The cost of a car, in dollars, t years after its purchase is $20,000 - $3,000t.

Which statement is correct?
A.
The cost of the car depreciates every year by $3,000.
B.
The cost of the car depreciates every year by $20,000.
C.
The cost of the car increases every year by $3,000.
D.
The cost of the car increases every year by $20,000.

Answers

Answer 1

Final answer:

The correct statement is that the cost of the car depreciates every year by $3,000. This is determined by analyzing the provided depreciation formula, $20,000 - $3,000t, where t is the number of years after purchase.

Explanation:

The cost of a car, in dollars, t years after its purchase is described by the equation $20,000 - $3,000t. This equation indicates that the value of the car is decreasing by a fixed amount each year. Taking a closer look at the formula given, we can see that the t variable, which represents time in years, is multiplied by $3,000. This $3,000 is then subtracted from the initial value of the car, $20,000. Therefore, each year, the value of the car decreases by this amount of $3,000.

Given the options:

A. The cost of the car depreciates every year by $3,000.B. The cost of the car depreciates every year by $20,000.C. The cost of the car increases every year by $3,000.D. The cost of the car increases every year by $20,000.

The correct answer is:

A. The cost of the car depreciates every year by $3,000.

Answer 2

Final answer:

The correct statement is A. The cost of the car depreciates every year by $3,000, which can be deduced from the depreciation equation of the car's value over time.

Explanation:

The cost of a car, in dollars, t years after its purchase is given by the equation $20,000 - $3,000t. This equation represents a linear function where the initial value of the car is $20,000 and it decreases by $3,000 for each year t that passes. Therefore, the correct statement is:

A. The cost of the car depreciates every year by $3,000.

Each year that passes, the term $3,000t increases by $3,000 since t increments by 1, thus reducing the overall value of the car by another $3,000.

Related Questions

which of the following are equivalent to 0.625 625/1000 100/625 5/8 125/200 20/125

Answers

625/1000= 0.625

100/625= 0.16

5/8= 0.625

125/200= 0.625

20/125= 0.16

(6.5/2) to the second power. Simplify

Answers

14 Bc 6.5 + 6.5 = 12 + 1/2+1/2 = 13

answer the question in the image

Answers

Answer: The percentage of decrease is: " 33 ⅓ %" .
_____________________________________________
Explanation:
____________________________________________
Given:
____________________________________________
10 years ago, # of illiterate people = 150 lakhs;

"Now" ; # of illiterate people = 100 lakhs ;
____________________________________________
So; the decrease in the # of illiterate people = "(150 - 100) = 50 lakhs ;
____________________________________________
To calculate the "percentage of decrease" :
____________________________________________
The "percentage of decrease" =

{"decrease in the # of illiterate people"} / {"# of illiterate people started with"] ;

× 100 (percent).
__________________________________________________
= [tex] \frac{50}{150} [/tex] * 100 % ;

{Note that: [tex] \frac{50}{150} [/tex] = [tex] \frac{5}{15}[/tex] ;
→ The "zeros" cancel out ;

→ [tex] \frac{50}{150} [/tex] * 100 % ;

= [tex] \frac{5}{15}[/tex] * 100 ;

Note: [tex] \frac{5}{15}[/tex] = [tex] \frac{(5/5)}{(15/5)} [/tex] ;
= [tex] \frac{1}{3} [/tex] ;
__________________________________________________
→ [tex] \frac{1}{3}[/tex] * 100 = [tex] \frac{1}{3}[/tex] * [tex] \frac{100}{1}[/tex] ;
_________________________________________________________
= [tex] \frac{(1*100)}{(3*1)} [/tex] % ;

= [tex] \frac{(100)}{(3)} [/tex] % ;

= "(100 ÷ 3) % ;

= " 33 ⅓ % " .
_____________________________________________________
Answer: The percentage of decrease is: " 33 ⅓ %" .
_____________________________________________________

Write an expression to represent the perimeter of:
2a-3
2a
3a+1

Answers

I am assuming this is a triangle.....P = a + b + c

P = 2a - 3 + 2a + 3a + 1....combine like terms
P = 7a - 2 <==

What is k/4+2-k=10.

