Superman throws a boulder of weight 3800 n at an adversary on the surface of the earth, where the magnitude of the acceleration due to gravity, g = 9.80 m/s2 . what horizontal force must superman apply to the boulder to give it a horizontal acceleration of 12.8 m/s2 ?

Answers

Answer 1
The weight of the boulder is 3800 N, therefore its mass i s
3800/9.8 = 387.755 kg

If the horizontal acceleration is 12.8 m/s², then the horizontal force applied is
F = (387.755 kg)*(12.8 m/s²) = 4.963 x 10³ n = 4.963 kN

Answer: 4.963 kN
Answer 2
Final answer:

Superman must apply a horizontal force of approximately 4963.33 N to the boulder to achieve the desired acceleration of 12.8 m/s^2. This calculation is based on the weight of the boulder and the given acceleration due to gravity.

Explanation:

To determine the horizontal force that Superman must apply to the boulder to achieve the given horizontal acceleration, we first need to calculate the mass of the boulder. Since the weight of the boulder (W) is given by the formula W = mg, where m is the mass of the boulder, g is the acceleration due to gravity (9.80 m/s2), and W is the weight (3800 N), the mass of the boulder (m) can be calculated as follows:

m = W / g = 3800 N / 9.80 m/s2 = 387.76 kg (rounded to two decimal places).

Now that we know the mass, we can find the horizontal force (F) needed to achieve the horizontal acceleration (a) using Newton's second law, F = ma. Substituting the known values results in:

F = m * a = 387.76 kg * 12.8 m/s2 = 4963.33 N.

So, Superman must apply a horizontal force of approximately 4963.33 N to provide the boulder with the desired acceleration of 12.8 m/s2.


Related Questions

If the coefficient of kinetic friction is 0.500, what was the object's speed as you released it?

Answers

The solution for this problem is:
Look first for the time to fall 1.1 m = √ 2.2 / 9.8 = 0.475 s 

Then, look for the speed at edge = 0.5 / 0.475 = 1.055 m/s 

Afterwards, compute for energy lost = word done against friction = F . d = µmgd = 0.5 x 0.1 x9.8 x 1.1 = 0.539 J 

Then, compute for original energy = 0.539 + 1/2 x m x v^2 = 0.539 + (0.5 x 0.1 x 1.055^2) = 0. 595 J

Original speed = √ 2 E / m = √ 1.19 / 0.1 = 3.45 m/s

How many revolutions does the object make during the first 3.9 s?

Answers

The area which is located under the curve gives us the angle in radians; we divide this by 2π to get units in revs (revolutions).


So for 0 ≤ t ≤ 2,

number of revs = 20rad/s * 2s * 1rev/2π rads = 6.37 revs 


So for 2 ≤ t ≤ 3.9,

number of revs = 10rad/s * 1.9s * 1rev/2πrads = 3.02 revs 

 

Therefore the total is about:

6.37 revs + 3.02 revs = 9.39 revs ≈ 9.4 revs

Final answer:

To answer how many revolutions an object makes in 3.9 seconds, we require knowledge of the object's constant angular velocity or angular acceleration. With the angular velocity, the total radians rotated can be found and divided by 2π to get the number of revolutions.

Explanation:

The question "How many revolutions does the object make during the first 3.9 s?" involves calculating the number of complete rotations or revolutions an object makes over a given period of time. In physics, this is often related to concepts of rotational motion, including angular velocity and angular acceleration. However, to calculate the number of revolutions over a certain time, we need to know either the constant angular velocity of the object, the angular acceleration, or another related quantity that would allow us to determine how the angle changes over time.

For example, if we know the angular velocity (ω) in radians per second (rad/s), we can calculate the number of revolutions by integrating the angular velocity over the given time period (3.9 s) or multiplying it by time if the angular velocity is constant. Since one revolution is equivalent to 2π radians, we can determine the total number of revolutions by dividing the total angle rotated (in radians) by 2π.

Rosa uses the formula (vi cos)t to do a calculation. Which value is Rosa most likely trying to find? the vertical acceleration of a projectile launched at an angle the vertical acceleration of a projectile launched horizontally the horizontal displacement of a projectile launched at an angle the horizontal displacement of a projectile launched horizontally

Answers

the horizontal displacement of a projectile launched at an angle

If Rosa uses the formula (vi cos)t to do a calculation, then Rosa most likely trying to find the horizontal displacement of a projectile launched at an angle to the horizontal, therefore the correct answer is option C.

