Answers
because it is square, meaning the width and height are the same, so therefore the width is also 4. to get the area of a square of rectangle, you times the width by the height. 4 × 4 = 16. so the answer is 16m² because the unit is metre so we write m²
Related Questions
Find the area of the shaded region. Thanks!
Answers
now, let's rationalize the denominator for "r" first.
also notice, that section is just 1/4 of the area of that circle, so, let's just find the area of the whole circle with that "r", get one-quarter of it, and subtract it from the half of the area of the square.
[tex]\bf r=\cfrac{8}{\sqrt{2}}\cdot \cfrac{\sqrt{2}}{\sqrt{2}}\implies r=\cfrac{8\sqrt{2}}{2}\implies \boxed{r=4\sqrt{2}} \\\\\\ \stackrel{\textit{area of that circle}}{A=\pi (4\sqrt{2})^2}\implies A=\pi (16\cdot 2)\implies A=32\pi \\\\\\ \textit{how much is one-quarter of that?}\quad \cfrac{32\pi }{4}\implies \boxed{8\pi }\\\\ -------------------------------\\\\[/tex]
[tex]\bf \stackrel{\textit{area of the square}}{A=8\cdot 8}\implies A=64\qquad \stackrel{\textit{half of that square's area}}{32}\\\\ -------------------------------\\\\ \textit{shaded region}\implies \stackrel{\stackrel{\textit{half of that square}}{area}}{32}~~-~~\stackrel{\stackrel{\textit{one-quarter of the circle}}{area}}{8\pi }[/tex]
Answer:
-8π + 32
6.8675
Step-by-step explanation:
So we know that the are of the square is 64, and we know that the equation for the are of the shaded region is Area of square - 1/4 area of circle with a radius of 4√2 - area of 90/45/45 triangle with side lengths of 8 and 8.
s = square area
c = circle area
t = triangle area
∆ = shaded region area
∆ = s - 1/4c - t
input the numbers that we have for those variables:
∆ = 64 - 1/4(100.53) - 32
∆ = 64 - 25.1325 - 32
∆ = 32 - 25.1325
shade region approximate ≈ 6.8675
or to get an exact answer in terms of pi
∆ = 64 - 1/4(32π) - 32
∆ = 32 - 8π
shaded region = -8π + 32
just added this because it is hard to pick out the actual answer in the other person's answer.
The sum of two integers is 28, and their product is 192. what are the two integers?
Answers
The product of 12 and 16 is 192, and the sum is 28.
a line that passes through two sides of triangles divides the sides proportionally
A. always
B. sometimes
C. never
Answers
How do I simplify ((3x^2+12x+12)/(2x^2+x-6))/((4x^2-9)/(3x^3+x^2-10))
Answers
[tex]= \dfrac{3(x + 2)^2}{(2x - 3)(x + 2)} \times \dfrac {3x^3+x^2-10} {(2x + 3)(2x - 3)} } [/tex]
[tex]= \dfrac{3(x + 2)}{2x - 3} \times \dfrac {3x^3+x^2-10} {(2x + 3)(2x - 3)} } [/tex]
[tex]= \dfrac{3(x + 2)(3x^3+x^2-10) }{(2x - 3)^2(2x + 3)} [/tex]
If $5000 is invested at 7.8% interest compounded monthly, how much would you have after 54 months?
Answers
5000 x (1+0.078/12)^54
5000 x (1.0065)^54
$7094.37
For what values of x and y must each figure be a parallelogram?
Answers
(6x - 180)° = 180°
6x = 360°
x = 60°
5(60)-180= 300-180=120°
What is the length of the hypotenuse of 385.7 and 321.84?
Answers
Pythagorean theorem: 385.7^2 + 321.84^2=hypotenuse^2
hypotenuse=502.34
Let p: The shape is a rhombus. Let q: The diagonals are perpendicular. Let r: The sides are congruent. Which represents "The shape is a rhombus if and only if the diagonals are perpendicular and the sides are congruent”?
Answers
"if and only if" is represented using the biconditional logic operator (↔) and "and" is represented using the logical conjuction operator (∧).
Therefore, "The shape is a rhombus if and only if the diagonals are perpendicular and the sides are congruent” is represented by "p ↔ (q ∧ r)"
Answer:
C.)p ↔ (q ∧ r)
Step-by-step explanation:
I scored a 100 on my quiz
You give up a full time salary of 45,000 a year to go to school for 2 years the total cost of going to school is 30,000, if want to be able to recover your investment in 5 years or less what is the minimum salary you would need to earn upon earning your degree?
