The main cause of accidents related to vehicles is rash driving, inexperienced drivers, and bad driving manners. Lack of awareness regarding the driving methods.
Most of the commonly made mistakes are due to drinking and driving. Most people feel drossy at night and some even don't horn when appropriate. Hence the blind spot after the vehicles is the most common cause of collisionsLearn more about the vehicle is one of the most common causes of collisions.
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The blind spot behind a vehicle is a common cause of collisions while driving. Safety measures like properly adjusted mirrors and checking over the shoulder before changing lanes can help. Cars with lighter plastic components crumple upon collision, increasing collision time and reducing the force exerted on occupants for increased safety.
Explanation:The blind spot behind a vehicle is one of the most common causes of collisions while driving. This pertains to the area of the road that cannot be directly seen by the driver while looking forward or through either the rear-view or side mirrors. The risk of such collisions can be minimized by proper adjustment of mirrors, use of blind spot mirrors, and always checking over one's shoulder before making a lane change.
Upon collision, cars with lighter weight are able to offer better protection to their occupants due to longer collision time, because of their plastic components. The crumpling of the car in an event of a collision or the deployment of dashboard padding and airbags increases the collision time and hence, the force exerted on the occupants to bring them to a stop is significantly less. Modern automobiles use this physics principle to enhance safety during collisions.
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The Kepler Space Telescope is searching for extrasolar planets by the transit method. It is necessary for Kepler to photometrically monitor a large number of stars because ____.
Answer:
The Kepler Space Telescope is searching for extrasolar planets by the transit method. It is necessary for Kepler to photometrically monitor a large number of stars because increase the probability to see a transit.
Explanation:
Photometry is the study of the intensivity of light radiated from a particular object.
In the other hand, the transit method consists in the measured of the dimming on the brightness of a star when a planet is passing in front of it, as long as the star, the planet and the detector (in this case the Kepler Telescope) are in the same line of sign.
However, that transit has a short duration. So it is necessary that the Kepler Telescope monitorates the brightness of several stars each thirty minutes in order to increase the probability of detection of a transit.
Suppose we imagine the Sun to be about the size of a grapefruit. How big an area would the orbits of the nine planets of the Solar System cover?
Answer:
size at this scale of the solar system is 10⁸ m²
Explanation:
For this exercise we can use a direct proportions rule or rule of three.
If the radius of the Sun is 7 10⁸ m is equal to the radius of a grapefruit is on average about 5 cm, the radius of the orbit of the plant is x
Mercury
r1 = 5.8 10¹⁰m
x = r1 / r_Sum 5
x = 5.8 10¹⁰/7 10⁸
x = 82 m
We repeat the same formula with all the radii of the orbit, the results in the table
Numb name r_orbit (m) x (m) A (m2)
0 Sun 7 10⁸ 1 3.14
1 mercury 5.8 10¹⁰ 8.2 10¹ 2.0 10⁴
2 venus 1 10¹¹ 1.4 10² 6.2 10⁴
3 Earth 1.5 10¹¹ 2.1 10² 1.4 10⁵
4 Mars 2.3 10¹¹ 3.2 10² 3.2 10⁵
5 Jupiter 7.8 10¹¹ 1.1 10³ 3.8 10⁶
6 Saturn 1.4 10¹² 2 10³ 1.3 10⁷
7 Uranus 2.9 10¹² 4.1 10³ 5.3 10⁷
8 Neptune 4.5 10¹² 6.4 10³ 1.3 10⁸
9 Pluto 5.9 10¹² 8.4 10³ 2.2 10⁸
The area of a circle is
A = π R²
Mercury
A = π 80²
A = 2.0 14 m²
The other values are in the table
The size at this scale of the solar system is 10⁸ m²
If the concentration of Ag+ is 0.0115 M, the concentration of H+ is 0.355 M, and the pressure of H2 is 1.00 atm, calculate the cell potential at 25.0°C. The standard reduction potentials are: $$ Eo = 0.80 V $$ Eo = 0.00 V
Answer: The cell potential is 0.712 V
Explanation:
The substance having highest positive [tex]E^o[/tex] potential will always get reduced and will undergo reduction reaction. Here, silver will undergo reduction reaction will get reduced. Hydrogen will undergo oxidation reaction and will get oxidized
Half reactions for the given cell follows:
Oxidation half reaction: [tex]H_2(1.00atm)\rightarrow 2H^{+}(0.355M)+2e^-;E^o_{H^{+}/H_2}=0.00V[/tex]
Reduction half reaction: [tex]Ag^{+}(0.0115M)+e^-\rightarrow Ag(s);E^o_{Ag^{+}/Ag}=0.80V[/tex] ( × 2 )
Net reaction: [tex]H_2(1.00atm)+2Ag^{+}(0.0115M)\rightarrow 2H^{+}(0.355M)+2Ag(s)[/tex]
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the [tex]E^o_{cell}[/tex] of the reaction, we use the equation:
[tex]E^o_{cell}=E^o_{cathode}-E^o_{anode}[/tex]
Putting values in above equation, we get:
[tex]E^o_{cell}=0.80-(0.00)=0.80V[/tex]
To calculate the EMF of the cell, we use the Nernst equation, which is:
[tex]E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[H^{+}]^2}{[Ag^{+}]^2}[/tex]
where,
[tex]E_{cell}[/tex] = electrode potential of the cell = ?V
[tex]E^o_{cell}[/tex] = standard electrode potential of the cell = +0.80 V
n = number of electrons exchanged = 2
[tex][Ag^{+}]=0.0115M[/tex]
[tex][H^{+}]=0.355M[/tex]
Putting values in above equation, we get:
[tex]E_{cell}=0.80-\frac{0.059}{2}\times \log(\frac{(0.355)^2}{(0.0115)^2})\\\\E_{cell}=0.712V[/tex]
Hence, the cell potential is 0.712 V
The cell potential of the cell is 0.71 V.
