if last years sales were $200,000 and this years increase was 250% how much are this years sales
Answer:
$700000
Step-by-step explanation:
We are given that last year sales=$200,000
This year sales increases=250%
We have to find the earn money from this year sales
Let x be the earn money in this year
According to question
[tex]\frac{250}{100}\times 200000+200000=x[/tex]
[tex]x=500000+200000=700000[/tex]
Hence, this year sales=$700000
A rectangular athletic field is twice as long as it is wide. if the perimeter of the athletic field is 192 yards, what are its dimensions
solve for n
4n + 2 = 6 (1/3n - 2/3)
The solution of expression for the value of n is, n = - 3.
Used the concept of expression that states,
Mathematical expression is defined as the collection of numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that,
The expression is,
[tex]4n + 2 = 6 (\dfrac{1}{3} n - \dfrac{2}{3} )[/tex]
Now simplify the expression by combining like terms and apply the distributive property as,
[tex]4n + 2 = 6 (\dfrac{1}{3} n - \dfrac{2}{3} )[/tex]
Apply distributive property,
[tex]4n + 2 = (\dfrac{6}{3} n - \dfrac{12}{3} )[/tex]
[tex]4n + 2 = 2n - 4[/tex]
Combine like terms,
[tex]4n - 2n = - 4 - 2\\[/tex]
[tex]2n = - 6\\[/tex]
[tex]n = - 3[/tex]
Therefore, the value of n is - 3.
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If h(x) = 5 for the function h(x) = 2x + 1, what is the value of x?
If it takes six men six days to dig six holes, how long will it take one man to dig half a hole?
It will take 3 days for 1 man to dig half of that complete hole.
What are direct and inverse proportion ?Direct proportion if increase in one quantity also results in increase in another quantity for example price and weight of something.
Inverse proportion is when increase in one quantity results in decrease in another quantity for example time is inversely proportional to (speed when distance is constant.
According to the given question
6 men are working together then it takes them 6 days to dig 6 holes.
∴ Number of men days = 6 days × 6 men = 36 men days
So, in 36 men days 6 holes are dug. Now the men days and the number of holes being dug are in direct proportion with one another.
Hence number of men-days required to dig one hole
= 36/6 men days
= 6 men days
∴ No. of men days required to dig half a hole
= 6/2
= 3 men days
So, It takes 1 man 3 days to dig half a hole.
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You have $200 in your savings account. You take $35 from your account each week for four weeks. How much is left in your account at the end of the four weeks?
Find the zeros with multiplicity for the function p(x) = (x^3 – 8)(x^5 – 4x^3)
Please show steps
What is the distance between -3 and 6?
-9
-3
3
9
Nine less than the product of ten and a number d is equal to eleven.
Use the graph below to fill in the blank with the correct number
How many license plates can be made using 2 digits then 5 letters if repeated digits and letters are not allowed?
Joe has $1,800 from his summer job to invest. If Joe wants to have $2,340 altogether and invests the money at 5% simple interest, in how many years will Joe have $2,340?
Simplify
Y+ z -2y. If y=4 and z=2
Solve the following system of linear equations. 3x + 2y = 10 2x + 3y = 15/2 No solution y = (-3/2)x + 5 x = 3, y = -1/2 x = 3, y = 1/2
The solution of the equations is the point(3,1/2)
What is the solution to a linear equation?The solution of a linear equation is defined as the points, in which the lines represent the intersection of two linear equations. In other words, the solution set of the system of linear equations is the set of all possible values to the variables that satisfies the given linear equation.
Given here: 3x + 2y = 10 2x + 3y = 15/2 Solving the two equations we get
the solution as x=3 and y=1/2
Hence, the solution of the equations is the point(3,1/2)
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Final answer:
Using the elimination method, we solved the system of linear equations to find that the solution is x = 3 and y = 1/2.
Explanation:
The student is asking us to solve a system of linear equations. The equations given are:
3x + 2y = 10
2x + 3y = 15/2
To solve these equations, we can use either substitution or elimination method. Let's go ahead with the elimination method to find the values of x and y.
Multiply the first equation by 3 and the second equation by 2 to make the coefficients of x the same:
9x + 6y = 30 (multiplying the first equation by 3)
4x + 6y = 15 (multiplying the second equation by 2)
Now, subtract the second equation from the first equation to eliminate y:
9x + 6y - (4x + 6y) = 30 - 15
5x = 15
x = 3
Now plug x=3 into the first original equation:
3(3) + 2y = 10
9 + 2y = 10
2y = 1
y = 1/2
Therefore, the solution to the system of equations is x = 3 and y = 1/2.
