x+x-1+x+1 =120
3x=120
x=40
40-1=39
40+1 =41
39 +40 +41 = 120
ages are 39 40 & 41
A football is thrown with an initial upward velocity of 25 feet per second from a height of 5 feet above the ground. The equation h = −16t^2 +25t + 5 models the height in feet t seconds after it is thrown. After the ball passes its maximum height, it comes down and hits the ground. About how long after it was thrown does it hit the ground?
Answer:
1.74 second long after it was thrown does it hit the ground.
Step-by-step explanation:
Given : A football is thrown with an initial upward velocity of 25 feet per second from a height of 5 feet above the ground. The equation [tex]h =-16t^2+25t+5[/tex] models the height in feet t seconds after it is thrown.
To find : How long after it was thrown does it hit the ground?
Solution :
The equation model is [tex]h(t)=-16t^2+25t+5[/tex]
After the ball passes its maximum height, it comes down and hits the ground.
i.e. h=0
So, [tex]-16t^2+25t+5=0[/tex]
Solve by quadratic formula of equation [tex]ax^2+bx+c=0[/tex] is [tex]x = \frac{-b \pm \sqrt{b^2-4ac}}{2a}[/tex]
Here, a=-16 , b=25 and c=5
[tex]t=\frac{-25 \pm \sqrt{(25)^2-4(-16)(5)}}{2(-16)}[/tex]
[tex]t=\frac{-25 \pm \sqrt{625+320}}{-32}[/tex]
[tex]t=\frac{-25 \pm \sqrt{945}}{-32}[/tex]
[tex]t=\frac{-25+\sqrt{945}}{-32},\frac{-25-\sqrt{945}}{-32}[/tex]
[tex]t=-0.179,1.741[/tex]
We reject t=-0.179.
Therefore, 1.74 second long after it was thrown does it hit the ground.
Jamie has a deck of 60 sports cards, of which some are baseball cards and some are football cards. jamie pulls out a card randomly from the deck, records its type, and replaces it in the deck. jamie has already recorded three baseball cards and nine football cards. based on these data, what is, most likely, the number of baseball cards in the deck?
12
15
24
30
3 baseball + 9 football 9+3 = 12
3 out of 12 were base ball
3/12=0.25
60*0.25 = 15
so there would be 15 baseball cards
Answer:
The answer is 15
Step-by-step explanation:
i took the test
If you earn one penny every 10 seconds of your life ,how many dollars would you have after 65 years?
There are 60 seconds in a minute, 60 minutes in an hour, 24 hours in a day, and 365 days in a year. You are assuming that 65 years is the length. We will find the number of seconds in 65 years.
60 x 60 x 24 x 365 x 65 = 2,049,840,000 seconds.
We should note that every 4 years there is an extra day, so if we find 65 % 4 or the modulus of 65 then we can add this. The modulus of this is 16.
60 x 60 x 24 x 16 x 65 = 89,856,000 seconds
2,139,696,000 seconds (when you add the two calculations together).
You are finding it "every 10 seconds" so divide this value by 10. Then divide by another 100 because you are only counting dollars and 100 pennies is equal to 1 dollar.
The answer is : $2,139,696
32x - 4 = 4x2 + 60 For the equation shown, choose the description of the solutions.
Final answer:
The quadratic equation 32x - 4 = 4x2 + 60 has real and equal solutions after rearranging to 4x2 - 32x + 64 = 0 and recognizing it as a perfect square.
Explanation:
To solve the equation 32x - 4 = 4x2 + 60, we first rearrange it into standard quadratic form ax2 + bx + c = 0.
We move all terms to one side: 4x2 - 32x + 64 = 0. Once in this form, we can use the quadratic formula, x = (-b ± √(b2 - 4ac)) / (2a), or factor if it is factorable, to find the solutions for x. After rearranging, we note that the quadratic is a perfect square, giving us (2x - 8)2 = 0, which means that the solution for x is 4, with multiplicity of two since it is a repeated root.
The description of the solutions would be that they are real and equal, since we have a repeated solution.
Reduce the following fraction: -36x^4y^4z^5/-12x^6y^3z
A. -3x^2yz^4
B. 3yz^4/1x^2
C. -9yz^5/-3x^2
D. 36yz^5/12x^2
600 is 1/10 of6000 true or false
A furniture store is having a going-out-of-business sale. Two hours after opening, there are 415 sofas still available. Three hours later, there are 301 sofas available. How many hours will the store have to stay open to sell the entire inventory? Assume the sales rate is constant and round your answer to the nearest whole hour.
Consider an assembly line with 20 stations. Each station has a 0.5% probability of making a defect. At the end of the line, an inspection step singles out the defective units. The inspection step catches 80% of all defects. From inspection, units that are deemed to be non-defective are moved to the shipping department. If a defect is found at inspection, it is sent to the rework department. Rework fixes about 95% of the defective units. Units are directly shipped from the rework department with no further inspection taking place. What is the probability that a unit ends up in rework (in decimal form)?
To find the probability of a unit ending up in rework in an assembly line process, you calculate the probabilities at each step of the process, including station defects, inspection, and rework.
To find the probability that a unit ends up in rework, we need to consider the probability at each step:
The probability of a defective unit at any station is 0.5% or 0.005.
The inspection catches 80% of defects, so the probability of defect detection at inspection is 0.8.
For the units that are sent to rework, the rework department fixes about 95% of the defects, making the probability of a defective unit passing rework 0.05.
Calculating the probability that a unit ends up in rework:
Multiplying the probabilities at each step: 0.005 (station) * 0.2 (not caught at inspection) * 0.95 (not fixed at rework) = 0.00095. Therefore, the probability that a unit ends up in rework is 0.00095 or 0.095% in decimal form.
STVU is an isosceles trapezoid. If SV= 3x - 11 and TU = x + 13, find the value of x.
Miguel earns $490 a week, and he works 5 days a week. What is his daily wage?
Answer: $98 per day
Step-by-step explanation:
Let us calculate the amount he is paid per day.
Since Miguel works 5 days a week, we will divide his total pay per week by the number of days he works every week to get the amount of money he is paid daily.
Therefore, daily pay = 490/5
daily pay =$ 98.
Alternatively,
If 5 days ------> $490
1 day------->$x
Cross multiply and work out the value of x:
5x = 490
therefore, x= 490/5
x=$98 /day
Find dy/dx and d2y/dx2, and find the slope and concavity (if possible) at the given value of the parameter. (if an answer does not exist, enter dne.) parametric equations point x = 6 cos θ, y = 6 sin θ θ = π 4
We are given the parametric equations:
x = 6 cos θ
y = 6 sin θ
We know that the derivative of cos a = - sin a and the derivative of sin a = cos a, therefore taking the 1st and 2nd derivates of x and y:
d x = 6 (-sin θ) = - 6 sin θ
d^2 x = -6 (cos θ) = - 6 cos θ
d y = 6 (cos θ) = 6 cos θ
d^2 y = 6 (-sin θ) = - 6 sin θ
Therefore the values we are asked to find are:
dy / dx = 6 cos θ / - 6 sin θ = - cos θ / sin θ = - cot θ
d^2 y / d^2 x = - 6 sin θ / - 6 cos θ = sin θ / tan θ = tan θ
We can find the value of the slope at θ = π/4 by using the dy/dx:
dy/dx = slope = - cot θ
dy/dx = - cot (π/4) = - 1 / tan (π/4)
dy/dx = -1 = slope
We can find the concavity at θ = π/4 by using the d^2 y/d^2 x:
d^2 y / d^2 x = tan θ
d^2 y / d^2 x = tan (π/4)
d^2 y / d^2 x = 1
Since the value of the 2nd derivative is positive, hence the concavity is going up or the function is concaved upward.
Summary of Answers:
dy/dx = - cot θ
d^2 y/d^2 x = tan θ
slope = -1
concaved upward
if the GCF of two numbers is 1, they are called relatively prime. Find three sets of relatively prime numbers
The GCF can be obtained by taking the prime factors of two numbers then multiplying the common prime factors. IF there are none, then the GCF is 1 and the numbers are called relatively prime.
There are a lot of relatively prime numbers. To name three sets:
3 and 19
7 and 20
15 and 28
For these sets, we see that there are no other common factors except 1. To illustrate the factors:
3 = 1, 3
19 = 1, 19
7 = 1, 7
20 = 1, 2, 2, 5
15 = 1, 3, 5
28 = 1, 2, 2, 7
So we see that only the number 1 is the factor in each set.
Final answer:
Three sets of relatively prime numbers are 9 and 16, 14 and 25, and 8 and 21, as they do not share any common prime factors other than 1.
Explanation:
If the Greatest Common Factor (GCF) of two numbers is 1, they are indeed referred to as relatively prime. To find sets of relatively prime numbers, we need to identify pairs of numbers that do not have any prime factors in common other than 1.
9 and 16: The prime factors of 9 are 3· 3, and the prime factors of 16 are 2· 2· 2· 2. They share no common prime factors, so they are relatively prime.
14 and 25: The prime factors of 14 are 2· 7, and the prime factors of 25 are 5· 5. Since they have no common factors, these numbers are also relatively prime.
8 and 21: The prime factors of 8 are 2· 2· 2, and the prime factors of 21 are 3· 7. With no prime factors in common, 8 and 21 are relatively prime.
Therefore, we have found three sets of relatively prime numbers: 9 and 16, 14 and 25, and 8 and 21.
1/2 of a group of chickens tried to cross the road. Only 3/4 of those chickens made it to the other side. What fraction of the original group of chickens made it to the other side?
Answer:
[tex]\frac{3}{8}[/tex] of the group
Step-by-step explanation:
[tex]\frac{1}{2}[/tex] of a group of chickens tried to cross the road.
only [tex]\frac{3}{4}[/tex] of those chickens made it to the other side.
So [tex]\frac{3}{4}[/tex] × [tex]\frac{1}{2}[/tex]
= [tex]\frac{3}{8}[/tex] of the group of chickens made it to the other side.
What is the simplified form of the rational expression below? 5x^2-5 over 3x^2+3x
Find the value of a and z: x5⋅x4=axz a = , z = Find the values of a and z: 6x20+5x20=axz a = , z = Find the value of a and z: (x5)4=axz a = , z = Find the value: x25−x25 = Find the values of a, b and z: 8x−9=abxz a = , b = , z =
To find the values of a and z, we need to solve the given equations. Without specific numerical values, we cannot determine the exact values of a and z.
Explanation:To find the values of a and z, we need to solve the given equations. Let's go through each question:
1. For the equation x^5 * x^4 = axz, we can simplify it as x^9 = axz. Since there is no specific numerical value given, we cannot find the exact values of a and z.
2. Similarly, for the equation 6x^20 + 5x^20 = axz, we can simplify it as 11x^20 = axz. Again, without a specific value for x, we cannot determine the values of a and z.
3. In the equation (x^5)^4 = axz, we can simplify it as x^20 = axz. Without numerical values, we cannot find the exact values of a and z.
4. The equation x^25 - x^25 simplifies to 0. There are no variables to solve for.
5. Lastly, for 8x - 9 = abxz, we cannot determine the values of a, b, and z without additional information.
Your six month old baby has doubled his birth weight, is grasping objects and pulling them to his mouth, and seems hungry all the time despite the eight full bottles he drinks each day. do you start solids yet
I would say that the child is prepared for solid foods because it is capable of grasping things such as food. If the baby can gulp easily and sit up without adjustment solids are okay to switch the child on at this point. Also you can give a child solid food anywhere starting from 4-6 months old.
Supplementary breast milk is given to babies after babies 6 months of age and over with a gradual texture starting from fine, filtered porridge, pureed porridge, then solid food such as adult food. Complementary food for breast milk is better if it contains 4 stars namely carbohydrates, vegetable protein, animal protein, and vegetables.
Further Explanation
When a baby enters the age of 6 months, he needs more calories than just the nutrition he gets through exclusive breastfeeding. At this age, you can introduce your baby's first solid food.
Feeding is not just filling the baby's stomach with nutritious food, but also provides education about pleasant interactions, stimulation of the sense of taste, fine motor training (moving hands and directing to the mouth that requires good coordination between hands, eyes, and of course, the brain), chewing and discipline.
8 Solid Foods for 6-Month-Old Babies
Cereal Banana Sweet Potato Avocado Chicken or Beef Meat Pear Tofu Wheat bread
In addition to some of the foods above, introduce other solid foods as well. Of course, the texture must be adjusted to the stage of growth of the baby. Do not forget, introduce food one by one to see what foods cause allergies in children.
In general, the purpose of first feeding for babies from 6 months of age are:
Meet the nutritional needs of babies. Develops the baby's ability to accept a variety of foods with different tastes and textures. Develops and trains baby's motor skills such as chewing and swallowing.
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Grade: College
Subject: Health
Keyword: complementary, food, baby
The figure has ____ lines of symmetry. A. 0 B. 4 C. 6 D. 8
A figure with 5-part symmetry has 5 lines of symmetry.
Explanation:A figure with 5-part symmetry has 5 lines of symmetry. This means that it can be divided into five equal parts by rotating it around these lines. Each line of symmetry divides the figure into two mirror-image halves.
Which is least? 0.105 0.501 0.015 or 0.15
The lowest decimal number from 0.105, 0.501, 0.015, and 0.15 is 0.015. This is because when we compare the numbers from left to right, 0.015 has the smallest digit (0) at the second decimal place which is the hundredths place.
Explanation:To determine which decimal number is the lowest, it's helpful to compare these numbers digit by digit from the left. The four numbers are 0.105, 0.501, 0.015, and 0.15. Each of them starts with 0. The second digit of 0.105, 0.501, and 0.15 is 1, but the second digit for 0.015 is 0. So, 0.015 is the lowest number because it has the smallest digit (0) in the second decimal place (hundredths place). Remember, these numbers are read as decimals and not as whole numbers, so the digit at each decimal place has a different significance.
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what is the sum of -7/10 + 1/4
As part of Kayla's exercise program, she either runs 6 miles/day or rides her bike 10 miles/day. Her new goal is to cover a minimum distance of 200 miles, with at least 15 of the days running. She would like to determine the number of days it would take to accomplish this.
Answer:
Kayla will be able to cover the distance of 200 miles by riding bike for 11 days and by running for 15 days.
Step-by-step explanation:
Numbers of days Kayla's has to run be x
Numbers of days Kayla's has to ride bike be y
Speed while running = 6 miles/day
Distance covered by running in x days = 6miles/day × x
Speed while riding a bike = 10 mile/day
Distance covered by riding bike in y days = 10 miles/day × y
Distance desired by Kayla to cover = 200 miles
[tex]200miles=6 miles/day\times x+10 miles/day \times y[/tex]
At least 15 of the days running.Put x = 15 days in above equation:
[tex]200miles=6 miles/day\times 15 days+10 miles/day \times y[/tex]
[tex]200 miles - 90 miles=10 miles/day \times y[/tex]
[tex]\frac{110 miles}{10 miles/day}=y[/tex]
y= 11 days
Kayla will be able to cover the distance of 200 miles by riding bike for 11 days and by running for 15 days.
The surface areas of two similar solids are 340 yd2 and 1,158 yd2. The volume of the larger solid is 1,712 yd3. What is the volume of the smaller solid?
Let us say that,
1 = smaller solid
2 = larger solid
We must remember that the surface area of an object is proportional to the square of their sides, therefore,
SA = k s^2
where k is the constant of proportionality.
By taking the ratio of the 2 similar solids:
SA2 / SA1 = k s2^2 / k s1^2
SA2 / SA1 = s2^2 / s1^2
sqrt (SA2 / SA1) = s2 / s1
s2 / s1 = sqrt (1158 / 340)
While the volume of an object is proportional to the cube of
their sides, therefore:
V = k’ s^3
where k’ is the constant of proportionality.
By taking the ratio of the 2 similar solids:
V2 / V1 = k’ s2^3/ k’ s1^3
V2 / V1 = s2^3/ s1^3
1712 / V1 = [sqrt (1158 / 340)]^3
1712/V1 = 6.28556705
V1 = 272.37 yd^3
A container holds 10 quarts of water. How much is this in gallons? Write your answer as a whole number or a mixed number in simplest form
The equation y = ax describes the graph of a line. If the valise of a is positive , the line:
Six years from today you need $10,000. you plan to deposit $1,500 annually, with the first payment to be made a year from today, in an account that pays an 8% effective annual rate. your last deposit, which will occur at the end of year 6, will be for less than $1,500 if less is needed to reach $10,000. how large will your last payment be?
Amount of last payment is approximately $497
Given that;
Number of year = 6 year
Annual deposit = $1,500
Annual rate = 8% = 0.08
Find:
Amount of last payment
Computation:
[tex]Future\ value = Annual\ deposit[(1+r)^n - 1]/r[/tex]
[tex]Future\ value\ of\ the\ 6\ annual\ deposits = 1500[\frac{(1+0.08)^6 - 1}{0.08}][/tex]
[tex]Future\ value\ of\ the\ 6\ annual\ deposits = 1500[(1.08)^6 - 1]/0.08\\\\Future value of the 6 annual deposits = 1500[0.58687]/0.08[/tex]
Future value of the 6 annual deposits = 11,003.25
Future value of the 6 annual deposits = $11,003 (Approx.)
Extra payment = 11,003 - 10,000
Extra payment = $1,003
So,
Amount of last payment = 1,500-1,003
Amount of last payment = $497
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A DELL computer hardware has a yearly 17% rate of failure. Answer the following question. Convert your answer to a percentage. What is the probability that if you buy four computers, at least 1 will fail within a year?
Answer:
Failure of a Single Dell computer in terms of percentage=17%
It means you buy a computer, there is 17% chance that it will be bad Machine and (100-17)%=83% chance that, it will be a good machine.
Probability that if you buy four computers, atleast 1 will fail within a year
[tex]=_{1}^{4}\textrm{P}\times [P(S)]^3\times P(F)+_{2}^{4}\textrm{P}\times [P(S)]^2\times [P(F)]^2+_{3}^{4}\textrm{P}\times P(S)\times [P(F)]^3+_{4}^{4}\textrm{P}\times [P(F)]^4\\\\=4 \times (0.83)^3\times (0.17)+6\times (0.83)^2\times (0.17)^2+4\times (0.83)\times (0.17)^3+1\times (0.17)^4\\\\=0.3881516+0.11945526+0.01631116+0.00083521\\\\=0.52475323[/tex]
=0.53(Approx)
=0.53 × 100
=53%
EASY 5 POINTS!!! Shaundra wants to triple the volume of a square pyramid. What should she do?
Answer: Triple the height of the pyramid
Step-by-step explanation:
To triple the volume of a square pyramid, triple the height of the pyramid. Therefore, the option C is the correct answer.
What is the volume?Volume is the measure of the capacity that an object holds.
Formula to find the volume of the object is Volume = Area of a base × Height.
The volume of a square pyramid refers to the space enclosed between its five faces. The volume of a square pyramid is one-third of the product of the area of the base and the height of the pyramid. Thus, volume = (1/3) × (Base Area) × (Height).
To triple the volume of a square pyramid, triple the height of the pyramid.
Therefore, the option C is the correct answer.
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Suppose a triangle has sides a, b, and c with side c the longest side, and that a^2 + b^2 > c^2. Let theta be the measure of the angle opposite the side of length c. Which of the following must be true? Check all that apply.
the triangle in question is a right triangle
cos(theta) <0
the triangle is not a right triangle
theta is an acute angle
The inequality [tex]a^2 + b^2 > c^2[/tex] indicates that the triangle is not a right triangle and the angle theta is acute. The cosine of an acute angle theta will be positive, not negative.
When it is given that a triangle has sides a, b, and c, with c being the longest side, and the inequality [tex]a^2 + b^2 > c^2[/tex] holds, we can deduce certain characteristics of the triangle and angle theta, which is opposite to side c. This inequality indicates that the triangle is not a right triangle, because for a right triangle, according to the Pythagorean theorem, the relationship between the sides is [tex]a^2 + b^2 = c^2.[/tex]
Since [tex]a^2 + b^2 > c^2[/tex], we can infer that the angle opposite the longest side, theta, must be acute because the sum of the angles in any triangle equals two right angles. Therefore, if theta were obtuse, the sum of the angles would be greater than two right angles, which contradicts the basic properties of triangles.
The correct statements are that the triangle is not a right triangle and that theta is an acute angle. cos(theta) is not necessarily < 0; for an acute angle, the cosine value will be positive. The first statement that the triangle is a right triangle is incorrect because it contradicts our given information and the Pythagorean theorem.
The numbers of seats in the first 12 rows of a high-school auditorium form an arithmetic sequence. The first row has 9 seats. The second row has 11 seats. a) Write a recursive formula to represent the sequence. b) Write an explicit formula to represent the sequence. c) How many seats are in the 12th row?
The recursive formula for the sequence is an = an-1 + 2. The explicit formula is an = 9 + (n-1)(2). There are 31 seats in the 12th row.
Explanation:a) Recursive formula: The difference between the numbers of seats in consecutive rows is always 2. So, the recursive formula can be written as: an = an-1 + 2. Here, an represents the number of seats in the nth row, and an-1 represents the number of seats in the (n-1)th row.
b) Explicit formula: The first term of the arithmetic sequence is 9, and the common difference is 2. The explicit formula can be written as: an = a1 + (n-1)d. Substituting the values, we get an = 9 + (n-1)(2).
c) Seats in the 12th row: Using the explicit formula, we can calculate the number of seats in the 12th row: a12 = 9 + (12-1)(2) = 9 + 22 = 31. So, there are 31 seats in the 12th row.
When a jug is half- filled with marbles, it weighs 2.6 kg. The jug weighs 4 kg when it is full. Find the weight of the empty jug.
the difference between a full jug and a jug that is half full will give us the weight of the marbles only in a half full jug:
4 - 2.6 = 1.4 kg
In a half full jug that weighs 2.6 kg, the weight of the marbles is 1.4 kg
the weight of the jug = 2.6 - 1.4 = 1.2 kg
Answer:
The jug weights empty 1.2 kg.
Step-by-step explanation:
In this case we can define two equations based on the description to find the weight of the empty jug, this is:
Eq. 1: [tex]Jug+\frac{1}{2} Marbles=2.6[/tex]
Eq. 2: [tex]Jug+Marbles=4[/tex]
Now putting the Eq. 2 in the Eq. 1 we have:
[tex]Jug+\frac{1}{2} (4-Jug)=2.6[/tex]
Clearing Jug:
[tex]\frac{1}{2}Jug=2.6-2[/tex]
[tex]Jug=0.6*2[/tex]
[tex]Jug=1.2[/tex]
The jug weights empty 1.2 kg.
Benjamin has $6000 invested in two accounts. One earns 8% interest per year, and the other pays 7.5% interest per year. If his total interest for the year is $472.50, how much is invested at 8%?
Answer:
Benjamin invested $4,500 at 8%.
Step-by-step explanation:
We know that Benjamin has invested $6,000 in two different accounts.
Let account 1 earn 8% interest per year be defined as [tex]x[/tex] and account 2 earn 7.5% interest per year as [tex]y[/tex].
The sum of both accounts must be $6,000:
[tex]x+y=6,000[/tex]
We also know that at the end of the year Benjamin earned $472.50, which is the sum of the interest he earned of the amount he invested in account 1 and in account 2, with their different interest rates (in this case, it is useful for us to transform the expression of the interest rate by dividing it by 100, so that it can be simplified):
[tex](0.08x)+(0.075y)=472.5[/tex]
We need to express the [tex]y[/tex] in terms of [tex]x[/tex].
From our first expression, we know that:
[tex]y=6,000-x[/tex]
So we substitute this value in our second equation and solve it:
[tex](0.08x)+(0.075(6,000-x))=472.5[/tex]
[tex](0.08x)+((0.075*6,000)-0.075x)=472.5[/tex]
[tex](0.08x)+((0.075*6,000)-0.075x)=472.5[/tex]
[tex]0.08x+450-0.075x=472.5[/tex]
[tex]0.08x-0.075x=472.5-450[/tex]
[tex]0.005x=22.5[/tex]
[tex]x=\frac{22.5}{0.005}[/tex]
[tex]x=4,500[/tex]
This way, we know that the amount that Benjamin invested in the account that earns 8% interest per year is $4,500.