TAKE ALL MY POINTS PLEASE HELP ME
The high temperatures for Dallas, Texas in June 1985 and June 2013 are shown. Use the data to create a comparative dot plot and comparative box plot and use them to compare the weather then and now. Remember to use at least two module vocabulary words in your responses.

1. Create a comparative dot plot for the data sets.

2. Assess the degree of overlap between the data sets and compare the shapes, centers, and spreads of the two groups using the comparative dot plot.

3. Create a comparative box plot for the data sets.

4. Assess the degree of overlap between the data sets and compare the shapes, centers, and spreads of the two groups using the comparative box plot.

you need to find the mean on these numbers that is step one in finding standard deviation. so this is 44.2. now you need to subtract the mean from each number and square the result. after that step you now have these numbers.... 3.24, 139.24, .64, .4,.64,282.24,116.64,77.44,27.04. now the next step is to find the mean of these numbers. you get 71.9 appx.. now all you do is square root this number you get 8.5 when you round to the nearest thenth

Answer:

0.5 hour

Step-by-step explanation:

Given

Speed of Dina = 10 km/h

Distance = 20 km

So the time Dina taken to complete the track is:

[tex]Speed=\frac{distance}{time}\\10=\frac{20}{time}\\time=\frac{20}{10}\\ time=2\ hours[/tex]

The time taken by Dina is 2 hours. As masha started with dina but she was 4 km of the path left to cycle,

her distance covered in 2 hours was:

[tex]Distance\ covered\ by\ Masha\ in\ 2\ hours=20-4\\=16 km[/tex]

So we know the time and distance:

Now,

[tex]Speed\ of\ Masha=\frac{distance}{time}\\ =\frac{16}{2}\\ =8\ kilometer\ per\ hour[/tex]

We have to calculate the time that will be needed by MAsha to complete the track:

As we know the speed and remaining distance

[tex]Speed=\frac{distance}{time}\\8=\frac{4}{time}\\ time=\frac{4}{8}\\time=0.5\ hours[/tex]

Masha needs 0.5 hour to complete the track ..

Answer:

30 minutes

Step-by-step explanation:

The answer is:

The correct option is:

B)  [tex]5^{12}\div5^{4}=5^{8}[/tex]

To solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

[tex]\frac{a^{m} }{a^{n} }=a^{m-n}[/tex]

If we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

So, we are given the expression:

[tex]5^{12}\div5^{4}[/tex]

Which is equal to write:

[tex]\frac{5^{12} }{5^{4}}[/tex]

Then, calculating we have:

[tex]\frac{5^{12} }{5^{4}}=5^{12-4}=5^{8}[/tex]

Hence, the answer is:

B)  [tex]\frac{5^{12} }{5^{4}}=5^{8}[/tex]

or

 [tex]5^{12}\div5^{4}=5^{8}[/tex]

Have a nice day!

Answer:

The correct answer is option B. 5^8

Step-by-step explanation:

Points to remember

Identities

xᵃ * xᵇ = x⁽ᵃ ⁺ ᵇ⁾

xᵃ/xᵇ = x⁽ᵃ ⁻ ᵇ⁾

x⁻ᵃ = 1/xᵃ

To find the correct option

It is given an expression, 5^12 ÷ 5^4  

⇒ 5¹²/5⁴

By using identities we can write,

5¹²/5⁴ = 5⁽¹² ⁻ ⁴⁾

 = 5⁸

Therefore the correct answer is option B. 5^8

Answer:

It has no horizontal asymptote

Step-by-step explanation:

It has no horizontal asymptote.  This is a cubic function which has the end behavior of the left tail down and the right tail up, so both the domain and the range are infinity.  That means that there is no horizontal asymptote to go through.  Because it is not a rational function, there are no vertical asymptotes that could make the denominator go to 0 since there is no denominator (not rational).

Answer:

C,

It crosses the horizontal asymptote at the origin.

Step-by-step explanation:

Plato

Answer:

The probability of missing both two-point conversion attempts is 7.5%

Step-by-step explanation:

We are informed that the probability of missing the first attempt is 50% of the time. Furthermore, the probability of missing on the second attempt given that he missed the first attempt is 15% of the time

Now,the probability of missing on both the two-point conversion attempts will simply be given by the product of these two probabilities since the events are independent;

50%*15% = 0.5 * 0.15 = 7.5%

Therefore, the probability of missing both two-point conversion attempts is 7.5%

Answer:

The probability of missing both two-point conversion attempts is 7.5%

Step-by-step explanation:

^^

Given that Peter contributes 20% of the total money and his part is $4.00, it is deduced that the total combined amount the five brothers have is $20.00.