Answers

i hope this help answer that

Tanya spent $8.15 on 5 cans of tuna. She used a coupon that gave her 35¢ off each can. What was the price of a can of tuna without the coupon? Enter your answer in the box.

Answers

Each can of tuna would cost $1.98 because you would do .35x5 then your total plus 8.15 and that would be the total without coupons then you would divide your grand total by 5 for the exact price of one can without the coupon

Answer: $1.98

Step-by-step explanation:

Given: The total amount Tanya spent on cans of tuna = $8.15

Also, she used a coupon that gave her 35 cents off each can.

Therefore, The total discount on 5 cans =[tex]5\times35=175\ cents[/tex]

Since, $1=100 cents or 1 cent= 0.01 dollar

Therefore, the total discount on 5 cans=[tex]0.01\times175=\$1.75[/tex]

Now, the price of 5 cans of tuna without the coupon=[tex]\$8.15+1.75=\$9.90[/tex]

The price of a can of tuna without the coupon=[tex]\frac{9.90}{5}=\$1.98[/tex]

Shelby is organizing the 12 prize ribbons she won for athletic competitions. She has twice as many first place ribbons as she does second place ribbons. How many first place ribbons does she have?

Answers

I think she has for because 2x+x=12
3x=12
X=4

I would use the box method to solve this problem. Since she has twice as many, you add the 2 to the 1 to get three. Then you divide the total amount (12) by 3. So, 4 goes in each of the 3 boxes. This tells you that there are 8 first place ribbons and 4 second place ribbons. Hope this helps.

Distance between the points

Answers

To understand the distance formula, you first need to understand the Pythagorean Theorem. For a refresher, the theorem states that the square of the legs of a right triangle is equal to the the square of its hypotenuse (the side opposite the right angle), or in symbols:

[tex]a^2+b^2=c^2[/tex], where a and b are the lengths of the legs, and c is the length of the hypotenuse. In the context of the x-y plane, the legs of the triangle correspond to separate x and y values on the plane, and the hypotenuse corresponds to a straight line between two points on that plane.

To find the distance between the points you've listed, (2√5,4) and (1,2√3), we'll first need to find the "legs" of the triangle. To find the length of the x leg, we'll just need the distance between the x values of the points, which we find to be 2√5-1. We do the same for the y component, which ends up being 4-2√3. Now that we have our legs, we're ready to find the hypotenuse - or the distance.

Going back to Pythagorus's equation, we have:

[tex](2 \sqrt{5}-1)^{2}+(4-2 \sqrt{3})^{2}=d^2 [/tex]

where d, the hypotenuse of the triangle, means "distance."

To solve for d, we take the square root of both sides:

[tex]d= \sqrt{(2 \sqrt{5}-1)^2+(4-2 \sqrt{3} )^2} [/tex]

And from there, all that's left to do is solve the right side of the equation, which just ends up being rote calculation.

Edit: I'll go through the steps of that calculation here. We'll start by expanding each of the squared terms inside the radical:

[tex](2 \sqrt{5}-1)^2=(2 \sqrt{5}-1)(2 \sqrt{5}-1)=(2 \sqrt{5}-1)2 \sqrt{5}-(2 \sqrt{5}-1)[/tex]
[tex]=(2 \sqrt{5})^2-2 \sqrt{5}-2 \sqrt{5}+1=20-4\sqrt{5}+1[/tex]

[tex](4-2\sqrt{3})^2=(4-2\sqrt{3})(4-2\sqrt{3})=(4-2\sqrt{3})4-(4-2\sqrt{3})2\sqrt{3}[/tex]
[tex]=16-8\sqrt{3}-8\sqrt{3}+(2\sqrt{3})^2=16-16\sqrt{3}+12[/tex]

Putting those values back under the radical:

[tex] \sqrt{20-4\sqrt{5}+1+16-16\sqrt{3}+12} [/tex]

Collecting constants:

[tex] \sqrt{49-4\sqrt{5}-16\sqrt{3}} [/tex]

If you wanted an exact answer, this messy-looking thing would be it, and you can verify those results on WolframAlpha if you'd like. If you want an approximation, just enter that expression in to the online calculator of your choice, and it should give out the value of approx. 3.51325.

