simplify sqaure root - 72

Answers

Answer 1

Answer:

[tex]\boxed{6\sqrt{2 i}}[/tex]

Explanation:

[tex]\sqrt{-72}=\sqrt{-1}=\sqrt{72}[/tex]

[tex]\sqrt{-1} \sqrt{72}[/tex]

Then you apply imaginary number rule.

[tex]\sqrt{72 i }[/tex]

[tex]\sqrt{72}=6\sqrt{2}[/tex]

[tex]\boxed{6\sqrt{2 i}}\checkmark[/tex], which is our final answer.

Hope this helps!

Thanks!

Have a nice day! :)

-Charlie

Answer 2

Explanation on how to simplify the square root of a negative number.

Simplify the square root of -72: To simplify the square root of a negative number like -72, first rewrite it as the square root of 72 times the square root of -1. The square root of 72 can be simplified as 6√2, making the final answer 6i√2.


Related Questions

what is the simplified form of 7 √x • 7 √x • 7 √x • 7 √x?

Answers

Answer:

2401 • x^2

Step-by-step explanation:

7 √x7 √x • 7 √x • 7

=(7)^4  (√x)^4

=2401 • x^2

Intercepts of x-2y=2

Answers

There would be 2 intercepts, the X and the Y.

To find the X intercept, set Y to 0 and solve for x.

To find the Y intercept, set X to 0 and solve for y.

x -2y = 2

x-2(0) = 2

x-0 = 2

x = 2

0 -2y = 2

-2y=2

y = 2/-2

y = -1

The x intercept is (2,0)

The y intercept is (0,-1)

Not sure what format you need the answer in, you may only need x = 2 and y = -1.

Which equation is true for the value b = 2?
OA. 2b + 24 = 30
B. 3b - 2 = 4
C.b + 4 = 8
D.2b - 3 = 0​

Answers

C is the correct answer

Answer:

B. 3b - 2 = 4.

Step-by-step explanation:

Let us check each equation by plugging in the value of b = 2 to see if it is true.

A. 2 × 2 + 24 = 4 + 24 = 28.

28 ≠ 30 . So A is not true.

B. 3 × 2 - 2 = 6 - 2 = 4.

4 = 4. B is true!

C. 2 + 4 = 6.

6 ≠ 8. C is not true.

D. 2 × 2 - 3 = 4 - 3 = 1.

1 ≠ 0. D is not true.

I hope this helps!

Suppose a college student pays $900 for tuition fees. However, she also has to pay $400 for her textbooks (ouch!). What percent of her total education costs does she pay for her books?

Answers

Answer:

31%

Step-by-step explanation:

The total this student must pay is $900 + $400 = $1300.

Dividing the cost of books ($400) by the total ($1300) yields:

$400

---------- = 0.3077, or approx. 31%

$1300

You have to make a part over whole proportion ([tex]\frac{part}{whole}=\frac{part}{whole}[/tex]

One fraction will be the unknown percent over 100 (the "whole" of all percents are always 100)

The other fraction will be cost of books over total education cost ([tex]\frac{400}{1300}[/tex]

Proportion:

[tex]\frac{400}{1300}=\frac{x}{100}[/tex]

Now cross multiply

400 * 100 = 1300 * x

40000 = 1300x

Solve for x by dividing 1300 to both sides

40000/13000 = 1300x/1300

x = 30.76923

I will round to the nearest tenth...

30.8% is the percent spent on books

Hope this helped!

~Just a girl in love with Shawn Mendes

Using the horizontal line test, which of the following can be concluded about the inverse of the graph of the function below?

Answers

Answer:

b. it is not a function. it's not a function because I'm does not pass the horizontal lines test

Answer:

The correct option is B.

Step-by-step explanation:

Vertical line test: A vertical line intersects a function's graph at most once.

Horizontal line test: A horizontal line intersects a function's graph at most once.

If a graph passes the vertical line test, then it represents a function.

If a graph passes the horizontal line test, then its inverse is a function.

Check whether the given graph passes horizontal line test or not.

Let x-axis or y=0 be a horizontal line. The curve intersect x-axis at (-2,0) and (2,0).

