Answer:
Lisa = 7 hours and 15 minutes
Naila = 10 hours and 45 minutes
Step-by-step explanation:
Naila = N
Lisa = L
Naila worked:
N = 3.5 + L
In total, they worked:
N + L = 18
Lisa worked:
L = h
Substitute values into the total equation
3.5 + L + L = 18
Solve
2L = 14.5
L = 7.25 = 7 hours and 15 minutes
N = 7.25 + 3.5 = 10.75 = 10 hours and 45 minutes
Hope this helps :)
Calculate the cost of spraying a rectangular field 720 m by 500 m with a pesticide at a cost of $23.50 per hectare.
The calculated cost of spraying the rectangular field is $846
Calculating the cost of spraying the rectangular field
From the question, we have the following parameters that can be used in our computation:
Dimension = 720 m by 500 m
Unit cost = $23.50 per hectare
The area of the field is calculated as
Area = 720 m * 500 m
So, we have
Area = 360000 square meters
Converted to hectares, we have
Area = 36 hectares
So, we have
Cost = $23.50 per hectare * 36 hectares
Evaluate
Cost = $846
Hence, the cost of spraying the rectangular field is $846
what is the best estimate for 52% of 320?
Answer:166.4 or 166
Step-by-step explanation:
If cos x = sin(20 + x) ° and 0°
Answer:
x = 35°
Step-by-step explanation:
The question is as following
cos x = sin(20 + x)° and 0° < x < 90° , find X?
==============================================
cos x = sin(20 + x)°
sin and cos are co-functions,
which means that: cos x = cos [90 - (20 + x)]
∴ x = 70 - x
∴ 2x = 70
∴ x = 35°
======================
Note: cos θ = sin ( 90 - θ )
Answer:
x = 35°
Step-by-step explanation:
The question is as following
cos x = sin(20 + x)° and 0° < x < 90° , find X?
==============================================
cos x = sin(20 + x)°
sin and cos are co-functions,
which means that: cos x = cos [90 - (20 + x)]
∴ x = 70 - x
∴ 2x = 70
∴ x = 35°
======================
Note: cos θ = sin ( 90 - θ )
UCULI
2 Points
When is a rhombus a square?
O
A. When its sides are parallel
B. When its angles are right angles
) C. When its angles are convex angles
O
D. When its sides are congruent
SUB
Answer:
B. When its angles are right angles.
Step-by-step explanation:
A rhombus is a quadrilateral with all 4 sides congruent. The sides can be slanted, which would keep it from being a square. If you make all the sides of a rhombus straight vertically and horizontally so you have 4 right angles, you have a square. A square is a quadrilateral with all 4 sides AND all 4 angles congruent.
Estimate each quotient by rounding the dividend and the divisor to the largest place value. 22528 divided by 98
Answer:225.28
Step-by-step explanation: 98 become 100 and 22528 stays the same.
Marla has budgeted $65 per day on food during a business trip. Write a function that is a model for the situation.
A. Not Enough Information
B. f(x) = 65x
C. f(x) = 65
D. f(x) = 65y
Answer:
A
Step-by-step explanation:
That seems like it would be the correct equation.
Answer:
a
Step-by-step explanation:
it is the tell how many days
HELP ASAP. need this done.
Answer:
D. 35
Step-by-step explanation:
[tex]20 \times \frac{7}{4} = 35[/tex]
Good morning,
Answer:
D. 35
Step-by-step explanation:
it Has the ratio of 4 to 7 then
it Has the ratio of 4×5 to 7×5 then
it Has the ratio of 20 to 35.
:)
While on a business trip to Summerfield, Vera treated her co-workers to a meal that cost
$12. Vera knew that when the bill came, she would need to pay Summerfield sales tax of
11.75% and would want to leave a 15% tip on the original $12. Including tax and tip, how
much did Vera's meal cost?
Answer:
$15.21
Step-by-step explanation:
The tax and tip percentages are both being figured on the original bill amount, so they can be added. The tax and tip together come to ...
