The leader of the group brought 8.03 ounces of trail mix. The hikers only ate 5.26 ounces of the trail mix. How much trail mix was left?

Answers

Answer 1

8.03 oz at the start- 5.26 oz eaten= 2.77 oz left

Final answer: 2.77 oz

Related Questions

Evaluate the limit using the appropriate limit law(s). (if an answer does not exist, enter dne.) lim x → 1 2x2 + 4 x2 + 4x − 4

Answers

Presumably, the limit to be evaluated is

[tex]\displaystyle\lim_{x\to1}\frac{2x^2+4}{x^2+4x-4}[/tex]

Since the given function is continuous at [tex]x=1[/tex], the limit of function is equal to the value of the function at [tex]x=1[/tex]:

[tex]\displaystyle\lim_{x\to1}\underbrace{\frac{2x^2+4}{x^2+4x-4}}_{f(x)}=f(1)=\frac{2+4}{1+4-4}=6[/tex]

Find the common ratio of the geometric sequence: −320,80,−20,5,…−320,80,−20,5,… A. −14−14 B. 1414 C. -4 D. 4

Answers

I'm assuming the sequence is: -320, 80, -20, 5

Divide each term by the previous term to get the common ratio r

r = (term 2)/(term 1) = 80/(-320) = -1/4
r = (term 3)/(term 2) = -20/80 = -1/4
r = (term 4)/(term 3) = 5/(-20) = -1/4

No matter which term you pick (as long as it's not the first one) dividing it by the previous term leads to -1/4 or -0.25 as the common ratio

Answer: -1/4

It seems like none of the answer choices have -1/4 but it could be choice A was supposed to show "-1/4" instead of "-14"? Perhaps the division sign didn't show up for some reason?

The volume of the Moon is about 2.18×10102 cubic kilometers. The volume of Earth is about 1.09×10121 cubic kilometers. The number of Moons that can fit inside Earth can be found by dividing Earth's volume by the Moon's volume. About how many Moons can fit inside Earth?

Answers

Volume of Earth is 1.09×1012 cubic kilometers

Volume of Moon is 2.18×1010 cubic kilometers

Hence number of Moons that can fit in Earth is

1.09×10122.18×1010

= 1012−102 as 2.18=1.09×2

= 1022

= 1002=50

Answer:

50 moons

Step-by-step explanation:

cause i got it right on the test

1 + 2 + 3 + 4 + 5 + . . . is an example of a finite series. True False

Answers

True is my answer hope I helped u

The ellipsis would indicate an infinite series. So I would say false.

(Technically all series are infinite, if they are not infinite they should be referred to as sequences.)

Find a_1 and d for an arithmetic sequence with these terms. a_4=9and a_7=18

Answers

[tex]\bf \begin{array}{llll} term&value\\ -----&-----\\ a_4&9\\ a_5&9+d\\ a_6&(9+d)+d\\ &9+2d\\ a_7&(9+2d)+d\\ &9+3d=\underline{18} \end{array}\\\\ -------------------------------\\\\ 9+3d=18\implies 3d=9\implies d=\cfrac{9}{3}\implies \boxed{d=3}[/tex]

[tex]\bf n^{th}\textit{ term of an arithmetic sequence}\\\\ a_n=a_1+(n-1)d\qquad \begin{cases} n=n^{th}\ term\\ a_1=\textit{first term's value}\\ d=\textit{common difference}\\ ----------\\ n=7\\ d=3 \end{cases} \\\\\\ a_7=a_1+(7-1)d\implies 18=a_1+(7-1)3\implies 18=a_1+18 \\\\\\ 18-18=a_1\implies \boxed{0=a_1}[/tex]

You deposit $5000 in an account earning 2% interest compounded continuously. How much will you have in the account in 15 years?

Answers

The compound interest is given by:
A=p(1+r/100)^n
where:
A=future amount
p=principle
r=rate
n=time in years
Therefore given that, p=$5000, r=2% and n=15 years, the amount after 15 years will be:
A=5000(1+2/100)^15
A=5000(1+0.02)^15
A=5000(1.02)^15
A=6,729.34
We conclude that the amount after 15 years will be $6,729.34

The extreme rock climbing club planned a climbing expedition. The total cost was $5000, which was to be divided equally among the members going. Prior to the trip, 3 members decided not to go. If the cost per person increases by $375, how many people went on the expedition?

Answers

Most useful original number of planned climbers were 687 members .hope i helped

687 I am pretty sure hope it helps,,,,,,,,,,m,,,,

Which of the following gives all of the sets that contain -1/2?

