José's lack of pain is likely due to the release of endorphins, which are natural pain relievers produced by the body during intense physical activity.
José's lack of pain after a long and bruising football game is most likely due to the release of endorphins. Endorphins are neurotransmitters produced by the central nervous system and the pituitary gland. Known as the body's natural pain relievers, they are released in response to stress or discomfort to inhibit the transmission of pain signals in the brain and produce a feeling of euphoria.
This phenomenon is often referred to as a 'runner's high' and can occur during and after intense physical activity.
A 50-kg box is placed in the bed of a truck. the coefficient of static friction between the box and the truck bed is 0.54. if the truck is traveling at 100 km/h then calculate the minimum distance the truck can stop in without the box sliding into the cab.
The minimum distance the truck can stop in without the box sliding into the cab is equal to 77m.
What is the equation of motion?The equations of motion can represent the relation between the initial and final velocity, acceleration, displacement, and time of a moving object.
The equations of motions are usually represented as shown below:
[tex]v = u +at\\S = ut +\frac{1}{2}at^2\\v^2 -u^2 = 2aS[/tex]
Given, the final velocity of the truck, v = 100 Km/h
The third equation of motion: v²- u² = 2ad
v² - 0 = 2 × a × d
a = v²/2d
The coefficient of static friction between the box and the truck = 0.54
We know that, F = ma = [tex]\mu_{s}m g[/tex]
[tex]a = \mu_{s} g[/tex]
[tex]{\displaystyle \frac{v^2}{2d} = \mu_s g[/tex]
(100)²/2d = 0.54 × 9.8
d = 73 m
Therefore, the minimum distance the truck can stop is equal to 73m.
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A dog in an open field runs 11.0m east and then 30.0 m in a direction 55.0 west of north
In what direction must the dog run to end up 10.0m south of her original starting point?
The direction of the resultant displacement of the dog is determined as 58.2⁰.
How to calculate the direction of the resultant displacement?
The direction of the resultant displacement of the dog is calculated by applying the following formula as shown below.
The sum of the x - component of the displacement;
Dx = 11 m - 30 m x cos(55)
Dx = - 6.21 m
If the dog must end the run 10 m south of her original starting point, then the resultant displacement in y - direction is 10 m.
Dy = - 10 m
The direction of the resultant displacement of the dog is;
tan θ = Dy / Dx
tan θ = -10 / -6.21
tan θ = 1.61
θ = arc tan (1.61)
θ = 58.2⁰
Calculate the pressure of an enclosed fluid on which a force of 150 N is exerted over an area of 10 cm2. give the answer in pascals.
The pressure of an enclosed fluid on which force is applied is 150 N over an area of 10 cm² will be 1500 N/m² or 1500 Pa.
What is Pressure?In the physical sciences, pressure is defined as the perpendicular force per unit area or the stress at a particular location within a confined fluid The force divided by the area over which it is exerted, or one-half pound per square inch, determines the pressure that a 42-pound box with an 84-square-inch bottom will impose on a surface.
Atmospheric pressure, which at sea level is roughly 15 pounds per square inch, is the amount of weight that the atmosphere exerts on each unit area of the Earth's surface. One pascal equals one newton per square meter when expressed in SI units, which is how pressure is calculated.
According to the question :
Pressure, P = F / A
P = 150 N
A = 10 cm² or
A = 0.1 m²
P = 150 / 0.1
P = 1500 Pa.
Hence, the Pressure on the enclosed fluid is 1500 Pa.
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On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. when max pulls on the sled with 12 n of force, directed at an angle of 15° above the ground, how much work does max do on the sled as he pulls his sister 25 m in the snow?
Answer: 290 J
Explanation:
1) Data:
i) Max's mass = 15 kg
ii) Maya in a sled's mass = 20 kg
iii) slippery snow ⇒ no friction
iv) F = 12 N
v) α = 15°
vi) d = 25 m
2) Physical principles and formula
i) The mechanical workg, W, developed by a constant force, F, that has an angle α with the displacement d, is given by the formula:
W = F × d × cos(α).
ii) The mass of Max is not relevant for the problem, nor the mass of the sled, since the fact that there is not friction, results in that the only force acting is F (12 N, α = 12°).
3) Solution:
W = 12 N × 25m × cos (15°) ≈ 290 J
Work done by Max on the sled is about 290 J.
