Pediatric asthma survey, n = 50. suppose that asthma affects 1 in 20 children in a population. you take an srs of 50 children from this population. can the normal approximation to the binomial be applied under these conditions? if not, what probability model can be used to describe the sampling variability of the number of asthmatics?

Answers

Answer 1
In this situation, 
n=50, p=1/20, q=(1-p)=19/20, and npq=19/8=2.4

We would like np and npq to be a large number, at least greater than 10.
The normal approximation can always be applied, but the result will be very approximate, depending on the values of np and npq.

Situations are favourable for the normal approximation when p is around 0.5, say between 0.3 and 0.7, and n>30.

"Normal approximation" is using normal probability distribution to approximate the binomial distribution, when n is large (greater than 70) or exceeds the capacity of most hand-held calculators.  The binomial distribution can be used if the following conditions are met:
1. Bernoulli trials, i.e. exactly two possible outcomes.2. Number of trials is known before and constant throughout the experiment, i.e. independent of outcomes.3. All trials are independent of each other.4. Probability of success is known, and remain constant throughout trials.
If all criteria are satisfied, we can model with binomial distribution, where the probability of x successes out of N trials each with probability of success p is given byP(x)=C(N,x)(p^x)(1-p)^(N-x)and,C(N,x) is number of combinations of selecting x objects out of N.
The mean is np, and variance is npq.

For the given situation, np=2.5, npq=2.375, so standard deviation=sqrt(2.375)=1.54.

Answer 2

n=50, p=1/20, q=(1-p)=19/20, and npq=19/eight=2.4

We would like np and npq to be a huge range, at least extra than 10.

The ordinary approximation can usually be carried out, but the result might be very approximate, relying on the values of np and npq.

conditions are favorable for the normal approximation when p is around 0.5, say among 0.3 and 0.7, and n>30.

For the given scenario, np=2.five, npq=2.375, so widespread deviation=sqrt(2.375)=1.54.

underneath what conditions binomial distribution tends to be everyday distribution?

the theory states that any distribution becomes normally allotted whilst the variety of variables is satisfactorily massive. for example, the binomial distribution has a tendency to alternate into the regular distribution with suggest and variance.

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Related Questions

Using the given zero, find all other zeros of f(x).
-2i is a zero of f(x) = x4 - 32x2 - 144


a) 2i, 12, -12

b) 2i, 6i, -6i

c) 2i, 6, -6

d) 2i, 12i, -12i

Answers

Using the given zero, find all other zeros of f(x). -2i is a zero of f(x) = x4 - 32x2 - 144 

Answer: C; 2i,6,-6

Answer:

c) 2i, 6, -6

Step-by-step explanation:

The given function is

[tex]f(x)=x^{4}-32x^{2} -144[/tex]

The given zero to this function is

[tex]x=-2i[/tex]

Remember that a function has so many roots as its grade dictates. So, in this case, the function grade is four, which means it has four solutions.

Now, the given function is an imaginary number, which happens in pairs, that means the second root must be [tex]x=2i[/tex], because a function can have complex roots as pairs, 2, 4, 6,... many solutions.

The other two solutions are 6 and -6, because if we replace them into the function, it will give zero.

[tex]f(6)=6^{4}-32(6)^{2} -144=0\\f(-6)=(-6)^{4}-32(-6)^{2} -144=0[/tex]

Therefore, the other three solutions missing are: c) 2, 6, -6.

(The image attached shows the real solutions).

A triangle has a perimeter of 10x+2. Two sides have lengths of 5x and 2x+9. What is the length of the 3rd side?

Answers

As we know perimeter of triangle is equal to sum of all three sides.

Let the third side = a.

So we can write perimeter as = 5x + 2x + 9 + a

As given perimeter = 10x + 2

So we can write 10x +  2 = 7x + 9 + a

10x + 2 - 7x - 9 = a

3x - 7 = a

So third side = 3x - 7.

What is the domain of y = sec(x)?

Answers

Final answer:

The domain of y = sec(x) is all real numbers except for values where the cosine function is zero.

Explanation:

The domain of y = sec(x) is all real numbers except for values where the cosine function is equal to zero. Since the secant function is the reciprocal of cosine, it is undefined when cosine is zero.

So, the domain of y = sec(x) is all real numbers except for values of x where cos(x) = 0.

