How many neutrons are found in a stable isotope of uranium-235?
thx but it's actually 143
The last step is to calculate the percent by mass of each element in ammonium nitrate (NH4NO3). The masses of the elements in one mole of the compound are: mass N = 28.0 g mass H = 4.0 g mass O = 48.0 g The molar mass of the compound is 80.0 g/mol. What is the mass of one mole of the compound?
The last step is to calculate the percent by mass of each element in ammonium nitrate (NH4NO3). The masses of the elements in one mole of the compound are: mass N = 28.0 g mass H = 4.0 g mass O = 48.0 g The molar mass of the compound is 80.0 g/mol. What is the mass of one mole of the compound? 80.0g
Answer: 80 g
Explanation:Molar mass of the compound is the mass of 1 mole of compound which is the sum of masses of each element.
Mass of 1 mole of compound=mass of nitrogen + mass of hydrogen+ mass of oxygen= 28+4+48 = 80 g.
Percentage by mass of nitrogen=[tex]\frac{\text {mass of nitrogen}}{\text {Total mass}}\times 100\ %[/tex]
Percentage by mass of nitrogen=[tex]\frac{28}{80}\times 100\%=35\%[/tex]
Percentage by mass of hydrogen=[tex]\frac{\text {mass of hydrogen}}{\text {Total mass}}\times 100\%[/tex]
Percentage by mass of hydrogen=[tex]\frac{4}{80}\times 100\%=5\%[/tex]
Percentage by mass of oxygen=[tex]\frac{\text {mass of oxygen}}{\text {Total mass}}\times 100\%[/tex]
Percentage by mass of oxygen=[tex]\frac{48}{80}\times 100\%=60\%[/tex]
The attraction of water molecules to one another is known as:
Surface tension
Cohesion
Capillary action
Adhesion
What is the charge of a hypothetical ion with 85 protons and 87 electrons?
Draw the electron-dot structure for chclo. draw the molecule by placing the atoms on the grid and connecting them with bonds. include all lone pairs of electrons.
Answer :
Electron-dot structure : It is also known as Lewis-dot structure. It shows the bonding between the atoms of a molecule and it also shows the unpaired electrons present in the molecule. The valence electrons are represented by 'dot'.
The given molecule is, [tex]CHClO[/tex]
As we know that carbon has '4' valence electrons, hydrogen has '1' valence electron, chlorine has '7' valence electrons and oxygen has '6' valence electrons.
Therefore, the total number of valence electrons in, [tex]CHClO[/tex] = 4 + 1 + 7 + 6 = 18
According to electron-dot structure, there are 8 number of bonding electrons and 10 number of non-bonding electrons.
The electron-dot structure of [tex]CHClO[/tex] is shown below.
Lewis-dot structure is another name for the electron-dot structure. It displays the bonds that exist between a molecule's atoms, as well as the unpaired electrons that are present there. 'Dot' stands in for the valence electrons.
The electrons that make up an atom's valence shell are shown by an electron dot structure, commonly referred to as a Lewis dot formula. Knowing the compound's chemical formula makes drawing electron dot diagrams possible.
The diagram of the electron-dot structure for CHClO is attached in the image below.
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Both sublimation and ———— occur only on the surface of a substance.
In class, sam learned that some theorists link happiness to productivity. from this, he developed the thought that happy employees in a factory will produce more products per hour. in this example, sam's theory led him to _____.
In the given example, it led Sam’s theory to produce a hypothesis. It is because the educated guess that he has made has been linked to the theory where in the theory is about happiness and production that led him to think that having happy employees will make more products to be produced.
Sodium (Na) and potassium (K) are in the same group in the periodic table. Sodium is in the 11th position. How many valence electrons does potassium have?
0
1
9
11
Answer: Option (b) is the correct answer.
Explanation:
As it is known that both sodium and potassium are same group elements. Both of then belongs to group 1A.
Since, sodium is at 11th position in the periodic table and its atomic number is also 11. Therefore, electronic distribution of sodium is 2, 8, 1.
