PLEASE HELPPP MEEEEE

PLEASE HELPPP MEEEEE

Answers

Answer 1
7.The required equation of the line is y= 2x-58.y=30

Step-by-step explanation:

Given , a line passes through the points (1,-3) and (3,1)

The equation of line which passes through the points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is

[tex]y - y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)[/tex]

Here [tex]x_1 = 1 , y_1= -3[/tex]     and      [tex]x_2 = 3 , y_2= 1[/tex]

The required equation of the line is

[tex]y+3=\frac{1+3}{3-1} (x-1)[/tex]

[tex]\Leftrightarrow y +3 =2(x-1)[/tex]

[tex]\Leftrightarrow y =2x-2-3[/tex]

[tex]\Leftrightarrow y =2x-5[/tex]

8.

Given, y varies directly with x and y=24 when x=8

Therefore,

[tex]y\propto x[/tex]

[tex]\Rightarrow y = kx[/tex].........(1)

y = 24 when x=8

[tex]\therefore 24 = 8k[/tex]

[tex]\Rightarrow k =3[/tex]

Equation (1) becomes

y= 3x

So, when x=10

y=3×10

⇒y=30


Related Questions

how do you solve 23.61 divided by 3

Answers

Answer:

7.87

Step-by-step explanation

Divide

the answer is 7.87 just divide 23.61 and 3

This really doesn’t make sense to me... Please explain and tell me the answer

Answers

Answer:

d)

Step-by-step explanation:

the answer would be d) because complementary angles equal 90 and, it said that angles d) and a) are complementary. well it would be false since d=125 and obviously angle a) would also be 125 since they are vertical angles

Solve the following by using mathematical Induction. For >/ 1
1^2+2^2+3^3+......+ n^2 = 1/6 n(n+1)(2n+[)

Answers

Answer:

See explanation

Step-by-step explanation:

Prove that

[tex]1^2+2^2+3^3+...+n^2=\dfrac{1}{6}n(n+1)(2n+1)[/tex]

1. When [tex]n=1,[/tex] we have

in left part [tex]1^2=1;[/tex] in right part [tex]\dfrac{1}{6}\cdot 1\cdot (1+1)\cdot (2\cdot 1+1)=\dfrac{1}{6}\cdot 1\cdot 2\cdot 3=1.[/tex]

2. Assume that for all [tex]k[/tex] following equality is true

[tex]1^2+2^2+3^3+...+k^2=\dfrac{1}{6}k(k+1)(2k+1)[/tex]

3. Prove that for [tex]k+1[/tex] the following equality is true too.

[tex]1^2+2^2+3^3+...+(k+1)^2=\dfrac{1}{6}(k+1)((k+1)+1)(2(k+1)+1)[/tex]

Consider left part:

[tex]1^2+2^2+3^2+...+(k+1)^2=\\ \\=(1^2+2^2+3^3+...+k^2)+(k+1)^2=\\ \\=\dfrac{1}{6}k(k+1)(2k+1)+(k+1)^2=\\ \\=(k+1)\left(\dfrac{1}{6}k(2k+1)+k+1\right)=\\ \\=(k+1)\dfrac{2k^2+k+6k+6}{6}=\\ \\=(k+1)\dfrac{2k^2+7k+6}{6}=\\ \\=(k+1)\dfrac{2k^2+4k+3k+6}{6}=\\ \\=(k+1)\dfrac{2k(k+2)+3(k+2)}{6}=\\ \\=(k+1)\dfrac{(k+2)(2k+3)}{6}[/tex]

Consider right part:

[tex]\dfrac{1}{6}(k+1)((k+1)+1)(2(k+1)+1)=\\ \\\dfrac{1}{6}(k+1)(k+2)(2k+3)[/tex]

We get the same left and right parts, so the equality is true for [tex]k+1.[/tex]

By mathematical induction, this equality is true for all n.

A factory is shipping 9 bicycles to a store. Each bicycle has a mass of 11.6 kg and is packed in a box with a mass of 3.41kg. What is the total mass of all the bicycles and their packing boxes?

