John’s gross pay for the week is $500. He pays 1.45 percent in Medicare tax, 6.2 percent in Social Security tax, 2 percent in state tax, 20 percent in federal income tax, and $20 as an insurance deduction. He does not have any voluntary deductions. What is John’s net pay for the week?

Answers

Answer 1
gross pay = 500

deductions :
medicare tax : 0.0145(500) = 7.25
S.S tax : 0.062(500) = 31.00
sales tax : 0.02(500) = 10.00
income tax : 0.2(500) = 100
insurance = 20
total deductions : 7.25 + 31 + 10 + 100 + 20 = 168.25

gross pay - deductions = net pay
500 - 168.25 = net pay
331.75 = net pay <===
Answer 2
Final answer:

John's net pay is calculated by subtracting deductions for Medicare, Social Security, state and federal taxes, and insurance from his gross pay of $500. The total deductions amount to $168.25, resulting in a net pay of $331.75.

Explanation:

Calculation of John's Net Pay

To calculate John's net pay, we need to subtract all the deductions from his gross pay. Since his gross pay is $500, we will apply the following deductions:

Medicare tax: 1.45% of $500 = $7.25

Social Security tax: 6.2% of $500 = $31.00

State tax: 2% of $500 = $10.00

Federal income tax: 20% of $500 = $100.00

Insurance deduction: $20.00

Add up all deductions: $7.25 (Medicare) + $31.00 (Social Security) + $10.00 (State Tax) + $100.00 (Federal Tax) + $20.00 (Insurance) = $168.25

John's net pay is therefore calculated by subtracting the total deductions from his gross pay: $500.00 - $168.25 = $331.75.


Related Questions

Dennis ran a mile in 593.7 seconds. Martina ran a mile in 573.36 seconds. What was the difference in their running times ?
A . 5.14 seconds
B . 6.01 seconds
C . 20.34 seconds
D . 26.01 seconds

Answers

The answer would be C.20.34

Choose the fraction that goes in the blank? 1/2 < _ < 4/5

I don't understand how they got 2/3

Answers

2/3 works here because its value is greater than 1/2 but less than 4/5. An easy way to visualize this is to take the decimal value of each number as decimals are often easier to understand than fractions.

1/2=.50
2/3=.67
4/5=.80

This inequality could be rewritten as .50 < .67 < .80 and would have the same value.
1/2 < __ < 4/5

1/2 = 0.5
4/5 = 0.8

they got 2/3 because 2/3 = 0.66 and it falls in between 1/2 and 4/5.

The other answer choices obviously did not fall in the solution range

A video game sets the points needed to reach the next level based on the function g(x) = 7(3)^x − 1, where x is the current level. The hardest setting promises to multiply the points needed in each level according to the function h(x) = 4x. How many points will a player need on the hardest setting of level 4?

Answers

well, using the current level function of g(x), the player on level 4 will then need 7(3)⁴-1 to get to the next level.

however, if the player is using the hardest setting, the hardest setting promises to quadruple any points on the current level, so, he/she will only need a quarter of 7(3)⁴-1.

now, 7(3)⁴-1 is 566, however, you don't need all 566 in hardest setting, you can do with only 566/4, since the hardest setting will give you 4x or quadruple of the amount of points.

A player will need 2,264 points on the hardest setting of level 4 as calculated by evaluating g(4) using the function g(x) = 7(3)^x - 1 and then applying the function h(x) = 4x.

To calculate the number of points a player will need on the hardest setting of level 4, we need to consider the function h(x) = 4x provided in the context of the question. However, the question also mentions the function g(x) = 7(3)^x - 1, which indicates the points needed to reach the next level normally. Since we need to find the hardest setting value, we will use the function h(x) but before that, we need to evaluate g(4) to find out the base points at level 4.

To find g(4), we substitute x = 4 into g(x):

g(4) = 7(3)^4 - 1 = 7(81) - 1 = 567 - 1 = 566

Now we apply the function h(x) to this value to get the points on the hardest setting:

h(g(4)) = 4 × 566 = 2264

Therefore, a player will need 2,264 points on the hardest setting of level 4.

estimate the product 731+207

Answers

The answer would be 938. So yeah
The estimated sum of 731 and 207 is 900.

I know this because...
  - 731 is rounded to 700
  - 207 is rounded to 200
  - 700 + 200 = 900

Hope this helps! :)

Set up a system of equations for the following scenario. Then solve for the system. Three students buy different combinations of tickets for a baseball game. The first student buys 2 senior, 1 adult, and 2 student tickets for $51. The second student buys 1 adult and 5 student tickets for $55. The third student buys 2 senior, 2 adult, and 7 student tickets for $75. Set up a system of equations to find the price of each ticket.