What is a projectile motion?

It can be defined as the motion of any object or body when thrown from the earth's surface and follows any curved path under the effect of the gravitational force of the earth.

The horizontal component of the velocity during any projectile motion is constant and is given by vicosθ.

Thus, If Rosa uses the formula (vi cos)t to do a calculation, then Rosa most likely trying to find the horizontal displacement of a projectile launched at an angle to the horizontal, therefore the correct answer is option C.

Learn more about projectile motion here, refer to the link given below ;

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The cold virus causes disease when it enters the _____ of the human body.

Answers

Cells of the human body

The cold virus causes disease when it enters the mucous membranes of the human body such as the nasal cavity.

The cold virus causes disease when it enters the mucous membranes of the human body, particularly the nasal cavity. The most common groups of cold viruses include rhinoviruses, coronaviruses, and adenoviruses. These viruses are transmitted through direct contact such as shaking hands, and droplet transmission which occurs when an infected person coughs or sneezes. The rhinoviruses in particular thrive in cooler temperatures found in the nasal passages, leading to symptoms such as runny nose, congestion, and sneezing.

Symptoms of a cold are a result of the body's inflammatory response to the viral infection. This response generates the typical signs of a cold, but the condition is usually self-limiting and resolves on its own within 1-2 weeks.

Two cars pass each other traveling at the same speed. one car has a constant velocity of 15.0 m/s, east. the other car has a constant acceleration of 1.00 m/s , west. how much time will have elapsed until the cars are 164 m apart?

Answers

The formula for calculating the distance at constant velocity is:

d = v * t

d = 15 t

 

The formula for distance at constant acceleration is:

d = v0 t + 0.5 a t^2

d = 15 t + 0.5 t^2

 

So after a sum distance of 164 m:

15 t + (15 t + 0.5 t^2) = 164

30 t + 0.5 t^2 = 164

t^2 + 60 t = 328

(t + 30)^2 = 328 + 30^2

t + 30 = ± 35.04

t = -65.04, 5.04

Since time cannot be negative, so the two cars are 164 m apart after about 5 seconds

Nylon is a “big” covalent molecule used to make backpacks. Which property of covalent compounds is most useful in making backpacks?

Answers

Covalent compounds are soft and relatively flexible.
The answer is 'soft'

Compare the orderliness of the particles. In general, which state has the most orderly arrangement?

Answers

The state of matter which has the most orderly arrangement is solid. Here is the order of the three basic states of matter arranged from fastest to slowest, it's better to memorize it :gas, liquid, solid. Also, remember that the colder your solid is, the more ordered it is.

We have that the state with the  orderly arrangement is

The Solid state

It is important to note that there are three states

Solid Liquid Gaseous

Generally,The crystalline solid is the most well orderly arranged particle bond as it made up of a crystal lattice that has its particles well arranged.

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what is beach nourishment

Answers

Beach nourishment describes a process by which sediment, usually sand, lost through longshore drift or erosion is replaced from other sources. A wider beach can reduce storm damage to coastal structures by dissipating energy across the surf zone, protecting upland structures and infrastructure from storm surges, tsunamis and unusually high tides

"for general projectile motion, when the projectile is at the highest point of its trajectory"

Answers

The projectile vertical velocity component is zero at the highest point of trajectory, then it starts falling vertically.

Hd 10180g orbits with a period of 600 days at a distance of 1.4 au from its star. what is the ratio of the star's mass to our sun's mass?

Answers

Use the expression -

P²k = a³---(i)

Where P is time in years, a is in AU, k is the function of the Sun's mass and set to unity.

Further, we're looking for the mass of the new star we have slightly modified Kepler's Third Law. After all, the inverse of a constant is also a constant. The reason we do it is because we want an answer in the form of K:1, where K is the mass of the HD 10180 and the mass of the Sun is 1, so k needs to start out on the other side.

