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Related Questions
what is the slope of the line given by the equation y=2.3x
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making the slope of this equation 2.3
I believe this is the correct answer. I hope it helps.
Find the coordinates of the other endpoint of the segment with the given endpoint (6,2) and midpoint (2,0)
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Need help doing this problem!!
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6x + 4x + 10 = 90 (the 90 is from the right angle)
You then combine like terms.
10x + 10 = 90
To isolate the variable you need to subtract 10 to both sides leaving you with...
10x = 80
Then you divide 10 from both sides and your final answer is x=8.
Lets check our work shall we???
6(8) +4(8) + 10 = 90
48 + 32 + 10 = 90
48 + 42 = 90
90 = 90
It is a solution! Yayyyyy!!!! So 8 is your answer. I hope this helps love! :)
What is the standard form of the following equation?
y=−2/5x+4 Use integers for A, B, and C. Enter your answer in the box.
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so
[tex] \frac{-2}{5} x -y=-4 [/tex]
multiply by -1 to make the x coefficient positive
[tex] \frac{2}{5} x+y=4 [/tex]
so we multiply by 5 to make them integers
[tex]2x+5y=20[/tex]
A=2,B=5,C=20
Which statement best explains whether △PQR is congruent to △XYZ?
△PQR is congruent to △XYZ because △PQR can be mapped to △XYZ by a rotation of 180° about the origin.
△PQR is congruent to △XYZ because △PQR can be mapped to △XYZ by a translation 5 units down followed by a reflection across the y-axis.
△PQR is not congruent to △XYZ because there is no sequence of rigid motions that maps △PQR to △XYZ.
△PQR is congruent to △XYZ because △PQR can be mapped to △XYZ by a reflection across the y-axis followed by a reflection across the x-axis.
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I feel really stupid but how do you solve: v+9/3+8
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The answer is v +11.
The answer would be simply
V 11
Name 3 decimals between 16.4 and 16.5 draw a number line estmating the placement of all five decimals
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Factor this expression completely.
mn - 4m - 5n + 20
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Factor by grouping.
[tex]mn-4m-5n+20[/tex]
[tex]m(n-4)-5(n-4)[/tex]
Find the GCF.
[tex](n-4)(m-5)[/tex]
Hope this helps.
-Benjamin
Heather works as a waitress at her family`s restaurant. she works 2 hours every morning during the breakfast shift and returns to work work each evening for the dinner shift. In the last 4 days ,she worked 28 hours. If Heather works the same number of hours every evening, how many hours did she work during each dinner shift?
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2 hours x 4 days = 8 hours
Subtract,
28 hours - 8 hours = 20 hours
Divide
20 hours ÷ 4 days = 5 hours each day.
Check you work by Multiplying and adding
5 hours x 4 days = 20
20 hours + 8 hours = 28 hours
Heather worked 5 hours each dinner shift
REALLY NEED HELP PLEASE!!
The Smith family rented a recreational vehicle for a seven-day vacation. The cost to rent the recreational vehicle was $560 plus $0.50 per mile. How many miles were driven if the total cost was $1350?
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Its 790
$0.50(x) = $1350 - $560
x = $790/$0.50
x = 1,580 miles
Sarah has a collection of nickels, dimes, and quarters worth $13.80. she has 10 more dimes than nickels and twice as many quarters as dimes. how many coins of each kind does she have?
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22 dimes = $2.20
44 quarters = $11.00
11.00
2.20
+ .60
———
13.80
Is - √3 a real number, whole number, natural number, rational number, irrational number, an integer, or imaginary number?
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what are the zeros of the quadratic function f(x)=8x2-16x-15
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Answer: The zeroes of the given polynomial f(x) are
[tex]x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]
Step-by-step explanation: We are given to find the zeroes of the quadratic function below:
[tex]f(x)=8x^2-16x-15.[/tex]
To find the zeroes, we must find the roots of the following equation
[tex]f(x)=0\\\\\Rightarrow 8x^2-16x-15=0~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex].