The overall equation of the redox reaction is;
2Ag^+(aq) + H2(g) ----> 2H^+(aq) + Ag(s)
The E°cell = E°cathode - E°anode
E°cell = 0.80 V - 0.00 V = 0.80 V
Using the Nernst equation;
Ecell = E°cell - 0.0592/n logQ
Where n = 2
Q = [H^+]^2/[Ag^+]^2 = (0.355 M)^2/(0.0115 M)^2
Q = 952.7
Substituting values;
Ecell = 0.80 V - 0.0592/2 log ( 952.7)
Ecell = 0.71 V
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You throw a ball straight up, it peaks out, and then cones back down to you. During this motion, the velocity and acceleration
a) always point in the same direction
b) always point in opposite direction
c) sometimes point in the same direction, and other times point in opposite to each other.
d) depends on the way the ball is thrown
e) depends in the mass of the ball
Answer:
The answer is C sometimes point in the same direction, and other times point in opposite to each other.
Explanation:
When you throw a ball straight up velocity direction head up to up side but the acceleration points opposite direction due to gravitation of earth. Gr aviation slows down the ball when it goes up, when it reaches the summit and starts to fall down both velocity and acceleration points the same way. The ball speeds up and drops down.
The velocity and acceleration of a ball thrown straight up sometimes point in the same direction and sometimes in opposite directions. On the way up, they are opposite, but when the ball peaks and begins falling, they align in the same direction (downward). Therefore, the correct answer is that they sometimes point in the same direction and other times in opposite directions.
Explanation:When you throw a ball straight up, it follows a parabolic trajectory due to the influence of gravity. Let's examine the ball's velocity and acceleration throughout its motion:
The ball's velocity is initially positive as it travels upwards after being thrown. When the ball reaches its highest point, its velocity becomes zero as it changes direction.From the moment the ball is released until it hits the ground, the acceleration due to gravity is a constant negative value, directed downward toward the center of the Earth.On the way up, the direction of the ball's velocity (upward) and the direction of acceleration (downward) are opposite. When the ball reaches its peak and starts to fall back down, the velocity (now downward) and the constant acceleration due to gravity (also downward) will be in the same direction.Therefore, during the motion of the ball, the acceleration does not always point in the same direction as the ball's motion. Instead, the direction of velocity and acceleration are opposite on the ascent and the same on the descent. Hence, our answer to the question is that the velocity and acceleration sometimes point in the same direction, and other times point in opposite to each other.
Two neutral metal spheres on wood stands are touching. A negatively charged rod is held directly above the top of the left sphere, not quite touching it. While the rod is there, the right sphere is moved so that the spheres no longer touch. Then the rod is withdrawn. Afterward, what is the charge state of each sphere? Use charge diagrams to explain your answer.
A. Both the spheres are neutral.
B. The left sphere is negatively charged, the right sphere is charged positively.
C. The right sphere is negatively charged, the left sphere is charged positively.
D. Both the spheres are charged positively.
E. Both the spheres are charged negatively.
Answer:
The right sphere is negatively charged, the left sphere is charged positively.
Explanation:
When a negatively charged rod is held above the top of left sphere, the rod will attract positive charges and repel negative charges. As the sphere are initially touching each other so positive charges from the both spheres will moves toward the rod. When we separate the spheres positive charges from right sphere have already moved toward the rod i.e. left sphere, creating a deficiency of positive charges in the right sphere and excessiveness of positive charges in left sphere , hence the right sphere will remain negatively charged and left sphere will remain positively charged.
why doesnt the moon get pulled into the sun
Answer:
The moon does not get pulled into the sun because of gravitational pull.
