. Patrick, by himself, can paint four rooms in 10 hours. If he hires April to help, they can do the same hob together in 6 hours. If he lets April work alone, how long will it take her to paint four rooms?

Answer:

Angle bisector

Step-by-step explanation:

Given that a food truck operator is parked in a lot at the corner of two streets. She wants to be equidistant from both streets.

We have to find out where she should park her truck on a perpendicular bisector, and angle bisector, a median, or an altitude

We know the perpendicular bisector is the locus of points equidistant form two points.

But here two streets can be treated as straight lines only.

The angle bisector of two lines will have all the points on the bisector.

Median is not applicable since here no triangle is there neither altitude

So right answer is angle bisector.

She should park her  truck on  the angle bisector of angle formed by intersection of two roads.

Answer:

a. A = {RRR,LLL,SSS}

b. B = {RLS, RSL, LSR, LRS, SRL, SLR}

c. C = {RRS, RRL, RSR, RLR, LRR, SRR}

d. D = {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

e. C U D= {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

C n D = {RRS, RRL, RSR, RLR, LRR, SRR}

Step-by-step explanation:

a..

All three vehicles go in the same direction

This means that all the three vehicles either go straight, or right or left at the same time.

So, A { {RRR, LLL, SSS}

b..

All three vehicles take different directions

Thus means that all the vehicle take different routes

If a vehicle takes the the straight direction, the other 2 vehicles take right and left directions respectively

So, B = {RLS, RSL, LSR, LRS, SRL, SLR}

c..

Exactly two of the three vehicles turn right

This means that two vehicles take right direction while the last vehicle either tske the straight route or left route.

C = {RRS, RRL, RSR, RLR, LRR, SRR}

d..

Exactly two vehicles go in the same direction.

The means that if two vehicles pass straight direction then the third vehicle takes either the right or left direction.

Also, if two vehicles pass right direction, the third vehicle either takes the left direction or straight direction

Lastly, if two vehicles pass left direction then the third vehicle either pass the straight direction or right direction.

D = {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

e. C U D = the union of items in C and D without repetition

So,

C U D= {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

C n D = Common items in C and D

C n D = {RRS, RRL, RSR, RLR, LRR, SRR}

List outcomes in D'.D' = List outcomes in C ∪ D.C ∪ D = List outcomes in C ∩ D.C ∩ D =

The question presents various scenarios of successive vehicles choosing directions. Outcomes are determined in cases where all vehicles choose the same direction, all choose different directions, exactly two choose right, exactly two choose the same direction (any), and the negation of the latter case. The outcomes of combining these scenarios (union and intersection) are also defined.

The events refer to the outcomes of the directions three successive vehicles could potentially take. There are three possibilities: right (R), left (L), or straight (S).

(a) Event A where all three vehicles go in the same direction, would include these outcomes: A = {RRR, LLL, SSS}.

(b) Event B where all three vehicles take different directions, would look like this: B = {RLS, RSL, LRS, LSR, SRL, SLR}.

(c) Event C where exactly two of the three vehicles turn right would include these outcomes: C = {RRS, RRL, SRR, LRR, RSR, RLR}.

(d) Event D where exactly two vehicles go in the same direction, would include these outcomes: D = {RRS, RRL, SRS, SSL, LRL, LLR, RRS, RLS, RSS, LSS, SLL, LLS, SSR, SRL, SRR, LLR, LRS, LRR}.

(e) Event D' which stands for everything that's not in event D, includes these outcomes: D' = {RLS, SLR, LRS, RSL, LSR, SRL}.

The union of events C and D, C ∪ D, combines the outcomes of both C and D, but without repetition: C ∪ D = {RRS, RRL, SRS, SSL, LRL, LLR, RRS, RLS, RSS, LSS, SLL, LLS, SSR, SRL, SRR, LLR, LRS, LRR, RSR, RLR}.

