please help urgent will mark brainliest

The perimeter of Jonah's square backyard is 56 meters.
What is the area of Jonah's backyard?

Answers

Answer 1

Perimeter of the square backyard=56m

Perimeter of a square=4*side

Side=

56=4*side

56/4=side

side=14 cm

Area of a square=side*side

=14*14

=196cm^2

So,the area of the square backyard is 196m^2.

Answer 2

Answer:

A=196

Step-by-step explanation:

Please mark brainliest and have a great day!


Related Questions

Need help with math question

Answers

Answer:

center (1,-3) and radius is 5

Step-by-step explanation:

We have to use completing the square here:

x^2-2x    + y^2+6y         =15  (reorder some things and added 15 on both sides)

x^2-2x+(-2/2)^2  + y^2+6y+(6/2)^2   =15+(-2/2)^2+(6/2)^2 (whatever you add on one side you also do to the other side)

x^2-2x+(-1)^2   + y^2+6y+(3)^2=15+1+9

(x-1)^2         +    (y+3)^2          =25

Center is (1,-3) and radius is 5

ANSWER

The center is (1,-3) and the radius is r=5 units.

EXPLANATION

The given equation is:

[tex] {x}^{2} + {y}^{2} - 2x + 6y - 15 = 0[/tex]

Let rearrange to get:

[tex]{x}^{2} - 2x + {y}^{2} + 6y=15[/tex]

We complete the square to get;

[tex]{x}^{2} - 2x + ( { - 1)}^{2} + {y}^{2} + 6y + {3}^{2} = 15+ ( { - 1)}^{2} + {3}^{2}[/tex]

[tex] ( {x - 1)}^{2} +( {y + 3)}^{2} = 15 + 1+ 9[/tex]

[tex] ( {x - 1)}^{2} +( {y + 3)}^{2} =25[/tex]

[tex]( {x - 1)}^{2} +( {y + 3)}^{2} = {5}^{2} [/tex]

Comparing to

[tex]( {x - h)}^{2} +( {y - h)}^{2} = {r}^{2} [/tex]

The center is (1,-3) and the radius is r=5 units.

What is the opposite of squaring a number

Answers

The opposite of squaring a number is taking the square root. They are inverse operations.

The opposite of squaring a number is taking the square root of the number. They are inverse operations.

What is a perfect square?

A perfect square is a number system that can be expressed as the

square of a given number from the same system.

Perfect squares are those integers whose square root is an integer.

Let x-a be the closest perfect square less than x,

Let x-a be the closest perfect square less than x, and let x+b be the closest perfect square more than x, then we get x-a < x < x+b (no perfect square in between x-a and x+b, except possibly x itself).

Then, we get:

[tex]\sqrt{x-a} < \sqrt{x} < \sqrt{x+b}[/tex]

Thus, these are the closest integers, less than and more than the value of[tex]\sqrt{x}[/tex]. (assuming x is a non-negative value).

The opposite of squaring a number is taking the square root of the number. They are inverse operations.

Learn more about square root here:

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Match each function formula with the corresponding transformation of the parent function y = (x - 1)2 1. y = - (x - 1)2 Reflected over the y-axis 2. y = (x - 1)2 + 1 Reflected over the x-axis 3. y = (x + 1)2 Translated right by 1 unit 4. y = (x - 2)2 Translated down by 3 units 5. y = (x - 1)2 - 3 Translated up by 1 unit 6. y = (x + 3)2 Translated left by 4 units

Answers

Answer:

y = -(x-1)² . . . . reflected over the x-axisy = (x-1)² +1 . . . . translated up by 1 unity = (x+1)² . . . . reflected over the y-axisy = (x-2)² . . . . translated right by 1 unity = (x-1)² -3 . . . . translated down by 3 unitsy = (x+3)² . . . . translated left by 4 units

Step-by-step explanation:

Since you have studied transformations, you are familiar with the effect of different modifications of the parent function:

f(x-a) . . . translates right by "a" unitsf(x) +a . . . translates up by "a" unitsa·f(x) . . . vertically scales by a factor of "a". When a < 0, reflects across the x-axisf(ax) . . . horizontally compresses by a factor of "a". When a < 0, reflects across the y-axis.

