what is the reasonable estimate of the average kinetic energy of an athlete during a 100m race that takes 10s ?
The Kinetic energy of the athlete will be 50 times of the mass of the athlete.
We have a athlete who completed a 100m race in 10 seconds.
We to estimate the average kinetic energy of the athlete.
What is the formula to calculate the Kinetic energy of any moving body?The formula to calculate the kinetic energy of any moving body is -
K.E. = [tex]\frac{1}{2} mv^{2}[/tex]
According to question -
Distance covered by athlete = 100 meters
Time taken by the athlete = 10 seconds
Let's assume the mass of the athlete = M Kg
Consider the formula for the Kinetic energy of the body -
K.E. = [tex]\frac{1}{2} mv^{2}[/tex]
We know that -
v = [tex]\frac{distance}{time} = \frac{x}{t}[/tex]
Substituting the value of velocity in equation of kinetic energy -
K.E = [tex]\frac{1}{2} m(\frac{x}{t}) ^{2}[/tex]
We can see that the kinetic energy of the athlete is -
K.E. [tex]\alpha\; (\frac{x}{t})^{2}[/tex]
Greater the square of the ratio of x and t, greater will be the kinetic energy.
K.E. = 0.5 x M x 10 x 10
K.E. = 50M
Hence, the Kinetic energy of the athlete will be 50 times of the mass of the athlete.
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If you were asked to design the most efficient nuclear fission reactor possible, what ratio of U-235 to U-238 would you use? Explain why?
The most efficient nuclear fission reactor would require a higher ratio of U-235 to U-238 due to the higher fissionability of U-235.
Explanation:The most efficient nuclear fission reactor would require a higher ratio of U-235 to U-238.
U-235 is the fissile isotope of uranium and readily undergoes fission, producing a large amount of energy. U-238, on the other hand, is a fertile isotope that can be converted into plutonium-239, which is also highly fissionable. By increasing the ratio of U-235 to U-238, more U-235 will be available for fission reactions, leading to a higher energy output and efficiency.
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Stan does 178 J of work lifting himself 0.5 m. What is Stan’s mass? The acceleration of gravity is 9.8 m/s 2 . Answer in units of kg
Answer:
The mass is 36.33 kilograms.Explanation:
The work is defined as the force needed to move an object a certain distance, if there's no change of position, there's no work.
In this case, the work is defined:
[tex]W=Fd[/tex]
Where [tex]F[/tex] is the weight defined with the following equation
[tex]F=W=mg[/tex]
Now, we'll replace all given values and solve for [tex]m[/tex]:
[tex]W=mgy\\178=m(9.8)(0.5)\\m=\frac{178}{4.9}=36.33 kg[/tex]
Therefore, the mass is 36.33 kilograms.
If a ball is thrown into the air with a velocity of 42 ft/s, its height (in feet) after t seconds is given by y = 42t − 16t2. Find the velocity when t = 1.
The velocity of a ball at t = 1 second when it was thrown up with an initial velocity of 42 ft/s, we differentiate the height function to get the velocity function and substitute t = 1 to find the velocity to be 10 feet per second.
The velocity of a ball thrown straight up into the air at a specific time (t = 1 second), using the given position function y = 42t - 16t². To find the velocity at t = 1, we differentiate the position function with respect to time to get the velocity function v(t) = dy/dt. After differentiation, we get v(t) = 42 - 32t and then plug in t = 1 to find the velocity at that moment.
After substituting t into the velocity function, we get v(1) = 42 - 32(1) = 10 ft/s. Hence, the velocity of the ball at t = 1 second is 10 feet per second.
According to newton's first law of motion, which force is expected to cause a body to accelerate
Answer: The answer to this question is Unbalanced force.
Explanation: There are two types of forces:
1. Balanced force: When two forces equal in their magnitude act opposite to each other are known as balanced force. The net force is equal to 0.
2. Unbalanced force: When two forces acting opposite to each other are not equal in magnitude results in the unbalanced force. The net force of this is not equal to 0. Direction of force is in the direction of net force.
Now, according to Newton's first law of motion, which says that force is the product of the object's mass and acceleration. The force should have some value and hence it cannot be equal to zero. therefore the force must be Unbalanced force.
According to Newton's second law of motion, a net external force causes a body to accelerate, with the acceleration being directly proportional to the force and inversely proportional to its mass.
According to Newton's second law of motion, a force is expected to cause a body to accelerate when it acts upon the body. This law can be summarized by the equation Fnet = ma, where Fnet denotes the net force acting on the body, m stands for mass, and a signifies acceleration. Therefore, the linear acceleration of a rigid body is directly proportional to the net force acting on it and inversely proportional to its mass. It is important to note that the acceleration occurs in the same direction as the net external force. In simple terms, if you apply a net external force to an object, it will accelerate, and the magnitude of this acceleration can be calculated by dividing the net force by the object’s mass.
