In the first 120 miles over 240 mile journey a truck driver maintained an average speed of 50 mph what was his average featuring the next 120 miles if the average speed of the entire trip with 60 mph
What is the third step when factoring the trinomial ax^2+bx+c, after you have factored out a common factor in each term?
a.) Add the linear terms together
b.)Multiply the factors together to check
c.)Factor the simplified trinomial
d.) Distribute the common factor
After factored out a common factor in each term. Factor the simplified trinomial. Option c) is correct.
Step after the the third step when factoring the trinomial ax^2+bx+c to be determine.
Factors is are the sub multiples of the value.
Here,
After factored out a common factor in each term. The next step come is to factor the simplified term which implies taking common and kept in parenthesis.
Thus, after factored out a common factor in each term. Factor the simplified trinomial.
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What is greater: a half dozen dozen pair of shirts or a half of two dozen dozen shirts
From the computation, a half of two dozen shirts will be greater.
A dozen = 12
It should be noted that a half dozen pair of shirts will be:
= 1/2 × 12
= 6 shirts
A half of two dozen shirts will be:
= 1/2 × (2 × 12)
= 12 shirts
Therefore, a half of two dozen shirts will be greater.
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If 2^m = 4x and 2^w = 8x, what is m in terms of w?
Two consecutive odd integers have a sum of 44 . Find the integers.
If 5x=17, what is the value of 15x-11
5x=17
x=17/5 = 3.4
15x-11 =
15(3.4)-11 = 51-11 = 40
Definition 7.1.1 laplace transform let f be a function defined for t ≥ 0. then the integral {f(t)} = ∞ e−stf(t) dt 0 is said to be the laplace transform of f, provided that the integral converges. to find {f(t)}. f(t) = cos t, 0 ≤ t < π 0, t ≥ π
Divide and state the quotient in simplest form.
The altitude of a triangle is increasing at a rate of 1 cm/ min while the area of the triangle is increasing at a rate of 2 cm2 / min. at what rate is the base of the triangle changing when the altitude is 10 cm and the area is 100 cm2 ?
The rate of change of the base of a triangle, given an increase of the altitude at 1 cm/min and an increase in area at 2 cm2/min, when the altitude is 10 cm and the area is 100 cm2, is 4 cm/min.
Explanation:The subject of this question is related to the field of calculus, specifically dealing with determining the rate of change, or the derivative, of a function. We're asked to determine the rate at which the base of the triangle is changing when the altitude is 10 cm and the area is 100 cm2, given that the altitude of the triangle is increasing at a rate of 1 cm/ min and the area of the triangle is increasing at a rate of 2 cm2 / min.
We know that the area of a triangle is given by the formula 1/2 * base * height. When it comes to rates, we can differentiate this with respect to time t to get dA/dt = 1/2 * (base * dh/dt + height * db/dt) where dA/dt is the rate of change of the area, dh/dt is the rate of change of the height, and db/dt is the rate of change of the base.
Given that dA/dt = 2 cm2/min and dh/dt = 1 cm/min, and we are finding db/dt when the height is 10 cm and the area is 100 cm2, we substitute these values to solve for db/dt. This simplifies to find that the base is increasing at a rate of 4 cm/min.
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F(x,y)=eâ8xâx2+8yây2. find and classify all critical points of the function. if there are more blanks than critical points, leave the remaining entries blank.
To find and classify critical points of a two-variable function, calculate and set the first partial derivatives to zero to find critical points. Then, use the second derivatives to classify these points. The determinant of the Hessian matrix, made up of the second derivatives, contributes to this classification.
Explanation:To find the critical points of the function F(x,y)=e^8x - x^2 + 8y - y^2, you first need to find the partial derivatives F_x and F_y and set them both equal to zero.
F_x = 8e^8x - 2x and F_y = 8 - 2y. By setting these equal to zero and solving for x and y, you will find the critical points.
Once the critical points are found, we classify them using the second derivative test. This involves computing the second partial derivatives F_xx, F_yy, and F_xy, and evaluating them at the critical points.