For example, if we consider the unit circle, the cosine function is equal to zero at π/2 and 3π/2. Therefore, the domain of y = sec(x) would exclude these values.

The domain of [tex]\( y = \sec(x) \)[/tex] is all real numbers except [tex]\( x = \frac{\pi}{2} + \pi \cdot n \)[/tex], [tex]\( n \)[/tex] integer.

Let's find the domain of [tex]\( y = \sec(x) \)[/tex].

The secant function, [tex]\( \sec(x) \)[/tex], is defined as the reciprocal of the cosine function, [tex]\( \cos(x) \)[/tex]. So, [tex]\( \sec(x) = \frac{1}{\cos(x)} \).[/tex]

The cosine function is defined for all real numbers, except where the denominator becomes zero, because division by zero is undefined.

So, to find the domain of [tex]\( \sec(x) \)[/tex], we need to find where [tex]\( \cos(x) \)[/tex] is not zero.

The cosine function has a range between -1 and 1. It equals zero at [tex]\( x = \frac{\pi}{2} + \pi \cdot n \)[/tex] and [tex]\( x = -\frac{\pi}{2} + \pi \cdot n \)[/tex], where [tex]\( n \)[/tex] is an integer.

So, the domain of [tex]\( \sec(x) \)[/tex] is all real numbers except where [tex]\( \cos(x) = 0 \)[/tex]. Therefore, the domain of [tex]\( \sec(x) \)[/tex] is [tex]\( x \neq \frac{\pi}{2} + \pi \cdot n \)[/tex] and [tex]\( x \neq -\frac{\pi}{2} + \pi \cdot n \)[/tex], where [tex]\( n \)[/tex] is an integer.

In interval notation, the domain of [tex]\( \sec(x) \)[/tex] is:

[tex]\[ (-\infty, -\frac{\pi}{2}) \cup (-\frac{\pi}{2}, \frac{\pi}{2}) \cup (\frac{\pi}{2}, \infty) \][/tex]

At an aquarium, 6 out of 18 deliveries are plants. Out of 15 deliveries in one week,how many are plants?

Answers

The answer to your question is:

5 deliveries.

The ordered pair (a, b) gives the location of point P on the coordinate plane. The value of a is negative and the value of b is zero. Where could point P be located on the coordinate plane?





Select one or more:
Quadrant I
Quadrant II
Quadrant IV
Quadrant III
x-axis
y-axis

Answers

If x is negative and y is zero the point would be located on the x-axis.

Answer:

X-axis.

Step-by-step explanation:

Givens

We have point which coordinates are (a,b)The value of a is negative.The value of b is zero.

Now, remember that all coordinates with the form (a,0), represents points on the x-axis, because the y-coordinate is zero.

In this case, we have negative horizontal coordinates and a null vertical coordinate, like (-a,0).

This points is on the x-axis, because y-value is null. Actually, it's on the negative part of x-axis, because its horizontal coordinate is negative.

Therefore, the right answer is x-axis.

What is the value of a?

Answers

Because the triangles are similar, we can form the proportion 3/4 = 4/a

Cross multiply and solve for 'a'

3/4 = 4/a
3*a = 4*4
3*a = 16
3*a/3 = 16/3
a = 16/3
a = (15+1)/3
a = (15/3)+(1/3)
a = 5+(1/3)

The answer is choice B)

A circular fountain has a circular walkway surrounding it with a width of 7 ft. The total area taken up by the walkway is 693π ft^2. Find the diameter of the pool.

Answers

check the picture below.

[tex]\bf A=2\pi pw\quad \begin{cases} w=7\\ A=693\pi \end{cases}\implies 693\pi =2\pi p7\implies \cfrac{693\pi }{14\pi }=p \\\\\\ 49.5=p\\\\ -------------------------------\\\\ r=p-\cfrac{w}{2}\implies r=49.5-3.5\implies r=46[/tex]

now, that's just the radius of the pool, the diameter would be twice as much, or 2r.

Can two numbers have a GCF that is bigger than their LCM? Explain how you know?

Answers

The answer to this question would be: No, they can't

Greatest common factor biggest possible value is the number value itself. There is no factor that bigger than the number.

But the least common multiple smallest possible value is the number. There is no multiple that smaller than the number.

So it is not possible to have GCF bigger than LCM.

