Math help please..............

Answer:

15 inches

Step-by-step explanation:

Suppose length of original square is L inches.

Now, to form a new square the length increases by 2.5 inches

So, new length=L+2.5 inches

Given that, perimeter of new square =70 inches.

Formula:-

        Perimeter=4*length of square

Therefore 70=4*(L+2.5)

                   70 =4 L+10

                   4 L=60

                  L=15 inches

Answer:

The original length of each side was 15 inches.

Step-by-step explanation:

In this case we have to have clear that the perimeter of square consists in the addition of the length of each one of its four sides, this is:

[tex]perimeter=a+a+a+a[/tex]

The new square has a perimeter of 70, and we have to find the original length of each side, the equation will be:

[tex]70=a+2.5+a+2.5+a+2.5+a+2.5[/tex]

[tex]70=4a+10[/tex]

We have to clear a:

[tex]a=\frac{70-10}{4} \\a=\frac{60}{4} \\a=15[/tex]

The original length of each side was 15 inches.

Answer:

first...you have to split the net into three rectangles and two triangles

picture inserted

Step-by-step explanation:

step 1

triangular base area

1/2 bh = 1/2 (44 in)(64 in)

= 1/2 (2,816 sq in)

= 1,408 sq in.

2 x 1,408 sq in = 2,816 sq in.

step 2

end rectangle area

lw = (68 in)(69 in)

= 4,692 sq in

2 x 4,692 sq in = 9,384 sq in

Now find the area of the middle rectangle

lw - (69 in) (44 in) = 3,039 sq in.

then add all the areas together

2,816 + 9,384 + 3,036 = 15,236 sq in

The fabric that is required to make the tent should be B. 15,236 sq in.

triangular base area

1/2 bh = 1/2 (44 in)(64 in)

= 1/2 (2,816 sq in)

= 1,408 sq in.

Now

2 (1,408 sq in) = 2,816 sq in.

Now

end rectangle area

lw = (68 in)(69 in)

= 4,692 sq in

So,

2  (4,692 sq in) = 9,384 sq in

Now determine the area of the middle rectangle

So,

lw - (69 in) (44 in) = 3,039 sq in.

So, the fabric required is

= 2,816 + 9,384 + 3,036

= 15,236 sq in

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Answer:

A and B

Step-by-step explanation:

Parallel lines are lines which have the same slope. Perpendicular lines have negative reciprocal slopes.

For the options:

A. Both equations have 7/5 as the slope. They are parallel.

B. The slopes are 1 and -1. These are perpendicular.

C. The slopes are 9/2 and are parallel.

D. The slopes are 7/3 and -3/7. They are perpendicular.

The solution is A and B.

When she adds to the original four sections by coloring three more, it represents the total colored sections.

Answer:

A. 4/8+3/8

E. 1/8+1/8+1/8+1/8+1/8+1/8+1/8

Step-by-step explanation:

Select the two correct answers:

A. 4/8+3/8

B. 4+3

C. 8/4+8/3

D. 1/8+3

E. 1/8+1/8+1/8+1/8+1/8+1/8+1/8

A rectangle is a quadrilateral with four 90-degree angles. The opposite sides are equal, with two sides being the length (10 inches) and the other two being the width (7 inches).

Ty, when painting a rectangle, it's important to understand its attributes. A rectangle is a quadrilateral, meaning it has four sides. Two of these sides will be 10 inches long, and the other two will be 7 inches high - these are referred to as the 'length' and 'width'. Additionally, all interior angles of a rectangle are 90 degrees, which is a right angle. So when you are painting, make sure each corner forms a 90-degree angle. Also, the opposite sides of a rectangle are always equal. If any of these attributes are not followed, the figure will not be a rectangle.

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The center of the circle is the x and y in the equation.

To find the center you need to solve for x and Y when the equations inside parenthesis are set to zero.

(x-6)=0

x = 6

(y+3)=0

y = -3

The center of the circle is (6,-3)

Answer:

36

Step-by-step explanation:

x^2 + 12 x = 2

In order to complete the square we need to add ( b/2)^2 to each side where b is the coefficient of the x term

b=12

12/2 = 6

6^2 = 36

We need to add 36 to each side

ANSWER

[tex]8 {cm}^{2} [/tex]

EXPLANATION

First let us determine the scale factor of the enlargement

[tex]k = \frac{image \: length}{corresponding \: object \: length} [/tex]

[tex]k = \frac{8}{1.6} [/tex]

[tex]k = 5[/tex]

This implies that that, the corresponding length of the smaller rectangle is

[tex]l = \frac{25}{5} = 5cm[/tex]

