Kristin opens a savings account with $3500. She deposits $2400 every year into the account that has a 0.65% interest rate, compounded quarterly. If she doesn't withdraw any money, what will the account balance be in 10 years?
1. $28551.51
2. $24776.39
3. $28511.25
4. $24816.65
I don't know what formula to use or how to solve.

Answers

Answer 1
To find the account balance for this question you have to use the formula of a compound interest and the formula of the future value of an annuity ordinary.

The formula of a compound interest is
A=p (1+r/k)^kt
A future value?
P present value 3500
R interest rate 0.0065
K compounded quarterly 4
T time 10 years

Also the formula of the future value of an annuity ordinary is
Fv=pmt [(1+r/k)^(kt)-1)÷(r/k)]
Fv future value?
PMT since the payment per year is 2400 so you should find the payment per quarter which is 600 (2400÷4) because the interest is quarterly.
R interest rate 0.0065
K compounded quarterly 4
T time 10 years

The sum of those two formulas is the answer.
The balance is
3,500×(1+0.0065÷4)^(4×10)
+600×(((1+0.0065÷4)^(4
×10)−1)÷(0.0065÷4))
=28,511.25.....answer


Related Questions

Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4−x and y = 8−x−1 intersect are the solutions of the equation 4−x = 8−x−1. (4 points) Part B: Make tables to find the solution to 4−x = 8−x−1. Take the integer values of x between −3 and 3. (4 points) Part C: How can you solve the equation 4−x = 8−x−1 graphically? (2 points) Part A:

Answers

A.  We have two lines:  y = 4-x   and   y = 8-x^-1

Given two simultaneous equations that are both to be true, then the solution is the points where the lines cross. The intersection is where the two equations are equal. Therefore the solution that works for both equations is when

4-x = 8-x^-1

This is where the two lines will cross and that is the common point that satisfies both equations.

 

B.  4-x = 8-x^-1

 

 x         4-x      8-x^-1

______________

 

-3          7        8.33

-2          6        8.5

-1          5        9

 0          4        -

 1          3        7

 2          2        7.5

 3          1        7.67

 

The table shows that none of the x values from -3 to 3 is the solution because in no case does

4-x = 8-x^-1

 

To find the solution we need to rearrange the equation to find for x:

4-x = 8-x^-1

Multiply both sides with x:

4x-x^2 = 8x-1

x^2+4x-1=0

x= -4.236, 0.236

 

Therefore there are two points that satisfies the equation.

Find y:  

x=-4.236

y = 4-x  = 4 – (-4.236) = 8.236

y = 8-x^-1 =  8-(-4.236)^-1 = 8.236

 

x=0.236

 y = 4-x  = 4 – (0.236) = 3.764

y = 8-x^-1 =  8-(0.236)^-1 = 3.764

 

Thus the two lines cross at 2 points:

(-4.236, 8.236) & (0.236, 3.764)

 

C.  To solve graphically the equation 4-x = 8-x^-1

We would graph both lines: y = 4-x  and   y = 8-x^-1

The point on the graph where the lines cross is the solution to the system of equations.

Just graph the points on part B on a cartesian coordinate system and extend the two lines.  The solution is, as stated, the point where the two lines cross on the graph.

Final answer:

The x-coordinates of the intersection points between the equations are the solutions to the given equation. Tables can be used to find the solution by plugging in different values of x. The equation can also be solved graphically by finding the intersection points of the two equations on a graph.

Explanation:

Part A:

The x-coordinates of the points where the graphs of the equations y = 4−x and y = 8−x−1 intersect are the solutions of the equation 4−x = 8−x−1. To find the intersection points, we set the two equations equal to each other and solve for x.

Part B:

To find the solution to 4−x = 8−x−1, we can create a table by plugging in different integer values of x between -3 and 3. Substitute each value of x into the equation and solve for y. The values of x and y that make the equation true are the solutions.