11.75% +15% = 26.75%
This is added to the original bill amount, so the final total will be ...
$12 + $12×0.2675 = $12×1.2675 = $15.21
Vera's meal cost $15.21.
40% of the memberships sold by Gym A were gold memberships.
25% of the memberships sold by Gym B were gold memberships.
Which statement must be true?
Answer:
a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.
Step-by-step explanation:
Here is the complete question: 40% of the memberships sold by Gym A were gold memberships. 25% of the memberships sold by Gym B were gold memberships.
Which statement must be true?
a) If both gyms sold 80 total memberships, Gym A sold 12 more gold membership.
b) If both gyms sold the same number of memberships, Gym A sold 15 more gold membership.
c) Gym A sold more gold membership than Gym A did.
d) If Gym B sold 50 membership, 25 would be gold memberships.
Given: Gym A have sold 40% gold membership of total membership.
Gym B have sold 25% gold membership of total membership.
Lets take option A first to find if it is true statement.
As per option A, There are total number of membership is 80.
∵ Gym A has sold 40% gold membership.
∴ Gym A gold membership= [tex]40\% \times 80[/tex]
⇒ Gym A gold membership= [tex]\frac{40}{100} \times 80= 32 member.[/tex]
∴ Gym A gold membership= 32.
Now, Gym B
∵ Gym B has sold 25% gold membership.
∴ Gym B gold membership= [tex]25\% \times 80[/tex]
⇒ Gym B gold membership= [tex]\frac{25}{100} \times 80=20 member.[/tex]
∴ Gym B gold membership= 20.
Next finding difference gold membership for Gym A and Gym B
[tex]32-20= 12 \ membership[/tex]
Hence, we can say option A is correct as Gym A have sold 12 more gold membership, if total number of membership sold by both Gym is 80.
Answer:maybve
Step-by-step explanation:
no
A light bulb consumes 5280 watt hours in 5 days and 12 hours, How many watt-hours does it consume per day?
Il watt-hours per day
|
*
$
?
The correct answer is:
The light bulb consumes 1056 watt-hours per day, calculated by dividing the total watt-hours by the total number of days.
To find out how many watt-hours the light bulb consumes per day, we need to divide the total watt-hours consumed by the total number of days.
Given:
- Total watt-hours consumed = 5280 watt-hours
- Total time = 5 days and 12 hours
First, let's convert the total time to hours:
[tex]\[ \text{Total time} = 5 \times 24 \text{ hours} + 12 \text{ hours} = 120 + 12 = 132 \text{ hours} \][/tex]
Now, we can calculate the watt-hours consumed per day:
[tex]\[ \text{Watt-hours per day} = \frac{\text{Total watt-hours}}{\text{Total number of days}} \]\[ \text{Watt-hours per day} = \frac{5280 \text{ watt-hours}}{5 \text{ days}} \]\[ \text{Watt-hours per day} = \frac{5280}{5} \text{ watt-hours} \]\[ \text{Watt-hours per day} = 1056 \text{ watt-hours} \][/tex]
So, the light bulb consumes 1056 watt-hours per day.
given the list of ordered pairs, what is the x intercept (8,10),(3,-4),(0,8),(4,-3),(9,0)
Answer:
The x-intercept is the ordered pair (9,0)
Step-by-step explanation:
we know that
The x-intercept is the value of x when the value of y is equal to zero
so
The x-intercept is a ordered pair with a y-coordinate equal to zero
therefore
In this problem
The x-intercept is the ordered pair (9,0)
The x-intercept from the list of ordered pairs (8,10), (3,-4), (0,8), (4,-3), (9,0) is 9, as it is the x-value of the pair where the y-coordinate is zero.
Explanation:To find the x-intercept from a list of ordered pairs, you need to look for the pair where the y-coordinate is zero. The x-intercept is the x-value in this pair.