The area of the smaller rectangle is

[tex] = 5 \times 1.6 = 8 {cm}^{2} [/tex]

Answer:

3 sin(41t) - 3 sin(t)

Step-by-step explanation:

The general formula to convert the product of the form cos(a)sin(b) into sum is:

cos(a) sin(b) = 0.5 [ sin(a+b) - sin (a-b) ]

The given product is:

6 cos(21t) sin(20t) = 6 [ cos(21t) sin(20t) ]

Comparing the given product with general product mentioned above, we get:

a = 21t and b = 20t

Using these values in the formula we get:

6 cos(21t) sin(20t) = 6 x 0.5 [ sin(21t+20t) - sin(21t-20t)]

= 3 [sin(41t) - sin(t)]

= 3 sin(41t) - 3 sin(t)

Therefore, second option gives the correct answer

Answer:

c

Step-by-step explanation:

The correct option is c. $336.36. The previous day's closing price of  stock was:c. $336.36.

To determine the closing price of stock the previous day, we need to use the information provided in the table. The table shows the net change (Chg) in the stock price and the current closing price (Close). The net change is the difference between the current closing price and the previous day's closing price.

From the table:

- Current closing price (Close): $342.64

- Net change (Chg): $6.28

Since the net change represents the increase in the stock price from the previous day to the current day, we can calculate the previous day's closing price by subtracting the net change from the current closing price.

[tex]\[\text{Previous day's closing price} = \text{Current closing price} - \text{Net change}\][/tex]

[tex]\[\text{Previous day's closing price} = 342.64 - 6.28 = 336.36\][/tex]

Therefore, the previous day's closing price of stock was:

c. $336.36

Answer:

Step-by-step explanation:

Answer:

x < 61

Step-by-step explanation:

Given

x + 12 < 73

Isolate x on the left side by subtracting 12 from both sides

x < 63 ← is the solution

He could be thinking of any number between 3.1451 and 3.1459

Mean (μ) ≈ 53.84, Standard deviation (σ) ≈ 16.51.

To solve this problem, we can use the properties of the normal distribution and the given information about the percentage of students scoring certain marks.

Let's denote the mean as μ and the standard deviation as σ. We know that in a normal distribution:

1. 10% of the students score more than 75 marks.

2. 20% of the students score less than 40 marks.

To find the values of μ and σ, we'll utilize the standard normal distribution table (Z-table), which provides the cumulative probabilities for a standard normal distribution (mean = 0, standard deviation = 1). Then we'll apply the z-score formula to convert these values to the corresponding marks in our distribution.

Let [tex]\( Z_{75} \)[/tex] be the z-score corresponding to 75 marks, and [tex]\( Z_{40} \)[/tex]  be the z-score corresponding to 40 marks.

From the standard normal distribution table:

1. The z-score corresponding to the 90th percentile (10% above) is approximately [tex]\( Z_{75} = 1.28 \)[/tex] .

2. The z-score corresponding to the 20th percentile (20% below) is approximately [tex]\( Z_{40} = -0.84 \)[/tex].

The z-score formula is:

[tex]\[ Z = \frac{{X - \mu}}{\sigma} \][/tex]

where:

- [tex]\( X \)[/tex] is the raw score (marks)

- [tex]\( \mu \)[/tex] is the mean

- [tex]\( \sigma \)[/tex] is the standard deviation

Using the z-score formula, we can write two equations based on the given percentiles:

1. For 75 marks:

[tex]\[ 1.28 = \frac{{75 - \mu}}{\sigma} \][/tex]

2. For 40 marks:

[tex]\[ -0.84 = \frac{{40 - \mu}}{\sigma} \][/tex]

Now, we have two equations with two unknowns [tex](\( \mu \) and \( \sigma \))[/tex], we can solve them simultaneously to find the values of [tex]\( \mu \) and \( \sigma \)[/tex].

From equation 1:

[tex]\[ 1.28\sigma = 75 - \mu \][/tex]

[tex]\[ \mu = 75 - 1.28\sigma \][/tex]

From equation 2:

[tex]\[ -0.84\sigma = 40 - \mu \][/tex]

[tex]\[ \mu = 40 + 0.84\sigma \][/tex]

Now, equating the expressions for [tex]\( \mu \)[/tex] :

[tex]\[ 75 - 1.28\sigma = 40 + 0.84\sigma \][/tex]

Solving for [tex]\( \sigma \)[/tex] :

[tex]\[ 1.28\sigma + 0.84\sigma = 75 - 40 \][/tex]

[tex]\[ 2.12\sigma = 35 \][/tex]