Finally, the intersection of event C and D, C ∩ D, includes only outcomes common to both C and D: C ∩ D = {RRS, RRL, SRR, LRR, RSR, RLR}.

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Answer:

The answer to your question is below

Step-by-step explanation:

Data

P (-5, 5)

Parallel to 6x - 5y - 9 = 0

Process

1.- Find the equation of the line

                  6x - 5y = 9

                       -5y = -6x + 9

                          y = -6/-5 x + 9/-5

                          y = 6/5 x - 9/5

slope = 6/5, as the lines are parallels, the slope is the same.

2.- Get the equation of the new line

                     y - y1 = m(x - x1)

                     y - 5 = 6/5 (x + 5)

                     y - 5 = 6/5x + 6

                          y = 6/5x + 6 + 5

                          y = 6/5x + 11                     Point-slope form

                   5y - 25 = 6(x + 5)

                   5y - 25 = 6x + 30

                   6x - 5y + 30 + 25 = 0

                  6x - 5y + 55 = 0                      General form

The equation of the line that passes through (-5,5) and is parallel to 6x - 5y - 9 = 0 can be written in point-slope form as y - 5 = (6/5)(x + 5) and in general form as -6x + 5y - 55 = 0.

To write an equation for the line that passes through the point (-5,5) and is parallel to the line 6x - 5y - 9 = 0, we first need to find the slope of the given line. By rewriting the equation in slope-intercept form (y = mx + b), we can identify the slope (m). The equation 6x - 5y - 9 = 0 can be rewritten as y = (6/5)x + 9/5, so the slope of the line is 6/5. Since parallel lines have the same slope, the slope of our new line is also 6/5.

Next, we use the point-slope form of the equation, which is y - y1 = m(x - x1), where (x1, y1) is a point on the line (here (-5,5)) and m is the slope. Substituting these values into the equation gives us y - 5 = (6/5)(x + 5).

To express this in general form (Ax + By + C = 0), we rearrange the equation: multiply both sides by 5 to clear the fraction, resulting in 5(y - 5) = 6(x + 5), which simplifies to 5y - 25 = 6x + 30. Rearranging gives -6x + 5y - 55 = 0.

Answer:

Byte

Step-by-step explanation:

We use byte to represent 1 and 0 in computing..

The most basic unit of computing is the 'bit', which can be represented as either 1 (on) or 0 (off). This binary information is used in digital circuits to perform tasks in computing devices. The use of bits was crucial to the development of modern computing.

The most fundamental unit of computing is the bit, which is represented as an on (1) or off (0) value. In digital circuits found in modern devices, transistors behave like switches that can be either on or off, encoding information in a binary code of ones and zeros. These bits are utilised to perform a variety of tasks like data manipulation and transmission of signals. Over time, scientists have found ways to amplify the computing capacity of bits by integrating vast collections of transistors on single silicon wafers, creating the integrated circuits (IC), which is foundational to the modern digital computer revolution.

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Answer:

40.112

Step-by-step explanation:

Answer:

[tex]x^{4}[/tex] + 3x² - 4

Step-by-step explanation:

Note that complex zeros occur in conjugate pairs

If 2i is a zero then - 2i is a zero

The zeros are x = 1, x = - 1, x = 2i, x = - 2i, thus the factors are

(x - 1), (x + 1), (x - 2i) and (x + 2i)

The polynomial is expressed as the product of the factors, thus

f(x) = (x - 1)(x + 1)(x - 2i)(x + 2i) ← expanding in pairs

     = (x² - 1)(x² - 4i²) → i² = - 1

     = (x² - 1)(x² + 4) ← distribute

     = [tex]x^{4}[/tex] + 4x² - x² - 4

     = [tex]x^{4}[/tex] + 3x² - 4

Answer:

C. The term linear refers to a straight line, and r measures how well a scatter plot fits a straight-line pattern

Step-by-step explanation:

In statistics, when two variables are being investigated, the location of the co-ordinates on a rectangular co-ordinates ystem is called a scatter diagram.