To solve this, we can set up a simple proportion where 20% (or 0.20 in decimal form) of the total amount is equal to $4.00.

Step-by-Step Solution:

Let x represent the total combined amount of money that Peter and his brothers have.

Since Peter contributes 20% of the total, we can express this as 0.20 imes x = $4.00.

To find x, we divide both sides of the equation by 0.20, giving us x = $4.00 / 0.20.

By performing the division, we find that x = $20.00.

Therefore, the total combined amount Peter and his brothers have is $20.00.

Answer:

A) 6

Step-by-step explanation:

This would be your best answer.

Answer:

30th percentile:109

90th percentile: 188

Step-by-step explanation:

The given data set is:

129, 113, 200, 100, 105, 132, 100, 176, 146, 152

We arrange the data set in ascending order to obtain;

Array= [tex]100,100,105,113,129,132,146,176,200[/tex]

The 30th percentile is located at

[tex](\frac{30}{100}\times 10 )}[/tex] -th position, where n=10 is the number of items in the data set

This implies that the 30th percentile is at the 3rd position.

Since 3 is an integer, the 30th percentile is the average of the 3rd and 4th occurrence in the array;

This implies that the 30th percentile = [tex]\frac{105+113}{2}=\frac{218}{2}=109[/tex]

The 90th percentile is located at

[tex](\frac{90}{100}\times 10 )}[/tex] -th position, where n=10 is the number of items in the data set

This implies that the 90th percentile is at the 9th position.

Since 9 is an integer, the 90th percentile is the average of the 9th and 10th occurrence in the array;

This implies that the 90th percentile = [tex]\frac{176+200}{2}=\frac{376}{2}=188[/tex]

Answer:

The measure of angle A is 115°

Step-by-step explanation:

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

∠C+∠A+∠B=180°

substitute values and solve for x

x°+(3x-35)°+(x-35)°=180°

5x°=180°+70°

x=250°/5=50°

Find the measure of angle A

∠A=(3x-35)°

substitute the value of x

∠A=(3(50)-35)=115°

Answer:

[tex]m\angle A=115\degree[/tex]

Step-by-step explanation:

The sum of angles in a triangle is 180 degrees.

[tex]\implies (x-35)\degree+x+(3x-35)\degree=180\degree[/tex]

[tex]\implies 5x-70\degree=180\degree[/tex]

[tex]\implies 5x=180+70[/tex]

[tex]\implies 5x=250[/tex]

Divide both sides by 5.

[tex]\implies x=50[/tex]

We substitute the value of angle A to obtain:

[tex]m\angle A=3(50)-35[/tex]

[tex]m\angle A=115\degree[/tex]

[tex]\bf \begin{array}{ccll} tons&weeks\\ \cline{1-2}\\ \frac{3}{4}&1\frac{1}{2}\\\\ 2&x \end{array}\implies \cfrac{~~\frac{3}{4}~~}{2}=\cfrac{~~1\frac{1}{2}~~}{x}\implies \cfrac{~~\frac{3}{4}~~}{2}=\cfrac{~~\frac{3}{2}~~}{x}\implies \cfrac{~~\frac{3}{4}~~}{\frac{2}{1}}=\cfrac{~~\frac{3}{2}~~}{\frac{x}{1}} \\\\\\ \cfrac{3}{4}\cdot \cfrac{1}{2}=\cfrac{3}{2}\cdot \cfrac{1}{x}\implies \cfrac{3}{8}=\cfrac{3}{2x}\implies 6x=24\implies x=\cfrac{24}{6}\implies x=4[/tex]

Answer:

I think I could help you

Have fun and feel free to ask me something new.

Or we can prove some properities without calculating by details

Step-by-step explanation:

I think I could help you

Have fun and feel free to ask me something new.

Or we can prove some properities without calculating by details

Answer:  The perimeter of triangle ABC is (112√3 + 168) cm.

Step-by-step explanation:  Given that in isosceles triangle △ABC, AB = BC and CH is an altitude. Also,

CH = 84 cm   and  

[tex]m\angle HBC = m\angle BAC+m\angle BCH~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]

We are to find the perimeter of triangle ABC

Since AB = BC, so the angles opposite to them are congruent and have equal measures.