A.the set of all rational numbers and the set of all real numbers
B.the set of all natural numbers and the set of all irrational numbers
C.the set of all integers and the set of rational numbers
D.the set of all natural numbers, the set of rational numbers, and the set of all real numbers

Answers

i think it might be.... A.the set of all rational numbers and the set of all real numbers

Answer:

Option A is Correct Option.

Step-by-step explanation:

Given: [tex]\frac{-1}{2}[/tex]

[tex]\frac{-1}{2}[/tex] is a rational no.

Option A:

Given no is a rational no.

⇒ Both Set of rational no and real nos. contain rational nos..

Thus, Correct Option.

Option B:

set of natural nos and irrational nos does not contain rational nos.

Thus, Not correct option.

Option C:

Set of integers does not contain rational numbers.

Thus, Incorrect Option.

Option D:

Set of all Natural Nos. does not contain rational nos.

Thus, This option is not correct option

Therefore, Option A is Correct Option.

You are trying to determine the half-life of a new radioactive element you have isolated. You start with 1 gram, and 5 days later you determine that it has decayed down to 0.7 grams. What is its half-life? (Round your answer to three significant digits.)

Answers

The half-life of a given radio active material is given by:
t(1/2)=[tln2]/[lnN-lnN(t)]
where;
t=time
N=initial amount
N(t)=final amount
thus the half-life of our material will be as follows:
t=5 days
N=1 g
N(t)=0.7 g
N(1/2)=[5*ln2]/[ln1-ln0.7]
=9.717

Suppose an isosceles triangle ABC has A = 45° and b = c = 4. What is the length of a2?

Answers

You can use the Law of Cosines (a^2=b^2+c^2-2bc cosA)

a^2=4^2+4^2-2*4*4*cos45°

a^2=32-32cos45°

a^2=32(1-cos45°)

a=√(32(1-cos45°))

a≈3.06 units (to nearest hundredth of a unit)

If a wheel with a radius of 80 inches spins at a rate of 50 revolutions per minute, find the approximate linear velocity in miles per hour.

Answers

[tex]\bf \textit{arc's length}\\\\ s=rw\qquad \begin{cases} r=radius\\ w=\textit{angular speed} \end{cases}\qquad w=\cfrac{50 rev}{min}\cdot \cfrac{2\pi }{rev} \\\\\\ w=\cfrac{100\pi }{min}\qquad s=80in\cdot \cfrac{100\pi }{min}\implies s=\cfrac{8000\pi\ in}{min}\\\\ -------------------------------\\\\ \textit{now to convert it to miles/hr} \\\\\\ \cfrac{8000\pi\ in}{min}\cdot \cfrac{ft}{12in}\cdot \cfrac{mile}{5280ft}\cdot \cfrac{60min}{hr}\implies \cfrac{8000\pi \cdot 60\ in}{12\cdot 5280\ hr}[/tex]

A rug is shaped like a rectangle who's per Perimeter there's 192 feet the length is five times longer with find the length and the width

Answers

P = Perimeter = 2(length) + 2(width). Let the width be x; then if the length is 5 times longer than the width, the length is 5x.

Plug these values into the Perimeter equation P = 2(length) + 2(width):

P = 2(5x) + 2(x), or P = 12x, and this is known to have the value 192 units. Solve for the width, x:

(192 units) = 12x gives us x = 16 units. Then the length is 5(16 units) = 80 units.

Check: Does 2(80 units) + 2(16 units) = 192 units? If so, then our width (16) and length (80) are correct.

A new cruise ship line just launched 3 new ships: the Pacific Paradise, the Caribbean Paradise, and the Mediterranean Paradise.
The Caribbean Paradise has 29 more than the Pacific Paradise. The Mediterranean Paradise has 30 fewer deluxe staterooms than twice the number of deluxe staterooms on the Pacific Paradise. Find the number of deluxe staterooms for each of the ships if the total of deluxe staterooms for the total of the three ships is 719.

Answers

c = caribbean, p = pacific, m = mediterranean

c = p + 29
m = 2p - 30
c + m + p = 719

(p + 29) + (2p - 30) + p = 719
4p - 1 = 719
4p = 719 + 1
4p = 720
p = 720/4
p = 180 <=== pacific paradise deluxe staterooms

c = p + 29
c = 180 + 29
c = 209 <=== caribbean paradise deluxe staterooms

m = 2p - 30
m = 2(180) - 30
m = 360 - 30
m = 330 <=== mediterranean paradise deluxe staterooms

Final answer:

To find the number of deluxe staterooms for each of the three ships, we can set up and solve an equation based on the given information.