Why is it important for scientist to repeat an experiment several times?
A mover uses a ramp to push a stereo into the moving van. The ramp is 3 meters long and 1.5 meters high. What is the ima of this ramp?
The Ideal Mechanical Advantage (IMA) of the ramp used to move the stereo is 2. This is calculated by dividing the length of the ramp (3 meters) by its height (1.5 meters).
Explanation:The question is asking for the Ideal Mechanical Advantage (IMA) of the ramp, also known as an inclined plane, used in moving the stereo. The IMA for an inclined plane, or ramp, can be calculated using the formula IMA = length of slope / height of slope. In this scenario, the length of the ramp is 3 meters and the height is 1.5 meters. Plugging these values into the formula, the IMA is calculated as 3 / 1.5 = 2. This means that the ramp multiplies the force applied to the stereo by two, making the task of loading the stereo easier.
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Which stage comes first in the life cycle of a high-mass star?
A. red giant
B. white dwarf
C. protostar
D. supernova
...?
Answer:
C. protostar
Explanation:
Due to the effect of gravity the hydrogen atoms are pulled together from the nebula. At this stage the star is not hot enough to start the nuclear fission. At this stage a star is called protostar. Eventually it will grow in size by attracting more hydrogen. When the temperature at the core is increased enough due to the gravitational pressure at the core of the star, then nuclear fission will start
When an object that has been thrown into the air reaches its maximum height, which is true?
a. its velocity is zero. b. it is at its terminal velocity. c. it is not in free fall. d. its acceleration is zero.
Answer:
a. its velocity is zero.
Explanation:
At maximum height no activities is going on that is the velocity becomes zero because no movement occurs at that point
Since there is no moveent the velocity is zero.
At an object's maximum height in projectile motion, its velocity is zero but its acceleration due to gravity remains constant. Therefore, the correct statement is option a).
Here is the detailed reasoning:
An object thrown upwards will decelerate due to gravity until its velocity becomes zero at the maximum height. This is the point where its upward motion stops, and it is about to start descending.
The velocity magnitude at maximum height is zero, but its acceleration is still the acceleration due to gravity (g), acting downwards. Therefore, option d. its acceleration is zero, is incorrect.
Terminal velocity refers to the constant speed that a free-falling object eventually reaches, which is not relevant here. So, option b is incorrect.
Even at its maximum height, an object is still under the influence of gravity, meaning it is in free fall, which makes option c incorrect.
Therefore, the correct answer is a. its velocity is zero.
The waves with the longest wavelengths in the electromagnetic spectrum are
a. infrared rays.
b. x-rays.
c. gamma rays.
d. radio waves.
A mechanical device requires 420 J of work to do 230 J of work to lift a crate. What is the efficiency of the device? In percentage please.
The efficiency of the machine is 54.76%.
The efficiency of a machine refers to the amount of useful work that is done by the machine. Efficiency is usually expressed as a percentage.
From the question;
Work output= 230 J
Work input= 420 J
We know that efficiency = Work output/work input × 100/1
efficiency =230 J/420 J × 100/1
efficiency = 54.76%
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What is g at a point in the earth's gravitational field where a 10 kg mass weighs 95 n?
If a car is traveling 40 mph, how far will it go in 5 hours?
a. 100 miles
b. 200 miles
c. 80 miles
d. 800 miles
a person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done? a person expended 500 newtons to move a full wheelbarrow 30 meters how much work was done?
Final answer:
The work done by a person who exerted a force of 500 Newtons to move a full wheelbarrow over a distance of 30 meters is 15000 Joules.
Explanation:
If a person exerted a force of 500 Newtons (F = 500 N) to move a full wheelbarrow over a distance of 30 meters (d = 30 m), the work done can be calculated using the formula:
Work (W) = Force (F) × Distance (d)
Plugging in the given values, we get:
W = (500 N) × (30 m) = 15000 Joules (J)
The work done is therefore 15000 Joules, which demonstrates the transfer of energy through force applied over a distance.
The figure shows the speed of a person's body as he does a chin-up. Assume the motion is vertical and the mass of the person's body is 64.0 kg. determine the force exerted by the chin-up bar on his body at t = 0s; t = 0.5s; t = 1.1s; and t = 1.6s
The force exerted by the chin-up bar on the person's body depends on the acceleration. At certain times, the force is 0 N, while at other times it can be calculated using the formula Force = Mass x Acceleration.
Explanation:The force exerted by the chin-up bar on the person's body can be calculated using the equation:
Force = Mass x Acceleration
At t = 0s, the person's body is at rest, so the acceleration is 0. Therefore, the force exerted by the bar is 0 N.