We know that the roots of the quadratic equation of the form [tex]ax^2+bx+c=0,~a\neq 0[/tex] is given by
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}.[/tex]
In the given quadratic equation , a = 8, b = -16 and c = - 15.
Therefore, the roots of the equation are
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\\\\Rightarrow x=\dfrac{-(-16)\pm\sqrt{(-16)^2-4\times 8\times (-15)}}{2\times 8}\\\\\\\Rightarrow x=\dfrac{16\pm\sqrt{256+480}}{16}\\\\\\\Rightarrow x=\dfrac{16\pm\sqrt{786}}{16}\\\\\\\Rightarrow x=\dfrac{16\pm4\sqrt{46}}{16}\\\\\\\Rightarrow x=\dfrac{4\pm\sqrt{46}}{4}\\\\\\\Rightarrow x=1\pm\sqrt{\dfrac{46}{16}}\\\\\\\Rightarrow x=1\pm\sqrt{\dfrac{23}{8}}\\\\\\\Rightarrow x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]
Thus, the zeroes of the given polynomial f(x) are
[tex]x=1-\sqrt{\dfrac{23}{8}},~~~x=1+\sqrt{\dfrac{23}{8}}.[/tex]
Option (C) is correct.
The zeroes of the given polynomial f(x) = 8x^2-16x-15 are x = 1 + [tex]\sqrt{23}[/tex] / 8 and x = 1 -[tex]\sqrt{23}[/tex] / 8 Thus, Option C is correct.
What is a quadratic equation?A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
We are given to find the zeroes of the quadratic function f(x) = 8x^2 - 16x-15
f(x) = [tex]8x^2-16x-15[/tex] = 0
We know that the roots of the quadratic equation ax² + bx + c = 0 is
x = -b ± [tex]\sqrt{b^2 - 4ac}[/tex] / 2a
In the given quadratic equation , a = 8, b = -16 and c = - 15.
So,
x = -b ± [tex]\sqrt{b^2 - 4ac}[/tex] / 2a
x = -(-16) ± [tex]\sqrt{(-16)^2 - 4(8)(-15)}[/tex] / 2(8)
x = 16 ± [tex]\sqrt{256+ 480}[/tex] / 16
x = 16 ± [tex]\sqrt{786}[/tex] / 16
x = 4 ± [tex]\sqrt{46}[/tex] / 4
x = 1 ± [tex]\sqrt{23}[/tex] / 8
Thus, the zeroes of the given polynomial f(x) are
x = 1 + [tex]\sqrt{23}[/tex] / 8 and x = 1 -[tex]\sqrt{23}[/tex] / 8. Option C is correct.
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How to do this ?? How
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The two bars | | is used to indicate the function absolute value.
Remember this definition:
| x | = - x if x < 0 and x if x > 0
So, | x | > c =>
x > c or x > - c
Therefore:
|ax - b| > c => ax - b > c or ax - b > - c
That is the third option of the answer list.
Please help with this equation!!! 30 points!
The following equation is shown.
[tex] x^{2} - \sqrt{2.5} -l + ( -\pi + z ) = A[/tex]
Solve for the variable z.
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z= -x²+l+4.72273148+A
Solve quadratic equations using completing the square then write in vertex form
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Assuming you have;
ax²+bx+c=y
a(x²+b/ax)+c=y
a(x²+b/ax+(b/2a)²-(b/2a)²)+c=y
a(x²+b/ax+(b/2a)²)+c-a(b/2a)²=y
a(x+b/2a)²+c-a(b/2a)²=y
Try to use this format to solve the problems.
Hope I helped :)
The 440 yard dash in track has been replaced by the 400 meter dash. which is the longer distance and by how many meters? hint: 1 yard = 3 feet
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Final answer:
The 400 meter dash is the longer distance by 2.336 meters.
Explanation:
In order to determine which is the longer distance, we need to convert both the 440 yards and the 400 meters into the same unit of measurement. Since 1 yard is equal to 0.9144 meters, we can convert the 440 yards into meters by multiplying it by 0.9144:
440 yards * 0.9144 meters/yard = 402.336 meters
Therefore, the 400 meter dash is the longer distance by 2.336 meters.
