The area of the parallelogram is (4x+16)(4x+16) square feet. write an expression for the base. expression for the base: 16x ft

Answers

Answer 1
The area of a parallelogram is given by base * height.

Given that the parallelogram has an area of 4x + 16,

i.e. base * height = 4x + 16.

Therefore, an expression for the base of the parallelogram is given by

[tex]Base= \frac{4x+16}{height} \ ft [/tex]
Answer 2

Answer:

[tex]base=\frac{4x+16}{height}[/tex]   which is the required expression.

Step-by-step explanation:

We have been given the area of parallelogram which is (4x+16)

And the formula for area of parallelogram is [tex]base\cdot height[/tex]

Hence, when we substitute the value if area of parallelogram in the formula we get:

[tex]4x+16=base\cdot height[/tex]

Now, rearranging the terms so, as to get the expression for the base or value of base in terms of height and area we get:

[tex]base=\frac{4x+16}{height}[/tex]   which is the required expression.


Related Questions

Find the next two terms in the sequence. 0, 1, 4, 9, ...


A. 13, 17

B. 13, 18

C. 16, 25

D 16, 23

Answers

0, 1, 4, 9, ...
+1, + 3, +5, +7, + 9, etc....

so 
9 + 7 = 16
16 + 9 = 25

answer
C. 16, 25

Answer:

16, 25

Step-by-step explanation:

the next two terms in the sequence. 0, 1, 4, 9, ...

Lets find the difference between the two terms

1-0 = 1

4-1=3

9-4= 5

the terms are increasing by odd numbers

0, 1, 4, 9, ...

 \/  \/  \/

+1   +3  +5

The next term will increase by +7

9+7= 16

Next term is 16

Next term will increase by 9

16 + 9 = 25

so , next two terms are 16 and 25

Write an equation of the line, in point-slope form, that passes through points (3,-10) and (-5,-2)

Answers

[tex]\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 3}}\quad ,&{{ -10}})\quad % (c,d) &({{-5}}\quad ,&{{ -2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-2-(-10)}{-5-3}\implies \cfrac{-2+10}{-5-3} \\\\\\ \cfrac{8}{-8}\implies -1 \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-10)=-1(x-3)\\\\\\ y+10=-(x-3)[/tex]

Equation of the line, in point-slope form, that passes through points (3,-10) and (-5,-2) is y + 10 = -(x - 3).

What are lines and their slopes?

We know lines have various types of equations, the general type is

Ax + By + c = 0, and equation of a line in slope-intercept form is y = mx + b.

Where slope = m and b = y-intercept.

the slope is the rate of change of the y-axis with respect to the x-axis and the y-intercept is the (0,b) where the line intersects the y-axis at x = 0.

Given it has points (3,-10) and (-5,-2) and we know slope(m)

= (y₂ - y₁)/(x₂ - x₁).

= (-2 + 10)/(-5 - 3).

= 8/-8.

= -1.

Equation of a line in point-slope form is (y - y₁) = m(x - x₁).

y - (-10) = -1(x - 3).

y + 10 = -(x - 3).

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( variable son both sides of an equation)
SHOW ALL WORK AND MAKE SURE IT MAKES SENSE
I WILL GIVE BRAINLIEST WITH BEST ANSWER THAT INCLUDES ALL OF THE ABOVE

Solve: 7b-20=3b+12

Answers

b=8 i hope this helps!!
Start by adding 20 to both sides to isolate '7b'. This gives you 7b = 3b + 32.

Next, Subtract 3b from both sides in order to make it so that the variable, which is 'b' in this case, is on one side of the equation.

This gives you 4b = 32.

Now divide both sides by 4 to cancel out 4b (opposite of multiplication is division).

This brings you to the answer b = 8 (32 divided by 4 is 8).

Hope this helps.

What is the value of x?



Enter your answer in the box.

