Percy works two part-time jobs to help pay for college classes. On Monday, he works 3 hours at the library and 2 hours at the coffee cart and earns $36.50. On Tuesday, he works 2 hours at the library and 5 hours at the coffee cart and earns $50. His hourly wage at the library, x, and hourly wage at the coffee cart, y, can be determined using the system of equations below. 3x + 2y = 36.50 2x + 5y = 50.00 At which job does Percy earn the greater hourly wage? How much does Percy earn each hour at this job? Percy earns a greater hourly wage of $7.00 at the library. Percy earns a greater hourly wage of $7.00 at the coffee cart. Percy earns a greater hourly wage of $7.50 at the library. Percy earns a greater hourly wage of $7.50 at the coffee cart.

The student is looking for the terms 'Verbal Description' and 'Function Notation' for their Algebra Vocabulary Crossword. These refer to a relation described in word format and a way to name a function identifying its input respectively.

Based on the number of letters you've indicated, it looks like you're looking for two vocabulary items in the field of Algebra.

First, a relation described in a word format is typically called a Verbal Description, which has 17 letters.

Second, a way to name a function identifying its input is called Function Notation, which has 16 letters.

In Algebra, Verbal Description is when you describe a mathematical relationship using words. For example, 'the sum of a number and three is seven.' This could be translated to the equation x+3=7.

Function Notation, on the other hand, is a way to name a function that is dependent on one or more inputs. For example, f(x) = x^2 is function notation, since the output 'f(x)' is dependent on the input 'x'.

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Answer:

I think B,not sure

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Got it right

Answer:

13

Step-by-step explanation:

it correct

Michael makes a total of $400 from his land investment after calculating the total losses and gains from the lands sold.

In order to find out the total money that Michael has made from his land investment, you need to calculate the losses and the gains individually. Michael sells two of his lands at a loss of $1,200 each, hence his total loss is 2 * $1,200 = $2,400. On the other hand, he sells the other two lands at a profit of $1,400 each, hence his total profit is 2 * $1,400 = $2,800.

To get the total money that he made on his investment, you subtract the total loss from the total profit. That is $2,800 (total profit) - $2,400 (total loss) = $400. Hence, Michael makes $400 on his investment.

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the answer is 5

1: a^3

2: 3a^2b

3: 4ab

4: 11b

5: 7

anything seporated by a + or - is a term

By solving the system of equations which includes the total commission and difference in quantity of iPhones and iPads sold, we determine that the salesperson sold 8 iPads and 12 iPhones.

The student is tasked with solving a system of linear equations to determine how many iPhones and iPads were sold based on the commission earned. Let's define the number of iPads sold as x and the number of iPhones as x + 4.

The total commission for iPhones is $30 per iPhone and the total commission for iPads is $20 per iPad. The total commission earned from selling these products is $520.

We can set up two equations based on the given information:

Commission from iPhones: 30(x + 4)

Commission from iPads: 20x

Total Commission: 30(x + 4) + 20x = 520

By solving the equation 30(x + 4) + 20x = 520, we find:

30x + 120 + 20x = 520

50x + 120 = 520

50x = 400

x = 8

So, the number of iPads sold is 8. Since the number of iPhones sold is 4 more than iPads, we have:

Number of iPhones sold = x + 4 = 8 + 4

Number of iPhones sold = 12

Therefore, the salesperson sold 8 iPads and 12 iPhones respectively.

The probability that the product of the numbers selected by Neil and Jean is even is approximately 0.8889.

To answer your question, let's first classify the numbers from the given set 1,2,3,4,5,6,7,9,10 into two categories: even numbers (2, 4, 6, 10) and odd numbers (1, 3, 5, 7, 9). Each of the people, Neil and Jean, can pick any number independently. Hence we have two scenarios which result in the product being even - either both pick even numbers or at least one of them picks even.

The probability of both picking an even number is (4/9)*(4/9) = 16/81. Also, there is no constraint on the second scenario, so, total probabilities = 1. Hence, the probability of at least one picking an even is 1 - probability(both picking odd) = 1 - (5/9)*(5/9) = 1 - 25/81 = 56/81.

Therefore, the total probability that the product of the numbers selected by Neil and Jean is even is the sum of the above two probabilities i.e., 16/81 + 56/81 = 72/81 = 0.8889 (approx).

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The number of students in the freshman class are:

                                 202

Let the number of students in Freshman class = x

This means that the number of students in sophomore class = x+60

This means that the number of students in junior class= 2x-50

This means that the number of students in senior class are: 3x

This means that:

[tex]x+x+60+2x-50+3x=1424\\\\x+x+2x+3x+60-50=1424\\\\7x+10=1424\\\\7x=1424-10\\\\7x=1414\\\\x=\dfrac{1414}{7}\\\\x=202[/tex]

Answer:

  5 : 1

Step-by-step explanation:

From your second-grade memorization of multiplication tables, you recognize that 15 = 3×5, so you know 3 is a factor of both numbers in the ratio. To reduce the ratio to simplest form, you divide out all common factors:

  15 : 3 = (15/3) : (3/3) = 5 : 1

[tex]\( b_1 = \frac{A}{12h} - b_2 \)[/tex] is the formula to solve for [tex]\( b_1 \)[/tex] in the trapezoid area equation.

To solve for [tex]\( b_1 \) in the equation \( A = 12h(b_1 + b_2) \), where \( A \)[/tex] is the area of the trapezoid, [tex]\( h \) is the height, \( b_1 \)[/tex]is one of the bases, and [tex]\( b_2 \)[/tex] is the other base, you can follow these steps:

1. Divide both sides of the equation by [tex]\( 12h \) to isolate \( (b_1 + b_2) \):[/tex]

[tex]\[ \frac{A}{12h} = b_1 + b_2 \][/tex]

2. Subtract [tex]\( b_2 \)[/tex] from both sides of the equation:

[tex]\[ \frac{A}{12h} - b_2 = b_1 \][/tex]

So, the equation for [tex]\( b_1 \) in terms of \( A \), \( h \), and \( b_2 \)[/tex] is:

[tex]\[ b_1 = \frac{A}{12h} - b_2 \][/tex]

The value of 'y' when x equals -486 using the same ratio (1:6) as given in the original input is -81.

To solve this problem, we're given a ratio of y to x (1:6) when x is -264 and y is 44. This ratio implies that y is one-sixth of x. Utilizing this information, we can determine y for a different x value (-486). By maintaining the 1:6 ratio, we divide -486 by 6, resulting in -81. Therefore, when x is -486, y equals -81. This solution stems from understanding the proportional relationship between y and x, allowing us to calculate y for any given x value based on the established ratio. In this case, the ratio of 1:6 guides the computation, ensuring the accurate determination of y as -81 when x is -486.

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1 package of plates = 10 plates  and 2 package of cups = 10 cups

 so 3 packages is least amount

Answer:

The answer is 27:125

Cho welcome

To determine if |3-8| is equal to |3+8|, we calculate the absolute values: |3-8|=5 and |3+8|=11. Since 5 is not equal to 11, the statement is false.

To solve the given problem, we need to understand the properties of absolute values. Absolute value measures the distance of a number from zero on the number line, regardless of direction.

       3 - 8 = -5, and the absolute value of -5 is 5. Therefore, |3-8| = 5.

        3 + 8 = 11, and the absolute value of 11 is 11. Therefore, |3+8| = 11.

In conclusion, it is not true that |3-8| equals |3+8|, as |3-8| = 5 and |3+8| = 11.

here is the full question-Is it true that |3-8| and |3+8| are equal?