Note that in the given list of transformed functions, there is one that is (x+1)². This is equivalent to both f(x+2) and to f(-x). The latter is a little harder to see, until we realize that (-x-1)² = (x+1)². That is, this transformed function can be considered to be either a translation of (x-1)² left by 2 units, or a reflection over the y-axis.

Solve: e^2x+5= 4 (for those who want the answer to this!)

Answers

Answer:

Step-by-step explanation:

With the way it is written, there are no values of x that make the equation true.


Rebecca buys a table that was priced $650. There is a 8% sales tax in her state. Fortunately, it was 25% off! So she only
paid $:

Answers

Answer:

$526.50

amount×discount=?

650×.25= 162.5

total-discount=?

650-162.5= 487.5

new amount×sales tax=?

487.5×.08= 39

new amount+tax=total

487.5+39= 526.5

Total=$526.50

Please answer this question correctly for 30 points and brainliest!!

Answers

Answer:

  22 quarters

Step-by-step explanation:

Let q represent the number of quarters in the bank. Then 60-q is the number of nickels, and the total value of the coins is ...

  0.25q + 0.05(60 -q) = 7.40

  0.20q + 3.00 = 7.40 . . . . . . . . simplify

  0.20q = 4.40 . . . . . . . . . . . . . . subtract 3.00

  q = 4.40/0.20 = 22 . . . . . . . . . divide by the coefficient of q

There are 22 quarters in the piggy bank.

_____

Check

The other 60-22 = 38 coins are nickels, so the total value is ...

  0.25×22 + 0.05×38 = 5.50 + 1.90 = 7.40 . . . . . . the required amount

Step-by-step answer:

Here's a different way to solve the problem, mentally.

Mixture of 60 coins composed of nickels (5 cents) and quarters (25 cents).

Total value = 7.40.

IF all coins were quarters, value would be 60*0.25 = $15

That makes too many quarters.

To conform to the value of $7.40, we need to reduce the mix by $15-7.40 = 7.60.

Each exchange of quarters and nickels reduces the value by $0.25-0.05=0.20.

It takes 7.60 / 0.20 = 38 exchanges.

So there are 38 nickels and 22 quarters.

Anzelm wants to burn 540 calories while jogging. Jogging burns about 12 calories per minute. When Anzelm goes jogging, he usually plans to stop and rest for about 5 minutes. Complete the equation below to find the total number of minutes (including rest) that Anzelm should plan to be out jogging. Use m to represent the total minutes ___( __–__) = ___

Answers

Answer:

  12(m -5) = 540

Step-by-step explanation:

The left side of the equation is in the form of a product. A suitable product is ...

  (calories/minute) × (minutes jogging) = (calories burned)

If m represent Anzelm's total minutes, then m-5 will represent the number of minutes actually jogging. This is what goes inside parentheses, so we have ...

  (12 calories per minute) × ((m -5) minutes) = 540 calories

Leaving off the units, which we know are consistent, we have ...

  12 (m -5) = 540

Answer:

12(m-5) = 540

Step-by-step explanation:

∵ The total calories have to burn = 540,

Also, here m represents the total time spent by Anzelm,

If he/she spent 5 minutes in rest,

Then the time he/she spent in jogging = (m - 5) minutes,

If the number of calories burnt in one minute = 12,

So, the number of calories burnt in (m-5) minutes = 12(m-5),

Therefore, for burning the whole calories,

Calories burnt by him/her = total calories

⇒ 12(m-5) = 540

Which is the required equation.

Please explain how you got this answer.

-Aparri

Answers

Answer:

She got a 87 on her chemistry test

Step-by-step explanation:

(72 + 85 + 92 + x)/4 = 84

249 + x = 336

x = 87

If the given sequence is a geometric sequence, find the common ratio.

