100% - 30% = 70%
P = 0.7*900
which equals $630
Answer:
The net price of the stove is $630.
Step-by-step explanation:
The list price of a stove = $900
Trade discount on the price = 30%
The net price = 900 - (30% of 900)
= 900 - ([tex]\frac{30}{100}[/tex] × 900)
= 900 - (0.30 × 900)
= 900 - 270
= $630
The net price of the stove is $630.
A number a is a root of P(x) if and only if the remainder, when dividing the polynomial by x - a, equals zero.
A. True
B. False
Answer:
statement is true .
Step-by-step explanation:
Given : Statement A number a is a root of P(x) if and only if the remainder, when dividing the polynomial by x - a, equals zero.
To find : Statement is true or false.
Solution : By polynomial theorem if x-a divide the polynomial P(x) and we get reminder zero then a would be the factor.
Therefore, statement is true .
Answer:
true
Step-by-step explanation:
Find the difference. (-ab+8a-5)-(-8ab-4)
The momentum of a system before a collision is 2.4 × 103 kilogram meters/second in the x-direction and 3.5 × 103 kilogram meters/second in the y-direction. What is the magnitude of the resultant momentum after the collision if the collision is inelastic?
A. 1.7 × 103 kilogram meters/second
B. 2.1 × 103 kilogram meters/second
C. 3.4 × 103 kilogram meters/second
D. 4.2 × 103 kilogram meters/second
E. 5.7 × 103 kilogram meters/second ...?
Answer:
Option D - [tex]4.2\times 10^3[/tex] kilogram meters/second.
Step-by-step explanation:
Given : The momentum of a system before a collision is [tex]2.4 \times 10^3[/tex] kilogram meters/second in the x-direction and [tex]3.5 \times 10^3[/tex] kilogram meters/second in the y-direction.
To find : What is the magnitude of the resultant momentum after the collision if the collision is inelastic?
Solution :
In inelastic,
The magnitude of the resultant momentum after the collision (and before) can be determined by using the Pythagorean theorem.
[tex]c^2 = a^2 + b^2[/tex]
Where, a is the momentum before collision [tex]a=2.4 \times 10^3[/tex]
b is the momentum after collision [tex]b=3.5 \times 10^3[/tex]
c is the total amount of momentum before and after collision.
Substitute the value,
[tex]c^2 = (2.4\times10^3)^2 + (3.5\times10^3)^2[/tex]
[tex]c^2 =5760000+ 12250000[/tex]
[tex]c=\sqrt{18010000}[/tex]
[tex]c=4243.819[/tex]
[tex]c=4.2\times 10^3[/tex] kg m/s
Therefore, Option D is correct.
The magnitude of the resultant momentum after the collision if the collision is inelastic is [tex]4.2\times 10^3[/tex] kilogram meters/second.
Three fractions that are equivalent to:
12/36
4/5 and
3/12 ...?
"A 23kg kg child goes down a straight slide inclined 38∘ above horizontal. The child is acted on by his weight, the normal force from the slide, kinetic friction, and a horizontal rope exerting a 30N force as shown in the figure.(Figure 1)
How large is the normal force of the slide on the child?"
Force is simply the pull or push that acts on an object.
The normal force acting on the child is 159.12 N
The forces acting on the child are
The 30 N force at 38 degreesThe weight of the childThe weight of the child along the vertical component is:
[tex]\mathbf{Weight = mg \times cos(theta)}[/tex]
So, we have:
[tex]\mathbf{Weight = 23 \times 9.8 \times cos(38)}[/tex]
[tex]\mathbf{Weight = 177.62}[/tex]
The horizontal component of the 30 N force is:
[tex]\mathbf{F_2 = 30 \times sin (38)}[/tex]
So, we have:
[tex]\mathbf{F_2 = 18.50}[/tex]
The normal force (F) on the child is:
[tex]\mathbf{F = Weight - F_2}[/tex]
[tex]\mathbf{F = 177.62N - 18.50N}[/tex]
[tex]\mathbf{F = 159.12N}[/tex]
Hence, the normal force is 159.12 N
Read more about force at:
https://brainly.com/question/14311831
On a certain map 3/4 inch represents one mile, what distance, in miles is represented by 1 3/4 inches
The daily fat allowance is 70g, the dinner has 48g. What percentage of her total daily allowance of fat will the dinner be?
Is 4yards greater, less, or equal to 13feet
I need to solve this problem in my exam:
Suppose that the dollar cost of producing x radios is c(x) = 400 + 20x - 0.2x^2. Find the average cost per radio of producing the first 35 radios. ...?
what is the domain of this function p(w) 2/3w^9
...?
