PLSSSSS help how much gravitation potential energy does a 5kg object have when it is 10 meters off the ground????

Answers

Answer 1

Considering the equation for gravitational potential energy, PE=mgh, where m as mass, g as the acceleration due to gravity, and h has the height.

Substituting the numbers given, you’ll get (taking g as 9.81)

PE = 5 x 9.81 x 10

PE = 490.5 J

Therefore the gravitational potential energy will be 490.5 J

Answer 2
Final answer:

The gravitational potential energy of a 5kg object at a height of 10 meters is 490 Joules.

Explanation:

The gravitational potential energy of an object can be calculated using the formula U = mgh, where U is the gravitational potential energy, m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object. In this case, we have a 5kg object at a height of 10 meters. Plugging the values into the formula, we get:

U = (5kg) * (9.8m/s^2) * (10m) = 490 J

Therefore, the 5kg object has 490 Joules of gravitational potential energy when it is 10 meters off the ground.

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Related Questions

apple newest ipad pro has a storage option of up to 128gb (gigabytes). how many bytes of storage will it have? use a conversion factor, and provide your answer in standard form and scientific notation

Answers

Explanation:

Storage offered by iPad pro = 128 gb

1 gigabyte = 1000,000,000 bytes

[tex]1 gb = 1\times 10^{9} bytes[/tex]

[tex]128 gb=128\times 10^9 bytes=128\times 10^9 bytes[/tex]

Standard form = 128,000,000,000 bytes of storage

Scientific notation = [tex]1.28\times 10^{11} \text{bytes of storage}[/tex]


Final answer:

The Apple iPad Pro with 128 GB of storage holds 137438953472 bytes of storage which in scientific notation would be written as 1.3744 x 10^11 bytes.

Explanation:

To find the number of bytes in 128 gigabytes (GB), we use the conversion factor that 1 GB is equal to 1024 megabytes (MB), and 1 MB is equal to 1024 kilobytes (KB), and 1 KB is equal to 1024 bytes. So, to convert 128 GB to bytes, we would do the following: 128 GB * 1024 (to get MB) * 1024 (to get KB) * 1024 (to get bytes).

Doing this calculation gives us a total of 137438953472 bytes. In scientific notation, this would be written as 1.3744 x 10^11 bytes.

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If we relied solely on the nonrenewable resources found in the U.S., which one would we run out of first at current usage levels?


A. natural gas

B. oil

C. uranium

D. coal

Answers

If we are depending on nonrenewable resources only then we will run out first at that resource which we are using at large level

that resource which is used at all levels at very fast level but we can't get it at that rate from natural sources

So out of all given choices we know that at most fastest rate we are using the OIL which we extract from the earth crust.

The rate with which we are extracting oil is very fast and if we use it at same rate then we will definitely run out of it

so correct answer would be

B. oil

Answer:

B: Oil

Explanation:

If consumption of natural resources continues at the 1994 rate, then without importing resources from other countries, the U.S. has approximately enough oil to last for 23 years, enough natural gas to last for 68 years, enough uranium to last for 364 years, and enough coal to last for 7,007 years.

Reference: Energy Information Administration's State Energy Data Report 1994

( study island )

Here is a force diagram of an object in water. The weight of the object is 15N and the buoyancy force is 17N. Will the object float or sink?


Float


Sink


Stay suspended just under the surface

Answers

Answer:

Object will float.

Explanation:

Total force on the body = Weight of body + Buoyancy force on body.

 Weight of body = 15 N downwards = 15 N

 Buoyancy force on body = 17 N upwards = -17 N

 Total force on body = 15 - 17 = -2 N = 2 N upwards

 So, the body will float.

Object will float.

Consider a boat heading due east at 15 miles/hour. The water's current is moving at 7.1 miles/hour at 45º south of east. Drag vectors for the boat and the current into the vector addition simulation.
What do Rx, Ry, , and |R| represent in terms of the force of the current, and what do they represent in terms of the forces moving the boat?

