Answer:
Part a) Is a growth function
Part b) The function's percent rate of change is 160%
Step-by-step explanation:
we have
[tex]f(x)=0.3(2.6^x)[/tex]
This is a exponential function of the form
[tex]f(x)=a(b^x)[/tex]
where
a is the initial value or y-intercept
b is the base of the exponential function
If b> 1---> we have a growth function
if b< 1---> is a decay function
r is the percent rate of change
b=(1+r)
In this problem we have
[tex]a=0.3[/tex]
[tex]b=2.6[/tex]
The value of b >1
so
Is a growth function
Find the value of r
[tex]r=b-1=2.6-1=1.6[/tex]
convert to percentage
[tex]r=1.6*100=160\%[/tex]
In one country, residents were asked to name their primary language. The ratio of residents who said French to those who said Punjabi was 110 to 7. If there 7,260,000 residents who said French, about how many thousands of residents said Punjabi?
Answer:
462000
Step-by-step explanation:
here,let the punjabi be x
110/7=7260000/x
110x=7260000*7
x=462000
Answer: 462
Step-by-step explanation: I had the question and it said it was 462
On the track team, 35of the members are boys. Of these boys, 47 are sixth-graders. Of the sixth-grade boys on the team, 13 are runners. What fraction of the track team are sixth-grade boy runners?
Answer:
The number of runners is [tex]\dfrac{4 }{35}[/tex] of Total number of the member in team .
Step-by-step explanation:
Given as :
The Total number of the member in team = x
The number of boys in team = [tex]\dfrac{3}{5}[/tex] of x
I.e number of boys in team = [tex]\dfrac{3 x}{5}[/tex]
Again
The number of sixth-grade boys = [tex]\dfrac{4}{7}[/tex] of total boys in team
I.e The number of sixth-grade boys = [tex]\dfrac{4}{7}[/tex] × [tex]\dfrac{3 x}{5}[/tex]
Or, The number of sixth-grade boys = [tex]\dfrac{12 x}{35}[/tex]
Again
The number of runners = [tex]\dfrac{1}{3}[/tex] of number of sixth-grade boys
i.e The number of runners = [tex]\dfrac{1}{3}[/tex] × [tex]\dfrac{12 x}{35}[/tex]
Or, The number of runners = [tex]\dfrac{4 x}{35}[/tex]
So, The number of runners = [tex]\dfrac{4 }{35}[/tex] of Total number of the member in team
Hence,The number of runners is [tex]\dfrac{4 }{35}[/tex] of Total number of the member in team . Answer
If you assume that there are exactly 365 days in a year, how many seconds are there in one year? Give your answer to the nearest 1000 seconds.
Answer:
31,536,000
Step-by-step explanation:
There are 3600 seconds in an hour and 24 hours in a day, so ...
(3600 s/h)(24 h/da) = 86400 s/da
Then in 365 days, there are ...
(365 da)(86400 s/da) = 31,536,000 s
_____
No rounding is needed.
There are 31,536,000 seconds in a year. This is calculated by multiplying 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 365 days in a year.
Explanation:To calculate the number of seconds in a year, start with the known values of time:
There are 60 seconds in 1 minute,60 minutes in 1 hour,24 hours in one day,and 365 days in one year (for this question, we're ignoring leap years).
We multiply all these values together to get the number of seconds in a year.
60 seconds/minute * 60 minutes/hour * 24 hours/day * 365 days/year = 31,536,000 seconds/year
To give the answer to the nearest 1000 seconds, we would round it to 31,536,000.
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Type the correct answer in the box. Use a comma to separate the x- and y-coordinates of each point. The coordinates of the point on the unit circle that corresponds to an angle of 0º are ( ). The coordinates of the point on the unit circle that corresponds to an angle of 90º are ( ).
Answer:
On a unit circle, the point that corresponds to an angle of [tex]0^{\circ}[/tex] is at position [tex](1, \, 0)[/tex].
The point that corresponds to an angle of [tex]90^{\circ}[/tex] is at position [tex](0, \, 1)[/tex].
