Answer:
7F is largest signed integer number, base 16, that can be store in a variable of type BYTE.
Explanation:
A BYTE has 8bits and it signed value ranges from -128 to 127. thus the largest maximum signed integer number, that can be store in a variable of type BYTE is 127.
Base 16 value for the decimal value of 127 is 7F.
Therefore 7F is largest signed integer number, base 16, that can be store in a variable of type BYTE.
What type of malicious software masquerades as legitimate software to entice the user to run it?
Answer:
Trojan horse
Explanation:
A Trojan horse is malicious software that masquerades as a legitimate computer program such as a video game, image file, utility program, or even an antivirus so as to entice the user to run it, thereby allowing an attackers (the developer of the malicious program) to gain access to the data on the computer in an illegal manner.
Consider the following class definition.public class Rectangle{private double length;private double width;public Rectangle(){length = 0;width = 0;}public Rectangle(double l, double w){length = l;width = w;}public void set(double l, double w){length = l;width = w;}public void print(){System.out.println(length + " " + width);}public double area(){return length * width;}public void perimeter(){return 2 length + 2 width;}}Suppose that you have the following declaration.Rectangle bigRect = new Rectangle();
Which of the following sets of statements are valid in Java?
(i) bigRect.set(10, 5);
(ii) bigRect.length = 10;bigRect.width = 5;
Answer:
The answer is "Option (i)".
Explanation:
In the given java code a class is defined that name is "Rectangle" inside a class two global private double datatype variable is defined that is "length and width". A default constructor is defined that contains the value of private variables. In the next line, a parameterized constructor and a set function is defined that contain the parameter values. Then three function is defined that is "print, area, and perimeter" in which print function prints value and area, perimeter function calculate values.
Option (i) is correct because it is the correct way to call the function. Option (ii) is incorrect because the private member does not accessible outside the class.
A user requests an unencrypted webpage from a web server running on a computer, listening on the Internet Protocol address 10.1.1.150. What will be the socket address?
Answer:
10.1.1.150:80
Explanation:
Socket address is the combination of an IP address and port number.
HTTP is what most unencrypted webpage use, instead of HTTPS which is the encrypted version of HTTP.
By default, webserver using Hypertext Transfer Protocol (HTTP) uses a standard port known as port 80.
The Socket address which is the combination of the IP address and standard port number will be something like this:
10.1.1.150:80
Based on the above scenario, the socket address will be 10.1.1.150:80.
What is socket address?This address is known to be composed of an IP address and also a port number. The client socket address is known to be the client method or process that is specific or uniquely made to that client.
Conclusively, the socket address will be 10.1.1.150:80 because the Unencrypted web traffic employs the use of port 80 and ports are said to be often denoted through the use of a colon after the IP address.
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Person-name: String+setName(String name): void+getName(): String^Student-studentID: long+Student(String sname, long sid)+setID(): longWhich of these fields or methods are inherited (and accessible) by the Student class?
1. getName(), setName(), name
2. name, getName(), setName(), getID()
3. studentID, name, getName(), setName(), getID()
4. getName(), setName(), toString()
5. None of them
6. getName(), setName(), studentID, getID()
Answer and Explanation:
Basically its answer is option 4 where getName(), setName().to String()
let us explained it through a program where get and set method has been used.
Create Student class that has marks and grade. Two parameters initialize data member using constructors .Each data member gives values and member function .Show the values of data member.
You can code it in turbo and Dev C++ tool .
# include<iostream.h>
#include<conio.h>
class Student
{
private:
int marks;
String name;
char grade;
public:
Student ( int m , char g) //get method where it get student marks and grade
{ marks = m ;
grade = g;
}
public void set Name(String a) {
name = a;
}
public String getName() {
return name;
}
void set()
{
cout <<"Marks = " <<marks <<endl;
cout<<"Name=" <<name<<endl;
cout <<"Grade = "<< grade <<endl;
}
};
void main ()
{
clrscr();
Student s1(730,'A','ali') s2(621,'B','haider')
cout <<"Recording of student 1 "<<endl;
s1.set();
cout <<"Recording of Student 2:"<<endl;
s2.set();
getch();
}
for the above program you can see from
//{
cout <<"Marks = " <<marks <<endl;
cout<<"Name=" <<name<<endl;
cout <<"Grade = "<< grade <<endl;
}//
where name marks and grade are inherited from the class Student with get and set methods.But name is take into data type of string because string hold zero ,more letters , space and commas.So it is used to represent the text data.
A system administrator suspects that there is an error in the replication configuration. How can the system administrator look for specific error messages related to replication?
A. By using the Active Directory Sites and Services administrative tool
B. By using the Computer Management tool
C. By going to Event Viewer > System Log
D. By going to Event Viewer > Directory Service Log
Answer:
Option D i.e., By going to Event Viewer > Directory Service Log is the correct option.
Explanation:
The following option is not false because the admin of the system assumes that there is the occurrence of the particular error message related to the replication, the main reason behind this is that the administrator firstly go the Event Viewer then, he go to the Directory Service Log. After that, a particular error message appears in the replication configuration.
