In which of the following functions would it be appropiate to use only positve integers for the domain?Select all that apply.

Answers

Answer 1

Complete Question:

As you may have unintentionally forgotten to add the answer choices in your question, but I was able to find the complete the question and answering your question based on this as it may surely clear your concepts. Here is the complete question.

In which of the following functions would it be appropriate to use only positive integers for the domain? Select all that apply.

The function c(p) represents The cost for P people to attend the movies. The function m(t) represents the miles driven over T hours. The function t(m) represents the average high temperature for a given number of months. The function p(w) represents the prophet of a farmer who sells whole watermelons. The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.

Answer Explanation:

Domain is termed as all the input values on a certain interval that define the function.

Here are the appropriate function scenarios where it is appropriate to use only positive integers.

The function c(p) represents The cost for P people to attend the movies.

As the function c(p) contains people. And People are not counted as negative, although they can be zero. So, only positive integers should be appropriate to use in this scenario.

The function m(t) represents the miles driven over T hours

As the function m(t) contains miles. And miles are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function t(m) represents the average high temperature for a given number of months.

As the function t(m) contains months. And months are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function p(w) represents the prophet of a farmer who sells whole watermelons.

As the function p(w) contains the number of watermelons. And watermelons are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.

As the function h(n) contains the number of engines. And engines are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.

Keywords: domain, function, positive integer

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Related Questions

Get a lot of points and brainliest if answer this question correctly and FAST!!!

Answer BOTH
I didn't answer first one, I accidentally clicked it!

Answers

Part 1: The right answer is Option B.

Part 2: The right answer is Option B.

Step-by-step explanation:

Given,

1 hour = 120 calories

Part 1: How many calories are burned per minute when walking on a treadmill?

1 hour = 120 calories

1 hour = 60 minutes

Therefore,

60 minutes = 120 calories

1 minute = [tex]\frac{120}{60}=2\ calories[/tex]

2 calories are burned per minute.

The right answer is Option B.

Part 2: Assuming you walk at a constant rate and burn 120 calories per hour, how many minutes will it take to burn 75 calories.

From part 1;

1 minute = 2 calories

1 calorie = [tex]\frac{1}{2}\ minute = 0.5\ minutes[/tex]

75 calories = 75*0.5 = 37.5 minutes

The right answer is Option B.

Keywords: multiplication, division

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Find the product of x2 + 2x - 4 and 3x .

Answers

Answer:x4+2x3+7x2+6x+12

Step-by-step explanation:

HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Answers

Answer:

see explanation

Step-by-step explanation:

The diagrams show triangular figures

The first figure has 1 dot

The second has 1 + 2 = 3 dots

The third has 3 + 3 = 6 dots

The fourth has 6 + 4 = 10 dots

Note the pattern is + 2 , + 3, + 4

Thus the fifth pattern is 10 + 5 = 15 dots

PLS HELP

What is the perimeter of the rhombus below?


A. [tex]8\sqrt{5}[/tex]

B. [tex]5\sqrt{8}[/tex]

C. [tex]4\sqrt{5}[/tex]

D. [tex]5\sqrt{4}[/tex]

Answers

Answer:

8√5 units.

Step-by-step explanation:

See the diagram in the coordinate plane attached.

A rhombus has four equal sides and to find the perimeter of the rhombus we have to measure any of the sides of the figure of the rhombus.

The coordinates of the topmost point are (-1,-1) and that of the rightmost point are (3,-3).

Therefore, side length of the rhombus will be  

[tex]\sqrt{(- 1 - 3)^{2} + (- 1 - (- 3))^{2}} = \sqrt{20} = 2\sqrt{5}[/tex] units.

So, the perimeter of the rhombus will be (4 × 2√5) units  = 8√5 units. (Answer)

The distance between two points [tex](x_{1},y_{1})[/tex] and [tex](x_{2},y_{2})[/tex] on a coordinate plane is given by  

[tex]\sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2}}[/tex]

Dylan uses the expressions (x^2 -2x+8) and (2x^2 + 5x - 7) to represent the length and width of his bedroom. Which expression represents the area (lw) of Dylan’s room ?