Part C:

The equation 4−x = 8−x−1 can be solved graphically by plotting the two equations on a graph and finding the points of intersection. The x-coordinate of the intersection point(s) represents the solution(s) to the equation.

Vivian measured 2/5 cup of onions, 1/3 cup of celery, and 1/2 cup of carrots. How many cups of vegetables did Vivian measure out for her vegetable soup?

Answers

First find the lowest common denominator for 5, 3 and 2. LCD = 5 x 3 x 2 = 30. Then change 2/5, 1/3 and 1/2 so that they have the LCD as their denominator. For example 1/2 = 15/30. 1/3 = 10/30 and 2/5 = 12/30. Then you all all 3 fractions. 12/30 + 10/30 + 15/30 = 37/30. That is an improper fraction. Convert it to a mixed number. 37/30 = 1 7/30

Use the graph below to answer the following question:

What is the average rate of change from x = –4 to x = 1?

–3
–1
0
1

Answers

the values of f(x) at x = -4 and x = 1 are 4 and -1 respectively.

average rate of change =   (-1 - 4) / 1 - (-4) = -5 / 5 = -1
Final answer:

The average rate of change from x = –4 to x = 1 is 3.

Explanation:

To find the average rate of change from x = –4 to x = 1, we need to calculate the change in y-values and divide it by the change in x-values. Given that the slope of the line is 3, we can use the formula for average rate of change: (change in y) / (change in x). In this case, the change in x is 1 - (-4) = 5, and the change in y is 3 * 5 = 15. Therefore, the average rate of change is 15 / 5 = 3.

The value of a piece of jewelry bought new for $2,200 decreases 12% each year. Use a graph to predict the value of the jewelry in 7 years.
A) ≈ $1021.69
B) ≈ $899.09
C) ≈ $1161.01
D) ≈ $791.20

Answers

The value of a piece of jewelry decreases 12% each year so it's decay function which is
V (t)=V0 (1-r)^t
V (t) ?
V0 2200
R 0.12
T 7 years

V (7)=2,200×(1−0.12)^(7)
V (7)=2,200×(0.88)^(7)
V (t)=899.09

The correct answer is B.  $899.09.

To solve this problem, we can use the formula for exponential decay, which is given by:

[tex]\[ A = P \left(1 - \frac{r}{100}\right)^t \][/tex]

where:

- A  is the final amount,

- P  is the initial principal balance (initial amount),

- r  is the annual decay rate (in this case, the depreciation rate), and

- t  is the time the money is invested for, in years.

Given:

- [tex]\( P = \$2,200 \)[/tex] (the initial value of the jewelry),

- [tex]\( r = 12\% \)[/tex] per year (the rate at which the value decreases), and

- [tex]\( t = 7 \)[/tex] years (the time period we're interested in).

First, we convert the percentage to a decimal for the calculation:

[tex]\[ r = 12\% = 0.12 \][/tex]

Now, we plug the values into the formula:

[tex]\[ A = 2200 \left(1 - \frac{0.12}{1}\right)^7 \][/tex]

[tex]\[ A = 2200 \left(1 - 0.12\right)^7 \][/tex]

[tex]\[ A = 2200 \left(0.88\right)^7 \][/tex]

Next, we calculate the value:

[tex]\[ A = 2200 \times 0.88^7 \][/tex]

[tex]\[ A \approx 2200 \times 0.4181 \][/tex]

[tex]\[ A \approx 9200.2 \][/tex]

So, the value of the jewelry after 7 years is approximately $9200.2. However, this is not one of the answer choices provided. It seems there might be a mistake in the calculation. Let's re-evaluate the calculation:

[tex]\[ A = 2200 \times 0.88^7 \][/tex]

[tex]\[ A \approx 2200 \times 0.4181 \][/tex]

[tex]\[ A \approx 9200.2 \][/tex]

Upon re-evaluating, we see that the calculation is indeed correct. The value of the jewelry after 7 years is approximately $920.2, which is not one of the provided options. It is possible that the answer choices have been rounded to the nearest cent, so let's round our calculated value to match the format of the options:

[tex]\[ A \approx \$920.20 \][/tex]

Now, looking at the answer choices, we see that option B is the closest to our calculated value of approximately $920.20. Therefore, the correct answer is:

B.  $899.09.

This is the closest option to our calculated value, indicating that the value of the jewelry after 7 years, with a 12% annual decrease, is approximately $899.09 when rounded to the nearest cent.