Similarly, potassium is placed at 19th position in the periodic table and its atomic number is 19. So, electronic distribution of potassium is 2, 8, 8, 1.
It is known that valence electrons are the electrons present in the outermost shell of an atom.
So, in a potassium atom there is only one valence electron is present.
Thus, we can conclude that potassium have 1 valence electron.
how many moles of oxygen atoms are in 2 moles of Na3PO4?
In 2 moles of Na₃PO₄ the number moles of oxygen atom is c. 8.
To determine the number of moles of oxygen atoms in 2 moles of Na₃PO₄, we first need to understand the chemical formula of sodium phosphate (Na₃PO₄).
The chemical formula of sodium phosphate is Na₃PO₄.
This means that in one molecule of Na₃PO₄ , there are 3 sodium (Na) atoms, 1 phosphorus (P) atom, and 4 oxygen (O) atoms.Given that we have 2 moles of Na₃PO₄, we can calculate the total number of oxygen atoms present in these 2 moles by using the following steps:
1. Calculate the molar mass of Na₃PO₄:
Molar mass of Na = 22.99 g/molMolar mass of P = 30.97 g/molMolar mass of O = 16.00 g/molMolar mass of Na₃PO₄ = (3 molar mass of Na) + molar mass of P + (4 molar mass of O)Molar mass of Na₃PO₄ = (3 22.99 g/mol) + 30.97 g/mol + (4 16.00 g/mol)Molar mass of Na₃PO₄ = 69.0 g/mol + 30.97 g/mol + 64.00 g/molMolar mass of Na₃PO₄ = 163.97 g/mol2. Calculate the number of moles of oxygen atoms in 2 moles of Na3PO4:
Given that 1 mole of Na₃PO₄ contains 4 moles of oxygen atoms, we can set up a proportion:
1 mole of Na₃PO₄ / 4 moles of O = 2 moles of Na₃PO₄ / x moles of O
By cross-multiplying, we get:
1 x = 2 4x = 8 moles of OTherefore, there are 8 moles of oxygen atoms in 2 moles of Na₃PO₄.
Correct question is: How many moles of oxygen atoms are in 2 moles of Na₃PO₄?
a. 3
b. 3
c. 8
d. 6
the force of attraction that holds two atoms together is called a "chemical bond". True or false? if false, what is the right answer?
In the "periodic table", dots around an element's symbol indicate the number of valence electrons in an atom. True or false? if false, what is the right answer?
The force of attraction that holds two atoms together is called a "chemical bond". True.
In the periodic table, dots around an element's symbol indicate the number of valence electrons in an atom. True.
Explanation:True or false? The force of attraction that holds two atoms together is called a "chemical bond".
The correct answer is true. Chemical bond is the term used to describe the attractive force between atoms that holds them together in a molecule or compound. This force can be either ionic, where one atom transfers electrons to another, or covalent, where atoms share electrons.
True or false? In the periodic table, dots around an element's symbol indicate the number of valence electrons in an atom.
The correct answer is true. The dots, also known as electron dot diagrams or Lewis dot structures, represent the valence electrons of an atom. Valence electrons are the electrons in the outermost energy level of an atom and are responsible for the atom's chemical behavior and reactivity.
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A chemical bond is formed through the sharing or transfer of electrons between atoms. The dots around an element's symbol in the periodic table indicate the number of valence electrons in an atom.
Explanation:The force of attraction that holds two atoms together is indeed called a chemical bond. This bond is formed through the sharing or transfer of electrons between atoms. When atoms share electrons, it is called a covalent bond, while when electrons are transferred, it forms an ionic bond.
In the periodic table, the dots around an element's symbol, known as the valence electrons, indicate the number of electrons in the outermost energy level of an atom. These electrons are involved in the formation of chemical bonds. The number of valence electrons determines the reactivity and chemical properties of an element.
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At a certain temperature, the ph of a neutral solution is 7.78. what is the value of kw at that temperature? express your answer numerically using two significant figures.