Explanation:
Gravitational pull is a force that pulls things down or into i guess you can say. Like are orbit, all of the planets (even the dwarf planet "pluto") are circling around are sun but we have things called moons that circle are planets. Are moon is orbiting us like we (are earth) are orbiting the sun. So to get into a little more detail, i will add that we circle the sun or the moon circles us because the action of earth pulling away from the suns gravitational pull is causing it to either rotate or revolve.So we are stuck in the gravitational force of the sun and the moon is stuck in ares. But as someone who LOVES astronamy will say that i watched a video about are earth, sun, and moon and it said that each year are moon is slowly pulling away from the earth. sooner or later we might not have a solar or lunar eclipse anymore.
Answer:
But the path of the Moon is always concave towards the Sun; the gravitational force exerted by the Sun on the Moon is always greater than the pull of the Earth on the Moon
Explanation:
A horse draws a sled horizontally across a snow-covered field. The coefficient of friction between the sled and the snow is 0.135, and the mass of the sled, including the load, is 195.9kg. If the horse moves the sled at a constant speed of 1.785m/s, what is the power needed to accomplish this?
Answer:
P = 462.62 watts
Explanation:
The power needed to accomplish this can be calculated how
P = Fv
Where F: The force exerted by the horse
v: velocity
The force exerted by the horse is against friction force; how the movement is with constant velocity these forces must be equals, then
Fr = μN
=μmg
= (0.135)(195.9)(9.8)
= 259.17 N
And the power is
P = (259.17)(1.785)
P = 462.62 watts
The power needed to accomplish this is 462.62 watts.
What is the coefficient of friction?It is defined as the numerical value that indicates the amount of friction present between the surfaces of two bodies. The lower the coefficient of friction the lower the friction between the surfaces and the higher coefficient of friction the higher the friction force between them.
We know the:
P = F×v
Where P is the power needed to accomplish this.
F = force exerted by the horse
v = velocity of the horse.
For F = [tex]\rm \mu N[/tex]
[tex]\mu = 0.135[/tex]
N = mg ⇒ 195.9×9.8 ( m= 195.9 kg and g = 9.8 [tex]\rm m/sec^2[/tex])
N = 1919.82 Newtons
F = 0.135×1919.82 ⇒ 259.1757 Newtons
Now P = F×v ⇒259.1757×1.785
P = 462.62 Watts
Thus, the power needed to accomplish this is 462.62 watts.
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A sound system is being set up in a gazebo in a park. It needs to produce music so that everyone can hear it. How much power would the speakers need to produce in order for the intensity at 5 meters away to be 1 x 10^-8 W/m^2? (assume the shape of the propagation of the sound wave is a hemisphere)
1.87 x 10^-7 W
1.57 x 10^-6 W
1.14 x 10^-6 W
2.46 x 10^-7 W
Answer:
Power, P=1.57×[tex]10^{-6}[/tex] Watt
Explanation:
Given
Intensity, I=1×[tex]10^{-8}[/tex] W/m²
Distance, r=5 meter
Considering the hemispherical space with radius 5 meter centered on the speaker. Speaker emits sound wave continuously with Power P. Intensity I is constant throughout the space and defined as power per unit area.
I=[tex]\frac{P}{A}[/tex]
so, P=I×A
where A is the area of shape of propagation.
since ,shape of propagation is hemispherical
so, A=2×p×r²=2×3.14×5×5=157 m²
P=1×[tex]10^{-8}[/tex]×157
P=1.57×[tex]10^{-6}[/tex] Watt
A 60.0-kg ball of clay is tossed vertically in the air with an initial speed of 4.60 m/s. Ignoring air resistance, what is the change in its potential energy when it reaches its highest point?
Answer:
the change in potential energy when it reaches the highest height = 634.8 J
Explanation:
Potential Energy: This is the energy a body posses due to position.
From the law of conservation of energy,
At the highest point and lowest points, potential energy is converted to kinetic energy
I.e
Ek = Ek
Where Ek = potential energy, Ep = potential energy
Ep₁ = 1/2mu² (potential energy at the lowest point)................ Equation 1
Ep₂ = 1/2mv² (potential energy at the highest point)............. Equation 2
ΔEp = Ep₂ - Ep₁ = 1/2mu² - 1/2mv²........................ Equation 3
Where ΔEp = change in potential energy, m = mass of the ball of clay, v = final velocity of the ball of clay, u = initial velocity of the ball of clay
Given: m= 60 kg, u = 4.6 m/s v = 0 ( velocity at the maximum height)
Substituting these values into equation 3
ΔEp = 1/2×60×4.6 - 1/2×60×0²
ΔEp = 30×21.16 - 0
ΔEp = 634.8 J.
Therefore the change in potential energy when it reaches the highest height = 634.8 J
Final answer:
The change in potential energy of the 60.0-kg ball of clay when it reaches its highest point, ignoring air resistance, is 636.0 J.
Explanation:
To calculate the change in potential energy of the 60.0-kg ball of clay at its highest point, we use the formula for gravitational potential energy ([tex]PE_{g}[/tex]):
[tex]PE_{g}[/tex] = m × g × h
where m is the mass of the object, g is the acceleration due to gravity (9.81 m/s² on Earth), and h is the height reached.