Soda is sold in aluminum cans that measure 6 inches in height and 2 inches in diameter. how many cubic inches of soda are contained in a full can?
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v=πr²h (now put in the values to find volume)
v=π(1)²(6)
v=18.85 inches cubed
Therefore, 18.85 inches cubed can be fit into the full can.
Hope I helped :)
A cylinder is a three-dimensional figure that has a radius and a height.
The volume of a cylinder is given as:
Volume = π r²h
The amount of soda in a full can is 18.84 cubic inches.
What is a cylinder?A cylinder is a three-dimensional figure that has a radius and a height.
The volume of a cylinder is given as:
Volume = π r²h
Example:
The volume of a cup with a height of 5 cm and a radius of 2 cm is
Volume = 3.14 x 2 x 2 x 5 = 62.8 cubic cm
We have,
Aluminum cans:
Height = 6 inches
Diameter = 2 inches
Radius = diameter/2 = 2 / 2 = 1 inches
The aluminum can is in the shape of a cylinder.
The volume of the aluminum can:
= πr²h
= 22/7 x 1 x 1 x 6
= 18.84 cubic inches
The amount of soda in a full can is 18.84 cubic inches.
Thus,
The amount of soda in a full can is 18.84 cubic inches.
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how do you find the derivative of 4
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by rule the derivative of a constant is 0
so the answer for this is 0
What is the answer for 35=-7z
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TEXASCHIC! :)
1. Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 51 km/h. After five hours, the velocity of the car is 59 km/h.
Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. (5 points)
Part B: How can you graph the equation obtained in Part A for the first six hours? (5 points)
My answer:
Part A:
y - 51 = 59 - 51 / 5 - 3 (x-3)
y - 51 = 4 (x-3)
y = 4x -12 + 51
y= 4x + 39
where x is the time and y is the velocity of car at any time x.
Part B:
y =4 * 6 + 39 = 24 + 39 = 63 ~km/h
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slope = (59 - 51) / (5 - 3) = 8/2 = 4
y = mx + b
slope(m) = 4
(3,51)...x = 3 and y = 51
sub and find b, the y int
51 = 4(3) + b
51 = 12 + b
51 - 12 = b
39 = b
so ur equation is : y = 4x + 39...but u need it in standard form
y = 4x + 39
-4x + y = 39
4x - y = -39 <==== this is ur equation...x = number of hrs and y = total velocity
====================
ur x axis is the number of hrs
ur y axis is total velocity in km
y = 4x + 39......slope = 4.....y int = (0,39)....x int is (- 9.75,0) or -9 3/4 for graphing purposes)....so start at (-9.75,0)...and since the slope is 4, go up 4 and to the right 1....plot that...then up 4 and to the right 1...plot that...u will cross the y axis at (0,39)....and just connect ur plotted points and u have ur line......or what u can do since it is asking for the first 6 hrs....sub in 1 for x and solve for y....then sub in 2 for x and solve for y...keep doing this up till 6 and u will have ur line up till 6 hrs
The velocity of the car is represented by the equation y = 4x + 39, where 'x' is time and 'y' is the velocity. You can graph this for the first six hours by substituting x=6 to find: y=63 km/h. Thus, the car's velocity after six hours would be 63 km/h.
Explanation:In order to solve this problem, we first find the equation representing the change in the car's velocity. The point (3, 51) represents the condition that after three hours, the car is moving at 51 km/h. Similarly, the point (5, 59) stands for the velocity being 59 km/h after five hours. We derive the slope of the line connecting these two points by subtracting the y-coordinates and dividing by the difference of the x-coordinates, (59-51)/(5-3) = 4.
This slope represents an increase of 4 km/h for every hour that passes. Our equation then becomes y - 51 = 4(x - 3) which simplifies to y = 4x + 39. In this equation, 'x' represents time in hours and 'y' is the car's velocity at any given time 'x'.
For Part B, we graph the equation over the first six hours by inputting x=6 into the equation, giving us y = 4*6 + 39 = 63 km/h. Therefore, after six hours, the car would be moving at a velocity of 63 km/h.
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MATH HELP 20 POINTS!!!
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A) Variable = x ( miles Tim walked )
B) Tim walked X miles, Molly walked 4+x miles ( 4 more than Tim)
Equation: x + x+4 = 10
C) x +x+4 = 10
2x+4 = 10
2x =6
x = 3
D)
Tim walked 3 miles, Molly walked 7 miles
Help me please thanks
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Write the fraction 20/32 in simplest form.
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The fraction given 20/32 can be written as 5/8 in its simplest form.
How to simplify fractions?The principle of simplifying fraction is to make both the numerator and the denominator smaller numbers but as proportional as the original fraction. This is convenient for mathematical operations and even for understanding proportions.
Now, to simplify fractions we need to divide the nominator and the denominator, the process is shown below:
20/32 divide both numbers by 420/ 4 = 532/ 4 = 8This means the new fraction is 5/8.
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The clean up hitter on a baseball tean batted 1/3 of the runs the team scored. The hitter batted in 3 runs. Select the equation that represents the number of n of runs the team scored. Then solve the equation:
a.1/3n=3B.n/3=1/3C.3n=1/3D.3n=9
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a. 1/3 (n)=3
n=9
annie dome worked from 8:15 am to 11:45 am and from 12:30 pm to 4:15 pm. How many hours did she work? (include steps on how to do this problem)
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How does the volume of a cone compare to the volume of a cylinder with the same radius and height?
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cone volume: π * r^2 * h/3
cylinder volume: π * r^2 * h
Now if you compare both of them with information that the radius and height is same, then the cone:cylinder volume ratio would be:
Cone volume/cylinder volume=
π * r^2 * h/3 / π * r^2 * h= 1/3
Cone volume is 1/3 of cylinder volume
If TOWN A has a yearly population of 3,225 and is growing by 100 people each year and TOWN B has a yearly population of 3,300 and is growing by 75 people per year, after how many years will the two populations be equal?
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so Town A arithmetic progressive expression =
tn=3225+(n-1)100
tn= 3225+100n-100 = 3125+100n
for Town B you have
tn= 3300+(n-1)75 = 3300+75n-75 = 3225+75n
equating both A and B
3125+100n=3225+75n
100n-75n=3225-3125
25n= 100
n=100÷25=4
n=4years
they'll be equal after 4years
Evaluate the determinant for the following matrix [144] [522] [155]
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1 4 4
5 2 2
1 5 5
=> Determinant =
1 * (2*5 - 2*5) - 4 * (5*5 - 1*2) + 4 * ( 5*5 - 2*1)
= 1*(10 - 10) - 4*(25 - 2) + 4*(25 -2) = 1*0 + 4* 23 + 4*(25 - 2) = 0 - 4*23 + 4*23 = 0
Answer: 0
The volume of air inside a rubber ball with radius r can be found using the function v(r)=4/3 πr3 . What does v[5/7] represent?
a. the radius of the rubber ball when the volome equals 5/7 cubic feet
b. the volome of the rubber ball when the radius equals 5/7 feet
c. that the volume of the rubber ball is 5 cubic feet when the radius is 7 feet
d. that the volume of the rubber ball is 7 cubic feet when the radius is 5 feet
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we know that
The volume of a sphere (rubber ball) is equal to
[tex]V=\frac{4}{3} \pi r^{3}[/tex]
where
r is the radius of the sphere (rubber ball)
The volume in function notation is equal to
[tex]V(r)=\frac{4}{3} \pi r^{3}[/tex]
in this problem we have
[tex]V(\frac{5}{7})[/tex]
that means
The radius of the rubber ball is [tex]\frac{5}{7}\ ft[/tex]
and
The volume of the rubber ball is [tex]V(\frac{5}{7})\ ft^{3}[/tex]
therefore
the answer is the option B
the volume of the rubber ball when the radius equals [tex]5/7[/tex] feet