In general, if you want to solve for the distance between two points [tex](y_{1},x_{1}) [/tex] and [tex] (y_{2},x_{2}) [/tex], the formula is:

[tex]d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2} [/tex]

How do you determine if a set of ordered pairs is a function or not?

Answers

You could set up the relation as a table of ordered pairs. Then, test to see if each element in the domain is matched with exactly one element in the range. If so, you have a function! Watch this tutorial to see how you can determine if a relation is a function.

A function is a set of ordered pairs in which no 2 pairs with the same first element have a different second element.

If you think about it, it makes sense. Think about f(x) = x + 1. The pairs (x, f(x)) look like (1,2), (2,3), (3,4), (4,5), etc. If you also had (1,3) in the set, then there'd be two different answers for 1+1. The same applies to any function. There can only be one result for a given input value. Your welcome!!

Is 3.2 a rational number?

Answers

The number is between integers, so it can't be an integer or a whole number. It's written as a ratio of two integers, so it's a rational number and not irrational. Allrational numbers are real numbers, so this number is rational and real.

Yes , all rational numbers are real numbers, so this number is rational and real

When a coordinate grid is superimposed on a map of harrisburg the highschool is located at (17,21) and the town park is located at (28,13) . If each unit represents 1 mile, how many miles apart are the highschool and the town park? round your answer to the nearest tenth

Answers

To find the distance between the high school at (17,21) and the town park at (28,13), use the distance formula which yields a result of approximately 13.6 miles apart, rounded to the nearest tenth.

When looking at the coordinates of the high school at (17,21) and the town park at (28,13) on a coordinate grid where each unit represents 1 mile, we need to use the distance formula to calculate the distance between the two points. The distance formula is derived from the Pythagorean theorem and is given by:

[tex]Distance = \sqrt{(x2 - x1)^2 + (y2 - y1)^2}[/tex]

Substituting the values -

[tex]Distance = \sqrt{{(28 - 17)^2 + (13 - 21)^2}[/tex]

Calculate the differences and square them:

Distance = [tex]\sqrt{{(11)^2 + (-8)^2}\\[/tex]

Distance = [tex]\sqrt{{121 + 64}[/tex]

Distance = [tex]\sqrt{{185[/tex]

Take the square root to find the distance:

Distance = 13.6 miles

Therefore, the high school and the town park are approximately 13.6 miles apart, rounded to the nearest tenth.

What property is this? if -5x-1=-11, then -5x=-10

Answers

I believe X is equal to 2

Then, the answer would be x=-2.

how many integers are greater than 9 37 and less than 37 9

Answers

The integer between this two given integer, If the two given interger in inclusive we will calculate it using 37 - 9 + 1 = 29. So we will have a total of 29 interger in the number line if both the given integer is included.

But if the two given integer in excluded we will subtract both, we will calculate it by 37 - 9 - 1 = 27. So we will have a total of 27 integer if both the number is excluded.

Which symbol correctly compares the two fractions use <, > or = 2/4 and 3/8

Answers

2/4>3/8_________________________________________

2/4>3/8———————-____________________________

Ahmad drove 638 miles in 11 hours. At the same rate, how long would it take him to drive 522 miles?

Answers

It would take him 9 hours to drive 522 miles since if you divide 638 with 11 you would get 58 and if you divide 522 with 58 you'll get 9.

