Answer: $69.30 per share (rounded up to the nearest penny)
Step-by-step explanation:
51.33 x 0.35 = 17.9655 (this is the increased value in the stock)
51.33 + 17.9655 = 69.2955
Which inequality is true? Use the number line to help.
Answer:
C) -1.5 < -0.5
The solution to the system of equation
-8x+4y=24
Answer:
x-intercept=(-3,0) y-intercept= (0,6)
Step-by-step explanation:
Hopefully this is the answer you wanted if not please let me know by commenting
Use the Law of Sines to solve the triangle. (Let b = 47.7 yd. Round your answers for a and c to two decimal places.)
Answer:
C = 68.667°
a = 123.31 yd.
c = 114.90 yd.
Step-by-step explanation:
The missing image for the question is attached to this solution.
In the missing image, a triangle AB is given with angles A and B given to be 88° 35' and 22° 45' respectively
We are them told to find angle C and side a and c given that side b = 47.7 yd.
A = 88° 35' = 88° + (35/60)° = 88.583°
B = 22° 45' = 22° + (45/60)° = 22.75°
The sum of angles in a triangle = 180°
A + B + C = 180°
C = 180° - (A + B) = 180° - (88.583° + 22.75°) = 68.667°
The sine law is given as
(a/sin A) = (b/sin B) = (c/sin C)
Using the first two terms of the sine law
(a/sin A) = (b/sin B)
a = ?
A = 88.583°
b = 47.7 yd.
B = 22.75°
(a/sin 88.583°) = (47.7/sin 22.75°)
a = (47.7 × sin 88.583°) ÷ sin 22.75°
a = 123.31 yd.
Using the last two terms of the sine law
(b/sin B) = (c/sin C)
b = 47.7 yd.
B = 22.75°
c = ?
C = 68.667°
(47.7/sin 22.75°) = (c/sin 68.667°)
c = (47.7 × sin 68.667°) ÷ sin 22.75°
c = 114.90 yd.
Hope this Helps!!!
Bin $A$ has one white ball and four black balls. Bin $B$ has three balls labeled $\$1$ and one ball labeled $\$7$. Bin $W$ has five balls labeled $\$8$ and one ball labeled $\$500$. A game is played as follows: a ball is randomly selected from bin $A$. If it is black, then a ball is randomly selected from bin $B$; otherwise, if the original ball is white, then a ball is randomly selected from bin $W$. You win the amount printed on the second ball selected. What is your expected win
Answer:
$20
Step-by-step explanation:
Bin A: Bin B: Bin W:
white ball: 20% $1: 75% $8: 5/6
black ball: 80% $7: 25% $500: 1/6
first we can calculate the expected return of bins B and W:
expected return if the ball is black = ($1 x 75%) + ($7 x 25%) = $2.50
expected return if the ball is white = ($8 x 5/6) + ($500 x 1/6) = $90
expected return of the game = (expected return of a black ball x probability of choosing a black ball) + (expected return of a white ball x probability of choosing a white ball) =($2.50 x 80%) + ($90 x 20%) = $2 + $18 = $20
Answer:
$20
Step-by-step explanation:
Since Bin A has one white ball and four black balls, the money ball has a 1/5 chance of coming from Bin W and a 4/5 chance of coming from Bin B. The total expected value therefore is $E = 1/5E_W+4/5E_B, where E_W and E_B are the expected values of a ball drawn from bins W and B, respectively. Since Bin W has five 8 dollar balls and one 500 dollar ball, its expected value is E_W = 5/6*8 + 1/6*500 = 90. Since Bin B has three 1 dollar balls and one 7 dollar ball, its expected value is E_B = 3/4*1 + 1/4*7 = $2.5. Therefore E = 1/5E_W + 4/5E_B = 1/5*90 + 4/5*2.5 = 20
Binomial Distribution Problem 1: (a) An urn contains 1000 balls, 100 are green and 900 are white. One ball is chosen from the urn 100 times with replacement. Use Excel (binom.dist) to find the probability that six or seven green balls are selected. (b) An urn contains 1000 balls, 100 are green and 900 are white. One ball is chosen from the urn 1000 times. Use Excel (binom.dist) to find the probability that between 110 and 120 of the balls, inclusive, are green. (c) Redo (a) and (b) again using Excel but use the normal approximation (normal.dist). How do the answers compare with the above? Are there any discrepancies? If so, please explain why they happened. Please submit your answers on an excel spreadsheet.
Find the attachments for solution and explanation
The student's question regards calculating binomial probabilities and normal approximations using Excel. Precise probabilities are found using the BINOM.DIST function, and normal approximations are made with NORM.DIST. Discrepancies can arise due to the approximation not perfectly representing the discrete binomial outcomes.
In solving problems using binomial probabilities with Excel, the function =BINOM.DIST(number_s, trials, probability_s, cumulative) is used to calculate the probability of a specified number of successes in a series of independent trials. In problem (a), to find the probability that six or seven green balls are selected, we would use =BINOM.DIST(6, 100, 0.1, FALSE) and =BINOM.DIST(7, 100, 0.1, FALSE) adding both probabilities together. For problem (b), to find the probability that between 110 and 120 green balls are chosen, we calculate the cumulative probability for 120 and subtract the cumulative probability for 109 using =BINOM.DIST(120, 1000, 0.1, TRUE) - BINOM.DIST(109, 1000, 0.1, TRUE).
The normal approximation can be applied to the binomial distribution when the number of trials is large and the success probability is not too close to 0 or 1, using Excel's =NORM.DIST(x, mean, standard_dev, cumulative) function. Comparing the results of the normal approximation with the exact binomial probabilities may reveal discrepancies due to the approximation being less accurate for probabilities that are far from the mean, especially when the success probability (p) is not near 0.5, or when the number of trials (n) is not large enough. These discrepancies are due to the smooth curve assumption in the normal distribution approximation, which may not perfectly represent the discrete nature of binomial outcomes.