You have a fractions, so the only thing you must be sure of is that the denominator is not zero.
In your case, the denominator is given by the function f(w)=3w9. You need to find out the values of w for which f(w)=0. You have
f(w)=0⇔3w9=0⇔w9=0⇔w=9√0=0
So, your only problem is w=0, and all other numbers are fine.
Your domain is thus given by the set {x∈R∣x≠0}
The domain can also be written as (−∞,0)∪(0,+∞).
I included a photo with the information! Here are the questions. A thorough explanation and diagram would help IMMENSELY. Thank you so much!
Question 1: reate a labeled diagram of the Brick. Use x to represent the length of a side of the base of the candle. Then write an equation for the volume of the candle in terms of x. Write the polynomial in standard form.
Question 2: Create a labeled diagram of the Egyptian. Use x to represent the length of a side of the base of the candle. Then write an equation for the volume of the candle in terms of x. Write the polynomial in standard form.
Question 3: 1. To impress management, you decide to propose your own original candle design based on solid figures. Make your candle design attractive and make sure it will be practical to manufacture. Draw the candle in the space below and label the drawing with dimensions. Then write an equation for the volume of the candle in terms of x, where x is a dimension that defines the area of the candle’s base. Write the polynomial in standard form.
Answer:
1) Labeled diagram in the first figure attached
Volume of the rectangular prism: x^2*(x-1) = x^3 - x^2 ; x in cm, volume in cm^3
2) Labeled diagram in the second figure attached
Volume of the right square pyramid: (1/3)*(x^2)*21 = 7*x^2, x in cm, volume in cm^3
3) A cylinder is proposed, where x is the radius of the base and the height is 4 times the radius. Labeled diagram in the third figure attached .
Volume of the cylinder: π*x^2*(4*x) = 4*π*x^3, x in cm, volume in cm^3
The function f(x) is represented by the table below. What are the corresponding values of g(x) for the transformation g(x) = 4f(x)?
Whenever you sign a lease for an apartment, you typically have to pay a security deposit before you even move in; this is in case something happens while you are occupying the apartment and repairs have to be made. One apartment building has apartments that rent for $900 a month and a security deposit of $600. Write an equation to represent the situation described. F(x) = 600x + 900 F(x) = 600x - 900 F(x) = 900x - 600 F(x) = 900x + 600
A country's population in 1991 was 136 million. In 2000 it was 141 million. Estimate the population in 2016 using the exponential growth formula. Round your answer to the nearest million. ...?
Which of the following is not a cost of being financially irresponsible?
You are late to work because you forgot to set the alarm.
You have no money to pay the cable bill, but you have a new flat screen television.
You can't afford to go to the movies.
You end up paying more for things because of credit card interest.
help with 8th grade math! will upvote!! <33
Which of these is a simplified form of the equation 8p + 4 = − p + 7 + 2p + 3p?
A. 14p = 11
B. 8 = 4
C. 4p = 3
D. 12 = 13
$250 at 5% simple interest for 3 years
How many meters are in 7.2 kilometers?
The area of a rectangle is 48 square centimeters and the length of the rectangle is 8 centimeters longer than the width.
The area of a rectangle is found by multiplying the length times the width.
Which equation models this situation?
8w = 48
w + 8 = 48
w(w+8)=48w(w+8)=48
w + 8w = 48
How do you solve this one 10x^2-25=x^2
Which expression is equivalent to 3x(-4x^2+5x-8)-6(x^2-5x+7)?
A. 12x^3-9x^2+6x-42
B.-12x^3-54x^2+6x-42
C.-12x^3+9x^2+6x-42
D.-27x^3-6x^2+6x-42
f(x)=2x- 1 what is odd number
A car travels at 65 mph going through construcion it travels at 3/5 this speed write this fraction as a decimal an the find the speed
What is the length of arc AB if the radius is 14
In the function y=-2(x-1)^2+4, what effect does the number 4 have on the graph, as compared to the graph of the function y=x^2?
A. It shifts the graph 4 units to the right.
B. It shifts the graph down 4 units.
C. It shifts the graph up 4 units.
D. It shifts the graph 4 units to the left. In the function y=-2(x-1)^2+4, what effect does the number 4 have on the graph, as compared to the graph of the function y=x^2?
A. It shifts the graph 4 units to the right.
B. It shifts the graph down 4 units.
C. It shifts the graph up 4 units.
D. It shifts the graph 4 units to the left.
Answer:
it shifts the graph up four units
Step-by-step explanation:
it shifts the graph up four units because its outside of the phranthasies, in y=a(x+h)k k is the shift vertically
In the function y=-2(x-1)²+4, the number 4 represents a vertical translation, shifting the graph up by 4 units when compared to the function y=x². Option C) is the correct answer.
