The standard used by LEED in the Water Efficiency (WE) category to determine the baseline case for building water usage is the national standard for maximum flush and flow rates called:

Answer:

The acceleration of the box is 2.

Explanation:

According to Newton's second law of motion, the acceleration of any object will be directly proportional to the net unbalanced force acting on the object and inversely proportional to the mass of the object.

Net force = Mass × Acceleration

So [tex]Acceleration = \frac{Net force}{Mass}[/tex]

Since in this case, the box is experiencing a force from east of magnitude 27 N and resisting force of about 17 N from west. So the net force will be the difference of acting and reacting force.

Net force = 27-17 = 10 N.

Thus, [tex]Acceleration = \frac{10 N}{5 kg}[/tex]

So 2 [tex]m/s^{2}[/tex] is the acceleration of the box. Thus the magnitude of acceleration of the box is 2.

Answer:

They will become aligned according to the charges on the metal plate.

Explanation:

When Polar molecules are placed between oppositely charged metal plates the molecules will tend to be attracted by their corresponding oppositely charged plates that is the positive and negative plates,

A polar molecule is one which has opposite charges on its ends. Non-polar molecules however do not have charges on their end

When polar molecules are placed between oppositely charged metal plates, the poles orient towards the oppositely charged plate.

These are the molecules that have positive and negative in opposite poles. For example- water molecules.

Therefore, when polar molecules are placed between oppositely charged metal plates, the poles orient towards the oppositely charged plate.

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Answer:

force between masses will be same as  [tex]3.24\times 10^{-7}N[/tex]

Explanation:

Let the masses are [tex]m_A\ and\ m_B[/tex] and distance between them is r

According to gravitational law force between two mass is given by

[tex]F=\frac{Gm_Am_B}{r^2}[/tex]

So [tex]3.24\times 10^{-7}=\frac{Gm_Am_B}{r^2}[/tex]

Now mass of both are doubled and distance between them is tripled

And now we have to find that from what factor the force between masses are changed

So [tex]F_{new}=\frac{G3m_A3m_B}{(3r)^2}=\frac{9Gm_Am_B}{9r^2}=\frac{Gm_Am_B}{r^2}=F[/tex]

So force between masses will be same as  [tex]3.24\times 10^{-7}N[/tex] as masses and distance between them both has the same effect

Answer:

The Commemorative head of a king (Oba)

Explanation:

The commemorative head of a king is similar to the other features mentioned in the question due to their royal statuses. These features are idolized by the people in their respective societies. The 'Oba' for example is respected by the people of Benin and he makes the rules and regulations for the people. When he dies, his eldest son usually takes his position.

Answer:

The Commemorative head of a king (Oba)

Explanation:

I took the test B )

Hi you didn't provide any images to solve the question, hence I am going to solve a different question of same concept so you can have an idea how to tackle such types of questions.(please refer to the attachment for question)

Answer:

Please refer to the attachment for answers and explanation

Explanation:

Please refer to the attachment for answers and explanation

To determine the resultant internal loadings at the cross sections, we need to consider the external and internal forces. Trigonometric principles can be used to calculate the magnitudes and directions of the loadings. More information about the frame is needed for a precise analysis.

In order to determine the resultant internal loadings acting at the cross sections at points F and G of the frame, we need to consider the external forces applied to the frame, as well as the internal forces generated within the frame due to those external forces. These internal forces include axial forces, shear forces, and bending moments.

Given that θ = 27º and t = 178 lb, we can use trigonometric principles to determine the magnitudes and directions of the internal loadings at points F and G.

For a more specific and accurate analysis, it would be helpful to have more information about the frame, such as its shape, structural elements, and boundary conditions. Without that information, it is not possible to provide a more detailed answer at this time.

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Answer:

1. This is to allow the tube of the tire to position itself properly inside the tire.

2. Inflating,deflating and reinflating aircraft tires help to eliminate all the air between the tube and the inside of the tire.

3. It helps to test the entire tube and tire assembly for any leaks.

Explanation:

Answer:

0.5A

Explanation:

GIVEN THAT:

V = 3 V

R =6 ohms

V=IR

I =V/R

I = 3/6 =0.5 A

Answer:

Yes, it will produce a diffraction pattern.

a. 3.9 mm b. 1.95 mm

Explanation:

The light shined from a single slit will produce a diffraction pattern because,  the wavefront act as wavelets which generates its own wave according to Huygens principle. This therefore causes the diffraction pattern.