Convert 600 days in years = 600/365 = 1.64 years

Put this in the expression mentioned at (i) -

1.64²k = a³

You gave us a = 1.4 AU

1.64²k = 1.4³ ; isolating k

k = 1.4³/1.64²

k = 2.744/2.702 = 1.015

So, the requisite ratio = 1.015 : 1

 

The ratio of the star's mass to the sun's mass is about 1.02 : 1

[tex]\texttt{ }[/tex]

Further explanation

Centripetal Acceleration can be formulated as follows:

[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]

a = Centripetal Acceleration ( m/s² )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

[tex]\texttt{ }[/tex]

Centripetal Force can be formulated as follows:

[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]

F = Centripetal Force ( m/s² )

m = mass of Particle ( kg )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

mass of the sun = M_sun = 1.99 × 10³⁰ kg

radius of the orbit = R = 1.4 AU = 2.094 × 10¹¹ m

Orbital Period of planet = T = 600 days = 600 × 24 × 3600 = 5.184 × 10⁷ seconds

Asked:

mass of the star = M = ?

Solution:

Firstly , we will use this following formula to find the mass of the star:

[tex]F = ma[/tex]

[tex]G \frac{ Mm}{R^2}=m \omega^2 R[/tex]

[tex]G M = \omega^2 R^3[/tex]

[tex]\frac{GM}{R^3} = \omega^2[/tex]

[tex]\omega = \sqrt{ \frac{GM}{R^3}}[/tex]

[tex]\frac{2\pi}{T} = \sqrt{ \frac{GM}{R^3}}[/tex]

[tex]M = \frac{4 \pi^2 R^3}{GT^2}[/tex]

[tex]M = \frac{4 \pi^2 (2.094 \times 10^{11})^3}{6.67 \times 10^{-11} \times (5.184 \times 10^7)^2}[/tex]

[tex]\boxed {M \approx 2.0 \times 10^{30} \texttt{ kg} }[/tex]

[tex]\texttt{ }[/tex]

Next , we will calculate the ratio of the star's mass to the sun's mass as follows:

[tex]M : M_{sun} = (2.0 \times 10^{30}) : (1.99 \times 10^{30})[/tex]

[tex]\boxed{M : M_{sun} \approx 1.02 : 1}[/tex]

[tex]\texttt{ }[/tex]

Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441

[tex]\texttt{ }[/tex]

Answer details

Grade: High School

Subject: Physics

Chapter: Circular Motion

Use this excerpt from the text to answer the question. "Some people insist the United States is more properly called a republic rather than a democracy." The people who support this statement argue that the United States is a republic because in its government,

Answers

Political power is utilized in a roundabout way by chose authorities, not straightforwardly by the natives themselves. Oftentimes, legislators and numerous standard Americans allude to the United States as a majority rules system. Others locate this disturbing in light of the fact that, not at all like in a vote based system where nationals vote specifically on laws, in the United States, chose agents do – and, thusly, the U.S. is a republic.

A source emits monochromatic light of wavelength 495 nm in air. when the light passes through a liquid, its wavelength reduces to 434 nm what is the liquid's index of refraction?
a. 1.14
b. 1.49
c. 2.03
d. 1.26
e. 1.33

Answers

By definition, the refractive index is
n = c/v
where c =  3 x 10⁸ m/s,  the speed of light in vacuum
v = the speed of light in the medium (the liquid).

The frequency of the light source is
f = (3 x 10⁸ m/s)/(495 x 10⁻⁹ m) = 6.0606 x 10¹⁴ Hz

Because the wavelength in the liquid is 434 nm = 434 x 10⁻⁹ m, 
v = (6.0606 x 10¹⁴ 1/s)*(434 x 10⁻⁹ m) = 2.6303 x 10⁸ m/s

The refractive index is (3 x 10⁸)/(2.6303 x 10⁸) = 1.1406

Answer:  a.  1.14
Final answer:

The liquid's index of refraction is approximately 1.88.

Explanation:

To find the index of refraction for the liquid, we can use the formula:

n₁ / n₂ = λ₁ / λ₂

where n₁ and n₂ are the indices of refraction for air and the liquid, respectively, and λ₁ and λ₂ are the wavelengths of light in air and the liquid, respectively.