Answers
I would say that this person has lost out on 2 years salary while in school plus 5 year repayment period. Total amount divided over 5 years is:
( (2+5)(45,000) + 30,000 ) / 5 =
(7(45,000)+30,00)/5 = 69,000 salary
Answer:
69,000
Step-by-step explanation:
Given,
There is loss of 45,000 per year for two years,
So, the total lost = 2 × 45000 = 90,000
Also, the cost of school going = 30,000
∴ the total recovering amount = 90,000 + 30,000 = 120,000
If this amount must recover in 5 years or less than 5,
Then, the minimum recovering amount per year = [tex]\frac{120000}{5}[/tex] = 24,000
Now, the original salary per year = 45,000
Hence, the new salary per year = original salary + recovering amount
= 45,000 + 24,000
= 69,000
Which is harder linear algebra or abstract algebra?
Answers
Linear algebra
I've always had trouble with graphs and it's much better if the algebra is similar to arthemetic
Please help thank you.
30 points.
Answers
The sum of all angles with a polygon with n sides is
180(n-2)
We have 20 sides.
180(20 -2) = 180 * 18
= 3240
Thus, the sum of all angles is 3240 degrees.
The second choice is your answer.
Question 2:
First, let's calculate the sum of all the angles.
180(12 - 2) = 1800
Now, divide that by the number of sides to get the measure of one angle.
1800/12 = 150
Your answer is the last choice.
Question 3:
Do the same as we did in question 2, but instead of 12 sides, there are 6 sides.
A regular hexagon has an interior angle measure of 120 degrees.
(Note: you should remember that for future reference).
Now, let's form the following equation
3x = 120
Divide both sides by 3
x = 40
The first choice is your answer.
Have an awesome day! :)
1. 3240. 20 gon is called an isogon
2.150 because the formula for the interior angle or regular polynomials is [tex] \frac{180(n-2)}{n}[/tex]
3.3x = 120
Divide both sides by 3
x = 40
The table below represents ordered pairs of a function. Which change could be made so that the relation in the table is no longer a function
Answers
which graph shows the inequality y>-2
Answers
the image from reflecting a figure in the third quadrant over the x-axis
Answers
Therefore, the image from refrecting a figure in the third quadrant over the x-axis is in the second quadrant.
The table below represents the atmospheric temperature at a location as a function of the altitude:
Altitude
(in thousand feet)
x
15
20
25
30
Temperature
(in °C)
f (x)
4
−6
−16
−26
The average rate of change of the function between x = 15 to x = 25 is ___degrees Celsius per thousand feet and represents the rate of change of temperature per thousand feet.
Answers
from x15 to x 25 is 4 - -16 = -20 degree change
25 -15 = 10000 feet
-20/10 = -2 degrees every 1000 feet
Answer: The average rate of change of the function between x = 15 to x = 25 is -2 degrees Celsius per thousand feet and represents the rate of change of temperature per thousand feet.
Step-by-step explanation:
The average rate of change of a function y=f(x) from [tex]x_1\ to\ x_2[/tex]is given by :-
[tex]k=\frac{f(x_2)-f(x_1)}{x_2-x_1}=\frac{-6-4}{20-15}[/tex]
Now, by the given table the average rate of change of the function between x = 15 to x = 25 will be :_
[tex]k=\frac{-16-4}{25-15}=\frac{-20}{10}=-2[/tex]
Hence, the average rate of change of the function between x = 15 to x = 25 is -2 degrees Celsius per thousand feet and represents the rate of change of temperature per thousand feet.
Can someone how to get the answer? Thanks! PLEASE HELPpppppppppppppppppppppppp
Answers
[tex]\mathrm{Apply\:log\:rule}:\ \log _a\left(x^b\right)=b\cdot \log _a\left(x\right) \ \textgreater \ \ln \left(6^x\right)=x\ln \left(6\right) [/tex]
[tex]x\ln \left(6\right)=\ln \left(21\right) \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}\ln \left(6\right) \ \textgreater \ \frac{x\ln \left(6\right)}{\ln \left(6\right)}=\frac{\ln \left(21\right)}{\ln \left(6\right)} [/tex]
[tex]Therefore \: x=\frac{\ln \left(21\right)}{\ln \left(6\right)}[/tex]
In your case ln means [tex] \frac{log 21}{log 6} [/tex]
after that you press (ALPHA) (L) which iOS the button for the parenthesis (. ). )
find LOG and then plug in the number you want.
repeat this until you get the equation you want.
The product of two consecutive even integers is 80. find all such pairs of integers
Answers
The possible pairs that fulfil the statement → "The product of two consecutive even integers is 80" are -
(8, 10)
(- 10, - 8)
What is Equation Modelling?
Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.
Given product of two consecutive even integers is 80.
Assume that the first integer is [n]. Then the second integer will be [n + 2]. According to the question, we can write -
n x (n + 2) = 80
n² + 2n = 80
n² + 2n - 80 = 0
n² + 10n - 8n - 80 = 0
n(n + 10) - 8(n + 10)
(n - 8)(n + 10) = 0
n = 8 and n = - 10
If → n = 8 then (n + 2) = 10.
If → n = - 10 then (n + 2) = -8.
Therefore, the possible pairs that fulfil the statement → "The product of two consecutive even integers is 80" are -
(8, 10)
(- 10, - 8)
To solve more questions on equation modelling, visit the link below-
https://brainly.com/question/17965009
#SPJ5
Final answer:
The consecutive even integers whose product is 80 are 8 and 10. This is found by setting up an equation for consecutive even integers and factoring the number 80.
Explanation:
The question is asking to find two consecutive even integers whose product is 80. When two numbers are consecutive even integers, they can be represented as n and n + 2, where n is an even integer. To find these numbers, we set up the equation n(n + 2) = 80.
First, we need to find two numbers that multiply to give 80. We can start by listing the factors of 80: 1 x 80, 2 x 40, 4 x 20, 5 x 16, 8 x 10. Since we are looking for even integers, we pick the pairs where both numbers are even: 4 x 20, 8 x 10. However, the numbers must also be consecutive even integers, which is the case for the pair 8 and 10, but not for 4 and 20.
Therefore, the pair of consecutive even integers that multiply to give 80 are 8 and 10.
Difference of two numbers is 8. find the smallest possible product.
Answers
The vertex of the graph of a quadratic function is (–2, –9) and the y-intercept is (0, –5). Which of the following is the equation of the function? A. y = x2 +10x + 2 B. y = x2 +10x – 2 C. y = x2 – 2x – 5 D. y = x2 + 4x – 5
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write an equation for the line that passes through (2,-5) and is parallel to 3x+4y=8
Answers
4y = -3x + 8; slope = -3
parallel lines, slope is the same so slope = -3
passes through (2,-5)
y = mx + b
b = y - mx
b = -5 - (-3)(2)
b = -5 + 6
b = 1
equation
y = -3x +1
hope it helps
The equation of the line which is parallel to the line 3x+4y=8 and passes through the point (2,-5) is y = -3/4x - 1/2.
Explanation:The given equation is 3x+4y=8, which is a linear equation. To make this simpler, we can isolate 'y' to make it in the form 'y = mx + b', where 'm' is the slope. When we do this, we get y = -3/4x + 2, so the slope of this line is -3/4.
Next, we know that parallel lines have the same slope. Therefore, the equation of the line parallel to the given line and passing through (2, -5) will also have a slope of -3/4. Using the point-slope form of a line, which is y – y1 = m(x – x1), where (x1, y1) is a point on the line, and 'm' is the slope, we can substitute the given values.
Therefore, y - (-5) = -3/4(x - 2), simplifying this gives us the equation of our line: y = -3/4x - 1/2.
Learn more about Equation of linehttps://brainly.com/question/7150168
[02.05]
Solve for x: 4 − (x + 2) < −3(x + 4) (1 point)
x < −7
x > −7
x < −9
x > −9
Answers
4-x-2<-3x-12 => 2-x<-3x-12
next, eliminate x on one side. here I'll eliminate -3x by adding 3x on both side:
2+2x<-12
2x<-14
x<-7
Option A
x<-7
Given :
[tex]4 - (x + 2) < -3(x + 4)[/tex]
Explanation :
Solve the given inequality for x by applying algebraic properties
We use order of operation to simplify the left and right side of inequality
[tex]4- (x + 2) < -3(x + 4)\\4-x-2<-3x-12\\-x+2 < -3x -12\\Add\; 3x \; on \; both \; sides\\2x+2<-12\\Subtract\; 2\; from \; both \; sides\\2x<-14\\Divide \; both \; sides \; by 2\\x<-7[/tex]
Learn more : brainly.com/question/13653788
Two months ago, the mean daily rainfall in a local city was 9.4 cm. The mean absolute deviation was 3.5 cm. Last month, the mean daily rainfall in that city was 11.5 cm, and the mean absolute deviation was 1.6 cm.
Which statement about the rainfall is true?
More rain fell two months ago than last month.
About the same amount of rain fell two months ago as last month.
Last month, the amount of rain that fell each day varied about the same as the month before.
Last month, the amount of rain that fell each day varied less than the month before.