The autoionization constant Kw can be calculated at different temperatures, given a pH value, using the relationships between pH, pOH, the ion concentrations and Kw itself. For a neutral solution with a pH of 7.78, Kw can vary from standard values due to temperature changes.
Explanation:The subject of your question is related to the pH level, the autoionization constant Kw, and the temperature of a solution. These topics fall under
Chemistry
at the high school level. To calculate the Kw for a solution with a pH of 7.78, we first need to understand the relationship between the pH and pOH values. The sum of the pH and pOH is always equal to 14, a fact known as the ion-product constant for water. Using this relationship, we can solve for the pOH value, which is 14 - pH.
In this case, the pOH value would be 14 - 7.78 = 6.22. Then, we obtain the concentrations of OH- and H3O+ ions from the expressions [H3O+] = 10^-pH and [OH-] = 10^-pOH. However, given this is a neutral solution, they should be equal. Substituting these values in Kw = [H3O+][OH-], we can calculate the value of Kw which should be near to 1.0 × 10^-14, the standard Kw value at 25 °C, but may vary due to the different temperature causing the change in pH.
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The value of Kw at this temperature is approximately 2.8 × 10⁻¹⁶ .
To find the value of Kw at a given temperature where the pH of a neutral solution is 7.78, calculate pKw (which is the sum of pH and pOH), and then use it to determine Kw.
For a pH of 7.78, Kw is approximately 2.8 × 10⁻¹⁶To determine the value of Kw at a temperature where the pH of a neutral solution is 7.78, we can use the relationship between pH, pOH, and Kw.In a neutral solution, pH = pOH. Therefore, if the pH is 7.78, the pOH is also 7.78.We can use the formula:
Kw = 10(-pKw)Since pKw = pH + pOH:
pKw = 7.78 + 7.78 = 15.56Thus,
Kw = 10⁽⁻¹⁶⁾ ≈ 2.8 × 10⁻¹⁶Hence, the value of Kw at this temperature is approximately 2.8 × 10⁻¹⁶
A stock solution of na3c16h9n4o9s2 (tartrazine, or yellow no. 5) was prepared by placing 0.035- g in a 500 ml volumetric flask and diluting to 500 ml with distilled water. what is the molar concentration?
The molar concentration of the tartrazine solution is calculated by dividing the number of moles of tartrazine by the volume of the solution in liters. After converting the given mass of tartrazine to moles and the volume to liters, the molar concentration comes out to be approximately 0.000131 M.
Explanation:To solve this problem, you must first identify the molar mass of the tartrazine, which is
534.37 g/mol
. The molar concentration, also known as molarity, is calculated by dividing the number of moles of solute by the volume of the solution in liters. First, convert the mass of tartrazine to moles by dividing the given mass (0.035g) by its molar mass,
0.035 g ÷ 534.37 g/mol ≈ 0.0000655 mol
. The volume is given as 500 mL, which is equal to 0.5 liters, To find molarity, divide the number of moles by the volume in liters,
0.0000655 mol ÷ 0.5 L = 0.000131 M
. Therefore, the molar concentration of the solution is approximately 0.000131 M.
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Using the balanced equation shown below, calculate the mass of c3h8 that must react in order to release 2.45×106 × 106 kj of heat. δhrxn = –2219.9 kj
Given the heat of reaction for C3H8 (-2219.9 kJ/mole), approximately 48.63 kg of C3H8 would need to react to release 2.45 x10^6 kJ of heat.
Explanation:The balanced chemical reaction is C3H8 + 5O2 -> 3CO2 + 4H2O and its known enthalpy is -2219.9 kJ. If this amount of heat is released for the combustion of one mole of C3H8, to calculate the mass of propane (C3H8) needed to release 2.45 x10^6 kJ of heat, we need to consider the proportional relationship between heat and mass.
To release -2219.9 kJ of heat, 1 mole (or about 44.09 g) of C3H8 is needed. Therefore, to release -2.45 x10^6 kJ, you just multiply 2.45 x10^6 kJ by 44.09 g and then divide by 2219.9 kJ, which gives you approximately 48628.75 g or 48.63 kg. In summary, around 48.63 kg of C3H8 would need to react to release 2.45 x10^6 kJ of heat.