First, determine the maximum height h the ball reaches using the conservation of energy principle, where the initial kinetic energy (KE) is fully converted to potential energy (PE) at the highest point:
[tex]KE_{initial}[/tex] = [tex]PE_{g,max}[/tex]
To find [tex]KE_{initial}[/tex], we use the kinetic energy formula:
KE = 1/2 × m × v²
[tex]KE_{initial}[/tex] = 1/2 × 60.0 kg × (4.60 m/s)²
[tex]KE_{initial}[/tex] = 1/2 × 60 kg × 21.16 m²/s²
[tex]KE_{initial}[/tex] = 636.0 J
Since [tex]KE_{initial}[/tex] = [tex]PE_{g,max}[/tex], the ball's change in potential energy is also 636.0 J.
What is a geologist’s role in the petroleum industry? stay with the drillers to examine rock and fossils brought to the surface chart information on a well log calculate the distance and direction of movement of the lost vein of ore locate environments in which petroleum forms
Answer:what is the role of of geologist in the petroleum industry
A. Stay with the drillers to examine rocks and fossils brought to the surface.
B. Chart information on a well log
C. Calculate the distance and direction of movement of the lost vein of ore
D. locate environment in which the petroleum forms
Correct option. Is D locate environment in which petroleum forms
Explanation:
Petroleum geologists are usually linked to the actual discovery of oil and the identification of possible oil deposits or leads. It can be a very labor-intensive task involving several different fields of science and elaborate equipment. Petroleum
geologists look at the structural and
sedimentary aspects of the stratum/strata to identify possible oil traps
Answer: D locate environment in which the petroleum forms
Explanation:
The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 71 kg ( 157 lb ) person of height 1.75 m (5.7 ft ) would have a body surface area of approximately 1.90 m².
What is the net amount of heat this person could radiate per second into a room at 19.0 °C (about 66.2 °F) if his skin's surface temperature is 30.0 °C? (At such temperatures, nearly all the heat is infrared radiation, for which the body's emissivity is 1.0, regardless of the amount of pigment.)
Answer:
125.04181 W
Explanation:
[tex]\sigma[/tex] = Stefan-Boltzmann constant = [tex]5.67\times 10^{-8}\ W/m^2K^4[/tex]
A = Surface area = 1.9 m²
[tex]T_b[/tex] = Skin surface temperature = 19°C
[tex]T_s[/tex] = Room temperature = 30°C
[tex]\epsilon[/tex] = Emissivity = 1
Radiated thermal energy is given by
[tex]P=\epsilon A\sigma (T_b^4-T_s^4)\\\Rightarrow P=1\times 1.9\times 5.67\times 10^{-8}((273.15+30)^4-(273.15+19)^4)\\\Rightarrow P=125.04181\ W[/tex]
The net amount of heat this person could radiate per second into the room is 125.04181 W
Which of the following are criticism of kohlberg's theory of moral developmen?
Answer:
Model reasoning vs Moral behavior,cultural differences, bias
Explanation:
The answer for this case: Model reasoning vs Moral behavior,cultural differences, bias
Model reasoning
In particular usually we have a positive correlation between higher stages of reasoning and higher levels of moral behavior. But in some cases, some found we have situational factors are better predictors of moral behavior.
One example is when people prefer to help people with some disease because an institute with most prestigy says this condition is given by a problem of the society when the reality is not true.
Cultural differences
This item can create some problem since we can create problems when we need to establish if one statement is true or not.
Bias
This is one of the most common problems since we don't have a criteria to decide if we have bias or no.
Suppose that a person riding on the top of a freight car shines a searchlight beam in the direction in which the train is traveling.
How does the speed of the light beam relative to the ground compare to the speed of beam when the train is at rest?
Answer:
same
Explanation:
Acc. to Einstien's postulate of special theory of
Relativity , Velocity of the light beam is same in all frames of references
(a) If the freight car is at rest
The frame we can assumed as Non - inertial frame of reference s
In the inertial frame of reference , velocity of the light beam has its own value as : 3 x 10^8 m/s
(b) If the freight car is moving , the frame we can assumed as Non -inertial frame of reference
In thus case also , The velocity of the light beam will also have the same value as ; 3 x 108 m/s
What would happen to Earth if ocean floor were created at divergent boundaries at a faster rate than it is destroyed at convergent boundaries?
Answer:
The Earth would increase in volume
Explanation:
What would happen to Earth if ocean floor were created at divergent boundaries at a faster rate than it is destroyed at convergent boundaries?
Divergent boundaries are boundaries where plates pull away from each other, forming mild earthquakes and volcanoes as magma comes to the surface. Earthquakes are as a result of vibrations travelling within the earth or ocean floors . Volcanoes occur as a result of the eruption of molten magma from the ocean floor
In divergent boundaries, the plates pull away and and the weakened crust in between collapse leaving more space thereby increasing in volume.
