Answer:
800
Step-by-step explanation:
Look at the tens if it's 0-4 keep the number the same if 5-9 go up one number
PLEASE MARK BRAINLIEST!
Answer:
832 --> ???
832 - we must round the underlined digit
832 --> ???
832 --> 800
The rounding rule is:
4 and below, stay down low! [Round down]. 5 and above, soar like a dove! [Round up].
So with that rule, 832 becomes 800.
800 is your answer.
I hope this helps!
A sandbox has an area of 26 square feet . The length is 6 1/2 feet. What is the width of the sandbox
Answer:
The width of the sandbox is 4 feet
Step-by-step explanation:
Area = Length x Width
Fill in known values
26 sq ft = 6.5 ft x w
Divide by 6.5 on both sides
4 ft = w
Width = 4 ft
:)
if 3 popsicles cost $5.25. at this rate how much would 1 popsicle cost?
A survey was given to residents of all 50 states asking
if they had earned a bachelor's degree or higher
The results from 7 of the states are given in the table
above. The median percent of residents who earned
a bachelor's degree or higher for all 50 states was
26.95%. What is the difference between the median
percent of residents who carned a bachelor's degree
or higher for these 7 states and the median for al
50 states!
Answer:
B.) 0.95%
Step-by-step explanation:
19.5, 21.9, 25.9, 27.9, 30.1, 35.5, 36.4
27.9 − 26.95 = 0.95
The difference is 0.95%
How to find the differenceThe data is given as 19.5, 21.9, 25.9, 27.9, 30.1, 35.5, 36.4
Organize the Data:
Arrange the percentages in ascending order:
19.5, 21.9, 25.9, 27.9, 30.1, 35.5, 36.4
Find the Median of the 7 States:
Since there are 7 data points, the median will be the 4th value.
Median = 27.9
Calculate the Median for All 50 States:
The median for all 50 states is given as 26.95%.
Find the Difference:
Difference = Median for all 50 states - Median for 7 states
Difference = 26.95 - 27.9
Difference = 0.95
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y=6x-7 and find the x intercept
Answer:
x-intercept
= 7/6
= 1.16667
A music player was marked down by 1/4 of the original price.
a. If the sales price is $128, what is the original price?
b. If the music player was marked up by 1/2 before it was placed on the sales floor, what was the price that the store paid for the player?
c. What is the difference between the discount price and the price that the store paid for the music player?
PLEASE SHOW ALL OF YOUR WORK! I NEED THIS ASAP! I WILL GIVE YOU BRAINLIEST! IF YOU SEND ME NONSENSE OR ANSWERS WITH NO WORK, I WILL REPORT YOU!!!! HAPPY NEW YEAR!!!!!!!!!!!
Answer:
A ) The Original price of music player before it was marked down by [tex]\dfrac{1}{4}[/tex] is $512
B ) The price that store paid for player is $256
C ) The difference between discount price and price paid by store is $128
Step-by-step explanation:
Given as :
A ) The sale price of music player = $128
The music player is marked down by [tex]\dfrac{1}{4}[/tex] of original price
Let The original price = $x
Now, According to question
[tex]\dfrac{1}{4}[/tex] of original price = $128
i.e [tex]\dfrac{1}{4}[/tex] × $x = $128
Or, x = 128 × 4
∴ x = $512
So, The Original price of music player before it was marked down by [tex]\dfrac{1}{4}[/tex] is $512
B ) The music player is marked up by [tex]\dfrac{1}{2}[/tex] before it was placed on sales floor .