Fill in the blanks:
a. __________ is based on travelling datagrams through internetworks one hop at a time. The entire route is unknown at the beginning of the journey.
b. __________ is group-based communication. It can be one-to-many or many-to-many distribution.
c. The most important requirement of a _______ network is the ability to treat different data types differently.
d. _______ process transmits telephone calls (voice) over the internet. 2
e. _______ is the standard recommended by the ITU for low bit-rate voice transmission over the Internet.
f. ________ is an unencrypted message data.
Answer:
(a). IP routing.
(b). Multicasting.
(c). converged.
(d). VoIP.
(e). VoIP.
(f). Plain text.
Explanation:
Ip routing is the method of transfer data from the one destination to another destination and it also send data from host to host across the network.
Multicasting is the type of distribution from one host to many hosts and also many hosts to many of them, it is used for the Internet Protocol Routing protocol in which the data is distributed to many receivers.
VoIP is that type of routing through which folks can use the internet services as the transmission mode.
Final answer:
Packet switching is based on travelling datagrams one hop at a time through internetworks. Multicast is group-based communication. A QoS network treats different data types differently.
Explanation:
a. **Packet switching** is based on travelling datagrams through internetworks one hop at a time. The entire route is unknown at the beginning of the journey.
b. **Multicast** is group-based communication. It can be one-to-many or many-to-many distribution.
c. The most important requirement of a **Quality of Service (QoS)** network is the ability to treat different data types differently.
d. **VoIP (Voice over IP)** process transmits telephone calls (voice) over the internet.
e. **G.729** is the standard recommended by the ITU for low bit-rate voice transmission over the Internet.
f. **Clear text** is an unencrypted message data.
Please Help!
Hailey wants to become a career counselor. What academic requirement will she need to complete in order to find a job?
A. a master’s degree
B. vocational training
C. on-the-job training
D. a doctorate degree
@$.
Explanation:
the answer is either c or b ask google not sure if my answer is correct
Answer:
A.
Explanation:
Under the Health Insurance Portability and Accountability Act (HIPAA) Security Rule, what type of safeguards must be implemented by all covered entities, regardless of the circumstances?
a. Addressable
b. Standard
c. Security
d. Required
Answer:
D. Required
Explanation: The required safeguard must be implemented for all covered entities.
Change the Towers of Hanoi program so that it does the following: a)Counts the number of ring moves and prints that - instead of the sequence of the moves. Use a static variable count of type int to hold the number of moves. b)Repeatedly prompts the user for the number of rings and reports the results, until the user enters a number less than 0
Answer:
Following are the program in the Java Programming Language.
//import scanner class package
import java.util.Scanner;
//define class
public class Tower_of_Hanoi {
//define static integer variable
public static int count = 0;
//define function
public static void Permute_Arrange(int n, char x, char ax, char to) {
//set if statement
if (n == 1) {
//increament in count by 1
++count;
}
//otherwise
else
{
Permute_Arrange(n - 1, x, to, ax);
++count;
Permute_Arrange(n - 1, ax, x, to);
}
}
//define main function
public static void main(String[] args)
{
//set scanner type object
Scanner sc = new Scanner(System.in);
//print message
System.out.println("Enter less than 0 to exit");
//set the while infinite loop
while(true)
{
//print message
System.out.print("Enter the number of Disks: ");
//get input from the user
int num_of_disk = sc.nextInt();
//set the if statement to break the loop
if(num_of_disk<0)
{
//exit from the loop
System.exit(0);
}
//call the function
Permute_Arrange(num_of_disk, 'A', 'B', 'C');
//print message with output
System.out.println("Total number of Disc Moves is: " + count);
count = 0;
}
}
}
Output:
Enter less than 0 to exit
Enter the number of Disks: 4
Total number of Disc Moves is: 15
Enter the number of Disks: 7
Total number of Disc Moves is: 127
Enter the number of Disks: -1
Explanation:
Here, we define a class named "Tower_of_Hanoi"
Set the integer data type static variable "count" and initialize the value to 0.Define void data type static function "Permute_Arrange" and pass three characters type arguments "x", "ax", and to and one integer type argument "n", inside it we set if condition to increment in the count variable otherwise call the function.Finally, we define the main function to get input from the user and pass the argument list in function and call the function.Suppose that you need to maintain a collection of data whose contents are fixed- i.e., you need to search for and retrieve existing items, but never need to add or delete items. Although the collection of data may be quite large, you may assume that it can fit in the computer's memory. Which of the following data structures is the most efficient one to use for this task?
a. a sorted array
b. a linked list
c. a binary search tree
d. a queue
e. they are all the same
Final answer:
A sorted array is the most efficient data structure for searching and retrieving existing items in a collection of fixed data.
Explanation:
The most efficient data structure to use for a collection of fixed data that needs efficient search and retrieval operations is a sorted array. A sorted array allows for fast search times using binary search, which has a time complexity of O(log n). This is because the elements in the array are sorted in a specific order, allowing for efficient comparisons.
In contrast, a linked list would require sequential traversal, resulting in a time complexity of O(n). A binary search tree can also provide efficient search times with a time complexity of O(log n), but it requires additional space for storing the tree structure.
A queue is not suitable for this task, as it is designed for adding and removing items, not for searching and retrieving existing items. Therefore, the most efficient data structure for this task is a sorted array.