Factor the expression. k2 + kf – 2f2
Answer:
Factorized form of the given expression is (k + 2f)(k - f).
Step-by-step explanation:
The given expression is k² + kf - 2f² and we have to factorize the given expression.
k² + kf - 2f² = k² + 2kf - kf - 2f²
= k(k + 2f) - f(k + 2f)
= (k + 2f)(k - f)
So the factorized form of the expression is (k + 2f)(k - f).
When the towels from a hotel were divided evenly among 5 laundry baskets, each basket contained 18 towels. Which equation, when solved, will show how many towels there were in all? t ÷ 5 = 18 5 ÷ t = 18 90 ÷ t = 18 18 – t = 5
write the ratio six to seven in other ways
What is the solution to the compound inequality in interval notation? 2(x+3)>6 or 2x+3≤−7
Answer: The required solution in interval notation is [tex](0,\infty)U(-\infty,-5].[/tex]
Step-by-step explanation: We are given to find the solution to the following compound inequality in interval notation :
[tex]2(x+3)>6~or~2x+3\leq -7~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
To find the solution to (i), we must solve both the parts separately.
The inequality (i) can be solved as follows :
[tex]2(x+3)>6\\\\\Rightarrow x+3>\dfrac{6}{2}\\\\\Rightarrow x+3>3\\\\\Rightarrow x>3-3\\\\\Rightarrow x>0\\\\\Rightarrow x\epsilon (0,\infty)[/tex]
or
[tex]2x+3\leq-7\\\\\Rightarrow 2x\leq-7-3\\\\\Rightarrow 2x\leq -10\\\\\Rightarrow x\leq -\dfrac{10}{2}\\\\\Rightarrow x\leq-5\\\\\Rightarrow x\epsilon(-\infty,-5].[/tex]
Thus, the required solution in interval notation is [tex](0,\infty)U(-\infty,-5].[/tex]
Which of the following inequalities contains points only in the first and second quadrants?
y > 4x2 − 1y ≤ 2x2 + 1y > −2x2 + 3y > 2x2 − 3x + 2
TRUE OR FALSE:if a function uses variables other than x and y for its input and output variables, you take the original and solve for the output variable to find the inverse.
Answer: False for apex
Step-by-step explanation: 1. because it is
2. for the junior monitor that deleted my answer, back off.
Answer:
false for apex
Step-by-step explanation:
1/3(9-6m)+1/4(12m-8)
Answer:
[tex]m+1[/tex]
Step-by-step explanation:
The question is
Simplify the expression
we have
[tex]\frac{1}{3}(9-6m)+\frac{1}{4}(12m-8)[/tex]
using the distributive property
[tex]\frac{1}{3}(9)-\frac{1}{3}(6m)+\frac{1}{4}(12m)-\frac{1}{4}(8)[/tex]
[tex]3-2m+3m-2[/tex]
Combine like terms
[tex]m+1[/tex]
Graph Jkl and its image after a reflection in the given line J(5,3), K(1,-2), l(-3,4); y-axis
When a shape is reflected, it must be reflected across a line.
See attachment for the graphs of JKL and the image of JKL
The coordinates of JKL are given as:
[tex]J = (5,3)[/tex]
[tex]K = (1,-2)[/tex]
[tex]L = (-3,4)[/tex]
The rule of reflection across the y-axis is:
[tex](x,y) \to (-x,y)[/tex]
So, we have:
[tex]J' =(-5,3)[/tex]
[tex]K' =(-1,-2)[/tex]
[tex]L' = (3,4)[/tex]
See attachment for the graphs of JKL and the image of JKL
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Expand the following using either the Binomial Theorem or Pascal’s Triangle. You must show your work for credit. (x - 5)5
Answer:
The expansion is [tex](x-5)^5= x^5-25x^4+250x^3-1250x^2+3125 x-3125[/tex]
Step-by-step explanation:
Given : Expression [tex](x-5)^5[/tex]
To find : Expand the following using either the Binomial Theorem or Pascal’s Triangle?
Solution :
Applying binomial theorem,
Defined as [tex](p+q)^n=\sum_{r=0}^{n} ^nC_rp^{n-r} q^r[/tex]
Where, [tex]^nC_r=\frac{n!}{(n-r)!r!}[/tex]
Now, expanding [tex](x-5)^5[/tex] by binomial formula,
We have,
[tex](x-5)^5=\sum_{r=0}^{5} ^5C_rx^{5-r} (-5)^r[/tex]
Open the summation,
[tex]\Rightarrow ^5C_0 x^{5-0} (-5)^0 + ^5C_1 x^{5-1} (-5)^1 + ^5C_2 x^{5-2} (-5)^2 + ^5C_3 x^{5-3} (-5)^3 \\+ ^5C_4x^{5-4} (-5)^4 + ^5C_5x^{5-5} (-5)^5[/tex]
[tex]\Rightarrow (1)(x^5)(1)+(5)(x^4)(-5)+(10)(x^3)(25)+(10)(x^2)(-125)+(5)(x^1)(625)+(1)(1)(-3125)[/tex]
[tex]\Rightarrow x^5-25x^4+250x^3-1250x^2+3125 x-3125[/tex]
Therefore, The expansion is [tex](x-5)^5= x^5-25x^4+250x^3-1250x^2+3125 x-3125[/tex]
Which term describes the set of all possible outcomes for a probability event?