The amount of linear correlation between two variables is expressed by a coefficient of correlation, given the symbol r. This is defined in terms of the deviations of the co-ordinates of two variables from their mean values and is given by the product-moment formula

For linear correlation, if points are plotted on a graph and all the points lie on a straight line, then perfect linear correlation is said to exist. When a straight line having a positive gradient can reasonably be drawn through points on a graph positive or direct linear correlation exists.

Answer:

XY is 4 units.              

Step-by-step explanation:

We are given the following in the question:

Right triangle ABC is similar to triangle XYZ.

AB = 20.8 units

BC = 36.4 units

YZ = 7 units

We have to find the length of side XY.

Since the given triangles are similar, they have the following property:

The ratio of corresponding sides of similar triangles are equal.

We can write,

[tex]\displaystyle\frac{AB}{XY}=\frac{BC}{YZ}=\frac{AC}{XZ}[/tex]

Putting the given values, we have,

[tex]\displaystyle\frac{AB}{XY}=\frac{BC}{YZ}\\\\\frac{20.8}{XY}=\frac{36.4}{7}\\\\XY = \frac{20.8\times 7}{36.4} =4 \text{ units}[/tex]

Thus, the length of XY is 4 units.

Answer:

[tex]V_{avg} = \frac{ln2}{e} = 0.255fts^{-1}[/tex]

Step-by-step explanation:

The question asks for the average velocity and not the instantaneous velocity (which would have meant to differentiate). So, the right formula is

[tex]V_{avg} = \frac{s(t_{2}) - s(t_{1} ) }{t_{2} -t_{1} } =[/tex]

From the question, [tex]t_{1}[/tex] corresponds to e seconds and [tex]t_{2}[/tex] corresponds to 2e seconds. So, we have

[tex]V_{avg} = \frac{ln(2e) - ln(e)}{2e - e}[/tex]

One of the laws of logarithms says that

[tex]ln(\frac{a}{b} )= ln(a) - ln(b). \\\\ Therefore, ln(2e) - ln(e) = ln(\frac{2e}{e} ) = ln(2)[/tex]

[tex]V_{avg} = \frac{ln(2)}{e} = 0.2550fts^{-1}[/tex] ≅ [tex]0.255fts^{-1}[/tex]

Answer:

50.75 units

Step-by-step explanation:

In this problem

Triangles HFM and PST are similar

we know that that

If two figures are similar, then the ratio of its corresponding sides is proportional, and this ratio is called the scale factor

step 1

Find the scale factor

Let

z ----> the scale factor

[tex]z=\frac{HF}{PS}[/tex]

substitute the given values

[tex]z=\frac{14}{8}=1.75[/tex]

step 2

Find the perimeter of triangle PST

[tex]P=8+9+12=29\ units[/tex]

step 3

Find the perimeter of triangle HFM

we know that

If two figures are similar, then the ratio of its perimeters is equal to the scale factor

so

The perimeter of triangle HFM is equal to the perimeter of triangle PST multiplied by the scale factor

so

[tex]29(1.75)=50.75\ units[/tex]

ANSWER: Adult tickets: 200  Student tickets:400

STEP-BY-STEP EXPLANATION:

n = number of adult tickets sold

2n = number of student tickets sold

2n(1.25) + n(1.75) = $850

2.50n + 1.75n = $850

4.25n = $850

n = 200

2n= 2 × 200= 400

Answer:

It would take skinny cat 6 mins to reach fat cat.

Step-by-step explanation:

Given:

Speed of Fat cat = 75 yd/min

Speed of skinny cat = 100 yd/min

We need to find the time taken by skinny cat to reach fat cat.

Let the distance covered by both be 'd'.

Also let the time taken by Fat cat to cover distance 'd'  be 't' mins.

Now we know that skinny cat started 2 mins later so time taken by Skinny cat will be [tex]t-2 \ mins[/tex].