Convergent boundaries are boundaries that pull into each other. mountain chains are formed as the two plates push into each other if they are of the same density.
A novice skier, starting from rest, slides down a frictionless 29.0∘ incline whose vertical height is 185 mm. How fast is she going when she reaches the bottom?
Answer:
Her speed when she reaches the bottom of the incline is 1.90 m/s.
Explanation:
Hi there!
To solve this problem, let´s use the energy conservation theorem:
Initially, the skier is at rest at a height of 0.185 m. Since she is at rest, her kinetic energy will be zero and her gravitational potential energy (PE) will be:
PE = m · g · h
Where
m = mass of the skier.
g = acceleration due to gravity.
h = height.
When she reaches the bottom, the height is zero and then the potential energy will be zero. Since there is no friction, the initial potential energy had to be converted into kinetic energy because the total energy of the skier remains constant, i.e., it is conserved.
Then, the final kinetic energy (KE) of the skier has to be equal to the initial potential energy:
PE = KE
The equation of kinetic energy is the following:
KE = 1/2 · m · v²
Then:
KE = PE
1/2 · m · v² = m · g · h
1/2 · m · v² = m · 9.8 m/s² · 0.185 m
v² = 2 · 9.8 m/s² · 0.185 m
v = 1.90 m/s
Her speed when she reaches the bottom of the incline is 1.90 m/s.
Suppose a 52 N sled runs on packed snow. The coefficient of friction is only 0.11. If a person weighing 700 N sits on the sled, what force is needed to pull the sled across the snow at constant speed?
Answer:
A force of 83 N is needed to pull the sled with constant speed.
Explanation:
Hi there!
Please, see the attached figure for a graphical description of the problem.
We have the following horizontal forces applied on the sled:
F = applied force.
Fr = friction force.
And the following vertical forces:
N = normal force.
W = weight of the sled + weight of the person
According to the Newton´s second law:
∑F = m · a
Where "m" is the mass of the object and "a" is its acceleration
So, in the horizontal direction:
F - Fr = m · a
We have to find what force, F, is needed so that the sled moves with constant speed (acceleration = 0). Then:
F - Fr = 0
F = Fr
The applied force has to be equal in magnitude to the friction force.
The friction force is calculated as follows:
Fr = μ · N
Where μ is the coefficient of friction and N is the normal force.
To find the normal force, let´s apply Newton´s second law in the vertical direction:
∑F = N - W = m · a
Notice that the sled is not accelerated in the vertical direction so that a = 0:
N - W = 0
N = W
The normal force is equal to the weight and the weight is the sum of the weight of the sled plus the weight of the person:
W = 52 N + 700 N = 752 N
Then:
N = 752 N
Fr = 0.11 · 752 N
Fr = 83 N
Then
F = 83 N
A force of 83 N is needed to pull the sled with constant speed.
A force of 83 N is needed to pull the sled with constant speed.
We have the following horizontal forces applied on the sled:
F = applied force.
Fr = friction force.
And the following vertical forces:
N = normal force.
W = weight of the sled + weight of the person
According to the Newton´s second law:
F = m * a
Where "m" is the mass of the object and "a" is its acceleration
So, in the horizontal direction:
F - Fr = m *a
To find what force, F, is needed so that the sled moves with constant speed (acceleration = 0). Then,
F - Fr = 0
F = Fr
The applied force has to be equal in magnitude to the friction force.
The friction force is calculated as follows:
Fr = μ · N
Where μ is the coefficient of friction and N is the normal force.
To find the normal force, let´s apply Newton´s second law in the vertical direction:
F = N - W = m · a
Notice that the sled is not accelerated in the vertical direction so that a = 0:
N - W = 0
N = W
The normal force is equal to the weight and the weight is the sum of the weight of the sled plus the weight of the person:
W = 52 N + 700 N = 752 N
Then:
N = 752 N
Fr = 0.11 · 752 N
Fr = 83 N
Then
F = 83 N
A force of 83 N is needed to pull the sled with constant speed.
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Galileo found that a ball rolling down one inclined plane would roll how far up another inclined plane?
A) the ball would not roll up the other plane at all
B) to nearly its original height
C) to about one quarter its original height
D) to nearly twice its original height
E) to nearly half its original height
Answer: B.) To nearly its original height
Explanation:
Because if you have a ball than the inclined plane is heading up you would get almost the same height as it started.
Galileo found that a ball rolling down one inclined plane then, the ball will reach about the original height. Hence, option B is correct.
What is momentum?The momentum is the result of a particle's velocity and its mass. Force and motion, meaning it has both magnitude and the direction.
According to Isaac Newton's second equation of motion, the force acting on a particle equals the time rate of increase of momentum.
