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The number of partial products in multiplication is determined by the number of digits in the multiplier.

In multiplication, the number of partial products is determined by the number of digits in the multiplier. In part a, there are three digits in the multiplier, so there are three partial products. Each partial product represents the product of a digit in the multiplier and the multiplicand. In part b, there are only two digits in the multiplier, so there are only two partial products.

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The number 48 is 30 percent of the number 160.

We have to find 30% of what number is 48.

let the unknown number be x.

so, we can set up the equation as

30% of x= 48

30/100 x = 48

30x = 4800

Divide both side by 30

30x/30= 4800/ 30

Now, simplify

x= 120

Thus, 48 is 30% of 160.

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Answer:

13/20

Step-by-step explanation:

1

4

+

2

5

=  

1 × 5

4 × 5

+

2 × 4

5 × 4

=  

5

20

+

8

20

=  

5 + 8

20

=  

13

20

hope this helps

Answer:

c)9x11=99

Step-by-step explanation:

Answer: A. 45 miles per hour

B. 135 miles

Step-by-step explanation:

Given: The distance traveled by a car at a constant rate is proportional to the time spent driving.

In the equation [tex]d=45t[/tex], d represents the distance (in miles) and t represents the time (in hours).

[tex]\Rightarrow\frac{d}{t}=45\text{ miles per hour}[/tex]

⇒ The constant of proportionality=45 miles per hour.

Also, the distance traveled by car in 1 hour=45 miles

⇒ The distance traveled by car in 3 hours=[tex]3\times45=135\text{ miles}[/tex]

∴ A car will travel 135 hours in 3 hours.

⁷/₁₀ kg

Given:

Question:

How many kilograms of cherries did they buy altogether?

The Process:

Since Linda bought [tex]\frac{1}{10} \ kg[/tex] of cherries less than Tiffany, we subtract [tex]\frac{1}{10} \ kg[/tex] from the [tex]\frac{2}{5} \ kg[/tex] of cherries Tiffany bought.

The least common multiple (LCM) of 5 and 10 is 10.

[tex]\boxed{ \ \frac{2}{5} - \frac{1}{10} = ? \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{2 \times 2}{5 \times 2} \bigg) - \frac{1}{10} \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{4}{10} \bigg) - \frac{1}{10} \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{3}{10} \ }[/tex]

Therefore, Linda bought [tex]\frac{3}{10} \ kg[/tex] of cherries.

Let us find out how many kilograms of cherries did they buy altogether.

[tex]\boxed{ \ Tiffany's cherries + Linda's cherries =? \ }[/tex]

[tex]\boxed{ \ \frac{2}{5} + \frac{3}{10} = ? \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{2 \times 2}{5 \times 2} \bigg) + \frac{3}{10} \ }[/tex]

[tex]\boxed{ \ = \bigg( \frac{4}{10} \bigg) + \frac{3}{10} \ }[/tex]

[tex]\boxed{\boxed{ \ = \bigg( \frac{7}{10} \ }}[/tex]

Thus, they bought [tex]\frac{7}{10} \ kg[/tex] of cherries altogether.

- - - - - - - - -

Using Diagram

[tex]\boxed{Tiffany's cherries: \frac{2}{5} = \frac{4}{10}}[/tex]

[tex]Tiffany's cherries: \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex] or 4 of 10 units.

[tex]\boxed{Linda's cherries = \frac{1}{10}}[/tex] less than Tiffany's, so we subtract 1 from 4 units of Tiffany's, that is [tex]\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex]

[tex]\boxed{ \ Tiffany's cherries + Linda's cherries =? \ }[/tex]

[tex]\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ} + \boxed{\circ}\boxed{\circ}\boxed{\circ} = \boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}\boxed{\circ}[/tex]

Thus, the number of the two diagrams is 7 out of 10 units or [tex]\frac{7}{10} \ kg[/tex] of cherries.

Keywords: Tiffany, bought, 2/5, kg of cherries, Linda, 1/10, less than, how many, kilograms, they buy altogether, 3/10, 7/10, LCM

Mr. Evans can ship approximately 70 freezers in the container.

To determine how many freezers can be shipped in the container, we first need to calculate the total weight of the ovens and then subtract it from the maximum weight the container can hold.

Given:

- Maximum weight the container can hold = 42,000 pounds

- Number of ovens = 90

- Weight of each freezer = 600 pounds

First, we need to calculate the total weight of the ovens:

Total weight of ovens = Number of ovens × Weight of each oven

Total weight of ovens = 90 ovens × 0 pounds = 0 pounds

Now, we subtract the total weight of the ovens from the maximum weight the container can hold to find the remaining weight for the freezers:

Remaining weight for freezers = Maximum weight of container - Total weight of ovens

Remaining weight for freezers = 42,000 pounds - 0 pounds

Remaining weight for freezers = 42,000 pounds

Now, we need to find out how many freezers can be shipped in the container. Since each freezer weighs 600 pounds, we divide the remaining weight for freezers by the weight of each freezer:

Number of freezers = Remaining weight for freezers / Weight of each freezer

Number of freezers = 42,000 pounds / 600 pounds

Number of freezers ≈ 70

So, Mr. Evans can ship approximately 70 freezers in the container.

To find the reduction in Kerrin's weight as a percentage of his initial weight, we convert the weights to pounds, find the weight difference, then this difference is divided by the initial weight and multiplied by 100. Kerrin lost about 7.41% of his initial weight.

To calculate the reduction in Kerrin's weight as a percentage of his initial weight, we first need to convert the weights from stones and pounds into just pounds. At the start of the diet, Kerrin weighed 13 stone 9 pounds. As there are 14 pounds in a stone, this equates to (13 x 14) + 9 = 189 pounds. Three months later, he weighed 12 stone 7 pounds which equates to (12 x 14) + 7 = 175 pounds.

The total amount of weight lost is then calculated by subtracting his later weight from his starting weight which gives us 189 - 175 = 14 pounds. The change in weight as a percentage of the initial weight can then be calculated by dividing the weight difference by the initial weight, then multiply the result by 100 to give the percentage. The resulting calculation is (14 / 189) x 100 = 7.407407407407407 which is approximately 7.41%. Therefore, Kerrin lost about 7.41% of his initial weight after three months on the diet.

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The answer is B. Hope this helped