Now we know that;

Distance is equal to speed times time.

framing in equation form we get;

Distance cover by fat cat = [tex]75t[/tex]

Distance cover by skinny cat = [tex]100(t-2) =100t-200[/tex]

Both distance have to made same since we need to find the time required more to reach the other cat.

[tex]100t-200=75t[/tex]

Combining like terms we get;

[tex]100t-75t=200\\\\25t =200[/tex]

Dividing both side by 25 we get;

[tex]\frac{25t}{25}=\frac{200}{25}\\\\t = 8\ mins[/tex]

Time taken by skinny cat = [tex]t-2 =8-2=6 \ mins[/tex]

Hence it would take skinny cat 6 mins to reach fat cat.

Skinny Cat catches up to Fat Cat 6 minutes after starting at 9:02 am, which is at 9:08 am. This is calculated by determining the head start that Fat Cat has and the faster pace at which Skinny Cat moves.

We are presented with a problem where two cats, one named Fat Cat and the other Skinny Cat, start at different times and move at different speeds. Fat Cat starts at 9:00 am moving at 75 yards per minute, and Skinny Cat starts at 9:02 am moving at 100 yards per minute. The question is to find out how long it takes for Skinny Cat to catch up to Fat Cat.

So, Skinny Cat will catch up to Fat Cat 6 minutes after starting at 9:02 am, which is at 9:08 am.

Answer:angular speed=471.429rad/sec

Step-by-step explanation:

One revolution is :

2×pi×radians

Then 4500 revolution will be:

2×pi×4500rad= 9000pi rad

1minutes = 60seconds

So the angular speed is :

=(9000×pi rad) / minutes

=9000×(22/7)rad /60seconds

=471.42857143 rad/sec

=471.429rad/sec to 3 d.p

The angular speed of the blade is [tex]471[/tex] radian per minute.

In one revolution, angle made is [tex]2\pi[/tex] radian.

In 4500 revolutions = [tex]2\pi *4500=9000\pi[/tex] radian.

We know that ,

1 hour = 60 minute.

Angular speed = [tex]\frac{9000\pi radian}{60minute} =\frac{9000*3.14}{60}=471radian/minute[/tex]

Therefore, the angular speed of the blade is [tex]471[/tex] radian per minute.

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Answer:

a) The problem says that this represent the values within 3 deviations from the mean and using the empirical rule we know that on this case we have 68% of the data on this interval.

b) For this case we can use the z score formula again:

[tex] z_1= \frac{98.73-98.38}{0.48}=0.729[/tex]

[tex] z_2= \frac{97.89-98.38}{0.48}=-1.020[/tex]

For this case we want this probability:

[tex] P(97.89<X<98.73) =P(-1.02<Z<0.729)= P(Z<0.729)-P(Z<-1.02)=0.767-0.154= 0.613[/tex]

So the approximate percentage of temperatures between 97.89F and 98.73F is 61.3%

Step-by-step explanation:

The empirical rule, also referred to as "the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ)". The empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

For this case we know that the body temperatures for a group of heatlhy adults represented with the random variable X follows this distribution:

[tex] X \sim N(\mu =98.38F, \sigma=0.48 F)[/tex]

Part a

For this case we can use the z score formula to measure how many deviations we are within the mean, given by:

[tex] z=\frac{x-\mu}{\sigma}[/tex]

If we find the z score for the values given we got:

[tex] z_1= \frac{99.57-98.38}{0.48}=2.479[/tex]

[tex] z_2= \frac{97.05-98.38}{0.48}=-2.771[/tex]

The problem says that this represent the values within 3 deviations from the mean and using the empirical rule we know that on this case we have 68% of the data on this interval.

