Mountain officials want to know the length of a new ski lift from A to C , as shown in the figure below. They measure angle DAC to be 32° . They then move 960 feet to point B and measure angle DBC to be 18° . What is the length of the new ski lift from A to C ? Round your answer to the nearest tenth of a foot.

Answers

Answer 1
We assume that the hill is represented by points ACD  and the ski lift is represented by points BCD. From the description above, points CDB would have an angle of 90 degrees. Then, we would have:

sin (32) = CD / 960
CD = 508.72

tan 32 = 508.72 / AD
AD = 814.13

Therefore, the distance would be 814.13 - 508.72 = 305.4 ft.

Answer 2

Knowing if trigonometry knowledge we can say that the distance will be 305.4 ft.

So knowing how sine and tangent work we can write the equals as:

[tex]sin (32) = CD / 960\\CD = 508.72[/tex]

[tex]tan (32) = 508.72 / AD\\AD = 814.13[/tex]

To calculate the distance, we will decrease the two values ​​found, like this:

[tex]814.13 - 508.72 = 305.4 ft[/tex]

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Related Questions

Quadrilateral ABCD is a parallelogram. ,  bisects , and . What is the best name for quadrilateral ABCD?

A.

rectangle

C.

isosceles trapezoid

B.

rhombus

Answers

C. Isosceles trapezoid

A line passes through the point (-8,3) and has a slope of 5/4.

Write an equation in slope-intercept form for this line.

Answers

y = mx + b
3 = 5/4(-8) + b
3 = -10 + b
b= 13


equation

y = 5/4x + 13
y - y1 = m(x - x1)
y - 3 = (5/4) ( x + 8)
y - 3 = 5/4x + 10
add 3 to both sides
y = 5/4 x + 13

I need help with #18 c-i

Answers

c - one is -4 due to that when y=0 the x coordinate shows -4, the other is when 4-x^2=0, and the square root of 4 is 2

d - x intercepts

e - it's 4 due to that 4 is shown where x=0 on the graph

f - y intercept

g - Since x>0, we do 4-x^2. x=1, and 1^2=1, so 4-1=3. 1 is x and 3 is f(x), or y, so the coordinates are (1,3)

h - Since it's <0, -1+4=3, and since 3 is the output the coordinates are (-1,3)

i - Since -3 <0, we do -3+4=1

How to tell if there is a horizontal asymptote?

Answers

If the degree of the numerator is smaller than the denominator, then horizontal asymptote is 0, if the degrees are the same then you take the coefficients and divide then if the degree is greater on top usually there is no horizontal asymptote. 

To tell if there is a horizontal asymptote, for rational functions, compare the degrees of the numerator and denominator; if they are equal, the asymptote is the ratio of their leading coefficients. If the numerator's degree is less, the asymptote is at y=0; if greater, there is no horizontal asymptote. Polynomials do not have horizontal asymptotes.

To determine if a function has a horizontal asymptote, we look at the behavior of the function as x approaches infinity (x →∞). For rational functions, the degrees of the numerator and denominator play a crucial role. If the degree of the numerator is equal to the degree of the denominator, the horizontal asymptote is the ratio of the leading coefficients of the numerator and denominator. For instance, as x approaches infinity, the term with the highest power dominates and the constant terms become less significant, leading to the horizontal asymptote at y = 1.

In a scenario where the degree of the numerator is less than the degree of the denominator, the function will have a horizontal asymptote at y = 0, since the function approaches zero as x increases without bound. Conversely, if the degree of the numerator is greater than the degree of the denominator, no horizontal asymptote exists because the function grows without limit.

Remember, polynomials do not have horizontal asymptotes, as their values continue to increase or decrease indefinitely with x.

Help with these three problems? Please

Answers

6. add the averages then take that average

50+74 = 124, 124/2 = 62

answer: 62

8. first put all the numbers in order

4, 5 ,6 ,8 11, 12,14, 15, 23 ,23

 Find the middle number, since there are 10 numbers find the average of the 2 middle numbers

11+12 =23/2 =11.5

 Lower half data = 4, 5, 6, 8, 11

 The middle number of that set is Q1,

Q1=6

9

9, find q3

1, 2, 3, 5, 5, 6, 9

 Find middle number (5)

upper half data = 5, 6, 9

Q3=  5 , 6, 9 = 5+10 +15 = 30

so answer is $30

.........simplify 3^2*3^5

Answers

Using order of operations, we can see we should first solve for the exponents, and then multiply the exponent values by each other.