Explanation:

Let's represent the number of deluxe staterooms on the Pacific Paradise ship as x.

The number of deluxe staterooms on the Caribbean Paradise is 29 more than the Pacific Paradise, so it can be represented as x + 29.

The number of deluxe staterooms on the Mediterranean Paradise is 30 fewer than twice the number of deluxe staterooms on the Pacific Paradise, so it can be represented as 2x - 30.

We can form an equation with the sum of the deluxe staterooms on all three ships: x + (x + 29) + (2x - 30) = 719.

Simplifying the equation gives us 4x - 1 = 719.

By adding 1 to both sides and dividing by 4, we can find the value of x which represents the number of deluxe staterooms on the Pacific Paradise ship.

Finally, we can substitute the value of x into the expressions for the other two ships to find their number of deluxe staterooms.

Learn more about Finding the number of deluxe staterooms on three cruise ships here:

https://brainly.com/question/305669

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A cone has a volume of 12 cubic inches. What is the volume of a cylinder that the cone fits exactly inside of?

Answers

check the picture below.

notice, the volume of a cylinder which is the same height(h) and radius(r) as a cone, is three times as much of that of the cone's.

Kathy walked 3 1/2 miles per hour for 1 1/4 hours. During 1/2 of her walking time it rained. How many miles did she walk while it was raining?

Answers

I think it's 2.2 miles walking in the rain

1 1/4 = 5/4 * 1/2 = 5/8

3 1/2 = 7/2 * 5/8 = 35/16 = 2 3/16 miles

The perimeter of a rectangular field is 168 feet. The field is 36 feet wide. How long is the field

Answers

To find the length, divide the peremiter by 2 and then subtract the width.

Length= Peremiter/2 - width
L = P/2 - W
L = 168/2 - 36
L = 84 - 36
L = 48

The length is 48

A rectangular greenhouse has an area of 6480 square meters and a length of 120 meters. How many meters is it in width?

Answers

Area is length x width. If the area is 6480, and you know the length, plug it into the formula to find the width.

120 x width = 6480

So, to solve, you would divide 6480 by 120 to find the width. 6480/120 = 54.

Therefore, the width is 54.

Comment under this post or message me for further help!

A=LW

W=A/L, A=6480 and L=120 so

W=6480/120 m

W=54 m

Expand the fraction 72/125 .so that it has a denominator of 1000.

Answers

x/1000=72/125 multiply both sides by 1000

x=72000/125

x=576

So the fraction is 576/1000

Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a unit of pressure). Construct an exponential model to represent the atmospheric pressure at a given altitude in thousands of meters. Use your model to determine the atmospheric pressure at an altitude of 4000 meters.
(Express your answer in millibars rounded correctly to the nearest tenth.)

Answers

at sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

[tex]\bf \textit{Periodic Exponential Decay}\\\\ A=I(1 - r)^{\frac{t}{p}}\qquad \begin{cases} A=\textit{accumulated amount}\to &1013\\ I=\textit{initial amount}\\ r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\ t=\textit{meters climbed}\to &0\\ p=period\to &1000 \end{cases} \\\\\\ 1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I[/tex]

so, the inital amount is 1013, when t = 0,

[tex]\bf \textit{Periodic Exponential Decay}\\\\ A=I(1- r)^{\frac{t}{p}}\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\to &1013\\ r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\ t=\textit{meters climbed}\to &t\\ p=period\to &1000 \end{cases} \\\\\\ A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}[/tex]

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.

The total ages of 2 buildings is 201 years. if one building is twice as old as the other, what are the ages of 2 buildings?

Answers

Answer: 67 years and 134 years

In this case, you are given the buildings sum ages ( building A ages+ building B ages = 201 years) and the building ratio ( Building A ages= 2x Building B ages).
To answer the question, you simply need to insert the second equation into the first. It would be:

building A ages + building B ages= 201
2x building B ages + building B ages= 201
building B ages= 67 years.

Then building A ages= 2x 67 years= 134 years.

The ages of the two buildings are 67 and 134 years. This is found by setting up an algebraic equation where the sum of their ages is 201, and one is twice as old as the other.

Finding the Ages of Two Buildings

If the total ages of two buildings is 201 years and one building is twice as old as the other, then we can express the ages of the buildings using algebra. Let's denote the age of the younger building as y years. The older building is twice as old, so its age would be 2y years. The equation based on their total ages would be:

y + 2y = 201 years

Solving this equation:

Combine like terms: 3y = 201.