X=

Answers

12=X 
4x-10=5x-22
     +22     +22
4x+12=5x
-4x      -4x
12=x
4x + 3x + 5x = 12x
-10 -22 = -32 + 2 = -30
12x - 30 + 180
       + 30  + 30
12x = 210
210/12x = 17.5
I think

how many lead cubes of side 3cm could be made from a lead of side 27cm

Answers

Nine lead cubes of side 3cm could be made from a lead of side 27cm. This is because 3+3=6. 6+3=9. 9+3=12. 12+3=15. 15+3=18. 18+3=21. 21+3=24. 24+3=27. Therefore, three goes into twenty-seven a total of nine full times.

Item 19 You pay $40 each month for satellite TV, plus $3.50 for every movie you purchase. Write and solve an equation to find the number of movies purchased during a month with a total bill of $57.50.

Answers

Let x be the number of movies purchased. If each movie you purchase costs $3.50 dollars, this means that the total cost of x movies in one month is $3.50x
In addition, you have to pay $40 for satellite TV. We can now find an equation to find the total cost per month:
40 + 3.50x

Now, by hypothesis, you paid $57.50 during a month as a total bill.
Which means that 40 + 3.50x = 57.50
We need to find the number of movies purchased during that month, or, in mathematical words, we need to solve for x.

40 + 3.50x = 57.50

First, let's put the variables apart and the numbers apart by subtraction 40 from each side, so we get:
40 - 40 + 3.50x = 57.50 - 40
3.50x = 17.50

Now divide both sides by 3.50
(3.50x)/(3.50) = 17.50 / 3.50
x = 5

So, during that month, you purchased 5 movies.

Hope this helps! :)

What does x equal and what does why equal?

Answers

1.

x^2 + 6.4^2 = 8^2

x^2 = 40.96 = 64

x^2 = 64 -40.96

x^2 = 23.04

x = sqrt(23.04) = 4.8


2. y=

y^2 + 3^2 = 5^2

y^2 +9 = 25

y^2 = 25-9

y^2 = 16

y = sqrt(16) = 4

Answer:

x^2 + 6.4^2 = 8^2

x^2 = 40.96 = 64

x^2 = 64 -40.96  

x^2 = 23.04  

x = sqrt(23.04) = 4.8

 y=

y^2 + 3^2 = 5^2

y^2 +9 = 25

y^2 = 25-9

y^2 = 16

y = sqrt(16) = 4

If cats prowl, mice will scatter. Mice are scattering

Answers

The answer should be Cats are prowling
Cats are prowling is the andwer

Find the standard form of the equation of the parabola with a focus at (5, 0) and a directrix at x = -5.

Answers

let's notice, the focus is at (5,0) and the directrix at x = -5.

keep in mind that there's a distance "p" from the vertex to either of those fellows, therefore, if the focus is at 5,0 and the directrix x = -5, the vertex is half-way between them, check the picture below.

notice the distance "p" there, now, is a horizontal parabola, opening to the right, meaning the value for "p" is positive, or just 5, thus

[tex]\bf \textit{parabola vertex form with focus point distance}\\\\ \begin{array}{llll} \boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\ (x-{{ h}})^2=4{{ p}}(y-{{ k}}) \end{array} \qquad \begin{array}{llll} vertex\ ({{ h}},{{ k}})\\\\ {{ p}}=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array}\\\\ -------------------------------\\\\ \begin{cases} h=0\\ k=0\\ p=5 \end{cases}\implies (y-0)^2=4(5)(x-0)\implies y^2=20x \\\\\\ \cfrac{y^2}{20}=x\implies \cfrac{1}{20}y^2=x[/tex]

a segment has endpoints (a,b) and (c,d). The segment is translated so that its image is 6 units up and 3 units left of the preimage. Are the two segments parallel, perpendicular, or neither?

Answers

The translation of the image can be describe as

x – 3

y + 6

 

Since the transformation that is made is purely translation, therefore this means that the original image and the new image will never intersect and hence:

 

Parallel

 

If the two are extended we can actually see that they will never meet.