A person 6 ft tall casts a shadow 5ft long. at the same time, a nearby tree casts a shadow 31 ft long. find the height of the tree
Therefore, the tree's height is 37.2 feet.
We can use proportions to find the height of the tree based on the shadow it casts and compare it to the height and shadow of a known object (in this case, a person). Given that a person 6 ft tall casts a 5 ft long shadow, we can set up a proportion with the tree's 31 ft long shadow to find its height. The formula we use for this comparison is:
Person's Height / Person's Shadow = Tree's Height / Tree's Shadow
Plugging in the numbers:
6 ft / 5 ft = Tree's Height / 31 ft
Now, we solve for the Tree's Height:
6 ft * (31 ft / 5 ft) = Tree's Height
Tree's Height = 37.2 ft
Therefore, the height of the tree is 37.2 feet.
How you will go about preparing yourself to confidently teach numeracy?
In preparation of yourself in having to teach numeracy, it is best to substantiate if learning the numeracy will have benefits or advantages, such as having to help other people or even empower them as an adult people learning and think of ways how will this could be important to them.
The first aircraft has 75 more seats than the second aircraft. The third aircraft has 49 fewer seats than the second aircraft. If their total number of seats is 401, find the number of seats for each aircraft.
1st = 75+x
2nd = x
3rd = x-49
401 = 75 +x+ x+ +x-49
401 = 75+3x-49
401 = 3x+26
375=3x
x=375/3 = 125
1st = 125+75 = 200
2nd = 125
3rd = 125-49 = 76
200 + 125 +76 = 401
Point E is drawn on the graph so that the line EF is parallel to line CD
Answer:
-8
Step-by-step explanation:
edg 2020
Mr. Plum's math class of 25 students had an average of 85 on a test. Miss Scarlett's class of 22 students had an average of 87 on the same test. What is the average of the two classes combined?
A mean is an arithmetic average of a set of observations. The average of the two classes combined is 85.936.
What is Mean?A mean is an arithmetic average of a set of observations. it is given by the formula,
Mean = (Sum of observations)/Number of observations
Mr. Plum's math class of 25 students had an average of 85 on a test.
Average = Total marks /Total number of students
Total marks of Mr. Plum's class = Total number of students × Average
Total marks of Mr. Plum's class = 25 × 85
Total marks of Mr. Plum's class = 2,125
Miss Scarlett's class of 22 students had an average of 87 on a test.
Average = Total marks /Total number of students
Total marks of Miss Scarlett's class = Total number of students × Average
Total marks of Miss Scarlett's class = 22 × 87
Total marks of Miss Scarlett's class = 1,914
Further, the average of the two classes combined is,
Average = Total marks / Total students
= (2,125 + 1914)/(25+22)
= 4039/47
= 85.936
Hence, the average of the two classes combined is 85.936.
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Take -4 + 3a 2 from 7a - a 2
Subtracting [tex]\( -4 + 3a^2 \)[/tex] from [tex]\( 7a - a^2 \)[/tex] yields [tex]\( 7a - 3a^2 + 4 - a^2 \)[/tex], after distributing the subtraction and combining like terms.
To subtract [tex]\( -4 + 3a^2 \)[/tex] from [tex]\( 7a - a^2 \)[/tex], we need to distribute the subtraction across both terms in [tex]\( 7a - a^2 \)[/tex] and then combine like terms:
[tex]\[ (7a - a^2) - (-4 + 3a^2) \][/tex]
Distributing the subtraction:
[tex]\[ 7a - a^2 + 4 - 3a^2 \][/tex]
Now, combine like terms:
[tex]\[ (7a - 3a^2) + (4 - a^2) \][/tex]
So, the result of subtracting [tex]\( -4 + 3a^2 \)[/tex] from [tex]\( 7a - a^2 \)[/tex] is [tex]\( 7a - 3a^2 + 4 - a^2 \)[/tex].
Comlpete Question:
Take [tex]\( -4 + 3a^2 \)[/tex] from [tex]\( 7a - a^2 \)[/tex]