles}{1 L}[/tex]

moles=5.12

5.12 moles of NaCl are required to prepare 0.80 L of 6.4 M NaCl.

[tex]\boxed{{\text{3213}}{\text{.15 s}}}[/tex] will be required to convert 1.50 mol of water completely into steam.

Further explanation:

Enthalpy of vaporization

It is the amount of energy that is required to convert a substance from its liquid state to a vapor or gaseous state. It is also known as the latent heat of vaporization or heat of evaporation. It is represented by [tex]\Delta {H_{{\text{vap}}}}[/tex].

The expression for the heat of vaporization is as follows:

[tex]{\text{q}} = {\text{n}}\Delta {H_{{\text{vap}}}}[/tex]                                                                …… (1)

Here,

q is the energy of the substance.

n is the number of moles of the substance.

[tex]\Delta {H_{{\text{vap}}}}[/tex] is the heat of vaporization.

Substitute 1.50 mol for n and 40.7 kJ/mol for [tex]\Delta {H_{{\text{vap}}}}[/tex] in equation (1).

 [tex]\begin{aligned}{\text{q}}&= \left( {1.50{\text{ mol}}} \right)\left( {\frac{{40.7{\text{ kJ}}}}{{1{\text{ mol}}}}} \right)\\&= 61.05{\text{ kJ}}\\\end{aligned}[/tex]

The amount of energy is to be converted into J. The conversion factor for this is,

 [tex]1{\text{ kJ}} = {\text{1}}{{\text{0}}^3}{\text{ J}}[/tex]

Therefore the amount of energy can be calculated as follows:

[tex]\begin{aligned}{\text{q}} &= \left( {61.05{\text{ kJ}}} \right)\left( {\frac{{{{10}^3}{\text{ J}}}}{{1{\text{ kJ}}}}} \right)\\&= {\text{61050 J}}\\\end{aligned}[/tex]

The time required for conversion of water into steam is calculated as follows:

[tex]\begin{aligned}{\text{Time required}}&= \left( {61050{\text{ J}}} \right)\left( {\frac{{1{\text{ s}}}}{{19{\text{ J}}}}} \right)\\&= 3213.15{\text{ s}}\\\end{aligned}[/tex]  

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Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Thermodynamics

Keywords: enthalpy of vaporization, q, n, 1.50 mol, water, steam, 3213.15 s, 61050 J, 61.05 kJ, 40.7 kJ/mol, liquid state, vapour state, substance, time, amount of energy.

To determine the specific heat capacity of an alloy, use the formula Q = mcΔT and rearrange for c. Substitute the given values and calculate the answer.

The specific heat capacity of an alloy can be calculated using the formula:

Q = mcΔT

Where Q is the heat energy, m is the mass of the alloy, c is the specific heat capacity, and ΔT is the change in temperature. Rearranging the formula to solve for c, we have:

c = Q / (mΔT)

Substituting the values given in the question, we get:

c = 59.3 kJ / (150.0 g × (398 K - 298 K))

After performing the calculations, the specific heat capacity of the alloy is obtained.

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The specific heat capacity of an alloy that requires 59.3 KJ to raise the temperature of 150.0 g alloy from 298 K to 398 K is 3.95 J/g·K.

To determine the specific heat capacity (c) of an alloy, we can use the formula:

q = mcΔT

where:

Given the information:

Plugging these values into the formula:

59,300 J = 150.0 g × c × 100 K

Solving for c:

c =  (59,300 J) / (150.0 g × 100 K) = 3.95 J/g·K

Therefore, the specific heat capacity of the alloy is 3.95 J/g·K.

Answer:

A saturated sraight-chain hydrocarbon with two carbons is ethane.

Explanation:

Saturated hydrocarbons are called as alkanes with general formula [tex]C_{n}H_{2n+2}[/tex] where n=1,2,3,4......

Now, as it contains two carbon atoms therefore name of this compound should contain a prefix "eth". Also a suffix "ane" will come due to the fact that it is a saturated hydrocarbon.

So, molecular formula of this compound is [tex]C_{2}H_{6}[/tex]

Structure of this straight chain compound has been attached below.

Final answer:

To release -1411 kJ of energy, 28.054 grams of [tex]C_2H_4[/tex] needs to burn since the heat of reaction is directly proportional to the amount of the substance.