In this problem, we are given that the wavelength of light in air is 495 nm and the wavelength in the liquid is 434 nm. Plugging in these values, we get:

n₁ / n₂ = 495 nm / 434 nm

n₂ ≈ n₁ * (434 nm / 495 nm)

n₂ ≈ 1 * (434 nm / 495 nm)

n₂ ≈ 0.876

To convert the index of refraction to its decimal form, we add 1, giving us:

n₂ ≈ 0.876 + 1

n₂ ≈ 1.876

The liquid's index of refraction is approximately 1.876, which can be rounded to 1.88.

What are volume and density? How do they relate to each other?

Answers

______________________________

Density= It is the mass divided by the volume. Density is defined as the mass per unit volume.

Volume= the quantity of three-dimensional space enclosed by a closed surface, for example, the space that a substance (solid, liquid, gas, or plasma) or shape occupies or contains.

______________________________

Density expresses the proportional relationship between mass and volume of the substance. If the density of a particular substance is given in grams per milliliter, it indicates the number of grams present in 1 milliliter of that substance.

______________________________

Assume each tick mark represents 1 cm. Calculate the total displacement from 0 if an object moves 3 cm to the left, then 7 cm to the right, and then 6 cm to the left. The object moves cm to the left. What is the total distance the object travels? cm

Answers

The total displacement and total distance of the object that traveled should be -2cm and 16 cm.

Given that,

Each tick mark should be presented 1cm.If an object moves 3 cm to the left, then 7 cm to the right, and then 6 cm to the left.Here we assume a positive x-axis to the right-hand side.

Based on the above information, the calculation is as follows:

The total displacement is

= 0 - 3 + 7 - 6

= -2 cm,

Thus,  the object shifts 2 cm to the left-hand side.  

Now

The total distance is  

= 0 + 3 + 7 + 6

= 16 cm

Therefore we can conclude that the total displacement and total distance of the object that traveled should be -2cm and 16 cm.

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Answer:

The object moves ✔ 2 cm to the left.

What is the total distance the object travels? ✔ 16 cm.

Explain how new discoveries influence contemporary psychological perspectives

Answers

New discoveries influence contemporary psychological perspectives because they provide new ways to look at things, or give new technology for new ways to diagnose problems and try to solve them.

Answer:

New discoveries can either provide evidence to support or refute contemporary psychological perspectives, or they can lead to the development of new theories and perspectives.Explanation:

What is the connection between the liver (organ), UV radiation (sunlight), and bone tissue

Answers

The answer to this question would be: vitamin D

The UV is needed by the skin to make previtamin D3. Previtamin D3 or cholecalciferol made from the skin will be changed in the liver into 25- hydroxyvitamin D3 and then sent to the kidney to be changed into 1,25- dihydroxyvitamin D3. The last change in the kidney will active the vitamin D. Vitamin D has a role in the calcium absorption which was will strengthen the bone tissue.

Is the change in kinetic energy of your ball greater than, less than, or equal to the change in kinetic energy of your friend's ball?

Answers

The change in kinetic energy of your ball is equal to the change in kinetic energy of your friend's ball. Because in the end they both fall from the same height picking up the same amount of kinetic energy as per the law fo conservation of energy theory

A 150 n sled is being pulled up a 28 ° rough ramp at constant speed by a force of 100 n parallel to the ramp. with what acceleration will the crate slide down, if it is released at some point on the ramp?

Answers

the answer:

we can use newton's second law for finding the value of acceleration

that is    F=MxA
M the mass
A is the acceleration

F= P-Fk,  Fk= -Mgcosθμ and P=Mgsinθ
μ is the coefficient of friction

The value of μ can be found with the above condition
(pulled up a 28 ° rough ramp at constant speed)
this implies the acceleration is equal to zero
 100N - mgsin(28°) -mgcos(28°)μ = 0 , from where 
μ= [100N - mgsin(28°)] / mgcos(28°)
μ=0.2

and then, 
F=MxA= Mgsinθ -Mgcosθμ   finally  A=gsin28° -gcos28° x0.2 =2.6m/s²

Refer to the diagram shown below.