Write a function named wordLineCount with the following input and output: Input: a string parameter, inFile, that is the name of a file Output: return a dictionary in which each unique word in inFile is a key and the corresponding value is the number of lines on which that word occurs The file inFile contains only lower case letters and white space. For example, if the file ben.txt contains these lines tell me and i forget teach me and i remember involve me and i learn then the following would be correct output:
>>> print(wordLineCount('ben.txt')){'remember': 1, 'and': 3, 'tell': 1, 'me': 3, 'forget': 1, 'learn': 1,'involve': 1, 'i': 3, 'teach': 1}
Answer:
def wordLineCount(file):
dic = {}
with open(file,'r') as file:
text = file.read()
text = text.strip().split()
for word in text:
if word in dic:
dic[word] += 1
else:
dic[word] = 1
return dic
print(wordLineCount('ben.txt'))
Explanation:
The programming language used is python.
The program starts by defining the function, an empty dictionary is created to hold the words and the number of times that they occur. the with key word is used to open the file, this allows the file to close automatically as soon as the operation on it is finished.
The data in the file is read to a variable text, it is striped from all punctuation and converted to a list of words.
A FOR loop and an if statement is used to iterate through every word in the list and checking if they are already in the dictionary. if the word is already contained in the dictionary, the number of occurrences increases by one. otherwise, it is added to the dictionary.
check the attachment to see code in action.
Given variables first and last, each of which is associated with a str, representing a first and a last name, respectively. Write an expression whose value is a str that is a full name of the form "Last, First". So, if first were associated with "alan" and last with "turing", then your expression would be "Turing,Alan". (Note the capitalization! Note: no spaces!) And if first and last were "Florean" and "fortescue" respectively, then your expression's value would be "Fortescue,Florean".
Answer:
The python code is attached
Explanation:
I defined a function called FullnameThe function accepts 2 parameters first and lastlast[0] gives the first letter of the last variable last[0].upper() modifies the first letter as upper lettersame applied to variable first+ sign concatenates strings and variables to the variable namethe function returns the variable nameFinal answer:
The answer provides a method for formatting first and last names into a specific string format "Last,First" with proper capitalization, using Python as an example. This involves string manipulation techniques including capitalization and concatenation.
Explanation:
The question is about creating an expression in a programming language to format names according to certain specifications. To achieve the result where a first and last name are transformed into a format "Last,First" with proper capitalization and no spaces in between, one can use a combination of string manipulation and formatting methods. For example, in Python, assuming first and last are your variables:
fullName = last.capitalize() + ',' + first.capitalize()
This line of code transforms both the first and last names to have their first letters capitalized using the capitalize() function. It then concatenates the last name with a comma, followed by the first name, creating a string in the desired format. This is a basic example that shows how to use string manipulation and formatting functions to format names correctly as per the given requirements.
PGP encryption can be performed from the command line as well. What is the PGP command line syntax to encrypt the my-message.txt file for a specific user (Sean) and save the output as secret-message.txt.gpg?
Answer:
pgp --encrypt "my-message.txt" --recipient (Sean) --output ("secret-message.txt.gpg")
Explanation:
PGP encryption from the command line can be done using the following format:
pgp --encrypt (input) --recipient (user) --output (output file)Therefore, PGP command line syntax to encrypt the my-message.txt file for a specific user (Sean) and save the output as secret-message.txt.gpg is:
pgp --encrypt "my-message.txt" --recipient (Sean) --output ("secret-message.txt.gpg")The PGP command line syntax for encrypting a file for a specific user and saving the output.
Explanation:The PGP (Pretty Good Privacy) command line syntax for encrypting a file for a specific user and saving the output is as follows:
Open the command line interface (CLI) on your computer.Navigate to the directory where the my-message.txt file is located.Enter the following command:gpg --recipient Sean --output secret-message.txt.gpg --encrypt my-message.txtThis command will encrypt the my-message.txt file using PGP for the user Sean and save the encrypted output as secret-message.txt.gpg.
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Assume the input data is structured as follows: first there is a non-negative integer specifying the number of employee timesheets to be read in. This is followed by data for each of the employees. The first number for each employee is an integer that specifies their pay per hour in cents. Following this are 5 integers , the number of hours they worked on each of the days of the workweek. Given this data, and given that an int variable total has been declared , write a loop and any necessary code that reads the data and stores the total payroll of all employees in total. Note that you will have to add up the numbers worked by each employee and multiply that by that particular employee’s pay rate to get the employee’s pay for the week– and sum those values into total.ASSUME the availability of a variable , stdin, that references a Scanner object associated with standard input.
Answer:
Following are the code of the program.
//set an integer data type variable
int num_Timesheets;
//set an integer data type variable and initialize to 0
int cents_PerHours = 0;
//set an integer data type variable
int hours_Worked;
//already declared and initialize to 0
total = 0;
//get input from the user
num_Timesheets = stdin.nextInt();
//set the for loop
for(int i = 1; i <= num_Timesheets; i++)
{
//initialize to 0
hours_Worked = 0;
//get input from the user
cents_PerHours = stdin.nextInt();
//set the for loop
for (int ii = 1; ii <= 5; ii++)
{
hours_Worked = hours_Worked + stdin.nextInt();
}
//perform calculation to find employee’s pay for the week
total = total + (hours_Worked * cents_PerHours);
}
Explanation:
Here, we set three integer data type variables "num_Timesheets", "cents_PerHours", and "hours_Worked" and initialize the value in the variable "cents_PerHours" to 0.