Answers

Answer:

135.09 kg

Step-by-step explanation:

First, we must determine the total weight of each bicycle including their boxes.  To do this, we must add 3.41 kg and 11.6 kg.  3.41 + 11.6 = 15.01.

Next, multiply the weight of one bike and its box to the total amount of bicycles there are.  There are 9 bikes, so 15.01*9 = 135.09 kg.

To find the total mass of all bicycles and their boxes, add the mass of one bicycle (11.6 kg) and its box (3.41 kg) to get the total mass for one unit (15.01 kg), and then multiply by the total number of bicycles (9), resulting in a total mass of 135.09 kg.

The total mass of all the bicycles and their packing boxes can be calculated by first determining the mass of one bicycle with its box, and then multiplying that by the total number of bicycles being shipped. The mass of one bicycle is 11.6 kg and the mass of its packing box is 3.41 kg. Adding these together gives us the total mass for one bicycle and its box.

Mass of one bicycle: 11.6 kg
Mass of one box: 3.41 kg
Total mass for one bicycle and its box: 11.6 kg + 3.41 kg = 15.01 kg

This total mass for one bicycle and its box must then be multiplied by the number of bicycles to obtain the total mass for all bicycles and their boxes.

Number of bicycles: 9
Total mass for all bicycles and boxes: 9 * 15.01 kg = 135.09 kg

Therefore, the total mass of all the bicycles and their packing boxes is 135.09 kg.

in an arithmetic series a1= -14 and a5=30 find the sum of the first 5 terms

Answers

The sum of the 5 terms in the arithmetic series is 40.

Step-by-step explanation:

Step 1;  First we need to determine the three values between a1= -14 and a5=30. The difference between the first and fifth value = 30 - (-14) = 30 + 14 = 44.

Since there are 4 values after a1 we divide the difference by the number of terms, the difference between each term = 44 / 4 = 11. So the difference between each term is 11.

Step 2; To find out the terms we just add the difference to the previous number.

a1 = -14.

a2 = -14 + 11 = -3.

a3 = -3 + 11 = 8.

a4 = 8 + 11 = 19.

a5 = 19 + 11 = 30.

So a1 + a2 + a3 + a4 + a5 = -14 -3 + 8 + 19 + 30 = 40.

Final answer:

The sum of the first 5 terms in this arithmetic series is 40, calculated based on the formulas for an arithmetic series involving the first term, the fifth term, and the common difference.

Explanation:

In an arithmetic sequence or series, the difference between each term (the common difference) is constant. We can represent this as: an = a1 + (n - 1) * d, where d is the common difference. Given in this problem that a1 = -14, a5 = 30, and n = 5.

First, we can find the common difference d using the formula: d = (a5 - a1) / (5 - 1) . So, d = (30 - (-14)) / (5 - 1) = 44 / 4 = 11.

Then, we can find the sum of the first 5 terms using the formula: Sn = n / 2 * (2a1 + (n - 1) * d). That gives us: S5 = 5 / 2 * (2(-14) + (5 - 1) * 11) = 5 / 2 * (-28 + 44) = 5 / 2 * 16 = 40.

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GRADE 8 UNIT 5 LESSON 5 OPEN UP RESOURCES
#3 A car is traveling on a small highway and is either going 55mph or 35mph, depending on the speed limits, until it reaches its destination 200 miles away. Letting x represent the amount of time in hours that the car is going 55mph, and y being the time in hours that the car is going 35mph, an equation describing the relationship is:
55x + 35y = 200
a. If the car spends 2.5 hours going 35mph on the trip, how long does it spend going 55mph?
b. If the car spends 3 hours going 55mph on the trip, how long does it spend going 35mph?
c. If the car spends no time going 35mph, how long would the trip take?

Answers

a. It spends 2.04 hours going 55 mph.

b. It will spend 1 hour going 35 mph.

c. The trip will take 3.64 hours.

Step-by-step explanation:

Given equation is;

55x + 35y = 200

Where

x represent the time when speed is 55 mph

y represent the time when speed is 35 mph

a. If the car spends 2.5 hours going 35mph on the trip, how long does it spend going 55mph?