θ = 28°, the angle of the slope.
W = 150 N, the weight of the sled.
The normal reaction is
N = W cosθ = 150*cos(28) = 132.442 N
The component of the weight acting down the plane is
F = W sin θ = 150*sin(8) = 70.421 N

Case A; The sled is pulled up the slope.
Because the sled is in dynamic equilibrium, therefore
F + μN = 100
where μ = the kinetic coefficient of friction.
That is,
70.421 + 132.442μ = 100
μ = (100 - 70.421)/132.442 = 0.2233

Case B: The sled accelerates down the slope.
When the applied force of 100 N is removed, the sled accelerates down the slope due to its weight acting down the slope. The motion is opposed by kinetic friction.
That is,
Wsinθ - μWcosθ = ma
where
m = (150 N)/(9.8 m/s²) = 15.306 kg, the mass of the sled
a =  the acceleration of the sled

Therefore
70.421 - 0.2233*132.442 = 15.306*a
a = 40.8467/15.306 = 2.669 m/s²

Answer:2.67 m/s²  (nearest hundredth)

A helicopter is ascending vertically with a speed of 7.00 m/s. at a height of 155 m above the earth, a package is dropped from a window. how much time does it take for the package to reach the ground? [hint: the package's initial speed equals the helicopter's.]

Answers

Given:
u = 7.00m/s, the initial vertical velocity of the package.

Assume that g = 9.8 m/s².
Neglect air resistance.
All quantities are measured as positive upwards.

The height from which the package is dropped is 155 m above ground.
Let t = the time for the package to hit the ground.
Therefore
(7.00 m/s)*(t s) - (1/2)*(9.8 m/s²)*(t s)² = (- 155 m)
4.9t² - 7t - 155 = 0
or
t² - 1.4286t - 31.6327  0
Solve with the quadratic formula.
t = (1/2)*[1.4286 +/- √(2.0409 + 126.5308)]
  = 6.384 s or - 4.955 s
Reject negative time.

Answer: 6.384 s

A force of 250 N is applied to an object that accelerates at a rate of 10m/sec2. What is the mass of the object?

Answers

F=ma. So if you have the Force and the Acceleration you can find the mass. m=F/a. So the mass is 25kg

What is the wavelength of an earthquake wave if it has a speed of 5 km/s and a frequency of 11 Hz?

Answers

The speed of a wave is given by this formula

v = f × λ

where:
v is the speed = 5 km/s 
f is the frequency = 11 Hz
λ is the wavelength (in metres)

We need to convert the speed into meters
5 km/s = 5000 m/s

Then substitute these values into the formula:

5000 = 11 × λ
λ = 5000 ÷ 11
λ = 454.5 meters

A particle of mass m=5.00 kilograms is at rest at t=0.00 seconds. a varying force f(t)=6.00t2−4.00t+3.00 is acting on the particle between t=0.00 seconds and t=5.00 seconds. find the speed v of the particle at t=5.00 seconds. express your answer in meters per second to three significant figures.

Answers

v =Integral(F/m)dtv=Integral(F/m)dt =â«50(6t2â’4t+3)/5dt=â«05(6t2â’4t+3)/5dt =1/5â—(2t3â’2t2+3t)|(0,5)=1/5â—(2t3â’2t2+3t)|(0,5) =1/5â—(250â’50+15)=1/5â—(250â’50+15) =215/5=215/5 =43m/s.

The speed of the particle at [tex]t = 5\,{\text{s}}[/tex] is [tex]\fbox{43\,{\text{m/s}}}[/tex].

Further explanation:

Applied force is directly proportional to the mass of the body and the acceleration of the body.

Given:

The function for force is [tex]F\left( t \right) = 6{t^2} - 4t + 3[/tex].

The limit of time is [tex]t = 0\,{\text{s}}[/tex] to [tex]t = 5\,{\text{s}}[/tex].

The mass of the particle is [tex]5\,{\text{Kg}}[/tex].

Concept used:

The rate of change of displacement of a body in unit time is called speed of the body. It is a scalar quantity.

Newton’s second law of motion states that the rate of change of momentum is equal to the applied force.

The expression for the Newton’s second law is given as.

[tex]F=ma[/tex]

Rearrange the expression for the acceleration of the body.

[tex]a=\dfrac{F}{m}[/tex]                                                              …… (1)

Here, a is the acceleration of the body, F is the force applied and m is the mass of the body.

The rate of change of speed of a body in unit time is called acceleration of the body.  

The expression for the acceleration is given as.