Answers

If a boat is going East at 15mph and there is a water current going southeast at 45° then the boat is being drifted southward.  So since the current is going at an angle then it has a x and y component.  So Rx refers to the x-component force of the current and Ry refers to the y-component of the current, and |R| refers to the magnitude of these forces.

Answer:

The boat velocity is 20.6 mph and  14 south of east

Explanation:

For this exercise it is best to write the speeds based on its components x and y

Boat    V1x = 15 mph

Water  V2 = 7.1 mph

           θ = - 45º

 Where the angle is measured from the x axis, the negative indicates that it is measured on an hourly basis

           V2x = V2 cos (-45) = 7.1 (0.707)

           V2y = V2 sin (-45) = 7.1 (-0.707)

           V2x = 5.0 mph

           V2y = -5.0 mph

The total system speed is the sum of each component

          Vx = V1x + V2x

          Vy = V1y + V2y

          Vx = 15 + 5.0

          Vy = 0 -5

          Vx = 20 mph

          Vy = -5.0 mph

We can give result in the form of magnitude and angle

          V² = Vx² + Vy²

          θ = tan-1 (Vy / Vx)

          V = √ [20² ++ (-5)²]

          θ = tan-1 (-5/20)

         

         V = 20.6 mph

         θ = -14º

 The boat velocity is 20.6 mph and  14 south of east

According to Newton, there were two things needed for an object to fall around or orbit the earth. Label the diagram below with these two things

Answers

Centripetal force and centrifugal force


Which statement correctly describes sound waves? Sound waves do not travel through a medium. Sound waves are transverse waves. Sound waves are longitudinal waves. Sound waves are not considered mechanical waves.

Answers

Sound waves are longitudinal waves.

What is a mechanical wave?

A mechanical wave is a type of wave that do not require material medium for its propagation.

Examples of mechanical waves;Sound wavesWater wavesSpring wavesSeismic waves

A mechanical wave can be longitudinal or transverse depending on the direction of the propagation.

Longitudinal waves

Longitudinal waves travel parallel to their direction of propagation, example sound waves.

Thus,  Sound waves are longitudinal waves.

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Final answer:

Sound waves are longitudinal waves that require a medium to propagate. The disturbances in sound waves are periodic variations in pressure that are transmitted in fluids.

Explanation:

Sound waves are longitudinal waves that require a medium to propagate. Unlike light waves, which can travel through a vacuum, sound waves need a medium, such as air, water, or solids, to travel through. The disturbances in sound waves are periodic variations in pressure that are transmitted in fluids, like air and water.

A force is a push or a pull applied to a body or an object. Consider the workout you just participated in. What forces were present on your body as you practiced your running stride or your jump shot? Were the forces helpful or hurtful? Explain using the ideas of external forces, internal forces, tension, and compression.

Answers

Gravity and friction

Answer: One external force was the ground pushing into my foot as I ran. This is a compression force. Gravity is also an external force that is working to pull my body down toward the ground. Since I’m trying to move my body forward, gravity is probably hurting my performance. Since I lean slightly forward when I run, there is a small tension force in my lower back. There is also tension in my shoulders as my arms swing by my sides.

Explanation: EDMENTUM

A 0.500-kilogram cart traveling to the right on a horizontal, frictionless surface at 2.20 meters per second collides head on with a 0.800-kilogram cart moving to the left at 1.10 meters per second. What is the magnitude ofthe total momentum of the two-cart system after the collision?

Answers

Consider the motion towards right as positive and motion towards left as negative.

m₁ = mass of the cart moving to right = 0.500 kg

v₁ = initial velocity before collision of the cart moving towards right = 2.2 m/s

m₂ = mass of cart moving to left = 0.800 kg

v₂ = initial velocity before collision of the cart moving towards left = - 1.1 m/s

initial momentum of the system of carts before the collision is given as

P₁ = m₁ v₁ + m₂ v₂

P₁ = (0.500) (2.2) + (0.800) (- 1.1)

P₁ = 0.22 kgm/s

P₂ = momentum of system of carts after collision

As per conservation of momentum,

Momentum of system of carts after collision = Momentum of system of carts before collision

P₂ = P₁

P₂ = 0.22 kgm/s

Final answer:

The magnitude of the total momentum of the two-cart system after the collision is 0.220 kg*m/s in the opposite direction of the initial velocity.