Answers

[tex]2x^4 + x^3 - x^2 +54x - 56[/tex] expression represents the area of Dylan’s room

Solution:

Given that,

Length of room = [tex]x^2 -2x+8[/tex]

Width of room = [tex]2x^2 + 5x - 7[/tex]

To find: Expression that the area (lw) of Dylan’s room

Since bedroom is generally of rectangular shape, we can use area of rectangle

The area of rectangle is given as:

[tex]\text {area of rectangle }=\text { length } \times \text { width }[/tex]

Substituting the given expressions of length and width,

[tex]area = (x^2 -2x+8)(2x^2 + 5x - 7)[/tex]

We multiply each term inside first parenthesis with each term inside the second parenthesis.

So it becomes,

[tex]2x^4 + 5x^3 - 7x^2 -4x^3 -10x^2 +14x +16x^2 +40x - 56[/tex]

Now combine like terms,

[tex]2x^4 + x^3 - x^2 +54x - 56[/tex]

Thus the above expression represents the area of Dylan’s room

Answer:

c

Step-by-step explanation:

What is the greatest common factor of 9 and 5

Answers

Answer:45

Step-by-step explanation:5 10 15 20 25 30 35 40 45

9 18 27 36 45

The greatest common factor of the number 9 and 5 is 1.

To find the greatest common factor (GCF) of 9 and 5, determine the largest number that evenly divides both 9 and 5.

The factors of 9 are 1, 3, and 9.

The factors of 5 are 1 and 5.

From these lists, the only common factor of 9 and 5 is 1.

Therefore, the greatest common factor of 9 and 5 is 1.

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HELP ME 20 POINTS!!!!!

Consider the characteristics of the graph. Which statement DOES NOT describe the data set?

A) The interquartile range (IQR) is 13.

B) The data is skewed right.

C) The data is skewed left.

D) The median is 50.

Answers

Answer:

B) The data is skewed right.

Step-by-step explanation:

The data is not skewed right. You can tell because the left side of the box is longer than the right, meaning that it is skewed left.

Answer:

B) The data is skewed right.

Step-by-step explanation:

The data is skewed right does not describe the data.

In this set of data, the left side tail is longer.

evaluat5-44*(-0.75)-18/ 2/380.8+(-4/5)

Answers

Answer:37.17 or 37.1763655462

Explanation:i just did the equation and evaulated it it's hard to explain sorry

Answer:

i dont know know because i have the same question but a little different its 5-44*(-0.75)-18 / 2/3 *.8 - 4/5

Step-by-step explanation:

Otto's investment portfolio consisted of shares of internet stock and copper stock. During the year, the value of his internet shares increased $10\%$, but the value of his copper shares decreased from $\$10{,}000$ to $\$9{,}000$. During the same year, the total value of his portfolio increased by $6\%$. What was the dollar value of his internet shares at the end of the year?

Answers

Answer:

44000

Step-by-step explanation:

Let w be the initial value of Otto's internet stock, in dollars. At the beginning of the year, the total value of his portfolio is w+10,000 dollars. At the end of the year, the total value of his portfolio is 1.1w+9,000 dollars. Since increasing by 6% is equivalent to multiplying by 1.06, we have

1.06(w+10,000)=1.1w +9,000

Distributing and collecting terms, we find w=40,000. At the end of the year, his internet stock is worth 40,000* 1.1=44,000 dollars.

*credits: AoPS

Richard has four times as many marbles as john. if Richard have 18 to John they would have the same number. how many marbles has each?​

Answers

Answer:

The number of marbles Richard has 24 and John has 6.

Step-by-step explanation:

Richard has four times as many marbles as john.

If Richard have 18 to John they would have the same number.

Now, to find number of marbles each has.

Let the marbles of John be [tex]x[/tex].

And the marbles of Richard be [tex]4x.[/tex]

According to question:

[tex]4x=x+18.[/tex]

Subtracting both sides by [tex]x[/tex] we get:

[tex]3x=18.[/tex]

Dividing both sides by 3 we get:

[tex]x=6.[/tex]

Marbles of John = [tex]6.[/tex]

Marbles of Richard = [tex]4x=4\times 6=24[/tex]

Therefore, the number of marbles Richard has 24 and John has 6.

