Please help me answer this Maths question.☺

***Must show step by step guide to how you got your answers***☺

The number 418,712,909 is written in word form as 'four hundred eighteen million, seven hundred twelve thousand, nine hundred nine'. This educates students on place value and the decimal system, crucial elements in middle school mathematics.

The number 418,712,909 in word form is written as four hundred eighteen million, seven hundred twelve thousand, nine hundred nine. Learning to convert numbers into words is an essential skill in mathematics, teaching students not only the names of large numbers but also helping to develop a deeper understanding of place value and the decimal system.

It's a fundamental part of mathematics education, especially in middle school, where students start engaging with more complex numerical concepts.

An algebraic expression with a quotient of [tex]x^{5}[/tex] is [tex]\frac{x^{7} }{x^{2} }[/tex] and An algebraic expression with a product of [tex]x^{5}[/tex] is [tex]x^{3}\times x^{2}[/tex].

We need to write two algebraic expressions, one with a quotient of [tex]x^{5}[/tex] and one with a product of [tex]x^{5}[/tex].

An algebraic expression (or) a variable expression is a combination of terms by the operations such as addition, subtraction, multiplication, division, etc.

Now, an algebraic expression with a quotient of [tex]x^{5}[/tex] is

[tex]\frac{x^{7} }{x^{2} } =x^{7-2}=x^{5}[/tex]  (∵[tex]\frac{a^{m} }{a^{n} } =a^{m-n}[/tex])

An algebraic expression with a product of [tex]x^{5}[/tex] is

[tex]x^{3}\times x^{2} = x^{3+2}=x^{5}[/tex]

Therefore, an algebraic expression with a quotient of [tex]x^{5}[/tex] is [tex]\frac{x^{7} }{x^{2} }[/tex] and An algebraic expression with a product of [tex]x^{5}[/tex] is [tex]x^{3}\times x^{2}[/tex].

To learn more about an algebraic expression visit:

https://brainly.com/question/19245500.

#SPJ2

Scale: 1 inch = 13 feet. 1.5 inches on the drawing. Actual length: 1.5 * 13 = 19.5 feet. Elephant length.

To find the actual length of the elephant, you need to use the scale provided by Maria's drawing. The scale states that 1 inch on the drawing represents 13 feet in reality. Since the elephant in the drawing is 1.5 inches long, we can calculate the actual length using the scale.

1. First, determine how many feet one inch on the drawing represents:

[tex]\( 1 \text{ inch on drawing} = 13 \text{ feet in reality} \)[/tex]

2. Multiply the number of inches in the drawing by the conversion factor to find the actual length:

 [tex]\( 1.5 \text{ inches on drawing} \times 13 \text{ feet/inch} = 19.5 \text{ feet in reality} \)[/tex]

So, the actual length of the elephant is 19.5 feet.

Answer:

Step-by-step explanation:

its the first one.

By solving a system of equations, we will see that Maggie has 18 dimes and 9 quarters.

First, we define the variables that we will use:

There are a total of 27 coins, so:

Q + D = 27.

The total value is 4.05, so:

Q*0.25 + D*0.10 = 4.05

Then our system of equations:

Q + D = 27

Q*0.25 + D*0.10 = 4.05

To solve this we need to isolate one of the variables in one of the equations, I will isolate Q in the first one.

Q = 27 - D

Now we can replace this on the other equation and solve it for D:

(27 - D)*0.25 + D*0.10 = 4.05

6.75 - D*0.25 + D*0.10 = 4.05

6.75 - D*0.15 = 4.05

6.75 - 4.05 = D*0.15

2.70 = D*0.15

2.70/0.15 = D = 18

So she has 18 dimes, and then the other 9 conis must be quarters.

If you want to learn more about systems of equations, you can read:

https://brainly.com/question/13729904

divide 20 by 10%

10% = 0.10

20 / 0.10 = 200

 20 is 10% of 200

Final answer:

Professor Bartlett can arrange the students in 1,440 different ways in the first row, considering Louise must sit next to her tutor on the right.

Explanation:

Professor Bartlett teaches a class of 12 students and needs to seat them in the front row which consists of 7 chairs. Specifically, Louise, who is visually challenged, must sit next to her tutor on the right side. To determine the number of different ways the students can be seated in the first row, we first consider the places of Louise and her tutor. Since Louise's tutor must be seated to her right, they can be viewed as a single entity with two internal arrangements: Louise on the left and the tutor on the right. Therefore, there are now effectively 6 entities to arrange (Louise and her tutor considered as one, plus the 5 other students) in 6 chairs in the front row.

The number of ways to arrange 6 entities in 6 spots is calculated by 6 factorial (6!), which equals 720. However, since Louise and her tutor can switch places within their designated spot, we must multiply this number by the 2 internal arrangements possible, resulting in 720 * 2 = 1,440 different seating arrangements for the first row.

Final answer:

There are 30 students in total, 12 of whom play an instrument, and 25 of whom play a sport.

Explanation:

The question asks about the number of students who play an instrument and the number who play a sport. There are 30 students in total.

To find the number of students who play an instrument, we multiply 30 by ⅓ (2/5), since 2/5 of the students play an instrument. To find the number of students who play a sport, we multiply 30 by ⅕ (5/6), since 5/6 of the students play a sport.

For the instrument calculation: 30 × 2/5 = 12, so 12 students play an instrument.

For the sport calculation: 30 × 5/6 = 25, so 25 students play a sport.

1/6  is the gravitational force (in Newtons) that the Earth exerts on him when he's standing on the moon.

The gravitational force is a force that attracts any two gadgets with mass. We name the gravitational force attractive as it always tries to pull masses together, it in no way pushes them apart. In fact, every item, consisting of you, is pulling on every different item in the entire universe.

Learn more about gravitational force here: https://brainly.com/question/13010127

#SPJ2

Answer: Option 'A' is correct.

Step-by-step explanation:

Since we have given that

Distributive property which is expressed as

[tex]a\times (b+c)\\\\=a\times b+a\times c[/tex]

Similarly, in option 'A', we have

(0.5⋅0.5)+(0.5⋅0.3)+(0.5⋅0.2)=0.5⋅(0.5+0.3+0.2) ​

Here, a = 0.5,

b= 0.5

c = 0.3

d = 0.2

So, it can be expressed as

[tex]a\times (b+c+d)=a\times b+a\times c+a\times d[/tex]

Hence, Option 'A' is correct.