Finally, we calculate the determinant D of the Hessian matrix, composed of the second derivatives, at the critical points. The signs and values of these results and the determinants help classifying the critical points.
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A music company executive must decide the order in which to present 6 selections on a compact disk. how many choices does she have
help which statement is true
If f(x) = 3/x+2 - √x-3, complete the following statement (round to the nearest hundredth) f(7)= PLEASE HELP ME
The value of given function f(7) is -1.8.
What is a function?A function is defined as a relation between a set of inputs having one output each. In simple words, a function is a relationship between inputs where each input is related to exactly one output. Every function has a domain and codomain or range.
According to the given problem,
f(x) = [tex]\frac{3}{x + 5}- \sqrt{x - 3}[/tex]
At x = 7,
⇒ f(7) = [tex]\frac{3}{7 + 5} - \sqrt{7-3}[/tex]
⇒ f(7) = [tex]\frac{1}{4} - 2[/tex]
⇒ f(7) = [tex]-\frac{7}{4}[/tex]
⇒ f(7) = - 1.75
≈ -1.8
Hence, we can conclude, the value of function f(7) is -1.8.
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A ship traveled at an average rate of 22 miles per hour going east. It then traveled at an average rate of 17 miles per hour heading north. If the ship traveled a total of 212 miles in 11 hours, how many miles were traveled heading east?
The house shown is a composite of more than one shape. Which of these methods would you use to find the volume of the house?
The method that can be used to find the volume of the house is:
Add the volume of a rectangular prism to the volume of the triangular prism.
Step-by-step explanation:In order to find the volume of the house we need to find the volume of the bottom part of the house which in the shape of a rectangular prism or cuboid and volume of the top of the house which is in the shape of a triangular prism.
Hence, the total volume of the house is:
Volume of rectangular prism+Volume of triangular prism.
Jane is going to walk once around the edge of a rectangular park. The park is 300 yards long and 200 feet wide. How far will Jane walk?
Jane will walk 733.34 yards around the edge of the rectangular park after converting the width from feet to yards and calculating the perimeter.
Jane is going to walk once around the edge of a rectangular park. The park is 300 yards long and 200 feet wide. To determine how far Jane will walk, we need to calculate the perimeter of the rectangle. First, let's convert all measurements to the same unit. Since the length is given in yards and the width in feet, we can convert the width to yards (1 yard = 3 feet).
Width in yards: 200 feet \/ 3 feet per yard = 66.67 yards.
Now that both measurements are in yards, we can calculate the perimeter:
Perimeter = 2 ×(length + width) = 2 × (300 yards + 66.67 yards) = 2 ×366.67 yards = 733.34 yards.
Therefore, Jane will walk 733.34 yards around the edge of the park.
The average winter snowfall in City A is 105 cm. City B usually gets 2.8 m of snow each winter. Compare the yearly snowfall in the two cities. Complete parts a and b. (A) the difference in one year is __ m. (B) the difference over two years is ___ cm
solve for m
2m = -6n -5; n = 1, 2 ,3
if log75=1.875
then what is the value of log (sub 100) 75?
Answer: The required value of [tex]\log_{100}75[/tex] is 0.9375.
Step-by-step Explanation: Given that [tex]\log 75=1.875.[/tex]
We are to find the value of the following logarithm :
[tex]log_{100}75.[/tex]
We will be using the following properties of logarithm :
[tex](i)~\log_ba=\dfrac{\log a}{\log b}\\\\\\(ii)~\log a^b=b\log a.[/tex]
Therefore, we have
[tex]\log_{100}75\\\\\\=\dfrac{\log 75}{\log100}\\\\\\=\dfrac{1.875}{\log10^2}\\\\\\=\dfrac{1.875}{2\times\log10}\\\\\\=\dfrac{1.875}{2}~~~~~~~~~~~[since~\log10=1]\\\\\\=0.9375.[/tex]
Thus, the required value of [tex]\log_{100}75[/tex] is 0.9375.
is the graph of y=sin(x^6) increasing or decreasing when x=12
The price of an item has been reduced by 15% . The original price was $51 .