Final answer:

John has 12 marbles, and Richard has 48 marbles, as Richard has four times as many as John, and giving John 18 marbles would equalize their amounts.

Explanation:

To find the answer, we need to set up an equation based on the information provided: Richard has four times as many marbles as John, and if Richard gives John 18 marbles, they would have the same number.

Let's denote the number of marbles John has as J. Then Richard has 4J marbles. If Richard gives 18 marbles to John, Richard would have 4J - 18 marbles, and John would have J + 18 marbles. According to the problem, after the exchange, they have an equal number of marbles, so we can write the equation:

4J - 18 = J + 18

Solving for J, we move all the J terms to one side and numeric terms to the other side:

4J - J = 18 + 18

3J = 36

Dividing both sides by 3, we get:

J = 12

So, John has 12 marbles. Since Richard has four times as many, he has 4 x 12 = 48 marbles. Therefore, Richard has 48 marbles and John has 12 marbles.

The owner of Ray’s Deli wants to find out if there is a relationship between the temperature in summer and the number of glasses of lemonade he sells. From the data shown in this scatter plot, you can tell that the A) hotter the temperature, the more lemonade was sold. B) cooler the temperature, the more lemonade was sold. C) most lemonade was sold when temperatures were above 90°F. D) data shows no relationship between temperature and lemonade sales.

Answers

Answer:

D) data shows no relationship between temperature and lemonade sales.  

Step-by-step explanation:

There is no correlation between temperature and lemonade sales. Sometimes two variables are not related. The data shows no relationship between temperature and lemonade sales.

The correct option will be D) data shows no relationship between temperature and lemonade sales.

What is the significant use of graphs in real life?

Graphs are a not unusual place technique to visually illustrate relationships withinside the statistics. The reason for a graph is to provide statistics that are too severe or complex to be defined appropriately withinside the textual content and in much less space.

Given, The owner of Ray’s Deli wants to find out if there is a relationship between the temperature in summer and the number of glasses of lemonade he sells.

Since,

There is no correlation between temperature and lemonade sales. Sometimes two variables are not related. The data shows no relationship between temperature and lemonade sales.

Therefore, The correct option will be D) data shows no relationship between temperature and lemonade sales.

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Determine the radius, to the nearest inch, of a large can of tuna fish that has a volume of 66 cubic
inches and a height of 3.3 inches.

Answers

The radius of can is 2.524 inches

Solution:

Given that large can of tuna fish that has a volume of 66 cubic  inches and a height of 3.3 inches

To find: Radius

Given a large can of tuna fish, we know that can is generally of cylinder shape, we can use the volume of cylinder formula,

The volume of cylinder is given as:

[tex]\text{ volume of cylinder}= \pi r^{2} h$[/tex]

Where,

"r" is the radius of cylinder

"h" is the height of cylinder

[tex]\pi[/tex] is a constant equal to 3.14

Substituting the given values in above formula,

[tex]66 = 3.14 \times r^2 \times 3.3\\\\66 = r^2 \times 10.362\\\\r^2 = \frac{66}{10.362}\\\\r^2 = 6.369\\\\r = 2.524[/tex]

Thus the radius of can is 2.524 inches

the cost of two pies and five cakes is $45.25. the cost of 2 pies and three cakes is $39.75 find the cost of each pie and each cake

Answers

Answer:

cost of each pie = $15.75

cost of each cake = $2.75

Step-by-step explanation:

Let x be the Pie and y be the cake.

Given:

The cost of two pies and five cakes is $45.25,

[tex]2x+5y=45.25[/tex]-----------(1)

The cost of 2 pies and three cakes is $39.75

[tex]2x+3y=39.75[/tex]--------------(2)

Now we subtract equation 2 from equation 1.

[tex]2y=5.5[/tex]

[tex]y=\frac{5.5}{2}[/tex]

y=2.75

Now we substitute the value of y in equation 1.

[tex]2x+5\times 2.75=45.25[/tex]

[tex]2x+13.75=45.25[/tex]

[tex]2x=45.25-13.75[/tex]

[tex]2x=31.5[/tex]

[tex]x=\frac{31.5}{2}[/tex]

x=15.75

So, The cost of each pie is $15.75

And the cost of each cake is $2.75

Final answer:

To find the cost of each pie and cake, two equations were set up based on the total cost of pies and cakes. By subtracting the second equation from the first, the cost of one cake was determined to be $2.75. Subsequently, the cost of one pie was calculated to be $15.75.