Answers

Let
x =  cost of a ticket for a senior
y = cost of a ticket for an adult
z =  cost of a ticket for a student.

The first student buys 2 senior, 1 adult, and 2  student tickets for $51.
Therefore
2x + y + 2z = 51                 (1)

Th second student buys 1 adult and 5  student tickets for $5.
Therefore
y + 5z = 55                       (2)

The third student buys 2 senior, 2 adult, and 7 student tickets for $75.
Therefore
2x + 2y + 7z = 75            (3)

Answer:
The system of equation for determining x, y, and z is
2x + y + 2z = 51
        y + 5z = 55
2x + 2y + 7z = 75

Warnng: The system of equations does not have a solution.

Find the surface of a cylinder with a base diameter of 4yd and a height of 6yd

Answers

pi*radius squared= area of a circle
3.14*2^2=12.56yd^2

pi*diameter=circumference
3.14*4=12.56yd

area of surface around the cylinder=circumference*height
12.56*6=75.36yd^2

area of surface around the cylinder+ (area of circle*2)= surface area
75.36+(12.56*2)=100.48

the answer should by 100.48 yards squared

hope this helps

Which equation does the graph of the systems of equations solve? two linear functions intersecting at 4, 1 the answers are one fourthx + 2 = 2x − 7 one fourthx + 2 = −2x − 7 −one fourthx + 2 = 2x − 7 −one fourthx + 2 = −2x − 7

Answers

1/4x + 2 = 2x - 7.....this has been broken down...ur system of equations is :  y = -1/4x + 2 and y = 2x - 7
-1/4x + 2 = 2x - 77 + 2 = 2x + 1/4x9 = 8/4x + 1/4x9 = 9/4x9 * 4/9 = x4 = x
y = 2x - 7y = 2(4) - 7y = 8 - 7y = 1
solution is : -1/4x + 2 = 2x - 7 letter c

Factor 2a^5b + 2a^4b^2 + 2a^3b^3.
A.)2a^2b(a^2+a

Answers

2a^5b + 2a^4b^2 + 2a^3b^3

2a^3b (a^2 + ab + b^2) <==

Given the Vectors s=(-3,2) and t= (-9,-4), find 6s and s+t

Answers

hello : 
s=(-3,2) and t= (-9,-4),
6s = (-3×6 , 2×6 ) = (-18 , 12)
s+t = ( -3-9 , 2-4 ) = (-12,-2)
6s=(-18,12), and t+s=(-12,-2).

Ivan was given two data sets, one without an outlier and one with an outlier.

Data without an outlier: 108, 113, 105, 118, 124, 121, 109
Data with an outlier: 108, 113, 105, 118, 124, 121, 109, 61

How is the median affected by the outlier?

Answers

Answer:

b

Step-by-step explanation:

The outlier affects the median of the data sets collected by Ivan by reducing the median.

What is an outlier?

An outlier is a number that is way smaller or way larger than that of other numbers in a data set. The outlier in the data set is 62. Median is the number at the center of a data set.

Median without an outlier is 113Median with an outlier is 111

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How do you subtract an integer from another integer without using a number line or counters? Give an example.

Answers

if they are two positive numbers, do it normally. If there is a negative and a positive, change it to addition and switch the SECOND integer sign. Only works with two integer…s in a subtraction question.

A brace for a shelf has the shape of a right triangle. Its hypotenuse is 8 inches long and the two legs are equal in length. How long are the legs of the​ triangle?

Answers

since it's a right triangle

[tex]\bf \textit{using the pythagorean theorem}\\\\ c^2=a^2+b^2\qquad \begin{cases} c=hypotenuse\\ a=adjacent\\ b=opposite\\ -------\\ c=8\\ b=a \end{cases}\implies 8^2=a^2+a^2 \\\\\\ 64=2a^2\implies \cfrac{64}{2}=a^2\implies 32=a^2\implies \sqrt{32}=a \\\\\\ \sqrt{16\cdot 2}=a\implies \sqrt{4^2\cdot 2}=a\implies 4\sqrt{2}=a[/tex]

At a certain time, the length of a rectangle is 5 feet and its width is 3 feet. At that same moment, the length is decreasing at 0.5 feet per second and the widthis increasing at 0.4 feet per second.