Step-by-step explanation:
On a cartesian plane, a unit circle is
a circle of radius [tex]1[/tex],centered at the origin [tex](0, \, 0)[/tex].The circle crosses the x- and y-axis at four points:
[tex](1, \, 0)[/tex],[tex](0, \, 1)[/tex], [tex](-1,\, 0)[/tex], and[tex](0,\, -1)[/tex].Join a point on the circle with the origin using a segment. The "angle" here likely refers to the counter-clockwise angle between the positive x-axis and that segment.
When the angle is equal to [tex]0^\circ[/tex], the segment overlaps with the positive x-axis. The point is on both the circle and the positive x-axis. Its coordinates would be [tex](1, \, 0)[/tex].
To locate the point with a [tex]90^{\circ}[/tex] angle, rotate the [tex]0^\circ[/tex] segment counter-clockwise by [tex]90^{\circ}[/tex]. The segment would land on the positive y-axis. In other words, the [tex]90^{\circ}[/tex]-point would be at the intersection of the positive y-axis and the circle. Its coordinates would be [tex](0, \, 1)[/tex].
Answer:
Angle of 0º: (1,0)
Angle of 90º: (0,1)
Step-by-step explanation:
A unit circle has a radius of 1.
Therefore, the points on the x- and y-axis are as follows:
Angle of 0º: (1,0)
Angle of 90º: (0,1)
Angle of 180º: (-1,0)
Angle of 270º: (0,-1)
Angle of 360º [have now circled back to an angle of 0º]: (1,0)
Find the solution of the differential equation dy/dt = ky, k a constant, that satisfies the given conditions. y(0) = 50, y(5) = 100
Answer: The required solution is [tex]y=50e^{0.1386t}.[/tex]
Step-by-step explanation:
We are given to solve the following differential equation :
[tex]\dfrac{dy}{dt}=ky~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
where k is a constant and the equation satisfies the conditions y(0) = 50, y(5) = 100.
From equation (i), we have
[tex]\dfrac{dy}{y}=kdt.[/tex]
Integrating both sides, we get
[tex]\int\dfrac{dy}{y}=\int kdt\\\\\Rightarrow \log y=kt+c~~~~~~[\textup{c is a constant of integration}]\\\\\Rightarrow y=e^{kt+c}\\\\\Rightarrow y=ae^{kt}~~~~[\textup{where }a=e^c\textup{ is another constant}][/tex]
Also, the conditions are
[tex]y(0)=50\\\\\Rightarrow ae^0=50\\\\\Rightarrow a=50[/tex]
and
[tex]y(5)=100\\\\\Rightarrow 50e^{5k}=100\\\\\Rightarrow e^{5k}=2\\\\\Rightarrow 5k=\log_e2\\\\\Rightarrow 5k=0.6931\\\\\Rightarrow k=0.1386.[/tex]
Thus, the required solution is [tex]y=50e^{0.1386t}.[/tex]
Answer:
[tex]\frac{1}{5}\ln(2)=k[/tex]
Solution without isolating [tex]y[/tex]:
[tex]\ln|y|=\frac{1}{5}\ln(2)x+\ln(50)[/tex]
Solution with isolating [tex]y[/tex]:
[tex]y=50 \cdot 2^{\frac{1}{5}x}[/tex]
Step-by-step explanation:
[tex]\frac{dy}{dx}=ky[/tex]
We will separate the variables so we can integrate both sides.
Multiply [tex]dx[/tex] on both sides:
[tex]dy=ky dx[/tex]
Divide both sides by [tex]y[/tex]:
[tex]\frac{dy}{y}=k dx[/tex]
Now we may integrate both sides:
[tex]\ln|y|=kx+C[/tex]
The first condition says [tex]y(0)=50[/tex].
Using this into our equation gives us:
[tex]\ln|50|=k(0)+C[/tex]
[tex]\ln|50|=C[/tex]
So now our equation is:
[tex]\ln|y|=kx+\ln(50)[/tex]
The second condition says [tex]y(5)=100[/tex].
Using this into our equation gives us:
[tex]\ln|100|=k(5)+\ln(50)[/tex]
[tex]\ln(100)=k(5)+\ln(50)[/tex]
Let's find [tex]k[/tex].