3/3, 3/12, 3/48, 3/192, 3/768

a. 4

b. 1/30

c. 30

d. 1/4

Answers

Answer:

  d.  1/4

Step-by-step explanation:

The ratio of adjacent terms is the common ratio:

  (3/12)/(3/3) = 3/12 = 1/4


A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude of 41,000 feet. Model the most fuel-efficient altitudes using a compound inequality.

x ≥ 29,000 and x ≤ 41,000
x ≤ 29,000 and x ≥ 41,000
x ≥ 41,000 and x ≥ 29,000
x ≤ 41,000 and x ≤ 29,000

Answers

Answer:

[tex]x\geq 29,000[/tex]  and  [tex]x\leq 41,000[/tex]

Step-by-step explanation:

Let

x -----> the altitude of a commercial aircraft

we know that

The expression " A minimum altitude of 29,000 feet" is equal to

[tex]x\geq 29,000[/tex]

All real numbers greater than or equal to 29,000 ft

The expression " A maximum altitude of 41,000 feet" is equal to

[tex]x\leq 41,000[/tex]

All real numbers less than or equal to 41,000 ft

therefore

The compound inequality is equal to

[tex]x\geq 29,000[/tex]  and  [tex]x\leq 41,000[/tex]

All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft

The solution is the interval ------> [29,000,41,000]

option 1 : x ≥ 29,000 and x ≤ 41,000 represents the most fuel-efficient altitudes using compound inequality.

We need to identify the correct compound inequality describing the altitude at which the aircraft operates most efficiently. The best fuel efficiency altitudes range from 29,000 ft to 41,000 ft, meaning the altitude must be at least 29,000 ft and at most 41,000 ft.

So, to represent that the altitude must be at least 29000 ft we use the mathematical expression:

[tex]x\geq 29,000[/tex]

To represent that the altitude must be 41000 ft at most we use the mathematical expression:

[tex]x\leq 41,000[/tex]

These two expression can be represented as a compound inequality as follows:

[tex]x\geq 29,000\[/tex] and [tex]x\leq 41,000[/tex]

Therefore, option 1 : x ≥ 29,000 and x ≤ 41,000 represents the most fuel-efficient altitudes using a compound inequality.

Someone please help me with this...

Answers

Answer:

The total number of points you score is dependent variable Because it change when x is change.

The number of question you answer correctly is independent variable Because it can change itself when you got more correct answers.

The top put a dot for dependent variable,
The bottom put independent variable.

Hope this helps!

Write the equation of a line that goes through point (0, −8) and has a slope of 0.

A.) x = -8
B.) x = 0
C.) y = - 8
D.) y = 0

Answers

Answer:

C.) y = - 8

Step-by-step explanation:

If the line has a slope of 0, it is a horizontal line.  That means y= a value

Since we have the point (0,-8)

y = -8

Final answer:

The equation of a line that goes through point (0, -8) with a slope of 0 is y = -8.(Option c)

Explanation:

We need to find the equation of a line that goes through the point (0, -8) and has a slope of 0. The general equation for a line in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept. Since the slope (m) is 0, the line is horizontal.

A horizontal line has an equation of the form y = b, where b is the y-coordinate of every point on the line. As the line goes through (0, -8), we can see that the y-coordinate is -8 for all points on this line. Therefore, the equation of this line is C) y = -8.

Complete a two-column proof for each problem.






In a difficult position right now all help is welcomed tyty

Answers

Answer:

D is the midpoint of AC                          Given

∠BDC ≅ ∠BDA                                        Given

BD ≅ BD                                                   Reflexive Property

AD ≅ DC                                                   Definition of line segment bisector

ΔADB ≅ ΔCBD                                         CPCTC (Congruent Parts of                   Congruent Triangles are Congruent)

~

Mr de guzman bought 7 1/2 of meat.He used 2 3/4 for afritada,3 1/8 kg for menudo and the rest for pochero.How many kilograms of meat did he used for pochero?