Explanation:

The question asks for the amount of  [tex]C_2H_4[/tex] (ethylene) that needs to be burned given the heat of reaction for its combustion is -1411 kJ/mol. First, it's essential to understand that the heat of reaction indicates how much energy is released (in this case, -1411 kJ) when 1 mole of a substance undergoes a chemical reaction. To find out how many grams of  [tex]C_2H_4[/tex] must burn to release a specific amount of energy, one has to relate this energy value to the molar mass of  [tex]C_2H_4[/tex].

The molar mass of  [tex]C_2H_4[/tex] is 28.054 g/mol, which means 28.054 grams of  [tex]C_2H_4[/tex] constitute one mole. Given the energy released is directly proportional to the amount of substance, to release -1411 kJ, one mole or 28.054 grams of  [tex]C_2H_4[/tex] needs to burn. If a different amount of energy is desired, the amount of  [tex]C_2H_4[/tex] needed can be calculated proportionally based on the given heat of reaction.

Answer: [tex]813.1\times 10^{23}[/tex] atoms.

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to the molecular mass and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.

1 molecule of [tex]C_2H_6O[/tex] contains = 9 atoms

1 mole of [tex]C_2H_6O[/tex] contains = [tex]9 \times 6.023\times 10^{23}=54.21\times 10^{23}[/tex] atoms

Thus 15 moles [tex]C_2H_6O[/tex] contains =[tex]\frac{54.21\times 10^{23}}{1}\times 15=813.1\times 10^{23}[/tex] atoms.

Thus the answer is [tex]813.1\times 10^{23}[/tex] atoms.

B. HCl is the limiting reactant; 2.8 mol AlCl3 can be formed

The half-life of a radioisotope that decayed from 0.5 g to 0.125 g in 9.6 min is 4.8 minutes, calculated by recognizing that two half-lives have occurred within the given timeframe.

The question concerns the calculation of the half-life of a radioisotope based on the amount of material that remains after a certain period of time. The half-life is the time taken for half of the radioactive nuclei in a sample to decay. To determine the half-life, we can apply the formula for exponential decay:

N(t) = N(0) * (1/2)^(t/T)

Where:

N(t) is the remaining quantity of the substance after time t,

N(0) is the initial quantity of the substance,

t is the time that has passed,

T is the half-life of the substance.

In this case, we start with 0.5 g and end with 0.125 g after 9.6 minutes. Since two half-lives have passed to get from 0.5 g to 0.125 g (0.5 g -> 0.25 g -> 0.125 g), we can calculate the half-life as:

9.6 minutes / 2 = 4.8 minutes

Therefore, the half-life of the radioisotope is 4.8 minutes.

Answer:

require only one electron to complete their outer shell

have a high electronegativity

Explanation:

The equation represents a combustion reaction is -

A reaction involves a substance reacting with oxygen and releasing energy in form of light or heat, such a chemical reaction is called a combustion reaction.

2C₂H₆ + 7O₂ -----> 4CO₂ + 6H₂O

Thus, the equation represents a combustion reaction is -

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11.2 moles of co2 are produced when 5.60 mole of ethane are burned in an excess of oxygen.

In chemistry, a standard scientific unit for measuring large quantities of very small entities such as atoms, molecules, or other specified particles.

The chemical reaction is given by :

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

2 mole C₂H₆ - 4 mole CO₂

5.60 mole C₂H₆ - x

x=5.60*4/2=11.2 mole

Thus, 11.2 moles of co2 are produced when 5.60 mole of ethane are burned in an excess of oxygen.

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Answer: The correct formula for phosphorous pentachloride is [tex]PCl_5[/tex] because a subscript 5 indicates five chlorine (Cl) atoms.

Explanation: For the given molecule, phosphorous pentachloride, there are 2 atoms present which are phosphorous and chlorine atoms.

Number of phosphorous atoms = 1

Number of chlorine atoms = 5

So, the correct formula for phosphorous pentachloride will be [tex]PCl_5[/tex] because the subscript 5 represents the 5 chlorine atoms.

The correct formula for phosphorus pentachloride is PCl₅. Therefore, option B is correct.

In the compound, phosphorus has a valence of +5, meaning it can form up to five bonds. Each chlorine atom has a valence of -1, allowing it to form a single bond.

By combining one phosphorus atom with five chlorine atoms, each chlorine atom can share one electron with the phosphorus atom, resulting in the formation of five P-Cl bonds.

In the compound, "penta" indicates that there are five chloride (Cl) atoms bonded to the central phosphorus (P) atom. The subscript of 5 in PCl5 represents the number of Cl atoms bonded to each P atom.

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