Subtract [tex]\ln(50)[/tex] on both sides:
[tex]\ln(100)-\ln(50)=k(5)[/tex]
I'm going to rewrite the left hand side using quotient rule for logarithms:
[tex]\ln(\frac{100}{50})=k(5)[/tex]
Reducing fraction:
[tex]\ln(2)=k(5)[/tex]
Divide both sides by 5:
[tex]\frac{\ln(2)}{5}=k[/tex]
[tex]\frac{1}{5}\ln(2)=k[/tex]
So the solution to the differential equation satisfying the give conditions is:
[tex]\ln|y|=\frac{1}{5}\ln(2)x+\ln(50)[/tex]
Most likely they will prefer the equation where [tex]y[/tex] is isolated.
Let's write our equation in equivalent logarithm form:
[tex]y=e^{\frac{1}{5}\ln(2)x+\ln(50)}[/tex]
We could rewrite this a bit more.
By power rule for logarithms:
[tex]y=e^{\ln(2^{\frac{1}{5}x})+\ln(50)}[/tex]
By product rule for logarithms:
[tex]y=e^{\ln(2^{\frac{1}{5}x} \cdot 50)}[/tex]
Since the natual logarithm and given exponential function are inverses:
[tex]y=2^{\frac{1}{5}x} \cdot 50[/tex]
By commutative property of multiplication:
[tex]y=50 \cdot 2^{\frac{1}{5}x}[/tex]
If quadrilateral WXYZ is inscribed in a circle with center O, the measure of angle W = 45 and the measure of angle X = 110, then the measure of angle Z = _____.
Check the picture below.
Estimate the quotient 430 divided by 9
Answer:
47.77778 but really it's just 47
Jackson sells two types of toolboxes. He plans on selling them during a farming fair this weekend. He estimates he will sell 20 of the smaller boxes and 12 of the larger boxes. If he'd like the profit to be $1300, which of the following best displays the equation that represents this information?
A. y = −5/3x + 325/3 ~~
B. 20x + 12y = 1300
C. y + 12 = 20(x–1300)
D. 12y = 20x – 1300
Answer:
B
Step-by-step explanation:
In this case, we use variables to represent the the cost of the big and the smaller boxes. Let x be the selling price of the big boxes while y be the selling price of the bigger boxes.
The total selling price of the smaller boxes is 20x. The total selling price of the bigger ones is 12y.
Now we know he is making a profit of $1,300
Hence in equation form, all the information above can be represented as:
20x + 12y = 1,300
The base of a 40-foot ladder is 8 feet from the wall. How high is the ladder on the wall (round to the nearest foot)?
Answer:
39 feet.
Step-by-step explanation:
E use the Pythagoras theorem:
40^2 = 8^2 + h^2 as h is the height we require.
h^2 = 1600 - 64
h^2 = 1536
h = 39.19 feet
Sajia has 30 books in her library she sold 9 books at a thrift store on Saturday write and solve an inquality to determine how many more books she can sell if she comes back on Sunday
Answer:
see the explanation
Step-by-step explanation:
Let
x ---->the number of books she can sell if she comes back on Sunday
y ----> the number of books sold on Saturday
we know that
The number of books sold on Saturday plus the number of books she can sell if she comes back on Sunday must be less than or equal to the initial number of books in the library (30 books)
so
The inequality that represent this situation is
[tex]x+y\leq 30[/tex]
we have
[tex]y=9\ books[/tex]
substitute
[tex]x+9\leq 30[/tex]
solve for x
subtract 9 both sides
[tex]x\leq 30-9[/tex]
[tex]x\leq 21\ books[/tex]
therefore
The maximum number of books she can sell on Sunday is 21
Ernie calculated the slope between two pairs of points. He found that the slope between ( ( -1, 4) 1 , 4 ) and (0, 0) ( 0 , 0 ) is -4 4 . He also found that the slope between (2, 7) ( 2 , 7 ) and (3, 3) ( 3 , 3 ) is -4 4 . Ernie concluded that all of these points are on the same line. Use the drop-down menus to complete the statements about Ernie's conclusion.