Let The price that store paid for player = $y
Now, According to question
∵ The original price of player = $512
So, The price that store paid for player = [tex]\dfrac{1}{2}[/tex] × original price of player
i.e y = [tex]\dfrac{1}{2}[/tex] × $512
Or , y = $256
So,The price that store paid for player = $256
C ) Let The difference between discount price and price paid by store = $z
So, According to question
z = y - discount price
Or , z = $256 - $128
∴ z = $128
So, The difference = $128
Hence, A ) The Original price of music player before it was marked down by [tex]\dfrac{1}{4}[/tex] is $512
B ) The price that store paid for player is $256
C ) The difference between discount price and price paid by store is $128
Answer
In which of the following functions would it be appropiate to use only positve integers for the domain?Select all that apply.
Complete Question:
As you may have unintentionally forgotten to add the answer choices in your question, but I was able to find the complete the question and answering your question based on this as it may surely clear your concepts. Here is the complete question.
In which of the following functions would it be appropriate to use only positive integers for the domain? Select all that apply.
The function c(p) represents The cost for P people to attend the movies. The function m(t) represents the miles driven over T hours. The function t(m) represents the average high temperature for a given number of months. The function p(w) represents the prophet of a farmer who sells whole watermelons. The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.
Answer Explanation:
Domain is termed as all the input values on a certain interval that define the function.
Here are the appropriate function scenarios where it is appropriate to use only positive integers.
The function c(p) represents The cost for P people to attend the movies.
As the function c(p) contains people. And People are not counted as negative, although they can be zero. So, only positive integers should be appropriate to use in this scenario.
The function m(t) represents the miles driven over T hours
As the function m(t) contains miles. And miles are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.
The function t(m) represents the average high temperature for a given number of months.
As the function t(m) contains months. And months are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.
The function p(w) represents the prophet of a farmer who sells whole watermelons.
As the function p(w) contains the number of watermelons. And watermelons are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.
The function h(n) represents the number of person-hours it takes to assemble n engines in a factory.
As the function h(n) contains the number of engines. And engines are not counted as negative. They normally initiate with 1. So, only positive integers should be appropriate to use in this scenario.
Keywords: domain, function, positive integer
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If (3, 5) is a solution of both y= 4x + 7 and y=5, what is the solution of 4x + 7=5?
Answer:
Step-by-step explanation:
X=-1/2
Hope this helps mark me as brainiest pls
Yes, -1/2 will be the x-coordinate for the solution. We can also find the y-coordinate by subbing in -1/2 for x in the equation y=4x+7.
y=4(-1/2)+7
y=-2+7
y=5
The intersection point would be (-1/2,5).
Trevor Has $178 in his bank account at the start of the week. He makes one withdrawal during the week. At the end of the week, Trevor Gets a notice from the bank that he has a negative balance of -$62. Write and solve an equation to determine how much money Trevor Took out in his withdrawal.
the answer that is correct and shows work gets the crown! good luck and happy new year!
Answer:
Equation: 178 - x = - 62
Explanation:
Start of the wee: 178
One withdrawal: x
End of the week: -62
178 - x = -62
Simplify both sides of equation
178−x=−62
178+−x=−62
−x+178=−62
Subtract 178 from both sides
−x+178−178=−62−178
−x=−240
Divide both sides by -1
-x / -1 = -240 / -1
x=240
Trevor withdrew $240 from his bank account. This was calculated by setting up an equation with his initial positive balance and final negative balance, and solving for the withdrawal amount.
To determine how much money Trevor withdrew from his bank account, we can set up an equation representing the transactions in his account. Let x represent the amount of money withdrawn. We start with Trevor's initial balance, subtract the withdrawal, and set that equal to his final negative balance:
Initial balance - Withdrawal = Final balance
178 - x = -62
To solve for x, we add x to both sides to get the withdrawal amount on its own and then add 62 to both sides to isolate x:
178 - x + x = -62 + x
178 = x - 62
178 + 62 = x
240 = x
So, Trevor withdrew $240 from his bank account.
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Find the area. You answer will be a decimal.
_________ ft²
Answer:
26.4 ft^2 (1 d.p.)