Putting y=2.5 in given equation

[tex]55x+35(2.5)=200\\55x+87.5=200\\55x=200-87.5\\55x=112.5\\[/tex]

Dividing both sides by 55

[tex]\frac{55x}{55}=\frac{112.5}{55}\\x=2.04\ hours[/tex]

It spends 2.04 hours going 55 mph.

b. If the car spends 3 hours going 55mph on the trip, how long does it spend going 35mph?

Putting x=3 in given equation

[tex]55(3)+35y=200\\165+35y=200\\35y=200-165\\35y=35[/tex]

Dividing both sides by 35

[tex]\frac{35y}{35}=\frac{35}{35}\\y=1[/tex]

It will spend 1 hour going 35 mph.

c. If the car spends no time going 35mph, how long would the trip take?

Putting y=0 in given equation

[tex]55x+35(0) = 200 \\55x+0=200\\55x=200[/tex]

Dividing both sides by 55

[tex]\frac{55x}{55}=\frac{200}{55}\\x=3.636[/tex]

Rounding off

x = 3.64

The trip will take 3.64 hours

Keywords: linear equation, division

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146+8 1/5
How do I solve this

Answers

Step-by-step explanation:

[tex]146 + 8 \frac{1}{5} \\ \\ = 146 + \frac{8 \times 5 + 1}{5} \\ \\ = \frac{146 \times 5 + 40 + 1}{5} \\ \\ = \frac{730 + 41}{5} \\ \\ = \frac{771}{5} \\ \\ = 154 \frac{1}{5} \\ \\ thus \\ \\ \huge \orange{ \boxed{146 + 8 \frac{1}{5} = 154 \frac{1}{5}}}[/tex]

PLEASE HELP ME!!!


Ms. Grady has 150 pictures in an album. Of these pictures, 48 show her friends, 24 show her family, and 78 show
only Ms. Grady. Ms. Grady is in of the pictures that show her friends and of the pictures that show her family.
Based on this information, which statement is true?
a. The probability of randomly selecting a picture that shows Ms. Grady is 76%.
The probability of randomly selecting a picture that shows Ms. Grady with her friends is greater than the
probability of randomly selecting a picture that shows Ms. Grady with her family.
The probability of randomly selecting a picture that does not show Ms. Grady is 52%.
d. The probability of randomly selecting a picture that shows Ms. Grady with her family is 3 times the
probability of randomly selecting a picture that shows only her friends.​

Answers

Answer:

B

Step-by-step explanation:

the others wouldn't make seans

A pitcher struck out 11 out of 40 batters. Write an equivalent decimal.

Answers

Answer:

0.275

Step-by-step explanation:

We want to write 11 out of 40 batters as a decimal.

We can write 11 out of 40 as a fraction to get:

[tex] \frac{11}{40} [/tex]

Note that:

[tex] \frac{11}{40} = \frac{1}{4} \times \frac{11}{10} [/tex]

This implies that:

[tex] \frac{11}{40} = 0.25 \times 1.1[/tex]

This gives us

[tex] \frac{11}{40 } = 0.275[/tex]

for every $50 of candy you sell, you get to keep 7% of it. how much commission do you make if you sell $200 worth of candy?

Answers

You'll make 14 dollars.

7% of 50 is 3.5.

If you add 3.5 four times you'll get 14.

200 - 7% is 186.

200 - 14 is 186.

Answer:

$14

Step-by-step explanation:

Well, first find 7% of 50.  To do this you need to make the percent a decimal by moving the decimal that is already(7 is the whole number, if there were any fractions it would be 7.00%) there two space to the left, adding zeros as needed.  

0.07 x 50 = x

3.5 = x

Now you can multiply it by whatever you want.  In this case it would be 4 since 50 time 4 is 200.

3.5 x 4 = 14

So the amount of money that you would make would be $14.

Hope this helped you out.

find the radius of a discus woth a circumference 8.6 pi inches​

Answers

Answer:

4.3π or 13.51 = r

Step-by-step explanation:

C=2πr To find the circumference of a circle, you must have the formula

8.6π = 2πr      Substitute the C for 8.6π

4.3π = r           Divide both sides by 2π

13.51 = r         Simplify 4.3π if needed

Classify the following triangle. Check all that apply.