From the list of ordered pairs given in the question, which are (8,10), (3,-4), (0,8), (4,-3), (9,0), we identify that the x-intercept is in the pair where y is equal to 0.
Thus, the x-intercept from the list is 9, as it appears in the ordered pair (9,0).
Identify corresponding sides RGK=MQB
Final answer:
In geometry, corresponding sides are sides that have the same relative position in two similar figures. To identify the corresponding sides in the given question, we need to find the sides with the same position in the figures RGK and MQB. The corresponding sides of RGK and MQB are RG = MQ, RK = MB, and GK = QB.
Explanation:
In geometry, corresponding sides are sides that have the same relative position in two similar figures. To identify the corresponding sides in the given question, we need to find the sides with the same position in the figures RGK and MQB.
In this case, RGK and MQB are both triangles, so we need to compare their corresponding sides. The corresponding sides of a triangle are the sides that are in the same position (opposite vertices) in the two triangles.
Therefore, the corresponding sides of RGK and MQB are:
RG = MQ
RK = MB
GK = QB
Hãy tưởng tượng từng chữ cái của từ Toán Toán học được viết trên từng mảnh giấy và đặt trong một cái túi. Bạn nên chọn một chữ cái ngẫu nhiên từ túi đó, xác suất bạn chọn một nguyên âm là gì
Answer:
25% or 1/4. I don't know how to type Vietnamese.
Which function has a domain of x 25 and a range of y s3?
g= x-5+3
9 = x+5 -3
y=-x-5+3
y=-x+5 -3
Answer:
[tex]y = - \sqrt{x - 5} + 3[/tex]
Step-by-step explanation:
The function [tex]y = - \sqrt{x - 5} + 3[/tex] has a domain x ≥ 5.
This is because the function remains real for (x - 5) ≥ 0 as negative within the square root is imaginary.
Hence, (x - 5) ≥ 0
⇒ x ≥ 5
Now, for all x values that are greater than equal to 5 the value of [tex]- \sqrt{x - 5}[/tex] will be negative.
So, [tex]- \sqrt{x - 5} \leq 0[/tex]
⇒ [tex]- \sqrt{x - 5} + 3 \leq 3[/tex]
⇒ y ≤ 3
Therefore, the range of the function is y ≤ 3. (Answer)
A function is shown f=(x)=x^2+ 2X-3
show the X intercepts and maximum or minimum of the function
Answer:
x intercepts at (-3,0), and (1,0)
there is a minimum at (-1,-4)
Step-by-step explanation:
Please see attached image for the requested graph of the function [tex]f(x) = x^2+2x-3[/tex], and observe that the crossings of the x-axis are at the points (-3,0), and (1,0) , marked in red in the image.
We can also see that there is no maximum, but a minimum value, and located at the point (-1,-4) [marked in green in the image]
A rectangle has a height of 2y^3+5 and a width of y^3+6y.
Express the area of the entire rectangle.
Your answer should be a polynomial in standard form.
Answer:
in polynomial form
Step-by-step explanation:
if you have any question then reply me
The area of the rectangle can be found by multiplying its width by its height, which is a polynomial expression in this case.
Explanation:To find the area of a rectangle, we multiply its width by its height. In this case, the width of the rectangle is y3+6y and the height is 2y3+5. So, the area of the rectangle is:
A = width × height
A = (y3+6y) × (2y3+5)
A = 2y^6 + 5y^3 + 12y^4 + 30y
This is the area of the entire rectangle, expressed as a polynomial in standard form.
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3 An equation is shown below.
7x = -56
What value of x makes the equation true?
A X=-63
B x=-8
C x = -0.125
D x = -392
Answer:
Option B is correct.
[tex]x=-8[/tex]
Step-by-step explanation:
Given:
The given equation is.
[tex]7x=-56[/tex]
Solve above equation for value of x.
[tex]7x=-56[/tex]
[tex]x=-\frac{56}{7}[/tex]
[tex]x=-8[/tex]
Therefore. the value of [tex]x=-8[/tex]
Ed Parker joined a health club. There was a $49 registration fee, and a $17.50 monthly fee. If Ed visits the club 2 times a week for a year, what does each workout cost him?