Explanation:

Calculating the Cost of Pies and Cakes

We have two equations based on the information provided:

2P + 5C = $45.25

2P + 3C = $39.75

Where P represents the cost of one pie, and C represents the cost of one cake. To solve for P and C, we can subtract the second equation from the first:

2P + 5C - (2P + 3C) = $45.25 - $39.75

2C = $5.50

C = $5.50 / 2

C = $2.75

Now that we know the cost of one cake, we can substitute C in one of the equations to find P:

2P + 5($2.75) = $45.25

2P + $13.75 = $45.25

2P = $45.25 - $13.75

2P = $31.50

P = $31.50 / 2

P = $15.75

Therefore, the cost of each pie is $15.75 and the cost of each cake is $2.75.

Write an equation with a slope of 1/2 and a Y intercept of -2

Answers

Step-by-step explanation:

y=1/2×-2 @$@@$@$@$@%@%@%#_##%#%

Y=1/2x -2 is my answer

11. If line a is parallel to line b, solve for x:
(7x + 11)
(10x - 43)

Answers

To find the value of x for parallel lines with expressions (7x + 11) and (10x - 43), set them equal and solve the resulting equation, which gives x = 18.

If line a is parallel to line b and we have the expressions (7x + 11) for line a and (10x - 43) for line b, then the corresponding angles formed by these lines and a transversal would be equal. To solve for x, we set the two expressions equal to each other because the slopes of parallel lines are equal. The equation would be 7x + 11 = 10x - 43.

Subtract 7x from both sides: 11 = 3x - 43.Add 43 to both sides: 54 = 3x.Divide both sides by 3: x = 54 / 3.Therefore, x = 18.

This is the value of x that makes the two expressions equal, thus confirming the lines are parallel.

Given the diagram below, what is sin (30°) ?

Answers

Answer:

A.  1/2.

Step-by-step explanation:

The ratio of the sides of a 30-60-90 triangle  is 2:1:√3   where  2 is the hypotenuse. 1 is the shortest leg and √3 is the longest leg.

In the diagram we see that the longest leg is opposite the 60 degree angle.

So the longest leg is 3.5√x and  the shortest leg ( from applying the ratios) = 3.5√x / √3.

and the hypotenuse is  2 *  3.5√x / √3    (using the ratios again).

So sin  30 = shortest leg / hypotenuse =  3.5√x / √3 /  2 *  3.5√x / √3

= 1/2.

Solve Ixl<13{(-13, 13}
{xl-13 [XIX<-13 or x 13)

Answers

Answer:

-13 < X < 13

Step-by-step explanation:

It is given |X| < 13.

Note that we have: |x| < a, for any real number 'a', then it equals:

-a < X < a.

So, in this case, |X| < 13 should be equal to -13 < X < 13.

Hence, the answer.

Four students graphed one linear function each. Which student graphed a linear function with a y-intercept at -4?

Answers

Answer:

who ever line crosses the y-axis at -4.

Step-by-step explanation:

Answer:

Ellis so c

Step-by-step explanation:

A car can hold gallons of fuel. It contains gallons of fuel. How much more fuel is needed to fill the car?

Answers

Question:

A car’s gas tank can hold 11 9/10 gallons of gasoline. It contains 8 3/4 gallons of gasoline. How much more gasoline is needed to fill the tank?

Answer:

[tex] 5\frac{3}{20}[/tex] more gasoline is needed to fill the tank?

Step-by-step explanation:

Given:

Capacity of the car tank = 11 9/10

Quantity of fuel already present = 8 3/4

To Find:

Quantity needed to fill the tank = ?

Solution:Let the quantity of the  gasoline needed to fill the tank be  x

Then

x = total capacity of the tank  -  quantity of fuel already present in the tank

x = [tex]11 \frac{9}{10}[/tex] - [tex]8 \frac{3}{4}[/tex]

x = [tex]\frac{119}{10}[/tex] - [tex]\frac{27}{4}[/tex]

x = [tex] 11.9[/tex] - [tex]6.75[/tex]

x = 5.15 or [tex] 5\frac{3}{20}[/tex]

Elyse has $18 on a gift card that she can use to rent movies online. The graph at the right shows the amount of money remaining on her gift card ba. sed on the number of movies she rents. Find the unit rate of the graph, and describe what it means in the context of the situation.