At t = 0.5s, the person's body is moving upward with a constant speed. Since the velocity is constant, the acceleration is 0 and the force exerted by the bar is 0 N.
At t = 1.1s, the person's body is moving upward with an increasing speed. The acceleration can be calculated using the change in velocity over time, and then substituted into the force equation to find the force exerted by the bar.
At t = 1.6s, the person's body is moving upward with a decreasing speed. The acceleration can be calculated using the change in velocity over time, and then substituted into the force equation to find the force exerted by the bar.
how to select a direction for the EMF included In a moving conductor?
Fleming's right-hand rule (for generators) shows the direction of induced current when a conductor moves in a magnetic field. It can be used to determine the direction of current in a generator's windings.
When a conductor such as a wire attached to a circuit moves through a magnetic field, an electric current is induced in the wire due to Faraday's law of induction. The current in the wire can have two possible directions. Fleming's right-hand rule gives which direction the current flows
The right hand is held with the thumb, first finger and second finger mutually perpendicular to each other (at right angles.
The thumb is pointed in the direction of motion of the conductor.A car heading north collides at an intersection with a truck of the same mass as the car heading east. If they lock together and travel at 28 m/s at 37° north of east just after the collision, how fast was the car initially traveling? Assume that any other unbalanced forces are negligible.
what is the correct answer
34 m/s
17 m/s
26 m/s
68 m/s
...?
The car was initially traveling at approximately 22.02 m/s.
Explanation:To solve this problem, we can break it down into horizontal and vertical components. Let's call the initial velocity of the car 'v.'
The car's horizontal velocity after the collision is given by its initial velocity multiplied by the cosine of the angle, which is 28 m/s * cos(37°). The truck's horizontal velocity after the collision is 0 m/s since it was initially stationary.
Since no horizontal forces act on the system after the collision, the momentum in the horizontal direction is conserved. Thus, the sum of the initial flat rates of the car and the truck must equal the final horizontal velocity. Therefore, m * v = m * (28 m/s * cos(37°)), where 'm' represents the mass of the car and the truck.
If we divide both sides of the equation by 'm', we get v = 28 m/s * cos(37°). Evaluating this expression, we find v ≈ 22.02 m/s.
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Is it professional a cyber crime
An unbalanced 16-n force is applied to a 2 kg mass what is the acceleration of the mass
Why do magnetic lines of forces make a closed loop?
If you drop a tennis ball from the top of a ladder, at what rate will it accelerate
a uniform rope of length l is pulled by a constant force F.what is the tension in the rope at a distance l from the end, where it is applied?
...?
A student librarian lifts a 2.2 kg book from the floor to a height of 1.25 m. He carries the book 8.0 m to the stacks and places the book on a shelf that is.35 m above the floor. How much work does he do on the book?
I understand most of it, but I am unsure of what distance to use. Please help? ...?
Answer:
[tex]W_{tot}=W_{1}+W_{2}=mgh_{2}=7.55[J][/tex]
Explanation:
The work done on an object is the scalar product between force and displacement. So we can write the work:
[tex]W=F\cdot d=Fd[/tex]
In our case F and d are parallels then we have a common product of their magnitudes.
Now, the total work will be the sum these two works:
Work done when the student librarian lifts a 2.2 kg book from the floor to a height of h₁=1.25 m.Work done when he places the book on a shelf that is h₂=0.35 m above the floor.Let's recall that the force in this problem is just the weight of the book. F=m*g
The first work will be: [tex]W_{1}=mgh_{1}[/tex]. F and h1 are parallelsThe second work will be:[tex]W_{2}=-mg(h_{1}-h_{2})[/tex] is negative because the vector force and the vector displacement are anti parallels.Finally, the total work will be the sum of W₁ and W₂.
[tex]W_{tot}=W_{1}+W_{2}=mgh_{2}=2.2*9.81*0.35=7.55[J][/tex]
I hope it helps you!
To calculate the work done on the book, the student librarian must use the formula W = mgh for each segment of lifting the book vertically. The total work done is the sum of the work for lifting the book to 1.25 m and then to 0.35 m. The horizontal distance carried does not contribute to work against gravity.
Explanation:The work done on the book by the student librarian can be calculated by considering the work done against gravity to lift the book to different heights. The distance carried horizontally does not involve work against gravity under the assumption that there is no horizontal force like friction opposing the motion. The work done to lift the book from the floor to 1.25 m can be calculated using the formula W = mgh, where m is the mass of the book, g is the acceleration due to gravity (approximately 9.8 m/s2), and h is the height.