Then, initialize the value in the integer variable "total" to 0 which is already declared.
Finally, we set two for loop first one to get input from the user and the second one to perform a calculation to find employee’s pay for the week.
Design and code a program including the following classes, as well as a client class to test all the methods coded:A Passenger class, encapsulating a passenger. A passenger has two attributes: a name, and a class of service, which will be 1 or 2.A Train class, encapsulating a train of passengers. A train of passengers has one attribute: a list of passengers, which must be represented with an ArrayList. Your constructor will build the list of passengers by reading data from a file called passengers.txt. You can assume that passengers.txt has the following format:...For instance, the file could contain:James 1Ben 2Suri 1Sarah 1Jane 2...You should include the following methods in your Train class:
a method returning the percentage of passengers traveling in first class
a method taking two parameters representing the price of traveling in first and second class and returning the total revenue for the train
a method checking if a certain person is on the train; if he/she is, the method returns true; otherwise, it returns false
Answer:
Code given below
Explanation:
/*
* Class to hold the Passenger data
* Stores the name and classOfService
* */
public class Passenger {
String name;
int classOfService;
public Passenger(String string, int classOfService) {
this.name = string;
this.classOfService = classOfService;
}
@Override
public String toString() {
return "Passenger [name=" + name + ", classOfService=" + classOfService
+ "]";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + classOfService;
result = prime * result + ((name == null) ? 0 : name.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Passenger other = (Passenger) obj;
if (classOfService != other.classOfService)
return false;
if (name == null) {
if (other.name != null)
return false;
} else if (!name.equals(other.name))
return false;
return true;
}
public String getName() {
return name;
}
public int getClassOfService() {
return classOfService;
}
}
----
import java.util.ArrayList;
import java.util.List;
/* Train class for holding the
* passengerList.
* The passengerList is the list of Passenger Object
*/
public class Train {
List<Passenger> passengerList;
public Train() {
passengerList = new ArrayList<Passenger>();
}
public Passenger getPassenger(int index) {
if (index <= 0 && getTotalNumberOfPassengersOnBoard() < index) {
return null;
} else {
return passengerList.get(index - 1);
}
}
public void addPassenger(Passenger p) {
passengerList.add(p);
}
public int getTotalNumberOfPassengersOnBoard() {
return passengerList.size();
}
public boolean isPassengerOnBoard(String name) {
boolean flag= false;
for (Passenger p : passengerList) {
if (p.getName().equalsIgnoreCase(name)) {
flag = true;
break;
} else {
flag = false;
}
}
return flag;
}
public double getRevenue(double priceFirstClass, double priceSecondClass) {
double total = 0.0;
for (Passenger p : passengerList) {
if (p.getClassOfService() == 1) {
total += priceFirstClass;
} else {
total += priceSecondClass;
}
}
return total;
}
public double getPercentageFirstClassTravellers() {
double count = 0.0;
for (Passenger p : passengerList) {
if (p.getClassOfService() == 1) {
count++;
}
}
return count / getTotalNumberOfPassengersOnBoard() * 100;
}
@Override
public String toString() {
return "Train [passengerList=" + passengerList + "]";
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result
+ ((passengerList == null) ? 0 : passengerList.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
Train other = (Train) obj;
if (passengerList == null) {
if (other.passengerList != null)
return false;
} else if (!passengerList.equals(other.passengerList))
return false;
return true;
}
}
-----------
public class TrainTest {
public static void main(String[] args) {
Train t = new Train();
Passenger p1 = new Passenger("James", 1);
Passenger p2 = new Passenger("Sarah", 2);
Passenger p3 = new Passenger("Jhon", 1);
Passenger p4 = new Passenger("Test", 2);
// add other passengers Test1 .. Test6
for (int j = 1; j < 7; j++) {
t.addPassenger(new Passenger("Test" + j, j % 2));
}
t.addPassenger(p1);
t.addPassenger(p2);
t.addPassenger(p3);
t.addPassenger(p4);
System.out.println("total revenue $" + t.getRevenue(10.0, 25.0));
System.out.println("total number of passengers on Board .. "
+ t.getTotalNumberOfPassengersOnBoard());
System.out.println("percentage of first class traveller .. "
+ t.getPercentageFirstClassTravellers());
System.out.println("getPassenger number # 2 .. " + t.getPassenger(2));
System.out.println("is passenger Jhon on board ? "
+ t.isPassengerOnBoard("Jhon"));
System.out.println("is passenger Dummy on board ? "
+ t.isPassengerOnBoard("Dummy"));
System.out.println("Printing all the Passengers on Board ...");
for (int i = 1; i <= t.getTotalNumberOfPassengersOnBoard(); i++) {
System.out.println("" + t.getPassenger(i));
}
// using the the Train toString to print all the passengers from Train
System.out.println(t.toString());
}
}
To use the mail merge feature in Access, the first step is to start the Microsoft Word Mail Merge Wizard.
a. True
b. False
Answer:
A) True
Explanation:
While working with MS Access, the mail merge feature allows us to quickly pickup records from the database tables and insert them on Microsoft word documents such as letters/envelops and name tags before printing them. The main advantage of a mail merge is the time saved as the process of creating several mailings for different individual letters/envelops is made simple.