Explanation:

The total momentum of the two-cart system after the collision can be determined by applying the law of conservation of momentum. According to this law, the total momentum before the collision is equal to the total momentum after the collision.

Before the collision, the momentum of the first cart is calculated by multiplying its mass (0.500 kg) by its velocity (2.20 m/s) and the momentum of the second cart is calculated by multiplying its mass (0.800 kg) by its velocity (-1.10 m/s) since it is moving in the opposite direction. Therefore, the total momentum before the collision is 0.500 kg * 2.20 m/s + 0.800 kg * (-1.10 m/s) = 1.100 kg*m/s - 0.880 kg*m/s = 0.220 kg*m/s.

After the collision, the carts stick together and move as one. Since they have the same velocity, the total momentum after the collision is the sum of the masses multiplied by the common velocity. The total mass of the two carts is 0.500 kg + 0.800 kg = 1.300 kg. Therefore, the total momentum after the collision is 1.300 kg * V, where V is the common velocity. Since the carts move in opposite directions, the common velocity is negative. Setting the total momentum before the collision equal to the total momentum after the collision, we have 0.220 kg*m/s = 1.300 kg * V. Solving for V, we find V = 0.220 kg*m/s / 1.300 kg = -0.169 m/s.

a missile is moving 1350 m/s at a 25.0 deg angle. it needs to hit a target 23,500 m away in 55.0 deg direction in 10.20 s. what is the magnitude of its final velocity?

Answers

In this question we have given

velocity of missile=1350m/s

angle at which missile is moving=25degree

distance between missile and targets=23500m

angle between target and missile=55degree

time=10.2s

To find the final velocity of missile we will first find the acceleration required

Let x be the horizontal component of distance

x - vertical component of distance

t-time

ax- horizontal component of acceleration

ay-Vertical component of acceleration

Vx-horizontal component of velocity

Vy-Vertical component of velocity


horizontally: x = Vx*t + ½*ax*t²  

23500m * cos55.0º = 1350m/s * cos25.0º * 10.20s + ½ * ax * (10.20s)²  

ax = 19.2 m/s²  

V'x = Vx + ax*t = 1350m/s * cos25.0º + 19.2m/s² * 10.20s = 1419 m/s  

similarly vertically:

y = Vy*t + ½*ay*t² 

23500m * sin55.0º = 1350m/s * sin25.0º * 10.20s + ½ * ay * (10.20s)²  

ay = 258 m/s²  


V'y = Vy + ay*t = 1350m/s * sin25.0º + 258m/s² * 10.20s = 3204 m/s  

Therefore

V = √(V'x² + V'y²) = 3504 m/s  

therefore magnitude of final velocity of missile=3504m/s

A 50-foot flagpole is at the entrance of a building that is 300 feet tall. If the length of the flagpole's shadow is 30 feet at a certain time of day, how long is the building's shadow at that time? A. 75 feet B. 150 feet C. 180 feet D. 200 feet

Answers

First you will want to sketch out both of the situations. It should be two sketches, one for the flagpole and one for the building.

To solve this, you will want to create a proportion.

Flagpole height/flagpole shadow=building height/building shadow

Therefore, it should look like this:
50/30= 300/x

Solve for x:
50x=9,000
X= 180 feet

YOUR ANSWER IS C.

Answer:

c on plato

Explanation:

A rocket ship starts from rest and turns on its forward booster rockets, causing it to have a constant acceleration of 4 \,\dfrac{\text m}{{\text s}^2}4 s 2 m ? rightward. After 3\,\text s3s, what will be the velocity of the rocket ship? Answer using a coordinate system where rightward is positive.