Step-by-step explanation:
[tex]area \: of \: circle = \pi {r}^{2} [/tex]
Since it is given that r, the radius of the circle, is 2.9 ft,
area of circle= π(2.9)^2= 8.41π= 26.4 ft^2 (1 d.p.)
when is the following rational expression undefined? 6d-4
-------
d+2
Answer:
For [tex]d=-2[/tex] rational expression will be undefined.
Step-by-step explanation:
Given function is [tex]\frac{6d-4}{d+2}[/tex]
We need to find for what value of variable [tex]d[/tex] this rational expression will be undefined.
The rational expression will be undefined if the denominator of the expression will become zero.
So, let us plug denominator equal to zero.
[tex]d+2=0\\\\Subtracting\ both\ side\ 2\\\\d+2-2=-2\\\\d=-2[/tex]
Hence, this rational expression will be undefined if the value of variable [tex]d=-2[/tex].
B Jamal says that 18:12 and 3:4 are not equivalent ratios Margie says they are equivalent ratios who is correct
Answer:
Jamal is correct.
Step-by-step explanation:
3:4 is equivalent to 9:12, not 18:12.
We can see that for 3:4, the left side is less than the right, but for 18:12, left side is greater than the right, which immediately tells us the ratios are not equivalent.
Jamal is correct. 18:12 and 3:4 are not equivalent ratios.
Equivalent ratiosTo determine if two ratios are equivalent, you can simplify them to their simplest form or find a common factor that divides both terms. In this case:
18:12 can be simplified by dividing both terms by their greatest common factor, which is 6:
18 ÷ 6 = 3
12 ÷ 6 = 2
So, 18:12 simplifies to 3:2.
Now, compare it to 3:4. Since they have different values (3:2 vs. 3:4), Jamal's statement is incorrect, and Margie is right; they are not equivalent ratios.
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Is 6 15/28 or 6 5/9 bigger?
Answer:
[tex]6 \frac{5}{9} [/tex]
is greater than
[tex]6 \frac{15}{28} [/tex]
Answer:6 5/9 is greater than 6 15/28
Step-by-step explanation: positive proper fractions: 15/28, 5/9;
1 positive integer number: 6; Any positive proper fraction is smaller than
any positive integer number Sort the positive proper fractions:
15/28 and 5/9 15/28 already reduced to the lowest terms;
the numerator and the denominator have no common prime factors:
15 = 3 × 5;
28 = 22 × 7;
5/9 already reduced to the lowest terms;
the numerator and the denominator have no common prime factors:
5 is a prime number;
9 = 32; 15 = 3 × 5;
5 is a prime number;
Multiply all the unique prime factors, by the largest exponents:
LCM (15, 5) = 3 × 5 = 15 Divide LCM by the numerator of each fraction:
For fraction: 15/28 is 15 ÷ 15 = (3 × 5) ÷ (3 × 5) = 1;
For fraction: 5/9 is 15 ÷ 5 = (3 × 5) ÷ 5 = 3; Build up all the fractions to the same numerator (which is LCM).
Multiply the numerators and the denominators by their expanding number:
15/28 = (1 × 15)/(1 × 28) = 15/28;
5/9 = (3 × 5)/(3 × 9) = 15/27;
Which has the greatest value?
Answer:
f(6)
Step-by-step explanation:
Answer:
f(2)
Step-by-step explanation:
What is 6 to the power of “h” equal to 126
Answer:
6^h=126
Step-by-step explanation:
6 to the power of h is just 6^h
Plug it into an equation with =126
Boom you have the equation 6^h=126
identify the vertex for
f(x)=4x^2-8x-4
Answer:
Step-by-step explanation:
You could complete the square to do this, or you could just evaluate the h coordinate using the simple formula
[tex]h=-\frac{b}{2a}[/tex]
then find k by subbing that h value into the equation for x to find y which is the same as k. In our quadratic, a = 4, b = -8, and c = -4.