Answers

Answer:

see the explanation

Step-by-step explanation:

The complete question in the attached figure

Let

x ----> the number of movies

y ----> the amount of money remaining on her gift card

we know that

The slope of the linear equation is equal to the unit rate

take two points from the graph

(0,18) and (2,12)

Find the slope

[tex]m=(12-18)/(2-0)[/tex]

[tex]m=(-6)/(2)=-\$3\ per\ movie[/tex] ---> is negative because is a decreasing function

That means -----> Each movie she rents cost her $3, so her  gift card balance will decrease $3 for every movie rented

The linear equation is equal to

[tex]y=-3x+18[/tex]

For y=0

[tex]0=-3x+18[/tex]

[tex]x=6[/tex]

so

6 is the maximum number of movies that Elyse can rent on line

Final answer:

The unit rate is the ratio of the change in the y-coordinate value to the change in the x-coordinate value between any two strategically chosen points. Elyse's unit rate represents the cost per movie rental.

Explanation:

While the graph isn't directly available, the principle to find the unit rate of the graph is the same. The unit rate is the ratio of the change in the vertical (y-axis) value to the change in the horizontal (x-axis) value between any two distinct points on the graph. In the context of Elyse's movie rentals, the unit rate would represent the cost per movie.

To calculate this, you'd subtract the y-coordinate value of the second point from the y-coordinate value of the first point. This represents the change in the balance of the gift card. Then you'd subtract the x-coordinate value of the second point from the x-coordinate value of the first point, representing the number of movies rented. Dividing the change in balance by the number of movies gives the cost per movie, which is our unit rate.

For example, if she had $12 after renting 2 movies and $6 on her card after renting 4 movies, the unit rate would be computed as: (12 - 6) / (4 - 2) = $3 per movie. This means that for every movie that Elyse rents, she spends $3 from her gift card.

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2.) A scuba diver is swimming 18 feet below the water's surface. The diver swims up slowly at 0.6 feet per second for 5 seconds and then swims up for 2 more seconds at 0.3 feet per second. What is the diver's new depth?

Answers

Answer:

The diver's new depth is 14.4 feet.

Step-by-step explanation:

Given:

A scuba diver is swimming 18 feet below the water's surface.

The diver swims up slowly at 0.6 feet per second for 5 seconds and then swims up for 2 more seconds at 0.3 feet per second.

Now, to find the diver's new depth.

As given,

Total depth = 18 feet.

Total distance covered:

[tex]Distance\ covered = 0.6\times 5+0.3\times 2[/tex]

[tex]Distance\ covered = 3+0.6[/tex]

[tex]Distance\ covered =3.6[/tex]

Now, to get the new depth:

New depth = Total depth - distance covered.

[tex]New\ depth=18-3.6[/tex]

[tex]New\ depth=14.4\ feet.[/tex]

Therefore, the diver's new depth is 14.4 feet.

Every student in the senior class is taking history or science. There are $200$ seniors in the class. If there are $126$ seniors taking history and $129$ seniors taking science, how many students are taking both history and science?

Answers

Answer: 55

Step-by-step explanation:

126+129= 255

255-200=55

55 students are taking both history and science.

To solve this, we set up the problem as follows: Let H represent the set of students taking history, S represent the set of students taking science, and N represent the total number of seniors. We're given that N = 200, |H| = 126 (the number of students taking history), and |S| = 129 (the number of students taking science). The number of students taking both can be found by adding the number of students in sets H and S and subtracting the total N. This calculation is often represented by the formula |H ∩ S| = |H| + |S| - N, where |H ∩ S| is the number of students taking both history and science.

Using the formula, we calculate: |H ∩ S| = 126 + 129 - 200 = 55. Therefore, 55 seniors are taking both history and science.