Since the graph of the function intersect a horizontal line more than one time, therefore it does not passes the horizontal line test and inverse of the given function is not a function.

Hence the correct option is B.

The two-way table shows the number of books of each type in Eliza's home ​what is the probability that a randomly selected reference book is hard cover

Answers

Answer:

B. 0.4

Step-by-step explanation:

Use the definition of the probability

[tex]Pr=\dfrac{\text{Number of all favorable outcomes}}{\text{Number of all possible outcomes}}[/tex]

You have to find the probability that a randomly selected reference book is hard cover. Hence, from the table

Number of all possible outcomes = Number of Reference books = 25Number of all favorable outcomes = Number of Hardcover Reference books = 10

So, the probability is

[tex]Pr=\dfrac{10}{25}=\dfrac{40}{100}=0.4[/tex]

Answer:

Hence, the probability that a randomly selected reference book is a hardcover is:

                             0.4

Step-by-step explanation:

Let A denote the event that the book selected is a reference book.

and B denote the event that the book  is hardcover.

Let P denote the probability of an event.

We are asked to find:

                  P(B|A)

We know that:

[tex]P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}[/tex]

From the table we have:

[tex]P(A)=\dfrac{25}{60}=\dfrac{5}{12}[/tex]

and

[tex]P(A\bigcap B)=\dfrac{10}{60}=\dfrac{1}{6}[/tex]

Hence, we have:

[tex]P(B|A)=\dfrac{\dfrac{1}{6}}{\dfrac{5}{12}}\\\\\\P(B|A)=\dfrac{2}{5}\\\\\\P(B|A)=0.4[/tex]

           Hence, the answer is:

                 0.4

You wish to use a long string of random digits to randomly assign one-half of a group of 100 students to a treatment group. You assign consecutive number labels to all the students, starting with zero. You then break the long string into chunks of digits. Should the chunks consist of single digits, pairs, triplets, or quadruplets?
A. Quadruplets
B. Pairs
C. Single digits
D. Triplets

Answers

Answer:

B. Pairs

Step-by-step explanation:

A P E X

Answer:

Triplets

Step-by-step explanation:

just did it on pex learning

At Alan’s Produce, all produce is 20% off on Tuesdays. If a head of lettuce is normally $2.50, how much would it cost on Tuesday?

Answers

Answer:

$2.00

Step-by-step explanation:

2.50*.20=.5

2.50-.5= $2

Final answer:

The question involves calculating a 20% discount on a head of lettuce normally priced at $2.50. The discount amounts to $0.50, therefore the lettuce would cost $2.00 on Tuesdays.

Explanation:

The subject of this question is mathematics, specifically numerical problem solving involving discounts. Alan's Produce is having a 20% off sale on all produce on Tuesdays. If a head of lettuce normally costs $2.50, we need to calculate how much it would cost with the discount.

The discount can be calculated by multiplying the original price by the percentage reduction. So, $2.50 (the original price) times 20% (the discount) equals $0.50. This means the head of lettuce is $0.50 cheaper on Tuesdays.

Therefore, to find the discounted price, subtract this amount from the original price: $2.50 - $0.50 equals $2.00. So on Tuesdays, a head of lettuce at Alan's Produce would cost $2.00.

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12(x-360)=120 solve for x

Answers

12x -4320 = 120

12x = 4440
X= 370

Hope this helps!

In order to solve this equation you must first simplify, then you re-range the terms, then solve.

[tex]12(x + -360) = 120[/tex]

[tex]12(-360 + x) = 120[/tex]

[tex](-360 \times 12 + x \times 12) = 120[/tex]

[tex](-4320 + 12x) = 120[/tex]

[tex]+ 4320+ 4320[/tex]

[tex]12x = 4440[/tex]

[tex]4440 \div 12 = 370[/tex]

[tex]x = 370[/tex]

Which means your answer is "x=370."

Hope this helps.