Answers

Answer:

+12 m/s

Explanation:

The velocity of an object moving of accelerated motion is given by:

[tex]v(t) = v_0 +at[/tex]

where

v0 is the initial velocity of the object

a is the acceleration

t is the time

In this problem, the rocket starts from rest, so [tex]v_0 =0[/tex]. The acceleration is [tex]a=4 m/s^2[/tex], so the velocity after [tex]t=3 s[/tex] will be

[tex]v(3 s)=0 +(4 m/s^2)(3 s)=+12 m/s[/tex]

A trumpet player is playing a musical note. A boy is running at a constant velocity toward the trumpet player, then stops quickly when he is 2.0 meters away. As the boy stops running, what change in pitch, if any, occurs to the musical note he perceives?

The pitch becomes higher
The pitch remains the same
The pitch becomes lower

Answers

According to Doppler's law when a listener move towards a source of sound at rest, the frequency observed by the listener is greater than the actual frequency of sound coming from the source. This observed frequency by the listener is given as

f' = (V + v) f/V

where  f = actual frequency of the sound from source

V = speed of sound ,  v = speed of listener towards the source.

Since (V+v)/v > 1

hence f'> f

but when the boy stops , he starts hearing the actual frequency of sound from the source which is smaller to what he was hearing before stopping. hence

The pitch becomes lower

The amount of kinetic energy an object has can And is related to the objects And.

Answers

he kinetic energy of an object is the energy it has because of its motion. In Newtonian (classical) mechanics, which describes macroscopic objects moving at a small fraction of the speed of light, the kinetic energy ( E) of a massive body in motion can be calculated as half its mass ( m) times the square of its velocity.

To get a sample material from the mantle, drilling will be done through the oceanic crust rather than through the continental crust because oceanic crust it? Explain why?



1)younger than the continental drift.


2)more dense than continental crust.


3)thinner than the continental crust.


4)softer than continental crust.

Answers

To get a sample material from the mantle, drilling will be done through the oceanic crust rather than through the continental crust because oceanic crust is thinner than continental crust. Continental crust is  thicker than oceanic crust and  it is composed of granite. Oceanic crust is easily drilled.

oceanic crust is younger than continental crust but it does not provide any advantage in drilling so it is not a reason.

oceanic crust is more dense than continetal crust but it also not provide any advantage in drilling so it is not a reason



Answer:

Option (3)

Explanation:

The oceanic crust has a thickness of about 7 to 10 km on average, which is much thinner than the continental crust. In order to obtain the rock sample from the mantle, drilling must be done through the rocks of oceanic crust. It is because the depth from the seafloor up to mantle will be much lesser than the depth from the surface of the continental crust to the mantle.

It will require a comparatively lesser amount of money for excavation, in comparison to the drilling done from the continental surface.

Thus, drilling is more favorable to obtain mantle rocks from the oceanic crust.

Hence, the correct answer is option (3).

If mechanical energy is conserved in a system the energy at any point in time can be in the form of

Answers

potential, kinetic, elastc energies

The mechanical energy of the system at any point in time can be in the form of kinetic energy, potential energy, and elastic energy. These all are interconvertible, hence mechanical energy is conserved.

What is Mechanical Energy?

The term mechanical energy accounts for the total energy by the virtue of position as well as the motion of an object.

When an object is dropped from a certain height, then the mechanical energy of the object at any instant is given as the sum of kinetic energy and potential energy. The expression is given as,

ME = KE + PE

But at some point in time, the potential energy can be in the form of elastic energy as well. This energy is known as spring potential energy. Hence, the mechanical energy is conserved in a system at any point considering the forms like kinetic energy, potential energy, and elastic energy.

Thus, we can conclude that the mechanical energy of the system at any point in time can be in the form of kinetic energy, potential energy, and elastic energy. These all are interconvertible, hence mechanical energy is conserved.

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What force besides gravity would act on something that had been thrown in the air

Answers

Air resistance could be acting on the object

A model rocket weighing 4.9 N launches from a pad. How much work does the little rocket engine do in the first 4 meters

Answers

Answer:

 Work done by the little rocket engine = 19.6 Joules.

Explanation:

 We know that work = force x displacement.