Given

wavelength of green light, λ = 520 nm = 520 × 10⁻⁹ m = 5.20 × 10⁻⁷ m

width of slit, d = 0.440 mm = 0.44 × 10⁻³ m = 4.4 × 10⁻⁴ m

Distance of slit from central maximum , D = 1.65 m

Distance of first minimum from central maximum, y = ?

a. The relationship between the slit width and wavelength is given by [tex} dsinθ = mλ [/tex]where d = slit width, θ = angular distance from central maximum, λ = wavelength of light and m = ±1, ±2, ±3...

The relationship between y and D is given by [tex] tanθ = y/D [/tex]

Since θ is small, sinθ ≈ θ ≈ tanθ

so, dθ = mλ ⇒ θ = mλ/d = y/D

Therefore, y = mλD/d

Now, for the first minimum above the slit, m = +1 and for the first minimum below the slit, m = -1. So, y₁ =  λD/d and y₋₁ =  -λD/d. So, the width of the central maximum Δy is the difference between the first minima below and above the central maximum. So, Δy = y₁ - y₋₁ = λD/d -(-λD/d) = 2λD/d

Substituting the values from above, Δy= 2 × 5.20 × 10⁻⁷ × 1.65/4.4 × 10⁻⁴ =  3900 × 10⁻⁶ m = 3.9 × 10⁻³ m = 3.9 mm

b. The first order fringe is the fringe located between the first minimum and the second minimum. From dsinθ = mλ and tanθ = y/D when θ is small, sinθ ≈ θ ≈ tanθ. So, y = mλD/d. Let m= 1 and m=2 be the first and second minima respectively. So,y₁ =  λD/d and y₂ =  2λD/d. The difference Δy₁ = y₂ - y₁ is the width of the first order fringe. Therefore, Δy₁ = 2λD/d - λD/d= λD/d. Substituting the values from above, we have

λD/d= 5.20 × 10⁻⁷ × 1.65/4.4 × 10⁻⁴= 1.95 × 10⁻³ m = 1.95 mm

Answer:

True

Explanation:

It can cause flooding and destruction of habitat because of dammed rivers create large reservoirs upstream which can spill out to the surrounding during heavy rainfall causing flooding and destruction of natural habitat.

Answer: Electrons

Explanation: For a neutral atom the number of positively charged protons inside the nucleus must be equal to the number of electrons in the orbital shells. Both charges will cancel out having a charge of 0 which makes an atom electrically neutral.

Answer:

i believe it would be classified as A shopping

Answer:

There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

Explanation:

For this exercise we will propose its solution from Newton's third law, which states that every action has a reaction of equal magnitude, but felt different.

As it is in space, we must assume that it is not subject to the gravitational attraction of nearby bodies, except the asteroid that attracts it. When he extends his hand and hits the asteroid, he exerts a force on him, by Newton's third law he responds with a force of equal magnitude applied to the astronaut, therefore without the two they are not united they could separate if this force is greater than the force of universal attraction between the two.

In summary There is a force that has the same magnitude as that of the hammer applied on the astronaut and with direction away from the asteroid, movement is given by

                F_hammer - F_Gravitation = m a

Answer:

The height of the water slide is 0.878 m

Explanation:

Given that,

Distance = 2.52 m

Suppose Children slide down a friction less water slide that ends at a height of 1.80 m above the pool.

We need to calculate the time

Using equation of motion

[tex]s=ut+\dfrac{1}{2}gt^2[/tex]

Put the value in the equation

[tex]1.80=0+\dfrac{1}{2}\times9.8\times t^2[/tex]

[tex]t^2=\dfrac{1.80\times2}{9.8}[/tex]

[tex]t=\sqrt{\dfrac{1.80\times2}{9.8}}[/tex]

[tex]t=0.606\ sec[/tex]

We need to calculate the velocity

Using formula of velocity

[tex]v = \dfrac{d}{t}[/tex]

Put the value into the formula

[tex]v=\dfrac{2.52}{0.606}[/tex]

[tex]v=4.15\ m/s[/tex]

We need to calculate height

Using conservation of energy

[tex]\dfrac{1}{2}mv^2=mgh[/tex]

[tex]h=\dfrac{v^2}{2g}[/tex]

Put the value into the formula

[tex]h=\dfrac{4.15^2}{2\times9.8}[/tex]

[tex]h=0.878\ m[/tex]

Hence, The height of the water slide is 0.878 m.