3²×[tex] 3^{5} [/tex]
9×243
2187

Another way to solve this is to add the exponents together and simply do [tex] 3^{7} [/tex]. We can only do that in this case, however, because the values are being multiplied by each other.

Either way we solve, we will get 2187 as our final answer.
Hello there!
[tex]#3^2 * 3^5# #(3*3) * (3*3*3*3*3)# #(3*3*3*3*3*3*3)# #3^7# = #2187# I hope I helped :)[/tex]

In the diagram below, what is the approximate length of the minor arc ? 

Answers

arc length = given angle/360 x 2 x PI x radius

120/450 x 2 x 3.14 x 23 = 48.17

 round to 48 cm

Answer:

Option A is correct

the approximate length of the minor arc is, 48 cm

Step-by-step explanation:

Length of an arc is given by:

[tex]l = r \theta[/tex]              .....[1]

here r is the radius of the circle from the center and [tex]\theta[/tex] is the angle in radian.

From the given figure, we have;

r = 23 cm

Use conversion:

1 degree = 0.0174533 radian

then

120 degree = 2.094396

[tex]\theta = 2.094396[/tex] radian.

Substitute these in [1] we have;

[tex]l = 23 \cdot 2.094396 = 48.171108[/tex] cm

Therefore, the approximate length of the minor arc is, 48 cm

The end points of AB are A(-2,-3) , B(3,2) point C lies on AB and is 2/5 of the way from A to . What is the coordinates of point C? Explain how you find your answer

Answers

check the picture below.

[tex]\bf \left. \qquad \right.\textit{internal division of a line segment} \\\\\\ A(-2,-3)\qquad B(3,2)\qquad \qquad 2:5 \\\\\\ \cfrac{AC}{CB} = \cfrac{2}{5}\implies \cfrac{A}{B} = \cfrac{2}{5}\implies 5A=2B \\\\\\ 5(-2,-3)=2(3,2)\\\\ -------------------------------\\\\[/tex]

[tex]\bf { C=\left(\cfrac{\textit{sum of "x" values}}{r1+r2}\quad ,\quad \cfrac{\textit{sum of "y" values}}{r1+r2}\right)}\\\\ -------------------------------\\\\ C=\left(\cfrac{(5\cdot -2)+(2\cdot 3)}{2+5}\quad ,\quad \cfrac{(5\cdot -3)+(2\cdot 2)}{2+5}\right)[/tex]
Final answer:

To find the coordinates of point C which divides line AB into a 2:5 ratio, use the section formula. Therefore, the coordinates are (-4/7, -11/7). This provides point C's location on the line segment AB.

Explanation:

The coordinates of C are determined through the section formula, which finds the coordinates of a point dividing a line segment into a specific ratio. In this case, the ratio is 2:5. To solve for the x-coordinate of C, the formula [(m*x2) + (n*x1)] / (m+n) is used, where m and n are the ratio values, x1 and x2 are the x-coordinates of points A(-2, -3) and B(3, 2). Using these, the x-coordinate of C is found to be (2*3 + 5*(-2)) / (2+5) = -4/7.

Similar calculations apply to solving for the y-coordinate of C: [(m*y2) + (n*y1)] / (m+n) = (2*2 + 5*(-3)) / (2+5) = -11/7.

Therefore, the coordinates of point C are (-4/7, -11/7). This is the point C on the line segment AB that is 2/5 of the way from point A to point B.

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Using the graph, find this information about the child’s movement in the vertical (y) direction:
1. the best trigonometric function to start with
2. the amplitude
3. the period
4. any horizontal displacement of the graph.
5. any vertical displacement of the graph.

Type your response here:

Answers

1. The sine and cosine function are sinusoidal waves such that they form waves when you graph them on a cartesian plane. The only difference between them is that the crest comes first followed by the trough in the sine function. The opposite is true for the cosine function. The graph in the picture is a sine function.

2. The amplitude is the measure from crest to crest, or from trough to trough. The amplitude in the graph is 1.5.

3. The period is the reciprocal of amplitude. Therefore,itis 1/1.5 or 2/3.

4. There is no horizontal displacement because the wave only moves in a vertical direction.

5. The vertical displacement is from crest to trough which is 1 unit.

Solve the quadratic equation by completing the square.

x^2-10x+15=0

First, choose the appropriate form and fill in the blanks with the correct numbers.
Then, solve the equation. Round your answer to the nearest hundredth.
If there is more than one solution, separate them with commas.

Form:
( x + _ )^2 = _
or
( x - _ )^2 = _

Solution:
x = _

^ Please use the template above to answer ^

Answers

Final answer:

To solve the quadratic equation x^2 - 10x + 15 = 0 by completing the square, we manipulate it to the form (x - 5)^2 = 10, then solve for x to get two solutions: x = 8.16 and x = 1.84.