[tex]a=\dfrac{{dv}}{{dt}}[/tex]

 

Substitute [tex]\dfrac{{dv}}{{dt}}[/tex] for [tex]a[/tex] in equation (1).

[tex]\dfrac{{dv}}{{dt}} = \dfrac{F}{m}[/tex]

 

On integrating the above expression we get.

[tex]v = \dfrac{1}{m}\int\limits_0^5 {Fdt}[/tex]                                 …… (2)

Substitute [tex]6{t^2} - 4t + 3[/tex] for[tex]F\left(t\right)[/tex] and [tex]5\,{\text{Kg}}[/tex] for m in equation (2).

[tex]\begin{aligned} v&=\frac{1}{{\left( {5\,{\text{Kg}}} \right)}}\int\limits_0^5 {\left( {6{t^2} - 4t + 3} \right)dt}\\&=\frac{1}{{\left( {5\,{\text{Kg}}}\right)}}\left|{3{t^3}-2{t^2}+ 3t}\right|_0^5\\&=\frac{{215}}{{5\,}}\,{\text{m/s}}\\&=43\,{\text{m/s}}\\\end{aligned}[/tex]

 

Thus, the speed of the particle is [tex]\fbox{43\,{\text{m/s}}}[/tex].

Learn more:

1.  Motion under force https://brainly.com/question/4033012.

2.  Conservation of momentum https://brainly.com/question/9484203.

3. Motion under friction https://brainly.com/question/7031524.

Answer Details:

Grade: College

Subject: Physics

Chapter: Kinematics

Keywords:

Acceleration, force, weight, mass, motion, impact, nail, hammer, acceleration, duration of impact, Newton’s laws, speed, rate of change, time , 43m/s, 5Kg.

Borace drew a diagram to compare the processes of scientific investigation and technological design.


Which belongs in the area labeled W?

Conduct an experiment
Design a solution
Analyze the results
Build a prototype

Answers

Answer:

Conduct an experiment

Explanation:

Borace drew a diagram to compare the processes of scientific investigation and technological design, then the area labeled W belongs to the Conduct an experiment, therefore the correct answer is option A.

What are the stages of technological design?

There are mainly five stages of the technological design

Identifying the issue that needs to be solved is the first step in every problem-solving process.

The second stage is to imagine; during this phase, a designer would generate several concepts and conduct research on potential creations. They must pick a handful of their greatest concepts and then narrow it down to the best.

The chosen product from the imaging stage is planned in the third stage.

Testing, evaluating, and modifying the product are the fourth stage.

Thus, If Borace drew a diagram to compare the processes of scientific investigation and technological design, then the area labeled W belongs to the Conduct an experiment, therefore the correct answer is option A.

Learn more about technological design here ;

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An electric field is established by applying a potential difference to the plates. it is found that a field of strength e0 will cause the droplet to be suspended motionless. write an expression for the droplet's charge q. let g be the acceleration due to gravity.

Answers

When the particle is suspended motionless its weight is in equilibrium with the force applied on through the electric field. Thus 
[tex]mg=qE[/tex]
From this equality we can deduce the charge of the droplet necessary for the particle to stay suspended:
[tex]q= mg/E[/tex]
where m is its mass and E is the electric field that is applied.

Final answer:

When a droplet is motionless in an electric field, it means the electrical force exactly balances gravity. Coulomb's law defines the electrical force as proportional to charge [tex](\( q \))[/tex] and the field strength [tex](\( E_0 \))[/tex]. Meanwhile, gravity exerts a force[tex]\( mg \)[/tex], where [tex]\( m \)[/tex] is the droplet's mass and [tex]\( g \)[/tex] is gravity's acceleration. Equilibrium occurs when these forces match:

[tex]\[ qE_0 = mg \][/tex]

Rearranging, we find the droplet's charge [tex]\( q \):[/tex]

[tex]\[ q = \frac{mg}{E_0} \][/tex]

This expression signifies the charge required for equilibrium in the given electric field.

Explanation:

To find the expression for the droplet's charge [tex](\( q \)),[/tex] we can use the equilibrium condition where the electric force [tex](\( F_{\text{electric}} \))[/tex] due to the electric field [tex](\( E_0 \))[/tex]balances the gravitational force [tex](\( F_{\text{gravity}} \))[/tex]acting on the droplet.