The impulse, which is the product of the force and the intervals (the impulse), is equal to the difference in momentum, according to Newton's 2nd law, if a steady force operates on a particle for a specific amount of time.
On the other hand, a particle's momentum is the amount of time needed for a consistent action to fight it to rest.
Because if you were to throw a ball while the inclined plane was moving upward, you would nearly reach its starting height.
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What is the relationship between height and gravitational potential energy of water behind a dam?
Water is contained in a tidal basin behind a dam. The water has a depth h at high tide and zero at low tide. The gravitational potential energy of the water stored in the basin between a high tide and a low tide is proportional to
1. h^(1/2)
2. h
3. h^2
4. h^3
Answer:
3. [tex]h^2[/tex]
Explanation:
Energy of volume contained in a dam is given by
[tex]E=\dfrac{1}{2}A\rho gh^2[/tex]
where,
A = Horizontal surface area of the barrage
[tex]\rho[/tex] = Density of water
g = Acceleration due to gravity = 9.81 m/s²
h = Vertical tidal range,
It can be seen that
[tex]E\propto h^2[/tex]
Hence, the energy is proportional to [tex]h^2[/tex]
Final answer:
The gravitational potential energy of water behind a dam is directly proportional to the height of the water column, using the formula PE = mgh. For a tidal basin, the GPE is proportional to the average height (h/2), therefore, the correct relationship is proportional to the height h. So the correct option is 2.
Explanation:
The relationship between the height and gravitational potential energy (GPE) of water behind a dam is that GPE is directly proportional to the height of the water column. The formula to calculate the GPE is PE = mgh, where PE is the potential energy, m is the mass of the water, g is the acceleration due to gravity, and h is the height above the reference point.
When we consider a tidal basin with water depth h at high tide transitioning to zero at low tide, the average height of water behind the wall is h/2. Since mass (m) is the product of the water's density (assumed to be 1,000 kg/m³ for water) and volume—which, in turn, is the area of the water surface (A) multiplied by its height (h)—the GPE of water stored between a high tide and low tide is proportional to the average height, thus proportional to h. Therefore, the correct answer is option 2, which states that the gravitational potential energy of the water stored in the basin between high tide and low tide is proportional to h.
Calculate the work WAB done by the electrostatic force on a particle of charge q as it moves from A to B.
Express your answer in terms of some or all the variables E, q, L, and α.
Answer:
[tex]W_{AB} = EqL[/tex]
Explanation:
The work done by the electrostatic force is
[tex]W_{AB} = \int\limits^A_B {\vec{F}(x)} \, d\vec{x}[/tex]
where F can be calculated by Coulomb's Law:
[tex]\vec{F} = \frac{1}{4\pi \epsilon_0}\frac{q_0q_1}{x^2}[/tex]
We can express this equation by the variables given in the question.
Electric field is denoted as E.
[tex]\vec{F} = \vec{E}q = Eq~(+\^i)[/tex]
The distance, x, is given as L. If B is greater than A, the work done is positive. Else, work is negative.
[tex]W_{AB} = \int\limits^A_B {\vec{E}q} \, d\vec{x} = Eq(B-A) = EqL[/tex]
The work done on a charge q moving from point A to B in an electrostatic field E can be calculated using the formula: WAB = - q * E * L * cos(α). The maximum work is done when the charge is moving parallel to the electric field.
Explanation:The work done on a charge, q, moving under an electrostatic field, E, from point A to B - referred to as WAB - can be calculated using the formula: WAB = - q * E * L * cos(α), where E is the electric field intensity, q is the charge, L is the displacement, and α is the angle between the electric field vector and the displacement.
This equation dictates that the work done is inversely proportional to the cosine of the angle between the electric field and the displacement direction - implying that the maximum work is done when the charge is moving parallel to the electric field direction(alpha=0).
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The purpose of antilock brake systems is to prevent the brakes from becoming locked.Choose one True False
Answer:True
Explanation:
The above statement is true as an anti-lock braking system (ABS) is a vehicle protection system that helps the wheels on a vehicle to keep up tractive force with the road. ABS does not allow the brake to lock during braking and thus avoiding skidding which is necessary to avoid in wet roads otherwise it could be fatal for drivers.
It is widely used in vehicles to improve the safety measures and reduce road accidents.
When rock retains its new shape (without fracturing) after stress has been removed, it has undergone ____________________ ____________________.
Answer:
Elastic deformation
Explanation:
When rock retains its new shape (without fracturing) after stress has been removed, it has undergone elastic deformation.
Elastic deformation is the process in which the object under temporary stress regains its original shape after the stress is removed. The stress must be low and not strong enough that it can create fracture and permanent damage to the object. for example, we can stretch a rubber band by applying some force and when we remove the force, the rubber band comes back to its original length and shape.
Elements that cycle in the environment and that also have a gaseous phase at some point in their cycle include what?
Answer:
Carbon, nitrogen and sulphur.