 Force = weight of rocket = 4.9 N

 Displacement = 5 meter.

 So work done by the little rocket engine = Weight of rocket x displacement.

  Work done by the little rocket engine = 4.9 x 4 = 19.6 J

    Work done by the little rocket engine = 19.6 Joules.

During the operation of a laser, as photons interacts with atoms inside the laser the photons _________.

Answers

Final answer:

Photons in a laser induce stimulated emission in atoms, creating additional photons of the same frequency and phase, which results in coherent and monochromatic light.

Explanation:

During the operation of a laser, as photons interact with atoms inside the laser, the photons stimulate those atoms to emit additional photons through a process known as stimulated emission. The original and the newly created photons have the same frequency and phase, leading to coherent and monochromatic light. The photons are initially absorbed by the electrons in the atoms, which are then elevated to higher energy levels. Most of these electrons drop back to their ground state immediately, while some remain in a metastable state. A population inversion is created when more atoms are in the excited state than in the ground state. When a photon with the correct energy interacts with an electron in the metastable state, it triggers the emission of a second photon with the same energy, contributing to the coherence of the laser light. The laser light amplification is thus derived from the energy input, such as from a flash tube or an electrical discharge, leading to a cascade or chain reaction of photon production.

WILL GIVE BRAINLIEST PLEASE

1. An amount of heat equal to 10.5 x 105 J is supplied to 5 kg of water to raise its temperature from 25°C to 75°C. What is the specific heat capacity of water?

4.2 J/kg.°C

4200 J/kg.°C

1000 J/kg.°C

4200 kcal/kg.°C

2. What is the heat required in kilocalories to convert 2 kg of ice at 0°C completely into steam at 100°C?

80 Calories

1440 Calories

4186 Calories

540 Calories

3. How many kg of ice needs to be added to 1.31 kg of water at 64.9°C to cool the water to 14.9°C when the Latent heat of ice = 80 kcal/kg?

0.69

6.9

690

6900

4. 540 g of ice at 0°C is mixed with 540 g of water at 80°C. What is the final temperature of the mixture?

0°C

40°C

80°C

less than 0°C

5. If ∆Q is the heat supplied to a gas so that the internal energy of the system increases by ∆U, then the work done ∆W by the gas is equal to:

∆Q – ∆U

∆Q + ∆U

∆Q x ∆U

∆U/∆Q

6. The internal energy of the gas in a gasoline engine cylinder decreases by 210 J. If 60 J of work is done by the gas, the energy transferred as heat is:

270 J

150 J

-150 J

-270 J

7. A gaseous refrigerant undergoes compression over 160 J of work done on it. If the internal energy of the gas increases by 130 J, the amount of heat transfer is:

290 J

-290 J

30 J

-30 J

Answers

the amount of heat trader is

Explain why your senses would lead you to believe that the Earth is center of the universe

Answers

Answer:

This is due to the apparent movement of the celestial bodies, seen from an observer centered on the Earth. If we did not have knowledge of the advances of science and the latest discoveries, we would think that the Earth is the center of the universe.

For example, for an observer on Earth as a reference system, the Sun moves every day from east to west, as do the planets and all the stars that we observe at night, which leads the observer to believe that those in motion are these bodies outside in the sky while the earth is still and fixed in the universe.

Keep in mind that this theory of geocentrism was widely accepted for a long time in antiquity, until the astronomer Nicolaus Copernicus proposed a completely different and opposite idea, heliocentrism (universe centered on the Sun).

However, at present it is known and accepted that the universe has no center, that the Earth revolves around the Sun and that in reality all the bodies of the universe are in movement.

Final answer:

Our senses, based on our observational perspective, may lead us to believe that Earth is the center of the universe, a belief supported by the ancient geocentric model. The shift to the Copernican principle that positions the Sun at the center of the solar system challenged this perception. In reality, we are part of a vast universe and not at its center.

Explanation:

Our senses can lead us to believe that Earth is the center of the universe because our daily observations suggest so. From our vantage point, it appears as if the Sun, Moon, and stars revolve around us, making Earth feel central. This observation is attributed to the geocentric model heavily rooted in ancient astronomical models where Earth was considered the universal center and all celestial bodies moved in circular orbits around it.