The electric force [tex](\( F_{\text{electric}} \))[/tex] exerted on the droplet with charge [tex]\( q \) i[/tex]n an electric field [tex]\( E_0 \)[/tex] is given by Coulomb's law:

[tex]\[ F_{\text{electric}} = qE_0 \][/tex]

The gravitational force [tex](\( F_{\text{gravity}} \))[/tex] acting on the droplet with mass [tex]\( m \)[/tex] in a gravitational field [tex]\( g \)[/tex] is given by:

[tex]\[ F_{\text{gravity}} = mg \][/tex]

At equilibrium, these forces balance each other:

[tex]\[ qE_0 = mg \][/tex]

Solving for [tex]\( q \):[/tex]

[tex]\[ q = \frac{mg}{E_0} \][/tex]

So, the expression for the droplet's charge [tex]\( q \)[/tex] is:

[tex]\[ q = \frac{mg}{E_0} \][/tex]

Which are the components of a typical refracting telescope? hints?

Answers

covex object and concave eyepiece.

The components of a typical refracting telescope are basically convex object and convex eyepiece. The correct option is 1.

A typical refracting telescope is made up of a series of convex lenses. The objective lens is a convex lens positioned at the front of the telescope that collects and focuses light from distant objects. At the focus point, it creates an inverted actual picture.

The eyepiece, which is located at the telescope's back end, is likewise a convex lens. Its goal is to amplify the picture created by the objective lens so that the viewer may see a bigger, upright, magnified image.

In a standard refracting telescope, the correct combination is a convex objective lens and a convex eyepiece.

Thus, the correct option is 1.

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Your question seems incomplete, the probable complete question is:

Which are the components of a typical refracting telescope?

1.convex object and convex eyepiece

2. concave object and convex eyepiece

3. convex object and concave eyepiece

15. To use your left hand to determine the direction of the voltage developed in a moving conductor in a stationary magnetic field, you must point your A. forefinger in the direction of the motion. B. forefinger in the direction of the lines of force. C. thumb in the direction of the electromagnetic force. D. thumb in the direction of the magnetic flux.

Answers

Correct answer choice is:

B. forefinger in the direction of the lines of force.

Explanation:

The direction of the force - and consequently the transfer of the wire - can be defined by applying Fleming’s left-hand rule.

The forefinger tends to the direction of the magnetic field. The middle finger points in the course of the current. The thumb supplies the direction of force or movement working on the conductor. Fleming's Left Hand Rule is applied in electronic engines which are utilized in coolers, appliances, printers, etc.

An airport has runways only 198 m long. a small plane must reach a ground speed of 39 m/s before it can become airborne. what average acceleration must the plane's engines provide if it is to take off safely from its airport? answer in units of m/s 2 .

Answers

s: 198 m 
v=39 m/s 
u=0
t=? 
a=?

v²=u²+2as
(39)²=(0)²+2(a)(198) 
1521=396a
1521/396=a
3.84 m/s^2 = a 

Hope I helped :) 

A person's height and weight will change gradually, while other things, such as getting a driver's license, may occur suddenly and mark the beginning of a new phase in life. This difference is an example of the theme of development known as:

Answers

Continuity vs. Stages --APEX

Answer:

Continuity vs. Stages

Explanation:

Continuity is the gradual changes that a person may experiment throught their life, good examples are the ones given in the question, height and weght increasing or changing over time, but stages start whenever something happens that changes the way of life of the person, for example graduating college and going into the labor force, or getting married.

Two masses m1 = 5.40 kg and m2 which has a mass 80.0% that of m1, are attached to a cord of negligible mass which passes over a frictionless pulley also of negligible mass. If m1 and m2 start from rest, after they have each traveled a distance h = 2.00 m, use energy content to determine the following.