Explanation:
In carbon cycle, carbon dioxide is in the gaseous form in atmosphere. This gaseous carbon dioxide is emitted in the atmosphere through combustion of fossils, respiration, decomposition. In nitrogen cycle, atmospheric nitrogen is in the gaseous form which is emitted through denitrification. In sulphur cycle, sulphur is in the form of gaseous sulphur dioxide in the atmosphere. This sulphur is emitted in the atmosphere by the volatilization of hydrogen sulphide.
Elements such as carbon, nitrogen, and oxygen go through a gaseous phase in their respective nutrient cycles (the Carbon Cycle and Nitrogen Cycle for instance), moving through the environment in a regular pattern.
Explanation:Certain elements move through our planet's systems, such as the water, atmosphere, and soils, in cycles known as nutrient cycles or biogeochemical cycles. These elements often go through a gaseous phase. Carbon, nitrogen, and oxygen are examples of elements that have a gaseous phase in their cycle. For instance, Nitrogen Cycle involves nitrogen gas in the atmosphere being converted into usable forms by bacteria in a process known as nitrogen fixation. Similarly, in the Carbon Cycle, carbon dioxide gas is absorbed by plants and converted into organic carbon through photosynthesis.
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A 15,000-N car on a hydraulic lift rests on a cylinder with a piston of radius 0.20 m. If a connecting cylinder with a piston of 0.040-m radius is driven by compressed air, what force must be applied to this smaller piston in order to lift the car? Group of answer choices
Answer:
[tex]F_{piston} = 600 N[/tex]
Explanation:
[tex]F_{car}[/tex] = weight of the car = Force on the larger piston = 15000 N
[tex]r_{1}[/tex] = radius of the larger piston = 0.20 m
[tex]F_{piston}[/tex] = force on the smaller piston
[tex]r_{2}[/tex] = radius of the smaller piston = 0.040 m
Using pascal's law, Pressure must be equal on each piston, hence
[tex]\frac{F_{car}}{\pi r_{1}^{2} } = \frac{F_{piston}}{\pi r_{2}^{2} } \\\\\frac{15000}{0.20^{2} } = \frac{F_{piston}}{0.040^{2} }\\\\F_{piston} = 600 N[/tex]
600 N force must be applied to this smaller piston in order to lift the car.
Let's solve the question:
Pascal's Law:It states that if some pressure is applied at any point of incompressible liquid then the same pressure is transmitted to all the points of liquid and on the walls of the container.
Given:
Force on car, F= 15,000 N
Radius of larger piston, r₁ = 0.20m
Radius of larger piston, r₂ = 0.040m
To find:
Force on piston, F=?
Using Pascal's law:
[tex]\frac{F_{car}}{\pi r_1^2} =\frac{F_{piston}}{\pir_2^2}\\\\ \frac{15000}{0.20^2}=\frac{F_{piston}}{0.40^2}\\\\F_{piston}=600N[/tex]
600 N force must be applied to this smaller piston in order to lift the car.
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You have purchased a new 20-pin power supply to replace one that failed. However, the motherboard only has a 24-pin connector. What should you do?
This question is incorrect.The correct question is here
You have purchased a new 24-pin power supply to replace one that failed. However, the motherboard only has a 20-pin connector. What should you do?
Answer:
To solve this problem you should plug the 24-pin power supply into the motherboard, as your mother board has 20 pin you leave pins 11, 12, 23, and 24 on the motherboard unconnected.
I have attached a picture from which you can see that there are pins for same working
A metal ball at 30°C is dropped from a height of 6.2 km. The ball is heated due to the air resistance and it completely melts just before reaching the ground. The molten substance falls slowly on the ground. If the specific heat of lead = 126 Jkg−1^o C^{-1} and melting point of lead = 130^oC and suppose that any mechanical energy lost is used to heat the ball, then the latent heat of fusion of lead is:__________.
Answer:
Explanation:
Given
height [tex]h=6.2 km[/tex]
Initial temperature [tex]T_1=30^{\circ}C[/tex]
Specific heat of lead [tex]c=126 J/kg-^{\circ}C[/tex]
Melting Point of Lead [tex]T_m=130^{\circ}C[/tex]
Here Potential Energy is converted to heat energy to melt the lead ball
Sphere ball will first will be heated to [tex]130^{\circ}C[/tex] then it starts melting
thus
[tex]mgh=mc\Delta T+mL[/tex]
where [tex]L=latent\ heat\ of\ fusion[/tex]
[tex]\Delta T=[/tex]change in Temperature
[tex]gh=c\Delta T+L[/tex]
[tex]9.8\times 6.2\times 1000=126\times (130-30)+L[/tex]
[tex]L=48,160\ J/kg [/tex]
[tex]L=48.16\ kJ/kg[/tex]
A day has 86,400 second (s). Notice that the decimal point is to the far right of the number. The first part of scientific notation is a number between 1 and 10. Move the decimal point to the left to obtain 8.64, which equals m in our traditional notation. The value for n is given by the number of places the decimal point was moved from its location in 86,400 to 8.64. Thus, 86,400 s = 8.64×104 s. Because the decimal was moved four places to the left (and the value is larger than 1), the exponent is a positive integer. If you had a very precise clock, you could write this as 8.640×104 s, or 8.6400×104 s. The number of digits you keep in the first part of the notation describes the precision of your value and determines the number of significant digits.
