PLEASE HELP ASAP 40 PTS + BRAINLIEST TO RIGHT/BEST ANSWER

[tex]\bf \textit{sum of all interior angles in a polygon}\\\\ n\theta =180(n-2)~~ \begin{cases} n=sides'~number\\ \theta =angle~in\\ \qquad degrees\\ \cline{1-1} \theta =140 \end{cases}\implies n140=180(n-2) \\\\\\ 140n=180n-360\implies 140n+360=180n\implies 360=40n \\\\\\ \cfrac{360}{40}=n\implies 9=n[/tex]

Answer:

-5

Step-by-step explanation:

∛-25 × ∛5

= ∛-75

= ∛(-5)^3

= - 5

Answer:

a

Step-by-step explanation:

(-25)^⅓ × 5^⅓

(-25 × 5)^⅓

(-125)^⅓

(-5)³^⅓

-5

Answer:

(3,-5

Step-by-step explanation:

x=3 y=-2*3+1=-5

Answer:

-12 is the correct answer

Answer:

The equation for the circle is (x-0)^2+(y+3)^2=25

Step-by-step explanation:

The radius is half the diameter.  To find the length of the diameter we need to calculate the distance that (3,1) is to (-3,-7) which is sqrt(6^2+8^2)=10 .

The radius is therefore 10/2=5.

We also need the center of the circle (the midpoint of a diameter is the center of a circle).  So we just need to average the x's and y's to find the midpoint between (3,1) and (-3,-7) which is (0,-3).

The equation for the circle is (x-0)^2+(y+3)^2=25

I just plugged my info into (x-h)^2+(y-k)^2=r^2

where (h,k) is center and r is radius

Answer:

29

Step-by-step explanation:

Neoli can see 4 patients in an hour. (60 min)/(15 min) = 4

In the 8-hour work day, with no break, she could see (8 h)×(4 patients/h) = 32 patients.

However, her lunch break takes a time that is equivalent to the time for 3 patients.

Neoli can see 32 -3 = 29 patients per day on average.

Answer:

  B.)  24(y² -1)

Step-by-step explanation:

The denominator of the first fraction is 2³(y +1).

The denominator of the second fraction is 2·3(y +1)(y -1).

The LCD is the product of the unique factors to their highest powers:

  2³·3·(y +1)(y -1) = 24(y² -1)

Answer:

B

Step-by-step explanation:

Multiply the speed by the time:

35 miles per hour x 2.5 hours = 87.5 miles total.

Answer: 87.5 miles

Step-by-step explanation:

35 miles per 1 hour

35 * 2.5 = 87.5

Answer:

  1

Step-by-step explanation:

When you take the log of ...

  b = b^1

you get ...

[tex]\log_{b}{b}=1[/tex]

Answer:

x ≈ 46°

Step-by-step explanation:

Since the triangle is right use the sine ratio to solve for x

sinx = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{10}{14}[/tex], hence

x = [tex]sin^{-1}[/tex] ( [tex]\frac{10}{14}[/tex] ) ≈ 46°

Answer:

72%

Step-by-step explanation:

You are looking at graduate students.  There are 2610 of them.

Of those graduates 1879 have financial aid.

So the probability of a graduate student having financial aid is 1879/2610.

Inserting this division into my calculator provides me with about 72%.

Answer:

B:  No

Step-by-step explanation:

P = 2L + 2W.  If L = 20 and W = 11, then P = 2(20) + 2(11), or 62.  This matches Answer B.

Answer:  The correct option is

(B) No. If the length is 20 and the width is 11, the perimeter is P = 40 + 22 = 62, not 64.

Step-by-step explanation:  Given that the perimeter of a rectangle can be found using the equation P = 2L + 2W, where P is the perimeter, L is the length, and W is the width of the rectangle.

We are to check whether the perimeter of the rectangle can be 64 units when its width is 11 units and its length is 20 units.

According to the given information, we have

Length, L = 20 units,  width, W = 11 units  and  Perimeter, P = 64 units.

We have

[tex]P\\\\=2L+2W\\\\=2\times20+2\times11\\\\=40+22\\\\=62\neq64.[/tex]

Therefore, if length is 20 units and width is 11 units, then perimeter P = 40 + 22 = 62 units, not 64.

Thus, the answer is NO.

Thus, option (B) is CORRECT.

Answer:

  4)  No, because over the long run your expected value is less than the cost to play

Step-by-step explanation:

The expected value is ...

  0.51×0.99 + 0.49×1.01 = 0.5049 +0.4949 = 0.9998

This expected value is less than the cost to play, so you will lose money in the long run. You should not play.

Answer:

The limitations on y-values changed from non-negative multiples of one-half to whole numbers, since Ezra cannot walk a fractional number of dogs.

The limitations on x-values did not change and must be non-negative multiples of one-half, since Ezra cannot work negative hours and charges by the half-hour.

The inequality x + y >= 1100 represents Ezra's earnings from his two jobs. If he changes his dog-walking fee to a per dog amount, the inequality changes to x + z >= 1100, shifting the solution set. This impacts the number of lawn mowing and dog walking jobs Ezra must do to earn at least $1100.

