Please answer right away and don’t guess

Answer:

D.) 6 and 2

Step-by-step explanation:

Supplementary angles are two angles which sum up to 180°.

Answer:

B. [tex]\angle 2\text{ and }\angle 5[/tex]

Step-by-step explanation:

We have been given an image of intersecting lines. We are asked to find the pair of angles that must be supplementary.

We know that two angles are supplementary when they add up-to 180 degrees.

Upon looking at our given image, we can see that the measure of angle 2 and measure of angle 5 is 90 degrees. So these angles will add up-to 180 degrees, therefore, option B is the correct choice.

50% is ur answer your welcome

Answer:

Part 1) [tex]z=4\sqrt{3}\ units[/tex]

Part 2) [tex]y=4\sqrt{2}\ units[/tex]

Part 3) [tex]x=4\sqrt{6}\ units[/tex]

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

Find the value of z

In the right triangle DBC

[tex]cos(C)=\frac{4}{z}[/tex] ----> equation A

In the right triangle ABC

[tex]cos(C)=\frac{z}{12}[/tex] ----> equation B

equate equation A and equation B

[tex]\frac{4}{z}=\frac{z}{12}[/tex]

[tex]z^{2}=48[/tex]

[tex]z=4\sqrt{3}\ units[/tex]

step 2

In the right triangle DBC

Applying the Pythagoras Theorem

[tex]z^{2}=y^{2}+4^{2}[/tex]

we have

[tex]z=4\sqrt{3}\ units[/tex]

substitute

[tex](4\sqrt{3})^{2}=y^{2}+4^{2}[/tex]

[tex]48=y^{2}+16[/tex]

[tex]y^{2}=48-16[/tex]

[tex]y^{2}=32[/tex]

[tex]y=4\sqrt{2}\ units[/tex]

step 3

Find the value of x

In the right triangle ABC

Applying the Pythagoras Theorem

[tex]12^{2}=x^{2}+z^{2}[/tex]

we have

[tex]z=4\sqrt{3}\ units[/tex]

substitute

[tex]12^{2}=x^{2}+(4\sqrt{3})^{2}[/tex]

[tex]144=x^{2}+48[/tex]

[tex]x^{2}=144-48[/tex]

[tex]x^{2}=96[/tex]

[tex]x=4\sqrt{6}\ units[/tex]

Answer:

B

Step-by-step explanation:

Test Yourself

Answer:

100pi in^2, or 314.16 in^2 to nearest hundredth.

Step-by-step explanation:

The areas of the surface of water for  full basin and area for the surface when the depth is 10 inches are in the ratio 25^2 : 10^2 = 6.25 : 1. (because the depth of the water = radius of the water when the basin is full).

The area for a full basin =  pi r^2 = 625pi in^2.

So the area  when depth is 10 inches =  625pi / 6.25 = 100pi in^2.

the answer is I think -10.2

To find out how many pounds of apples Meredith has left after 4 hours, we need to subtract the total change in apples from the original amount.

To find out how many pounds of apples Meredith has left after 4 hours, we need to subtract the total change in apples from the original amount. Let's calculate step-by-step:

To find the total change, we need to add the individual changes:

Total Change = -8.5 + (-12 2/3) + (-16 1/5) + (-10.2) = -47 61/60 pounds

Now, we subtract the total change from the original amount:

Final Amount = 85.4 - 47 61/60 pounds

Calculate the final amount to find out how many pounds of apples Meredith has left.

https://brainly.com/question/20438352

#SPJ11

Answer:

D. 13 cm

hope it helps

Answer:

13d

Step-by-step explanation:

I believe it’s D or B

Answer:

0.27

Step-by-step explanation:

Red marbles = 4

Yellow marbles = 16

Purple marbles = 5

Blue marbles = 16

Green marbles = 10

Total marbles

= 4 + 16 + 5 + 16 + 10

= 51

Red and Green marbles

= 4 + 10

= 14

P(Red or green marbles)

= 14/51

= 0.27

Answer:

0.27

Step-by-step explanation:

Red marbles = 4

Yellow marbles = 16

Purple marbles = 5

Blue marbles = 16

Green marbles = 10

Total marbles

4 + 16 + 5 + 16 + 10 = 51

Red and Green marbles

= 4 + 10

= 14

P(Red or green marbles)

= 14/51

= 0.27

hope this helps pls make my answer the brainliest

ANSWER

[tex]( \sin(x) + 2)( \sin(x) - 1)[/tex]

EXPLANATION

The given trigonometric function is:

[tex] \sin^{2} x + \sin(x) - 2[/tex]

This is a quadratic trinomial in sinx

We split the middle term to obtain:

[tex]\sin^{2} x + 2 \sin(x) - \sin(x) - 2[/tex]

[tex] \sin \:x ( \sin(x) + 2 ) - 1( \sin(x) + 2)[/tex]

The factors are:

[tex]( \sin(x) + 2)( \sin(x) - 1)[/tex]

Answer:

x1= 14/4 and X2 = -2

Step-by-step explanation:

To find the values of "X" for which when the function is evaluated gives 19 we need to equal the function to 19, as follows:

2x^2+3x+5 = 19

2x^2+3x+5-19=0

2x^2+3x-14=0

Then, solving for "x" we need to use the quadratic formula (Attached), where a, b, and c, are the following:

a: 2 b: 3 c: 14

Using the quadratic formula, we get:

x1= 14/4 and X2 = -2

50 F

32 F - - 18 = 32 F + 18= 50 F

Step-by-step explanation:

Whole numbers means 0,1,2,3,4,5 ........................................ up to infinity.