Answer:
There are 2 number of significant figures.
Explanation:
Significant figures include a zero at the start or between the digits after the decimal. But do not include a zero at the end. There are two zeros . It is 6400 but these zeros are at the end so they will not be counted in the significant figures. If they were present at the start or between any two non zero digits they would be included in significant figured
A 4.00-m-long, 500 kg steel beam extends horizontally from the point where it has been bolted to the framework of a new building under construction. A 70.0 kg construction worker stands at the far end of the beam. What is the magnitude of the gravitational torque about the point where the beam is bolted into place?
Answer:
12544 N.m
Explanation:
given,
length of beam = 4 m
mass of steel = 500 Kg
mass of worker = 70 Kg
torque at hinge = ?
weight of the beam will at the center of mass which is at 4/2 = 2 m distance form the hinge.
distance of worker = 4 m
torque acting at hinge=
= Mg x 2 + mg x 4
= 500 x 9.8 x 2 + 70 x 9.8 x 4
= 12544 N.m
hence, torque experience at the hinge is equal to 12544 N.m
In which one of the following circumstances could mechanical energy not possibly be conserved, even if friction and air resistance are absent?
A car moves down a hill, its velocity continually increasing alongthe way.
A car moves up a hill at a constant velocity.
A car moves along level ground at a constant velocity.
A car moves up a hill, its velocity continually decreasing alongthe way.
Answer:
A car moves up a hill at a constant velocity
Explanation:
Since the velocity is constant, the speed is also constant and so is the kinetic energy. However, total mechanical energy is sum of gravitational potential energy and kinetic energy, and the car is moving up the hill so its potential energy rises.
Thus, in the circumstances described the mechanical energy cannot be conserved.
The correct answer is A car moving up the hill with constant velocity.
If an astronaut landed on a planet that had the same radius as Earth but 4 times its mass, then the astronaut's weight on the planet would be:
Answer:
4 times
Explanation:
[tex]M[/tex] = mass of the earth
[tex]R[/tex] = radius of the earth
[tex]g_{e}[/tex] = acceleration due to gravity on earth
acceleration due to gravity on the earth is given as
[tex]g_{e} =\frac{GM}{R^{2}}[/tex]
[tex]w_{e}[/tex] = weight of the astronaut on earth
weight of the astronaut on earth is given as
[tex]w_{e} = m g_{e} = \frac{GMm}{R^{2}}[/tex]
[tex]M_{p}[/tex] = mass of the planet = [tex]4 M[/tex]
[tex]R_{p}[/tex] = radius of the planet = R
[tex]g_{p}[/tex] = acceleration due to gravity on earth
acceleration due to gravity on the planet is given as
[tex]g_{p} =\frac{GM_{p}}{R_{p}^{2}}\\g_{p} = \frac{4GM}{R^{2}}\\g_{p} = 4 g_{e}[/tex]
[tex]w_{p}[/tex] = weight of the astronaut on planet
weight of the astronaut on planet is given as
[tex]w_{p} = m g_{p}\\w_{p} = m (4) g_{e}\\w_{p} = 4 w_{e}[/tex]
hence the weight of the astronaut on the planet is four times.
Final answer:
An astronaut would weigh 4 times more on a planet with the same radius as Earth but 4 times its mass, due to the direct relationship between mass and gravitational force.
Explanation:
To understand how an astronaut's weight would change on a planet with the same radius as Earth but 4 times its mass, we need to consider the universal law of gravitation. The formula to calculate gravitational force (which determines weight) is F = G (m1m2) / r^2, where F is the gravitational force, G is the gravitational constant, m1 and m2 are the masses of the two objects, and r is the distance between the centers of the two masses (the radius of the planet, in this case).
Since the planet has 4 times the mass of Earth but the same radius, applying these values to the formula shows that the astronaut's weight would be 4 times greater on this new planet compared to Earth. The increase in mass directly increases the gravitational force, while the radius remains constant, leading to an increase in weight.
Scientists who wished to study the metabolic function of cells with balanced translocations while preventing cell replication would be best served by arresting the cells during which phase of the cell cycle?
Answer:
Interphase.
Explanation:
interphase
When scientists were to prevent cell duplication, they would have to interrupt the division of cells (mitosis). Interphase is the stage of the cell life cycle that occur in between cell dividing stages.
It is during this phase that preventing cell replication would be best served by arresting the cells.