(a) speed v of the masses

Answers

2.09 m/s OK, you have 2 masses.. m1 = 5.40 kg and m2 is 80% of that or 0.80 * 5.40 = 4.32 kg. With the setup, The total mass of the system is 5.40 kg + 4.32 kg = 9.72 kg The kinetic gained from the falling mass is 5.40 kg * 2 m * 9.8 m/s^2 = 105.84 kg m^2/s^2 The kinetic energy lost from the rising mass is 4.32 kg * 2 m * 9.8 m/s^2 = 84.672 kg m^2/s^2 So the total kinetic energy gained by the system is 105.84 kg m^2/s^2 - 84.672 kg m^2/s^2 = 21.168 kg m^2/s^2 Now this energy has been working on a system with a total mass of 9.72 kg, so 21.168 kg m^2/s^2 / 9.72 kg = 2.177777778 m^2/s^2 over a distance of 2m, so 2.177777778 m^2/s^2 / 2 m = 1.088888889 m/s^2 So the effective acceleration your system is undergoing is 1.089 m/s^2 Now to calculate the speed. Distance under constant acceleration is d = 0.5 A T^2, so plugging in the known values and solving for T gives: 2 m= 0.5 * 1.089 m/s^2 T^2 2 m = 0.5445 m/s^2 T^2 3.673094582 s^2 = T^2 1.92 s = T Multiply the time by the acceleration gives: 1.92 s * 1.089 m/s^2 = 2.09 m/s Note, the acceleration of 1.0888889 m/s^2 can be easily obtained using the relative masses of the two objects. We have an object of mass 1 and a second object of mass 0.8 for a total mass of 1.8, this mass is being accelerated by the difference of 0.2, so the effective acceleration is 0.2/1.8 = 0.111111 times that of the local gravity, which is 9.8 m/s^2. And 0.11111 * 9.8 = 1.088889 m/s^2.
Final answer:

To determine the speed of the masses after traveling a distance of 2.00 m, we can use the principle of conservation of energy.

Explanation:

To determine the speed of the masses after traveling a distance of 2.00 m, we can use the principle of conservation of energy. The initial potential energy of the system is equal to the final kinetic energy. The potential energy is given by m1gh, where g is the acceleration due to gravity and h is the distance traveled. The kinetic energy is given by (1/2)m1v^2 + (1/2)m2v^2, where v is the speed of the masses.

Given that m2 has a mass of 80.0% of m1, m2 = 0.80 * m1. Plugging this information into the equation and solving for v, we get:

v = √(2gh / (m1 + m2))

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in a 4 kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third kilometer in 6.3 minutes, and the final kilometer in 6 minutes. the average speed of the runner for the race is approximately

Answers

To find the average of data collected, add all of the measurements: 5.9+6.2+6.3+6= 12.2

Then, divide the total amount by the number of data collected which is 4: 12.2/4= 3.05

The average speed of the runner of the race is approximately 3.05 km/min

Feel free to ask me any other questions you might have :)

Answer:

9.83 km/h

Explanation:

Given: in a 4 kilometer race, a runner completes the first kilometer in 5.9 minutes, the second kilometer in 6.2 minutes, the third kilometer in 6.3 minutes, and the final kilometer in 6 minutes.

To Find:  the average speed of the runner for the race.

Solution:

In a 4 kilometer race,

time required to travel first kilometer = [tex]5.9[/tex] [tex]\text{minutes}[/tex]

time required to travel seoond kilometer = [tex]6.2[/tex] [tex]\text{minutes}[/tex]

time required to travel third kilometer = [tex]6.3[/tex] [tex]\text{minutes}[/tex]

time required to travel final kilometer = [tex]6[/tex] [tex]\text{minutes}[/tex]

we know that,

[tex]\text{Average speed}=\frac{\text{Total distance traveled}}{\text{Total time taken}}[/tex]

Total distance traveled = [tex]4[/tex]  [tex]\text{kilometer}[/tex]

Total time taken = [tex](5.9+6.2+6.3+6)[/tex]

                           =  [tex]24.4[/tex] [tex]\text{minutes}[/tex]

                           = [tex]\frac{24.4}{60}[/tex]  [tex]\text{hours}[/tex]

putting values,

[tex]\text{Average speed}=\frac{4}{\frac{24.4}{60}}[/tex]

 [tex]\text{Average speed}=\frac{4\times60}{24.4}[/tex]

                                            =[tex]9.83[/tex] [tex]\text{km}/ \text{h}[/tex]

the average speed of the runner for the race is approximately [tex]9.83[/tex] [tex]\text{km}/ \text{h}[/tex]

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