Answers

Answer:

hola puto

Step-by-step explanation:

bggyyhh yyesws kihtwrqas bts23e4gyhun

Which description best describes the solution to the following system of equations?

y = –x + 4
y = 3x + 3 (4 points)


Line y = –x + 4 intersects the line y = 3x + 3.

Lines y = –x + 4 and y = 3x + 3 intersect the x-axis.

Lines y = –x + 4 and y = 3x + 3 intersect the y-axis.

Line y = –x + 4 intersects the origin.

Answers

Answer:

  Line y = –x + 4 intersects the line y = 3x + 3

Step-by-step explanation:

The solution is described as the point of intersection of the two lines. The description above is the only one that says anything about that.

___

Comments on other answer choices

Any line with finite non-zero slope intersects both the x- and y-axes. That fact does not describe the solution to a system of equations.

Any linear equation with an added (non-zero) constant will not intersect the origin. These two equations have +4 and +3 added, so neither line intersects the origin.

Combine Radicals/Fractional Exponents

Image Below, Will Give Brainliest~

What is the product of a b and c

Answers

[tex]\mathsf{Given :\;\;\dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{64x^3y^3}}}[/tex]

[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{4^3x^3y^3}}}[/tex]

[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{\sqrt[3]{(4xy)^3}}}[/tex]

[tex]\bigstar\;\;\textsf{We know that : \boxed{\mathsf{\sqrt[n]{a} = a^{\dfrac{1}{n}}}}}[/tex]

[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{(4xy)^{\dfrac{3}{3}}}}}[/tex]

[tex]\mathsf{\implies \dfrac{5x^{\dfrac{-3}{2}}y^{-2}}{{4xy}}}[/tex]

[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) \left(\dfrac{x^{\dfrac{-3}{2}}}{{x}}\right)\left(\dfrac{y^{-2}}{y}\right)}[/tex]

[tex]\bigstar\;\;\textsf{We know that : \boxed{\dfrac{a^m}{a^n} = a^{m - n}}}}[/tex]

[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3}{2} - 1\right)}}y^{(-2 - 1)}}[/tex]

[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-3 - 2}{2}\right)}}y^{-3}}[/tex]

[tex]\mathsf{\implies \left(\dfrac{5}{4}\right) x^{\left(\dfrac{-5}{2}\right)}}y^{-3}}[/tex]

[tex]\textsf{Comparing the above with $\mathbf{ax^by^c}$, We can notice that :}[/tex]

[tex]\bigstar\;\;\mathsf{a = \dfrac{5}{4}}[/tex]

[tex]\bigstar\;\;\mathsf{b = \dfrac{-5}{2}}[/tex]

[tex]\bigstar\;\;\mathsf{c = -3}[/tex]

[tex]\implies \mathsf{Product\;of\;a,\;b\;and\;c = \left(\dfrac{5}{4}\times \dfrac{-5}{2} \times -3\right)}[/tex]

[tex]\implies \mathsf{Product\;of\;a,\;b\;and\;c = \dfrac{75}{8}}[/tex]

Below is the beginning of the construction of a line parallel to the y-axis through point P. What is the next step of this construction?


A. Measure the distance from the intersection of the transversal to point P.

B. Place the compass on the point of intersection and mark an arc through the transversal and y-axis.

C. Draw another transversal.

D. Connect the arc intersections using a straight edge.

Thanks!

Answers

Answer:

  B. Place the compass on the point of intersection and mark an arc through the transversal and y-axis

Step-by-step explanation:

Creating a parallel line through a point involves copying the angle a transversal makes with the given line. The copied angle has the given point as its vertex, and the transversal as one side.

Copying an angle uses the steps of ...

draw an arc through the sides of the given angledraw an arc with the same radius centered at the new vertex...

The step this question is referring to is the first bullet above. The given angle is the angle between the transversal and the y-axis.

Divide the binomial by the monomial to find the quotient.