A. Right
B. Scalene
C. Acute
D. Equilateral
E. Obtuse
F Isosceles

Answers

Answer:

A, E

Step-by-step explanation:

I think it is obtuse and scalene, but I don't think that is the only answer. Hope that can help a little.

The triangle is an isosceles and an obtuse triangle.

A triangle with two sides of equal length is an isosceles triangle. The isosceles triangle has three acute angles, meaning that the angles are less than 90°. The sum of three angles of an isosceles triangle is always 180°.

In an isosceles triangle, the two equal sides are called legs, and the remaining side is called the base. The angle opposite the base is called the vertex angle

The three types of Isosceles Triangles are :

Isosceles acute triangle

Isosceles right triangle

Isosceles obtuse triangle

Given data ,

Let the triangle be represented as ΔABC

Now , the measure of ∠ABC = 120°

So , it is an obtuse triangle with angle > 90°

Now , the measure of sides AB = measure of BC

So , an isosceles triangle, the two equal sides are called legs, and the remaining side is called the base

Therefore , it is an Isosceles obtuse triangle

Hence , the triangle is isosceles

The length of a rectangle is five times its width. If the area of the rectangle is 320m, find the perimeter

Answers

Answer: The perimeter is 96 m

Step-by-step explanation:

If we tag the length of the rectangle as [tex]l[/tex] and the width as [tex]w[/tex], and if in addition we are told [tex]l=5 w[/tex],the dimensions of the rectangle are as shown in the figure.

Now, the area of a rectangle is given by:

[tex]A=(l)(w)=320 m^{2}[/tex]

Since [tex]l=5 w[/tex]:

[tex]A=(5w)(w)=320 m^{2}[/tex]

Isolating [tex]w[/tex]:

[tex]5w^{2}=320 m^{2}[/tex]

[tex]w=\sqrt{\frac{320 m^{2}}{5}}[/tex]

[tex]w=8 m[/tex]

On the other hand, the perimeter of a triangle is given by the addition of each of its sides. Then, if the rectangle has two sides that measure [tex]w[/tex] and two sides that measure [tex]5 w[/tex], the perimeter is:

[tex]P=2(5)(w)+2w[/tex]

Substituting the value of [tex]w[/tex] in the last equation:

[tex]P=2(5)(8 m)+2(8 m)[/tex]

Finally the perimeter is:

[tex]P=96 m[/tex]

Final answer:

The perimeter of the rectangle is determined by first finding the width using the area given, then calculating the length as five times the width and using the formula P = 2l + 2w. The perimeter is 96 meters.

Explanation:

To solve for the perimeter of the rectangle when we know the area is 320m² and the length is five times the width, we first let w represent the width of the rectangle. Therefore, the length is 5w. Given that the area A is equal to the length times the width, we have the equation w × 5w = 320. Solving for w, we get w² = 64 so w = 8 meters.

Since the length is five times the width, it is 5 × 8 = 40 meters. The perimeter P of a rectangle is given by P = 2l + 2w, where l is the length and w is the width. Substituting the values we have, P = 2(40) + 2(8) = 96 meters.

A oth grade student can complete 20 multiplication facts in 1 minute. If he works at the same rate, how long should it
take him to complete 35 multiplication facts? (Type your answer as a decimal number]
minutes

Answers

1 minuet =20 facts
1.3 minutes = 30 facts
1.45 minutes =35 facts
Answer is 35

It should take the student 1.75 minutes to complete 35 multiplication facts.

To determine how long it will take the 5th grade student to complete 35 multiplication facts at the same rate as 20 facts in 1 minute, we can set up a proportion or use unit rates. Since the student can complete 20 facts in 1 minute, we find the time per fact by dividing the total time by the number of facts:

1 minute / 20 facts = 0.05 minutes per fact

Then, we multiply the rate by the number of new facts:

0.05 minutes per fact * 35 facts = 1.75 minutes

Therefore, it should take the student 1.75 minutes to complete 35 multiplication facts.

The box plots below show the ages of college students in different math courses.