Answer:

Velocity is zero.

Explanation:

Given:

We know that acceleration is defined as the rate of change in velocity and hence we integrate the expression of acceleration.

Now the velocity can be given as:

[tex]v=\int\limits {a} .\, dt=-k.\frac{t^3}{3}[/tex]

Put t = 0 we get:

[tex]v=0\ m.s^{-1}[/tex]

Answer:

0.056 miles away

Explanation:

From sound wave,

v = 2x/t .................................. Equation 1

Where v = velocity of sound in air, x = distance of echo, t = time.

making x the subject of the equation,

x = 2v/t........................... Equation 2.

Given: v = 344 m/s, t = 7.6 s.

Substituting into equation 2

x = 2(344)/7.6

x = 90.53 m.

x = 90.53/1609.344

x = 0.056 mile.

Thus the lighting strike 0.056 miles away

To find the line charge density (λ) on a long wire, the formula E = λ/ (2πε0r) can be used. The known values are plugged into the formula and solved to give λ = 1.31 x 10^-8 C/m.

To calculate the line charge density (λ) on a long wire, we use the formula that relates electric field and line charge density: E = λ/(2πε0r), where E is the magnitude of electric field, λ is the line charge density, ε0 is the permittivity of free space, and r is the distance from the wire.

In this given scenario, the magnitude of the electric field (E) is 260 kN/C (or 260,000 N/C). The distance from the wire (r) is 45 cm (or 0.45 m). The permittivity of free space (ε0) is a constant value of approximately 8.85 x 10^-12 C²/Nm².

By substituting these known values into the formula, we solve for λ: λ = E* (2πε0r) = 260,000 N/C * 2π * 8.85 x 10^-12 C²/Nm² * 0.45 m = 1.31 x 10^-8 C/m.

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At a speed of 58.8mi/hr must he drive for the remainder of the trip to complete the trip in the usual amount of time.

The change of displacement with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The time it takes to go 120 miles at that speed in normal conditions is;

[tex]\rm t = \frac{d}{v} \\\\ t =\frac{120}{55} \\\\ t= 2 hour \ 11 minute[/tex]

However, the driver was 30 minutes behind schedule at this distance, so the time the has to spend is;

T== 2hr 11 min +30 min

T= 2hr 41 mins

He has to fulfill the initial planned moment of 10 hours. The time to cover the remaining distance;

T'=(10-2.41)

T' = 7hr19mins

The remaining distance will be ;

S={550-120}

S=430mile.

The speed is to be maintained the following distance on the time;

[tex]\rm V'=\frac{430}{(\frac{439}{60} )} \\\\V'=58.7699 \ miles / hour[/tex]

The speed must he drive for the remainder of the trip to complete the trip in the usual amount of time will be 58.5 mile/hr.

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To complete his remaining 430 miles in 8 hours, the truck driver needs to drive at a speed of 53.750 mph for the rest of the trip.

The driver has covered 120 miles during which he used up 30.0 minutes more than what he would usually take.

We can calculate the remaining distance he needs to cover which is 550 total miles minus the 120 miles he's already driven, which equals to 430 miles.

The remaining time he has is the total normal trip time of 10.0 hours minus the 2.0 hours he's already spent (previous 1.5 hours plus the extra 0.5 hours), which equals 8 hours.

To cover the remaining 430 miles in the 8 hours left, he must drive at a speed of 430 miles divided by 8 hours, which equals to 53.750 mph.

This is the speed the driver needs to maintain for the remainder of the trip to complete it in the usual amount of time.

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Answer: The person will still have a mass of 90kg on Mars

Explanation: The Truth is, the mass of a body remains constant from place to place. It is the weight which is equal to {mass of body * acceleration due to gravity{g}} that varies from place to place since it is dependent on {g}.

In this case the person will have a Weight of 90*9.8 = 882N on Earth.