If c(x) = 4x – 2 and d(x) = x2 + 5x, what is (cxd)(x)

Answers

Answer:

(cxd)(x) = 4x^3 + 18x^2 - 10x

Step-by-step explanation:

We have two functions:

c(x) = 4x – 2

d(x) = x2 + 5x

And we need to find (cxd)(x) which is the multiplication of both functions:

(cxd)(x) = (4x – 2)(x^2 + 5x) = 4x × x^2 + 20x^2 - 2x^2 -10x

= 4x^3 + 18x^2 - 10x

Then: (cxd)(x) = 4x^3 + 18x^2 - 10x

Answer: [tex](c*d)(x)=4x^3+18x^2-10x[/tex]

Step-by-step explanation:

You know that the function [tex]c(x)[/tex] and the function [tex]d(x)[/tex] are:

[tex]c(x) = 4x - 2\\\\d(x) = x^2 + 5x[/tex]

Then, in order to find [tex](c*d)(x)[/tex] you need to multiply the function [tex]c(x)[/tex] by the function [tex]d(x)[/tex]:

[tex](c*d)(x)=(4x - 2)(x^2 + 5x)[/tex]  

You must remember the Product of powers property, which states that:

[tex](a^m)(a^n)=a^{(m+n)}[/tex]

Now you can apply Distributive property:

[tex](c*d)(x)=4x^3+20x^2-2x^2-10x[/tex]

Finally, add the like terms. Then:

[tex](c*d)(x)=4x^3+18x^2-10x[/tex]

Help a A young black man pls

Answers

Answer:

27

Step-by-step explanation:

Evaluate the [tex]\sqrt[4]{81}[/tex] = 3

Since [tex]3^{4}[/tex] = 81

We are noe left to evaluate (3)³ = 27

In the graph below, the hyperbola gets close to the red lines but never touches
them. Which of the following terms best describes each of the red lines?
center

Answers

Answer:

Option A asymptote.

Step-by-step explanation:

Asymptotes are lines to which the graph approaches very it can come very close to it but will never touch it. Asymptote are the limits of a graph.

IN the given graph of Hyperbola the two blue lines representing the Hyperbola are coming too close to the red lines but not touching it .

The two red lines are called the Asymptotoes of the Hyprbola.It is the limit of the Hyperbola.

Step-by-step explanation:

Answer:

It is an asymptote.

Step-by-step explanation:

I did it on A P E X

Put these in order from least to greatest 22% 0.3 1/5

Answers

Answer:

1/5,22%,0.3

Step-by-step explanation:

Please mark brainliest and have a great day!

Answer:

1/5,22%,0.3

Step-by-step explanation:

To put 22% 0.3 1/5 in order, convert all to decimal to determine the least

22% = 22/100

= 0.22

0.3 is already in decimal form

1/5 = 0.2

So, the least is 0.2

and the greatest is 0.3

Answer: 0.2, 0.22 and 0.3

The perimeter of the scalene triangle is 60 cm. The length of the longest side is 4 times that of the shortest side. Which statements about the possible measures of the sides are reasonable? Check all that apply. The value of x can equal 40. The longest side can equal 30 cm. The shortest side can equal 7 cm. The value of x can equal 25. The shortest side can equal 5.

Answers

Answer:

We know that in a scalene triangle all sides (and angles) are different.

Let

z = length of longest side

y =  length of second side

x =  length of shortest side

The perimeter of the scalene triangle is 60 cm

x + y + z = 60 cm

The length of the longest side is 4 times that of the shortest side.

z = 4*x

We are left with the following equations

x + y + z = 60

z = 4*x

We will test every affirmation

Number one

The value of x can equal 40.

FALSE. The longest side cannot be greater than the perimeter.

Number two

The longest side can equal 30 cm

z = 30 cm

x = 30/4 cm = 7.5 cm

y = [60 -30 - 7.5] cm  = 22.5 cm

This statement is TRUE

Number three

The shortest side can equal 7 cm

x = 7 cm

z = 4*7 cm = 28 cm

y = [60 -28 - 7] cm  = 25 cm

This statement is TRUE

Number four

The value of x can equal 25

x = 25 cm

z = 4*25 cm = 100 cm

The longest side cannot be greater than the perimeter.