Answers
Answer:
C
Step-by-step explanation:
Last month, more rain fell compared to two months ago, and there was less variation in the daily rainfall.
Explanation:To determine whether more rain fell two months ago or last month, we need to compare the mean daily rainfall and the mean absolute deviation for both months. Two months ago, the mean daily rainfall was 9.4 cm with a mean absolute deviation of 3.5 cm. Last month, the mean daily rainfall was 11.5 cm with a mean absolute deviation of 1.6 cm.
Thus, based on this information, we can conclude that more rain fell last month. The mean daily rainfall was higher and the mean absolute deviation was lower. This indicates that there was less variation in the amount of rain that fell each day last month compared to two months ago.
I have a graphing question
Answers
[tex](y-y_1)=m(x-x_1)[/tex]
where [tex](x_1,\ y_1)[/tex] is a point on the line.
Given
[tex]y-3=\frac{3}{4}(x+2) \\ \\ y-3=\frac{3}{4}(x-(-2))[/tex]
Thus the line has a slope of 3/4 and passes through the point (-2, 3), we can obtain another point on the line by substituting an arbitrary value for x.
Consider x = 2, then
[tex]y-3= \frac{3}{4} (2+2)= \frac{3}{4} (4)=3 \\ \\ \Rightarrow y=3+3=6[/tex]
Thus another point on the line is (2, 6).
The line can then be graphed by joining the two points.
Find the quotient of 3 2/5 and 3 2/6. Express your answer in simplest form.
Answers
Which graph represents the solution set of the system of inequalities?
Answers
(see image)
bottom right image
Explanation:
First try the origin (0,0) to rule out two of the graphs.
3y ≥ x - 9
3(0) ≥ (0) - 9
3 ≥ - 9 yes
3x + y > - 3
3(0) + (0) > - 3
3 > - 3 yes
so the origin should be in the shaded area of the graph, which rules out the top right and bottom left graphs.
Now try a coordinate that is in the shaded area of one of the remaining graphs, but not in the other one. If it works, the graph is the one that has that point in the shaded region, and vice versa.
Try point (4, 2)
3y ≥ x - 9
3(2) ≥ (4) - 9
6 ≥ - 5 yes
3x + y > - 3
3(4) + (2) > - 3
12 + 2 > - 3
14 > - 3 yes
So the graph is the bottom right one since (4, 2) is included in that shaded region.
Find the geometric mean of 6 and 7.
A. √42
B. 4√3
C. 7
D. 42
Please select the best answer from the choices provided.
Answers
The Arithmetic Mean: (this is the mean we are used to seeing)
[tex]m= \frac{a+b+c}{n} [/tex]
(n= number of variables, in this case n=3)
To Find the Geometric Mean of n #'s:
[tex]m_{geometric} = \sqrt[n]{a*b} [/tex]
(n= number of variables, in this case n=2)
So, using this information we can find the geometric mean of 6,7 by plugging them into the equation as "a" and "b". n=2 (when n=2 a square root can be used)[tex]m_{geometric} = \sqrt[n]{a*b}[/tex]
[tex]m_{geometric} = \sqrt{a*b} [/tex]
[tex]m_{geometric} = \sqrt{6*7} [/tex]
[tex]m_{geometric} = \sqrt{42} [/tex]
So the answer in this case is A.[tex] \sqrt{42} [/tex]
1. y and x have a proportional relationship, and y = 7 when x = 2. What is the value of x when y = 21?
2. y and x have a proportional relationship, and y = 9 when x = 2. What is the value of y when x = 3?
3.he table shows a proportional relationship.
x y
2 2.8
4 5.6
6 8.4
8 11.2
Complete the equation that represents the table.
Enter your answer as a decimal in the box. y = ____x
Answers
Answer: 6
Step-by-step explanation:
What is the mixed number for -10.125
Write in simplest form please!
Answers
Hope this helps!
the -10 is ur whole number...it stays ur whole number
the 0.125....the last digit (5) is in the thousandths place...so put it over 1000
-10 125/1000 reduces to -10 1/8 <==
Help please! I need to show my work
Answers
a.
PC is 2/3 of PY, and CY is 1/3 of PY.
If CY = 10, then PC = 20, and PY = 30
b.
If QC = 10, then ZC = 5, a nd ZQ = 15.
c.
X is the midpoint of side PQ.
PX = XQ = 1/2(PQ)
If PX = 20, PQ = 40
What is the equation of the line shown in this graph?
pls help
Answers
the line of the graph is vertical since both x coordinates are the same ( both are -2)
so the equation would be x = -2