Answer:
His conclusion was incorrect.
Step-by-step explanation:
Since, slope of a line passes through [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] is,
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Thus, the slope between (-1, 4) and (0, 0),
[tex]m_1=\frac{0-4}{0+1}=-4[/tex]
Also, the slope between (2, 7) and (3, 3),
[tex]m_2=\frac{3-7}{3-2}=\frac{-4}{1}=-4[/tex]
Now,
There are two cases possible,
Case 1 : line passes through (-1, 4) and (0, 0) is parallel to line passes through (2, 7) and (3, 3)
Case 2 : (-1, 4), (0, 0), (2, 7) and (3, 3) are on the same line
Hence, we can not say that they are on same line only after getting same slope.
i.e. his conclusion was incorrect.
Answer:
Okay so this picture is basically the answer for anyone who needs it...
Step-by-step explanation:
On august 1st, a plant was 79 centimeters tall. in june of that year it grew 12 centimeters, then 9 more centimeters in july. how many centimeters tall was it on june 1st?
a.67
b.70
c.100
d.5
Answer: d. 58
The height of the plant in June 1st is 58 centimeters.
Step-by-step explanation:
Given : On August 1st, a plant was 79 centimeters tall.
In June of that year it grew 12 centimeters, then 9 more centimeters in July.
Order of Month = June → July → August
Then , the height of the plant on June 1st would be
Height in August 1st - Height grew in June - height grew in July
= 79-12-9 centimeters
= 67-9 centimeters
= 58 centimeters
Therefore , the height of the plant in June 1st = 58 centimeters
Hence, the correct answer is d. 58
Help plz... I forgot how to find the angles...can someone tell me how to do it por favor...y
gracias
Answer: a=70°
b=45°
c=65°
d=45°
e=70°
f=110°
Step-by-step explanation:
a=70°
b=180°-135°=45°
c=180-(70+45)=180-115=65°
c=65°
e=70°
d=180-(c+e)=180-(65+70)=180-135=45°
d=45°
f=180-e=180-70=110°
Simplify the expression.
1-cot x / tan x-1
A) cot x
B) tan x
C) -cot x
D) csc x
Answer:
The answer to your question is letter A) cot x
Step-by-step explanation:
[tex]\frac{1 - cot x}{tan x - 1}[/tex]
Remember that cot x = [tex]\frac{1}{tan x}[/tex]
Then
[tex]\frac{1 - \frac{1}{tan x} }{tanx -1}[/tex]
Simplify
[tex]\frac{\frac{tan x - 1}{tan x} }{tan x - 1}[/tex]
[tex]\frac{tan x - 1}{tan x (tan x - 1)}[/tex]
[tex]\frac{1}{tan x}[/tex]
Result
[tex]\frac{1}{tan x} = cot x[/tex]
Kylo bought a pizza for $12.75 and four medium drinks at Pauli's Pizza. Define a variable and write an expression to represent the total amount of money he spent. Then find the total cost if one drink cost $3.
Answer:
Step-by-step explanation:
Let d be the cost of a drink. The expression for the cost of the pizza and 4 drinks is
12.75 + 4d
If each drink costs $3, then
12.75 + 4(3) simpifies to
12.75 + 12 which equals 24.75
The final agreed-to sample size is a trade-off between acceptable error and research cost.
Answer:
True
Step-by-step explanation:
Sample size selection is the act of choosing the number of observations or replicates to include in a statistical sample. The sample size is important in any empirical statistical study in which the goal is to make inferences about a population from a sample. The actual sample size used in a study is determined based on the time money and technical cost of data collection, and the need to have sufficient statistical accuracy.
Finding a balance between acceptable error and research cost gives rise to concepts like Confidence Interval and Margin of Error.