A box-and-whisker plot labeled Math 1 is shown. The number line goes from 16 to 22. The whiskers range from 17 to 21, and the box ranges from 18-20. A line divides the box at 19. A box-and-whisker plot labeled Math 2 is shown. The number line goes from 16 to 24. The whiskers range from 17 to 23, and the box ranges from 18-20. A line divides the box at 19.
Math 1 Math 2

Which statement is true?
The median age of the students in Math 1 is greater than the median age of the students in Math 2.
The median age of the students is Math 1 is less than the median age of the students in Math 2.
The mean and median age are most likely the same for both sets of data.
The mean and median age are more likely to be the same for the students in Math 1.

Answers

Answer:

The correct option for this is C.) The mean and median age are more likely to be the same for the students in Math 1.

Step-by-step explanation:

i) The median age of the students is Math 1 is less than the median age of the students in Math 2.

This statement is NOT TRUE as the median age of students in Math 1 = median age of students in Math 2 = 19

ii) The mean and median age are most likely the same for both sets of data.

   This statement is NOT TRUE. The mean age of students in Math 2 should be greater than mean age of students in Math 1.

iii) The mean and median age are more likely to be the same for the students in Math 1.

  This statement is TRUE.

Answer:

The mean and median age are more likely to be the same for the students in Math 1.

Step-by-step explanation:

The median age of the students for the student is Math 1 is less than the median age of the students in Math 2.

The statement is not true as the median age of students in Math 1 is equal to the median age of the students in Math 2 = 19.

Also, the mean and median age are the most likely to be the same for both sets of data.

The above statement is also not true as the mean age of students in Math 2 should be greater than the mean age of students in Math 1.

I have my friends answer but I need to show working out?

Answers

Answer:

42

Step-by-step explanation:

You change 1/2 to 3/6

1/2=3/6

Then, you take 3-1=2 to find the difference

Next, as you found out that 2 units equals to 14, you take 14÷2=7

As there are 6 units, you take 7×6=42

Thus, the answer 42

Answer:

42

Step-by-step explanation:

Let total no. of trees be 'X'

Lemon are (1/6) of X = X/6

Orange are (1/2) of X = X/2

Difference is 14

X/2 - X/6 = 14

Lcm is 6

(3X-X)/6 = 14

2X = 14×6

X = 42

If a triangle has side lengths 27, 79, and 84 is it a right triangle

Answers

Answer:

Nope

Step-by-step explanation:

A right triangle must have a 90 degree angle.

What is 70% of 38, please show work

Answers

Answer: 26.6

Step-by-step explanation: To solve this problem, let's ignore the first  2 words which are "what is."

So, we can really change the problem to say 70% of 38.

To find 70% of 38, first write 70% as a decimal by moving the decimal point 2 places to the left to get .70.

Next, the word "of" means multiply, so we have (.70)(38) which is 26.6.

So 70% of 38 is 26.6.

A cylinder has a height of h meters, and the base has a radius of 7 meters. If the volume of the cylinder is 539π find the height

Answers

Answer:

Therefore,

The Height of Cylinder is 11 meters.

Step-by-step explanation:

Given:

Cylindrical Shape

Radius = r = 7 meter

Volume of Pipe = 539π

To Find:

Height = ?

Solution:

Formula for Volume of Cylinder is given by

[tex]\textrm{Volume of Cylinder}=\pi (Radius)^{2} \times Height[/tex]

Substituting the given values we get

[tex]539\pi=\pi(7)^{2}\times Height\\\\Height=\dfrac{539}{49}=11\ meter[/tex]

Therefore,

The Height of Cylinder is 11 meters.

Suppose that you have 7 green cards and 5 yellow cards. The cards are well shuffled. You randomly draw two cards without replacement.

G1 = the first card drawn is green
G2 = the second card drawn is green

a. P(G1 and G2) =
b. P(At least 1 green) =
c. P(G2|G1) =
d. Are G1 and G2 independent?

Answers

a. P(G1 and G2) = 0.154 b. P(At least 1 green) = 0.592 c. P(G2|G1) = 19/49

d. G1 and G2 are not independent

Let's assume we are drawing cards from a deck without replacement.