This statement is FALSE

Number five

The shortest side can equal 5

x = 5 cm

z = 4*5 cm = 20 cm

y = [60 -20 - 5] cm  = 35 cm

This statement is FALSE. The second side (y) cannot be greater than the longest side (z).

vallues of 3×-2ײ=7​

Answers

Answer:

Step-by-step explanation:

"Find the values of x that satisfy 3x - 2x^2 = 7."  Please do not use " × " to represent a variable; " × " is an operator, the "multiply" operator.

Rearrange these three terms in descending order by powers of x:

-2x^2 + 3x - 7 = 0.   Here the coefficients are a = -2, b = 3 and c = -7, and so the discriminant of this quadratic is b^2-4ac, or 9 - 4(-2)(-7), or 9 - 56, or -47.

Because the discriminant is negative, we'll have two different complex roots here.  The quadratic formula becomes

       -3 ± i√47         -3 ± i√47

x = ----------------- = -------------------

        2(-2)                     -4

Final answer:

The question involves solving a quadratic equation using the quadratic formula. Substituting a, b, and c values into the formula will give us the solutions for x, with the discriminant indicating the nature of the roots.

Explanation:

The question asks for the solution to the quadratic equation 3x - 2x² = 7.

To solve this equation, we first move all terms to one side of the equal sign to set the equation to zero:

2x² - 3x + 7 = 0

Since this is a quadratic equation, we can use the quadratic formula:

x = [-b ± √(b² - 4ac)] / (2a)

In this case, a = -2, b = 3, and c = -7. We substitute these values into the quadratic formula to find the values of x:

x = [(-3) ± √((3)² - 4(-2)(-7))] / (2(-2))

The discriminant, √(b² - 4ac), will determine the nature of the roots.

Depending on the value of the discriminant, the solutions may be real and distinct, real and equal, or complex.

The slope of a line is –2 and its y-intercept is (0, 3). What is the equation of the line that is parallel to the first line and passes through (2, 2)? A. 2x + y = 6 B. y = –2x + 3 C.y=1/2x +6 D.y=-2x-6

Answers

Answer:

D. y=-2x-6

Step-by-step explanation:

First start with what we know....

y = -2x + 3 (Slope Intercept Form)

Because of this we can eliminate B.  

Parallel means that the lines wouldn't be touching which means they should have the same slope and the only one with the same slope is D.

For this case we have that an equation of a line of the slope-intersection form is given by:

[tex]y = mx + b[/tex]

Where:

m: It's the slope

b: It is the cutoff point with the y axis

They give us the following information:

[tex]m = -2\\b = 3[/tex]

Then the line is:

[tex]y = -2x + 3[/tex]

They ask us to find a parallel line. By definition, if two lines are parallel then they have the same slope. Thus, the line sought is of the form:

[tex]y = -2x + b[/tex]

We look for the cut point "b" substituting the point where the line passes: [tex](2,2)[/tex]

[tex]2 = -2 (2) + b\\2 = -4 + b\\2 + 4 = b\\b = 6[/tex]

Finally, the line is:

[tex]y = -2x + 6\\y + 2x = 6[/tex]

Answer:

Option A

A steamboat went 8miles upstream in 1 hour. The return trip only took 30 minutes. Assume that the speed and direction of the current was constant during both parts of the trip. Find the speed of the boat in still water and the speed of the current.

Answers

recall your d = rt, distance = rate * time.

b = rate of the boat in still water

c = rate of the currrent

the distance going upstream is 8 miles, the distance going downstream is also the same 8 miles.

the boat took 1 hour going upstream, now, the boat is not going "b" mph fast, since it's going against the current, the current is eroding speed from, thus the boat going up is really going "b - c" fast.

likewise, when the boat goes downstream, is not going "b" fast either, is going faster because is going with the current and thus is really going "b + c" fast, and we know that trip back took 1/2 hour or 30 minutes.