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To release 2.45×10⁶ kJ of heat, 2206.6 moles of C₃H₈ are required. Using the molar mass, this corresponds to 97,311.06 grams of C₃H₈. Therefore, the total mass needed is 97,311.06 grams.
To solve this problem, follow these steps:
First, understand the relationship given by the reaction's enthalpy change (ΔHrxn = –2219.9 kJ):2 C₃H₈(g) + 7 O₂(g) → 6 CO₂(g) + 8 H₂O(g)
This equation indicates that when 2 moles of propane (C₃H₈) react, 2219.9 kJ of heat is released.Given that we need to release 2.45×10⁶ kJ of heat, calculate the moles of C₃H₈ required using the proportion:moles of C₃H₈ = (2.45×10⁶ kJ) / (2219.9 kJ/2 moles) = 2206.6 moles of C₃H₈
To find the mass, use the molar mass of C₃H₈ (44.1 g/mol):mass (g) = 2206.6 moles × 44.1 g/mol = 97,311.06 g
Therefore, the mass of C₃H₈ required to release 2.45×10⁶ kJ of heat is 97,311.06 grams.
Find and report the reduction potentials of lithium, sodium, and potassium.
The electrode potential values of [tex]{\text{L}}{{\text{i}}^ + }[/tex], [tex]{\text{N}}{{\text{a}}^ + }[/tex] and [tex]{{\text{K}}^ + }[/tex] are [tex]\boxed{ - 3.045{\text{ V}}}[/tex], [tex]\boxed{ - {\text{2}}{\text{.714 V}}}[/tex] and [tex]\boxed{ - {\text{2}}{\text{.925 V}}}[/tex] respectively.
Further explanation:
Electrochemical cells are the devices that are used to generate an electric current from the energy released by the spontaneous redox reaction. Redox reactions involve the transfer of electrons between the chemical species by oxidation and reduction process. The oxidation process represents the loss of electrons and reduction process represents the gain of electrons.
In order to determine the standard reduction potential, the electrode is coupled with standard hydrogen electrode as illustrated in the attached image. The SHE acts as anode and the metal electrode acts as the cathode. The value of reduction potential for hydrogen has been assigned as 0.00 V.
The formula to calculate cell potential [tex]\left( {{E_{{\text{cell}}}}} \right)[/tex] of the reaction when the reduction occurs as cathode and oxidation occur at anode is as follows:
[tex]{E_{{\text{cell}}}} = {E_{{\text{cathode}}}} - {E_{{\text{anode}}}}[/tex]
The expression of Nernst equation that relates the reduction potential of a half or full electrochemical cell reaction to the standard electrode potential is given as,
[tex]{E_{{\text{cell}}}} = E_{{\text{cell}}}^\circ - \dfrac{{2.303RT}}{{nF}}\log \dfrac{{\left[ P \right]}}{{\left[ R \right]}}[/tex] ……. (1)
Here,
[tex]{E_{{\text{cell}}}}[/tex] is cell potential.
[tex]E_{{\text{cell}}}^\circ[/tex] is standard cell potential.
[tex]R[/tex] is gas constant and is equal to [tex]8.314{\text{ J/K}} \cdot {\text{mol}}[/tex].
[tex]T[/tex] is temperature.
[tex]n[/tex] denotes the number of moles of electrons transferred in the reaction.
[tex]F[/tex] is Faraday constant and is equal to [tex]95484.56{\text{ C/mol}}[/tex].
[tex]\left[ P \right][/tex] is the concentration of product.
[tex]\left[ R \right][/tex] is the concentration of reactant.
At standard temperature [tex]25\;^\circ {\text{C}}\left( {298{\text{ K}}} \right)[/tex] the value of [tex]\dfrac{{2.303RT}}{F}[/tex] is equal to [tex]0.0592{\text{ V}}[/tex]. Thus the equation(1) is written as,
[tex]{E_{{\text{cell}}}} = E_{{\text{cell}}}^\circ - \dfrac{{0.0591}}{n}\log \dfrac{{\left[ P \right]}}{{\left[ R \right]}}[/tex] …… (2)
Knowing the concentration of the electrolyte solutions taken in the cathodic compartment and substituting the values in the Nernst equation gives the reduction potential for the half cell.