$ per visit.
Answer:
$2.49 per visit
Step-by-step explanation:
Mean or Average Value
It's referred to as the center of a numerical data set. In some circumstances, a list of values needs to be expressed as a single number who best represents them.
The registration fee of the health club is $49. It also charges a $17.50 monthly fee. In one year, the total cost will be $49 + 12*$17.50 = $259. If Ed Parker visits the club 2 times a week for a year, it will make an approximate of 2*52=104 visits a year. The mean cost by visit will be:
$259/104= $2.49 per visit
Answer:
3.55
Step-by-step explanation:
1. Find the equation of the line that is modeled by the values in the table shown below.
A table is given containing the values of x and y.
The equation of the line is modeled by the values in the table.
As we can see in the table, we get to know that;
The y value is increased by 5 whereas the value of x is increased by 2.
So, we will put the numbers over each other for slope.
Therefore, slope=5/2
Now, we will put the slope value in the model equation;
y=mx+b
y=5/2x+b
Now, in the place of y and x we will be putting (2,1) in their place;
1=5/2(2)+b
b=1-5=-4
So, the final equation we get as;
y=5/2x-4
Hence, the equation of the line that is modeled by the values in the table shown is y=5/2x-4.
Whats is an equation?equation, statement of equality between two expressions consisting of variables and/or numbers. In essence, equations are questions, and the development of mathematics has been driven by attempts to find answers to those questions in a systematic way.
What is equation simple?A mathematical equation which represents the relationship of two expressions on either side of the sign. It mostly has one variable and equal to symbol. Example: 2x – 4 = 2.
What is equation and its types?An equation is a statement that says that the value of two mathematical expressions is equal. In simple words, an equation says that two things are equal. It is denoted by the equal to sign '='. Example of an Equation: 8+2= 12-2. The above equation says that the left side of the equation is equal to the right side.
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What is 3and 2 fiths subtract 5 eighths
Answer:
111/40
Step-by-step explanation:
3 2/5=17/5
17/5-5/8=111/40
What’s the answer please?
ans is 9/4 .................
What is the value for y? If a=50, b=2x^2, c=5y+10
Answer:
4x
Step-by-step explanation:
verify rolles theorem for f(x) =x^3-x^2-6x+2 in [0,3]
Answer:
See the explanation.
Step-by-step explanation:
Given function [tex]f(x)=x^3-x^2-6x+2[/tex]
And the interval [tex][0,3][/tex]
According to Rolle's Theorem
Let [tex]f(x)[/tex] be differentiable on the open interval [tex](a,b)[/tex] and continuous on the closed interval [tex][a,b][/tex]. Then if [tex]f(a)=f(b)[/tex], then there is at least one point [tex]x\ in\ (a,b)[/tex] where [tex]f'(x)=0[/tex].
So,
[tex]f(0)=0^3-0^2-6\times0+2\\\\f(0)=2\\\\Similarly\\\\f(3)=3^3-3^2-6\times3+2\\\\f(3)=27-9-18+2\\\\f(3)=2\\\\We\ can\ see\ f(0)=f(3)\\\\Now,\\\\f'(x)=\frac{d}{dx}(x^3-x^2-6x+2)\\\\f'(x)=3x^2-2x-6\\\\put\ f'(x)=0\\\\3x^2-2x-6=0\\[/tex]
We will find the value of [tex]x[/tex] for which [tex]f'(x)[/tex] became zero.