Use the number 913,256. Write the name of the period that has the digits 913.

Answers

9 hundred 13 thirteen thousand

The Grand Prix Formula 1 race this weekend is in Singapore. The race consists of 61 laps around a 5.067 km long track. At 225 miles per hour, how long will it take to go around once?

Answers

1 mile ≈ 1.6 km

5.067 km ≈ 5.067÷1.6 ≈ 3.2 miles

time travelled = distance ÷ speed
time travelled = 3.2÷225
time travelled = 0.0142 hour = 51.2 seconds

when I make macaroni and cheese for my brother and me, I use 2 2/3 tablespoons of butter. how much butter will I n need to make my macaroni and cheese dish for Thanksgiving dinner if 15 people are attending?

Answers

if you use 2 2/3 tablespoons for you and your brother, that means, you need 2 2/3 tablespoons for two servings, how many tablespoons for 15 servings then?

well  [tex]\bf 2\frac{2}{3}\implies \cfrac{2\cdot 3+2}{3}\implies \cfrac{8}{3}\\\\ -------------------------------\\\\ \begin{array}{ccllll} \textit{butter spoons}&servings\\ -----&-----\\ \frac{8}{3}&2\\ x&15 \end{array}\implies \cfrac{\frac{8}{3}}{x}=\cfrac{2}{15}\implies \cfrac{\frac{8}{3}}{\frac{x}{1}}=\cfrac{2}{15} \\\\\\ \cfrac{8}{3}\cdot \cfrac{1}{x}=\cfrac{2}{15}\implies \cfrac{8}{3x}=\cfrac{2}{15}\implies 8\cdot 15=3x\cdot 2\implies 120=6x \\\\\\ \cfrac{120}{6}=x\implies 20=x[/tex]

Shelley spent 17 minutes washing dishes. She spent 38 minutes cleaning her room. Explain how you can use mental math to find how long Shelley spent on the two tasks.

Answers

17 + 38 your add both numbers. and you get 55
All you need to do is round up 17 and 38 to 20 and 40 in your head. Solve for that in your head and then subtract 5 from the sum.

20+40=60
60-5+55

Kevin is solving this problem. 737 × 205 What are the partial products Kevin will need to solve the problem? A. 3,685 and 147,400 B. 3,685 and 14,740 C. 3,685 and 1,474 D. 3,685 and 7,370 and 147,400

Answers

the answer is A

700 x 5 = 3500

30 x 5 = 150

7 x 5 = 35

3500 + 150 +35 = 3685

700 x 200 = 140,000

30 x 200 = 6000

7 x 200 = 1400

140000 + 6000 + 1400 = 147400

Steps to solve y=3x + 8

Answers

Step 1. Subtract 8 from both sides

[tex]y-8=3x[/tex]

Step 2. Divide both sides by 3

[tex] \frac{y-8}{3} =x[/tex]

Step 3. Switch sides

[tex]x= \frac{y-8}{3} [/tex]

Done! :) Hope this helps!

how to simplify expression by distribution 3(2y-7)

Answers

6y-27
Multiply 3 by everything inside the parenthesis

The sum of two consecutive even integers equals 6426?

Answers

First integer: x
Second integer: x+2

x+x+2=6426
2x+2=6426
2x=6424
x=3212

So your two integers are: 3212 and 3214

In a survey of 3450 registered voters who reside in California, 1789 were found to be republican. Construct a confidence estimate for the true percentage of republicans among registered voters in California. Use a confidence level of 95%.

Answers

Given:
n = 3450, sample size
p = 1789/3450 = 0.519 = 51.9%, proportion
Confidence level = 95%

The confidence interval is given by
[tex]p \pm z*\sqrt{ \frac{p(1-p)}{n} }[/tex]
where z* = 1.96 at the 95% confidence level.

[tex]1.96 \sqrt{ \frac{0.519(1-0.519)}{3450} } = 0.0167[/tex]
Therefore the 95% confidence interval is
(0.519 - 0.0167, 0.519 + 0.0167)
= (0.5023, 0.5357)
= (50.2%, 53.6%)

Answer:
At the 95% confidence level, the interval for the proportion is about (50%, 54%).