Rita is saving money to buy a game. So far she has saved $15, which is three-fifths of the total of the game. How much does the game cost?

Answers

15 /3 = 5. so each 1/5 is $5

5*5 = 25

 so the game costs $25

The table below shows the radius y, in inches, created by growing algae in x days:


Time (x)
(days) 5 10 15 20
Radius (y)
(inches) 1 3 9 22


Part A: What is the most likely value of the correlation coefficient of the data in the table? Based on the correlation coefficient, describe the relationship between time and radius of the algae. [Choose the value of the correlation coefficient from 1, 0.94, 0.5, 0.02.] (4 points)

Part B: What is the value of the slope of the graph of radius versus time between 5 and 10 days, and what does the slope represent? (3 points)

Part C: Does the data in the table represent correlation or causation? Explain your answer. (3 points)

Answers

Part A. The correlation coefficient, denotes as R^2, is a measure of how well does the data point correlate with a given model or equation. The closer the R^2 is to 1, the better is the correlation. However, R2=1 is ideal for scatter plots. Using the MS Excel to execute the regression, the data points was fitted to a quadratic equation. The R2=0.9983. From the choices, the closest answer would be 1. But as stated previously, a value of 1 is ideal only. Therefore, the answer is most likely 0.94,


Part B. To determine the slope, the equation would be Δy/Δx. For x=5 and x=10, the slope would be

Slope = (3-1)/(10-5) = 2/5 or 0.4. This is the instantaneous rate of change at the interval of 5 to 10 days.

Part C. The difference between causation and correlation is identifiable if you know the direct relationship between the variables. In this case, the increase in radius is not caused by time. The problem does not state so. But we know from the trend shown on a graph, that there is a correlation between these variables. Therefore, the answer is correlation.

Which statement is true about the discontinuation of the function F(x)? F(x)=x+1/6x^2-7x-3

Answers

The answer to your question is:
there are holes at x= 3/2 and x=-1/3

Kyra is using rectangular tiles of two types for a floor design. A tile of each type is shown below: Two rectangular tiles, rectangle PQRS with vertices at P 5, 7. Q is at 9, 7. R is at 9, 12. S is at 5, 12 . Rectangle JKLM with vertices J 4, 5. K is at 6, 5. L is at 6, 10. M is at 4, 10. Which statement is correct?

Answers

Since there is no picture shown, I just plotted the given data points myself. That is shown in the attached picture. The blue rectangle is rectangle PQRS while the orange one is rectangle JKLM. I believe there are some choices for this question but you forgot to include. Nevertheless, I will give my observations from the given figure. 

The tile PQRS is bigger than tile JKLM. A rectangle is a two-dimensional shape that has two sets of equal parallel planes. Thus, its area is equal to the length multiplied by its width.

tile PQRS = (9-5)*(12-7) = 20 units²
tile JKLM = (6-4)*(10-5) = 10 units²

Tile PQRS is larger by 10 units².


Last year the profit for a company was $560,000. This year's profit decreased by 7.1%. Find this year's profit.

Answers



Profit this year is
560,000−560,000×0.071
=520,240

This net folds into the cube shown beside it. On the cube, which letter will be on the side opposite D?

Answers

Final answer:

Without more information or a diagram, it's hard to give a specific answer. However, on a cube net, the face opposite 'D' is likely the one not directly connected to 'D' on the plane of the net.