Select the correct answer.
During the summer, Jody earns $10 per hour babysitting and $15 per hour doing yardwork. This week she worked 34 hours and earned $410.
If x represents the number hours she babysat and y represents the number of hours she did yardwork, which system of equations models
this situation?
A.
X+ y = 34
10x+ 15y = 410
OB. X + y = 410
10x + 15y = 34
C.
X+ y = 34
15x+10y= 410
OD. x + y = 410
15x+10y = 34​

Answers

Answer:

A

Step-by-step explanation:

x+y=34 (add the seperate hours together to get the total amount of hours)

10x+15y=410 (multiply the money made each hour by the hours worked and add them together to get the amount of money joy made)

The system which creates a mathematical representation of the given condition will be X+ y = 34 and 10x+ 15y = 410 so option (A) will be correct.

How to form an equation?

When trying to set up or construct a linear equation to fit a real-world application, identify the known quantities and use the unknown quantity as a variable.

In other words, an equation is a set of variables that are constrained through a situation or case.

x = number of hours babysitting.

y = number of hours yard work.

Given that

She worked a total of 34 hours

So x + y = 34 will be the correct formation.

Jody earns $10 per hour babysitting

So a total of 10x money Jody will earn through babysitting.

$15 per hour doing yardwork

So a total of 15x money Jody will earn through yard work.

Given that

A total of $410 Jody earned so

10x + 15y = 410 will be the correct formation.

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A tour company has a ticket price that goes down $2 for every additional person who signs up for a group trip. They charge, per person, 52-2n Where n is the number of people that go on the trip. Their total revenue, R, as a function of the number of people who can go in the trip is R=52n-2n^2. How many people Maximize the revenue for the tour company

Answers

The maximum revenue occurs at [tex]\( n = 13 \).[/tex]

The correct option is (a).

To maximize the revenue for the tour company, we need to find the value of ( n ) that maximizes the revenue function [tex]\( R = 52n - 2n^2 \).[/tex]

1. Find the derivative of the revenue function:

  The derivative of a function gives us the rate of change of the function. We will find the derivative of the revenue function with respect to ( n ) to find where the revenue function is increasing or decreasing.

Given the revenue function [tex]\( R = 52n - 2n^2 \)[/tex], we'll find its derivative [tex]\( \frac{dR}{dn} \):[/tex]

[tex]\[ \frac{dR}{dn} = \frac{d}{dn}(52n - 2n^2) \][/tex]

[tex]\[ \frac{dR}{dn} = 52 - 4n \][/tex]

2. Set the derivative equal to zero to find critical points:

  To find the critical points, we set the derivative equal to zero and solve for ( n ):

[tex]\[ 52 - 4n = 0 \][/tex]

[tex]\[ 4n = 52 \][/tex]

[tex]\[ n = \frac{52}{4} \][/tex]

[tex]\[ n = 13 \][/tex]

3. Determine the nature of the critical point:

  To determine if ( n = 13 ) is a maximum or minimum, we use the second derivative test. If the second derivative is negative at the critical point, it's a maximum; if positive, it's a minimum.

Taking the second derivative of ( R ):

[tex]\[ \frac{d^2R}{dn^2} = \frac{d}{dn}(52 - 4n) \][/tex]

[tex]\[ \frac{d^2R}{dn^2} = -4 \][/tex]

Since the second derivative [tex]\( \frac{d^2R}{dn^2} = -4 \) is negative, \( n = 13 \)[/tex] corresponds to a maximum.

4. Verify the endpoints:

  Since the domain of ( n ) is not specified, we need to check if the endpoints of the domain have any maximum revenue. In this case, we don't have any specific domain constraints, so we don't need to check the endpoints.

5. Conclusion:

The maximum revenue occurs at [tex]\( n = 13 \).[/tex]

Therefore, the correct answer is option a) 13.

complete question given below:

A tour company has a ticket price that goes down $2 for every additional person who signs up for a group trip. They charge, per person, 52-2n Where n is the number of people that go on the trip. Their total revenue, R, as a function of the number of people who can go in the trip is R=52n-2n^2. How many people Maximize the revenue for the tour company

a.13

b.26

c.39

d.22

Maximized revenue for the tour company occurs with 13 people on the trip, yielding $676.