[tex]\[ \sigma[/tex] ≈ [tex]\frac{35}{2.12}[/tex]

[tex]\[ \sigma[/tex] ≈ [tex]16.51[/tex]

Now that we have [tex]\( \sigma \)[/tex], we can find [tex]\( \mu \)[/tex] using one of the equations for [tex]\( \mu \)[/tex]:

[tex]\[ \mu = 75 - 1.28 \times 16.51 \][/tex]

[tex]\[ \mu[/tex] ≈ [tex]75 - 21.16[/tex]

[tex]\[ \mu \approx 53.84 \][/tex]

So, the values of [tex]\( \mu \) and \( \sigma \)[/tex] are approximately 53.84 and 16.51, respectively.

Answer:

advance tickets cost $20 each & same-day tickets cost $35 each

Step-by-step explanation:

Let cost of advanced ticket be x and cost of same-day ticket be y. Now we can write 2 equations and solve them simultaneously.

"The combined cost of one advance ticket and one same-day ticket is $55":

[tex]x+y=55[/tex]

and

"...40 advance tickets and 15 same-day tickets were sold. The total amount paid for the tickets was $1325":

[tex]40x+15y=1325[/tex]

We solve for x in the first equation to get x = 55 - y and substitute this into 2nd equation and solve for y:

[tex]40(55-y)+15y=1325\\2200-40y+15y=1325\\-25y=1325-2200\\-25y=-875\\y=\frac{-875}{-25}=35[/tex]

Now plugging in y = 35 into the first equation, we can solve for x:

[tex]x+y=55\\x+35=55\\x=55-35\\x=20[/tex]

Hence, advance tickets cost $20 each & same-day tickets cost $35 each

Answer:

Option C is correct

[tex]3x^3-4x^2-10[/tex]

Step-by-step explanation:

Like terms are those terms which have same variable to the same power.

Find the difference of the following:

[tex](3x^3-2x^2+4)-(2x^2+14)[/tex]

Remove the parenthesis we get;

[tex]3x^3-2x^2+4-2x^2-14[/tex]

Combine like terms;

[tex]3x^3-4x^2-10[/tex]

Therefore, the difference of [tex](3x^3-2x^2+4)-(2x^2+14)[/tex] is, [tex]3x^3-4x^2-10[/tex]

Answer its 5

Step-by-step explanation:

look it up theirs others with this question :)

Answer:

D. 5

Step-by-step explanation:

got it right n the test

let's recall something about a right-triangle.

it has a 90° angle, and the longest side, the hypotenuse, from the pythagorean theorem, is c² = a² + b², or namely c = √( a² + b²).

so, let's take a peek at the two smaller sides, 60 and 11, can we get the longest side from it using the pythagorean theorem?

[tex]\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=\stackrel{hypotenuse}{61}\\ a=\stackrel{adjacent}{60}\\ b=\stackrel{opposite}{11}\\ \end{cases} \\\\\\ 61=\sqrt{60^2+11^2}\implies 61=\sqrt{3600+121} \\\\\\ 61=\sqrt{3721}\implies 61=61~~\stackrel{\textit{yeap, it is}}{\checkmark}[/tex]

The given lengths of 60ft, 61ft, and 11ft can form a right triangle. This has been confirmed by applying the Pythagorean theorem, which gives equal results for both sides of the equation.

In the field of Mathematics, the formation of a right triangle with given side lengths can be verified using the Pythagorean theorem. The theorem states: If a triangle is a right triangle, then the square of the length of the hypotenuse equals the sum of the squares of the lengths of the other two sides, as represented by this formula: a² + b² = c².

Applying this theorem to your question, we can use the three lengths you've provided: 60ft, 61ft, and 11ft. Let's assign the longest length (considered as the hypotenuse in a right triangle) as 'c', which is 61ft in this case. The other sides 'a' and 'b' would be 60ft and 11ft.

Here's how the theorem fits: 60² + 11² = 61².

Calculating the squares gives us 3600 + 121 = 3721 for the left-hand side, and 3721 for the right-hand side as well. Since the results are equal, the given lengths can indeed form a right triangle according to the Pythagorean theorem.

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D is the answer............

Answer:

5/13

Step-by-step explanation:

Since the triangles are similar, the cos F = cos C

Cos C = adjacent side/ hypotenuse

Cos C = 5/13

Cos F = 5/13

Answer:

B

Step-by-step explanation:

Answer:

Option 2 -  [tex]-6x^3+x^2-\sqrt5[/tex]

Step-by-step explanation:

To find : Which algebraic expression is a polynomial?

Solution :

Polynomial is defined is the expression consisting of several terms with variable and constant.