48x^4y-72x^6y^2
-------------------------
-12x^2y

Answers

Answer:

  -4x² +6x⁴y

Step-by-step explanation:

Deal with it term by term, factor by factor.

[tex]\dfrac{48x^4y-72x^6y^2}{-12x^2y}=\dfrac{48x^4y}{-12x^2y}+\dfrac{-72x^6y^2}{-12x^2y}\\\\=\dfrac{48}{-12}\cdot\dfrac{x^4}{x^2}\cdot\dfrac{y}{y}+\dfrac{-72}{-12}\cdot\dfrac{x^6}{x^2}\cdot\dfrac{y^2}{y}=-4x^2+6x^4y[/tex]

Final answer:

To divide the binomial by the monomial, divide each term's coefficients and subtract their exponents, resulting in the quotient [tex]-4x^2 + 6x^4y[/tex].

Explanation:

To divide the given binomial by the monomial, we divide each term in the numerator by the term in the denominator. In this case, we need to divide both terms of the binomial [tex]48x^4y - 72x^6y^2[/tex] by the monomial[tex]-12x^2y[/tex]. This involves dividing the coefficients (the numbers in front of the variables) and subtracting the exponents for like bases according to the rules of division of exponentials.

Starting with the first term:

[tex]\frac{48x^4y}{ -12x^2y} = -4x^{(4-2)}y^{(1-1)} = -4x^2y^0 = -4x^2[/tex]

Now the second term:

[tex]\frac{-72x^6y^2}{-12x^2y } = 6x^{(6-2)}y^{(2-1)} = 6x^4y[/tex]

The final quotient of dividing the binomial by the monomial is:

[tex]-4x^2 + 6x^4y[/tex]

Ben drew 3 two-dimensional shapes that had II angles in all. Draw shapes Ben could have drawn.

Answers

The figure is attached to show the shapes Ben could have drawn

He could have drawn  2 four angled polygon , 1 triangle and  1 pentagon , 2 triangles .

What are Two Dimensional Shapes ?

The shapes which lie on two coordinate axis and has length ,and breadth are called Two dimensional shapes.

A polygon is included in two dimensional shapes.

It is given in the question that

Ben drew 3 two-dimensional shapes that had 11 angles in all.

11 angles mean

2 four angled polygon , 1 triangle

2 quadrilaterals ( rectangle , square , rhombus etc.) and a triangle

1 pentagon , 2 triangles

A figure is attached  for the above stated answer .

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NEED HELP FAST PULEASEE

Please help fast asap

What is the probability of drawing three black cards, one at a time with replacement, from a standard deck of 52 cards?


A.'3/52

Its not b

C.1/8

d.75/676


Need help fasttt

GIve p(6,6) and q=(-5,-3) find the magnitude of 2p+3q



A.2 sqr3


B. 3 sqr2


its not C


D.14



According to NFL statistics, the Cincinnati Bengals will lose 13 out of 16 games, regardless of opponent. What are the odds of Cincinnati losing a game?



A.3;13


its not b


C.13;3


D16;13



Determine which trigonometric function to use to solve for the hypotenuse. Then,


solve for the length of the hypotneuse.

b=9

A=55.8


A.cosin, .062

B.sin,10.8

C.sin,16.0

its not D

Answers

Answer:

6

Step-by-step explanation:

HELP awarding 60 points and brainliest answer!!!

Answers

Answer:

A

Step-by-step explanation:

Choice A is right because there is no dot above the two.

Choice B is not right because there is 2 dots above 1 and not 3.

Choice C is not right because the data doesn't go passed 5 to get to 8

Choice D is not right because it was 5 games because there is 5 dots above 3

The answer would be A. the team never scored exactly 2 goals in a single game

If you look at the number two on the dot plot you can see that there are NO dots above it. This means that the team never scored exactly 2 goals.

It can't be B. because they scored exactly 1 goal for 2 games NOT 3

It can't be C.  because no where on the graph is the number 8. They never scored 8 goals. Five is actually the highest number of goals they ever scored.