There are two possibilities for the first card drawn (G1):

The first card drawn is green (G1).

The first card drawn is not green (Non-G1, which means it's either red or blue).

a. P(G1 and G2) = P(G1) * P(G2|G1)

Since we are drawing without replacement, after drawing a green card for G1, there is one less green card in the deck. Therefore:

P(G1) = Number of green cards / Total number of cards = 20/50 = 2/5

P(G2|G1) = Number of green cards remaining / Total number of cards remaining = 19/49

So, P(G1 and G2) = (2/5) * (19/49) ≈ 0.154

b. P(At least 1 green) = 1 - P(no green cards) = 1 - P(non-G1 and non-G2)

P(non-G1) = Number of non-green cards / Total number of cards = 30/50 = 3/5

P(non-G2|non-G1) = Number of non-green cards remaining / Total number of cards remaining = 29/49

P(no green cards) = P(non-G1) * P(non-G2|non-G1) = (3/5) * (29/49)

So, P(At least 1 green) = 1 - P(no green cards) = 1 - (3/5) * (29/49) ≈ 0.592

c. P(G2|G1) = Number of green cards remaining / Total number of cards remaining = 19/49

d. No, G1 and G2 are not independent because the outcome of drawing the first green card (G1) affects the probability of drawing a green card in the second draw (G2). The conditional probability P(G2|G1) is not equal to the unconditional probability P(G2).

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The value of the probabilities are: a) P(G1 and G2) =0.3182, b) P(At least 1 green) = 0.8485,c)  P(G2|G1) = 0.5455 and d) G1 and G2 dependent.

Given:

Total number of cards = 7 (green) + 5 (yellow)

                                     = 12 cards

a. Since the cards are drawn without replacement, the probability can be calculated as:

P(G1 and G2) = P(G1) * P(G2|G1)

P(G1) = Number of green cards / Total number of cards

        = 7 / 12

or, P(G2|G1) = Number of remaining green cards / Total remaining cards

                    =6/11

So, P(G1 and G2) = (7 / 12) * (6 / 11)

                            = 0.3182

b. P(At least 1 green) = 1 - P(Both yellow)

P(Both yellow) = P(Yellow1) * P(Yellow2|Yellow1)

P(Yellow1) = Number of yellow cards / Total number of cards

                 = 5 / 12

P(Yellow2|Yellow1) = remaining yellow cards / Total remaining cards

                               = 4 / 11

So, P(Both yellow) = (5 / 12) * (4 / 11)

                               = 0.1515

Therefore,

P(At least 1 green) = 1 - 0.1515

                               = 0.8485

c. Since one green card has already been drawn, there are now 6 green cards and 11 cards in total remaining:

P(G2|G1) = Number of green cards / Total remaining cards

              = 6 / 11

              = 0.5455

d. In this case, G2|G1 is not equal to the overall probability of G2.

This indicates that the events are dependent, as the probability of drawing a green card for the second draw changes based on the outcome of the first draw.

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Warm up your day with a easy math problem! Which quantity is proportional to 35⁄80?
Comment all that are true.
A. 3⁄5

B. 14⁄36

C.26⁄52

D.21⁄48

E. 7⁄16

Answers

D and E are the only ones true.

Answer:

E

Step-by-step explanation:

You simplify the fraction by dividing both top and bottom by 5

35÷5=7

80÷5=16

Evaluate
Evaluate -(-7)7

Answers

Answer:

The answer is 49 because -(-7)×7 =7×7 = 49

Yo sup??

-(-7)7

=(-1)*(-1)*7*7

=1*49

=49

Hope this helps.

A water pipe floods 50 square feet every 1/5 minute.what is the flooded area after 6 minutes

Answers

Final answer:

To find the flooded area after 6 minutes, calculate the number of 1/5-minute intervals in 6 minutes, which is 30. Then, multiply by the area flooded in each interval. The flooded area after 6 minutes would be 1500 square feet.

Explanation:

The question is asking to calculate the area that would be flooded by a water pipe after 6 minutes, given that the pipe floods 50 square feet every 1/5 of a minute. To find the answer, we need to determine how many 1/5-minute intervals are in 6 minutes, and then multiply that number by the area flooded in each interval.