[tex]\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Upstream&8&b-c&1\\ Downstream&8&b+c&\frac{1}{2} \end{array}\qquad \begin{cases} 8=(b-c)(1)\\ 8+c=\boxed{b}\\ \cline{1-1} 8=(b+c)\left( \frac{1}{2} \right) \end{cases}[/tex]

[tex]\bf \stackrel{\textit{substituting in the 2nd equation}~\hfill }{8=\left(\boxed{8+c}+c \right)\cfrac{1}{2}\implies 8=(8+2c)\cfrac{1}{2}}\implies 16=8+2c \\\\\\ 8=2c\implies \cfrac{8}{2}=c\implies \blacktriangleright 4=c \blacktriangleleft \\\\\\ \stackrel{\textit{we know that }~\hfill }{8+c=b\implies 8+4=b\implies \blacktriangleright 12=b \blacktriangleleft}[/tex]

Final answer:

To find the speed of the boat in still water and the speed of the current, two equations are formed using the distances and times of the upstream and downstream trips. Solving the equations reveals that the speed of the boat is 12 miles/hour and the speed of the current is 4 miles/hour.

Explanation:

The problem describes a boat moving upstream and then downstream in a river with a constant current. To solve for the speed of the boat in still water and the speed of the current, we use some simple algebra based on the relative speeds of the boat and the current.

Let's denote:

Speed of the boat in still water as ‘b’.
Speed of the current as ‘c’.

When going upstream, the boat's effective speed is (b-c), and when going downstream, it is (b+c). We are told that the boat went 8 miles upstream in 1 hour and the return trip only took 30 minutes (or 0.5 hours).

Therefore, for the upstream trip:

Distance = Speed × Time

8 miles = (b - c) × 1 hour

8 = b - c ...... (equation 1)

For the downstream trip:

8 miles = (b + c) × 0.5 hours

16 = b + c ...... (equation 2)

Solve the two equations simultaneously:

Add equation 1 and equation 2:

8 + 16 = (b - c) + (b + c)

24 = 2b

b = 12 miles/hour

Substitute b into equation 1:

8 = 12 - c

c = 4 miles/hour

Therefore, the speed of the boat in still water is 12 miles/hour and the speed of the current is 4 miles/hour.

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In the following situation, determine whether you are asked to determine the number of permutations or combinations. Then
do the calculation
How many ways are there to pick a starting five from a basketball team of twelve members?
a. Permutation; Ps - 2520
b. Combination; 1C, - 792
c. Combination: 2Cs - 2520
d. Permutation; Ps - 95040

Answers

Answer:

There are 95040 ways to chose the starting five players

The answer is d ⇒ Permutation; Ps - 95040

Step-by-step explanation:

* Lets explain the difference between permutations and combinations

- Both permutations and combinations are collections of objects

- Permutations are for lists (order matters)

- Combinations are for groups (order doesn't matter)

- A permutation is an ordered combination.

- Permutation is nPr, where n is the total number and r is the number

 of choices

# Example: chose the first three students from the group of 10 students

  n = 10 and r = 3,then 10P3 is 720

- Combinations is nCr, where n is the total number and r is the number

 of the choices

# Example: chose a group of three students from the group of 10 students

  n = 10 and r = 3,then 10C3 is 120

* Lets solve the problem

- We want to pick starting five players from a basketball team of

 twelve players

∵ We will pick the starting five

∴ The order is important

∴ We will use the permutations

∵ The total number of the players is 12

∵ The number of choices is 5

∴ n = 12 and r = 5

∵ The number of ways is nPr

∴ 12P5 = 95040

∴ There are 95040 ways to chose the starting five players

Answer is D

Step-by-step explanation:

What is the y-intercept of the function f(x) = -2/9x+1/3?
A _2/9
B -1/3
C 1/3
D 2/9​

Answers

Answer: C 1/3

Step-by-step explanation:

The +1/3 is the y-intercept and the -2/9 is the slope.

It is the same as y=mx+b, just that f(x) means function of x and is usually referred to as y.

The perimeter of a rectangle is 38 inches,if the length is 3 inches more than the width ,find the width

Answers

Answer:

8 inches

Step-by-step explanation:

We are given:  2L+2W=38  or simplified version: L+W=19

                          L=3+W

So plug 2nd equation into first, like so, (3+W)+W=19

                                                                 3+W+W=19

                                                                 3+2W=19

                                                                     2W=16

                                                                       W=8

The width of rectangle is,

⇒ W = 8 inches

We have to given that,

The perimeter of a rectangle is 38 inches.

And, the length is 3 inches more than the width.