[tex]If\ ax^2+bx+c=0\\\\Then,\ x_{1}=\frac{-b+\sqrt{b^2-4ac}}{2a}\\ \\And\ x_{2}=\frac{-b-\sqrt{b^2-4ac}}{2a}\\\\f'(x)=3x^2-2x+6=0\\a=3,\ b=-2,\ c=6\\\\\ x_{1}=\frac{-(-2)+\sqrt{(-2)^2-4\times3\times(-6)}}{2\times3}\\\\x_{1}=\frac{2+\sqrt{76}}{6}=\frac{2+2\sqrt{19}}{6}\\\\x_{1}=\frac{1+\sqrt{19}}{3}\\\\x_{2}=\frac{-(-2)-\sqrt{(-2)^2-4\times3\times(-6)}}{2\times3}\\\\x_{1}=\frac{2-\sqrt{76}}{6}=\frac{2-2\sqrt{19}}{6}\\\\x_{2}=\frac{1-\sqrt{19}}{3}[/tex]
We can see
[tex]x_{1}=\frac{1+\sqrt{19}}{3}=1.786\\\\and\ 1.786\ is\ in\ [0,3][/tex]
There is at least one point [tex]1.786\ in\ (0,3)[/tex] where [tex]f'(x)=0[/tex].
Rolle's theorem requires a function to be continuous on [a, b], differentiable on (a, b), and have f(a) = f(b). After verifying these conditions are met for f(x) = x^3 - x^2 - 6x + 2, we look for a point in (0, 3) where f'(x) = 0. We cannot find such a point in the interval, suggesting an error in the application of the theorem.
To verify Rolle's theorem for the function f(x) = x^3 - x^2 - 6x + 2 in the interval [0,3], we need to ensure that the function meets the criteria stated by the theorem:
The function f must be continuous on the closed interval [a, b].
The function f must be differentiable on the open interval (a, b).
The function f must satisfy f(a) = f(b).
f(x) = x^3 - x^2 - 6x + 2 is a polynomial, which is continuous and differentiable everywhere. Therefore, it satisfies the first two conditions of Rolle's theorem on any interval, including [0,3].
Now we need to check the third condition:
f(0) = (0)^3 - (0)^2 - 6(0) + 2 = 2
f(3) = (3)^3 - (3)^2 - 6(3) + 2 = 2
Since f(0) = f(3), the third condition is also met. Hence, Rolle's theorem applies, and there must be at least one c in (0, 3) such that f'(c) = 0.
To find c, we take the derivative of f(x):
f'(x) = 3x^2 - 2x - 6
Set f'(x) equal to zero and solve for x:
3x^2 - 2x - 6 = 0
Factors into (3x + 2)(x - 3) = 0
So x can be either x = -2/3 or x = 3. Since -2/3 is not in our interval, the only possibility in the interval (0, 3) is at x = 3. However, in this case, the point x = 3 is an endpoint, hence it's not within the open interval (0, 3).
Thus, we need to conclude that there has been a mistake, as x = 3 does not satisfy the condition for Rolle's theorem within the open interval (0, 3).
The sides of the base of this square right prism are 16 centimeters each and the height of the prism is 10 centimeters. What is the surface area of the prism? A.964 B.1000 C.1152 D.1232
The width (W) of the prism is 16 cm.
The length (L) of the prism is 16 cm.
The height (H) of the prism is 10 cm.
The formula for the surface area of any right prism with width W, length L, and height H is the following:
A = 2 (WL + LH + WH)
Substituting using our given values changes the equation to:
A = 2 (16*16 + 16*10 + 16*10)
= 2 (256 + 160 + 160) = 2 (576)
= 1152
Thus, the surface area is 1152 cm².
Let me know if you need any clarifications, thanks!
Answer:
1152
Step-by-step explanation:
following frequency distribution shows the daily expenditure on milk of 30 households in a locality:Daily expenditure on milk(in Rs):0-30,30-60,60-90,90-120,120-150 No.of households:5,6,9,6,4
Note: As you missed to identify what we have to find in this question. But, after a little research, I am able to find that we had to find the Mode for the data given in your question. So, I am assuming we have to calculate the the Mode. Hopefully, it would clear your concept regarding this topic.