The first step in creating a mail merge is starting the Microsoft Word Mail Merge Wizard in MS Access which will guide you in the entire steps, some of these steps include:
1. Selecting the document you wish to work with
2. Switching to MS Word
3. Selecting the the size of the envelope .
4. Selecting the recipients records from the database table
5. Arranging and inserting records from the database (addresses on the envelope).
6. Review/Preview and Print
Create a FLOWCHART and a PSEUDOCODE for each problem.
Use the information below to create a pseudocode (which can be a text-based description for solving the problems) and a flowchart (using flowchart symbols to illustrate how you would program) to solve each problem. You may use Microsoft Word® for your pseudocode and Microsoft PowerPoint® for your flowchart.
1. Problem 1: Write a program that will calculate the problem and stop after the condition has been met. This is an IF/THEN/ELSE problem.
a=1
b=a+1
c=a+b
Condition: If c is less than 5, then the loop will continue; else, it will end.
2. How many loops will be necessary to meet the condition incrementing 'c' by 1? Why?
Provide a correct response to "How many loops will be necessary to meet the condition incrementing 'c' by 1? Why?"
Answer:
1.
Problem 1: I am using IF ELSE in this pseudo code
PSEUDOCODE1
initialize a to 1
b = a+1
c = a + b
If c is less than 5
start from the beginning (and increment a)
else
stop the program
This can be better done using simple english words
PSEUDOCODE2
Steps Statement
01 initialize a to 1
02 assign value of a+1 to b
03 assign the sum of a and b to c
04 If c is less than 5
05 go to the beginning
06 increment a in 01
07 repeat 02 and 03
08 repeat steps 06 02 and 03 Until c<5
09 else stop
Flowchart
It is given in the attached file flowchart
Problem 2
In the question the condition increment 'c' by 1 seems to be a typo. and it should be 'a' by 1. If we increment c by 1 each loop, it does nothing because c is will be set again by the calculation of c = a + b.
IF the condition is increment c by 1 then the answer is that no amount of loops will have c meet the condition as it resets each loop.
For the condition increment a by 1 the answer is that it will take two loops. First loop c has 3 and in the second loop if it is according to incrementing by 1, c is 5. When c is 5 this means that the condition c<5 becomes false as c gets equal to 5. So the program will end after this i.e after 2nd loop.
Lets understand this
At first a=1, b=a+1=1+1=2, so b=2, c=a+b so c=1+2 c=3At second a is incremented by 1, so it becomes a=2, b=a+1 so b=2+1 so b=3, c=a+b which means c=2+3 so c=5Program ends after two loops as the condition has been met.Above pseudo code can be modified for 2 as
PSEUDOCODE1
initialize a to 1
b = a+1
c = a + b
If c is less than 5
start from the beginning (and increment a)
else
stop the program
print a
Flowchart 2 is attached
For the condition incrementing c by 1
PSEUDOCODE
a=1
b=a+1
c=a+b
while c is less than 5:
increment c by 1
END while
display c
Flowchart 3 is attached
Number of loops here will be 5. This is explained below:
first iteration: a=1, b=2, c=3c<5 so c is incremented by 1. This means c becomes 4 (c=3+1)condition c<5 is again true, so c is incremented by 1 again, This means value of c becomes 5 (c=4+1). The loop breaks as the condition c<5 gets false because now the value of c=5. This value is displayed.So 5 loops will be necessary to meet this condition.
Write a function isRed() that accepts a string parameter and looks for the presence of the word ‘red’ in the string. If it is found, return boolean True otherwise False. Finally output the result of calling the function with the value in text.
Answer:
Using the Python Programming Language:
def isRed(myString):
if "red" in myString:
return True
else:
return False
Explanation:
The function definition is given above. To output the result of calling this function, we declare a string variable and call the function inside a print statement. See the two lines of code below:
myString= "My house is coloured red"
print (isRed(myString))
Notice that we defined the function called isRed to receive a string as a parameter, Then using the in keyword with an if statement, we check for the presence of the word 'red' in the string that is passed as argument to the function, the function will then return True if the word 'red' is present or False if it is not.
Answer:
Following is the code for the function isRed() that works according to given scenario:
import sys
text = sys.argv[1]
def isRed(text):
if(text.find('red')!=-1):
return True
else:
return False
Explanation:
First of all the input is taken from the user through command line using statement text = sys.argv[1]The function named isRed is defined by putting text variable as parameter to it.The function uses if else statement and says if the input text contains red then return True as the output to the function.Otherwise if 'red' is not found then the output of the function will be False.i hope it will help you!
Explain how you would assess the operating system requirements for virtualization if the organization wanted to virtualize 25% of physical stand-alone servers.
Answer:
The requirement of the virtualization in the operating system:
• The virtualization of the resources from single systems input can be partitioned into a small virtual environment in multiple system data processes.
• Virtualization can collect the physical system's hardware and software data, they can transfer the virtualization process and also verify that the working system is running properly.