That is, [tex]m\angle BAC=m\angle ACB~~~~~~~~~~~~~~~~~~~~~~~~(ii)[/tex]

Now, since angle HBC is an exterior angle of triangle ABC and triangles BAC and ACB are remote interior angles.

So, we have

[tex]m\angle HBC=m\angle BAC+m\angle ACB\\\\\Rightarrow m\angle BAC+m\angle BCH=m\angle BAC+m\angle ACB\\\\\Rightarrow m\angle ACB=m\angle BCH.[/tex]      

Therefore, from equation (i) implies that

[tex]m\angle HBC = m\angle BAC+m\angle BCH\\\\\Rightarrow m\angle HBC=m\angle BCH+m\angle BCH~~~~~~~[\textup{applying equations (ii) and (iii)}]\\\\\Rightarrow m\angle HBC=2m\angle BCH.[/tex]

Now, from angle sum property in triangle BCH, we have

[tex]m\angle HBC+m\angle BCH+m\angle BHC=180^\circ\\\\\Rightarrow 3m\angle BCH+90^\circ=180^\circ\\\\\Rightarrow 3m\angle BCH=90^\circ\\\\\Rightarrow m\angle BCH=30^\circ.[/tex]

So, we get

[tex]m\angle BAC=m\angle ACB=m\angle BCH=30^\circ,\\\\m\angle HBC=2\times30^\circ=60^\circ.[/tex]

In right-angled triangle ACH, we have

[tex]\tan 30^\circ=\dfrac{CH}{AH}\\\\\\\Rightarrow \dfrac{1}{\sqrt3}=\dfrac{84}{AH}\\\\\\\Rightarrow AH=84\sqrt3.[/tex]

In right-angled triangle BCH, we have

[tex]\tan 60^\circ=\dfrac{CH}{BH}\\\\\\\Rightarrow \sqrt3=\dfrac{84}{BH}\\\\\\\Rightarrow BH=\dfrac{84}{\sqrt3}.[/tex]

And,

[tex]\sin 60^\circ=\dfrac{CH}{BC}\\\\\\\Rightarrow \dfrac{\sqrt3}{2}=\dfrac{84}{BC}\\\\\\\Rightarrow BC==\dfrac{168}{\sqrt3}=56\sqrt3.[/tex]

Therefore,

[tex]AB=AH-BH=84\sqrt3-\dfrac{84}{\sqrt3}=\sqrt3(84-28)=56\sqrt3.[/tex]

Now, in triangle ACH,

[tex]\sin 30^\circ=\dfrac{CH}{AC}\\\\\\\Rightarrow \dfrac{1}{2}=\dfrac{84}{AC}\\\\\Rightarrow AC=168.[/tex]

Thus, the perimeter of triangle ABC is given by

[tex]P=AB+BC+CA=56\sqrt3+56\sqrt3+168=112\sqrt3+168.[/tex]

The perimeter of triangle ABC is (112√3 + 168) cm.

ANSWER

The correct choices are:

[tex] {8a}^{15} - 27[/tex]

and

[tex]216 {a}^{6} - 27 {y}^{3} [/tex]

EXPLANATION

A difference of perfect cube is of the form:

[tex] {(m)}^{3} - {(n)}^{3} [/tex]

We can rewrite

[tex]216 {a}^{6} - 27 {y}^{3} [/tex]

Try rewriting the terms as powers to an exponent of 3.

[tex]216 {a}^{6} - 27 {y}^{3} = {6}^{3}( {a}^{2})^{3} - {3}^{3} {y}^{3} [/tex]

This implies that:

[tex]216 {a}^{6} - 27 {y}^{3} = ( 6 {a}^{2})^{3} - {(3y)}^{3} [/tex]

Hence this is a difference of perfect cube.

Also, we can rewrite

[tex] {8a}^{15} - 27[/tex]

as

[tex]{8a}^{15} - 27 = {2}^{3} ( {a}^{5})^{3} - {3}^{3} [/tex]

[tex]{8a}^{15} - 27= {(2{a}^{5})}^{3} - {3}^{3} [/tex]

Answer:

D. f(2) = 0

Step-by-step explanation:

If x-2 is a factor of a function, then f(2) must be zero

f(x) = p(x) * (x-2) since (x-2) is a factor of f(x)

Substitute in x=2

f(2) = p(2) (2-2)

f(2) = p(2) *(0)

Anything times 0 = 0

f(2) = 0

Answer:

$0.84

Step-by-step explanation:

The expected value of target A = 12% of $7

12% = [tex]\frac{12}{100}[/tex] = 0.12

expected value of A  = 0.12 × $7 = $0.84

Answer:

D

Step-by-step explanation:

Use the formula for the SA of a hemisphere.