Part b

For this case we can use the z score formula again:

[tex] z_1= \frac{98.73-98.38}{0.48}=0.729[/tex]

[tex] z_2= \frac{97.89-98.38}{0.48}=-1.020[/tex]

For this case we want this probability:

[tex] P(97.89<X<98.73) =P(-1.02<Z<0.729)= P(Z<0.729)-P(Z<-1.02)=0.767-0.154= 0.613[/tex]

So the approximate percentage of temperatures between 97.89F and 98.73F is 61.3%

Answer:888 cubic centimeters

Step-by-step explanation:

The formula for determining the volume of a rectangular prism is expressed as

Volume = length × height × width

Length = 10 centimeters

Width = 8 centimeters

Height = 12 centimeters

Therefore, the volume of the rectangular prism would be

10 × 8 × 12 = 960 centimeters³

A rectangular hole with a length of 2 centimeters and a width of 3 centimeters is cut through the prism. The height of the hole would also be 12 centimeters.

Therefore, the volume of the rectangular hole would be

2 × 3 ×12 = 72 cm³

the volume of the resulting figure would be

960 - 72 = 888 cm³

STEP-BY-STEP EXPLANATION:

Let be x the number of boxeds of crackers you can buy

If each box has a cost of $2.30 and you have $11.50

we can represent this into this equation

2.30x= 11.50

x=[tex]\frac{11.50}{2.30}[/tex]

x=5

You can buy 5 boxes of crackers

Answer: [tex]137\dfrac{1}{3}\ cm,\ 137\dfrac{1}{3}\ cm,\ 250\dfrac{1}{3}\ cm[/tex]

Step-by-step explanation:

Let x be the equal sides of the triangle .

The , the third side would be x+113 cm.

The perimeter is the sum of all sides of a triangle.

So , The perimeter of triangle would be  x+x+(x+113)= 3x+113 --------(1)

Since , it is given that the perimeter of triangle is 525. -----(2)

So from (1) and (2) , we have

[tex]3x+113=525\\\\ 3x=525-113=412\\\\ x=\dfrac{412}{3}=137\dfrac{1}{3}[/tex]

Then, third side = [tex]137\dfrac{1}{3}+113=250\dfrac{1}{3}\ cm[/tex]

Hence , the sides of a triangle  are:[tex]137\dfrac{1}{3}\ cm,\ 137\dfrac{1}{3}\ cm,\ 250\dfrac{1}{3}\ cm[/tex]

Answer: 1 16/45, 1 16/45, 2 31/45

Step-by-step explanation:

Say x is the equal side of the triangle.

The third side would be x+113 cm.

The perimeter is the sum of all sides of a triangle.

So, the perimeter of the triangle would be  x+x+(x+113)= 3x+113

Since the triangle's perimeter is 5 2/5, 3x + 1 1/3 = 5 2/5.

1 1/3 is 1 5/15. 5 2/5 is 5 6/15. 5 6/15 - 1 5/15 = 4 1/15.

This means 3x = 4 1/15.

4 1/15 = 61/15

3x = 61/15

To make 3x into x, you can multiply it by 1/3.

3x*1/3 is x. 61/15*1/3 = 61/45.

x = 1 16/45 because 61/45 = 1 16/45.

The longer side is x + 1 1/3 so you have to add 1 1/3 to 1 16/45 which is

2 31/45.

So, the sides are 1 16/45, 1 16/45 and 2 31,45.

Stem and Leaf plot would be the best choice to display the given data if we want to display the numbers which are outliers as well as the mean.

Hence option C is correct.

Given, representation of outliers and mean.

Data: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

Stem and Leaf plot would be the best choice to display the given data if we want to display the numbers which are outliers as well as the mean.

Therefore option C is correct.

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Options for question :

1) Pie Graph

2) Bar Graph

3) Stem and Leaf Plot

4) Line Chart

5) Venn Diagram

A box and whisker plot is the best choice to display data including outliers and the mean in mathematics. It clearly shows the median, quartiles, and outliers. The mean can be depicted as an additional point.

