In this scenario involving an elevator's movement, the negative velocity indicates downward motion and corresponds to the slope in the equation of a line. By applying the slope and initial conditions, we calculated that Monica was initially 470 feet above the ground, which is the y-intercept in the slope-intercept form.
Explanation:The student's question involves understanding the implications of negative velocity in a real-world situation involving an elevator, calculating an initial position based on this velocity and elapsed time, and tying these concepts to algebraic representations in slope-intercept form.
A negative rate of -20ft/s indicates that the elevator is moving downward. This rate represents the slope in the slope-intercept form of an equation, y = mx + b, where m is the rate of change or slope.To find how many feet Monica was above the ground when she got on the elevator, we use the formula y = mx + b, where y is the final position (350 ft), m is the rate of change (-20 ft/s), and x is the elapsed time (6 s). Replacing the values and solving for b (initial position), we get 350 = -20(6) + b, leading to b = 470 ft. Therefore, Monica was 470 feet above the ground when she got on the elevator.The answer to part a, -20ft/s, represents the slope, and the answer to part b, 470 feet, represents the y-intercept (b) in the slope-intercept form.Identify the x-intercept and y-intercept of the line 2x−5y=20.
Select one:
a. The x-intercept is (2, 0) and the y-intercept is (0, -5).
b. The x-intercept is (10, 0) and the y-intercept is (0, -4).
c. The x-intercept is (0, -4) and the y-intercept is (10, 0).
d. The x-intercept is (0, 10) and the y-intercept is (-4, 0).
An artifact was found to have an original amount of Carbon-14 of 32 grams. Approximately how many grams of Carbon-14 remain after 4300 years? Carbon 14 decays at a rate of -0.00012 grams per year.
9.6 grams
19.1 grams
22.4 grams
31.2 grams
Find the 6th term of the expansion of (2p - 3q)11. a. -7,185,024p4q7 c. -7,185p4q7 b. -7,185,024p6q5 d. -7,185p6q5
Answer: B. [tex]-7185024p^6q^5[/tex]
Step-by-step explanation:
The (r+1)th term in [tex](a+b)^n[/tex] is given by :
[tex]^nC_r(a)^{n-r}(b)^r[/tex]
The given binomial : [tex](2p - 3q)^{11}[/tex]
For the 6th term, we put r=6-1=5 , we get
[tex]^{11}C_5(2p)^{11-5}(-3q)^5\\\\=\dfrac{11!}{5!(11-5)!}(2p)^6(-243q^5)\\\\=-dfrac{11\times10\times9\times8\times7\times6!}{6!5!}(64p^6)(243q^5)\\\\=-462\times(64p^6)(243q^5)\\\\=-7185024p^6q^5[/tex]
Hence, the 6th term of the expansion of [tex](2p - 3q)^{11}[/tex] = [tex]-7185024p^6q^5[/tex]
The money collected from selling bacon at a butcher store is given by the function f(x) = 3.55x – 4, where f(x) is the sales revenue in dollars and x is the number of customers visiting the store each day. If {17, 21, 24, 34} customers visited over four days, what is the income from bacon sales each day?
{50.55, 63.45, 80.34, 99.8}
{43.45, 58.75, 73.4, 93.5}
{56.35, 70.55, 81.2, 116.7}
{45.74, 65.7, 83.8, 105.7}
{63.25, 68.35, 79.7, 97.6}
Answer:
Hi!
The correct answer is {56.35, 70.55, 81.2, 116.7} .
Step-by-step explanation:
The set {17, 21, 24, 34} represents the values of x.
If you replace each value in the equation:
f(17) = 3.55 * 17 – 4 = 60.35 - 4 = 56.35f(21) = 3.55 * 17 – 4 = 74.55 - 4 = 70.55f(24) = 3.55 * 17 – 4 = 85.2 - 4 = 81.2f(34) = 3.55 * 17 – 4 = 120.7 - 4 = 116.7Then you have the values {56.35, 70.55, 81.2, 116.7} .
When x is 2, y is 4, p is 0.5, and m is 2. If x varies directly with the product of p and m and inversely with y, which equation models the situation?
b. StartFraction x y Over p m EndFraction = 8
Two times the least of three consecutive odd integers exceeds two times the greatest by 15. what are the integers
The vertical distance from a fixture outlet to the trap weir should not be more than _______ inches.
The maximum allowable vertical distance from a fixture outlet to the trap weir in plumbing is 24 inches. This standard ensures proper drainage and the maintenance of a water seal, preventing sewer gases from entering a building.
The vertical distance from a fixture outlet to the trap weir, which is a critical aspect of plumbing design, should not be more than 24 inches. The fixture outlet is the point where water exits the fixture, and the trap weir is the peak point inside a P-trap, which maintains a water seal to prevent sewer gases from entering the building.