[tex]\texttt{ }[/tex]
Further explanationLet's recall the Kinetic Energy and Work formula as follows:
[tex]\boxed {E_k = \frac{1}{2}mv^2 }[/tex]
Ek = kinetic energy ( J )
m = mass of object ( kg )
v = speed of object ( m/s )
[tex]\texttt{ }[/tex]
[tex]\boxed {W = F d}[/tex]
W = work done ( J )
F = force ( N )
d = displacement ( m )
Let us now tackle the problem!
[tex]\texttt{ }[/tex]
Given:
mass of Max = m = 15 kg
mass of Maya and sled = M = 20 kg
magnitude of force = F = 12 N
direction of force = θ = 15°
displacement = d = 25 m
Asked:
work done by Max = W = ?
Solution:
[tex]W = F_x \ d[/tex]
[tex]W = ( F \cos \theta ) d[/tex]
[tex]W = ( 12 \times \cos 15^o ) \times 25[/tex]
[tex]W \approx 290 \texttt{ J}[/tex]
[tex]\texttt{ }[/tex]
Conclusion:Work done by Max on the sled is about 290 J.
[tex]\texttt{ }[/tex]
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Answer detailsGrade: High School
Subject: Mathematics
Chapter: Energy
Ella has a mass of 56 kg, and Tyrone has a mass of 68 kg. Ella is standing at the top of a skateboard ramp that is 1.5 meters tall. Which conclusion is best supported by the given information?
If Tyrone stands at the top of the same ramp, his potential energy will be less than Ella’s.
If Tyrone stands at the top of a 1 m high ramp, his potential energy will be greater than Ella’s.
If Tyrone stands at the top of the same ramp, his potential energy will be the same as Ella’s.
If Tyrone stands at the top of a 2 m high ramp, his potential energy will be greater than Ella’s.
THE ANSWER IS D YOUR WELCOME:)
A power station delivers 510 kw of power at 12,000 v to a factory through wires of total resistance of 2.5 ω. how much less power is wasted if the electricity is delivered at 47,000 v rather than 12,000 v?
The currents (Amperes)
in the two cases are calculated as power/voltage:
510000W / 12000V = 42.5 A
510000W / 47000V = 10.85 A
And that the power wasted in the two cases is calculated as current^2
x resistance:
(42.5 A)^2 (2.5 Ohms) = 4,515.625 W
(10.85 A)^2 (2.5 Ohms) = 294.30625 W
So the amount of power saved is the difference:
4,515.625 - 294.30625 = 4221.32 Watts
This is the main reason why distribution grids aim to operate at the highest voltages possible.
If the pulley was not set so that the string was parallel to the track, what effect would this have on the acceleration of the system? what effect would this have on the normal force from the track? would this be a random or systematic error? explain your reasoning.
Final answer:
If the pulley is not set parallel to the track, it will introduce a perpendicular component of the tension force, resulting in a reduction in the acceleration of the system. The normal force from the track will also increase, opposing the motion. This would be a systematic error as it stems from a consistent deviation from the correct setup.
Explanation:
If the pulley is not set so that the string is parallel to the track, it will introduce a component of the tension force that is perpendicular to the track. This perpendicular component will result in a normal force from the track which will oppose the motion of the system. Consequently, the acceleration of the system will be reduced. This effect can be understood by breaking down the tension force into components parallel and perpendicular to the track.
When the string is not parallel to the track, let's say at an angle theta, the tension force can be resolved into two components:
1. A component parallel to the track (T_parallel = T * cos(theta))
2. A component perpendicular to the track (T_perpendicular = T * sin(theta))
The parallel component (T_parallel) is responsible for providing the force that accelerates the system. The tension force is equal to the product of mass and acceleration (T_parallel = m * a). Therefore, any decrease in the parallel component of the tension force will result in a decrease in acceleration.
The perpendicular component (T_perpendicular) introduces a force perpendicular to the track, which is counterbalanced by the normal force from the track. As the angle theta increases, the normal force increases, opposing the motion and reducing the acceleration of the system.
This would be a systematic error because it is a consistent deviation from the correct setup. Systematic errors occur due to flaws in the experimental setup or technique. In this case, the error arises from the misalignment of the pulley and the track.
As the wavelength increases, the frequency (2 points) decreases and energy decreases. increases and energy increases. decreases and energy increases. increases and energy decreases
Answer:
I TOOK THE TEST! the answer is INCREASES AND ENERGY INCREASES!
Keeping in mind the kinetic energy of a moving vehicle, how can a driver best prepare to enter sharp curves in the roadway?
What does each letter stand for in the formula p=v x i?
. Why must the cyclist accelerate before reaching the hillock?