Explanation:

To solve the quadratic equation by completing the square, we need to manipulate the equation x^2 - 10x + 15 = 0 so it takes the form of (x - a)^2 = b, where a is half of the coefficient of x, and b is a constant.

First, we move the constant to the other side of the equation:

x^2 - 10x = -15

Next, we find the value that completes the square. This value is (10/2)^2 = 25.

Adding 25 to both sides, we get:

x^2 - 10x + 25 = 25 - 15

Now the equation is a perfect square:

(x - 5)^2 = 10

To find the solution for x, we take the square root of both sides:

x - 5 = ±10√10

x = 5 ± √10

Thus, the solutions rounded to the nearest hundredth are:

x = 5 + √10 ≈ 8.16

x = 5 - √10 ≈ 1.84

The complete answer in the template is:

Form:
( x - 5 )^2 = 10
Solution:
x = 8.16, 1.84

I really need help :(...............

Answers

Add the terms straight down (ie add like terms)

For the x terms
(3x) plus (-3x) = 3x-3x = (3-3)x = 0x = 0
The result being zero means the x terms effectively cancel out and go away

For the y terms
(-y) plus (3y) = -1y+3y = (-1+3)y = 2y

And finally the terms on the right hand side
(-1) plus (27) = -1+27 = 26

---------------------------------------------------------------

After adding the two equations, we end up with 0+2y = 26
which simplifies to 2y = 26. So the answer is choice D
Add the left hand side parts together and right hand side parts together.

3x - y - 3x + 3y = 2y
-1 + 27 = 26

So, 2y = 26 is the answer.

Find the greatest common factor of the following monomials 28g5h2 12g6h5
Also explain step by step how to solve these problems please

Answers

28g^5h^2 and 12g^6h^5

first, we find the GCF of the coefficients 28 and 12. What is the highest number that will go into both 28 and 12 evenly ? That number is going to be 4.

now, we look at our variables....to find the GCF of the variables, pick the lowest exponent.
another words, the lowest exponent of ur variable h is h^2...and the lowest exponent of ur variable g is g^5

therefore, the GCF of these monomials is : 4h^2g^5

A surface on which all points are at the same potential is referred to as

Answers

equipotential, equi=equal

HELP! Type the correct answer in each box. Use numerals instead of words, if necessary, use / for the fractions bar(s)

Answers

The piecewise function is:

[tex]\[ f(x) = \begin{cases} 4 & \text{if } -1 \leq x \leq 1 \\ x - 1 & \text{if } 3 \leq x \leq 5 \end{cases} \][/tex]

To determine the piecewise function represented by the given coordinates, let's examine the points and their corresponding intervals.

The coordinates are (-1, 4), (1, 4), (3, 2), and (5, 4).

The points (-1, 4) and (1, 4) have the same y-coordinate, indicating that on the interval [tex]\(-1 \leq x \leq 1\)[/tex], the function has a constant value of 4. Therefore, the piecewise function for this interval is f(x) = 4 for [tex]\(-1 \leq x \leq 1\).[/tex]

The points (3, 2) and (5, 4) indicate that on the interval [tex]\(3 \leq x \leq 5\)[/tex], the function is a line passing through these two points. We can find the slope (m) and y-intercept (b) for this line.

[tex]\[ m = \frac{\text{change in } y}{\text{change in } x} = \frac{4 - 2}{5 - 3} = \frac{2}{2} = 1 \][/tex]

Using the point (3, 2), we can find the y-intercept:

2 = 1(3) + b

b = -1

Therefore, the equation for the line on the interval [tex]\(3 \leq x \leq 5\) is \(f(x) = x - 1\) for \(3 \leq x \leq 5\).[/tex]

Putting it all together, the piecewise function is:

[tex]\[ f(x) = \begin{cases} 4 & \text{if } -1 \leq x \leq 1 \\ x - 1 & \text{if } 3 \leq x \leq 5 \end{cases} \][/tex]

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Which equation is not equivalent to the formula m = ca?
A: [tex]c = \frac{m}{a} [/tex]
B: [tex]a = \frac{c}{m} [/tex]
C: [tex]a = \frac{m}{c} [/tex]
D: m = ac

Answers

m = ca

If we find a, we must do c = m/a and if we find c we must do a = m/c

The bigger measure over the known one.

Answer B

Answer:m=ca i remember my teacher telling me how to do this.

