Liquids can take the shape of their container but their atoms cannot move away from each enough to always fill the container true false

According to Charles's law, the volume of a given amount of gas is directly proportional to its temperature in Kelvin when the pressure is held constant. In this case, the final volume of the methane gas can be calculated using the formula V2 = V1 * (T2 / T1) where V1 is the initial volume, T1 is the initial temperature in Kelvin, T2 is the final temperature in Kelvin, and V2 is the final volume.

According to Charles's law, the volume of a given amount of gas is directly proportional to its temperature in Kelvin when the pressure is held constant. This means that as the temperature of the methane gas increases from 25°C to 88°C, its volume also increases. To find the final volume, you can use the formula:

V2 = V1 * (T2 / T1)

Where V1 is the initial volume (36.4 L), T1 is the initial temperature in Kelvin (25°C + 273.15), T2 is the final temperature in Kelvin (88°C + 273.15), and V2 is the final volume.

Plugging in the values:

V2 = 36.4 L * (361.15 K / 298.15 K)

Calculating, the final volume of the gas is approximately 43.88 L.

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The balanced chemical reaction for rusting of iron is [tex]\boxed{{\text{4Fe}}\left(s\right)+3{{\text{O}}_2}\left(g\right)\to2{\text{F}}{{\text{e}}_2}{{\text{O}}_{\text{3}}}\left(s\right)}[/tex] .

Further explanation:

The chemical reaction that contains an equal number of atoms of the different elements in the reactant as well as in the product side is known as a balanced chemical reaction. The chemical equation is required to be balanced to follow the Law of the conservation of mass.

Rusting of iron occurs when impure iron comes in contact with water, oxygen, and other oxidants. The extent of rusting increases in seawater due to the presence of salt in it. Rust consists of hydrated iron oxides and iron oxide-hydroxides.

The steps to balance a chemical reaction are as follows:

Step 1: Complete the reaction and write the unbalanced symbol equation.

In the rusting reaction, Fe reacts with [tex]{{\text{O}}_2}[/tex] to form [tex]{\text{F}}{{\text{e}}_2}{{\text{O}}_{\text{3}}}[/tex] . The physical state of Fe is solid, [tex]{{\text{O}}_2}[/tex]  is gas, [tex]{\text{F}}{{\text{e}}_2}{{\text{O}}_{\text{3}}}[/tex] is solid. The unbalanced chemical equation is as follows:

[tex]{\text{Fe}}\left(s\right)+{{\text{O}}_2}\left(g\right)\to{\text{F}}{{\text{e}}_2}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

Step 2: Then we write the number of atoms of all the different elements that are present in a chemical reaction in the reactant side and product side separately.

⦁ On reactant side,

Number of iron atoms is 1.

Number of oxygen atoms is 2.

⦁ On product side,

Number of iron atoms is 2.

Number of oxygen atoms is 3.

Step 3: Initially, we try to balance the number of other atoms of elements except for carbon, oxygen, and hydrogen by multiplying with some number on any side. To balance the number of iron atoms, multiply Fe by 2. Now the reaction is,

[tex]\boxed{\text{2}}{\text{Fe}}\left(s\right)+{{\text{O}}_2}\left(g\right)\to{\text{F}}{{\text{e}}_2}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

Step 4: After this, we balance the number of atoms of carbon and then hydrogen atom followed by oxygen atoms. To balance the number of oxygen atoms, multiply  [tex]{{\text{O}}_{\text{2}}}[/tex] by 3, Fe by 2 and [tex]{\text{F}}{{\text{e}}_{\text{2}}}{{\text{O}}_{\text{3}}}[/tex]  by 2. Now the reaction is,

[tex]\boxed{\text{4}}{\text{Fe}}\left(s\right)+\boxed3{{\text{O}}_2}\left(g\right)\to\boxed2{\text{F}}{{\text{e}}_2}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

Step 5: So the balanced chemical equation is given as follows:

[tex]{\text{4Fe}}\left(s\right)+3{{\text{O}}_2}\left(g\right)\to2{\text{F}}{{\text{e}}_2}{{\text{O}}_{\text{3}}}\left(s\right)[/tex]

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Answer details:

Grade: High School

Subject: Chemistry

Chapter: Chemical reaction and equation

Keywords: balanced chemical reaction, rusting of iron, Fe, O2, Fe2O3, solid, gas, 2, 3, 4, iron atoms, oxygen atoms, reactant side, product side, 4 Fe, 3 O2, 2 Fe2O3.

The balanced chemical equation for the reaction between the iron and oxygen to produce iron (iii) oxide is:

Chemical equation is a representation of chemical reaction with symbols and formula of the reactants and products taking part in the reaction.