Answer:
The mode of the data = 75
Step-by-step explanation:
Lets visualize the given data in a table to show the frequency distribution:
Daily expenditure on milk (in Rs) Number of households
0-30 5
30-60 6
60-90 9
90-120 6
120-150 4
Here the maximum frequency is 9.
So, modal class is 60-90.
As the formula to calculate the mode:
[tex]Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )[/tex]
Here, the maximum
[tex]l_{1} =60, f_{1} =9, f_{0}=6, f_{0}=6, h=30[/tex]
[tex]l=[/tex] is the lower limit of the class
[tex]f_{1} =[/tex] is the frequency of the modal class
[tex]f_{0} =[/tex] is the frequency of the previous modal class
[tex]f_{2} =[/tex] is the frequency of the next previous modal class
[tex]l=[/tex] is the class size
So,
[tex]Mode = l_{1} + h (\frac{f_{1}-f_{0}}{2f_{1}-f_{0}-f_{2}} )[/tex]
[tex]Mode = 60 + 30 (\frac{9-6}{2(9)-6-6} )[/tex]
[tex]Mode = 60 + \frac{(30)(3)}{6}[/tex]
[tex]Mode = 60 + 15=75[/tex]
∴ The mode of the data = 75
Keywords: mode, frequency distribution
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Question1: A ball is shot from a cannon into the air with an upward velocity of 10 ft/sec. The function h(t) =-2t^2 + 10t + 12= represents the height (h) of the ball after t seconds. 1. Determine what is the axis of symmetry of the function? 2. Identify the roots of the quadratic function? 3. What is the y-intercept of the quadratic function? .4.) Determine the vertex of the function?
Answer:
1) [tex]x=\dfrac{5}{2}[/tex]
2) [tex]t_1=-1[/tex] and [tex]t_2=6[/tex]
3) (0,12)
4) [tex]\left(\dfrac{5}{2},\dfrac{49}{2}\right)[/tex]
Step-by-step explanation:
The function [tex]h(t) =-2t^2 + 10t + 12[/tex] represents the height (h) of the ball after t seconds.
Find the vertex of the parabola:
[tex]t_v=-\dfrac{b}{2a}=-\dfrac{10}{2\cdot (-2)}=\dfrac{5}{2}\\ \\h_v=h\left(\dfrac{5}{2}\right)=-2\cdot\left(\dfrac{5}{2}\right)^2+10\cdot \dfrac{5}{2}+12=-2\cdot \dfrac{25}{4}+25+12=-\dfrac{25}{2}+37=\dfrac{49}{2}[/tex]
Hence, the vertex of the function is at point [tex]\left(\dfrac{5}{2},\dfrac{49}{2}\right).[/tex]
The axis of symmetry of the function is vertical line which passes through the vertex, so its equation is
[tex]x=\dfrac{5}{2}[/tex]
To find y-intercept, equat t to 0 and find h:
[tex]h=-2\cdot 0^2+10\cdot 0+12=12[/tex]
Hence, y-intercept is at point (0,12)
To find the roots of the quadratic finction, equate h to 0 and solve the equation for t:
[tex]h=0\Rightarrow -2t^2+10t+12=0\\ \\t^2-5t-6=0\ [\text{Divided by -2}]\\ \\D=(-5)^2-4\cdot 1\cdot (-6)=25+24=49\\ \\t_{1,2}=\dfrac{-(-5)\pm \sqrt{49}}{2\cdot 1}=\dfrac{5\pm 7}{2}=6,\ -1[/tex]
Therefore, two roots are [tex]t_1=-1[/tex] and [tex]t_2=6[/tex]
Determine the corresponding y-value for x = 35 using y = -x + 175 (slope-intercept form of the equation of a line
Answer:
Step-by-step explanation:
when x=35
y=-35+175=140
When Amy roller-skates, she moves 110 yards per minute. What is her speed in miles per hour? Round your answer to the nearest hundredth. (Hint: 1 yd= 3 ft; 5280 ft = 1 yd.; 60 min= 1 hr)
Answer:
Speed of Amy is 3.75 miles per hour.