A department store purchases a dress for $80. To sell the dress to customers, the price is marked up by 19%. You hand the clerk $110. How much change will you get back?a. $30.00b. $15.20c. $95.20d. $14.80
Answer:
Amount returned will be $14.80
So option (D) will be correct answer
Step-by-step explanation:
We have given the purchase price of store = $80
To sell the dress price is marked up by 19 %
So marked up price [tex]=80+\frac{80\times 19}{100}=$95.2[/tex]
He give the $110 to clerk
We have to find the amount which is returned by clerk
So the amount will be equal to $110-$95.2 = $14.8
So option (d) will be correct answer
Sam watched television the past five nights for 42 minutes, 23 minutes, 56 minutes, 19 minutes, and 67 minutes. What was the median amount of time Sam watched TV the past five nights?
Answer:
42 minutes is the median amount of time
Step-by-step explanation:
The Median is the middle value of data set.
If there is "odd" number of numbers, and there are n numbers, the median is:
(n/2) + 1 th number
If there is "even" number of numbers, and there are n numbers, the median is:
Average of n/2th and (n/2) + 1 th number
Here, we have 5 numbers, so the median would be:
(5/2) + 1 th number
That is
3rd number
But, we need to arrange the numbers from least to greatest. Lets write it:
19, 23, 42, 56, 67
The third number is 42, this is the median
A simple random sample of size n from a finite population of size N is a sample selected such that each possible sample of size n
a. has the same probability of being selected
b. has a probability of 1/n of being selected
c. has a probability of n/(N-1) of being selected
d. has a probability of 1/N of being selected g
Answer:
a) has the same probability of being selected
Step-by-step explanation:
A simple random sampling means that each possible sample of size n has the same probability of being selected.
Then your answer is:
a) has the same probability of being selected
The definition of a simple random sampling method implies that each possible sample of a given size has an equally likely chance of being selected. Hence, option a. 'has the same chance of being selected' is the correct answer.
Explanation:The simple random sampling method is a statistical method used to select individual samples from a large population where each sample is given an equal chance of being selected. In a simple random sampling of size n from a finite population of size N, each possible sample of size n would have the same probability of being selected. Therefore, the correct answer is a. has the same probability of being selected.
It is crucial to note that the probability of a sample being selected is not dependent on its size (n) nor the total size of the population (N), as options b, c, and d suggest. Instead, it is determined solely by the sampling method, i.e., simple random sampling.
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Rewrite with only sin x and cos x.
cos 3x
A. cos x - 4 cos x sin2x
B. -sin3x + 2 sin x cos x
C. -sin2x + 2 sin x cos x
D. 2 sin2x cos x - 2 sin x cos x
Option A
[tex]\cos 3 x=\cos x-4 \cos x \sin ^{2} x[/tex]
Solution:
Given that we have to rewrite with only sin x and cos x
Given is cos 3x
[tex]cos 3x = cos(x + 2x)[/tex]
We know that,
[tex]\cos (a+b)=\cos a \cos b-\sin a \sin b[/tex]
Therefore,
[tex]\cos (x+2 x)=\cos x \cos 2 x-\sin x \sin 2 x[/tex] ---- eqn 1
We know that,
[tex]\sin 2 x=2 \sin x \cos x[/tex]
[tex]\cos 2 x=\cos ^{2} x-\sin ^{2} x[/tex]
Substituting these values in eqn 1
[tex]\cos (x+2 x)=\cos x\left(\cos ^{2} x-\sin ^{2} x\right)-\sin x(2 \sin x \cos x)[/tex] -------- eqn 2
We know that,
[tex]\cos ^{2} x-\sin ^{2} x=1-2 \sin ^{2} x[/tex]
Applying this in above eqn 2, we get
[tex]\cos (x+2 x)=\cos x\left(1-2 \sin ^{2} x\right)-\sin x(2 \sin x \cos x)[/tex]
[tex]\begin{aligned}&\cos (x+2 x)=\cos x-2 \sin ^{2} x \cos x-2 \sin ^{2} x \cos x\\\\&\cos (x+2 x)=\cos x-4 \sin ^{2} x \cos x\end{aligned}[/tex]
[tex]\cos (x+2 x)=\cos x-4 \cos x \sin ^{2} x[/tex]
Therefore,
[tex]\cos 3 x=\cos x-4 \cos x \sin ^{2} x[/tex]
Option A is correct
There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter
Answer:
The question is incomplete, this is the complete question.;
There are five nickels, five dimes and five quarters in your pocket. You randomly pick three coins and place them on the counter the first coin is a nickel, the second is a dime and the third is a quarter.find the probability of this occurring.