All chemical equation must be balanced in order to validate the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

NOTE: An unbalanced equation simply means matter has been created or destroyed.

The equation for the reaction between iron and oxygen to produce iron (iii) oxide is given below:

Fe(s) + O₂(g) —> Fe₂O₃(s)

The above equation can be balance as follow:

Fe(s) + O₂(g) —> Fe₂O₃(s)

There are 2 atoms of O on the left side and 3 atoms on the right side. It can be balance by writing 3 before O₂ and 2 before Fe₂O₃ as shown below:

Fe(s) + 3O₂(g) —> 2Fe₂O₃(s)

There are 4 atoms of Fe on the right side and 1 atom on the left side. It can be balance by writing 4 before Fe as shown below:

4Fe(s) + 3O₂(g) —> 2Fe₂O₃(s)

Therefore, the balanced equation for the reaction between iron and oxygen to produce iron (iii) oxide is

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By applying Hess's law, we can calculate the unknown standard enthalpy of formation for AgI(s) using the given standard enthalpy of reaction, and the standard enthalpies of formation for the other reactants and products.

In order to determine the value of ΔHf° for AgI(s), we need to use Hess's law which states that the total enthalpy change in a chemical reaction is independent of the pathway over which the reaction takes place. The formula is as follows: ΔHrxn = Σ ΔHf°(products) - Σ ΔHf°(reactants).

Given: ΔHrxn = -54.0 kJ, ΔHf° for AgBr(s) = -100.4 kJ/mol, and ΔHf° for Br2(g) = +30.9 kJ/mol. Making AgI(s) the subject of the formula, we find ΔHf° for AgI(s) =  Σ ΔHf°(products) - ΔHrxn, which upon substituting the values gives us the answer.

This method which employs Hess's law, enthalpy of formation, and the known quantities to provide the unknown standard enthalpy of formation for AgI(s) is representative of typical approaches in thermochemistry.

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The enthalpy of formation for AgI(s) is calculated using Hess's Law with the known enthalpies of formation for AgBr(s) and Br₂(g). Applying the enthalpy change for the reaction, the ΔH°f for AgI(s) is found to be -15.5 kJ/mol.

To determine the enthalpy of formation (ΔH°f") of AgI(s) for the reaction AgI(s) + Br₂(g) → AgBr(s) + I₂(s) using Hess's Law:

Answer:

Although the story of Beowulf is set in Scandinavia what language was it written in Old English.

Explanation:

Beowulf is a very old piece of literary genre. It is one of the earliest European epic written in vernacular language. It is an epic poem written in old English. The setting of the story has been set in Scandinavia. Beowulf is the hero of the poem. He is the protagonist of the story who survives the attacks of the monster named Grendel.

Answer:

OLD ENGLISH

Explanation:

what language "Beowulf" was written in originally. The first manuscript was written in the language of the Saxons, "Old English," also known as "Anglo-Saxon." Since then, the epic poem has been estimated to have been translated into 65 languages

Final answer:

To neutralize 0.220 g of NaOH with 0.130 M H2SO4, you would need approximately 21.2 mL of the sulfuric acid solution.

Explanation:

To determine how many milliliters of 0.130 M H2SO4 are needed to neutralize 0.220 g of NaOH, follow these steps:

Calculate the moles of NaOH by using its molar mass (Molar mass of NaOH = 40.00 g/mol):

0.220 g NaOH × (1 mol NaOH / 40.00 g NaOH) = 0.0055 mol NaOH

Write the balanced chemical equation for the neutralization reaction:

H2SO4 (aq) + 2NaOH(aq) → Na2SO4 (aq) + 2H2O(l)

Calculate the moles of H2SO4 needed using the stoichiometry of the reaction:

0.0055 mol NaOH × (1 mol H2SO4 / 2 mol NaOH) = 0.00275 mol H2SO4

Calculate the volume of H2SO4 needed by rearranging the molarity equation (Molarity = moles / volume in liters):

Volume of H2SO4 = 0.00275 mol H2SO4 ÷ 0.130 mol/L

Volume of H2SO4 = 0.0212 L

Convert the volume from liters to milliliters:

0.0212 L × 1000 mL/L = 21.2 mL

Therefore, approximately 21.2 mL of the 0.130 M H2SO4 solution is needed to neutralize the given amount of NaOH.

The standard formation reaction of solid calcium hydroxide can be represented by the balanced chemical equation: CaO(s) + H2O(l) → Ca(OH)2(s).