What is the length of the diagonal at that time?
How fast is the length of the diagonal changing? Is this length increasing or decreasing?

Answers

check the picture below

[tex]\bf r^2=x^2+y^2\implies 2r\cfrac{dr}{dt}=2x\cfrac{dx}{dt}+2y\cfrac{dy}{dt}\implies \cfrac{dr}{dt}=\cfrac{x\frac{dx}{dt}+y\frac{dt}{dt}}{r} \\\\\\ \cfrac{dr}{dt}=\cfrac{(5\cdot -0.5)+(3\cdot 0.4)}{\sqrt{34}}[/tex]

if it's a negative value, thus a negative rate, thus is decreasing, if it is a positive value, then increasing.
The diagonal is the hypotenuse of a 5 by 3 triangle.
d = (L^2 + W^2)^.5 = SQRT(34) or 34^.5
Taking the derivative of d:
d' = (1/2)(2LL' + 2WW')(L^2 + W^2)^(-.5)
Solving for d' given the L=5, L'=-.5, W=3, W'=+.4
yields d is decreasing at a rate of -2229 feet/sec.

subtract, 8 3/8 - 10 1/6

Answers

[tex] 8\frac{3}{8} = \frac{67}{6} \\ 10\frac{1}{6} = \frac{61}{6} [/tex]

[tex] 8\frac{3}{8} - 10\frac{1}{6}[/tex]

[tex]convert [/tex] them to: [tex] \frac{67}{8} - \frac{61}{6} [/tex]

[tex] \frac{67}{8} - \frac{61}{6} = \frac{-43}{24} [/tex]

Your [tex]answer[/tex]: [tex] -1\frac{19}{24} [/tex]

Good luck on your assignment  & enjoy your day 





                  ~[tex]MeIsKaitlyn :)[/tex]

With 400,000 sq ft or 16% of total office space. How much space did the city have

Answers

if 400,000 is 16%, and "x" is say the 100%

well then    [tex]\bf \begin{array}{ccllll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 400,000&16\\ x&100 \end{array}\implies \cfrac{400000}{x}=\cfrac{16}{100}[/tex]

solve for "x".

Find f(-5), if f(x) = -x^2 - 2x+1

Answers

Simple as subbin' in -5 for x.
f(-5) = -(-5)² - 2(-5) + 1
= -25 + 10 + 1
= -14
f(x) = -x² - 2x + 1

f(-5) = -(-5)² - 2(-5) + 1

f(-5) = -25 + 10 + 1

f(-5) = -15 + 1

f(-5) = -14

-14 <----- answer

yesterday's low temperature was -2.5 degrees celsius. today's low temperature is 5 times as low as yesterday's low temperature. what was the low temperature today?

Answers

The temperature is -12.5 degrees Celsius.

Answer:

The temperature is -12.5 degrees Celsius.

Step-by-step explanation:

The daily maximum temperature, or high, describes how warm you can expect the air to be, usually from 7 a.m. to 7 p.m. The daily minimum temperature, or low, tells how much the air is expected to cool, usually overnight from 7 p.m. to 7 a.m.

A basketball is thrown with an initial upward velocity of 25 feet per second from a height of 8 feet above the ground. The equation h=-16t^2+25t+8 models the height in feet t seconds after it is thrown. After the ball passes its maximum height, it comes down and then goes into the hoop at a height of 10 feet above the ground. About how long after it was thrown does it go into the hoop?

Answers

So we want to know the later time when h=10 so

10=-16t^2+25t+8

16t^2-25t+2=0

Using the quadratic formula for expediency...

t=(25±√497)/32, we want the time when it was falling so

t=(25+√497)/32

t≈1.48 seconds (to nearest hundredth of a second)

Answer:

A quadratic equation is in the form of [tex]ax^2+bx+c =0[/tex]........[1], then the solution for this equation is given by:

[tex]x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]

As per the statement:

The equation is given by:

[tex]h=-16t^2+25t+8[/tex]

where, h is the height in feet t seconds after it is thrown.

After the ball passes its maximum height, it comes down and then goes into the hoop at a height of 10 feet above the ground.