Short answer:
So that the cyclist does not slide back down
Long answer:
The main forces a cyclist must conquer are air resistance and gravity. Air resistance increases exponentially with speed. In the switch from cycling on a flat road to hiking a hill, the decreased speed reduces air resistance to the point where drafting other riders offers small benefit. At this point, smaller cyclists, who have finer power-to-weight ratios, will be able to break away from the peloton. Climbing skill can be improved by minimizing weight, and also by pedalling at a constantly elevated rhythm. Large cyclists can attain greater downhill speeds, but on mountainous courses smaller cyclists still have a benefit.
On the ride "spindletop" at the amusement park six flags over texas, people stood against the inner wall of a hollow vertical cylinder with radius 2.5 m. the cylinder started to rotate, and when it reached a constant rotation rate of 0.60 rev/s, the floor on which people were standing dropped about 0.5 m. the people remained pinned against the wall.
a) In this case the forces are the centrifugal force Fcp, which is directed horizontally toward the wall; the force of static friction Ff with the wall, directed upward; the normal force Fn by the wall, which is directed away the wall; the force of gravity Fg, directed downwards. Then we have that the horizontal forces are all equal in magnitude; similarly the vertical forces are also all equal in magnitude.
b) The minimum coefficient s occurs when force of gravity is equals the max friction force, that is
Fg = Ff,max
m g = s Fn
Also, the normal force has equal magnitude to the centrifugal force:
m g = s Fcp
m g = s m w^2 r
g = s w^2 r
s = g / (r w^2)
With values: g = 9.81 m/s^2; r = 2.5 m; and w = 2pi * 0.60 = 3.77 rad/s; we find
s = 9.81 / (2.5 * 3.77^2) = 0.276
The minimum value of coefficient of static friction for which the person does not slide is [tex]\boxed{0.276}[/tex].
Further Explanation:
As the cylinder start to rotate, the people standing against the wall remain stick to the wall. So if we draw the free body diagram of the person, then we can see the balanced forces acting on person's body.
Given:
The rate of rotation of the cylinder is [tex]0.60\text{ rev}/\text{s}[/tex].
The radius of the cylinder is [tex]2.50\text{ m}[/tex].
Concept:
The friction force between the person’s body and the inner surface is balanced by the gravitational firce acting on the person's body.
[tex]\boxed{f_\text{friction}=f_\tect{gravity}}[/tex] ...... (1)
The force of friction acting on the person's body is:
[tex]f_\text{friction}=\mu N[/tex]
Here, [tex]N[/tex] is the normal reaction, [tex]\mu[/tex] is coefficient of static friction.
The gravitational force acting on the person's body is:
[tex]f_\text{gravity}=mg[/tex]
Here, [tex]m[/tex] is mass of the body, and [tex]g[/tex] is the acceleration due to gravity.
Substitute [tex]\mu N[/tex] for [tex]f_\text{friction}[/tex] and [tex]mg[/tex] for [tex]f_\text{gravity}[/tex] in equation (1).
[tex]{\begin{aligned}\mu N&=mg\\\mu&=\dfrac{mg}{N}\end{aligned}[/tex]
The Normal force acting on the person's body is balanced by the centrifugal force acting on the persion due to the rotation of the cylinder.
[tex]\boxed{f_\text{normal}=f_\text{centrifugal}}[/tex] ...... (2)
The centrifugal force acting on the person's body is:
[tex]f_\text{centrifugal}=m\omega^2r[/tex]
Here, [tex]\omega[/tex] is the angular speed of the cylinder, [tex]r[/tex] is the radius of the cylinder.
Substitute [tex]m\omega^2r[/tex] for [tex]f_\text{centrifugal}[/tex] in equation (2).
[tex]N=m\omega^2r[/tex]
Substitute the value of [tex]N[/tex] in equation of static friction coefficient.
[tex]\begin{aligned}\mu&=\dfrac{mg}{m\omega^2r}\\&=\dfrac{g}{\omega^2r}\end{aligned}[/tex]
The acceleration due to gravity on the surface of Earth is [tex]9.81\text{ m}/\text{s}^2[/tex].
The angular speed of rotation of the cylinder is given as:
[tex]\begin{aligned}\omega&=2\pi\times\text{Revolutions per second}\\&=2\pi\times0.6\\&=3.77\text{ rad}/\text{s}\end{aligned}[/tex]
Substitute the values of [tex]\omega[/tex], [tex]g[/tex] and [tex]r[/tex] in above expression.