Answer:

Step-by-step explanation:

Solve the inequality.Explain all steps and Identify the properties used. n/-3 + 5>4

Answers

n/-3>4-5
then you can just times by -3 to get n on it's own
n>-3(4-5)
n>-3*-1
n>3

For this..
[tex]\frac{n}{-3}+5 \ \textgreater \ \mathrm{Apply\:the\:fraction\:rule}:\ \frac{a}{-b}=-\frac{a}{b} \ \textgreater \ -\frac{n}{3}+5 \ \textgreater \ \frac{n}{3}+5\ \textgreater \ 4[/tex]

[tex]\mathrm{Subtract\:}5\mathrm{\:from\:both\:sides} \ \textgreater \ -\frac{n}{3}+5-5\ \textgreater \ 4-5 \ \textgreater \ \ \textgreater \ -\frac{n}{3}\ \textgreater \ -1[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:}3 \ \textgreater \ 3\left(-\frac{n}{3}\right)\ \textgreater \ 3\left(-1\right) \ \textgreater \ \mathrm{Simplify} \ \textgreater \ -n\ \textgreater \ -3[/tex]

[tex]\mathrm{Multiply\:both\:sides\:by\:-1\:\left(reverse\:the\:inequality\right)} [/tex]
[tex]\left(-n\right)\left(-1\right)\ \textless \ \left(-3\right)\left(-1\right) \ \textgreater \ \ \textgreater \ \mathrm{Simplify} \ \textgreater \ n\ \textless \ 3[/tex]

Hope this helps!

PLEASE HELP ANSWER WITH ALL STEPS PLS

NUMBER 3 WILL BE A PICTURE

QUESTION 4

Solve for n.
–2.34n = –12.168

n = 5.2

n = 9.828

n = –5.2

n = –9.828

QUESTION 5

Use a transformation to solve the equation.

–8c = 56

c = –48

c = 7

c = –7

c = 48

Answers

Hello.

Question 4:

-2.34n = -12.168
Divide both sides by -2.34;

n = 5.2 is your answer to #4 (Answer choice "C.)"

For Question 5:

-8c = 56
Divide both sides by -8 to solve for c;

c = -7 (remember your signs!) is your answer for #5 (Answer choice "C.)"

[tex] \frac{n}{-12.168} [/tex] = -2; To solve for this, we need to multiply both sides by -12.168 to isolate and solve for our variable.

[tex] \frac{n}{-12.168} [/tex] = -2; Multiply by -12.168

n = 24.336 (A negative multiplied by a negative results in a positive product.);

Your answer for #3 is n = 24.336 (Answer choice "B.)")

I hope this helps!

Answers:
3.) n = 24.336

4.) n = 5.2

5.) c = – 7

Explanations:

Which number has a 5 whose value is 10 times the value as the 5 in 24092.52

A.3,498.05
B.65
C.4835.19
D.859.24

Answers

C. 4835.19

24092.52's 5 is in the tenths, which means the 5 has to be in the one's place inside your answer

hope this helps

The answer is C. There ya go

An international company has 13,600 employees in one country. If this represents 19.3% of the company's employees, how many employees does it have in total?

Answers

Hi there! To solve this question, we can write and solve a proportion. Let’s set it up like this: 13,600/x = 19.3/100. We do this, because we’re looking for the total amount of people, which would be the whole. We already have the part. Cross multiply the values in order to get 1,360,000 = 19.3x. Now, divide each side by 19.3 to isolate the variable. When you do, you get x is approx. 70,466.3212 or 70,466 when rounded to the nearest whole number. Plus, you can’t have a fraction of a person, anyway. The company has a total of 70,466 employees.

Find the measure of angel b

Answers

52+88+x=180
140+x=180
x=40

If 3 onions weigh 0.75 lb,how much do 10 onions weigh

Answers

Use a proportion:

.75 / 3 = x /10

Solve for x

So if you do, 0.75 × 9 =6.75
Then, 0.75 ÷ 3 =0.25
Lastly, 6.75 + 0.25 = 7
Your final answer is 7.

The sum of two consecutive numbers is 95. What are the two numbers?