However, this perception changed with the introduction of the Copernican principle, which redefined our understanding of celestial mechanics, positioning the Sun as the center of our solar system and not the Earth.

From everyday observation, it does seem like everything in the sky orbits the Earth. This perception is due to our positional perspective, not a reflection of the true cosmic order. The reality is that Earth orbits the Sun, and we are just one of many objects in the universe, not at its center.

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Does displacement = Δx?

Answers

Typically no. Displacement can be in multiple directions as a vector. of something is traveling only along x, then it would be true though this is usually not the case.

Displacement is the distance and direction from the start point to the end point.

If the motion starts and stops on the x-axis, then the displacement is equal to delta-x toward either the left or the right. But that would be rare and unusual.

. What is the relationship between potential energy, kinetic energy, and speed as the skater moves down and up the U-shaped ramp?

Answers

Top of the U ramp: potential energy is the highest, while kinetic energy is the lowest

Bottom of the U ramp(aka the curve part): potential energy is the lowest and the kinetic energy is the highest

THEREFORE, PE and KE have an INVERSE RELATIONSHIP.

They are in the inverse relationship between potential energy, and kinetic energy.

What is kinetic energy?

The energy of the body by the virtue of its motion is known as the kinetic energy of the body. It is defined as the product of half of mass and square of the velocity.

According to the law of conservation of energy, total energy is defined as the sum of kinetic energy and potential energy.

Total energy = kinetic energy+potential energy

At the top of the U ramp, potential energy is greatest, while kinetic energy is least. The potential energy is the lowest and the kinetic energy is the largest at the bottom of the U ramp.

Hence, PE and KE have an inverse relationship.

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As you hold book at rest in your hand two forces are being exerted on the book identify the force

Answers

gravity dwn, your hand up and equal to grav

Final answer:

When you hold a book at rest, two forces act upon it: the downward gravitational force exerted by the Earth represented as -14ĵ N and the upward force exerted by your hand that equals 14 N, balancing out the weight of the book. These forces cancel each other out, keeping the book at rest as per Newton's Second Law.

Explanation:

When you hold a book at rest in your hand, two primary forces are acting upon it. These are the gravitational force, which is the book's weight pulling it downwards, and the force exerted by your hand, pushing upwards against the book. The downward gravitational force is caused by the earth's mass attracting the book's mass. This force is represented as -14ĵ N in physics. The force exerted by your hand counters this gravitational pull, allowing the book to remain at rest in your hand.

By Newton's second law, since the book is at rest, the net force acting on the book is zero. Meaning, the gravitational force and the force exerted by your hand cancel each other out. This is represented as: FPH + FEH = 0, where FPH is the force exerted by your hand and FEH is the force exerted by the Earth. With proper calculation, the force exerted by your hand on the book equals 14 N in the upward direction, counteracting the book's weight.

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The picture above shows a football player kicking a football. This is known as two dimensional motion. In which direction does the football move?
A) vertical only (y)
B) horizontal only (x)
C) horizontal and vertical (x, y)
D) horizontal, vertical, and side to side (x, y, and z)

The diagram shows the motion of a tennis ball that has just been hit with a racket (air resistance is neglected). Which of these is true of the horizontal and vertical components of the ball’s velocity?
A) Both the horizontal and the vertical components are constant.
B) Both the horizontal and the vertical components are accelerated.
C) The horizontal component is constant but the vertical component is accelerated.
D) The horizontal component is accelerated but the vertical component is constant.