Step-by-step explanation:

The measure of an inscribed angle is 110°. What is the measure of the intercepted arc? 55° 110° 220°

Answers

the measurement of an inscribed angle is half of the measure of the intercepted arc.

the inscribed angle is 110 degrees, so we multiply 110 by 2.

110*2 = 220 degrees

The measure of the intercepted arc is 220 degrees

220° is the measure of the intercepted arc

If four times a number plus 3 is 11, what is the number

Answers

4x + 3 = 11
4x = 11 -3
4x = 8
x =8/4
x =2

answer
the number is 2
4x + 3 = 11
4x = 11-3 = 8
x = 2

number is 2

Determine the common ratio and find the next three terms of the geometric sequence.



3/4,3/10,3/25,...

Answers

to find the common ratio, divide the 2nd term by the 1st term
(3/10) / (3/4) = 3/10 * 4/3 = 12/30 = 2/5 <==

In a geometric sequence, the next term is found by multiplying the term by the common ratio.
3/25 * 2/5 = 6/125 <==
6/125 * 2/5 = 12/625 <==
12/625 * 2/5 = 24/3125 <==

The next three terms of the sequence are 6/125, 12/625 and 24/3125

Geometric sequence

The nth term of a geometric sequence is given as:

Tn = ar^n-1

Given the geometric sequence

3/4,3/10,3/25,...

Find the common ratio

r = 3/10 * 4/3

r = 2/5

Find the 4th, 5th and 6th terms

T4 = (3/4)(2/5)^3
T4 = 3/4 * 8/125
T4 = 6/125

T5 = (3/4)(2/5)^4
T5 = 3/4 * 16/625
T5 = 12/625

T6 = (3/4)(2/5)^5
T6 = 3/4 * 32/3125
T6 = 24/3125

Hence the next three terms of the sequence are 6/125, 12/625 and 24/3125

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Quadrilateral $abcd$ is a trapezoid with $ab$ parallel to $cd$. we know $ab = 20$ and $cd = 12$. what is the ratio of the area of triangle $acb$ to the area of the trapezoid $abcd$? express your answer as a common fraction.

Answers

Draw a diagram to illustrate the problem as shown below.

The area of triangle acb is
A₁ = (1/2)*20*h = 10h

The area of trapezoid abcd is
A₂ = (1/2)*(20+12)*h = 16h

The ratio A₁/A₂ is
A₁/A₂ = (10h)/(16) = 5/8

Answer:
The ratio of triangle acb to the area of trapezoid abcd is 5/8.

Guys help me out with this one plizz

Answers

Getting two 6's in four rolls can happen in 6 ways. 4C2 = 6

The probability of getting two 6's is 1/36. Therefore,

6 times 1/36 = 1/6 or 0.16666666...

 Converting to a percent to the nearest tenth is 16.7%


The velocity of a train, measured in meters per second, is described by vector t=(-1,-4). Find the direction the train is traveling using standard position

Answers

The vector (-1,-4) tells us that the train is moving 1 unit in the negative x-direction while moving 4 units in the negative y-direction. This vector makes an angle theta with the x-axis. We can find theta by using the inverse tan function. tan(theta) = 4/1 theta = inverse tan (4) = 75.96 Note that this is the angle below the x-axis. The angle in standard position must be measured from the positive x-axis, so we need to add 180 degrees. Therefore, the direction of the train in standard position is: 75.96 + 180 which equals 255.96 degrees.

Answer:

inverse tangent 4/1

75.96 + 180 bc 3rd quadrant which equals 255.96 degrees.

Step-by-step explanation:

round 256 degrees

How many 3 digit numbers can be made if no digit is repeated and the number can not begin with a zero?

Answers

digit #1 - 9 numbers (1-9)

digit #2 = 9 numbers (0-9 minus the first digit)

digit #3 = 8 numbers ( 0-9 minus the first 2 digits)

9*9*8 = 648 combinations

We have to select 3 digits out of 10 with the following conditions:
1) It can't start with 0
 2) repetition is not allowed.
 Let ABC this number:
A = 9 choices (out of 10, excluding 0, because it can't be 0)
B = 9 choices (out of 10 including 0, because it can be 0)
C= 8 choices (out of 10 because 2 digits already selected)
 The total ways to write this number are:
9 x 9 x 8 = 648 ways

Another method:
A can be written in ⁹C₁
B can be written in ⁹C₁
C can be written in ⁸C₁

Total ways: ⁹C₁ x ⁹C₁ x ⁸C₁ = 648 ways

Parallel to the line 2x-3y=9 and having a y intercept of 3

Answers

Switch the signs which brings -2x+3y=-9

Can you use the ASA Postulate or the AAS Theorem to prove the triangles congruent?