It's important to adhere to this standard to ensure proper drainage and maintain the water seal. If the distance is too great, it could lead to poor drainage and a loss of the trap seal due to siphoning, which would allow sewer gases to enter the home or building.
What number must be added to the expression below to complete the square? x2 - 11x
Since we are to complete the square, therefore I believe the correct given should be:
x ^ 2 – 11 x
Take note of the symbol ^ which denotes that 2 is an exponent of x.
The general form of a binomial equation is in the form of:
a x^2 + b x + c
Where in this case:
a = 1
b = -11
c = unknown
To complete the square, we have to find for the value of c. This is calculated using the formula:
c = (b / 2) ^ 2
c = (-11 / 2) ^ 2
c = 30.25
Therefore the complete equation is:
x ^ 2 – 11 x + 30.25
30.25 is correct but apex asks for a fraction so 121/4
70/x = 15/21 solve proportion
How to multiply scientific notation with another scientific notation?
1. Multiply the coefficients and round to the number of significant figures in the coefficient with the smallest number of significant figures.
2. Add the exponents.
3. Convert the result to scientific notation.
Answer:
Let's say that I have to multiply 2.5 x 10^3 and 6.23 x 10^5.
First, Let's multiply 10^3 and 10^5.
It would be 10^8.
next, let's multiply 2.5 and 6.23.
It is 15.575.
So, my answer is 15.575 x 10^8.
the fraction 6/9 produces a repeating decimal 0.6 ?
true or false
While crossing the Atlantic, sailors spot two mermaids 120° apart on each end of an island that is 6 miles away. How far apart are the mermaids around the outer edge of the island to the nearest tenth of a mile?
A. 12.6 miles
B. 3.1 miles
C. 7.2 miles
D. 20.2 miles
Geometry help please.
A normal population has a mean of 75 and a standard deviation of 5. you select a sample of 40. compute the probability the sample mean is
The probability that the sample mean is less than 74 is about 10.38%.
To solve the problem step-by-step, let's go through each calculation in detail:
1. Compute the Standard Error (SE):
Given:
- Population mean [tex](\(\mu\))[/tex] = 75
- Population standard deviation [tex](\(\sigma\))[/tex] = 5
- Sample size (n) = 40
The standard error of the mean is calculated using the formula:
[tex]\[ \text{SE} = \frac{\sigma}{\sqrt{n}} \][/tex]
Substituting the given values:
[tex]\[ \text{SE} = \frac{5}{\sqrt{40}} = \frac{5}{6.3246} \approx 0.791 \][/tex]
2. Compute the Z-score for a sample mean of 74:
The Z-score is calculated using the formula:
[tex]\[ Z = \frac{X - \mu}{\text{SE}} \][/tex]
Where:
- (X) is the sample mean.
Given (X = 74):
[tex]\[ Z = \frac{74 - 75}{0.791} = \frac{-1}{0.791} \approx -1.26 \][/tex]
3. Find the probability corresponding to the Z-score:
The Z-score of -1.26 corresponds to the cumulative probability from the standard normal distribution table.
A Z-score of -1.26 gives a cumulative probability (area under the curve to the left of the Z-score) of approximately 0.1038.
Therefore, the probability that the sample mean is less than 74 is about 10.38%.
What is the location of point F, which partitions the directed line segment from D to E into a 5:6 ratio?
-1/11
1/11
2/15
15/2
The correct answer is b
F is a point which is greater than zero and F must be in the location of 1/11 and it can be determine by using arithmetic operations.
Given :
F partitions the directed line segment from D to E into a 5:6 ratio.
Given that F partitions the directed line segment from D to E into a 5:6 ratio therefore, total segments is (5 + 6 = 11).
From point D to E in the given line segment there are 9 units. To divide the line segment of 9 unit into 11 unit, first find the distance between two units, that is:
[tex]\dfrac{9}{11}=0.82[/tex]
[tex]0.82\times 5 = 4.1[/tex]
Now, it can be say that F is a point which is greater than zero and F must be in the location of 1/11.
For more information, refer the link given below:
https://brainly.com/question/12431044
in a book 3/8 of the pages have pictures on them.Given that 72 pages have a picture on, work out the number of pages in the book.
Roger is renting a tuxedo for prom. Once he has chosen his jacket, he must choose from three types of pants, four colors of vests, and two different styles of shoes. How many different ways can he select his attire for the prom?
The number of ways he can select his attire for the prom to look differently will be twenty-four (24).
What are permutation and combination?A permutation is an act of arranging the objects or elements in order. Combinations are the way of selecting objects or elements from a group of objects or collections, in such a way the order of the objects does not matter.
Roger is renting a tuxedo for prom.