Answers

1. C) horizontal and vertical (x, y)

The picture shows the motion of a projectile, which consists of two separate motions along two different directions:

- horizontal (x): along this direction, the football has a uniform motion, with constant horizontal speed [tex]v_0 cos \theta[/tex],where [tex]v_0[/tex] is the magnitude of the initial velocity of the ball and [tex]\theta[/tex] the angle at which it has been thrown

- vertical (y): along this direction, the football has an accelerated motion, with initial vertical velocity [tex]v_0 sin \theta[/tex] upward and constant acceleration [tex]g=9.8 m/s^2[/tex] downward (acceleration due to gravity)


2. C) The horizontal component is constant but the vertical component is accelerated.

As described in the previous part of the exercise:

- along the horizontal direction there are no forces exerted on the ball, so it is a uniform motion, therefore the acceleration is zero and the horizontal component of the velocity is constant

- along the vertical direction there is one force acting on the ball (the force of gravity, which pushes downward), so there is an acceleration (downward) equals to [tex]g=9.8 m/s^2[/tex] and therefore the vertical component of the velocity is not constant.

In the diagram below, a student compresses the spring in a pop-up toy a distance of 0.020 m. If 0.068 J of energy are stored in the toy, what is the toy’s spring constant? a) 120 N/m b) 170 N/m c) 225 N/m d) 340 N/m

Answers

Answer: option d) 340 N/m

Explanation:

Energy stored in the spring of the toy,

[tex] E = \frac{1}{2}kx^2 = 0.068 J [/tex]  ( given)

Where, k is the spring constant and x is the length of the string after compression.

x = 0.020 m

Then spring constant, [tex]k = \frac{2E}{x^2}[/tex]

[tex]k = \frac{2\times 0.068 J}{(0.020 m)^2} = 340 N/m[/tex]

Thus, the spring constant of toy is 340 N/m. Correct option is d.

Please help me out! Thanks! (:
A physical quantity X depends on mass, distance, and time. Use dimensional analysis to decide which of these is a possible expression for X, where a is acceleration, v is velocity, and F is force.

A. X=1/2at²
B. X=at
C. X=Ft
D. X=vt

Answers

X=Ft is a possible equation for X because by using SI units its final term became Kg metre per second

The correct expression for a physical quantity depending on mass, distance, and time is C. X = Ft, as it has the dimensions MLT⁻¹ and includes all three: mass (M), distance (L), and time (T).

In order to determine which expression for a physical quantity X that depends on mass m, distance s, and time t, is possible using dimensional analysis, we examine the provided options. Using the dimensions given [m] = M, [s] = L, [v] = LT⁻¹, [a] = LT⁻², and [t] = T:

X = 1/2at² has dimensions of L( T⁻² )( T² ) = L which does not involve mass.

X = at has dimensions of L( T⁻² )( T ) = LT⁻¹ which is velocity, not involving mass.

X = Ft has dimensions of ( M LT⁻² )( T ) = MLT⁻¹ which represents impulse or momentum, and it involves mass, length, and time.

X = vt has dimensions of L( T⁻¹ )( T ) = L which is distance, but it does not involve mass.

The correct option that includes dimensions of mass, distance, and time is C. X = Ft which represents impulse or momentum.

The waters of a lake will be most layered in which season

A. winter
B. spring
C. summer
D. fall

Answers

Your answer is C) Summer

I think that the waters of a lake will be most layered in spring

11. A 3.8 kg object is lifted 12 meters. Approximately how much work is performed during the lifting?

Answers

Hope this answers your question!! Ask any help at anytime

Suppose that we look at a photograph of many galaxies. Assuming that all galaxies formed at about the same time, which galaxy in the picture is the youngest?
a. the one that is closest to us
b. the one that appears smallest in size
c. the one that is farthest away
d. the one that is bluest in color
e. the one that is reddest in color

Answers

A. The one that is closet to us

A 1.5m wire carries a 6 A current when a potential difference of 68 V is applied. What is the resistance of the wire?

Answers

Answer:

[tex]11.3 \Omega[/tex]

Explanation:

We can find the resistance of the wire by using Ohm's law:

[tex]V=RI[/tex]

where

V is the voltage applied

R is the resistance

I is the current

In this problem, we know I = 6 A and V = 68 V, so we can re-arrange the equation to find the resistance of the wire:

[tex]R=\frac{V}{I}=\frac{68 V}{6 A}=11.3 \Omega[/tex]

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