The question involves understanding of inequalities and how the solution set changes when the conditions change. Suppose Ezra earns x dollars for every lawnmowing job and y dollars for every dog-walking job. Then, his earnings would be represented by the inequality: x + y >= 1100.

Now, if he changes his dog-walking charges to be per dog instead of per hour, say z dollars per dog, we can modify our inequality to: x + z >= 1100.

The solution set for the new inequality would include all values of x and z that makes the inequality true - essentially how many lawn mowing and dogs walking jobs he needs to do to earn at least $1100. One thing to bear in mind is that both x and z must hold positive value since one cannot earn negative money from a job.

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Answer:

a red graph

Step-by-step explanation:

slope is 5 and the y intercept is negative 2(the y intercept is where the line crosses the y axis) then you rise over run

[tex]\bf ~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$625\\ r=rate\to 7\%\to \frac{7}{100}\dotfill &0.07\\ t=years\dotfill &12 \end{cases} \\\\\\ A=625e^{0.07\cdot 12}\implies \implies A=625e^{0.84}\implies A\approx 1447.73[/tex]

The investment will be $1447.73 worth in 12 years.

Continuous compounding exists the mathematical limit that compound interest can reach if it's calculated and reinvested into an account's balance over a theoretically infinite number of terms. While this exists not possible in practice, the vision of continuously compounded interest stands important in finance.

Since, the amount formula is compounded continuously,

[tex]$$A=P e^{r t}$$[/tex]

Where,

P is the principal amount,

[tex]$\mathbf{r}$[/tex] is the rate per period,

t is the number of periods,

e is Euclid number,

Here, [tex]$P=\$ 625$[/tex],

[tex]$$r=7 \%=0.07 \text {, }$$[/tex]

t=12 years

Thus, the amount after 12 years would be,

[tex]$$A=625 e^{0.07 \times 12}=625 e^{0.84}=\$ 1447.72936049 \approx \$ 1447.73$$[/tex]

Hence, $1447.73 will the investment be worth 12 years.

To learn more about continuous compound interest refer to:

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Answer:a= 0.9, b= -1, c= -0.6, d= 0.2

Step-by-step explanation:

Answer:

A= 0.9

B= -1

C= -0.6

D= 0.2

Answer:

88°

the total angle of hexagon is 720°

so 720-(120+120+172+125+95)=88

The total number of degrees in a hexagon is 720.

x + 172 + 120 + 95 + 120 + 125 = 720

x + 632 = 720

x = 720 - 632

x = 88

Answer:

Step-by-step explanation:

First we find the area of the circular sectors. From that we can find the cost of cement and their radius.

The area of the playground is ...

  playground area = (109 yd)^2 = 11,881 yd^2

Then the area of the skating rinks is ...

  rink area = playground area - remaining field

  rink area = 11,881 yd^2 - 9,055 yd^2 = 2,826 yd^2

Then the cost of cement for the rink area is ...

  (2826 yd^2)($2.50/yd^2) = $7065

__

The four quarter-circle skating rinks add to a total area of a full circle. That area is given by ...

  A = πr^2

Substituting what we know, we have ...

  2826 = 3.14r^2

  900 = r^2 . . . . . . . . divide by 3.14

  30 = r . . . . . . . . . . . take the square root

The radius of each quadrant is 30 yards.

Answer:

C.  two chords

Step-by-step explanation:

If the sides of an angle are inscribed in a circle that means that the endpoints of the sides of said angle lie on the circle.  That makes both of them chords.  

A diameter has to go through the center

A tangent is outside the circle

A radius comes from the center of the circle and meets the outside of the circle

The sides of an angle inscribed in a circle are two radii. These two radii connect from a single point on the circumference of the circle to two different points on the circumference.

In the field of Geometry, particularly in relation to circles, the sides of an angle that is inscribed in a circle constitute two radii. An inscribed angle is an angle formed by two lines (in this case, two radii) drawn from a single point on the circumference of a circle to two different points on the circumference. Therefore, the correct answer to the given problem would be option D, which states that the sides of an inscribed angle in a circle are two radii.

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You're gonna have to draw your own plot; let's fill in the table.

First let's count and sort the numbers;

2, 9, 10, 12, 14, 14, 15, 22, 32, 36, 43

n = 11

Median is the sixth one, in the middle:  14

Min: 2

Max: 43

Q1: For 11 points, the first quarter is between the 2nd and the 3rd: 9.5

Q3: Between 32 and 36: 34

Outlier? 43 maybe, hard to tell.

Mean: (2+9+10+12+14+14+15+22+32+36+43)/11 = 19

Range: from 2 to 43  

IQR: from 9.5 to 39.5

The mean doesn't get plotted in a box and whiskers plot.  The left whisker goes to the minimum, the left box Q1, the line through the box the median, the right box edge Q3, and the right whisker the maximum.

2.