[tex]\begin{aligned}\mu&=\dfrac{9.81}{(3.77)^2\times2.5}\\&=\dfrac{9.81}{35.53}\\&=0.276\end{aligned}[/tex]
Thus, the minimum value of coefficient of static friction for which the person does not slide is [tex]\boxed{0.276}[/tex].
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Answer Details:
Grade: Senior school
Subject: Physics
Chapter: Circular motion
Keywords:
Amusement park, ride, spindle top, six flags, texas, vertical cylinder, hollow, 2.5m, 0.60 rev/s, dropped about, minimum static friction coefficient, rotation rate 0.60.
"recall that the speed of sound in water is 1507 meters/second (4944 feet/second). if a sonar sounding had a total travel time of 5 seconds, what is the water depth?"
When the ground gets warm, it emits an invisible type of light called infrared light. This light can travel into the atmosphere and heat the air that it encounters.
What type of heat transfer is described above
Answer:
Radiation
Explanation:
Infrared radiation, that portion of the electromagnetic spectrum that extends from the long wavelength, or red, end of the visible-light range to the microwave range. ... Most of the radiation emitted by a moderately heated surface is infrared; it forms a continuous spectrum.
A wire with a resistance of 5.3 ω is drawn out through a die so that its new length is 4 times its original length. find the resistance of the longer wire, assuming that the resistivity and density of the material are unchanged.
Two objects exert a gravitational force of 3 N on one another when they are 10 m apart. What would that force be if the distance between the two objects were reduced to 5 m?
A. 1.5 N
B. 6 N
C. 12 N
D. 24 N
A ball thrown horizontally at vi = 30.0 m/s travels a horizontal distance of d = 55.0 m before hitting the ground. from what height h was the ball thrown?
Final answer:
To find the height from which the ball was thrown, we can use the equations of motion for projectile motion. The ball was thrown from a height of 44.1 meters.
Explanation:
To find the height from which the ball was thrown, we can use the equations of motion for projectile motion. Since the ball is thrown horizontally, the initial vertical velocity is 0. We can use the equation h = (1/2) g t^2, where h is the height, g is the acceleration due to gravity, and t is the total time the ball is in the air.
Using the given values, we can substitute g = 9.8 m/s^2 and t = 3 s into the equation to solve for h: h = (1/2) * 9.8 m/s^2 * (3 s)^2 = 44.1 m.
Therefore, the ball was thrown from a height of 44.1 meters.
A runner with a mass of 80kg accelerates from 0 to 9 m/s in 3 s find the net force
Calculate the acceleration if you push with a 20-N horizontal force against a 2-kg block on a horizontal friction- free air table
One part of a freely swinging magnet always points
a. east.
b. to Earth’s geographic north pole.
c. toward Earth’s core.
d. to Earth’s magnetic pole in the Northern Hemisphere.
Answer: The correct answer is (d).
Explanation:
Magnet has two poles: South pole and North pole. The same poles of the magnets repel each other. The opposite poles of the magnets attract each other.
In the absence of other magnet, a freely swinging magnet points in North-South direction. The earth has a magnetic field. The magnetic field of the bar magnet is same as the magnetic field of the earth's magnet.
The position of the earth's magnetic poles are not fixed. The south pole of the earth's magnet lies in the geographic north as it attracts the north pole of the freely swinging magnet.
If one part of a freely suspended magnet always points to Earth's magnetic pole in the Northern Hemisphere.
A wheel which is initially at rest starts to turn with a constant angular acceleration. after 4 seconds it has made 4 complete revolutions. 1) how many revolutions has it made after 8 seconds?
Which property do metalloids share with nonmetals?
Both are brittle.
Both are shiny.
Both have low melting points.
Both are very conductive.
Answer: Both are Brittle
Explanation:
Metals are lustrous, malleable and ductile. Metals are good conductors of heat and electricity.
Non-metals are poor conductors of heat and electricity. Non-metals are brittle and non-lustrous elements.
Elements which have properties between metals and non-metals are known as metalloids.
Some mettaloids are lustrous and conductors of electricity. One property that these elements share with non-metals is that these are brittle i.e. they can easily break.
The property metalloids share with nonmetals is [tex]\boxed{{\text{Both are brittle}}}[/tex].
Further explanation:
Nonmetals:
Elements that gain electrons in a chemical reaction are non-metals. They are the electronegative element that has high ionization energy. Non-metals are either gas, liquid or solid. Nonmetal oxides react with bases and form salts.