• Virtualization has to determine the specific components such as workload, file location, network traffic and console administration process. The requirement for moving into the virtual environment must be selected based on windows for the operating system(32-bit), windows host operating system(4-bit) and Linux operating system.
To assess operating system requirements for virtualization, one needs to check OS compatibility, monitor resource usage for CPU, memory, and storage, evaluate the network configuration and security features, and consider licensing requirements for virtualized environments.
Explanation:Assessing Operating System Requirements for VirtualizationTo assess the operating system requirements for virtualization when planning to virtualize 25% of physical stand-alone servers, an organization needs to analyze several key aspects. Firstly, identify the types of operating systems running on the current servers and check their compatibility with the chosen virtualization platform. The next step is to understand the resource requirements by monitoring the current usage of CPU, memory, and storage. Each virtual machine (VM) will need adequate resources allocated to perform optimally.
Additionally, it is important to evaluate the current network configuration to ensure that it can handle the increased network traffic caused by virtualization. Security features are another important aspect, with attention to be given to the built-in security measures of the operating systems in the context of a virtual environment.
Finally, consider the licensing implications as some operating systems may have different licensing requirements when run on a virtualized environment compared to physical servers. This evaluation will assist in creating a smooth transition plan and ensuring the organization's infrastructure is ready for virtualization.
create a new Java application called "CheckString" (without the quotation marks) according to the following guidelines.** Each method below, including main, should handle (catch) any Exceptions that are thrown. ** ** If an Exception is thrown and caught, print the Exception's message to the command line. **Write a complete Java method called checkWord that takes a String parameter called word, returns nothing, and is declared to throw an Exception of type Exception. In the method, check if the first character of the parameter is a letter. If it is not a letter, the method throws an Exception of type Exception with the message of: "This is not a word."Write a complete Java method called getWord that takes no parameters and returns a String. The method prompts the user for a word, and then calls the checkWord method you wrote in #1 above, passing as a parameter the word the user provided as input. Make sure the getWord method handles the Exception that may be thrown by checkWord.
Answer:
The Java code is given below
Explanation:
import java.io.*;
import java.util.Scanner;
import java.util.ArrayList;
public class StringCheck{
//There are several implementation approaches. This is one example framework/outline which might be helpful. Please feel free to try other approaches.
public static void checkWord(String word) throws Exception {
// Uses charAt method to test if the first letter of string variable word
// is a character. If not, throw new exception
if(Character.isLetter(word.charAt(0))){
return;
}else{
throw new Exception("This is not a word");
}
}
public static String getWord() {
// Declare a local scanner
// Prompt the user to enter a word
// Think about using a loop to give the user multiple opportunities to correctly enter a string
// Read into a string
// Call checkWord method passing the string as a parameter
// checkWord can throw an exception; call checkWord in a try/catch block
// Return the string to main if a valid string
Scanner sc = new Scanner(System.in);
boolean st = true;
String word = null;
while(st){
System.out.println("Enter a Word : ");
word = sc.next();
try{
checkWord(word);
st = false;
}catch(Exception e){
System.out.println(e);
st = true;
}
}
sc.close();
return word;
}
public static void writeFile(String[] arrayToWrite, String filename) throws IOException {
// Example using FileWriter but PrintWriter could be used instead
// Create a FileWriter object
FileWriter fileWordStream = new FileWriter(filename);
// Use a loop to write string elements in arrayToWrite to fileWordStream
for(int i = 0;i<arrayToWrite.length;i++){
fileWordStream.write(arrayToWrite[i]+System.lineSeparator());
}
fileWordStream.flush();
fileWordStream.close();
// In the loop use the lineSeparator method to put each string on its own line
}
public static ArrayList readFile(String filename) throws FileNotFoundException, IOException {
// Declare local ArrayList
ArrayList<String> words = new ArrayList<>();
// Create a new File object using filename parameter
File file = new File(filename);
// Check if the file exists, if not throw a new exception
if(!file.exists()){
throw new FileNotFoundException("File not Found");
}
// Create a new BufferedReader object
Scanner fsc = new Scanner(file);
// use a loop and the readLine method to read each string (on its own line) from the file
while(fsc.hasNextLine()){
words.add(fsc.nextLine());
}
fsc.close();
// return the filled ArrayList to main
return words;
}
public static void main(String[] args) {
// create a string with literal values to write to the file
String[] testData = {"cat", "dog", "rabbit"};
// Create an ArrayList for reading the file
ArrayList<String> words = new ArrayList<>();
// Declare a string variable containing the file name "data.txt"
String file = "data.txt";
// Call getWord, assign the returned string to a variable and display it
String word = getWord();
System.out.println("The word is : "+word);
// Call writeFile and readFile methods in a try block
try{
writeFile(testData,file);
words = readFile(file);
// Printout the contents of the ArrayList after the call to readFile
for(int i = 0;i<words.size();i++){
System.out.println(words.get(i));
}
}catch(FileNotFoundException e){
System.out.println(e);
}catch(IOException e){
System.out.println("IOException: error occured in input output");
}
// catch two types of exceptions
}
}
Final answer:
To create the 'CheckString' Java application, you need to write a method called 'checkWord' that throws an Exception if the word doesn't start with a letter, and another method called 'getWord' that prompts the user for input and handles any Exceptions thrown by 'checkWord'.