Choose the solution for the equation.

d3=284? need help asap

Answers

[tex]d^3=284\\ d=\sqrt[3]{284}[/tex]

Answer:

the answer is A

Step-by-step explanation:

ttm

Carlos is putting money into a savings account. He starts with $750 in the savings account, and each week he adds $40 . Let S represent the total amount of money in the savings account (in dollars), and let W represent the number of weeks Carlos has been adding money. Write an equation relating S to W . Then use this equation to find the total amount of money in the savings account after 11 weeks.

Equation:
Total amount of money after 11 weeks:

Answers

Final answer:

The equation relating the total amount of money S in Carlos's savings to the number of weeks W he adds money is S = 750 + 40W. By substituting W with 11, we find that after 11 weeks, Carlos will have $1,190 in his savings account.

Explanation:

The question involves creating a linear equation to represent the relationship between the total amount of money S in Carlos's savings account and the number of weeks W he has been adding money. The equation can be written as S = 750 + 40W, where 750 represents the initial amount and 40 is the amount added each week. To find the total amount of money after 11 weeks, substitute W with 11:

S = 750 + 40(11) = 750 + 440 = 1190

Therefore, after 11 weeks, the total amount of money in the savings account would be $1,190.

During a sale, a dress decreased in price from $90 to &63. What was the percent of decrease?

Answers

%change=100(final-initial)/initial

%change=100(63-90)/90

%change= -30%

So the price was decreased by 30%

If the minimum value of the function y = cos θ + d is –5, the value of d is...

Answers

the minimum value of cosθ is -1
-1 + d = -5
d = -4

The value of d, when the function is at its minimum is -4.

What is a Function?

A function is a law that relates two variables namely, a dependent and an independent variable.

A function always has a defined range and domain, domain is all the value a function can have as an input and range is all the value that a function can have.

The function is of various types, logarithmic, exponential, quadratic, radical etc.

The function is y = cos [tex]\rm \theta[/tex] + d

The minimum value of the function, y = cos [tex]\rm \theta[/tex] + d is -5.

The minimum value is the lowest value of the function.

The minimum value of cos [tex]\rm \theta[/tex] is at 180 degree equals to  -1

Substituting the value in the equation.

-5 = - 1 + d

d = -5 +1

d = -4

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what is the other measurement of the shape?

Answers

for the length of the side that is not given:

look at it as part of a triangle with the legs being 4m tall by 6 m wide

 so 4^2 + 6^2 = X62

16+36 = 52^2

square root(52) = 7.211 m

 does it as to round of to nearest whole number? nearest tenth?

round off answer as needed

FIND THE FOLLOWING USING THE GIVEN TRIANGLE...PLEASE HELP ME SUCK AT MATH...SOS!!! ASAP!!!!

Answers

perimeter = 20 +20 +24 = 64 feet

 area = 12^2 + x^2 = 20^2

144 + x^2 = 400

x^2 = 256

x = sqrt(256) = 16 feet

area = 1/2 x 16 x 24 = 192 square feet


 cost = 192 x $2 = $384

1. An elf, a dwarf, a hobbit, a wizard, and a man are sitting in a line. How many different ways can they sit if the elf and the dwarf insist on sitting next to each other?

a. 6 ways
b. 48 ways
c. 36 ways
d. 12 ways
e. 24 ways

2. How many ways can you order a hamburger of you can order it with or without cheese, lettuce, tomatoes, pickles, or onions?

a. 10
b. 32
c. 64
d. 5

Answers

1. An elf, a dwarf, a hobbit, a wizard, and a man are sitting in a line. How many different ways can they sit if the elf and the dwarf insist on sitting next to each other?

a. 6 ways
b. 48 ways
c. 36 ways
d. 12 ways
e. 24 ways

elf, dwarf, hobbit, wizar, man = 5 characters

Treat first elf and dwarf as one unique character, due to they will sit next to each other.

So, calculate the number of different ways 4 can sit, i.e permutations of 4 = 4! = 4*3*2*1 = 24 ways.

Given thath elf and dwarf can exchage their position between them, the above quantity has to be multiplied by 2:

24 * 2 = 48.