In the field of mathematics, to display the data with outliers and the mean, a box and whisker plot is the most suitable graph. This type of graph can highlight outliers and also show the mean. For instance, our given data [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32] when plotted on a box and whisker plot would display the median (the line inside the box), the quartiles (the ends of the box), and outliers (points outside the whiskers). The mean can additionally be added as a separate point on the plot.

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Answer:B

Step-by-step explanation:

Given

Right circular cone is inscribed in a hemisphere so that the base of the cone coincides with base of hemisphere

Height of cone is equal to radius of hemisphere

so ratio of the height of cone to the radius of the hemisphere is 1:1

Answer:he borrowed $22000 from bank 1.

He borrowed $2000 from bank 2

Step-by-step explanation:

Let x represent the amount of money that he borrowed from bank 1.

Let y represent the amount of money that he borrowed from bank 2.

Bobby Borrowed 24,000 from two different banks to start a business. This means that

x + y = 24000

The formula for simple interest is expressed as

I = PRT/100

Where

P represents the principal

R represents interest rate

T represents time

Considering the money borrowed from bank 1,

P = x

R = 4%

T = 1

I = (x × 4 × 1)/100 = 0.04x

Considering the money borrowed from bank 2,

P = y

R = 5.5%

T = 1

I = (y × 5.5 × 1)/100 = 0.055y

if the total interest after 1 year was $990, it means that

0.04x + 0.055y = 990 - - - - - -1

Substituting x = 24000 - y into equation 1, it becomes

0.04(24000 - y) + 0.055y = 990

960 - 0.04y + 0.055y = 990

- 0.04y + 0.055y = 990 - 960

0.015y = 30

y = 30/0.015 = $2000

Substituting y = 2000 into

x = 24000 - y, it becomes

x = 24000 - 2000

x = 22000

Answer:

(0.2599,0.3401)                                                

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 500

x = 150

[tex]\hat{p} = \dfrac{x}{n} = \dfrac{150}{500} = 0.3[/tex]

Confidence interval:

[tex]\hat{p}\pm z_{stat}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}[/tex]

[tex]z_{critical}\text{ at}~\alpha_{0.05} = \pm 1.96[/tex]

Putting the values, we get:

[tex]0.3\pm 1.96\sqrt{\dfrac{0.3(1-0.3)}{500}} = 0.3 \pm 0.0401 =(0.2599,0.3401)[/tex]

The 95% confidence interval is (0.2599,0.3401).

Answer:

See the plot below.

For this case we can consider as an outlier the value 8.0 since is far away from the other points

Step-by-step explanation:

For this case we can create the stem plot like this:

Stem      Leaf

 0      |     5 7

 1       |     1 2 2 3 3 5 5 7 7 8 9

 2      |     0 2 5 6 8 8 8

 3      |     5 8

 4      |     4 8 9

 5      |     2 5 7 8

 6      |

 7      |

 8      |    0

Notation : "1 |1 means 1.1 for example and 3|5 means 3.5"

By definition an outlier is "an observation that lies an abnormal distance from other values in a random sample from a population"

For this case we can consider as an outlier the value 8.0 since is far away from the other points

9514 1404 393

Answer:

  each has to work 5 hours and earn $42

Step-by-step explanation:

Let m and h represent hours Nai spends mowing and hauling, respectively. Then (m+h) will be the number of hours Priya spends babysitting. In order for their earnings to be equal, we must have ...

  7m +14h = 8.40(m+h)

  5.60h = 1.40m . . . . . . . . subtract 7m+8.40h

  m = 4h . . . . . . . . . . . . . . divide by 1.40

Then the total number of hours worked by either person is ...

  m + h = (4h) +h = 5h

If only whole numbers of hours are worked, then the smallest number of hours that will make earnings equal is 5h, with h=1, or 5 hours. In that time, each will earn 5×$8.40 = $42.

Each must work 5 hours and earn $42 before they go to the movies.

__

Nai will work 4 hours mowing and 1 hour hauling.