First, calculate the number of intervals: 6 minutes × (5 intervals/minute) = 30 intervals.

Next, multiply the number of intervals by the area flooded per interval: 30 intervals × 50 square feet/interval = 1500 square feet.

Therefore, after 6 minutes, the flooded area would be 1500 square feet.

What is the slope of the line that contains these points?
x -4, 1, 6, 11
y -3,-2,-1,0

Answers

Answer:

slope = 1/5

Step-by-step explanation:

[tex]\frac{0-(-3)}{11-(-4)} =\frac{3}{15} =1/5[/tex]

Solve using substitution:
y = -3x + 5
5x - 4y = -3​

Answers

Answer:

x = 1 y = 2

Step-by-step explanation:

5x - 4y = -3

5x - 4 (-3x + 5) = -3

5x + 12x - 20 = -3

17x - 20 + 20 = -3 + 20

17x = 17 ÷ 17

x = 1

y = -3x + 5

y = -3 (1) + 5

y = -3 + 5

y = 2

8904 divided by 21 long dividion

Answers

The answer would be 424

Answer:424

Step-by-step explanation:

Shira has 20 books on her bookshelf. Of those 15 are about horses, the rest are nature books. What fraction of Shiras books are about nature.

Answers

Answer:

1/4

Step-by-step explanation:

15 out of the 20 books are horses. 5 of those are nature. 5/20 is the fraction, but can be simplified to 1/4

Final answer:

Shira has 5 out of 20 books about nature on her bookshelf, which simplifies to a fraction of 1/4 of her books being about nature.

Explanation:

Shira has 20 books in total on her bookshelf. Out of these, she has 15 books about horses, meaning the remaining books are about nature.

To find the fraction that represents the nature books, we need to subtract the number of horse books from the total number of books.

So, the number of nature books is 20 total books - 15 horse books = 5 nature books. The fraction of books about nature would therefore be the number of nature books divided by the total number of books, which is 5/20.

This fraction can be simplified by dividing both the numerator and the denominator by 5, resulting in 1/4. Therefore, 1/4 of Shira's books are about nature.

List 3 rational numbers between 3 and 3.9

Answers

The number are "3.4, 3.7, and 3.8"

Rational numbers:

List of number 3 rational numbers in 3 and 3.9.

The number sequence has the form a/b, where a and b are integers, and b is not equivalent to 0.As there were numerous quantities or measures that numerals alone could not effectively explain, rational numbers were required. The most typical application of rationals is the measurement, either of length, mass, time, or whatever.

Therefore the number are "3.4, 3.7, and 3.8".

Learn more about the numbers here:

brainly.com/question/26304625

Final answer:

Three rational numbers between 3 and 3.9 are 3.2, 3.3, and 3.6.

Explanation:

To list 3 rational numbers between 3 and 3.9, we can consider the numbers that lie between these two values.

We can start by looking for numbers with a tenths place greater than 3 but less than 9.

To find three rational numbers between 3 and 3.9, we simply need to choose numbers that have a finite number of digits after the decimal point.

Some examples of rational numbers in this range are 3.2, 3.3, and 3.6.

These satisfy the condition of being between 3 and 3.9.

What is 5(z+4) + 5(2-z) simplified?

Answers

Answer: 30

Step-by-step explanation:5(Z+4) + 5(2-Z).

Open the brackets by multiplying true by the number out of the bracket.

5Z + 20 + 10 - 5Z

Now, collect like terms, we have.

5Z - 5Z + 20 + 10. Now we have

0 + 30 = 30//

What is the difference of (Negative 3.4 x + 4.7) minus (3 + 2.9 x)?
Negative 0.5 x + 1.7
Negative 6.3 x minus 1.7
Negative 0.5 x minus 1.7
Negative 6.3 x + 1.7

Answers

Answer:

A.-0.5x+1.7

Step-by-step explanation:

-3.4x+4.7-3+2.9x

-0.5x+1.7

Answer:

-0.5x+1.7

Step-by-step explanation:

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