Divide both sides by 3 to isolate y: y = 201 / 3.

Calculate the exact value: y = 67 years.

So, the younger building is 67 years old, and the older building, being twice as old, is 134 years old.

The length of a shadow of a building is
29 m
. The distance from the top of the building to the tip of the shadow is
35 m
. Find the height of the building

Answers

h^2=x^2+y^2

35^2=29^2+y^2

y^2=35^2-29^2

y^2=384

y=√384

y≈19.60 m (to the nearest hundredth of a meter, or nearest centimeter)

what is the remainder when 3 is synthetically divided into the polynomial -x^2+5x-9

Answers

-3 is the remainder when you synthetically divide

Answer:

REmainder is -3

Step-by-step explanation:

find remainder when 3 is synthetically divided into the polynomial -x^2+5x-9

In synthetic division we write all the coefficient of the polynomial and divide by 3

3 -1 5 -9

0 -3 6

-------------------------------

-1 2 -3 ----> Remainder

So the remainder is -3

Out of 30 students surveyed 17 have a dog based on these results predict how many of the 300 students in the school have a dog

Answers

17/30 = 0.5666 so about 57% of the sample had dogs

300 x 0.57 = 171 would have dogs

What property describes the number sentence? 6+0=6

Answers

hello :
the property describes the number sentence 6+0=6 is : " 0 Neutral element for addtion"

an airline ramp with a base of 50 makes an angle of 27 with the ground. find the distance a person will walk on a ramp round to the nearest foot

Answers

check the picture below.

make sure your calculator is in Degree mode.

A wheelchair access ramp has an angle of elevation of 20°. If the ramp reaches to the top of a 33 inch high porch, how long is the ramp?

Answers

sinα=height/length

length=height/sinα, we are given that α=20° and h=33 in

length=33/sin20° in

length≈96.49 in (to nearest hundredth of an inch)

This is a sin operation, Sin is the relationship between the opposite (height) and the hypotenuse (length of ramp). Plugging in: Sin(20deg) = 33/x

Sin(20) = 33/x

x*Sin(20) = 33

x = 33/Sin(20)

x = 96.49in long.

*This answer is the length of the SLOPE of the ramp.

Ann is grouping 38 rocks. She can put them into groups of 10 rocks or as single rocks.what are different ways Ann can group the rocks?

Answers

Answer: 4 ways

To answer this question, you need to make a list based on how much "10 group" of rock can be made.
The possible way to group it should be:
0 pcs of 10 group + 38 pcs of 1 group
1 pcs of 10 group + 28 pcs of 1 group
2 pcs of 10 group + 18 pcs of 1 group
3 pcs of 10 group + 8 pcs of 1 group

The table below represents the distance of a train from its destination as a function of time: Time (hours) x Distance (miles) y 0 665 1 570 2 475 3 380 4 285 Part A: What is the y-intercept of the function, and what does this tell you about the train? (4 points) Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 4 hours, and tell what the average rate represents. (4 points) Part C: What would be the domain of the function if the train continued to travel at this rate until it reached its destination? (2 points)

Answers

A. y=-95x+665 y-intercept is 665
B. Ave rate of change is -95
C. y=0 so x=7 Domain is [0,7]

What is the greatest common factor of 4k, 18k4, and 12?

Answers

factor each
4k=2*2*k
18k⁴=2*3*3*k*k*k*k
12=2*2*3

GCF=2

the greatest common factor is 2

the great common factor is 2

which algebraic expression shows the average melting points of helium, hydrogen, and neon if h represents the melting point of helium, j represents the melting point of hydrogen, and k represents the melting point of neon?

A. h + j + k
B. hjk
c. h+j+k over 3
d. hjk over 3

Answers

Answer:

c. h+j+k over 3

Step-by-step explanation:

We know that,

[tex]\text{Average}=\frac{\text{Sum of observations}}{\text{Total number of observation}}[/tex]

Here, h, j and k represents the melting point of helium, hydrogen and Neon respectively,

Since, the sum of melting points = h + j + k,

Also, the total number of gases = 3,

Thus,

[tex]\text{Average melting points}=\frac{h+j+k}{3}[/tex]

Or (h+j+k) over 3

⇒ Option c is correct.

The algebraic expression which shows the average melting

points of helium, hydrogen, and neon is h+j+k over 3.

What is Average?

This is calculated with the sum of the items divided by the

number of items.

In this scenario, we were given the items as h, j and k. The

total number of items is 3.

The average will therefore be = h+j+k/3

Read more about Average here https://brainly.com/question/8728504

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