Find a polynomial function of lowest degree with rational coefficients that has the given numbers as some of its zeros 2+i, 2

Answers

Final answer:

To find a polynomial with given zeros 2+i and 2, include the conjugate 2-i to ensure rational coefficients, resulting in the polynomial x^2 - 4x + 3.

Explanation:

Finding a Polynomial with Given Zeros

To find a polynomial function of the lowest degree with rational coefficients that has 2+i and 2 as some of its zeros, you should remember that complex zeros in polynomials with real coefficients come in conjugate pairs. This means that if 2+i is a zero, so is its conjugate 2-i. You now have three zeros: 2, 2+i, and 2-i.

The polynomial with these zeros can be written as (x-2)(x-(2+i))(x-(2-i)). To find the polynomial, we simply multiply these factors:

(x-2)(x-2+i)(x-2)(x-2) - i(x-2)

Now add the resulting quadratics:

(x-2)2 - i2

This results in:

x2 - 4x + 4 - 1

Which simplifies to x2 - 4x + 3. Thus, the required polynomial function of the lowest degree is x2 - 4x + 3.

Part A: Sam rented a boat at $225 for 2 days. If he rents the same boat for 5 days, he has to pay a total rent of $480.

Write an equation in the standard form to represent the total rent (y) that Sam has to pay for renting the boat for x days. (4 points)

Part B: Write the equation obtained in Part A using function notation.(2 points)

Part C: Describe the steps to graph the equation obtained above on the coordinate axes. Mention the labels on the axes and the intervals. (4 points)

Answers

Part A
Let y = a  + b*x
where
x = number of days
y = cost

When x = 2, y =$225. Therefore
a + 2b = 225                  (1)
When x = 5, y = 480. Therefore
a + 5b = 480                 (2)
Subtract (1) from (2).
3b = 480-225 = 255
b = 85
From (1), obtain
a = 225 - 2*85 = 55

Answer: 
y = 55 + 85x
where x =  the number of days
y = the cost (dollars)

Part B.
The cost is
f(x) = 55 + 85x

Part C
To graph y = 55 + 85x,
The y-intercept is 55
The x-intercept occurs when y = 0. That is
55 + 85x = 0
x = -55/85 = -11/17
The graph is shown below.

The perimeter of a rectangle is 102 cm. if the length is 28 cm, how wide is the rectangle?

Answers

(102 - (28*2)) / 2=
(102 - (56)) / 2 =
(46) / 2 = 23

The width is 23 cm
The answer to this question is 23cm

Aaron bought 132 inches or wire he cut the wire into 9 pieces that were the same lenght what is the length of each piece or wire

Answers

The length of each piece of wire is about 14.7 inches.

What is division?

Division is the process of dividing a number by a given number.

Given that, the length of the wire is 132 inches.

Now, the wire is cut into 9 equal pieces, therefore, the length of each piece is:
132/9

= 14.7 inches

Hence, the length of each piece of wire is about 14.7 inches.

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Identify the 7th term of the geometric sequence in which a2 = 324 and a4 = 36

Answers

the answer is 4/3 or -4/3

Answer:

4/3

Step-by-step explanation:

a2 = 324 and a4 = 36

second term is 324  and fourth term is 36

[tex]a_n= a_1(r)^{n-1}[/tex]

To get second term, replace n with 2

[tex]a_2= a_1(r)^{2-1}[/tex]

[tex]a_2= a_1(r)[/tex]

replace a2 with 324

[tex]324= a_1(r)[/tex] -----------> equation 1

To get fourth term , replace n with 4

[tex]a_4= a_1(r)^{4-1}[/tex]

[tex]a_4= a_1(r)^3[/tex]      

Replace the value

[tex]36= a_1(r)[/tex]  -----------> equation 2

divide second equation by first equation

[tex]36= a_1(r)^3[/tex]    divide by [tex]324= a_1(r)[/tex]