Properties of Nonmetals:
Physical State: Most non-metals exist in the form of gas and solid. The exception includes bromine that exists as liquid at room temperature.
Non-Malleable and Ductile: They are brittle and cannot be transformed into wires.
Conduction: Poor conductor of heat.
Luster: Non-metals have no metallic luster.
Melting and Boiling Point: Melting point of non-metals is lower than metals. Also, it is highly variable.
Metalloid:
An element that is a mixture of metals and nonmetals is called metalloids. The six known metalloids are boron, silicon, germanium, arsenic, antimony, and tellurium.
Properties of Metalloids:
Metalloids are metallic brittle solids.
Mostmetalloids are semiconductors and thermal conductors.
Some metalloids conduct electricity like metals.
1. Metalloids are brittle and also nonmetals are very brittle. Hence, both metalloids and nonmetals have this property. Hence option 1 is correct.
2. Metalloids can be either shiny or dull but nonmetals are dull. Hence, option 2 is incorrect.
3. Metalloids have melting points as similar to metals whereas nonmetals have melting points lower than metals. Hence, option 3 is incorrect.
4. Some metalloids conduct electricity like metals whereas nonmetal does not conduct electricity. Hence, option 4 is incorrect.
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Answer details:
Grade: High School
Subject: Chemistry
Chapter: Metals and non-metals
Keywords: metalloids, brittle, lustrous, conductors, melting point, nonmetals, low, metals, high and shiny.
If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current? note: power is defi ned as the product of voltage and current
To reduce the dissipated power by 10% while maintaining the same leakage current, the voltage needs to be reduced in such a way that the new power dissipation equals 90% of the original power, due to the direct proportionality between power and voltage in the formula P = IV.
Explanation:The question asks: If the total dissipated power is to be reduced by 10%, how much should the voltage be reduced to maintain the same leakage current? Power dissipation in an electrical circuit is described by the formula P = IV, where P is the power in watts, I is the current in amperes, and V is the voltage in volts.
To find the new voltage required to reduce the power dissipation by 10%, we first have to understand that if the leakage current remains constant, the power reduction is directly proportional to the reduction in voltage. Given the initial power Pm = 1.0 × 10³ W, reducing this power by 10% results in Pnew = 0.9Pm = 0.9 × 1.0 × 10³ W.
Since P = IV and I remains constant, the new power equation after reduction can be written as 0.9Pm = I × Vnew. Substituting the values and assuming the initial current remains unchanged, we solve for Vnew, resulting in a voltage reduction proportionate to the desired 10% power reduction.
A man starts walking north at 2 ft/s from a point p. five minutes later a woman starts walking south at 4 ft/s from a point 500 ft due east of p. at what rate are the people moving apart 15 minutes after the woman starts walking? (round your answer to two decimal places.)
To find the rate at which the man and woman are moving apart, calculate the distance each has traveled and add their speeds since they are moving in opposite directions. The man traveled 2400 ft and the woman 3600 ft in their respective times, and the rate at which they are moving apart 15 minutes after the woman starts walking is 6 ft/s.
The student's question involves determining the rate at which two people are moving apart after a certain amount of time has passed, with one walking north and the other south from different starting points. To solve this, we can use the concept of relative velocity in one dimension, as the paths of the man and the woman are perpendicular to each other.
Firstly, we calculate the distance the man has walked in 20 minutes (since he started 5 minutes before the woman). At 2 ft/s, he would have walked 2 ft/s × 1200 s = 2400 ft north of point P. The woman, having started 5 minutes later, would have walked for 15 minutes at 4 ft/s, so she would have walked 4 ft/s × 900 s = 3600 ft south of her starting point.
When calculating the rate at which they are moving apart, we need to consider the sum of their speeds as they are moving in opposite directions. The man's speed is 2 ft/s and the woman's speed is 4 ft/s, so the rate at which they are moving apart is 2 ft/s + 4 ft/s = 6 ft/s.
Classify each of these soluble solutes as a strong electrolyte, a weak electrolyte, or a nonelectrolyte. drag each item to the appropriate bin.
One of the most significant properties of water is its ability to dissolve a wide variety of substances. Solutions in which water is properly the dissolving medium are called aqueous solutions. For electrolytes, water comes by the most primary solvent.