Answers

[tex]\huge{\boxed{47}}\ \ \huge{\boxed{48}}[/tex]

First, represent the situation with numbers and variables. The first number will be [tex]x[/tex] and the second number will be [tex]x+1[/tex]. [tex]x+x+1=95[/tex]

Combine like terms. [tex]2x+1=95[/tex]

Subtract 1 on both sides. [tex]2x=94[/tex]

Divide both sides by 2. [tex]x=\boxed{47}[/tex]

Find the second number. [tex]x+1\ =\ 47+1\ =\ \boxed{48}[/tex]

A stamp collector bought 160 stamps for $25.00. The purchase included 5¢ stamps, 15¢ stamps, and 25¢ stamps. The number of 15¢ stamps is three times the number of 5¢ stamps. How many of each type of stamp was purchased?

Answers

5- 30
15- 90
52- 40
Questions?

Final answer:

The stamp collector purchased 40 5¢ stamps, 120 15¢ stamps, and 0 25¢ stamps.

Explanation:

To solve this problem, let's assign variables to the number of each type of stamp purchased. Let x be the number of 5¢ stamps, y be the number of 15¢ stamps, and z be the number of 25¢ stamps. We are given that the number of 15¢ stamps is three times the number of 5¢ stamps, so we can write this as y = 3x. We also know that the total number of stamps is 160, so we have the equation x + y + z = 160.

Using these equations, we can set up a system of equations:

y = 3x

x + y + z = 160

We can substitute the first equation into the second equation to eliminate y:

x + 3x + z = 160

Combining like terms, we get 4x + z = 160. We can rearrange the equation to solve for z:

z = 160 - 4x

Now we can substitute this expression for z back into the second equation:

x + 3x + 160 - 4x = 160

Simplifying, we get 4x = 0. Solving for x, we find x = 40. Plugging this value back into the equation y = 3x, we get y = 120. Finally, we can find z by substituting x and y into the equation z = 160 - 4x:

z = 160 - 4(40) = 160 - 160 = 0.

So, 40 5¢ stamps, 120 15¢ stamps, and 0 25¢ stamps were purchased.

Learn more about Stamps here:

https://brainly.com/question/22056874

#SPJ12

The population of a town decreased from 15,925 people to 8759 people. What was the approximate percent decrease?

Answers

fourty four. nine percent so fourty five

65%

% change = 15925 / (15925 + 8759)

Simplify: % change = 15925 / 24684 = 0.645 = 64.5% which is 65% rounded.

Write 0.8 as a fraction.

Answers

Using the place value chart, we can see that the decimal 0.8 is eight-tenths, so we can write 0.8 as the fraction [tex]\frac{8}{10}.[/tex] We are able to simplify so we will divide the numerator and the denominator by 4.

Image is provided.

Therefore, the decimal 0.8 can be written as [tex]\frac{4}{5}[/tex].

Answer:

4/5

Step-by-step explanation:

0.8=8/10=4/5

What are the missing angles?

Answers

y=30
2y=60

i believe this is the correct answer

y +90+2y=180
3y=90
y=30
2y=60

What is the positive square root of 36? Enter your answer in the box.

Answers

the answer to this question is going to be negative 6

answer is 6

√36 = 6 because 6 x 6 = 36

Which expression results on a rational number?

Answers

where are the answers

What is the relationship between the values of the two 4s in 3.441

Answers

The first 4 (.4) is 10x bigger than the second 4 (.04)

Answer:

The given number is 3.441

The first 4 is in the tenth place that is written like [tex]\frac{4}{10}[/tex] or 0.4

The second 4 is in the hundredth place that is written like [tex]\frac{4}{100}[/tex] or 0.04

We can see that the second 4 is one tenth times the first 4. This is shown like = [tex]\frac{1}{10} \times\frac{1}{10}[/tex] = [tex]\frac{1}{100}[/tex]

Or we can say the opposite that the first 4 is ten times the second 4.

Maria has 5 6/7 square yards of fabric. She uses 2 2/3 square yards fo fabric to make a dress. Does she have enough fabric left over to make a shawl that takes 2 1/4 square yards of fabric?

Answers

yea she has enough to get the third

5 6/7 - 2 2/3 =

5 - 2 = 3
6/7 - 2/3 = 18/21 - 14/21 = 4/21
3 + 4/21 = 3 4/21
so she has 3 4/21 yds left over....so yes, she has enough to make the shawl that takes 2 1/4 yds

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