1/9 = r^2

take square root on both sides

1/3= r

now we find a1

[tex]324= a_1(r)[/tex]  

[tex]324= a_1(\frac{1}{3})[/tex]

multiply by 3 on both sides

972= a_1

So a1= 972,  r= 1/3

now find out 7 term by replacing 'n' with 7

[tex]a_7= 972(\frac{1}{3})^{7-1}[/tex]

So 7th term is 4/3

Will the solution to the following equation be positive or negative? b ÷ -2 = 5

positive

negative

Answers

The answer will be negative (-10)

The diagram shows a trapezium ABCD in which BC parallel to AD

Answers

Answer:

if its the diagram i think then:

f = 6cm

g = 8cm

Step-by-step explanation:

square = 48cm²

triangle = 12cm²

24 / 4 = 6

AD = 6cm

So

BC = 6cm

CD = 48 / 6 = 8cm

CD = 8cm

f = 6cm

g = 8cm

In geometry, a quadrilateral with at least each pair of parallel sides is referred to as a trapezoid. Therefore, the length of BC is 6cm and the length of CD is 8cm.

What is trapezium?

In geometry, a quadrilateral with at least each pair of parallel sides is referred to as a trapezoid both Canadian and American English, and perhaps a trapezium in British as well as other forms of English. In Euclidean geometry, a trapezoid is a convex quadrilateral by definition.

The bases of a trapezoid are the parallel sides. If the remaining two sides are parallel, they are referred to as the legs; if not, the trapezoid is indeed a parallelogram, with 2 sets of bases. A trapezoid without equal-sized sides is called a scalene trapezoid.

area of square = 48cm²

area of triangle = 12cm²

24 / 4 = 6

AD = 6cm

BC = 6cm

CD = 48 / 6 = 8cm

CD = 8cm

f = 6cm

g = 8cm

Therefore, the length of BC is 6cm and the length of CD is 8cm.

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Your question is incomplete but most probably your full question was,

The diagram shows a trapezium ABCD in which BC parallel to AD. What is the length of BC and CD.

Jada typically earns 1545 each month of which 47.20 is spent on eletricity. What percent of jadas earnings are spent on eletricity each month

Answers

so, if we take 1545 to be the 100%, what is 47.20 in percentage off of it anyway?

[tex]\bf \begin{array}{ccll} amount&\%\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ 1545&100\\ 47.20&p \end{array}\implies \cfrac{1545}{47.20}=\cfrac{100}{p}\implies p=\cfrac{47.20\cdot 100}{1545}[/tex]

Adam draws three parallelograms. He measures the sides of each figure, as shown.

What is a reasonable conjecture for Adam to make by recognizing a pattern and using inductive reasoning?

In a parallelogram, all sides are congruent.

In a parallelogram, opposite sides bisect each other.

In a parallelogram, opposite sides are congruent.

In a parallelogram, all sides bisect each other.

Answers

The best answer is C) In a parallelogram, opposite sides are congruent.

Answer:

In a parallelogram, opposite sides are congruent.

Step-by-step explanation:

Writing the lengths of the sides of the parallelograms shows him a pattern for the side lengths of opposite sides.  Doing this will show him that opposite sides are congruent.

to make 12 muffins, Mr. J's recipe requires 3/4 of a cup of sugar. If Mr. J wants to make 96 muffins, how much sugar will he need?

Answers

6 cups of sugar


12  x8  =   96
__            __
¾ x8   =    6  

A line segment is different from a line in that a segment has

Answers

A line segment is different from a line in that a segment has TWO END POINTS.
A line segment has two end points while a line has only one end point. Also you can measure the length of a line segment but you can not measure the length of a line, that is because it continues indefinitely.

The position of a particle on the x-axis at time t, t > 0, is s(t) = e^t with t measured in seconds and s(t) measured in feet. What is the average velocity of the particle for 0 ≤ t ≤ In3?