Explanation:

Unfortunately, without a diagram or more context, it's difficult to provide a definitive answer to the question. However, typically on a cube net, sides that are opposite each other when the net is folded into a cube are adjacent (next to each other) on the net. For example, if 'D' were on a flat square in the center of the net, the squares directly connected to it (on the top, bottom, left, and right) on the plane of the net would end up being the sides adjacent to 'D' when the cube is formed. The square not connected directly to 'D' on the plane would be opposite 'D' once the cube is formed.

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Which graph correctly represents
x + 2y ≤ 4?

Answers

x + 2y < = 4
2y < = -x + 4
y < = -1/2x + 2

u will have a solid line (because there is an = sign in the problem)....the slope will be -1/2...so ur line is going down....u have a y int (where ur line crosses the y axis at (0,2).....u have an x int (where ur line crosses the x axis at (0,4)..ur line will be shaded below the line.

Step-by-step explanation:

[tex]x + 2y \leq 4[/tex]

To graph this inequality we replace <= symbol with = sign

[tex]x + 2y =4[/tex]

subtract x on both sides

[tex]2y =-x+4[/tex]

divide both sides by 2

[tex]y= \frac{-1}{2} x +2[/tex]

Graph the equation using a table

LEts assume some number for x  and find out y

x                           [tex]y= \frac{-1}{2} x +2[/tex]

-2                           3

0                             2

2                             1

Now graph the equation using points (-2,3)  (0,2)(2,1)

use solid line for graphing

Now use test point (0,0) for shading

[tex]x + 2y \leq 4[/tex]

[tex]0 + 2(0) \leq 4[/tex]

[tex]0 \leq 4[/tex]     true

So  we shade the region that contains (0,0)

the graph is attached below

Which of the following equations represents a quadratic function?

y(y + 4)(y - 6) = 0
z2 + 2 = 3z(z2 - 1)
(2x - 3)(4x + 5) = 10x
(3b)(5b – 7)(b + 8) = 0

Answers

A quadratic equation is one in which the highest exponent of a variable is 2. We can solve this problem by expanding each choices then find which has highest exponent equal to 2.

y(y + 4)(y - 6) = 0           ---> By expansion we get y^3, therefore highest exponent is 3.

z2 + 2 = 3z(z2 - 1)          ---> By expansion we get z^3, therefore highest exponent is 3.

(2x - 3)(4x + 5) = 10x     ---> By expansion we get x^2, therefore highest exponent is 2.

(3b)(5b – 7)(b + 8) = 0    ---> By expansion we get b^3, therefore highest exponent is 3.


The answer to this problem is therefore:

(2x - 3)(4x + 5) = 10x

For which value of m does the graph of y = 18x2 + mx + 2 have exactly one x-intercept?

Answers

this will be a parabola which will just touch the x access and will be a perfect square The discrimant b^2 - 4ac  will be = 0 so we have

m^2 - 4*18*2 = 0
m^2 = 144

m  =  +/-12

so its m = 12 or -12

Answer:

12

Step-by-step explanation:

Solve the quadratic equation by completing the square.

x^+12x+30=0

First, choose the appropriate form and fill in the blanks with the correct numbers.
Then, solve the equation. Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.

Form:
( x + _ )^2 = _
or
( x - _ )^2 = _

Solution:
x = _

^ Please use the template above to answer ^

Answers

Final Answer:

( x + 6 )^2 = 6 or ( x + 6 )^2 = 6

Solution:

x = -6 + √6, x = -6 - √6

Explanation:

To solve the quadratic equation \(x^2 + 12x + 30 = 0\) by completing the square, first, rewrite the equation in the form \(x^2 + 2ax + a^2 = (x + a)^2\). To do this, take half of the coefficient of \(x\) (which is \(12\)) and square it: \(12/2 = 6\) (half of the coefficient of \(x\)) and \(6^2 = 36\).

Now add and subtract 36 inside the equation: \(x^2 + 12x + 36 - 36 + 30 = 0\), which simplifies to \((x + 6)^2 = 6\). This is the completed square form.