Explanation:
To create a new Java application called CheckString, you need to write two methods. The method checkWord will take a String parameter and throw an Exception if the word does not start with a letter. The method getWord will prompt the user for a word, call checkWord, and handle any Exceptions.
Method: checkWord
public void checkWord(String word) throws Exception {
if (Character.isLetter(word.charAt(0)) == false) {
throw new Exception("This is not a word.");
}
// otherwise, the input is considered a valid word
}
Method: getWord
public String getWord() {
Scanner scanner = new Scanner(System.in);
while (true) {
try {
System.out.print("Enter a word: ");
String word = scanner.nextLine();
checkWord(word);
return word;
} catch (Exception e) {
System.out.println(e.getMessage());
}
}
}
Which section in an ethernet frame contains the data from higher layers, such as Internet Protocol (IP) and the transport and application layers?
Answer:
The correct answer to the following question will be Payload.
Explanation:
Payload: The section that contains the data from the higher layer, such as the transport layer, application layer and Internet Protocol (IP) is Payload.
It carries the capacity of the transmission data unit or other packets.The data is received by the system of the destination.The section in an ethernet frame which contains the data from higher layers, such as Internet Protocol (IP) and the transport and application layers is: Payload.
A payload can be defined as a section of an ethernet frame comprising the transmitted data from higher layers of the open systems intercommunication (OSI) model such as:
Internet Protocol (IP) layer.Transport layer.Application layer.On a related note, the encapsulating security payload (ESP) protocol is a standard protocol that provides secrecy for the transmitted data via network communications, as well as system-to-system authentication and data integrity verification so as to prevent unauthorized access.
In conclusion, the encapsulating security payload (ESP) protocol is a transport layer protocol that provides data confidentiality, integrity and authentication in IPv6 and IPv4 protocols.
Read more: https://brainly.com/question/24214475
(Method Overloading)
Given the following methods, write down the printed output of the method calls:
public static void doSomething(String x) { System.out.println("A");
}
public static void doSomething(int x) { System.out.println("B");
}
public static void doSomething(double x) { System.out.println("C");
}
public static void doSomething(String x, int y) { System.out.println("D");
}
public static void doSomething(int x, String y) { System.out.println("E");
}
public static void doSomething(double x, int y) { System.out.println("F");
} Method calls
1. doSomething(5);
2. doSomething (5.2, 9);
3. doSomething(3, "Hello");
4. doSomething("Able", 8);
5. doSomething ("Alfred");
6. doSomething (3.6);
7. doSomething("World");
Answer:
1. doSomething(5);
B
2. doSomething (5.2, 9);
F
3. doSomething(3, "Hello");
E
4. doSomething("Able", 8);
D
5. doSomething ("Alfred");
A
6. doSomething (3.6);
C
7. doSomething("World");
A
Explanation:
Method overloading is an ability available in some programming languages such as Java to enable two or more methods share the same name but with different argument list.
For example, a method with a single string argument doSomething(String x). The method can be overloaded by having a different argument list as follows:
doSomething(int x) - different variable typedoSomething(String x, int y) - different number of argumentsdoSomething(int y, String x) - different sequence of arguments
When calling the method with a specified argument list such as doSomething("Able", 8), only the matched version (e.g. doSomething(String x int y)) will be invoked and print out D.
Which of the following is a best practice regarding the Administrator account?
A. This account should be used by the Administrator at all times, never his or her own account.
B. This account should be given a nondescript account name that cannot be easily guessed.
C. This account should be used only for low-level access to the network.
D. This account should be used only to run low-security applications.
Answer:
B. The account should be given a nondescript account name that cannot be easily guessed.
1. Please write the following code in Python 3.2. Please also show all outputs.Create a dictionary named letter_counts that contains each letter and the number of times it occurs in string1. Challenge: Letters should not be counted separately as upper-case and lower-case. Intead, all of them should be counted as lower-case.string1 = "There is a tide in the affairs of men, Which taken at the flood, leads on to fortune. Omitted, all the voyage of their life is bound in shallows and in miseries. On such a full sea are we now afloat. And we must take the current when it serves, or lose our ventures."
Answer:
string1="There is a tide in the affairs of men, Which taken at the flood, leads on to fortune. Omitted, all the voyage of their life is bound in shallows and in miseries. On such a full sea are we now afloat. And we must take the current when it serves, or lose our ventures."
string1=string1.lower() #covert whole string to lowercase
letter_counts={}
for ch in string1:
letter_counts[ch]=letter_counts.get(ch,0)+1 #updates counter for each letter
letter_counts['o']
OUTPUT :
17
Explanation:
lower() is used to change the string to lowercase characters so that uppercase and lowercase is not differentiated for the same letter. After that, letter_counts is declared as a dictionary which is empty. for loop is used in which every letter of string will be stored ch variable. Dictionary in python has a get method in which 2 arguments can be passed, first one is the key whose value to be retrieved and the other argument would be default value to be set if not found and ch in string1 will increment the value of key ch in letter_counts.
Which two security measures must an engineer follow then implementing Layer 2 and Layer 3 network design?