It can't be D. because they scored 3 goals in a game for 5 games not for 4 games

Hope this helped!

~Just a girl in love with Shawn Mendes

what is the measure of DEF

Answers

Answer:

The measure of arc DEF is 204° ⇒ answer C

Step-by-step explanation:

* Lets talk about some facts in the circle

- If the vertex of an angle on the circle and the two sides of the

 angle are chords in the circle, then this angle is called  

 an inscribed angle

- Each inscribed angle subtended by the opposite arc, the arc name

 is the starting point and the ending point of the angle

- The measure of any circle is 360°

# Ex: ∠CAB is inscribed angle subtended by arc CB

- There is a relation between the inscribed angle and its  

  subtended arc, the measure of the inscribed angle equals half

  the measure of its subtended arc

* Now lets solve the problem

- ∠DEF is an inscribed angle subtended by arc DF

∴ m∠DEF = (1/2) measure of arc DF

∵ The measure of ∠DEF = 78°

∴ 78° = (1/2) measure of arc DF ⇒ multiply both sides by 2

∴ The measure of arc DF = 78° × 2 = 156°

∵ The measure of arc DF + The measure of arc DEF = The measure of

   the circle

∵ The measure of the circle = 360°

∵ The measure of the arc DF = 156°

∴ 156° + measure of arc DEF = 360° ⇒ subtract 156 from both sides

∴ The measure of arc DEF = 360° - 156° = 204°

* The measure of arc DEF is 204°

Answer: OPTION C.

Step-by-step explanation:

By definition:

[tex]Inscribed\ Angle = \frac{1}{2} Intercepted\ Arc[/tex]

Then we can calculate the measure of DF. This is:

[tex]78\°=\frac{1}{2}DF\\\\DF=(2)(78\°)\\\\DF=156\°[/tex]

We know that there are 360 degrees in a circle, therefore, in order to find the measure of DEF, we need to make the following subtraction:

[tex]DE[/tex][tex]F[/tex][tex]=360\°-156\°[/tex]

[tex]DE[/tex][tex]F[/tex][tex]=204\°[/tex]

 You can observe that this matches with the option C.

If tuvw is an an isoaceles trapezoid with tu parallel to wv, name a pair of similar traingles. Explain

Answers

Answer:

  TUW ~ UTV, TWV ~ UVW

Step-by-step explanation:

An isosceles trapezoid is symmetrical about the perpendicular bisector of its bases. A triangle formed by deleting a vertex on one side of that line of symmetry will be similar to the corresponding triangle formed by deleting the symmetrically opposite vertex on the other side. The two pairs listed above are the possibilities.

The cost of a long-distance phone call is $0.45 for the first minute and $0.36 for each additional minute. If the
total charge for a long-distance call is $6.93, how many minutes was the call?
The call was for
minutes.

Answers

Answer:

19 minutes

Step-by-step explanation:

cost = .45+.36m

If we take 6.93 minus .45 for the minute, we get 6.48. We take 6.48 and divide it by .36 for each additional minute, which is 18. We take the 18 and add one more minute to it since .45 was covered for the first minute.

Final answer:

The long-distance phone call that cost $6.93 was 19 minutes long. This was calculated by first deducting the cost of the first minute from the total cost, then dividing the remaining cost by the cost of each additional minute, and finally adding back the first minute.

Explanation:

The subject of this question is mathematics, and it involves understanding the cost structure of a long-distance phone call. So here's how we solve the problem:

Subtract the first minute's cost from the total cost. So, $6.93 - $0.45 = $6.48.Then divide the remaining total by the cost of each additional minute. So, $6.48 / $0.36 = 18 additional minutes.Last, add back in the first minute that we subtracted at the start. So, 18 minutes + 1 minute = 19 minutes total.

Therefore, the duration of the long-distance phone call that cost $6.93 was 19 minutes.

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If an object is dropped from a height of 144 feet, the function h(t) = -16t2 + 144 gives the height of the object after t seconds. When will the object hit the ground?