The standard formation reaction of solid calcium hydroxide can be represented by the balanced chemical equation:

CaO(s) + H2O(l) → Ca(OH)2(s)

In this reaction, solid calcium oxide (CaO) reacts with liquid water (H2O) to produce solid calcium hydroxide (Ca(OH)2) as the only product.

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Solid calcium hydroxide is formed from the reaction of solid calcium oxide with liquid water, following the balanced chemical equation: CaO(s) + H₂O(l) → Ca(OH)₂ (s). The primary reactant, calcium oxide, can be readily obtained from the decomposition of calcium carbonate.

A balanced chemical equation for the standard formation reaction of solid calcium hydroxide can be derived from the reaction of solid calcium oxide with liquid water. The reaction can be represented as follows:

CaO(s) + H₂O(l) → Ca(OH)₂ (s)

 In this equation, solid Calcium Oxide (CaO) reacts with liquid water (H₂O) to form solid Calcium Hydroxide (Ca(OH)₂). Solid calcium oxides can be obtained from the decomposition of CaCO3 where the reaction is represented as CaCO3(s) → CaO(s)+CO2(g). By allowing the CO₂ to escape, we can achieve a 100% yield of CaO. This CaO then reacts with water to yield calcium hydroxide.

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Sucrose is insoluble in dichloromethane solution because the hydrogen bonds in sucrose are much more polar than the dipole-dipole interactions in dichloromethane.

Sucrose is an organic compound which is a disaccharide which is made up of glucose and fructose subunits. It has hydrogen bonds which are responsible for binding in the molecule. Dichloromethane is an organochlorine compound which is colorless and volatile in nature. Dichloromethane is insoluble in water because of the absence of hydrogen bonding.

Sucrose has hydrogen bonding which is much more polar than the dipole-dipole interactions which are present in the dichloromethane molecule. Thus, sucrose does not dissolve in dichloromethane solution.

Solubility of a substance is affected by four main factors which include temperature, pressure, polarity, and molecular interactions. Solubility of a substance increases with temperature for most of the solids which are dissolved in liquid water. This is because of the higher temperature which increases the kinetic energy of the solute molecules.

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A compound that consist of two elements in which elements are chemically combined in a fixed proportion.

Compounds:

They are made up of two or more than two elements when combine in a fixed ratio. One compound from all sources have same same constituent ratio.

Example:

In Water or [tex]\rm \bold{H_2O}[/tex] , ratio of Hydrogen and Oxygen is 2:1. If this ratio will change to 2:2 this become Hydrogen peroxide [tex]\rm \bold{H_2O_2}[/tex].

Water gives you life but  Hydrogen peroxide can kill you if you consume it.

Hence, we can conclude that a compound that consist of two elements in which elements are chemically combined in a fixed proportion.

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23.7 g of Ca₃(PO₄)₎₂ contains 9.20 x 10^22 ions of PO₄³⁻  

23.7 g of Ca₃(PO₄)₎₂ contains 0.1528 moles of PO₄³⁻ which is equivalent to 9.20 x 10^22 ions of PO₄³⁻

Therefore;

Ca₃(PO₄)₎₂ ionizes to give out 3 Ca²⁺ ions and 2 PO₄³⁻ ions

Ca₃(PO₄)₎₂ → 3Ca²⁺ + 2PO₄³⁻

Required to determine the number of ions of PO₄³⁻ ions

Number of moles = Mass /Molar mass

Molar mass of Ca₃(PO₄)₎₂ = 310.1767 g/mol

Thus;

Moles = 23.7 g/310.1767 g/mol

          = 0.0764 moles

1 mole of  Ca₃(PO₄)₎₂ ionizes to give 2 moles PO₄³⁻ ions

Therefore;

0.0764 moles will produce;

 = 0.0764 moles x 2

 = 0.0152 moles PO₄³⁻ ions

1 mole of PO₄³⁻ ions contains 6.022 x 10^23 ions

Therefore;

0.01528 moles PO₄³⁻ ions contains;

= 0.01528 x 6.022 x 10^23 ions

= 9.20 x 10^22 ions

Keywords: Atoms, ions, Moles, molar mass

Level: High school

Subject: Chemistry

Topic: Moles

Sub-topic: Avogadro's constant

Option 3, 23/11Na and 23/11Na+, have the most nearly identical atomic and molecular properties.

The pair of species with the most nearly identical atomic and molecular properties is option 3, 23/11Na and 23/11Na+.

Three examples of liquid substances with large dipole-dipole attractions are water (H₂O), due to hydrogen bonding, hydrogen chloride (HCl), and acetonitrile (CH₃CN), both of which have significant differences in electronegativity between their respective atoms leading to strong dipole-dipole attractions.