[tex]h=\frac{-(-8)}{2(4)}=1[/tex]
Now sub that value into the quadratic to find y (k):
[tex]4(1)^2-8(1)-4=4-8-4=-8[/tex]
The vertex of the quadratic is (1, -8)
The sum of two numbers is 278. One number is 52 more than the other number. What are the two numbers
Answer:
The numbers are 165 and 113
Step-by-step explanation:
Let
x ----> one number
y ----> the other number
we know that
[tex]x+y=278[/tex] ----> equation A
[tex]x=y+52[/tex] ----> equation B
substitute equation B in equation A
[tex](y+52)+y=278[/tex]
solve for y
[tex]2y=278-52[/tex]
[tex]2y=226[/tex]
[tex]y=113[/tex]
Find the value of x
[tex]x=y+52[/tex]
[tex]x=113+52=165[/tex]
therefore
The numbers are 165 and 113
If h is an angle bisector of the given isosceles triangle, what is the measure of ∠a if ∠c = 55°?
Answer:
[tex]\angle a=35^o[/tex]
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
An isosceles triangle has two equal sides and two equal interior angles
The angles opposite to the equal sides of an isosceles triangle are equal.
[tex]\angle b=\angle c[/tex]
we have
[tex]\angle c=55^o[/tex] -----> given problem
so
[tex]\angle b=55^o[/tex]
Remember that
The sum of the interior angles in any triangle must be equal to 180 degrees
[tex]\angle b+\angle c+2\angle a=180^o[/tex]
substitute the given values
[tex]55^o+55^o+2\angle a=180^o[/tex]
[tex]110^o+2\angle a=180^o[/tex]
[tex]2\angle a=180^o-110^o[/tex]
[tex]2\angle a=70^o[/tex]
[tex]\angle a=35^o[/tex]
Triangles ABC and DEF are similar.
I added in a photo...
Part 1: Find the lenght of segment DF (rounded to the nearest hundreth) _____ units.
Part 2: Find the lenght of segment EF (rounded to the nearest hundreth) _____units.
A triangle has an area of 52 square meters. and a height of 13 meters. Find the length of the base.
Answer:
Length of the base = 8
Step-by-step explanation:
Area of a triangle = 1/2(h*b)
h = height
b = base
52 = 1/2 (13 * b)
Rearrange the equation to get b on it's own
52 * 2 = 13 * b
104 = 13 * b
104/13 = b
b = 8
A = 1/2(bh)
in this case, b = 2a/h. plug in the values:
steps
b = 2a/h
b = 2(52)/13
b = 104/13
b = 8 meters
A.
discrete
B.
continuous
C.
linear
D.
nonlinear
E.
increasing
F.
decreasing
G.
both increasing and decreasing
H.
neither increasing nor decreasing
1. Simplify f(g(x)) in terms of x if f(x) = x² - 1 and g(x) = 2 x + 3.
In this question, you're plugging in g(x) into f(x) to simplify.
You would plug the g(x) equation into the x variable in the f(x) equation.
Plug g(x) into f(x):
(2x+3)² - 1
Solve:
(2x+3)² - 1
Use FOIL:
F = First
O = Outsides
I = Insides
L = Last
4x² + 12x + 9 - 1
Combine like terms:
4x² + 12x + 8
Answer:
4x² + 12x + 8
2m- -3m + -15 =20 solve for m
Answer:
m=7
Step-by-step explanation:
2m-(-3m)+(-15)=20
2m+3m-15=20
5m-15=20
5m=20+15
5m=35
m=35/5
m=7
Which number is greatest?
2.89 x 10^-8
1.997 x 10^2
8.9×10^-6.
5×10^-6
Answer:
1.997 x 10²
Step-by-step explanation:
The number with the highest exponent is the greatest value.
10² is bigger than 10⁻⁶ and 10⁻⁸, so 1.997 x 10² is your answer.