I'm not really sure what they're talking about here, how about b for big blue squares, r for blue rectangles and s for small squares:

(5b + 6r + 10s) - (3b + 2r + 7s) = 2b + 4r + 3s

For this case we expand the series for each value of "n":

[tex]125 (\frac {1} {5}) ^ {1-1} +125 (\frac {1} {5}) ^ {2-1} +125 (\frac {1} {5}) ^ {3 -1} +125 (\frac {1} {5}) ^ {4-1} =[/tex]

[tex]125+ \frac {125} {5 ^ 1} + \frac {125} {5 ^ 2} + \frac {125} {5 ^ 3} =\\125+ \frac {125} {5} + \frac {125} {25} + \frac {125} {125} =\\125 + 25 + 5 + 1[/tex]

So, the correct option is: A

Answer:

Option A

Answer:

It’s A

Step-by-step explanation:

Answer:

  x = -11

Step-by-step explanation:

It is convenient to use 3·4 = 12 as a common denominator. That is, we can clear the fractions by multiplying the equation by 12.

  12(x +1)/2 -12(x +2)/3 = 12(x +3)/4

  6x +6 -4x -8 = 3x +9 . . . . . . simplify

  2x -2 = 3x +9 . . . . . . . . . . . . collect terms

  -11 = x . . . . . . . . . . . . . . . . . . add -9-2x

_____

Check

  (-11+1)/2 -(-11+2)/3 = (-11+3)/4 . . . . substitute -11 for x in the original

  -10/2 - (-9/3) = -8/4 . . . . . . . . . . . . simplify

  -5 +3 = -2 . . . . . . . . . . true

Answer:

Inter-quartile range =  3 .

Step-by-step explanation:

Given : diagram with data.

To find : What is the inter-quartile range of the given data set.

Solution : We have given data .

We can see from the given data lowest value of data is  15 .

highest value of data  = 21.

First quartile ( Q1) = 17

Second quartile (Q2) =18

Third quartile (Q3) = 20.

Inter-quartile range = Third quartile (Q3) - First quartile ( Q1) .

Inter-quartile range =  20 -  17

Inter-quartile range =  3 .

Therefore, Inter-quartile range =  3 .

Answer:

The area of the brick border is [tex](24x+144)\ ft^{2}[/tex]

Step-by-step explanation:

we know that

The area of the brick border is equal to

[tex]A=(x+12)(x+12)-(x)(x)\\ \\A=(x+12)^{2} -x^{2}\\ \\A=x^{2}+24x+144-x^{2}\\ \\A=(24x+144)\ ft^{2}[/tex]

Your answer should be C because the slope line is negative so you're answer should be negative

We are given y = ax + b.

Here, [a] represents the slope.

Which graph shows NEGATIVE SLOPE?

The graph starting at the upper left going to the bottom right is CHOICE C.

CHOICE C is the answer because the slope [a] must be negative.

Answer:

5 is the width and 7 is the length

Answer:

x=5 in (Width)

x+2=5+2=7 in (Length)

Step-by-step explanation:

You are given the equation 2x+2(x+2)=24 to solve for x where x is the width.

First step, use distributive property 2x+2x+4=24

Second step, subtract 4 on both sides  and combine the like terms on the left hand side: 4x=20

Divide both sides by 4:  x=20/4

So x=5 in

And since length is 2 more than the width so the length is 2+5=7 in

Answer:

  missing value: 7

Step-by-step explanation:

Put 2 where x is in the function and do the arithmetic.

  y = 5·2 -3 = 10 -3 = 7

The value corresponding to x=2 is y=7.

To complete the table of values for the function y = 5x - 3, you substitute the given x-value into the equation. The missing y-value for x=2 is 7.

The function provided is y = 5x - 3. This is a linear function. To get the y values, you need to substitute the x values from the table into this equation. For the last row where x = 2, substitute 2 into the equation:

y = 5(2) - 3 = 10 - 3 = 7

So, the y-value corresponding to x=2 is 7.

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Answer:

she overlooked 30

Step-by-step explanation:

The number 30 appears on both her lists. Maria apparently overlooked that value.

Answer:

n is the fixed number of trials. x is the specified number of sucesses. N - X is the number of failures. P is the probablity of success on any given trail. 1 - P is the probabilty of failure on any given trial.

These probabilities hold for any value of X between 0 (lowest number of possible successes in n trials) and n (highest number of possible successes).

Hope this helps

Step-by-step explanation:

Answer: the first option

Step-by-step explanation:

A reflection means that the object is flipped.

A reflection is a transformation that flips a shape over a line, creating a mirror image. You identify a reflection by looking for a shape which appears to have been flipped across a line.

In mathematics, a reflection is a type of transformation that flips a shape over a line, creating a mirror image. To identify a reflection, you should look for a shape that appears to be flipped over a line. This line is called the line of reflection. For example, if you have a triangle ABC and its image A'B'C' such that A'B'C' is a mirror image of ABC, this is a reflection. The point A is reflected over the line to point A', B to B', and C to C'. The distances from the line of reflection to A, B, and C are equal to the distances from the line to A', B', and C' respectively.

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