The initial lift is W = 2.2 kg × 9.8 m/s2 × 1.25 m. When placing the book from the carried position to a shelf at 0.35 m height, the work done is W = 2.2 kg × 9.8 m/s2 × 0.35 m since the vertical displacement is from 1.25 m to 0.35 m, not the full 1.25 m again.
The total work done on the book is the sum of these two amounts of work. Please note that the gravitational constant (g) could be given or assumed in this context. The exact value used may vary slightly depending on the context of the problem.
Which of the following frictionless ramps (A, B, or C) will give the ball the greatest speed at the bottom of the ramp? Explain.
The frictionless ramp A will give the ball the greatest speed at the bottom of the ramp.
What is speed?Speed is defined as the rate of change of the distance or the height attained. it is a time-based quantity. it is denoted by u for the initial speed while u for the final speed. its si unit is m/sec.
The potential energy is due to the virtue of the position and the height. The unit for the potential energy is the joule. Ball has the most potential energy due to her position at C.
The potential energy is mainly dependent upon the height of the object.
Potential energy = mgh
The potential energy gets converted into kinetic energy at the bottom. If the ramp is frictionless the potential energy completely gets converted into kinetic energy.
The kinetic energy results in the motion of the body.
Hence frictionless ramp A will give the ball the greatest speed at the bottom of the ramp.
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How much power does a toaster have if it does 21,000 joules of work in 30 seconds?
The power of the toaster, calculated using the formula P = W/t, is 700 Watts.
Explanation:The power of an appliance like a toaster can be calculated using the formula for power which is P = W/t, where P is Power, W is work done or energy consumed, and t is time.
Given that the toaster does 21,000 Joules of work or consumes 21,000 joules of energy in 30 seconds, the power would thus be calculated as follows: P= 21,000J / 30 s. This equals 700 Watts. So, the toaster has a power of 700 Watts.
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You have done 3,404 J of work with a force of 37 N on a 46-kg object. Over what distance did you do the work?
A. 92 m
B. 150 m
C. 3131 m
D. 1702 m
^_^ ...?
Newton's third law with magnetic forces?
Now while I was studying more about this matter, as I asked before when two bar magnets attract do they both their forces on each other? The answer was "YES." Now, let me go indepth with this more and more, when two bar magnets of un-equal forces attract! Do they equally apply the same force or no?
Imagine Magnet A capable of applying 50N of force while magnet B is applying 10N of force, they both attract! I think the two forces add up! What do you all think?
A window washer stands on a scaffolding 30 meters above the ground. If he did 23,520 joules of work to reach the scaffolding what is his mass
The mass of the window washer who stands on a scaffolding 30 meters above the ground is 78.4 Kg.
What is Potential Energy?Energy of the body due to its position with respect to some other object (say earth) is called potential energy.
Given is a a window washer who stands on a scaffolding 30 meters above the ground.
The amount of work done by the window washer will be stored inside him in the form of potential energy. Therefore, we can write -
mgh = 23520
m x 10 x 30 = 23520
m = 23520/300
m = 78.4 Kg
Therefore, the mass of the window washer who stands on a scaffolding 30 meters above the ground is 78.4 Kg.
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Please help.: Sliding from left to right in a straight line on a horizontal steel surface, an aluminum block weighing 20 newtons is acted on by a 2.4 newton friction force. The block will be brought to rest by the friction force in a distance of 10 meters. Determine the magnitude of the acceleration of the block as it is brought to rest by the friction force. (Show all work)
Answer:
-1.176 m/s²
Explanation:
Given:
weight of aluminium block is w = 20.0 N
frictional force, f = 2.4 N
final velocity, v = 0
distance covered, d = 10 m
From Newton's second equation of motion,
F = ma
where, m is the mass and a is the acceleration.
mass of the block, m g = 20.0 N
m = 2.04 kg
The block is brought to rest by friction force:
f =- m a
⇒ 2.4 N = -(2.04 kg)(a)
⇒a = -1.176 m/s²
Which of these most likely causes an annular solar eclipse?
A.moon moving closer to Earth than sun and forming a triangle
B.Earth moving closer to sun than moon and forming a triangle
C.the moon at apogee coming between Earth and the sun along a straight line
D.the moon at perigee coming between Earth and the sun along a straight line
Answer:
C.the moon at apogee coming between Earth and the sun along a straight line
Explanation:
As we know that Earth rotate about the sun in elliptical orbit as one of the planet.
While moon rotate about the Earth similarly as one of the satellite around it
now when moon, Sun and Earth all lie in the same line such that position of moon is between the positions of Sun and Earth then in this case the light coming from sun is totally bounded by the position of moon
This situation of moon is known as Solar Eclipse
so here during the motion if the moon at apogee coming between Earth and the sun along a straight line then it is the most likely cause of annular solar eclipse.