The question is about calculating the new price of an item after a discount. The original price of the item was $51.00, and it was reduced by 15%, making the new price $43.35.
Explanation:The subject of this question is Mathematics and it is looking for a solution to a percentage price reduction problem. The item had an original price of $51.00 and its price has been reduced by 15%. To find the new price after the discount, we have to calculate the amount of the reduction and subtract it from the original price.
First, let's calculate the amount of the discount: 15/100 * 51 = $7.65.}
Now, we subtract this amount from the original price: 51 - 7.65 = $43.35.
Therefore, the new price of the item after a 15% discount is $43.35.
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What expression is equivalent to 10x2y+25x2
Effective rate (APY) is: Never related to compound table Interest for one year divided by annual rate Interest for one year divided by principal for 2 years Interest for one year divided by principal None of these
The widrh of a rectangle is w yards and the length of a rectangle is (6w-4) yards. The perimeter of the rectangle is given by the algebraic expression 2w+2(6w-4). Simplify the algebraic expression 2w+2(6w-4) and determine the perimeter of a rectangle whose width w is 4 yards
p=2w+2(6w-4) can be simplified to:
p=2w+12w-8
p=14w-8
if w=4
p=14(4)-8
p=56-8 = 48 yards
check:
w = 4
length = 6w-4= 6(4)-4 = 24-4=20
perimeter = 4*2 + 20*2 = 8+40 = 48
it checks out, perimeter = 48 yards
The Center of the Circle is at the origin on a coordinate grid. The vertex of a Parabola that opens upward is at (0,9). If the Circle intersects the parabola at the parabola's vertex, which Statement must be true?
The parabola and the circle have the same axis of symmetry, and can intersect at one point only.
The statement that must be true is; The maximum number of solution is one
Reason:
The given parameters are;
Location of the center of the circle = The origin (0, 0)
Location of the vertex of the parabola opening upwards = (0, 9)
Point where the circle intersects the parabola = The vertex
Required:
The statement that must be true
Solution;
The equation of the circle is x² + y² = r²
The vertex (0, 9) is a point on the circle, therefore;
0² + 9² = r²
The radius, r = 9
The highest point on the circle is the point with the maximum vertical
distance from the center, which is the point (0, 9), which is also the lowest
point on the parabola.
Therefore, the parabola and the circle can intersect at only the point (0, 9),
which gives;
The maximum number of solution is one.
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Theo started to solve the quadratic equation (x + 2)2 – 9 = –5. He added 9 to both sides and the resulting equation was (x + 2)2 = 4. Next, he took the square root of each side. Which was the resulting equation of that step?
we have
[tex](x + 2)^{2}-9=-5[/tex]
Adds [tex]9[/tex] both sides
[tex](x + 2)^{2}-9+9=-5+9[/tex]
[tex](x + 2)^{2}=4[/tex]
square root both sides
[tex](x+2)=(+/-)\sqrt{4}\\(x+2)=(+/-)2\\x1=2-2=0 \\x2=-2-2=-4[/tex]
therefore
the answer is
the resulting equation is [tex](x+2)=(+/-)2[/tex]
Answer: [tex](x+2) = \pm 2[/tex]
Step-by-step explanation:
If the given expression is,
[tex](x + 2)^2 - 9 = -5[/tex]
For solving this expression, By adding 9 on both sides,
[tex](x+2)^2 = 4 [/tex]
By taking square root on both sides,
[tex]\sqrt{(x+2)^2} = \sqrt{4}[/tex]
[tex]({(x+2)^2)^{\frac{1}{2} = \pm 2[/tex] [tex]( \text{ Because, }\sqrt{4} = \pm 2 \text { and }\sqrt{x} = x^{\frac{1}{2}})[/tex]
[tex]{(x+2)^{2\times \frac{1}{2} = \pm2[/tex] [tex]((a^m)^n=a^{m\times n})[/tex]
[tex](x + 2) = \pm2[/tex]
Which is the required next step.