Priya and Nai have to work 0 hours before they go to the movies.

To find out how much money Priya and Nai each have to work before they go to the movies, we need to set up an equation. Let x represent the number of work hours for both Priya and Nai. Nai earns $7 per hour, so her earnings in x hours would be 7x dollars. Priya earns $8.40 per hour, so her earnings in x hours would be 8.40x dollars. Since they want to earn the same amount, we can set up the equation:

7x = 8.40x

To solve for x, we can subtract 7x from both sides of the equation:

0.40x = 0

Now, divide both sides of the equation by 0.40 to solve for x:

x = 0 / 0.40

x = 0

Therefore, both Priya and Nai have to work 0 hours before they go to the movies. This means they have already earned the same amount of money.

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Answer:

Step-by-step explanation:

The function t, where t(x) = 9.50x represents the amount of money Fernando earns given the number of hours, x, that he works.

The domain of a function are the set of possible values of x, the independent variable that satisfies the function.

Fernando works between 12 and 25 hours each week. It means that the statement that best represents the domain of this function for any given week would be

12 ≤ x ≤ 25

The statement that best represents the domain of this function for any given week would be 12 ≤ x ≤ 25.

The function is a type of relation, or rule, that maps one input to a specific single output.

Fernando works between 12 and 25 hours each week.

The function t, where t(x) = 9.50x represents the amount of money Fernando earns given the number of hours, x, he works.

The domain is the set of values x for which the given function is defined.

Or The independent variable that satisfies the function.

The statement that best represents the domain of this function for any given week would be 12 ≤ x ≤ 25.

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Answer:

Step-by-step explanation:

Let x represent the number of farmers that grew all three crops.

Let y represent the number of farmers that grew corn and oat.

The Venn diagram representing the scenario is shown in the attached photo.

W represents the subset for wheat

C represents the subset for corn

O represents the subset for oat

199 grew wheat. It means that

121 + 57 - x + x + 60 - x = 199

238 - x = 199

x = 238 - 199

x = 39

182 grew corn. It means that

113 + 60 - x + x + y - x = 182

173 + y - x = 182

y = 182 - 173 + 39

y = 48

a) the number of farmers who grew at least one of the three would be

121 + 113 + 90 + 57 - x + 48 - x + 60 - x + x

= 121 + 113 + 90 + 57 - 39 + 48 - 39 + 60 - 39 + 39 = 411

b) the number of farmers that grew all three would be

x = 39

c) the number of farmers who did not grow any of the three would be

500 - 411 = 89

d) the number of farmers who grew exactly two of the three would be

60 - x + 57 - x + 48 - x

= 60 - 39 + 57 - 39 + 48 - 39

= 21 + 18 + 9

= 48

The number of farmers who grew at least one of the crops is 328, all three is not stated, none of the three is 172 and exactly two of them is 117.

To solve this problem, we have to understand Venn Diagrams and set theory. When adding up counts for different categories, it is important to not double count any item.

The number of farmers who grew at least one of three crops (wheat, corn, oats) can be determined by the sum of all the individual and intersection categories. However, we subtract the counts that have been mentioned twice.

a) At least one: (121 wheat only + 113 corn only + 90 oats only + 199 wheat + 60 wheat&corn + 57 wheat&oats + 182 corn) - (2*(60 wheat&corn) + 2*(57 wheat&oats) + 2*(182 corn&-)) = 328

b) All three: There is no clear information about farmers growing all three crops. We may assume it to be 0, as it is not stated.

c) None of three: The survey includes 500 farmers, if 328 grow at least one crop, then the number of farmers that did not grow any of the three is 500 - 328 = 172

d) Exactly two: 60 grew wheat and corn, 57 grew wheat and oats. Hence 117 farmers grew exactly two of the three crops.

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The reciprocal of n must be less than –10

Solution:

Given n denotes a number to the left of 0 means n < 0.