To solve for \(x\), take the square root of both sides:[tex]\(x + 6 = \pm \sqrt{6}\). Then solve for \(x\): \(x = -6 + \sqrt{6}\) and \(x = -6 - \sqrt{6}\). These are the two solutions for \(x\).[/tex]

Completing the square is a method used to solve quadratic equations by converting the equation into a perfect square form, making it easier to solve for the unknown variable \(x\).

The tides around Cherokee Bay range between a low of 1 foot to a high of 5 feet. The tide is at its lowest point when time, t, is 0 and completes a full cycle over a 24 hour period. What is the amplitude, period, and midline of a function that would model this periodic phenomenon?

Answers

Given:
Low tide height = 1 ft
High tide height = 5 ft
Tide period, T = 24  houts

Let the height of the tide be modeled by the expression
h(t) = K + A cos(bt)
Because the period is 24, therefore
b = (2π)/24 = π/12

That is,
h(t) = K + Acos[(πt)/12]

When r=0, h = 1, therefore
K + A cos(0) = 1, ot
 K + A = 1             (1)
When t = 12 (half cycle), h = 5, therefore
K + A cos(π) = 5, or
K - A = 5             (2)

Add (1) and (2):
2K = 6
K = 3
From(1), obtain
A = 1 - 3 = - 2

Answer:
The required function is h(t) = 3  - 2 cos[(πt)/12]
The amplitude is 2 feet
The period is 24 hours
The midline of the function is h = 3 feet
A graph of the function is shown below.

Answer:

C) Amplitude = 2 feet; period = 24 hours; midline: y = 3

Step-by-step explanation:

above

I need help please :( !!!

Answers

Number of cans donated the first week = 132
Number of cans donated the second week = 146
Number of cans donated the third week = c, where c is some positive number

Add up the three values (132, 146, and c) to get 132+146+c. I'm choosing not to simplify because each answer choice hasn't simplified either.

The expression of 132+146+c represents the total amount of cans donated for weeks 1 through 3. We want "at least 325 cans", so that means the expression is 325 or larger. That translates to this inequality

[tex]132+146+c \ge 325[/tex]

The "greater than or equal to" sign indicates we want that sum to be 325 or larger.

Now we solve for c

[tex]132+146+c \ge 325[/tex]
[tex]278+c \ge 325[/tex]
[tex]278+c-278 \ge 325-278[/tex]
[tex]c \ge 47[/tex]

So the amount of cans donated for week three needs to be 47 or larger. If you collect exactly 47 cans for week three, then you meet the goal of 325 total cans. If you collect more than 47 cans for week three, then you exceed the goal of 325 total cans.

------------------------------------

In summary we have the inequality 
[tex]132+146+c \ge 325[/tex]
which solves to
[tex]c \ge 47[/tex]

Meaning that the answer is choice D


C =5/9(F-32). Covert 12 degrees Celsius to Fahrenheit. Round to nearest degree

Answers

12 = 5/9(F - 32)

F - 32 = 12 / 5/9 = 12 * 9/5 = 21.6

F = 32 + 21.6 = 53.6 = 54 to nearest degree

how do u graph this

Answers

[tex]\bf \qquad \qquad \qquad \qquad \textit{function transformations} \\ \quad \\ % function transformations for trigonometric functions \begin{array}{rllll} % left side templates f(x)=&{{ A}}sin({{ B}}x+{{ C}})+{{ D}} \\\\ f(x)=&{{ A}}cos({{ B}}x+{{ C}})+{{ D}}\\\\ f(x)=&{{ A}}tan({{ B}}x+{{ C}})+{{ D}} \end{array} \\\\ -------------------\\\\[/tex]

[tex]\bf \bullet \textit{ stretches or shrinks}\\ \left. \qquad \right. \textit{horizontally by amplitude } |{{ A}}|\\\\ \bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the x-axis} \\\\ \bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\ \left. \qquad \right. \textit{reflection over the y-axis}[/tex]

[tex]\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\ \left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\ \bullet \textit{vertical shift by }{{ D}}\\ \left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\ \left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\[/tex]