[tex]SA=2\pi r^2[/tex]

Now we can find the radius of the hemisphere, which is 15.

Then, we can square that and multiply it by 2 to get 450.

Now, let's use the formula for the Volume of a hemisphere.

[tex]V=\frac{2\pi r^3}{3}[/tex]

Now we can cube 15 and multiply it by 2 to get 6750.

Then we can divide this number by 3.

2250.

So the answer is D.

The median is 12.

The arithmetic mean is 12.7

The geometric mean is 11.3

Answer: r=16tan theta sec theta

Step-by-step explanation:

I have this question on my test but all the answers are different except that one

The polar form of the parametric equation is option (A), r = 16 tan theta sec theta is the correct answer.

Polar form of a complex number is represented by a line whose length is the amplitude and by the phase angle. A polar form of a vector is denoted by  ( , ) , where represents the distance from the origin and represents the angle measured from the -axis.

Given the parametric equations x=4t and y=t².

Consider x= 4t

⇒ t = x/4

Now substitute  t in y equation,

[tex]y= (\frac{x}{4} )^2[/tex]

[tex]y=\frac{x^2}{16}[/tex]

We know that in polar form,

x= r cosθ and y= r sinθ

Now y becomes

r sinθ= [tex]\frac{r^2\cos^2\theta}{16}[/tex]

16 r sin θ = r² cos²θ

r = 16 sinθ/cos²θ

⇒r =16 tanθ secθ

Hence we can conclude that the polar form of the parametric equation is option (A), r = 16 tan theta sec theta is the correct answer.

Learn more about the polar form here:

brainly.com/question/2272407

#SPJ2

Answer:

85%

Step-by-step explanation:

If the sporting goods store received a lot of 80 baseball caps... and 12 of them were green that means that 68 (80-12) were NOT green.

Thus, the probably to randomly pick up a cap that is NOT green is 68 out of 80...

68/80 = 17/20 = 85%

Answer:

Padma pays $11 dollars a month for the sports channel. I do not see the question for the magazine:(

Step-by-step explanation:

To work this out, you find out how many triangles can fit into the shape.

To do this, you take the number of sides and subtract it by 2.

So in a polygon with 11 sides, there are:

9 triangles          (11 - 2 = 9)

Remember, the total number of angles in one triangle is 180 degrees.

So to work out the total number of angles in a polygon, you multiply the number of triangles in it by 180.

So the total sum of interior angles in a polygon with 11 sides is:

180 x 9  = 1620 degrees          (180 degrees times number of triangles)

-------------------------------------------------------------

Answer:

1620 degrees

The question is asking to solve a problem that'll "add up", or in other words, makes sense; through the use of Trigonometric functions. The leaning ladder is the hypotenuse of 17ft, adjacent to that is a wall that measures 16.5ft above the ground. The angle both sides make must be <=70°. The function here is Opposite over Hypotenuse i.e 16.5/17 . We use the inverse operation of Sin which is Sin^(-1) to find if the angle is < or = to 70°. Using a calculator, we find the angle to be 76.06°, which is > more than, 70°.

Thus, the ladder will not be safe for its height and therefore won't make sense.

Answer:

Required logarithmic function is :

[tex]f\left(x\right)=\log_3\left(x\right)[/tex]

Step-by-step explanation:

We have been fiven that table for the logarithmic function is:

x f(x)

9 2

27 3

81 4

which can be rewritten as:

x f(x)

3^2 2

3^3 3

3^4 4

Which are basically powers of 3

So we can use logarithmic function as

[tex]\log_3\left(9\right)=\log_3\left(3^2\right)=2\log_3\left(3\right)=2(1)=2[/tex]

Hence required logarithmic function is :

[tex]f\left(x\right)=\log_3\left(x\right)[/tex]

Answer:

46 craft sticks per student

Step-by-step explanation:

The simplest situation would be that in which the available 644 craft sticks are evenly divisible by the number of students receiving them.  If that's the case, all we have to do is to divide:

644 craft sticks

----------------------- = 46 craft sticks per student

     14 students

Answer:  The point is (-2, 7)

Step-by-step explanation:

If we have a function f(x) and we apply the transformation

[tex]y = f (x + h)[/tex] then ::

If [tex]h <0[/tex] the graph of f(x) moves horizontally h units to the right

If [tex]h> 0[/tex] the grace of f(x) moves horizontally h units to the left

In this case we have the function f(x) and the point (0,7) and the transformation [tex]y = f (x + 2)[/tex]

Then [tex]h = 2> 0[/tex]. Therefore the graph of f(x) moves 2 units towards the left.