Examples of Liquid Substances with Strong Dipole-Dipole Attractions

Dipole-dipole attractions occur when the positive end of a dipole molecule is attracted to the negative end of another. Substances with large dipole moments will exhibit stronger dipole-dipole attractions in the liquid state. Here are three examples of such substances:

Water (H₂O): Water molecules are polar, with a significant dipole moment due to the electronegativity difference between hydrogen and oxygen atoms. This leads to strong hydrogen bonding, a type of dipole-dipole interaction.

Hydrogen chloride (HCl): In the liquid state, HCl molecules exhibit strong dipole-dipole attractions due to the electronegativity difference between hydrogen and chlorine atoms.

Acetonitrile (CH₃CN): This substance has a relatively high dipole moment and consequently strong dipole-dipole attractions because of the polarity of the carbon-nitrogen triple bond.

These examples demonstrate how the characteristics of molecular structure directly affect the intermolecular forces present in a substance. Larger dipole moments yield stronger dipole-dipole attractions, affecting properties like boiling points and solubility.

Answer: D. A person pushing a couch without being able to move it.

Explanation:

The reason why is because static friction is where it prevents surfaces from sliding past each other, the static friction strength changes to match the applied force. If someone was to increase their force the static friction would still prevent the object from moving....

as in what the person above me said that goes towards sliding friction because if you were trying to push something with static friction if you have more than one person applying force then you would be able to move the object but with only having one the static friction would be greater then the applied force.

The subatomic particle with no charge is a neutron. Ions have a net charge because they have gained or lost electrons, and electrons themselves are negatively charged. The whole atom can be charged or neutral.

The subatomic particle that possesses no electrical charge is called a neutron. This is different from ions, which are atoms or molecules that have gained or lost one or more electrons, and thus have a net electrical charge. Electrons are subatomic particles that have a negative charge. Neutrons, along with protons, make up the atom's nucleus, or core. The atom itself is composed of a central nucleus surrounded by a cloud of electrons. However, the atom as a whole can be charged (an ion) or neutral, depending on whether it has equal numbers of electrons and protons.

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Explain how this was solved please

Thermometers are filled with alcohol instead for water because of the lower freezing point.

Thermometer is an instrument which is used to measure the temperature of any substance which is present in liquid state.

In most of the thermometers mercury is used as it shows high fluctuations and small change will also measurable. We did not use water in the thermometers as they have normal freezing point as 0 degree celsius, but we will use alcohols in the thermometers as they have low freezing point than water as of -114 degree celsius.

And for this reason we will use thermometers filled with alcohol in all places under cold season also.

Hence due to lower freezing point we will use.

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This plasma is most likely influenced by magnetic and electric fields. The massive positively charged ions which are influenced the lighter electrons than replace the ions to keep charge impartiality.

Therefore electric field influence the plasma. The movement of charged particles identical to a magnetic field line is not influenced. Plasma contains charged particles which are positive nuclei and negative electrons which can be molded and restricted by magnetic forces.

Alike iron filings in the closeness of a magnet, bits in the plasma will ensue magnetic field lines.

Answer is C)magnetic and electric fields.

Chemical reactions create simpler or more complex products from reactants and gives off energy. The statement (A), (B), and (C) are correct for the chemical reactions.

A Chemical Reaction is a process that takes place in which two or more reactants interact with each other to produce a new product.

In a chemical reaction, a chemical change takes place and is generally noticed with physical changes such as precipitation,  heat production, color change, etc.

In the combination reaction, two simple elements combine to produce a compound. For example, sodium chloride is formed from sodium and chlorine gas.

In the decomposition reaction of Calcium carbonate dissociates into calcium oxide and carbon oxide. In the combusion reaction, heat is released.

But in the chemical reaction of atoms of one element can never be cahnged into another element.

Therefore, all statements are correct except option D.

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The mass of sucrose in 1.55 L of a 0.758 M sucrose solution can be found by first determining the moles of sucrose present and then converting those moles to grams using the molar mass of sucrose. The calculation yields approximately 401.93 grams of sucrose in the solution.

The student is asking about the mass of sucrose in a specific volume of a sucrose solution with a given molarity. To find the number of grams of sucrose in a 1.55 L solution of 0.758 M sucrose, we first need to calculate the moles of sucrose present in the solution using the molarity (mol/L) and the volume of the solution (L). After calculating the number of moles of sucrose, we can then find the mass in grams using the molar mass of sucrose (C12H22O11), which is 342.30 g/mol.

This result provides the mass of sucrose in the given volume of the solution.