The answer to the question is;
the probability of this occurring is 1/27
Step-by-step explanation:
Let n(N) =5 ( the number of nickels)
n(D) =5 ( the number of dimes) and
n(Q) = 5 ( the number of quarters)
P(N)= 5/15=1/3 (prob of picking a nickel)
P(D) =5/15=1/3 (prob of picking a dime)
P(Q) = 5/15= 1/3 (prob of picking a quatre)
The probability of picking the three= P(N)×P(D)×P(Q)
= 1/3×1/3×1/3
= 1/27
If the mix ratio for certain chemical is 1:6 when it is mixed with water (chemical:water), how much water would be mixed with 1/2 gallon of the chemical?
Answer:3 gallons of water would be mixed with 1/2 gallon of the chemical
Step-by-step explanation:
If the mix ratio for certain chemical is 1:6 when it is mixed with water. This means that for every 1 gallon of the chemical, 6 gallons of water is required.
Therefore, the number of gallons of water that would be mixed with 1/2 gallon of the chemical becomes
1/2 × 6 = 3 gallons of water.
Answer: 3 gallons of water would be mixed with 1/2 gallon of the chemical
Step-by-step explanation:
If the mix ratio for certain chemical is 1:6 when it is mixed with water. This means that for every 1 gallon of the chemical, 6 gallons of water is required.
Therefore, the number of gallons of water that would be mixed with 1/2 gallon of the chemical becomes
1/2 × 6 = 3 gallons of water.
If working together, brothers Tom and Jack can paint a wall in 4 hours, how much time would it take Jack to paint the wall alone? (1) Jack is painting twice as fast as Tom. (2) If Tom painted twice as fast as he actually does, the brothers would finish the work in 3 hours.
Identify an attribute of the "a" element that indicates the media type of z linked document
Answer:
Step-by-step explanation:
The id attribute requires a unique string to identify the element.
Among the options provided, the attribute of the "an" element that indicates the media type of a linked document is:
C) type="mime-type"
In HTML, when creating links to external resources or documents, the "an" element is typically represented by the "a" anchor tag. This tag often uses the 'type' attribute to specify the media type of the linked document.
For instance, if you have an anchor tag (<a>) linking to a document like a stylesheet, image, or script, you can specify the media type using the 'type' attribute. The 'type' attribute helps the browser interpret the linked document's format or MIME (Multipurpose Internet Mail Extensions) type. An example might look like:
<a href="url_to_linked_document" type="text/css">Link Text</a>
In this example, 'type="text/css"' indicates that the linked document is a CSS file (text/css MIME type), which helps browsers understand how to handle the resource being linked. Therefore, option C) type="mime-type" is the attribute used to indicate the media type of the linked document.
Complete Question:
Identify an attribute of the "an" element that indicates the media type of z linked document.
A) rel-"type"
B) hrefland="lang"
C) type="mime-type"
D) href="url"
What are the conditions a sample needs to meet before you can assume it's binomial and that it approximates a normal distribution?
Answer:
1) [tex]np\geq 5[/tex]
2) [tex]nq = n(1-p)\geq 5[/tex]
Other conditions that are important are:
3) n is large
4) p is close to 1/2 or 0.5
Step-by-step explanation:
1) Previous concepts
The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".
2) Solution to the problem
Let X the random variable of interest, on this case we now that:
[tex]X \sim Binom(n, p)[/tex]
The probability mass function for the Binomial distribution is given as:
[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]
Where (nCx) means combinatory and it's given by this formula:
[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]
In order to apply the normal apprximation we need to satisfy these two conditions:
1) [tex]np\geq 5[/tex]
2) [tex]nq = n(1-p)\geq 5[/tex]
Other conditions that are important are:
3) n is large
4) p is close to 1/2 or 0.5
Mary is consuming at a point on her budget line. Her income is $40 a week, and she purchases hamburgers and grilled cheese sandwiches. If both goods cost $2 each, and she purchases five hamburgers, how many grilled cheese sandwiches does Mary buy?