Therefore the point (0,7) moves 2 units to the left and we have the point (-2, 7) in the transformed function

Step-by-step explanation:

The letters of the word troposphere can be sorted to be:

ee h oo pp rr s t

with 7 distinct letters of which 4 are in pairs for a total of 11 letters.

The number of words that can be formed from n distinct letters

= n!/(1!1!1!....1!)   [n times in the denominator]

The number of words that can be formed from n letters of which 2 are duplicated and the rest distinct is

= n!/(2!1!1!....1!)     [n-1 times 1!]

Similarly, the number of words that can be formed from 11 letters, of which there are 4 pairs of duplicated letters is

N=11! / (2!2!2!2!1!1!1!)

= 39916800 / (2*2*2*2*1*1*1)

= 2494800

Answer:

The parent function y = 0.5x is DECREASING  across its domain because its base, b, is such that 0<b<1.

The function, f, shifts the parent function 8 units UP .

The function, f, shifts the parent function 5 units RIGHT .

Translation involves moving a function vertically or horizontally.

The function [tex]\mathbf{y = 0.5^{x- 5} + 8}[/tex] shifts the parent function 5 units right, and 8 units up.

The parent function is given as:

[tex]\mathbf{y = 0.5^x}[/tex]

Move the function right, by 5 units

[tex]\mathbf{y = 0.5^{x- 5}}[/tex]

Move the function up by 8 units

[tex]\mathbf{y = 0.5^{x- 5} + 8}[/tex]

So, the function [tex]\mathbf{y = 0.5^{x- 5} + 8}[/tex] shifts the parent function 5 units right, and 8 units up.

Read more about translations at:

https://brainly.com/question/12463306

Answer:

50.29 in^2

Step-by-step explanation:

From the circumference we need to find the radius.

Since C = 2*pi*r, r = C / (2*pi).

Here, with C = 25  1/7 in, r = (25  1/7 in) / [ 2(22/7) ], or r = 4 in

The area of the cake is A = pi*r^2, or (here)  A = (22/7)(4 in)^2 = 50.29 in^2

Answer:

C C C C

Step-by-step explanation:

DONT LISTEN TO THE FIRST GUY ITS C THEY MADE A MATH ERRORRR

Answer:

[tex]f(g(x)) = 16x ^ 4-32x ^ 2 + 18[/tex]

Step-by-step explanation:

we have two functions

[tex]f (x) = x ^ 2 -2x + 3\\\\g (x) = 4x ^ 2-3[/tex]

We wish to find the compound function f(g(x))

To find f(g(x)) you must introduce the function g(x) within the function f(x). This is change the variable x, in the function f(x), by g(x).

[tex]f (g (x)) = (4x ^ 2-3) ^ 2 - 2 (4x ^ 2-3) +3[/tex]

Now simplify the expression:

[tex]f (g (x)) = 16x ^ 4-24x ^ 2 + 9 - 8x ^ 2+6 +3\\\\f(g(x)) = 16x ^ 4-32x ^ 2 + 18[/tex]

ANSWER

[tex]f(g(x)) = 16 {x}^{4} -3 2{x}^{2} +18[/tex]

EXPLANATION

The given functions are:

[tex]f(x)={x}^{2} - 2x + 3[/tex]

and

[tex]g(x) = 4 {x}^{2} - 3[/tex]

We want to find

[tex]f(g(x)) = f(4 {x}^{2} - 3)[/tex]

This implies that;

[tex]f(g(x)) = ( 4 {x}^{2} - 3)^{2} - 2(4 {x}^{2} - 3) + 3[/tex]

We expand to get,

[tex]f(g(x)) = 16 {x}^{4} - 24 {x}^{2} + 9- 8 {x}^{2} + 6+ 3[/tex]

[tex]f(g(x)) = 16 {x}^{4} -3 2{x}^{2} +18[/tex]

d = 92+6 = 98

an = a1 + 98 (n-1)

a1=a19-98 (n-1)

a1=-92 -98 * 18

=-1856

It’s A ( an = -1856+98(n-1) )