Once he has chosen his jacket, he must choose from three types of pants, four colors of vests, and two different styles of shoes.
Then the number of the ways he can select his attire for the prom will be
[tex]\rm Number \ of \ ways = ^3C_1 \times ^4C_1 \times ^2C_1 \\\\ Number \ of \ ways = 3 \times 4 \times 2\\\\Number \ of \ ways = 24[/tex]
More about the permutation and the combination link is given below.
https://brainly.com/question/11732255
Patrick spins the spinner 9 times. What is the theoretical probability that it stops on the brown sector on the last spin?
1 over 45
1 over 25
1 over 9
1 over 5
The sum of the roots of the equation x 2 + x = 2 is:
Answer:
The sum of the roots of the equation [tex]x^{2} + x = 2[/tex] is -1
Step-by-step explanation:
You have two options to find the sum of the roots,
The first option is to use the Quadratic Formula to find the two roots:[tex]x_{1,2} = \frac{-b\±\sqrt{b^{2}-4ac}}{2a} [/tex]
[tex]x^{2} + x - 2= [/tex] where:
a = 1
b = 1
c = -2
[tex]x_{1} = \frac{-1-\sqrt{1^{2}-4*1*-2}}{2*1}[/tex] = -2
[tex]x_{2} = \frac{-1+\sqrt{1^{2}-4*1*-2}}{2*1}[/tex] = 1
The sum of the roots is -2 + 1 = -1
2. The second option is use the fact that a general quadratic equation is in the form of:
[tex]ax^{2}+bx+c=0[/tex]
if you divided by [tex]a[/tex] you get:
[tex]x^{2}+\frac{b}{a} x+\frac{c}{a} =0[/tex]
and always the sum of roots will be given for this expression [tex]x_{1} + x_{2} = \frac{-b}{a}[/tex]
Why this is true?
Because if we use the Quadratic Formula as follows:
[tex]x_{1} + x_{2} = \frac{-b+\sqrt{b^{2}-4ac}}{2*a} + \frac{-b-\sqrt{b^{2}-4ac}}{2a}[/tex]
[tex]x_{1} + x_{2} = \frac{-2b+0}{2a}}[/tex]
[tex]x_{1} + x_{2} = \frac{-b}{a}[/tex]
In the case of this equation:
[tex]x_{1} + x_{2} = \frac{-1}{1} = -1[/tex]
what is the solution to the equation 4(3x - 11) + 23 = 5x - 14 ?
What is the slope of the graph of 2y – 5x = 14?
Using the parkland formula, calculate the hourly rate of fluid replacement with lactated ringerâs solution during the first 8 hours for a client weighing 75 kg with total body surface area (tbsa) burn of 40%. record your answer using a whole number.
A cone-shaped paper drinking cup is to be made to hold 33 cm3 of water. find the height and radius of the cup that will use the smallest amount of paper. (round your answers to two decimal places.)
Final Answer:
To minimize the paper used for a cone-shaped drinking cup holding 33 cm³ of water, the optimal dimensions are a radius of approximately 1.65 cm and a height of around 3.30 cm.
Explanation:
To minimize the paper required for the cone-shaped cup, we must consider its volume, which is given as 33 cm³. The formula for the volume of a cone is V = (1/3)πr²h, where r is the radius and h is the height. To find the dimensions that minimize paper usage, we can use calculus and optimization techniques.
The first step involves expressing the volume formula in terms of a single variable, either r or h. In this case, expressing it in terms of h is preferable. Then, taking the derivative and setting it equal to zero helps find critical points. The second derivative test can determine whether these points are minima.
Once we find the critical points, substituting them back into the original volume formula gives us the optimal dimensions. In this context, the optimal radius is approximately 1.65 cm, and the optimal height is around 3.30 cm. These dimensions ensure the cone holds 33 cm³ of water while minimizing the surface area of the paper, thus reducing material usage and waste.
In conclusion, by applying calculus and optimization principles, we determine that a cone with a radius of 1.65 cm and a height of 3.30 cm uses the smallest amount of paper to hold 33 cm³ of water.
The height and radius of the cup that will use the smallest amount of paper, rounded to two decimal places, are:
[tex]\[ \boxed{h \approx 6.04 \text{ cm}} \][/tex]
[tex]\[ \boxed{r \approx 3.02 \text{ cm}} \][/tex]
These are the dimensions of the cone-shaped cup that will minimize the amount of paper used while still holding [tex]33 cm^3[/tex] of water.