We need to find graph of whole number greater than 3

The numbers are 4, 5 , 6 , 7 , 8 , 9 ............................................... up to infinity.

The graph representing this is the second graph.

Second graph is the correct answer.          

Answer: graph number 2 is correct

Step-by-step explanation:

i just wanted to verify for others

Answer: 1/6

Step-by-step explanation:

1/6+1/6+16 hope this helps!

the answer would be -3,1,2

Hello!

From Least To Greatest Your Numbers Would Be

ANSWER

The mean absolute deviation is 1.75

EXPLANATION

The given date set is 2, 2, 5, 6, 8, 4, 8, 5

The mean is

[tex]\bar X = \frac{2 + 2 + 5 + 6 + 8 + 4 + 8 + 6}{8} = 5[/tex]

The mean absolute value deviation is given by:

[tex] =\frac{ \sum |x -\bar X| }{n} [/tex]

[tex] = \frac{ | 2 - 5| + |2 - 5|+ |5- 5|+ |6 - 5|+ |8 - 5| + |4 - 5|+ |8- 5|+ |5 - 5| }{8} [/tex]

[tex]= \frac{ 3 + 3+ 0+ 1+ 3 + 1+3+ 0}{8} [/tex]

[tex] = \frac{14}{8} [/tex]

[tex] = 1.75[/tex]

Answer:

1. f(x)= [tex]\left \{ {{1/xWHEN x<1 ANDx\neq 0} \atop {\sqrt[3]{x}WHEN x\geq 1}} \right.[/tex]

2. yes this graph represents a polynomial, this line is of the form y=mx+b; there are no turning points as it is a polynomial of degree 1.

Step-by-step explanation:

For problem 1:

as can be seen in the given graph, the graph of 1/x is ended at the value of x=1 and for all the values of x>1.

so the condition x<1 and x[tex]\neq[/tex]0 applies here

then for graph [tex]\sqrt[3]{x}[/tex], the graph starts from (1,1) and there is no extension of it beyond the value of x=1.

so the condition x[tex]\geq[/tex]1 applies here.

For Problem 2:

the given graph is a linear line which is represent by polynomial y=mx+b

and the polynomial y=mx+b is a polynomial of degree 1.

As the given graph is a graph of straight line represented by y=mx+b there are no turning points.

!

Answer:

13.64%

Step-by-step explanation:

The increase, from 132 to 150, is 18.

Comparing 18 to the original 132, we get 18/132 = 0.1364

Rewriting this as a percentage change, we get 0.1364, or 13.64%.   The percentage increase from 132 to 150 is 13.64%.

Answer:

The dependent variable is the rate (3 meters per second) and the independent variable is m (the amount of meters he runs). This is because the rate changes based on the amount of meters he runs.

Answer:

The seconds are independent and the meters are dependent

Answer:

x = 4 in

Step-by-step explanation:

scale factor of reduction is

[tex]\frac{6}{18}[/tex] = [tex]\frac{1}{3}[/tex], thus

x = [tex]\frac{1}{3}[/tex] × 12 = 4

Answers

Part a: Opposite

Part b: cos

Part c: Adjacent

Explanation

If you doing sine, cosine, and tangent, just remember SOHCAHTOA.

Answer:

The measures of angles of this Δ are 23° , 67° , 90°

Step-by-step explanation:

* Lets talk about some facts in the circle

- An inscribed angle is an angle made from points sitting on the

 circle's circumference

- A central angle is the angle formed when the vertex is at the center

 of the circle

- The measure of an arc of a circle is equal to the measure of the

 central angle that intercepts the arc.