Answer:
Mary buy $30 / $ 2 = 15 grilled cheese sandwiches
Step-by-step explanation:
five hamburgers cost 42 x 5 = $10
money left for grilled cheese sandwiches = $40 - $ 10 = $ 30
each grilled cheese sandwiches cost $2
Mary buy $30 / $ 2 = 15 grilled cheese sandwiches
Which of the following triangles is closest to being right? Explain your reasoning.
Answer: Second triangle.
Step-by-step explanation:
For this exercise you need to use the Pythagorean Theorem. Based on it, you know that in a right triangle:
[tex]a^2=b^2+c^2[/tex]
Where "a" is the hypotenuse of the right triangle and "b" and "c" are the legs.
In this case you can identify that the legs of the first triangle and the legs of the second triangle are equal. These are:
[tex]b=7\\c=3.3[/tex]
Knowing their values, you can substitute them into the Pythagorean Theorem and solve for "a":
[tex]a^2=(7)^2+(3.3)^2\\\\a=\sqrt{(7)^2+(3.3)^2}\\\\a=7.738[/tex]
Therefore, you can conclude that the triangle that is closest to being a right triangle is the second one.
Neural networks, fuzzy systems, and evolutionary computation are all forms of __________, where systems develop intelligence through an iterative learning process.a. relational intelligenceb. conventional intelligencec. fuzzy logicd. computational intelligence
Answer:
d. computational intelligence
Step-by-step explanation:
Neural networks, fuzzy systems, and evolutionary computation are all forms of computational intelligence, where systems develop intelligence through an iterative learning process.
Computational intelligence (CI) is a machine intelligence which usually refers to the ability of a computer to learn or perform a specific task from data or experimental observation. This implies the systems have the ability to learn and generalize from examples and develop intelligence through an iterative process. Computer intelligence is also known as soft computing. The major Computational intelligence are Fuzzy logic, Neural networks and Evolutionary Computing. Presently, Computational Intelligence is an evolving field. New additions are evolving in addition to the three major CI. These new CI include soft computing like artificial endocrine networks, artificial life, ambient intelligence, cultural learning and social reasoning.
Neural networks, fuzzy systems, and evolutionary computation contribute to the field of computational intelligence, demonstrating adaptive learning capabilities and continuous improvement. Option d) is the correct answer.
Neural networks, fuzzy systems, and evolutionary computation are all forms of computational intelligence, where systems develop intelligence through an iterative learning process. Concepts such as evolution and adaptation, which originate in evolutionary biology, stretch to the domain of complex systems involving the development of adaptive, non-biological processes that have dynamic learning and creative abilities.
These systems are part of artificial intelligence, where computer systems learn from data to improve over time. These forms of artificial intelligence have been rapidly developing since the 1980s and are often associated with machine learning, suggesting a broad category where systems can adapt, process information, and optimize problems.
If the units digit of the three-digit positive integer k is nonzero, what is the tens digit of k ?
Answer:
any digit 0 to 9
Step-by-step explanation:
Nothing about your description of the number suggests that the 10s digit depends on the units digit. The tens digit can be any digit 0 to 9.
Over the course of four weeks Mia spent 35 1 2 hours training for a race. Michael spent 1 1 2 times that amount training for the same race. How many hours did Michael spend training? A) 49 1 2 hours B) 53 1 4 hours C) 71 hours D) 73 1 4 hours
Answer:Michael spent 53 1/4 hours
training.
Step-by-step explanation:
Over the course of four weeks Mia spent 35 1 2 hours training for a race. This can be written in decimal point as 35.5 hours.
Michael spent 1 1 2 times that amount training for the same race. Converting 1 1 2 to decimal, it becomes 1.5 hours.
This means that the number of hours that Michael spent training will be 35.5 × 1.5 = 53.25 hour.
Converting 53.25 hours to mixed fraction, it becomes
53 1/4 hours
Answer:
The answer is B
Step-by-step explanation: