The area of a circular place is 45 square inches. Estimate the radius to the nearest integer.

To simplify [tex]\(3x(-11x + 1)\)[/tex], we distribute [tex]\(3x\)[/tex] to both terms inside the parentheses, resulting in [tex]\(-33x^2 + 3x\)[/tex]. Thus, the simplified expression is [tex]\(-33x^2 + 3x\)[/tex]. Therefore, the correct answer is option A) [tex]\(-33x^2 + 3x\)[/tex].

To simplify the expression [tex]\(3x(-11x + 1)\)[/tex], we'll use the distributive property, which states that [tex]\(a(b + c) = ab + ac\)[/tex].

1. **Apply the distributive property**:

  We distribute [tex]\(3x\)[/tex] to both terms inside the parentheses:

   [tex]\[3x \cdot (-11x) + 3x \cdot (1)\][/tex]

2. **Perform multiplication**:

   [tex]\[= -33x^2 + 3x\][/tex]

Now, let's break down each step in detail:

- **Step 1: Apply the distributive property**:

 We distribute [tex]\(3x\)[/tex] to both terms inside the parentheses: [tex]\(-11x\) and \(1\)[/tex]. This results in two separate terms.

- **Step 2: Perform multiplication**:

 Multiply each term inside the parentheses by [tex]\(3x\)[/tex]. This results in:

 [tex]\[3x \cdot (-11x) = -33x^2\][/tex]

 [tex]\[3x \cdot (1) = 3x\][/tex]

 Combining these two terms, we get [tex]\(-33x^2 + 3x\)[/tex].

Therefore, the simplified form of the expression [tex]\(3x(-11x + 1)\) is \(-33x^2 + 3x\).[/tex]

Hence, the correct answer is option A) [tex]\(-33x^2 + 3x\)[/tex].

We are given that about 56% of the 2,553 students are enrolled in at least one honors lass.

So we basically need to find the value of 56% of 2553

converting 56% to decimal we get 56/100 =0.56

now multiplying 0.56 with 2553, we get

0.56*2553=1429.68

Rounding off we get 1430

Answer : 1430 students are enrolled in an honors class

Answer:

Answer : 1430 students are enrolled in an honors class

Step-by-step explanation:

Compound inequalities are used to group at least two inequalities

The open sentence that could result in the solution set is r<6 or r>4

From the question, we understand that the solution set consists of real numbers

From the list of options, only the open sentence r<6 or r>4 satisfy the given condition.

This is so because;

r<6 or r>4 = {4.0...... to 5.99...}

The solution set of other open sentence are not true

Hence, the open sentence that could result in the solution set is r<6 or r>4

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Final answer:

The expression for the number of goals Sarah scored, if Christina scored g goals, is 2g, representing that Sarah scored twice as many goals as Christina.

Explanation:

If Christina scored a certain number of goals, g, during a soccer season, and Sarah scored twice as many goals during the same season, we can write an expression for the number of goals Sarah scored as 2g. This expression simply states that Sarah's goals are double the quantity of Christina's goals.

To think about this conceptually, if Christina scored 5 goals, we would substitute g with 5 and calculate Sarah's goals as 2 × 5, which equals 10 goals. This expression is a straightforward representation of the relationship between the number of goals scored by Christina and by Sarah.

The image that represents the final image after the transformation is: Image 4

Given transformation rule is ry-axis ◦ T3, -1.

First of all, we will reflect the coordinates of LMNP across y axis by the rule: (x, y) -> (-x, y)

Then, we will carry out a translation of shifting 3 units to the right and then 1 unit down.

So, if the original point was (x, y), after the translation of it becomes (x + 3, y - 1 ).

Now, the coordinates of LMNP are:

L (-5, 1)

M (-5, 4)

N(-3, 4)

P(-3, 1).

Then, after reflection from y axis, we have:

L' (5, 1),

M' (5, 4),

N'(3, 4)

P'(3, 1).

Then, after Transformation T (3, -1) the coordinates are:

L' (5 + 3, 1 - 1)  - L"(8, 0),

M' (5 + 3, 4 - 1) = M"(8, 3),

N'(3+3, 4-1) = N"(6, 3),

P'(3+3, 1-1) = P"(6, 0)

Therefore, the required transformed figure is (4).

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To find the values of x and y, we need to set up and solve a system of two equations based on the fact that the angles form a linear pair and are congruent.

You are asked to find the values of x and y in two congruent angles which are linear pairs. A linear pair is a set of adjacent angles whose uncommon sides form a straight line, thus their sum is 180 degrees. Therefore, we can form the equation (7x + 34)° + (2y/3)° = 180°.

Since the two angles are also congruent (meaning they have the same measure), we can also form the equation (7x + 34)° = (2y/3)°. Now you have a system of two equations that you can solve to find the values of x and y.

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To find out how many stamps Scott started with, we can set up an equation. After solving the equation, we find that Scott started with 26 stamps.

To find out how many stamps Scott started with, we can set up an equation using the information given. Let's represent the number of stamps he started with as 'x'. After selling half of them, he would have 'x/2' stamps left. But since he changed his mind and bought sixteen more, he now has 'x/2 + 16' stamps. We know that he currently has 29 stamps, so we can set up the equation: x/2 + 16 = 29. We can solve this equation to find the value of x, which represents the number of stamps Scott started with.

To solve the equation, we can subtract 16 from both sides: x/2 + 16 - 16 = 29 - 16. Simplifying, we get: x/2 = 13. To isolate x, we can multiply both sides of the equation by 2: 2 * (x/2) = 13 * 2. Simplifying, we get: x = 26. Therefore, Scott started with 26 stamps.

The distance between the points (−5, −9) and (−5, 13) would be 22. units.

The shortest distance (length of the straight line segment connecting both given points) between points ( p,q) and (x,y) is:

D = √[(x-p)² + (y-q)²]  

We have been given two points as (−5, −9) and (−5, 13)

Then the distance formula :

D = √[(x-p)² + (y-q)²]  

Now we substitute;

[tex]d = \sqrt{(-5 - (-5)^2 + (13 - (-9)^2}\\d = \sqrt (-5 + 5)^2 + (13 + 9)^2\\d = \sqrt (0^2 + 22^2)\\d = \sqrt (484)\\d = 22[/tex]

Therefore, the distance between the points (−5, −9) and (−5, 13) would be 22. units.

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