In the function y=-2(x-1)²+4, the number 4 acts as a vertical translation of the graph. Comparing this function to the standard parabola y=x², the addition of 4 to the equation represents shifting the entire graph of the parabola upwards by 4 units. Therefore, the correct answer to the effect of the number 4 on the graph, as compared to the graph of the function y=x² is: C. It shifts the graph up 4 units.
Understanding graph transformations is key in analyzing how different parts of the function equation affect the function's graphical representation.
A positive constant added to a function results in a vertical shift of the graph in the upward direction. This means that every point on the graph y=x² is moved 4 units higher on the y-axis to create the graph of y=-2(x-1)²+4.
Which graph best represents the solution to the following system?
5x - 2y < (less than or equal to) 10
x + y < 5
The graph that best represents the solution to the given system is:
Graph A.
Step-by-step explanation:We are given a system of inequalities as:
[tex]5x-2y\leq 10[/tex]
and [tex]x+y<5[/tex]
i.e. the graph of first inequality is a solid straight line( since the inequality is not strict) that passes through (2,0) and (0,-5) and the shaded region is towards the origin( since it passes the zero point test)whereas the graph of second inequality is a dotted straight line(since the inequality is strict) that passes through (0,5) and (5,0) and the shaded region is towards the origin( since it passes the zero-point test)Hence, the graph is:
Graph A.
Average speed of Car 1 = 35 mph. Average speed of Car 2 = 55 mph. Time elapsed between start of Car 1 and start of Car 2 = 18 minutes.
How long before Car 2 overtakes Car 1? ___________ hour.
Answer:
.525
Step-by-step explanation:
35(t+18/60) = 55t
35t +10.5 = 55t
10.5 = 20t
0.525 = t
One airplane is approaching an airport from the north at 124 km/hr. A second airplane approaches
from the east at 223 km/hr. Find the rate at which the distance between the planes changes when
the southbound plane is 34 km away from the airport and the westbound plane is 15 km from the
airport.
The distance between the planes is increasing at a rate of approximately 252 km/hr when the southbound plane is 34 km from the airport and the westbound plane is 15 km from the airport.
Explanation:Identify the relative motion: We need to find the rate of change of the distance between the planes, which is a relative motion problem.
Calculate individual velocities: Since the planes are approaching from different directions, we need to consider their velocities as vectors. The southbound plane has a southward velocity of 124 km/hr, and the westbound plane has an eastward velocity of 223 km/hr.
Apply Pythagorean theorem: At the given moment, the distance between the planes is the hypotenuse of a right triangle formed by their individual velocities. Using the Pythagorean theorem:
Distance^2 = Southbound velocity^2 + Westbound velocity^2
Distance^2 = (124 km/hr)^2 + (223 km/hr)^2
Distance ≈ 258.5 km
Differentiate distance equation: To find the rate of change of the distance, we need to differentiate the distance equation with respect to time. This gives us the relative velocity between the planes.
Calculate relative velocity: Taking the derivative of the distance equation and plugging in the individual velocities:
Rate of change of distance = (Southbound velocity * Eastward velocity) / Distance
Rate of change of distance ≈ (124 km/hr * 223 km/hr) / 258.5 km ≈ 252 km/hr
Therefore, the distance between the planes is increasing at a rate of approximately 252 km/hr when the southbound plane is 34 km from the airport and the westbound plane is 15 km from the airport.
Hue is 56in.tall. His friend is 42in.tall. Hue's shadow is 24in.long. How long is his friend's shadow at the same time?
By setting up a proportion based on the concept of similar triangles, we can solve for the length of Hue's friend's shadow, which is 18 inches.
Explanation:To find the length of Hue's friend's shadow, we can use the concept of similar triangles. The ratio of Hue's height to his shadow's length is the same as the ratio of his friend's height to his friend's shadow's length, assuming the sun's rays are parallel and create similar angles with respect to the ground for both individuals.
Hue's height to shadow length ratio is 56 inches to 24 inches. Let's denote the length of his friend's shadow as x inches. We can set up a proportion:
56 inches (Hue's height) / 24 inches (Hue's shadow) = 42 inches (friend's height) / x inches (friend's shadow)
Solving for x, we get: 56/24 = 42/x, which simplifies to x = (42 * 24)/56 = 18. Therefore, Hue's friend's shadow is 18 inches long.
assume 1 card is drawn from a standard deck of 52 cards.find the probability of drawing a 6 or a face card