Polynomial is always positive not a negative exponential.

Option 1 - [tex]4x^2-3x+\frac{2}{x}[/tex]

This is not a polynomial because it has a negative exponent.

Option 2 - [tex]-6x^3+x^2-\sqrt5[/tex]

This is a polynomial by definition.

Option 3 - [tex]8x^2+\sqrt x[/tex]

This is not a polynomial as  [tex]\sqrt x[/tex] is not considerable.

Option 4 - [tex]-2x^4+\frac{3}{2x}[/tex]

This is not a polynomial because it has a negative exponent.

Therefore, Option 2 is correct.

Answer:1.33

Step-by-step explanation:

Byron spent $1.38 more than Cassandra on other groceries, as we subtracted Cassandra's spending ($11.50) from Byron's ($12.88) to determine the difference.

The question asks us to determine how much more money Byron spent compared to Cassandra on their grocery shopping. To find this out, we need to compare the total amount of money each person spent. We have the cost of other groceries for each person, but the cost of yogurt is not given. To solve this problem, we just need to compare the cost of other groceries since that is the only information provided.

Byron spent $12.88 on other groceries.

Cassandra spent $11.50 on other groceries.

To find out how much more Byron spent, we subtract Cassandra's total from Byron's total:

$12.88 - $11.50 = $1.38

Therefore, Byron spent $1.38 more than Cassandra on other groceries.

Answer:

55

Step-by-step explanation:

So first of all I would convert the 20% to a decimal by dividing by 100 and you get 0.2

Then multiply 0.2 and 275 together and you get 55

If you are unsure on an answer, a way to quickcheck is setting the answer over your total

55

-------- =  0.2   ⇒  which equals 20%

275

Answer: 55

Step-by-step explanation:

First, find 10% of 275 (move the decimal place back once).

We now have 27.5.

Now, multiply 27.5 by 2 because we are finding 20%

So, 27.5 x 2= 55

Answer:

20 quarts of milk used

Step-by-step explanation:

♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫

➷since there are 4 quarts in a gallon, you have 20 quarts.

There are four quarts in a gallon, so you times 4 and 5. The result you get is 20 quarts.  

✽

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

DOGE

Answer:

Step-by-step explanation:

2x = 27

Answer:

The answer is 17 1/6  you didnt notice the little line above the six you techniclly just convert the decimal to a fraction i had this on my lesson it tricked me to

Step-by-step explanation:

Answer:

The answer is c, 24 units.

10% × 23.8 =

(10 ÷ 100) × 23.8 =

(10 × 23.8) ÷ 100 =

238 ÷ 100 =

2.38

Proof

2.38 ÷ 23.8 =

0.1 =

0.1 × 100/100 =

0.1 × 100% =

(0.1 × 100)% =

10%

Answer:

238

Step-by-step explanation:

Question: Find 10% of 238.  

Answer: 10% of 238 is 23.8.

Explanation

STEP 1: 1% of 238 = 238100=2.38

STEP 2: 10% of 238 = 10⋅2.38=23.8

Explanation 2:

STEP 1: Write 10% as a decimal number: 10%=10100=0.1

STEP 2: Multiply 0.1 by 238: 0.1⋅238=23.8

Result

Question: The number 238 is 10% of what number?

Answer: The number 238 is 10% of 2380.

Explanation

STEP 1: Write 10% as a decimal number:

10=10100=0.1

STEP 2: Divide 238 by 0.1:

2380.1=2380

Answer: C. The y-intercept means the concentration will remain 30% if no solution is added.  <-- on edgen2020

Explanation: The first person who answered is correct! I'm attaching a screenshot of my quiz with this- Good luck everyone! :)

Answer:

C. The y-intercept means the concentration will remain 30% if no solution is added.  

Step-by-step explanation:

edge2022

It is JG! You must rotate the second triangle so both triangles are at the same angle. Then, look at the lines and find the corresponding line segment on the other triangle.

Answer:

9/10

Step-by-step explanation:

convert 3/5 to 6/10

6/10+3/10=9/10

The value of fraction will be;

⇒ 9/10

A fraction is a part of whole number, and a way to split up a number into equal parts. Or, A number which is expressed as a quotient is called fraction. It can be written as the form of p : q, which is equivalent to p / q.

Given that;

The fraction is,

⇒ 3/5 + 3/10

Now,

Since, The fraction is,

⇒ 3/5 + 3/10

Solve as;

⇒ 3/5 + 3/10

⇒ 6/10 + 3/10

⇒ (6 + 3) / 10

⇒ 9 / 10

Thus, The value of fraction = 9/10

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