Match the pairs of equations that represent concentric circles. Tiles

Answer:To find the image of B, first find the scale factor for the dilation. The scale factor should be greater than 1 because the image of A is farther from the origin than A. Divide the coordinates of the image of A by the coordinates of A: –6/–4 = 3/2 and 9/6 = 3/2, so the scale factor is 3/2. Now, apply the dilation to B by multiplying the coordinates by 3/2 to get ((3/2)(1), (3/2)(4)), or (3/2, 6).

Hope I helped

Answer: I’m just adding this to verify that the other answer was correct

Each side of [tex]49^{3x} = 343^{2x + 1}[/tex], expressed in terms of their bases, is: [tex]7^{2(3x)} = 7^{3(2x + 1)}\\\\[/tex].

To solve an equation, the bases can be made equivalent and cancelled out by creating exponents.

Given:

[tex]49^{3x} = 343^{2x + 1}[/tex]

First, express each side by simplifying their bases and make them equivalent. Let the base be 7.

Thus:

[tex]7^{2(3x)} = 7^{3(2x + 1)}\\\\[/tex]

To solve, cancel the bases to have, 2(3x) = 3(2x + 1) and solve for x.

Therefore, each side of [tex]49^{3x} = 343^{2x + 1}[/tex], expressed in terms of their bases, is: [tex]7^{2(3x)} = 7^{3(2x + 1)}\\\\[/tex].

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Answer: 7 then B on edge

Step-by-step explanation:

Answer: it’s

Step-by-step explanation:

The value of m in the equation [tex]13m +3 -56m = -15[/tex] is [tex]\frac{18}{43}[/tex]

Given: [tex]13m +3 -56m = -15[/tex]

To find: value of m

To find the value of m we need to move all the terms containing variables on LHS and the constants on RHS. This can be done as follows:

[tex]13m +3 -56m = -15\\13m -56m =-15-3\\[/tex]

Now we can solve for m as follows:

[tex]13m-56m =-15-3\\-43m = -18\\[/tex]

The negative sign on both LHS and RHS will cancel out and it will give us:

[tex]m = \frac{18}{43}[/tex]

Since 18 and 43 do not have any common multiples so the fraction cant be simplified further. So, [tex]m = \frac{18}{43}[/tex]

area of painting = 13 * 17 = 221 square inches

221 * 0.30 = 66.30

 the price would be $66.30

Question 1:

14 - 6 = ?

To determine the difference between 14 and 6 is the same is 14 – 6. In other words, the different is the result we get if we subtract both values.

Therefore, the difference between 14 and 6 is 8.

14 – 6

= 8.

There is always three parts in any subtraction equation and these include:

Question 2:

10 - ? = ?

The given question means you should for a number that when being subtracted from 10 will give the same number.  

Therefore, to solve the question, let the missing be X

10 – X = X

If you simplify the equation, then you should have:

10 = X + X

10 = 2X (divide both side by 2)

[tex]\frac{10}{2}[/tex] = [tex]\frac{2x}{2}[/tex]

5 = X

X = 5

Therefore, the answer for question 1 and 2 are 8 and 5 respectively

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Answer:

The factored form of [tex]4a^3b^5-16a^5b^2+12a^2b^3[/tex] is [tex]4a^2b^2\left(ab^3-4a^3+3b\right)[/tex].

Step-by-step explanation:

To find the factored form of [tex]4a^3b^5-16a^5b^2+12a^2b^3[/tex] you must:

Apply exponent rule: [tex]a^{b+c}=a^ba^c[/tex]

[tex]a^2b^3=a^2b^2b,\:a^5b^2=a^2a^3b^2,\:a^3b^5=a^2ab^2b^3[/tex]

So, we can write our expression as [tex]4a^2ab^2b^3-16a^2a^3b^2+12a^2b^2b[/tex].

Next, rewrite 12 as [tex]3\cdot \:4[/tex] and -16 as [tex]4\cdot \:4[/tex]

[tex]4a^2ab^2b^3+4\cdot \:4a^2a^3b^2+3\cdot \:4a^2b^2b[/tex]

Factor out common term: [tex]4a^2b^2[/tex]

Therefore,

[tex]4a^3b^5-16a^5b^2+12a^2b^3= 4a^2b^2\left(ab^3-4a^3+3b\right)[/tex]

Answer:

The cost would be $ 5.38.

Step-by-step explanation:

Given,

The price of 5 pounds of cheese = $ 13.45,

So, the price of 1 pounds of cheese = [tex]\frac{\text{Price of }5\text{ pounds of cheese}}{5}[/tex]

[tex]=\frac{13.45}{5}[/tex]

[tex]=\$ 2.69[/tex]

Thus, the price of 2 pounds of cheese = 2 × price of each pound of cheese

= 2 × 2.69

= $ 5.38

Answer:

Measure of angle s is 22°

Step-by-step explanation:

Given that lines a and b are parallel. Horizontal parallel lines a and b intersect with another line making 8 angles, the top right angle of line a is labeled 158° and the top left angle of line b is labeled s degrees

we have to find the measure of angle s.