What is the standard form of 8 hundreds + 2 hundreds
The standard form of 8 hundred + 2 hundred will be 1000.
What is the standard form of the number?A number can be expressed in a fashion that adheres to specific standards by using its standard form. Standard form refers to any number that may be expressed as a decimal number between 1.0 and 10.0 when multiplied by a power of 10.
Given that the number is 8 hundred + 2 hundred the standard form of the number will be:-
Standard form = 8 hundreds + 2 hundreds
Standard form = 800 + 200
Standard form = 1000
Therefore, the standard form of 8 hundred + 2 hundred will be 1000.
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A package contains 3 cups of trail mix. A serving of trail mix is ⅓ cup. How many servings of trail mix is in the package?
Derek and Mia place two green marbles and one yellow marble in a bag. Somebody picks a marble out of the bag without looking and records its color (G for green and Y for yellow). They replace the marble and then pick another marble. If the two marbles picked have the same color, Derek loses 1 point and Mia gains 1 point. If they are different colors, Mia loses 1 point and Derek gains 1 point. What is the expected value of the points for Derek and Mia?
Answer:
Thus, the expected value of points for Derek and Mia are [tex]\dfrac{-1}{9}[/tex] and [tex]\dfrac{1}{9}[/tex] respectively.
Step-by-step explanation:
Number of green marbles = 2 and Number of Yellow marbles = 1
Then, total number of marbles = 2+1 = 3
A person selects two marbles one after another after replacing them.
So, the probabilities of selecting different combinations of colors are,
[tex]1.\ P(GG)=P(G)\times P(G)\\\\P(GG)=\dfrac{2}{3}\times \dfrac{2}{3}\\\\P(GG)=\dfrac{4}{9}[/tex]
[tex]2.\ P(GY)=P(G)\times P(Y)\\\\P(GY)=\dfrac{2}{3}\times \dfrac{1}{3}\\\\P(GY)=\dfrac{2}{9}[/tex]
[tex]3.\ P(YG)=P(Y)\times P(G)\\\\P(YG)=\dfrac{1}{3}\times \dfrac{2}{3}\\\\P(YG)=\dfrac{2}{9}[/tex]
[tex]4.\ P(YY)=P(Y)\times P(Y)\\\\P(YY)=\dfrac{1}{3}\times \dfrac{1}{3}\\\\P(YY)=\dfrac{1}{9}[/tex]
Now, we have that,
If two marbles are of same color, then Mia gains 1 point and Derek loses 1 point.
If two marbles are of different color, then Derek gains 1 point and Mia loses 1 point.
Also, the expected value of a random variable X is [tex]E(X)=\sum_{i=1}^{n} x_i\times P(x_i)[/tex].Then, the expected value of points for Derek is,
[tex]E(D)= (-1)\times \dfrac{4}{9}+1\times \dfrac{2}{9}+1\times \dfrac{2}{9}+(-1)\times \dfrac{1}{9}\\\\E(D)= \dfrac{-5}{9}+\dfrac{4}{9}\\\\E(D)=\dfrac{-1}{9}[/tex]
And the expected value of points for Mia is,
[tex]E(M)= 1\times \dfrac{4}{9}+(-1)\times \dfrac{2}{9}+(-1)\times \dfrac{2}{9}+1\times \dfrac{1}{9}\\\\E(M)= \dfrac{5}{9}-\dfrac{4}{9}\\\\E(M)=\dfrac{1}{9}[/tex].
Thus, the expected value of points for Derek and Mia are [tex]\dfrac{-1}{9}[/tex] and [tex]\dfrac{1}{9}[/tex] respectively.
Answer: P(GG)= 4/9
P(GY)= 2/9
P(YG)= 2/9
P(YY)= 1/9
Derek, E(X) = -1/9
Mia, E(X) = 1/9
Step-by-step explanation: just did it on edge
Ruby is visiting a wildlfe center to gather information for he paper . The center has circular pond with a diameter if 20. What is the approximate area of the pond ?
area = PI x r^2
r = 20/2 = 10
3.14 x 10^2 = 314 square units