Answer: option b) 48 ways


2. How many ways can you order a hamburger if you can order it with or without cheese, lettuce, tomatoes, pickles, or onions?

a. 10
b. 32
c. 64
d. 5

with or without cheese => 2 options
with or without lettuce => 2 options
                        tomatoes => 2 options
                        pickles => 2 options
                        onions  => 2 options

=> 2*2*2*2*2 = 32 ways.

answer: option b) 32

Final answer:

In this question, the arrangements of characters sitting together and the options for hamburger toppings are explored using permutations and combinations in Mathematics for High School.

Explanation:

(1) When the elf and the dwarf insist on sitting next to each other, treat them as one entity. Then, there are 4 entities: {elf & dwarf}, hobbit, wizard, man. This gives 4! ways to arrange them, and the elf and dwarf can be arranged within their entity in 2! ways.

So, the total ways are 4! x 2! = 48 ways.

(2) For the hamburger order, since you can choose to include/exclude each topping independently, there are 2 options for each topping (with or without).

Hence, the total ways to order the hamburger are 2⁵ = 32 ways.

Write five numbers that round to 360 When rounded to the nearest 10.

Answers

355, 356, 357, 358, 359

Mateo is constructing an equilateral triangle inscribed in a circle with center P. He draws the diameter of the circle through center P using a straight edge. Next he opens his compass to a width equivalent to the radius of the circle. What is his next step?

Answers

Reading the question carefully, "He draws the diameter of the circle through center P using a straight edge. Next he opens his compass to a width equivalent to the radius of the circle." - that implies that Mateo is still in the process of drawing the circle by which the equilateral is inscribed to.

The next steps should be:
*He should draw the upper and lower arcs using the compass opened to a width equivalent to the radius of the sircle.
*Make a vertical diameter using centroid P as basis.
*Draw two right triangles facing the opposite directions using the top most point by which the vertical diameter of the circle touches the top most circumference of the circle.

Doing these steps, Mateo will be able to draw an equilateral triangle inscribed in a circle.
 

on a certain planet, objects weight about 7/12 of what they weigh on earth. an object weights 13 5/12 pounds on the planet. solve the equation 7/12 w= 13 5/12 for w to find the objects weight on earth in pounds.

Answers

Although the concept here is physics, the solution is technically just algebra. You have two situations that are related to each other which can be expressed in equation form. Actually, the equation is already given which is 7/12 w= 13 5/12. So, basically, all you have to do is solve for w.

Let's simplify 13 5/12 first into an improper fraction.You do this by multiplying the denominator with the whole number and adding to it the numerator. This will be your new numerator, The denominator would still be 12. So, this is equal to (12*13 + 5)/12 = 161/2. Then,

(7/12) w = 161/12

By cross multiplication,

7*12*w = 161*12
w = 161/7 = 23

Therefore, w = 23 pounds which is the weight of the object on Earth.


To keep heating costs down for a structure, architects want the ratio of surface area to volume as small as possible. An expression for the ratio of the surface area to volume for the square prism shown is ​. Find the ratio when b = 12 ft and h = 18 ft.

Answers

The answer is 5/6

Hope this helps!

How long will it take a bird traveling at an average speed of 12 miles per hour to travel 202 miles while flying south for winter?

Answers

divide 202 by 12, and you will get 16.83 so basically you woukd round that up and say it is about 17 hours time, I dont know if whoever is asking you the question but if they dont want it rounded up then it is 16.83 hours, if they do want it estimated/rounded up then it is 17 hours , hope this helps you have a blessed day

Answer:

16 50 min

Step-by-step explanation:

Which of the following is the conjugate of a complex number with 2 as the real part and −8 as the imaginary part?

Answers

The complex number is given as: 2-8i

So for conjugate, you just flip the sign of the imaginary part:

2+8i will be the answer
Answer:

The conjugate of the given complex number is:

                        [tex]2+8i[/tex]

Step-by-step explanation:

We know that any complex number is written in the form of:

            [tex]z=a+ib[/tex]

where a and b are real numbers.

The conjugate of the complex number is given by:

              [tex]\bar z=\bar {a+ib}\\\\i.e.\\\\\bar z=a-ib[/tex]

Here we are given that:

We have a complex number such that the  real part of a complex number is 2 and it's imaginary part is -8.

i.e.

a=2 and b= -8

i.e. the complex number is:

[tex]z=2+(-8)i[/tex]

Hence, the conjugate of this number is:

[tex]\bar z=2-(-8)i\\\\i.e.\\\\\bar z=2+8i[/tex]

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