Answers

Answer:

3 seconds is correct.

Step-by-step explanation:

The object hit the ground at 3 seconds

What are equations?

An equation is a mathematical statement which equate two algebraic expressions. An equation has an equal to (=) sign in between the expression.

How to find when will the object hit the ground?

According to the problem,

An object is dropped from a height of 144 feet

The given function is h(t) = -16t2 + 144.

When the object reaches the ground h(t) becomes 0

So, the equation will be 0 =  -16t2 + 144.

Solving the equation we get t = 3 seconds

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A student received a 75% on an exam. If there were 20 questions on the exam, which ratio would show the number of questions answered correctly to the total number of questions? A. 5:20 B. 15:20 C. 20:15 D. 20:5

Answers

Answer:

15:20

Step-by-step explanation:

15:20 = 15/20 = .75 = 75%

What should be the next letter in the following series? A z e b i y o _ ?_

Answers

Answer:  c

Step-by-step explanation:

Notice the pattern (vowel, consonant, vowel, consonant):

A: first vowel            z: last consonant

e: second vowel                                        b: first consonant      

i: third vowel             y: second to the last consonant

o: fourth vowel                                           c: second consonant

A salesperson obtained a systematic sample of size 20 from a list of 500 clients. to do​ so, he randomly selected a number from 1 to 25​, obtaining the number 18. he included in the sample the 18th client on the list and every 25th client thereafter. list the numbers that correspond to the 20 clients selected

Answers

Final answer:

The salesperson selected clients 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493 through systematic sampling from a list of 500 clients.

Explanation:

This is a question related to systematic sampling, which is a statistical method where elements are selected from an ordered sampling frame. In this case, the 20 clients were selected beginning with the 18th client and then continuing every 25th client.

To find the specific client numbers selected, we would follow the pattern by adding 25 to the prior number starting from 18. Keep adding until you reach 20 numbers. Let me list them for you:

18 (Starting client) 43 (18 + 25) 68 (43 + 25) 93 (68 + 25) 118 (93 + 25) 143 (118 + 25) 168 (143 + 25) 193 (168 + 25) 218 (193 + 25) 243 (218 + 25) 268 (243 + 25) 293 (268 + 25) 318 (293 + 25) 343 (318 + 25) 368 (343 + 25) 393 (368 + 25) 418 (393 + 25) 443 (418 + 25) 468 (443 + 25) 493 (468 + 25)

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Final answer:

The salesperson used systematic sampling to select clients from the list. Starting with the 18th client, the salesperson then selected every 25th client thereafter. The client numbers selected were 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493.

Explanation:

In this scenario, the salesperson obtained a systematic sample by first selecting the 18th client and then every 25th client thereafter from a list of 500 clients. This method of sampling is called systematic sampling. It's a type of sampling where we select items from an ordered population using a fixed, periodic interval after a random start. So, the numbers of the clients selected would be: 18, 43, 68, 93, 118, 143, 168, 193, 218, 243, 268, 293, 318, 343, 368, 393, 418, 443, 468, and 493.

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A survey found that 78% of students do their homework before 10:00 P.M. Predict how many students out of 975 do their homework before 10:00 P.M.

a.

about 761

b.

about 78

c.

about 800

d.

about 13

Answers

The answer is about 761

The product shown is a difference of squares. What is the missing constant term in the second factor?

(–5x – 3)(–5x +?

Answers

Answer:

[tex]\boxed{3)}[/tex]

Step-by-step explanation:

A difference of squares has the form (a - b)(a + b)

Your expression is (-5x - 3)(-5x + ?

Let's compare this with your expression.

[tex]\begin{array}{cclccl}(a & - & b) & (a & + & b)\\\downarrow & & \downarrow & \downarrow & & \downarrow \\(-5x & - & 3) & (-5x & + & \mathbf{3)} \\\end{array}\\\\\text{The missing term is }\boxed{\mathbf{3)}}[/tex]

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