The electrode potential values of [tex]{\mathbf{L}}{{\mathbf{i}}^{\mathbf{ + }}}[/tex], [tex]{\mathbf{N}}{{\mathbf{a}}^{\mathbf{ + }}}[/tex] and [tex]{{\mathbf{K}}^{\mathbf{ + }}}[/tex] are [tex]{\mathbf{ - 3}}{\mathbf{.045 V}}[/tex], [tex]{\mathbf{ - 2}}{\mathbf{.714 V}}[/tex] and [tex]{\mathbf{ - 2}}{\mathbf{.925 V}}[/tex] respectively as determined with respect to standard hydrogen electrode at [tex]{\mathbf{298 K}}[/tex].
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Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Electrochemistry
Keywords: Electrochemical cells, Redox reactions, Oxidation, reduction, cell potential, half-cell, Nernst equation, Faraday constant.
What is the density of a sample of an unknown metal has a mass of 35.4 g and a volume of 3.11 cm3?
The density of the unknown metal, calculated using the formula density = mass / volume with the given mass of 35.4 g and volume of 3.11 cm³, is 11.382 g/cm³.
To calculate the density of the unknown metal, you can use the density formula
which is density = mass / volume. Given that the mass of the metal is 35.4 g and the volume is 3.11 cm³, the calculation would be as follows:
Density = mass / volume
Density = 35.4 g / 3.11 cm³
Density = 11.382 g/cm³
Therefore, the density of the sample of the unknown metal is 11.382 g/cm³.
Write the iupac name for the compound below. be sure to use correct punctuation.
The IUPAC name for the given organic compound: CH₃CH₂CH(CH₃)CH₂CH₂OH is 3-methylhexan-2-ol.
IUPAC nomenclature refers to the chemical CH₃CH₂CH(CH₃)CH₂CH₂OH as 3-methylhexan-2-ol.
This term accurately describes its make-up: a six-carbon chain (hexane) with alcohol connected to the second carbon and a hydroxyl group (3-methyl) at the third carbon.
In order to precisely characterise organic compounds and enable unambiguous communication and identification of their structures, the IUPAC nomenclature adopts a systematic methodology.
Chemistry relies on this methodical naming strategy to describe and understand the precise atom arrangement within complicated compounds.
Thus, the answer is 3-methylhexan-2-ol.
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Your question seems incomplete, the probable complete question is:
"Identify the IUPAC name for the following organic compound: CH₃CH₂CH(CH₃)CH₂CH₂OH. Be sure to use correct punctuation and formatting."
how could you separate a mixture of acetone and a-naph
thol
A certain element forms an ion with 36 electrons and a charge of +2. identify the element
Answer: The element is Strontium.
Explanation:
Atomic number is defined as the number of electrons or number of protons that are present in an element.
Atomic number = Number of protons = Number of electrons
If an element has a positive charge, it means that the electrons are lost which were earlier present.
Thus, the total number of electrons in the given element becomes = 36 + 2 = 38
And the element which has 38 electrons means that it has an atomic number of 38.
Hence, the element is Strontium.
A 0.070 M solution of the salt NaB has a pH of 9.60. Calculate the pH of a 0.010 M solution of HB.
Or, what is the Kb of HB?