⇒h = 10 feet

then;

[tex]-16t^2+25t+8=10[/tex]

Subtract 10 from both sides we have;

[tex]16t^2-25t+2=0[/tex]

On comparing this equation with [1] we have;

a =16 , b =-25 and c =2

then;

[tex]t= \frac{25 \pm \sqrt{(-25)^2-4(16)(2)}}{2(16)}[/tex]

⇒[tex]t= \frac{25 \pm \sqrt{625-128}}{32}[/tex]

⇒[tex]t= \frac{25 \pm \sqrt{497}}{32}[/tex]

as we want the time when it was falling so ,

[tex]t= \frac{25 + \sqrt{497}}{32}[/tex]

Simplify:

[tex]t \approx 1.48[/tex] sec

Therefore, 1.48 sec long after it was thrown does it go into the hoop

Stacy is walking his dog on a path and his dog wiggled out of his collar. If the dog is 30 feet lower than the owner and the angle of elevation from the dog to the owner is 10 degrees, find the distance from the dog to the owner.

Answers

It would be best to draw the problem described above. Sketching it, you will see that a right triangle would be formed from the description where the vertical distance of the dog to its owner is the height of the triangle and the angle of elevation of the triangle would be 10 degrees. The hypotenuse of the triangle represents the distance of the dog from its owner. By using trigonometric functions, we can easily calculate for this value. We use the sine function which is equal to the opposite side divided by the hypotenuse.

sine 10 = 30 feet / hypotenuse
hypotenuse = 172.76 feet ( distance of the dog to its owner )

if I have 3 layers of 14 cases per layer of an item,how many total cases should I have

Answers

3 layer 14 cases multiply
3×14=42 cases

The total number of cases I should have is 42.

How many cases should I have?

Multiplication is the mathematical operation that is used to determine the product of two or more numbers.

Total number of cases = number of layers x cases per layer

14 x 3 = 42

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The sum of differences between the group mean and the grand mean summed over all groups for a given set of observations is called _____ variance.

Answers

The sum of differences between the group mean and the grand mean summed over all groups for a given set of observations is called the partitioning variance. This is used in the statistical tool ANOVA- between groups variance. It is abbreviated to SSB which means the sum of squares between groups. 

a plane takes 2hr to travel 1000mi with the wind. it can travel only 880mi against the wind in the same amount of time. find the speed of the wind and the speed of the plane in still air

Answers

recall  your d = rt, distance = rate * time

so... let's say, the plane's speed in still air is "p", and the speed of the wind is "w".

when the plane is travelling with the wind over those 1000 miles, is really not going "p" fast, is going " p + w " fast, since it's going with the wind.

now, when the plane is travelling against the wind, is not going "p" fast either, is going " p - w " fast, since the wind is subtracting speed from it.

bearing in mind he cover the 1000 miles as well as the 880 miles in 2 hrs each way.

[tex]\bf \begin{array}{lccclll} &distance&rate&time\\ &-----&-----&-----\\ \textit{with the wind}&1000&p+w&2\\ \textit{against the wind}&880&p-w&2 \end{array} \\\\\\ \begin{cases} 1000=2(p+w)\\ \qquad 500=p+w\\ \qquad 500-p=\boxed{w}\\ 880=2(p-w)\\ ----------\\ \frac{880}{2}=p-w\\ 440=p-\left( \boxed{ 500-p }\right) \end{cases} \\\\\\ 940=2p\implies \cfrac{940}{2}=p\implies 470=p[/tex]

what's the speed of the wind?  well, 500 - p = w.

Autumn is thinking about buying a car. The table below shows the projected value of two different cars for three years.


Number of years 1 2 3
Car 1 (value in dollars) 38,000 32,000 26,000
Car 2 (value in dollars) 38,000 32,300 27,455


Part A: What type of function, linear or exponential, can be used to describe the value of each of the cars after a fixed number of years? Explain your answer. (2 points)

Part B: Write one function for each car to describe the value of the car f(x), in dollars, after x years. (4 points)

Part C: Autumn wants to purchase a car that would have the greatest value in 6 years. Will there be any significant difference in the value of either car after 6 years? Explain your answer, and show the value of each car after 6 years. (4 points)

Answers

PART A

The value of car A decreases by 6000 every year. Since the decrease is the same every year, the function is linear

The value of car B decreases by the ratio of [tex] \frac{17}{20} [/tex] every year. Since the decrease is by the same ratio every year, the function is exponential

PART B

Car 1: the function is [tex]y=-6000x+44000[/tex], where [tex]y[/tex] is the value after [tex]x[/tex] years. Negative 6000 shows the decrease every year and 44000 is the value of the car in Year 0

Car 2: the function is [tex]y=(38000) ( \frac{17}{20}) ^{x-1} [/tex], where [tex]y[/tex] is the value after [tex]x[/tex] years. 38000 is the value of the car after Year 1 and [tex] \frac{17}{20} [/tex] is the ratio of depreciation

PART C

Value of car 1 after 6 years is [tex]-6000(6)+44000=8000[/tex]
Value of car 2 after 6 years is [tex](38000) ( \frac{17}{20}) ^{6-1} =16860.8[/tex]

There is a significant difference in the values of the cars after 6 years
Final answer:

The value of Car 1 decreases linearly and can be described by a linear function. Without an exact exponential function for Car 2, we'll assume it may have a slower depreciation rate compared to Car 1. Autumn should consider Car 2 to likely have greater value after 6 years.