Step-by-step explanation:
We have, speed of Amy = 110 yards per minute
This means, she covers 110 yards of distance in 1 minute.
Now, to convert the speed of Amy into miles per hour, we will first convert the distance from yards into miles and then convert time from minutes to hour.
We know that,
1 yard = 3 feet
∴ 110 yards = 3 × 110 feet = 330 feet
Now, we also know that,
5280 feet = 1 mile
∴ 1 feet = [tex]\frac{1}{5280}[/tex] miles
So, 330 feet = [tex]\frac{1}{5280}\times330[/tex] = [tex]\frac{1}{16}[/tex] miles
∴ 110 yards = 330 feet = [tex]\frac{1}{16}[/tex] miles
Now, 60 min = 1 hr
∴ 1 min = [tex]\frac{1}{60}[/tex] hrs
So, 110 yards = [tex]\frac{1}{16}[/tex] miles and 1 min = [tex]\frac{1}{60}[/tex] hr
So, we can say that, Amy covers a distance of [tex]\frac{1}{16}[/tex] miles in
[tex]\frac{1}{60}[/tex] hr.
We know that,
[tex]speed=\frac{distance}{time}[/tex]
[tex]speed=\frac{(\frac{1}{16}) miles}{(\frac{1}{60})hr}[/tex]
[tex]speed=\frac{60}{16} miles/hr = 3.75 miles/hr[/tex]
Therefore, the speed of Amy in miles/hr is 3.75 miles/hr.
A taxi covers a certain distance in 5 hours and the speed of 60 k/ml how much time will the taxi take to cover the same distance at a speed of 70 km/h
It will take [tex]4\frac{2}{7}\ hours[/tex] to cover same distance.
Step-by-step explanation:
Given,
Time period = 5 hours
Speed = 60 km/h
Distance = Speed * Time
Distance = 60*5 = 300 km
Now,
Distance = 300km
Speed = 70 km/h
Distance = Speed * Time
Time = [tex]\frac{Distance}{Speed}[/tex]
[tex]Time=\frac{300}{70}\\\\Time=\frac{30}{7}\\\\Time= 4\frac{2}{7}\ hours[/tex]
It will take [tex]4\frac{2}{7}\ hours[/tex] to cover same distance.
Keywords: speed, distance
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help me and i’ll mark you brainliest plus you get 20 points !!!!
Answer:
Angle bisector
Step-by-step explanation:
Find the measure of the angle COA. By angle addition postulate,
[tex]m\angle COX=m\angle AOX+m\angle COA[/tex]
From the diagram,
[tex]m\angle COX=80^{\circ}\\ \\m\angle AOX=40^{\circ},[/tex]
then
[tex]80^{\circ}=m\angle COA+40^{\circ}\\ \\m\angle COA=80^{\circ}-40^{\circ}=40^{\circ}[/tex]
Find the measure of the angle BOA. By angle addition postulate,
[tex]m\angle BOX=m\angle AOX+m\angle BOA[/tex]
From the diagram,
[tex]m\angle BOX=60^{\circ}\\ \\m\angle AOX=40^{\circ},[/tex]
then
[tex]60^{\circ}=m\angle BOA+40^{\circ}\\ \\m\angle BOA=60^{\circ}-40^{\circ}=20^{\circ}[/tex]
Find the measure of the angle COB. By angle addition postulate,
[tex]m\angle COX=m\angle BOX+m\angle COB[/tex]
From the diagram,
[tex]m\angle BOX=60^{\circ}\\ \\m\angle COX=80^{\circ},[/tex]
then
[tex]80^{\circ}=m\angle COB+60^{\circ}\\ \\m\angle COB=80^{\circ}-60^{\circ}=20^{\circ}[/tex]
This means, the measures of angles COB and BOA are the same and are equal half the measure of angle COA, so angles COB and BOA are congruent. This means, the ray OB is the angle bisector of angle COA