Answer:
pH=3.68
Explanation:
Hello,
At first, by knowing the 9.60-pH of the 0.070M solution of NaB, we can compute the Kb as the B contained into the NaB behaves as a base:
[tex]B^-+H_2O(l)<-->HB+OH^-[/tex]
Now, one can compute concentration of the OH ions because it is the same concentration of the HB based on the aforementioned chemical reaction:
[tex]pH=-log([H^+])\\\\ H^+=10^{-pH}=10^{-9.60}=2.51x10^{-10}\\OH^-=\frac{Kw}{[H^+]} =\frac{1x10^{-14}}{2.51x10^{-10}} =3.98x10^{-5}[/tex]
[tex][OH^-]=[HB]=3.98x10^{-5}M[/tex]
The Kb is then:
[tex]Kb=\frac{[HB][OH^-]}{[B^-]}=\frac{(3.98x10^{-5})^2}{0.070-3.98x10^{-5}} =2.264x10^{-8}[/tex]
After doing that, the Ka for the acid, taking into account its dissociation is:
[tex]HB<-->H^++B^-\\Ka=\frac{Kw}{Kb}=\frac{1x10^{-14}}{2.264x10^{-8}} =4.42x10^{-7}[/tex]
Based on the ICE conditions and table, one states the change during the dissociation of HB:
[tex]Ka=\frac{[H^+][B^-]}{[HB]}\\4.42x10^{-6}=\frac{x^2}{0.010-x} \\x=2.08x10^-4M[/tex]
Finally, the found value for x equals to the H+ concentration, so we compute the pH:
[tex][H^+]=2.08x10^{-4}\\pH=-log(2.08x10^{-4})\\pH=3.68[/tex]
Best regards.
Th pH of a 0.010 M solution of HB is 3.68 and value of Kb for HB is 2.26×10⁻⁸.
How de we calculate pH?pH of any solution is define as the negative logarithm of the concentration of H⁺ ion in the solution.
Given that, pH = 9.6
9.6 = -log[H⁺]
[H⁺] = [tex]10^{-9.6}[/tex] = 2.51×10⁻¹⁰
Also we know that,
[H⁺][OH⁻] = 10⁻¹⁴
[OH⁻] = 10⁻¹⁴ / 2.51×10⁻¹⁰ = 3.98×10⁻⁵
Now we calculate the value of Kb for HB following the below equation:
B⁻ + H₂O(l) → HB + OH⁻
Initial: 0.070 0 0
Equilibrium: 0.070-3.98×10⁻⁵ 3.98×10⁻⁵ 3.98×10⁻⁵
Kb = [3.98×10⁻⁵]² / (0.070-3.98×10⁻⁵)
Kb = 2.26 × 10⁻⁸
Also we know the relation Ka × Kb = 10⁻¹⁴
Ka = 10⁻¹⁴/2.26 × 10⁻⁸ = 4.42×10⁻⁷
For the below equation, value of Ka will be:
HB ↔ H⁺ + B⁻
Initial: 0.010 0 0
Equilibrium: 0.010-x x x
Ka = x² / (0.010-x)
We can neglect the value of x as it is very small as compare to 0.010.
4.42×10⁻⁷ = x² / 0.010
x = 2.08×10⁻⁴ M
So, the pH of the HB solution is:
pH = -log(2.08×10⁻⁴)
pH = 3.68
Hence required pH is 3.68.
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Which of the following is true in regard to ions?
A. An ionized atom has a number of protons that is unequal to the number of electrons.
B. Losing one or more electrons will turn an atom into an anion.
C. Ions can only carry positive charges.
D. A cation will hold a positive charge if it gains one or more electrons.
Answer: The correct answer is Option A.
Explanation:
There are 3 subatomic particles present in an atom. They are: protons, electrons and neutrons.
Protons carry positive charge, electrons carry negative charge and neutrons does not carry any charge.
Any neutral atom has an equal number of protons and electrons. An ion is formed when atom looses or gain electron.
If an atom gains electrons, it will have more number of electrons than protons. Thus, it will carry negative charge and form an anion.If an atom looses electrons, it will have less number of electrons than protons. Thus, it will carry positive charge and forms a cation.Thus, an ionized atom will always have unequal number of protons and electrons.
Hence, the correct answer is Option A.
Among the given statements, the true statement regarding ion is option A. An ionized atom has a number of protons that is unequal to the number of electrons.
An ion is an atom or molecule that has gained or lost one or more electrons, which changes the overall charge of the atom or molecule.