Square of n is less than [tex]\frac{1}{100}[/tex] means [tex]n^2<\frac{1}{100}[/tex].

Therefore, we have [tex]n<0[/tex] and [tex]n^2<\frac{1}{100}[/tex].

⇒ [tex]n^2<\frac{1}{100}[/tex]

Taking square root on both sides, we get

⇒ [tex]n<\± \frac{1}{10}[/tex]

⇒[tex]\frac{-1}{10}<n<\frac{1}{10}[/tex]

⇒ But we know that n < 0, so [tex]n<\frac{1}{10}[/tex] false.

It should be [tex]\frac{-1}{10}<n[/tex].

To equal the expression, multiply both sides of the equation by –10n.

⇒ [tex]-\frac{1}{10} \times\frac{-10}{n}>n \times\frac{-10}{n}[/tex]   (symbol < changed to > when multiply by minus)

⇒ [tex]\frac{1}{n}>-10[/tex]

Hence, the reciprocal of n must be less than –10.

Answer:

The average life of the mice that are placed on this diet is less than 40 months.

Step-by-step explanation:

Consider the provided information.

When 40% of the calories in their diet are replaced by vitamins and protein. Is there any reason to believe that μ < 40.

The null and alternative hypothesis are:

[tex]H_0:\mu=40\\H_a:\mu<40[/tex]

64 mice that are placed on this diet have an average life is 38 months with a standard deviation of 5.8 months.

Therefore, [tex]n = 64, \bar x=38\ and\ \sigma=5.8[/tex]

Use the formula: [tex]z=\dfrac{\bar x-\mu}{\frac{\sigma}{\sqrt{n} }}[/tex]

Substitute the respective values in the above formula.

[tex]z=\dfrac{38-40}{\frac{5.8}{\sqrt{64} }}[/tex]

[tex]z=-\dfrac{2}{\frac{5.8}{8}}\approx-2.76[/tex]

Now using the table [tex]P(Z<z)=0.029[/tex]

The p value is smaller than 0.05 so reject the null hypothesis.

Therefore, the average life of the mice that are placed on this diet is less than 40 months.

Answer:

DIRECT WAY EXCEL

"=NORM.DIST(75,80,3,TRUE)"

And we got: [tex] P(X\leq 75)= 0.04779[/tex]

OTHER WAY

[tex]P(X\leq 75)=P(\frac{X-\mu}{\sigma}\leq \frac{75-\mu}{\sigma})=P(Z\leq \frac{75-80}{3})=P(Z<-1.67)[/tex]

And we can find this probability using the normal standard table or excel:

[tex]P(Z<-1.67)=0.04779[/tex]

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the diameter of a population, and for this case we know the distribution for X is given by:

[tex]X \sim N(80,3)[/tex]  

Where [tex]\mu=80[/tex] and [tex]\sigma=3[/tex]

And we know that if the diameter is 75 or less the ring would be considered defective , so then in order to find the proportion of defective we need to find the following probability:

[tex] P(X\leq 75)[/tex]

One way to do this in excel is with the following formula:

"=NORM.DIST(75,80,3,TRUE)"

And we got: [tex] P(X\leq 75)= 0.04779[/tex]

And the other way is use the z score formula given by:

[tex]z=\frac{x-\mu}{\sigma}[/tex]

If we apply this formula to our probability we got this:

[tex]P(X\leq 75)=P(\frac{X-\mu}{\sigma}\leq \frac{75-\mu}{\sigma})=P(Z\leq \frac{75-80}{3})=P(Z<-1.67)[/tex]

And we can find this probability using the normal standard table or excel:

[tex]P(Z<-1.67)=0.04779[/tex]

Answer:

Siham ran for 305 minutes

Step-by-step explanation:

Let

Siham Ran for time = X

Siham Ran for time = X-60

According to given condition

X + (X-60) = 670

X + X - 60 = 670

2X = 670-60

2X = 610

X = 610/2

X = 305

So Siham ran for 305 minutes only