To maximize revenue, we need to find the maximum point of the revenue function [tex]\( R = 52n - 2n^2 \)[/tex]. We can do this by finding the derivative of the revenue function with respect to n and then setting it equal to zero to find the critical points. Then, we can determine whether these critical points correspond to a maximum or minimum by analyzing the second derivative.

So, let's start by finding the derivative of the revenue function:

[tex]\[ \frac{dR}{dn} = 52 - 4n \][/tex]

Setting this derivative equal to zero and solving for [tex]\( n \):[/tex]

[tex]\[ 52 - 4n = 0 \][/tex]

[tex]\[ 4n = 52 \][/tex]

[tex]\[ n = \frac{52}{4} \][/tex]

[tex]\[ n = 13 \][/tex]

Now, we need to check whether this critical point corresponds to a maximum or a minimum. To do this, we'll take the second derivative of the revenue function:

[tex]\[ \frac{d^2R}{dn^2} = -4 \][/tex]

Since the second derivative is negative, the critical point [tex]\( n = 13 \)[/tex]corresponds to a maximum.

So, the tour company will maximize its revenue when 13 people go on the trip.

IF THIS WRONG I FAIL!!!!

Matt has started a car washing business to save money for college. Each week, he
washes 3 more cars than he did the week before.
Part A: Matt started by washing 6 cars his first week in business. Write an explicit formula that can be used to find the number of cars he washed on any given week.
Part B: Part B: How many cars will Matt wash on his 11th week in business?

Answers

Part A: 3x+6
Part B: 3(11)+6
Not a 100% sure but hope this helps

Answer:

Part A:

An= 6 + 3(n-1)

Part B:

36 cars

Find the solutions to x2 = 18.

Answers

Answer:

6^3

Step-by-step explanation:

Ape-x

The solutions are [tex]\(x = 3\sqrt{2}\)[/tex] and [tex]\(x = -3\sqrt{2}\)[/tex]. Each represents a square root of 18.

To find the solutions to [tex]\( x^2 = 18 \)[/tex], you need to take the square root of both sides of the equation.

[tex]\[ x = \pm \sqrt{18} \][/tex]

[tex]\[ x = \pm 3\sqrt{2} \][/tex]

So, the solutions to [tex]\( x^2 = 18 \)[/tex] are [tex]\( x = 3\sqrt{2} \)[/tex] and [tex]\( x = -3\sqrt{2} \).[/tex]

There are 100 freshman students at a school. The probability that a freshman plays a sport is 0.55. The probability that a freshman plays a musical instrument is 0.34. The probability that a freshman plays both a sport and a musical instrument is 0.15. What is the probability that a freshman student at this school plays either a sport or a musical instrument?

Answers

The probability that a freshman student at this school plays either a sport or a musical instrument is 0.74

Step-by-step explanation:

The addition rules in probability are:

P(A or B) = P(A) + P(B) ⇒ mutually exclusive (events cannot happen at the same time)P(A or B) = P(A) + P(B) - P(A and B) ⇒ non-mutually exclusive (if they have at least one outcome in common)

∵ The probability that a freshman plays a sport is 0.55

∴ P(sport) = 0.55

∵ The probability that a freshman plays a musical instrument is 0.34

∴ P(music) = 0.34

∵ The probability that a freshman plays both a sport and a musical

    instrument is 0.15

∴ P(sport and music) = 0.15

To find the probability that freshman student at this school plays either a sport or a musical instrument use the second rule above because it is non-mutually exclusive

∵ P(sport or music) = P(sport) + P(music) - P(sport and music)

∴ P(sport or music) = 0.55 + 0.34 - 0.15

∴ P(sport or music) = 0.74

The probability that a freshman student at this school plays either a sport or a musical instrument is 0.74

Learn more:

You can learn more about the probability in brainly.com/question/9178881

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The probability that a freshman student at this school plays either a sport or a musical instrument is indeed 0.74

To find the probability that a freshman student plays either a sport or a musical instrument, we can use the principle of inclusion-exclusion for probability.

The principle states that for any two events A and B, the probability of the union of A and B is given by:

[tex]\[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \][/tex]

Let event A be the event that a freshman plays a sport, and event B be the event that a freshman plays a musical instrument.