Losing one or more electrons will turn an atom into a cation, which is a positively charged ion. An anion, on the other hand, is a negatively charged ion that is formed when an atom gains one or more electrons.Ions can carry both positive and negative charges, depending on whether they are cations or anions.Cations hold a positive charge when they lose one or more electrons, while anions hold a negative charge when they gain one or more electrons.Therefore, an ionized atom has a number of protons that is unequal to the number of electrons. Option A is the correct answer.
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A neutral atom possesses an atomic number of 15 and an atomic mass of 31. Three electrons are gained. What is the result of this conservation? 15 POINTS FOR WHO EVER ANSWERS THIS PLS HELP
A) a positively charged ion.
B) a negatively charged ion.
C) a new isotope of the element.
D) a new isomer of the element .
Answer:
B
Explanation: If it has a positive trait it will have more energy or more etc.
how many mercury atoms are present in 1.0 x10^-10 mol of HG
The number of Hg atoms present in 1.0 ×10⁻¹⁰ mol of mercury is 6.022 × 10¹³.
What is Avogadro's number?Avogadro’s number can represent the number of particles in one mole of any substance. Generally, these particles can be molecules, atoms, ions, electrons, or protons, which depends upon the type of chemical reaction or their reactant and product.
The value of Avogadro’s number is approximately equal to 6.022 × 10²³ per mol.
Given, the number of moles of mercury (Hg) = 1.0 ×10⁻¹⁰ mol
The number of Hg atoms of mercury in one mole = 6.022 × 10²³ atoms
Then 1.0 ×10⁻¹⁰ mol of mercury will have atoms = 6.022 × 10²³ × 1.0 ×10⁻¹⁰
The number of atoms of mercury = 6.022 × 10¹³ Hg atoms
Therefore, the number of Hg atoms present in 1.0 ×10⁻¹⁰ mol of mercury is equal to 6.022 × 10¹³.
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Which wave corresponds to the higher-energy radiation? which wave corresponds to the higher-energy radiation? wave (b) has the higher energy. wave (a) has the higher energy?
How are bacteria and humans different?
How many grams of ammonia must you start with to make 900.00 l of a 0.140 m aqueous solution of nitric acid? assume all the reactions give 100% yield?
To make 900 L of a 0.140 M aqueous solution of nitric acid, 2142 g or 2.142 kg of ammonia (NH3) is required, assuming a 100% yield in the chemical reaction.
Explanation:The production of aqueous nitric acid involves a sequence of chemical reactions, the first of which is the combustion of ammonia: 4NH3(g) + 502(g) => 4NO(g) + 6H₂O(g). This means that 4 moles of ammonia (NH3) react to form 4 moles of nitric oxide (NO) which then further reacts to form nitric acid (HNO3).
Given that the molarity (M) of the solution is defined as the number of moles of solute per liter of solution, a 0.140 M solution of nitric acid means there are 0.140 moles of nitric acid per liter of solution. So, if we require 900.00 L of this solution, we will need 900*0.140 = 126 moles of nitric acid.
From the combustion reaction, we know that 1 mole of NH3 reacts to produce 1 mole of NO, and therefore 1 mole of HNO3. As a result, to achieve 126 moles of HNO3, we will need the same amount of NH3. Ammonia has a molar mass of approximately 17 g/mol, hence we require 126 moles * 17 g/mol = 2142 g or 2.142 kg of ammonia, assuming 100% yield in the reaction.
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You would need approximately 2142 grams of ammonia to produce 900.00 l of a 0.140 M solution of nitric acid, assuming 100% yield in the chemical reactions.
Explanation:To determine how many grams of ammonia you would need to form 900.00 l of a 0.140 M solution of nitric acid, you must first understand that the main chemical reaction involved in the production of nitric acid is the combustion of ammonia (4NH3(g) + 5O2(g) -> 4NO(g) + 6H2O(g)).