HCl = hydrochloric acid, a strong acid. HNO₃ = nitric acid, a strong acid .NaOH = sodium hydroxide, a strong base .HF = hydrofluoric acid, a weak acid .HC₂H₃O₂ or CH₃COOH = acetic acid, a weak acid .C₂H₅OH = ethanol, a nonelectrolyte .C₆H₁₂O₆ = glucose, a nonelectrolyte .Notes:
Some acids ionize completely in water, some partially. Thus acids are not all of equal strength in terms of the production of H⁺ ions in solution. If an acid ionizes completely, it is strong acid. If we pass hydrogen chloride gas through water, almost all the molecules ionize to give H⁺ and Cl⁻ ions. Hence, HCl is a strong acid. If an acid ionizes partially, on the other hand, it is a weak acid. In the ionization of weak acids, some of the ions recombine and remain as molecules. HF is a weak acid. If we pass hydrogen fluoride gas through water, some of it will ionize to give H⁺ and F⁻. Most of the dissolved hydrogen fluoride will remain as HF molecules in water. Bases that completely ionize in water are called strong bases. The bases of alkali metals and some alkaline earth metals are strong, e.g., NaOH, KOH, and Ba(OH)₂. They conduct electricity well in an aqueous solution. Bases that dissociate in water slightly are weak bases, e.g., Mg(OH)₂ and NH₃. Water solutions of weak bases are poor conductors of electricity. Learn more About the solution as a homogeneous mixture https://brainly.com/question/637791 Calculating the pH value of weak base https://brainly.com/question/9040743 Flammability as one of the chemical properties https://brainly.com/question/1767022Keywords: classify, each of these soluble solutes, as a strong electrolyte, a weak, a nonelectrolyte. drag each item to the appropriate bin, acids, bases, dissolve, ionize, conduct electricity, water
A deli owner creates a lunch special display board by taking a uniform board which has a weight of 217 n, cutting it in half, hinging the halves together with a frictionless hinge, and setting it up as an inverted "v". determine the minimum coefficient of static friction needed between the board and the ground in order for her to set the display board up with an angle of 30° between the two sides
The minimum coefficient of static friction needed for the deli owner to set up her display board with an angle of 30° between the two sides is 0.577.
Explanation:The problem asks for the minimum coefficient of static friction needed for the board to remain stable in a 'V' position. The forces acting on the board in this scenario would be gravity, which acts downward, and the force of static friction, which acts to prevent the board from sliding. The weight of the board acts at the center of gravity, which is at the midpoint of the height of the 'V'.
We need to consider the forces acting horizontally and vertically. Vertically, the total force must be zero, so the gravitational force (weight of the board) equals twice the vertical component of the force of friction. Horizontally, the net force must be zero as well, so the two horizontal forces of friction (one on each board) must balance each other.
Using the formula for the force of friction (friction = normal force x coefficient of friction), and knowing that for each side the normal force equals half the weight of the board, we can establish an equation and solve for the coefficient of friction.
Setting up these relationships, solving for the coefficient of friction gives us a value of tan(30°), which is 0.577. Thus, the minimum coefficient of static friction needed would be 0.577 to keep the board stable at an angle of 30°.
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If you drop a silver dollar off a building and it hits the ground in 10 seconds, how fast was the coin going just before?
A system absorbs 186 kj of heat and the surroundings do 110 kj of work on the system. what is the change in internal energy of the system? express the internal energy in kilojoules to three significant figures.
Final answer:
The change in internal energy of the system is 296 kJ, calculated using the first law of thermodynamics by adding the heat absorbed by the system (186 kJ) to the work done on the system by the surroundings (110 kJ).
Explanation:
The question involves the concept of change in internal energy of a system which is a part of thermodynamics in Chemistry. To determine the change in internal energy, we use the first law of thermodynamics, which states that the change in internal energy (ΔU) of a system is equal to the heat (Q) added to the system minus the work (W) done by the system on the surroundings.
In this case, the system absorbs 186 kJ of heat and the surroundings do 110 kJ of work on the system. As work is done on the system, it is treated as positive input of energy. Therefore, the change in internal energy (ΔU) for the system can be calculated as follows:
ΔU = Q + W
ΔU = 186 kJ + 110 kJ
ΔU = 296 kJ
The change in internal energy of the system is 296 kJ, assuming all quantities are in the same units (in this case, kilojoules).
A group of students were collecting soil samples near a river. One student noted there was a lot of sand in one of the samples. He said" All this sand must have washed up from beach where the river enters the ocean." Another student said, "I think it came from the rocks in the mountains. But there aren't any mountains near us. I don't understand how the sand got there." What would you tell the students to help them solve where the sand came from?
What is the kinectic energy of 150kg object that is moving at 72 m/s
the answer it actually 388800