Let us assume that,

Width = W

Length = W + 3

Hence, We get;

2 (W + W + 3) = 38

2 (2W + 3) = 38

4W + 6 = 38

4W = 38 - 6

4W = 32

W = 32/4

W = 8

Therefore, The width of rectangle is,

⇒ W = 8 inches

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Solve the system of linear equations: 1/5 x + 1/8 y = 1 1/2 x − 1/3 y = 1

Answers

Answer:

x = 75 and y = -72

Step-by-step explanation:

It is given that,

1/5 x + 1/8 y = 1   ------(1)

1/2 x − 1/3 y = 1  -------(2)

To find the solutions of the system of equations

Step 1: eq(1) * 5 ⇒

x + 5/8y = 5  ----(3)

Step 2:  eq(2) * 2 ⇒

x - 2/3y = 2  -----(4)

Step 3: eq(3) - eq(4) ⇒

x + 5/8y = 5  ----(3)

x - 2/3y = 2  -----(4)

0 +(5/8 - 2/3)y = 3

 -1/24 y = 3

y = -24*3 = -72

Step 4: Substitute the value of y in eq(1)

1/5 x + 1/8 y = 1   ------(1)

1/5 x + 1/8 (-72) = 1   ------(1)

1/5 x  - 24 = 1

1/5 x = 25

x = 5*25 = 75

Therefor x = 75 and y = -72

Answer:

[tex]x = \dfrac{110}{31}; \qquad y = \dfrac{72 }{31}[/tex]

Step-by-step explanation:

I am guessing that your two equations are

(1) ⅕x + ⅛y = 1

(2) ½x - ⅓ y = 1

To get rid of fractions, I would multiply each equation by the least common multiple of its denominators.

[tex]\begin{array}{rcrl}(3) \qquad 8x + 5y & = & 40 & \text{Multiplied (1) by 40}\\(4) \qquad 3x - 2y & = & 6 & \text{Multiplied (2) by 6}\\\end{array}[/tex]

We can solve this system of equations by the method of elimination.

[tex]\begin{array}{rcrl}(5) \qquad \, \, 16x + 10y & = & 80 & \text{Multiplied (3) by 2}\\(6) \qquad \, \: 15x - 10 y & = & 30 & \text{Multiplied (4) by 5}\\31x & = & 110 & \text{Added (5) and (6)}\\\\(7)\qquad\qquad \qquad x & = & \dfrac{110 }{31} & \text{Divided each side by 31}\\\end{array}[/tex]

[tex]\begin{array}{rcrl}3 \left (\dfrac{110}{31} \right) - 2y & = & 6 & \text{Substituted (7) into (4)}\\\\ (5) \qquad16x + 10y & = & 80 & \text{Multiplied (3) by 2}\\\\(6)\qquad 15x - 10 y & = & 30 & \text{Multiplied (4) by 5}\\\\31x & = & 110 & \text{Added (5) and (6)}\\\\(7)\qquad \qquad \qquad x & = & \dfrac{110 }{31} & \text{Divided each side by 31}\\\\3 \left(\dfrac{110}{31} \right ) - 2y & = & 6 & \text{Substituted (7) into (4)}\\\\\end{array}\\\\[/tex]

[tex]\begin{array}{rcll}\dfrac{330}{31} - 2y & = & 6 &\\\\-2y & = & 6 - \dfrac{330}{31} &\\\\y & = & \dfrac{165}{31} -3 & \text{Divided each side by -2}\\\\ & = & \dfrac{165 - 93}{31} &\\\\ & = & \dfrac{72}{31} &\\\\\end{array}\\\\\therefore x = \dfrac{110}{31}; \qquad y = \dfrac{72 }{31}[/tex]

The diagram below shows the graphs of your two functions intersecting at (3.548, 2.323). These are the decimal equivalents of your fractional coordinates.

What is the difference between –7 and 3?

Answers

The difference is 10.
-7+x=3
x=10

Answer:

ITS NEGATIVE 10

Step-by-step explanation:

The measure of A is 20° greater than the measure of B. The two angles are complementary. Find the measure of each angle.

The m A is ° and m B is °.