3k-k+5k-7=7 solve for k
Answer:
k=2
Step-by-step explanation:
3k-k+5k-7=7
2k+5k=7+7
7k=14
k=14/7
k=2
Answer:
[tex] \: \: \: \: \: \: \: \: 3k - k + 5k - 7 = 7 \\ = > 8k - k = 7 + 7 \\ = > 7k = 14 \\ = > k = \frac{14}{7} \\ = > k = 2[/tex]
Which coordinate grid shows Point A at (0.75, −1.50)?
Answer:
Very bottom graph
Step-by-step explanation:
Go .75 units right (positive x) then go 1.5 units down (negative y)
Answer:
Your answer will be D.
Step-by-step explanation:
Coordinate grid shown from negative 2 to positive 2 on the x-axis and negative 2 to positive 2 on the y-axis in increments of 1 over 4. Only the whole numbers are labeled. A point A is shown at the intersection of 3 grid lines to the right of the y-axis and 6 grid lines below the x-axis.
can you help find the quotient for 4/5 ÷ 10
Answer:
2/25
Step-by-step explanation:
Answer:
0.08
Step-by-step explanation:
Find the distance from the point (-6,8) to the line y=-3x+10. Round distance to nearest hundredths.
The distance from the point (-6,8) to the line y=-3x+10 is calculated using the distance formula which yields a value of approximately 6.32, when rounded to the nearest hundredths.
Explanation:The subject of this question is mathematics, specifically it pertains to finding the distance between a point and a line. The distance between a point (x1, y1) and a line ax + by + c = 0 can be calculated using the formula: distance = |ax1 + by1 + c|/sqrt(a²+b²). In your case, the given point is (-6,8) and the line is y = -3x + 10, which can be rewritten as 3x + y - 10 = 0. Therefore, a = 3, b = 1, c = -10, x1 = -6, and y1 = 8.
Substituting these values into the distance formula: distance = |3*(-6) + 1*(8) - 10|/sqrt((3)² + (1)²) = |-18 + 8 - 10|/sqrt(10) = |-20|/sqrt(10) = 20/sqrt(10) = 6.32, rounded to the nearest hundredths.
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Tammi deposited $520 into a bank account that earned simple interest each year. After 5 years, she had earned $156 in interest.
If no money was deposited into or withdrawn from the account, what was the annual interest rate?
Enter your answer in the box.
% / new questoin Gloria deposited $500 into a bank account that earned 7.5% simple interest each year. She earned $225 in interest before closing the account.
If no money was deposited into or withdrawn from the account, for how many years was the money in the account?
Round your answer to the nearest whole year.
Enter your answer in the box.
years
Answer:
For Tammi it is 6% interest Rate.
For Gloria it is 6 Years.
Step-by-step explanation:
Tammi:
Principal = $520
Time = 5 Years
Interest = $156
Interest Rate = Interest / (Principal x Time)
Interest Rate = $156 / ($520 x 5)
Interest Rate = $156 / $2,600
Interest Rate = 0.06
Hence Interest Rate is 6%
Gloria:
Principal = $500
Interest Rate = 7.5%
Interest = $225
Time = Interest / (Principal x Interest Rate)
Time = $225 / ($500 x 0.075)
Time = $225 / $37.5
Time = 6 Years
Hence it will take 6 Years
Answer:
6%
Step-by-step explanation:
We did percent and converting problems in class and we've been doing it since yesterday.
I hope this helps!
Please Help!!!! Give me your own real life scenarion using an inequality thanks so much :)
Scenario:
Tony has $727.29 in his checking account. He must maintain a $500 balance to avoid a fee. He wrote a check for $248.50 today. Write an inequality that would be used to solve for the least amount of money he needs to deposit to avoid a fee.
Equation:
727.29 − 248.50 + x ≥ 500
Answer:
x ≥ 21.21
In which quadrant or on which axis would you find the point B(-8,0)?
Answer:
The x-axis, it would be between quadrant 2 and quadrant 3