Answers

Answer:

ASA only

Step-by-step explanation:

Given is a picture of two triangles with one side and one angle congruent.

Comparison of these two triangles given

side = side

one angle = one angle (given)

Second angle = second angle (Vertically opposite angles)

Thus we find here that two angles and one corresponding side are congruent.

HEnce we say that these two triangles are congruent by ASA theorem

ASA theorem can be applied here because the equal side is between the two congruent angles.  

Instead if the side is not between the congruent angles but corresponding side then we can only use AAS

SO here ASA is correct.

Answer:

ASA only

Step-by-step explanation:

We are given that  two triangles in which

An angle of triangle is equal to its corresponding angle of second triangle.

One side of a triangle is equal to one side of other triangle.

ASA  postulate: It states that two angles and included side of one triangle are congruent to its corresponding angles and corresponding side of other triangle , then the two triangles are congruent.

AAS postulate: It states that two angles and non- included side of one triangle are congruent to its corresponding two angles and its corresponding side of another triangle, then the triangles are congruent by AAS postulate.

In triangle AOB and COD

[tex]\angle AOB= \angle COD[/tex]  (Vertical angles are equal )

[tex]\angle ABO=\angle CDO[/tex] ( Given )

[tex]OB=OD[/tex] (Given )

[tex]\triangle AOB\cong \triangle COD[/tex] ( ASA Postulate )

Answer: ASA only

3. Simplify log3 20 - log3 5

Answers

[tex]\log_320-\log_35=\log_3\dfrac{20}{5}=\log_34[/tex]

Three out of four students in a school said they would vote for nuncio for class president. Predict how many of the 340 students would vote for nuncio

Answers

3/4 = x / 340....3 to 4 students = x to 340 students
cross multiply
(4)(x) = (3)(340)
4x = 1020
x = 1020/4
x = 255 <==

or this way.....

3 out of 4 students.....3/4 = 75%
so 75% of 340 = 0.75(340) = 255 <=

Find the exact values of sin A and cos A. Write fractions in lowest terms. A right triangle ABC is shown. Leg AC has length 15, leg BC has length 20, and hypotenuse AB has length 25.

Answers

sin A = opposite / hypotenuse = BC/AB = 20/25 = 4/5

cos A = adjacent / hypotenuse = AC/AB = 15/25 = 3/5

In the right triangle with sides 15, 20, and 25, the exact values of sin A and cos A are 4/5 and 3/5, respectively.

In the right triangle ABC, we can use the given side lengths to find the trigonometric ratios for angle A. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (AB) is equal to the sum of the squares of the lengths of the legs (AC and BC).

Let's denote the angle A as angle A:

Find sin A:

sin A = (opposite / hypotenuse) = BC / AB = 20 / 25 = 4/5.

Find cos A:

cos A = (adjacent / hypotenuse) = AC / AB = 15 / 25 = 3/5.

So, the exact values are sin A = 4/5 and cos A = 3/5.

In summary, in the right triangle ABC with side lengths AC = 15, BC = 20, and AB = 25, the exact values of sin A and cos A are 4/5 and 3/5, respectively.

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There are (72)3 ⋅ 70 lambs on a farm. What is the total number of lambs on the farm?

Answers

72(3)= 216
216(70)= 15,120

15,120 lambs

Heyyy guys just thought I’d let y’all know the answer is *117649* if you (7^2)^3 that’s the answer and 7^0 is 0 soooo yeah!

A caterer expects a minimum of 160 but no more than 192 people at a wedding. One fruit tray serves 16 people. The compound inequality represents x, the number of fruit trays the caterer should bring to the wedding.

160 ≤ 16x≤ 192

Which is a possible number of fruit trays the caterer might bring to the wedding?

A. 8
B. 10
C. 14
D. 16

Answers

Answer: B) 10

This is because once x is replaced with 16 in the equation, it becomes the number 160, which fits the equation. (it is equal to 160 and less than 192).

All the other numbers are either too large or too small to fit the equation. 

Answer:

b. 10

Step-by-step explanation:

I did the test

PLEASE ANSWER ASAP!!! WORTH 13 POINTS! I need help D:

Lucy's goal for her cycling class at the gym is to burn 450 calories in one hour. The number of calories (c) she actually burns in one hour varies no more than 45 calories. Which inequality below represents this scenario?

A) |c − 450| less than or equal to 45

B) |c + 450| greater than or equal to 45

C) |c − 45| less than or equal to 450

D) |c − 45| greater than or equal to 450

Answers

im  putting the 3rd one but im just guessing sry
i would say its c... yeah its c
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