As ∠1 and 158° and on straight line hence are supplementary

i.e ∠1+158°=180°

⇒ ∠1=180°-158°=22°

Also, angle s and ∠1 are alternate interior angles.

As a and b are parallel then alternate interior angles are equal.

Hence, ∠s=∠1=22°

Measure of angle s is 22°

Answer:

[tex]153.9\ cm^{2}[/tex]

Step-by-step explanation:

Hello, thanks for asking this question here at Brainly, I think I can help you with this

the area of circle is given by:

[tex]Area=\pi * radius^{2} \\[/tex]

Step one

Let

[tex]\pi =3.14\\and\\r= 7 cm[/tex]

Step two

put the values into the equation

[tex]Area=\pi * radius^{2} \\Area=3.14* (7 cm)^{2}\\ Area=3.14* 49\ cm^{2} \\Area=153.9\ cm^{2} \\[/tex]

Hence, the area of a circle with radius 7 cm is 153.9 cm2

I hope it helps,do not hesitage in asking me anything about this,  have a great day

The rates of 7 inches per 9 hours and 42 inches per 54 hours do form a proportion, as demonstrated by cross-multiplying the two ratios which resulted in equal cross products (378 inch-hours on both sides).

To determine if the two rates form a proportion, we need to compare the ratios of inches to hours for both scenarios. For the first rate, we have 7 inches in 9 hours, and for the second rate, we have 42 inches in 54 hours. A proper proportion exists when two ratios are equivalent.

Let's set up our two ratios:

Now, we will test if these ratios form a proportion by creating a fraction out of each ratio and then cross-multiplying.

(7 inches / 9 hours) = (42 inches / 54 hours)

Cross multiply:

7 inches * 54 hours = 378 inch-hours

42 inches * 9 hours = 378 inch-hours

Since the cross products are equal, the two rates indeed form a proportion.

Answer:

Three sides with the same length because that is what an equilateral triangle is.

Step-by-step explanation:

Answer:

Step-by-step explanation:

The function f(x) = 9,000(0.95)x represents the situation.

After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.

The range values, in the context of the situation, are limited to whole numbers.

The true representation of the declining bee population is f(x) = 9,000(0.95)^x, accounting for a 5% annual decrease. The function and expected number of bees after 2 years are correct if rounded to approximately 8,120. The domain and range values are limited to whole numbers in this context.

The given situation of the farmer noticing a decrease of bees in his population can be represented by a mathematical function that models the decline. This function is f(x) = 9,000(0.95)^x, which correctly represents a 5% annual decrease in the bee population.

After analyzing the situation:

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The equation of the line will be y = 4/3x + 3. The correct option is C.

An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.

The general form of the equation of the line:-

y = mx + c

m = slope

c = y-intercept

Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )

From the given graph the slope will be calculated as:-

Rise = 4

Run = 3

Slope = Rise / Run = 4 / 3

The y-intercept is 3.

The equation can be written as:-

y = mx + c

y = 4/3x + 3

Therefore, the equation of the line is y = 4/3x +3.

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The maximum value of the electric current is [tex]I_{max}=\dfrac{1}{3}[/tex]

the minimum value of the electric current is [tex]I_{min}=-\dfrac{1}{3}[/tex]

The given expression for electric current is [tex]I=\cos(\omega t)+\sqrt{8}\sin(\omega t)[/tex] where [tex]\omega \neq 0[/tex].

Differentiate the given function with respect to [tex]t[/tex]-

[tex]\dfrac{dI}{dt}=\dfrac{d(\cos(\omega t)+\sqrt 8 \sin(\omega t))}{dt}\\\dfrac{dI}{dt}=-\omega \sin(\omega t)+\sqrt 8 \omega \cos(\omega t)[/tex]

Equate the derivative to 0-

[tex]\dfrac{dI}{dt}=0\\-\omega \sin(\omega t)+\sqrt 8 \omega \cos(\omega t)=0\\\sin(\omega t)=\sqrt 8 \cos (\omega t)\\\tan (\omega t)=\sqrt 8\\\omega t=\tan^{-1}\sqrt 8\\\omega t=2n\pi-2\tan^{-1}\sqrt 2}\\or,\\\omega t=2n\pi+2\tan^{-1}\sqrt {1/2}}[/tex]

[tex]2n\pi[/tex] is the period of sine and the cosine trigonometric function.

So, the maximum value of the electric current is

[tex]I_{max}=\cos(2\tan^{-1}\sqrt {1/2})\\I_{max}=\dfrac{1}{3}[/tex]

Also, the minimum value of the electric current is

[tex]I_{min}=\cos(2\tan^{-1}\sqrt {2})\\I_{min}=-\dfrac{1}{3}[/tex]

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Answer:

(3,1)

Step-by-step explanation:

Hi, to solve this problem:

[tex]2 x + 4y = 10\\ +\\3x-4y=5\\-----\\5x =15\\x = 15/5\\x= 3[/tex]

then, replacing the value of "x" in one equation.

2x (3) + 4 y = 10

6 +4y =10

4y= 10- 6

4 y = 4

y = 4/4

y =1

So, the correct option is d.(3,1).

Feel free to ask for more if it´s necessary or if you did not understand something.