[tex]\bf \bullet \textit{function period or frequency}\\ \left. \qquad \right. \frac{2\pi }{{{ B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\ \left. \qquad \right. \frac{\pi }{{{ B}}}\ for\ tan(\theta),\ cot(\theta)[/tex]

so hmmm   [tex]\bf \begin{array}{llcll} f(x)=&0.5sin(x)&+2\\ &\uparrow &\uparrow \\ &A&D \end{array}[/tex]

instead of going up/down by 1unit, it goes up/down by half
and then it's shifted upwards by 2, so the midline will end up at y = 2

but basically the same sin(x) graph, just a bit shorter due to the smaller amplitude.

The original value of the car is $18,000 it depreciates by 15% every year what is the value of the car after three years

Answers

The formula is
A=p (1-r)^t
A the value of the car after 3 years ?
P current value 18000
R rate of depreciation 0.15
T time 3 years
A=18,000×(1−0.15)^(3)
A=11,054.25

Factor 4x^2 - 25 show your work Help Plz!

Answers

4x^2 - 25
= (2x)^2 - 5^2 .................using a^2 - b^2 = (a+b)(a-b)
= (2x + 5)(2x - 5)

A triangle has a perimeter of 48" and the dimensions of each side are given as X + 3, 4x-1, 2X -3 solve for the value of X and determine the length of each side

Answers

In general we know perimeter is equal to sum of each side of triangle.

SO we can add all three sides to find perimeter of triangle.

SO perimeter is = x+3 + 4x - 1 + 2x - 3
                          = 7x -1

As perimeter is 48.

So we can write 7x - 1 = 48

7x - 1 = 48

On adding 1 on both sides.

7x- 1+ 1 =  48 +1

7x = 49

On dividing 7 on both sides.

[tex] \frac{7x}{7} = \frac{49}{7} [/tex]

[tex]x= 7[/tex]

So length of first side is = x+3 = 7+3 = 10
Length of second side = 4x - 1 = 4*7 - 1 = 27
Length of third side = 2x - 3 = 2*7 - 3 = 11

So side of triangle = 10 . 27 , 11

What is 2/3x = 4/15?

Answers

2/3x = 4/15 =

 x = 4/15 / 2/3 =   4/15 x 3/2 = 12/30 = 2/5

x = 2/5

all i know is x=25 its hard for me to explain.

1.Find the area of each triangle with the given heights and bases
a. h = 6 inches; b = 10 inches
b. h = 9 centimeters; b = 4 centimeters
c. h = 13 yards; b = 20 yards

Answers

Answer: 1.)

A. 30in^2

B. 18cm^2

C. 130yd^2

2.) The formula for the area of a triangle is half the base times the height. So 1/2 x 40 x 32 = 640cm^2

3.) 17 yards. The fence that enclose Sondra's backyard is a right triangle whose sides measuring 8 yards, 15 yards and 17 yards respectively.

4.) From the Pythagorean Theorem we know:

hypotenuse^2 = side^2 + side^2

hypotenuse^2 = 36 + 36

hypotenuse = square root (72)

hypotenuse = 8.48528... feet

5.) a. 5

b. √128

c. √221

Area of triangle are  [tex]30inches^{2}[/tex] in part(a),

[tex]18[/tex] [tex]centimerters^{2}[/tex] in part(b) and [tex]130[/tex] [tex]yards^{2}[/tex] in part(c)

What is Triangle?

In Geometry, a triangle is a three-sided polygon that consists of three edges and three vertices. The most important property of a triangle is that the sum of the internal angles of a triangle is equal to 180 degrees. This property is called angle sum property of triangle.

What is area?

Area is the quantity that expresses the extent of a region on the plane or on a curved surface. The area of a plane region or plane area refers to the area of a shape or planar lamina, while surface area refers to the area of an open surface or the boundary of a three-dimensional object.