We are given the following probabilities:

P(A) = 0.55 (the probability that a freshman plays a sport)

P(B) = 0.34 (the probability that a freshman plays a musical instrument)

P(A and B) = 0.15 (the probability that a freshman plays both a sport and a musical instrument)

 Using the principle of inclusion-exclusion, we calculate the probability  Upon reviewing the calculation, it appears there was an error in the final step.

The correct calculation should be:

[tex]\[ P(\text{either A or B}) = P(A \cup B) \][/tex]

[tex]\[ P(\text{either A or B}) = 0.74 \][/tex]

Therefore, the probability that a freshman student at this school plays either a sport or a musical instrument is indeed 0.74, not 0.64 as initially stated.

The final answer is [tex]\(\boxed{0.74}\).[/tex]

Given: x - 5 > -10.
Choose the solution set.
{xIXER, X<-15)
O {xIXER, x>-5)
O {xIXER,x<5)
{XIXER, x> 15)

Answers

Answer:

The solution set is given as:

B) [tex]\{x|x\epsilon R, x>-5\}[/tex]

Step-by-step explanation:

Given inequality:

[tex]x-5>-10[/tex]

To find the solution set for the given inequality.

Solution:

We have : [tex]x-5>-10[/tex]

Solving for [tex]x[/tex]

Adding 5 both sides.

[tex]x-5+5>-10+5[/tex]

[tex]x>-5[/tex]

Thus the solution set is all real numbers greater than -5. This can be given as:

[tex]\{x|x\epsilon R, x>-5\}[/tex]

Portage Park is a perfect square. The length of each side of the park is 200 feet.

Mr. Carter and his wife are standing at the corner of N. Long Avenue and W. Irving Park Rd. They plan to walk diagonally across Portage Park from point C to point A. Which mathematical statement could be used to find the distance they will walk?

Answers

Final answer:

The question is a Mathematics problem related to the concept of the Pythagorean Theorem. The solution entails considering the diagonal walk as the hypotenuse in a right triangle, whose sides' lengths are known (200 feet). The Pythagorean theorem is then used to calculate the hypotenuse's length.

Explanation:

The subject of this question is mathematics, specifically, the concept of the Pythagorean Theorem in geometry. The park is described as a perfect square, so the diagonal Mr. Carter and his wife plan to walk across can be thought of as the hypotenuse of a right triangle formed by two sides of the square.

Given that each side of the square is 200 feet, the length between points C and A can be calculated using the Pythagorean theorem, which is a² + b² = c². Here, both a and b are the lengths of the sides of the park, which is 200 feet. So the calculation would be: 200² + 200² = c². This simplifies to 40000 + 40000 = c², leading to a total of 80000 = c². To find c, which is the distance they will walk across the park, we take the square root of 80000, which can be rounded down to 283 feet if we use a calculator.

Learn more about Pythagorean Theorem here:

https://brainly.com/question/28361847

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Final answer:

Mr. Carter and his wife can find the distance they will walk across the park by using the Pythagorean theorem. They substitute the length of the sides of the square (200 feet) into the theorem's formula: sqrt (200^2 + 200^2) to calculate the distance.

Explanation:

The subject of this question is Mathematics, and it pertains to the topic of geometry, specifically the Pythagorean theorem. We are given a perfect square (Portage Park) with sides of 200 feet, and we want to find the distance from one corner (point C) to the diagonally opposite corner (point A). This distance forms the hypotenuse of a right triangle, where the sides of the square become the two legs of the triangle.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (c) is equal to the sum of the squares of the lengths of the other two sides (a and b). So the distance  Mr. Carter and his wife will walk (d) can be described with the equation: d = sqrt (a^2 + b^2).

Since Portage Park is a perfect square, both a and b are 200 feet. You can substitute 200 for both a and b in the equation to find d: d = sqrt (200^2 + 200^2).

Learn more about Pythagorean theorem here:

https://brainly.com/question/28361847

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Last week, it rained x inches. This week, the amount of rain decreased by 5% Which
expressions represent the amount of rain that fell this week? Select all that apply.
A. g - 0.05
B. g - 0.05g
C. 0.95g
D. 0.058
E. (1 – 0.05)g

Answers

Hope it helps u..............

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