To find the height and radius of the cone-shaped paper drinking cup that will use the smallest amount of paper, we need to minimize the surface area of the cone. The surface area [tex]\( A \)[/tex] of a cone consists of the base area and the lateral surface area, which can be expressed as:
[tex]\[ A = \pi r^2 + \pi r l \][/tex]
where [tex]\( r \)[/tex] is the radius of the base of the cone, and [tex]\( l \)[/tex] is the slant height of the cone. The slant height can be found using the Pythagorean theorem:
[tex]\[ l = \sqrt{r^2 + h^2} \][/tex]
where [tex]\( h \)[/tex] is the height of the cone. The volume [tex]\( V \)[/tex] of the cone is given by:
[tex]\[ V = \frac{1}{3} \pi r^2 h \][/tex]
We are given that the volume [tex]\( V \)[/tex] is [tex]33 cm^3[/tex]. We can use this to express [tex]\( h \)[/tex] in terms of [tex]\( r \)[/tex]:
[tex]\[ h = \frac{3V}{\pi r^2} \][/tex]
Substituting the volume into the equation, we get:
[tex]\[ h = \frac{3 \times 33}{\pi r^2} \][/tex]
Now, we substitute [tex]\( h \)[/tex] into the expression for [tex]\( l \)[/tex]:
[tex]\[ l = \sqrt{r^2 + \left(\frac{3 \times 33}{\pi r^2}\right)^2} \][/tex]
Substituting [tex]\( l \)[/tex] back into the surface area equation, we have [tex]\( A \)[/tex] as a function of [tex]\( r \)[/tex] :
[tex]\[ A(r) = \pi r^2 + \pi r \sqrt{r^2 + \left(\frac{3 \times 33}{\pi r^2}\right)^2} \][/tex]
To find the minimum surface area, we need to take the derivative of [tex]\( A \)[/tex] with respect to [tex]\( r \)[/tex] and set it equal to zero:
[tex]\[ \frac{dA}{dr} = 0 \][/tex]
Solving this equation will give us the value of [tex]\( r \)[/tex] that minimizes the surface area. Once we have [tex]\( r \)[/tex], we can substitute it back into the equation for [tex]\( h \)[/tex] to find the height that corresponds to the minimum surface area.
After performing the differentiation and solving for [tex]\( r \)[/tex], we find that the radius that minimizes the surface area is approximately 3.02 cm. Substituting this value into the equation for [tex]\( h \)[/tex], we find that the corresponding height is approximately 6.04 cm.
How far away can a boy ride on a bicycle if he rides away at 10 kilometers per hour and returns at 9 kilometers per hour? The entire trip takes 9.5 hours.
Four more than the product of 18 and a number Use the variable n to represent the unknown number.
The library has at least 5,000 books. Which inequality represents the situation an has an infinite number of solutions?
The original value of a car is 18000 and it depreciates by 15% each year. what is the value of the car after three years?
Replace ? with a whole number to make the statements true.
a. 20 ÷ 4 ? means ? × 4 = 20
b. 2,725 ÷ 5 ? means ? × 5 = 2,725
c. ? ÷ 5 = 0
Answer:
a. 5
b. 545
c. 0
Step-by-step explanation:
These are straightforward division problems, easily solved using your own memorized multiplication facts, or using a calculator.
a. 20 ÷ 4 = 5 means 5 × 4 = 20
b. 2725 ÷ 5 = 545 means 545 × 5 = 2725
c. 0 ÷ 5 = 0 means 0 × 5 = 0
_____
When using the Google calculator and standard keyboard symbols, you can use the slash (/) for "divided by" and the asterisk (*) for "times."
Which statement is correct with respect to f(x) = -3|x − 1| + 12?
The V-shaped graph opens upward, and its vertex lies at (-3, 1).
The V-shaped graph opens downward, and its vertex lies at (-1, 3).
The V-shaped graph opens upward, and its vertex lies at (1, -12).
The V-shaped graph opens downward, and its vertex lies at (1, 12).
Dishwashers are on sale for 25% off the original price (d), which can be expressed with the function p(d) = 0.75d. Local taxes are an additional 14% of the discounted price, which can be expressed with the function c(p) = 1.14p. Using this information, which of the following represents the final price of a dishwasher with the discount and taxes applied?
c(p) ⋅ p(d) = 0.855pd
c(p) + p(d) = 1.89d
c[p(d)] = 0.855d
d[c(p)] = 1.89p
We are given the functions:
P (d) = 0.75 d ---> 1
C (P) = 1.14 P ---> 2
The problem asks us to find for the final price after discount and taxes applied; therefore we have to find the composite function of the two given functions 1 and 2. To solve for composite function of the final price of the dishwasher with the discount and taxes applied, all we have to do is to plug in the value of P (d) with variable d into the equation of C (P). That is:
C (P) = 1.14 (0.75 d)
C (P) = 0.855 d
or
C [P (d)] = 0.855 d
Answer:
0.855d
Step-by-step explanation:
I took the test. I also checked a bunch of other answers by completing the test. at least 2 other people had the same answer as me.