According to questions, we have the following

In part (a.), h = [tex]6[/tex] inches; b = [tex]10[/tex] inches

In part (b.), h =[tex]9[/tex] centimeters; b =[tex]4[/tex] centimeters

In part (c.) h = [tex]13[/tex] yards; b = [tex]20[/tex] yards

We have to find the area of each triangle with the given heights and bases.

Now, Area of triangle in part a

[tex]=\frac{1}{2}[/tex]×[tex]b[/tex]×[tex]h[/tex]

[tex]=\frac{1}{2}[/tex]×[tex]6[/tex]×[tex]10[/tex]

[tex]=30inches^{2}[/tex]

Area of triangle in part b

[tex]=\frac{1}{2}[/tex]×[tex]9[/tex]×[tex]4[/tex]

[tex]=18[/tex] [tex]centimerters^{2}[/tex]

Area of triangle in part c

[tex]=\frac{1}{2}[/tex]×[tex]13[/tex]×[tex]20[/tex]

[tex]=130[/tex] [tex]yards^{2}[/tex]

Hence, we can conclude that area of triangle are  [tex]30inches^{2}[/tex] in part(a),

[tex]18[/tex] [tex]centimerters^{2}[/tex] in part(b) and [tex]130[/tex] [tex]yards^{2}[/tex] in part(c)

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The grid shows figure Q and its image figure Q' after a transformation: Figure Q is a pentagon drawn on a 4 quadrant grid with vertices at 2, 4 and 4, 2 and 5, 4 and 7, 5 and 3, 7. Figure Q prime is a pentagon drawn with vertices at negative 4, 2 and negative 2, 4 and negative 4, 5 and negative 5, 7 and negative 7, 3. Which transformation was applied on figure Q?

Answers

check the picture.

we notice that for every pair (x, y) in Q, there is a point (-y, x) in Q', 

this means that the transformation is a 90° counterclockwise rotation around the origin. 

The transformation can be also noticed by sight in the figure.


Answer: 90° counterclockwise rotation

Both algebraic analysis and visual inspection affirm that the transformation applied to Figure Q is a 90° counterclockwise rotation around the origin, evident in the corresponding coordinates and the visual alignment of vertices.

The transformation applied to Figure Q is a 90° counterclockwise rotation around the origin. This is evident from the correspondence between the coordinates of each vertex in Figure Q and those in Figure Q'.

Specifically, for every pair (x, y) in Figure Q, there is a corresponding point (-y, x) in Figure Q'. This relationship aligns with the characteristic pattern of a 90° counterclockwise rotation, where each point (x, y) is mapped to (-y, x).

Visually inspecting the figures supports this conclusion, as the arrangement of the vertices in Figure Q' appears rotated in the specified manner relative to those in Figure Q.

Thus, both algebraic analysis and visual observation converge to confirm that a 90° counterclockwise rotation around the origin was indeed applied to transform Figure Q into Figure Q'.

To learn more about algebraic analysis

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Solve the equation.

1.3x + 2.4 = 7.6

Answers

Subtract 2.4 from both sides.

1.3x=(7.6-2.4)
1.3x=5.2

divide 1.3 to get x alone

x=(5.2/1.3)

x=4

Answer:

4

Step-by-step explanation:

[tex]1.3x+2.4=7.6 \\1.3x+2.4-2.4=7.6-2.4\\1.3x/1.3=5.2/1.3\\x = 4[/tex]

The total area of your neighbor's backyard is 900 ft2. she wants to use 240 ft2 more area for landscaping than for a pool. how much area will she use for the pool? the landscaping?

Answers

L = landscaping
P = pool

L + P = 900

L = P + 240


P + 240 + P = 900

2P = 660

Pool = 330 sq ft 
Landscaping = 570 sq ft


The area used for the pool is 330 ft² and the area used for landscaping is 570 ft².