- The measure of an inscribed angle is equal to 1/2 the measure of

 its intercepted arc

- An angle inscribed across a circle's diameter is always a right angle

- The triangle is inscribed in a circle if their vertices lie on the

  circumference of the circle, and their angles will be inscribed

  angles in the circle

* Now lets solve the problem

- Δ ABC is inscribed in a circle

∵ its side AB is a diameter of the circle

∵ Its vertex C is on the circle

∴ ∠C is inscribed and across the circle's diameter

∴ ∠C is a right angle

∴ m∠C = 90°

∵ The measure of arc BC = 134°

∵ ∠A is inscribed angle subtended by arc BC

∵ The measure of an inscribed angle is equal to 1/2 the measure

   of its intercepted arc

∴ m∠A = 1/2 × 134° = 67°

∵ The sum of the measures of the interior angles of a triangle is 180°

∵ m∠A = 67°

∵ m∠C = 67°

∵ m∠A + m∠B + m∠C = 180°

∴ 67° + m∠B + 90° = 180°

∴ 157° + m∠B = 180° ⇒ subtract 157 from both sides

∴ m∠B = 23°

* The measures of angles of this Δ are 23° , 67° , 90°

Answer: B

Step-by-step explanation: Got it right on edge

Answer:B

Step-by-step explanation:I did it

For this case we must simplify the following expression:

[tex]\sqrt [3] {64 * a ^ 6 * b ^ 7 * c ^ 9}[/tex]

We rewrite:

[tex]64 = 4 ^ 3\\a ^ 6 = (a ^ 2) ^ 3\\b ^ 6 * b = ((b ^ 2) ^ 3 * b)\\c ^ 9 = (c ^ 3) ^ 3[/tex]

So:

[tex]\sqrt [3] {4 ^ 3 * (a ^ 2) ^ 3 * (b ^ 2) ^ 3 * b * (c ^ 3) ^ 3} =\\\sqrt [3] {4 * a ^ 2 * b ^ 2 * c ^ 3) ^ 3 * b} =[/tex]

By definition of properties of powers and roots we have:

[tex]\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}[/tex]

So:

[tex]4a ^ 2b ^ 2 c ^ 3 \sqrt [3] {b}[/tex]

Answer:

Option B

The area is the length x the height.

Length = 11.40 cm

Height = 6.90 cm

Area = 11.40 * 6.90 = 78.66 cm^2

The answer is D.

[tex]\bf \stackrel{\textit{let's recall that }}{a+a \implies a(1+1)\implies a(2)\implies 2a} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{a}{\cfrac{9}{12}}+\stackrel{a}{\cfrac{9}{12}}\implies \stackrel{a}{\cfrac{9}{12}}(1+1)\implies \cfrac{9}{12}(2)\implies 9\cdot \cfrac{2}{12}\implies 9\cdot \cfrac{1}{6}\implies \cfrac{9}{6}\implies \cfrac{3}{2}[/tex]

Answer:

[tex]6T+4Z\leq 49[/tex]

Step-by-step explanation:

Let

T----> the number of tomatoes

Z---> the number of zucchinis

we know that

The inequality that represent this situation is

[tex]6T+4Z\leq 49[/tex]

using a graphing tool

The solution is the triangular shaded area

see the attached figure

Answer:

Data set B has a higher range than data set A and thus B has a higher degree of variability than A.

Step-by-step explanation:

There are several measures of variability in Statistics among them being;

The range

The inter-quartile range

Variance and standard deviation

To compare the variability of two or more sets of data, we can compute any of the above measures of dispersion and compare them across the various data sets.

In this question we have been given two data sets;

Data Set A: 18, 24, 29, 30, 39

Data Set B: 26, 29, 39, 40, 52

The simplest measure of variability or dispersion is the range. The range is defined as the difference between the maximum and the minimum values in a data set.

The range of data set A is; 39 - 18 = 21

The range of data set B is; 52 - 26 = 26

Data set B has a higher range than data set A and thus B has a higher degree of variability than A.

Answer:

1) 48

C) It corresponds to the 48-degree angle

Step-by-step explanation:

k║l

1) <1 = 48

because corresponding angles are equal

Why?

C) It corresponds to the 48-degree angle

Answer:

1) 48 and C) It corresponds to the 48-degree angle.

Step-by-step explanation:

Seeing the parallel lines k and l, and the transversal line m, we have that 48° and angle 1 are corresponding angles because k and l are parallel, then, the angle formed with the same transversal line will have the same measure.

So, the measure of angle 1 is 48 (option 1) and the reason is C) It corresponds to the 48-degree angle.

Answer:

9. ∠A ≅ ∠R

10. SI ≅ GH

11. MN ≅ RN

12. FE ≅ TU

Step-by-step explanation:

Look at the reason identifier: A means "angle"; S means "side". The order is important. AAS means two adjacent angles with only one of them next to the corresponding sides. SAS means the angle is between two corresponding sides.

9. Sides CS and TS correspond and are congruent. The vertical angles at S are congruent, so the AAS identifier means you're looking for angles A and R to be congruent. (Using angles C and T would invoke the ASA identifier.)

__

10. Sides HI are congruent; the angles at H and I are congruent. The SAS identifier means you're looking for the sides on the other side of those angles to be congruent: sides SI and GH.

__

11. SSS means you're claiming all three sides are congruent to their corresponding sides. The common side is congruent to itself; the marked sides are congruent. So, you need the unmarked sides to be congruent to each other.

__

12. HL means you're claiming the hypotenuse and one leg of the right triangle are congruent. One leg is already marked, so you need the hypotenuses to be congruent.