Explanation:

Part A: Identifying the Type of Function

To determine which type of function best describes the value of each car after a fixed number of years, we must look at the rate at which the car's value decreases. For Car 1, the value decreases by a constant amount each year ($6,000), which suggests a linear function. Conversely, Car 2 does not decrease by the same amount each year, but rather by amounts that seem to be getting progressively larger, hinting at an exponential function.

Part B: Writing the Functions

The linear function for Car 1 can be represented as f(x) = -6,000x + 44,000, since we start at $44,000 and decrease by $6,000 each year. For Car 2, an exponential decay function may fit the data; however, with only three points provided, determining the exact exponential function would require more complex regression analysis which we do not perform here. Assuming the rate of depreciation remains similar, we might estimate the function for Car 2 using a linear approximation for simplicity.

Part C: Future Car Value Comparison

Extending the linear depreciation model for Car 1, its value after 6 years would be f(x) = -6,000(6) + 44,000 = $8,000. A precise prediction for Car 2 after 6 years cannot be determined without an accurate exponential function, but it's apparent that Car 2 depreciates less rapidly than Car 1. Therefore, Autumn would likely find that Car 2 retains more value over 6 years.

If the constant c is chosen so that the curve given parametrically by ct, c 2 8 t 2 , 0 ≤ t ≤ 3 , is the arc of the parabola 8y = x 2 from (0, 0) to (4, 2), find the coordinates of the point p on this arc corresponding to t = 2.

Answers

Since the parabola is given by [tex]8y=x^2[/tex], and [tex]x[/tex] is parameterized by [tex]x(t)=ct[/tex], it follows that when [tex]t=3[/tex] and [tex]x=4[/tex], we have

[tex]4=3c\implies c=\dfrac43[/tex]

So when [tex]t=2[/tex], the [tex]x[/tex]-coordinate of the point [tex]p[/tex] would be

[tex]x=\dfrac43(2)=\dfrac83[/tex]

I'm not sure how [tex]y[/tex] is parameterized, but my best guess is that you mean to say

[tex]y(t)=\dfrac{c^2}8t^2[/tex]

which means when [tex]t=2[/tex] we would get a [tex]y[/tex]-coordinate of

[tex]y=\dfrac{\left(\frac43\right)^2}82^2=\dfrac89[/tex]
Final answer:

By solving the given equations using the provided information, and assuming the constant c = 4/3, we can find the coordinates of the point P on the curve corresponding to t = 2 are (8/3, 32/9). There is a probable discrepancy in the question which causes two different solutions for c, therefore making the canonical form of the parabola ambiguous.

Explanation:

The given parametric curve has its equations as x = ct and y = c/8 * t^2. We're given that it's the arc of the parabola 8y = x^2 from (0, 0) to (4, 2), meaning that we can set x = ct = 4 and y = c/8 * t^2 = 2 when t=3 (the upper limit of t) to find the value of the constant c. Solving these equations gives c=4/3 and c=48. Since c must be the same in both equations, there seems to be a discrepancy here, which could possibly originate from a mistake in the question. However, if we only use c from the first equation (x = ct), we get c = 4/3.

The question asks for the coordinates of the point on the curve corresponding to t = 2. Substituting t = 2 into x = ct and y = c/8 * t^2 gives x = 8/3 and y = 32/9, assuming c = 4/3. So, the coordinates of the point would be (8/3, 32/9).

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Consider the function f(x) = (x − 3)2(x + 2)2(x − 1). The zero has a multiplicity of 1. The zero −2 has a multiplicity of?

Answers

The zero with a multiplicity of 1 is x = 1, and the zero x = -2 has a multiplicity of 2.

How to find the multiplicity of zeros in a polynomial?

For a general polynomial like:

[tex]p(x) = (x - x_1)^n*(x - x_2)^m*...[/tex]

The zero x₁ has a multiplicity of n (same as the exponent in the term where the zero appears), while the zero x₂ has a multiplicity m.