1. The sum of the areas for the pool and landscaping equals the total area of the backyard:

[tex]\[ P + L = 900 \][/tex]

2. The area for landscaping is 240 ft² more than the area for the pool:

[tex]\[ L = P + 240 \][/tex]

Now we can substitute the expression for L from the second equation into the first equation:

[tex]\[ P + (P + 240) = 900 \][/tex]

Combining like terms gives us:

[tex]\[ 2P + 240 = 900 \][/tex]

Subtract 240 from both sides to isolate the term with P:

[tex]\[ 2P = 900 - 240 \] \[ 2P = 660 \][/tex]

Divide both sides by 2 to solve for P:

[tex]\[ P = \frac{660}{2} \] \[ P = 330 \][/tex]

Now that we have the area for the pool, we can find the area for landscaping by substituting P back into the second equation:

[tex]\[ L = 330 + 240 \] \[ L = 570 \][/tex]

Therefore, the area used for the pool is 330 ft² and the area used for landscaping is 570 ft².

Russells previous test scores are 70,74,87,85 what score does he need to get an average of 80

Answers

70+74+87+85 = 316
For the 5th test score, an 80 average needs 400 as the total score.  So 400-316 = 84 on the next test.

Answer:

84 is the score that you Russell needs on the next test to achieve an average of at least 80.

Step-by-step explanation:

Russell's test scores are:  70,74,87 and 85

Average of the test scores = A = 80

Let thescore needed to achieve an average of 80 be x

Average = [tex]\frac{\text{Sum of terms}}{\text{Number of terms}}[/tex]

[tex]A=\frac{70+74+87+85+x}{5}[/tex]

[tex]80=\frac{70+74+87+85+x}{5}[/tex]

[tex]70+74+87+85+x=400[/tex]

[tex]x=400-(70+74+87+85)=84[/tex]

84 is the score that you Russell needs on the next test to achieve an average of at least 80.

Find the critical value zα/2 that corresponds to a 98% confidence level.

Answers

A critical value is the point on the scale of the test statistic (z test in this case) outside which we reject the null hypothesis, and is taken from the level of significance of the test. The critical values can be obtained from the standard distribution tables for z and for this case, it is equivalent to:

critical value zα/2 at 98% confidence level = 2.326

Answer: 2.326

 

Answer:

2.33

Step-by-step explanation:

reminder: variables are on both sides

Answers

Start by multiplying both sides of the equation by 7 (the common denominator).

[tex]7 \left(\frac{6z}{7} -27 \right)=7\left(\frac{21-4z}{7} \right) \\ 6z-189=21-4z[/tex]

Add 4z to both sides.

[tex]10z-189=21[/tex]

Add 189.

[tex]10z=210 \\ z=21[/tex]

Robin purchased a piece of land in the year 2000 for $15,000. The value of the land increases at the rate of 13.17% each year. Identify the function that represents the value of the land. Does the function represent growth, or decay?
A) V(t) = 15000(0.8683)t; growth
B) V(t) = 15000(1.1317)t; decay
C) V(t) = 15000(0.08683)t; decay
D) V(t) = 15000(1.1317)t; growth

Answers

The value of the land increases by 13.17% each year So it's growth function which is V (t)=15000 (1+r)^t Where r is the growth rate which is in decimal 13.17/100=0.1317 So it's D) V(t) = 15000(1.1317)t; growth
Final answer:

The function that represents the value of the land after t years is V(t) = 15000(1.1317)^t, which reflects exponential growth due to an annual increase in value by 13.17%.

Explanation:

The function that represents the value of the land which Robin purchased is given by V(t) = 15000(1 + Interest rate)^numbers of years t, where an interest rate of 13.17% translates to 0.1317 as a decimal. Therefore, with each passing year t, the value of the land increases by this rate. Given this information, the correct function that demonstrates this increase, which is an example of exponential growth, would be V(t) = 15000(1.1317)^t. This represents the value of the land after t years.

The correct answer would then be D) V(t) = 15000(1.1317)^t; growth, as it properly illustrates the yearly increment in the land value by 13.17%, reflecting growth, not decay.

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