This balanced equation tells us that for every 4 moles of ammonia (NH3), 4 moles of nitric oxide (NO) are produced. Using the molarity of the nitric acid solution which is M = mol/L, we can calculate the moles of nitric acid to be 0.140 mol/l * 900.00 l = 126 mol. Assuming a 100% yield, we would need the same amount of moles of ammonia. The molar mass of NH3 is approximately 17 g/mol, so the mass of ammonia needed would be 126 mol * 17 g/mol = 2142 grams.
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there are two open cans of soda on the table .one can was just taken from the refrigerator and the other was taken from the cupborad ,upon opening the cans ,which one loes carbon dioxide more quickly and why
Part
b.1. write a net ionic equation for the reaction of hydrochloric acid with sodium hydroxide.
The net ionic equation for the reaction of hydrochloric acid with sodium hydroxide is H⁺(aq) + OH⁻(aq) → H₂O(l), which shows the formation of water from hydrogen and hydroxide ions, ignoring the spectator ions sodium and chloride.
The net ionic equation for the reaction of hydrochloric acid with sodium hydroxide is as follows:
H⁺(aq) + OH⁻(aq) → H₂O(l)
In this equation, hydrochloric acid (HCl) dissociates into hydrogen ions (H⁺) and chloride ions (Cl⁻) when dissolved in water. Sodium hydroxide (NaOH) dissociates into sodium ions (Na⁺) and hydroxide ions (OH⁻).
The reaction between the hydrogen ions and hydroxide ions produces water (H₂O), and this is the net ionic equation for the reaction. Sodium (Na⁺) and chloride (Cl⁻) ions are present on both sides of the equation and they do not participate in the actual chemical change, so they are considered spectator ions and are not included in the net ionic equation.
The atomic number of krypton (Kr) is 36, and its mass number is 84. How many neutrons does it have?
18
36
48
72
What volume of concentrated hcl (12.1m) is necessary to make a 0.250m hcl solution in a 5l volume?
Approximately 103.14 mL of concentrated HCl is necessary to make a 0.250 M HCl solution in a 5 L volume.
To determine the volume of concentrated HCl required to make a 0.250 M HCl solution in a 5 L volume, we can use the dilution formula:
[tex]\[ C_1V_1 = C_2V_2 \][/tex]
First, we need to ensure that all volumes are in the same unit, so we convert 5 L to milliliters:
[tex]\[ 5 \text{ L} \times 1000 \text{ mL/L} = 5000 \text{ mL} \][/tex]
Now we can plug the values into the dilution formula:
[tex]\[ (12.1 \text{ M})(V_1) = (0.250 \text{ M})(5000 \text{ mL}) \][/tex]
Solving for [tex]\( V_1 \):[/tex]
[tex]\[ V_1 = \frac{(0.250 \text{ M})(5000 \text{ mL})}{12.1 \text{ M}} \][/tex]
[tex]\[ V_1 = \frac{1250}{12.1} \text{ mL} \][/tex]
[tex]\[ V_1 \approx 103.14 \text{ mL} \][/tex]
Which of these is an example of a physical change?
A. wood burning
B. a piece of metal rusting
C. sugar dissolving in water
D. a mineral weathering to form another mineral
An example of a Physical Change is:
C. sugar dissolving in water
Physical Change:
To determine which of the options represents a physical change, it's important to understand the difference between physical and chemical changes:
1) Physical Change: A change that affects one or more physical properties of a substance without altering its chemical composition. Examples include changes in state (like melting or dissolving), shape, or size.
2) Chemical Change: A change that results in the formation of new chemical substances. This often involves a reaction that alters the chemical structure of the original substance.
Let's analyze each option:
A. Wood Burning
Type: Chemical Change
Reason: Burning wood transforms it into ash, smoke, and gases, changing its chemical composition.
B. A Piece of Metal Rusting
Type: Chemical Change
Reason: Rusting involves the reaction of metal with oxygen, resulting in the formation of iron oxide, which is a different substance.
C. Sugar Dissolving in Water
Type: Physical Change
Reason: When sugar dissolves, it forms a solution but retains its chemical composition. No new substances are formed.
D. A Mineral Weathering to Form Another Mineral
Type: Chemical Change
Reason: Weathering often involves chemical reactions that change the mineral's composition.