Now let's go to our polynomial:

[tex]f(x) = (x - 3)^2(x + 2)^2(x - 1)[/tex]

Here we can see that the only zero with a multiplicity of 1, is x = 1, while the zero x = -2 has a multiplicity of 2.

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Answer:

first one is 1 and second is 2

Step-by-step explanation:

just got it right

The radius of a circular park is 114 yd. To the nearest yard, what is the circumference of the park?

Answers

circumference = 2 x pi x r

using 3.14 for pi

2 x3.14x114=715.92

 round to 716 yards

Answer:

The circumference of a circle is 715.92 yd.

Step-by-step explanation:

Formula

[tex]Circumference\ of\ a\ circle = 2\pi r[/tex]

Where r is the radius of a circle.

As given

The radius of a circular park is 114 yd.

[tex]\pi = 3.14[/tex]

Put in the formula

[tex]Circumference\ of\ a\ circle = 2\times 3.14\times 114[/tex]

Circumference of a circle = 715.92 yd

Therefore the circumference of a circle is 715.92 yd.



Classify the four angles of the quadrilateral.


A
B
C
D
90°
105°
75°
90°
Right , Acute, Obtuse
∠A

∠B

∠C

∠D


Answers

90 = right angle
Any angle bigger than 90 is obtuse and any angle smaller than 90 is acute

All the angles of the quadrilateral are,

⇒ ∠A = Right angle

⇒ ∠B = Obtuse angle

⇒ ∠C = Acute angle

⇒ ∠D = Right angle

What is mean by Angle?

An angle is a combination of two rays (half-lines) with a common endpoint. The latter is known as the vertex of the angle and the rays as the sides, sometimes as the legs and sometimes the arms of the angle.

Now, We know that;

Any angle which is greater than 90° is called obtuse angle and less than 90° is called acute angle and 90° is called Right angle.

Here, The four angles of the quadrilateral are,

⇒ ∠A = 90°

⇒ ∠B = 105°

⇒ ∠C = 75°

⇒ ∠D = 90°

Hence, We get;

⇒ ∠A = Right angle

⇒ ∠B = Obtuse angle

⇒ ∠C = Acute angle

⇒ ∠D = Right angle

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What are two numbers whose sum is 11 and whose product is -60?

Answers

Step 1:
Enumerate pairs of numbers whose product is 60
(1,60)
(2,30)
(3,20)
(4,15)
(5,12)
(6,10)
(10,6)
...
2. identify the pair whose components have a difference of 11.
(4,15)
3. attach a negative sign to the smaller component so that the sum is +11.
(-4,15)

Answer: the numbers are -4 and 15.

You are hiking on a trail that leads to the top of a mountain. At 12 P.M. you reach an elevation of 3700 feet. At 4 P.M. you reach an elevation of 4500 feet. What is your mean hourly change in elevation?

Answers

average rate=(change in height)/(change in time)

r=(4500-3700)/(4+12-12)

r=800/4

r=200 ft/hr

200 feet per hour.

Answer: 200 ft per hour

Step-by-step explanation:

Given : You are hiking on a trail that leads to the top of a mountain.

At 12 P.M. you reach an elevation of 3700 feet. At 4 P.M. you reach an elevation of 4500 feet.

The formula for the mean hourly change in elevation is :-

[tex]\dfrac{\text{Change in elevation}}{\text{Time in hours}}[/tex]

From the given information, the change in elevation=4500 ft-3700 ft= 800 ft

Time taken = 4 hours   [From 12 pm to 4 pm]

Now, Mean hourly change in elevation=[tex]\dfrac{800}{4}=200[/tex]

Hence, the mean hourly change in elevation = 200 ft

Suppose that it costs ​$25 to place a classified advertisement in the​ newspaper, plus ​$4 for each line. Then the cost to place an ad x lines long is given by y​ dollars, where y= 4x + 25.

express as an ordered pair the fact that a 14 line cost $81. _

Express as an ordered pair the fact that an ad costing $37 is 3 lines long. _

Answers

Hello.

We have a function y = f(x), that associates for each value of x a value in y. We represent this in a ordered pair (x, y). In this exercise, we have the price in function of the number of lines, so, the first element of the pair is the number of lines and the following is the price.

Therefore, for 14 lines and $81, we have x = 14 and y = 81 and the pair is:

(14, 81)


b) The cost is the value in y, so, we have y = 37 and x = 3. The pair is:

(3, 37)
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