Answers

Answer: The m∠A is 55° and m∠B is 35°. Hope this helps

Step-by-step explanation:

Step 1: m∠A + m∠B = 90°

Step 2: m∠A + (m∠A − 20°) = 90°

Step 3: m∠A + (m∠A − 20°) = 90°

+20° = +20° Add 20° to both sides.

m∠A + m∠A = 110°

2(m∠A) = 110° Divide both sides by 2.

m∠A = 55°

Step 4: m∠A + m∠B = 90°

55° + m∠B = 90° Substitute 55° for m∠A.

m∠B = 35°

The measures of two complementary angles where one is 20° greater than the other, we set up equations based on the sum of their measures being 90°. Solving these equations, we find that the measure of angle A is 55° and the measure of angle B is 35°.

The measures of two complementary angles, where the measure of angle A is 20° greater than the measure of angle B. To find these measures, we can set up the following equations based on the properties of complementary angles:

Let m B be the measure of angle B.

Therefore, m A will be m B + 20° because it's given that angle A is 20° greater than angle B.

Since angles A and B are complementary, their measures must add up to 90°, hence m A + m B = 90°.

Substitute m A = m B + 20° into the equation m A + m B = 90° to get (m B + 20°) + m B = 90°.

Combine like terms to form 2m B + 20° = 90°.

Solve for m B by subtracting 20° from both sides to get 2m B = 70°.

Divide both sides by 2 to find m B = 35°.

Substitute m B = 35° into m A = m B + 20° to find m A = 35° + 20° = 55°.

Therefore, the measure of angle A is 55° and the measure of angle B is 35°.

solve log3(x+1)=log6(5-x) by graphing. what equations should be graphed​

Answers

Answer:

x=1.25

Step-by-step explanation:

We want to solve [tex]\log_3(x+1)=\log_6(5-x)[/tex] by graphing.

We let  [tex]y=\log_3(x+1)[/tex] and also

[tex]y=\log_6(5-x)[/tex].

We graph both equations to obtain the graph shown in the attachment.

The two graphs intersect at (1.25,0.74)

Therefore the solution to [tex]\log_3(x+1)=\log_6(5-x)[/tex]  is the x-coordinate of the point of intersection of the two graphs which is x=1.25.

Answer:  a and d

Step-by-step explanation:

I got it right on edge

In which place is the digit 8 in this number?
383,170,272
O A.
the hundred billions place
B.
the one millions place
c.
the ten millions place
D.
the hundred thousands place​

Answers

Answer:

The ten millions place

Step-by-step explanation:

because the three after it is the unit million then the 8 being before the 3 would definitely be it's tens

6x7-8/4 using the order of operations will reward 10 pts best answer will be marked brainliest.

Answers

Answer:

40

Step-by-step explanation:

6x7-8/4 =42 - 2 = 40

Final answer:

To solve the expression 6x7-8/4, follow PEMDAS rule: Multiply 6 by 7, divide 8 by 4, and subtract the result from the multiplication.

Explanation:

To solve the expression 6x7-8/4 using the order of operations, we follow the acronym PEMDAS, which stands for Parentheses, Exponents, Multiplication, and Division (from left to right), and Addition and Subtraction (from left to right). Firstly, we perform the multiplication: 6x7 = 42. Then, we divide 8 by 4, which equals 2. Finally, we subtract 2 from 42, which gives us the final answer of 40.

Learn more about Order of Operations here:

https://brainly.com/question/15840745

#SPJ2

Which expression gives the distance between the points (-3, 4) and (6, -2)?

Answers

For this case we have that by definition, the distance between two points is given by:

[tex]d = \sqrt {(x_ {2} -x_ {1}) ^ 2+ (y_ {2} -y_ {1}) ^ 2}[/tex]

We have the following points:

[tex](x_ {1}, y_ {1}) = (6, -2)\\(x_ {2}, y_ {2}) = (- 3,4)[/tex]

Substituting we have:

[tex]d = \sqrt {(- 3-6) ^ 2 + (4 - (- 2)) ^ 2}\\d = \sqrt {(- 3-6) ^ 2 + (4 + 2) ^ 2}[/tex]

Answer:

Option B

Final answer:

The distance between the points (-3, 4) and (6, -2) is calculated using the distance formula from the Pythagorean Theorem, resulting in approximately 10.82 units.