A.Utilize the native VLAN only on trunk ports to reduce the risk of an Double-Tagged 802.1q VLAN hopping attack
B.Utilize an access list to prevent the use of ARP to modify entries to the table
C.Utilize DHCP snooping on a per VLAN basis an apply ip dhcp snooping untrusted on all ports
D.Utilize the ARP inspection feature to help prevent the misuse of gARPE.Utilize private VLANs an ensure that all ports are part of the isolated port group
Answer:
A. Utilize the native VLAN only on trunk ports to reduce the risk of a Double-Tagged 802 1q VLAN hopping attack
C. Utilize DHCP snooping on a per VLAN basis an apply IP DHCP snooping entrusted on all ports.
D. Utilize the ARP inspection feature to help prevent the misuse of garpe Utilize private VLANs an ensure that all ports are part of the isolated port group.
Explanation:
We must configure the native VLAN only on trunk ports because in this way we are not to receive fake VLAN, and can steal information.
We can use DHCP snooping to configure trusted ports and entrusted ports, in this case, the trusted port can accept trust messages, only with those messages we can connect with the server.
We could ask the MAC address with ARP inspections, MAC address is unique value for a physical hardware in the world.
Problems with using a single Local Area Network (LAN) to interconnect devices on a premise include ______.
A. insufficient reliability, limited capacity, and inappropriate network interconnection devices
B. insufficient reliability, limited capacity, and limited distances
C. insufficient reliability, limited distances, and inappropriate network interconnection devices
D. limited distances, limited capacity, and inappropriate network interconnection devices
Answer:
A. insufficient reliability, limited capacity, and inappropriate network interconnection devices
Explanation:
LANs are unsecured and unreliable because they provide a way of another users to have access to others computers. They are also difficult to manage and access because the data they use is always shared between many different sources and this reduces the internet speed and limits the network capacity.
Which components can be added to a lightning app on custom object (choose 3 answers)A. Visualforce B. Standard Lightning component C. Custom lightning component D. global actions E. object specific actions on the custom object
Answer:
b. Standard Lightning component.
c. Custom Lightning component.
d. Global actions
These three components are best used in a ligthening app, for custom object i.e standard, Custom and Global Actions.
Adding Visualforce components to a Lightning Application is impossible, but one can add Lightning components into Visualforce pages.
A company purchased a high-quality color laser printer to print color brochures and sales proposals. The printer is connected to a marketing PC via USB and is configured as a shared local printer for use by the sales and marketing teams. The manager is concerned about the cost of consumables for the printer and does not want users to unintentionally print to the printer. What can be done to ensure that only authorized users can send print jobs to the printer?
Answer:
In order to ensure that only authorized users can send print jobs to the printer, the option of enabling the user authentication on shared printer can be used.
Explanation:
The manager can create user Id and password only for those people who have the permission to send the printer jobs to the printer. In this way, whenever a command is given to the printer, it will ask the user credentials before doing the printing job. If the person is unable to give the credentials then the printing will not start. Moreover, it will decrease the probability of the printing unintentionally so it will save the resources from wastage.You just finished training a decision tree for spam classification, and it is gettingabnormally bad performance on both your training and test sets. You know that yourimplementation has no bugs, so what could be causing the problem?
(a) Your decision trees are too shallow.
(b) You need to increase the learning rate.
(c) You are overfitting.
(d) All of the above
Answer:
Option B is the correct option.
Explanation:
The following answer is true because when the person completed our training of a decision tree and after the following presentation he getting not good working performance on both side i.e., test sets and during the training period. After the training there is no bug on the implementation of the presentation then, he has to increase the rate of the learning.
The option that is causing the bad performance problem is that your decision trees are too shallow.
What is a decision tree?A decision tree is known to be a kind of decision support tool that is often employed in a tree-like model of decisions and the consequences that follows these decision.
They include the likelihood of event outcomes, resource costs, and others. The reason why the individual is getting bad performance on both the training and test sets is that the decision trees are too shallow and as such one should widen the decision tree to get better result.
Learn more about decision tree from
https://brainly.com/question/26675617
The Universal Containers customer support organization has implemented Knowledge Centered Support (KCS) in the call center. However, the call center management thinks that agents are not contributing new knowledge articles as often as they should. What should the company do to address this situation? ( Select 2 )
A. Require agents to check a box on case when submitting a new suggested article
B. Create a dashboard for articles submitted by agents & approved for publication
C. Measure & reward agents based on the # of new articles submitted for approval
D. Measure & reward agents based on the # of new articles approved for publication
Answer:
B. Create a dashboard for articles submitted by agents and approved for publication.
C. Measure & reward agents based on the # of new articles submitted for approval.
Explanation:
A data dashboard is a tool that manages, visually traces, displays and measures success in meeting performance objectives. In this scenario, creating a dashboard will keep track of submitted and approved publication. This helps agents to determine the quality of their articles. It guarantees that the correct procedures and methodology are being pursued for article creation. This will increase productivity of the company and saves time as the staff would not have to spend a lot of time in making reports in Excel. As a matter of fact when agents view their key measurements on dashboard, they will instinctively start improving and contributing new knowledge articles. Measuring and rewarding agents on the basis of new articles submitted for approval is a way to encourage and motivate the agents in order to make them make contributions. As a result of this motivation they will work harder. Giving rewards as encouragement will also attract new agents.