3
2/ln3
3/ln3
3/2

Also please just tell me which on it is

Answers

0 ≤ t ≤ ln(3)

When t = 0
[tex]s(0) = e^0 = 1[/tex]

when t = ln(3)
[tex]s(ln(3)) = e^{ln3} = 3[/tex]

We have two coordinates: (0, 1) and (ln(3), 3)

The rate of change = The difference in y-coordinates ÷ the difference in x-coordinates

The rate of changes  = [3 - 1] ÷ [ln(3) - 0] = 2/ln(3)

Answer: 2/ln(3)

Can someone tell me what these angles are

Answers

4 and 5 are alternate interior angles.

what is the limit as x is approaching 0 of the absolute value of x

Answers

recall that, an absolute value expression is a piece-wise in effect, thus we'd check the single-sided limits,

[tex]\bf \lim\limits_{x\to 0}~|x|\implies \begin{cases} \lim\limits_{x\to 0^-}~-x\\\\ \lim\limits_{x\to 0^+}~+x \end{cases}\implies \begin{cases} 0\\\\ 0 \end{cases}\implies \lim\limits_{x\to 0}~|x|=0[/tex]
Final answer:

The restriction of the outright worth of x as x methodologies 0 will be 0. Outright worth guarantees that the result is non-negative, and as x methodologies zero from one or the other side, the outcome stays at 0.

Explanation:

The inquiry you're posing relates to the furthest reaches of the outright worth capability as the variable x methodologies are the worth of nothing. In science, explicitly in math, we assess cutoff points to comprehend the way of behaving of capabilities as they approach a specific point.

To track down the breaking point as x methodologies 0 of the outright worth of x, signified as lim x→0 |x|, we want to think about the meaning of outright worth. The outright worth of a number is the non-negative worth of that number regardless of its sign. In this manner, as x methodologies 0 from either the positive or negative side, the outright worth of x will likewise move toward 0.

Consequently, the cutoff is 0, since as x gets increasingly close to nothing, so does the outright worth of x.

How do you multiply mixed negative number fractions?

Answers

Turn it into an improper fraction and just multiply across like normal fractions. Simplify your answer.

solve for y 3x - 5y = 8

Answers

y= -8/5 + 3/5 hope this helps

Final answer:

To solve for y in the equation 3x - 5y = 8, we subtract 3x from both sides and then divide by -5, resulting in y = (3/5)x - 8/5.

Explanation:

Solving for y in the equation 3x - 5y = 8

To solve for y in the equation 3x - 5y = 8, we need to isolate y on one side of the equation. Here are the steps:

Start with the original equation: 3x - 5y = 8.

Subtract 3x from both sides of the equation to get -5y = -3x + 8.

Divide each term by -5 to solve for y: y = (3/5)x - 8/5.

So the solution for y in terms of x is y = (3/5)x - 8/5.

What is the degree of the polynomial function shown in the graph?


1



2



3



4

Answers

the answer to your Q is 4

The correct answer is

4

:)

What two consecutive odd integers have a sum of 48?

Answers

>>>>>>>23 & 25<<<<<<<

Plot the line for the equation on the graph.





y−4=−14(x−5)

Answers

Answer: I just did the test and the correct answer was (9,3) 9 on the x axis and 3 on the y and (4,9) 4 on the x axis and 9 on the y


Step-by-step explanation:


Find the constant of variation and the slope of the direct variation model
y=2x

Answers

a direct proportional variation, is really just a slope-intercept form of equation, except that the y-intercept is always 0, and the constant of variation "k" is the slope pretty much.

[tex]\bf \qquad \qquad \textit{direct proportional variation}\\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array}\\\\ -------------------------------\\\\ y=\stackrel{\stackrel{slope}{k}}{2}x\stackrel{y-intercept}{+0}\impliedby \stackrel{k}{2}\qquad \qquad \stackrel{slope}{\cfrac{2}{1}}[/tex]
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