Explanation:

To calculate the distance between two points in a coordinate system, you can use the distance formula derived from the Pythagorean Theorem. This is expressed as:

d = √((x₂ - x₁)² + (y₂ - y₁)²)

Given the points (-3, 4) and (6, -2), you can plug these into the formula as follows:

d = √((6 - (-3))² + (-2 - 4)²)

d = √((6 + 3)² + (-6)²)

d = √(9² + (-6)²)

d = √(81 + 36)

d = √(117)

d ≈ 10.82

This result means the distance between the points (-3, 4) and (6, -2) is approximately 10.82 units.

Carla is cutting pieces of string that are exactly 24 3/8 inches long. How many pieces can she cut from a ball of string that’s is 100 feet?

Answers

It can go into 100 feet 4 times. After you add four times you should have 97 and 4/8 or 97 and 1/2

Answer:  She can cut 49 pieces from the ball of string that’s is 100 feet.

Step-by-step explanation:  Given that Carla is cutting pieces of string that are exactly [tex]24\dfrac{3}{8}[/tex] inches long.

We are to find the number of pieces that she can cut from a ball of string with weight 100 feet.

We know that

1 feet = 12 inches.

So, 100 feet = 1200 inches.

Also, [tex]24\dfrac{3}{8}=\dfrac{195}{8}.[/tex]

Now, the number of pieces with length [tex]\dfrac{195}{8}[/tex] inches = 1.

So, the number of pieces with length 1 inch will be

[tex]\dfrac{1}{\frac{195}{8}}=\dfrac{8}{195}.[/tex]

Therefore, the number of pieces that can be cut from 1200 inches is given by

[tex]\dfrac{8}{195}\times1200=49.23.[/tex]

Thus, she can cut 49 pieces from the ball of string that’s is 100 feet.

Find the values for a, b, and c that complete the simplification.

Answers

Answer:

a = 6, b = 4, c = 2

Step-by-step explanation

see attached

Answer:

The required values are a=6, b=4 and c=2.

Step-by-step explanation:

The given expression is

[tex]\sqrt{x^{12}y^{9}z^{5}}=(x^{a}y^bz^c)\sqrt{yz}[/tex]          .... (1)

It can be written as

[tex]\sqrt{x^{12}\cdot y^{8}\cdot y\cdot z^{4}\cdot z}[/tex]

[tex]\sqrt{x^{12}\cdot y^{8}\cdot z^{4}\cdot y\cdot z}[/tex]

[tex]\sqrt{(x^{6})^2\cdot (y^{4})^2\cdot (z^{2})^2\cdot y\cdot z}[/tex]     [tex][\because (a^m)^n=a^{mn}][/tex]

[tex]\sqrt{(x^{6}y^4z^2)^2\cdot y\cdot z}[/tex]          [tex][\because a^xb^x=(ab)^x][/tex]

[tex](x^{6}y^4z^2)\sqrt{yz}[/tex]               .... (2)       [tex][\because \sqrt{x^2}=x][/tex]

From (1) and (2), we get

[tex]a=6,b=4,c=2[/tex]

Therefore the required values are a=6, b=4 and c=2.

What is the slope intercept form of a line that passes through points (2,11) and (4,17)?

Answers

Answer:

[tex]y = 3x + 5[/tex]

Step-by-step explanation:

The equation of a line in the pending intercept form has the following form:

[tex]y = mx + b[/tex]

Where m is the slope of the line and b is the intercept with the y axis.

If we know two points [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] that belong to the line then:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]b=y_1-mx_1[/tex]

In this case:

[tex](x_1, y_1)=(2,11)[/tex]

[tex](x_2, y_2)=(4,17)[/tex]

[tex]m=\frac{17-11}{4-2}[/tex]

[tex]m=\frac{6}{2}[/tex]

[tex]m=3[/tex]

[tex]b=11-3(2)[/tex]

[tex]b=11-6[/tex]

[tex]b=5[/tex]

Finally the equation is:

[tex]y = 3x + 5[/tex]

Answer:y=3x-5

Step-by-step explanation:

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