{ "g" on Earth is 9.8m/s²}

And a Weight of 90*3.3 = 297N on Mars.

{ From the question "g" on Mars is {9.8m/s²}/3 which is 3.3m/s²}

From this analysis you notice that the WEIGHT of the person Varies but the MASS remained Constant at 90kg.

Answer:

Change, increase in note frequency of the sound that comes as a result of the reduction in the vibrating length (wavelength) when the string movement is slightly restricted at its midpoint

Explanation:

When the midpoint of a vibrating guitar string is lightly touched it reduces the wavelength of the guitar string sound, halving it and such increases the the frequency inversely by a factor of 2

The relationship

f = vw/λ, for sound wave where vw is the speed of sound, frequency, f and λ is the wavelength

Frequency varies inversely with wavelength

An Octave

is the frequency vibration of sound-wave twice that of its lower note

Answer

given,

Electric field,E = 490 N/C

time, t = 54 ns

for electron

Mass of electron me = 9.1 x 10⁻³¹ kg

Charge of electron e = -1.6 x 10⁻¹⁹  C

electrostatic force

F = E q

F = 490 x 1.6 x 10⁻¹⁹

F = 784  x 10⁻¹⁹ N

now, using newton second law

[tex]a = \dfrac{784\times 10^{-19}}{9.1\times 10^{-31}}[/tex]

  a = 8.62 x 10¹² m/s²

using equation of motion

v = u + a t

v = 0 + 8.62 x 10¹² x 54 x 10⁻⁹

v = 4.65 x 10⁵ m/s

velocity of electron is equal to v = 4.65 x 10⁵ m/s

For Proton  

Mass mp = 1.67 x 10⁻²⁷ kg  

Charge p = 1.6 x 10⁻¹⁹ C

Electric field E = 490 V/C

from above solution

F = 784  x 10⁻¹⁹ N

now, acceleration

[tex]a = \dfrac{784\times 10^{-19}}{1.67\times 10^{-27}}[/tex]

  a = 4.69 x 10¹⁰ m/s²

using equation of motion

v = u + a t

v = 0 + 4.69 x 10¹⁰ x 54 x 10⁻⁹

v = 4.65 x 10³ m/s

velocity of electron is equal to v = 4.65 x 10³ m/s

Answer:

Explanation:

Electric field, E = 490 N/C

mass of electron, me = 9.1 x 10^-31 kg

mass of proton, mp = 1.67 x 10^-27 kg

charge of electron or proton = 1.6 x 10^-19 C

time, t = 54 ns = 54 x 10^-9 s

initial velocity, u = 0 m/s

Force on each particle, F = q E = 1.6 x 10^-19 x 490 = 7.84 x 10^-17 N

acceleration of electron = Force / mass of electron

ae = (7.84 x 10^-17) / ( 9.1 x 10^-31) = 8.6 x 10^13 m/s²

Let the velocity of electron is ve.

use first equation of motion

ve = u + ae x t

ve = 0 + 8.6 x 10^13 x 54 x 10^-9

ve = 4.65 x 10^6 m/s

acceleration of proton = Force / mass of proton

ap = (7.84 x 10^-17) / ( 1.67 x 10^-27) = 4.69 x 10^10 m/s²

Let the velocity of electron is vp.

use first equation of motion

vp = u + ap x t

vp = 0 + 4.69 x 10^10 x 54 x 10^-9

ve = 2535.1 m/s

Answer:

(a) 2.88×10⁻² W/m²

(b) 8.36×10⁻³ W/m²

Explanation:

The intensity of sound from an isotropic point source, with distance L is given as

I = P/(4πL²) .................................... Equation 1

Where I = intensity of sound, P = Power from the source, L = length, π = pie.

(a)

1.4 m from the source.

I = P/(4πL²)

Given: P = 0.71 W, L = 1.4 m, π = 3.14.

Substitute into equation 1

I = 0.71/(4×3.14×1.4²)

I = 0.71/24.6176

I = 0.0288 W/m².

I = 2.88×10⁻² W/m²

(b) 2.6 m from the source.

Given: P = 0.71 W, L = 2.6 m, π = 3.14

Substitute into equation 1

I = 0.71/(4×3.14×2.6²)

I = 0.71/84.9056

I = 0.00836 W/m²

I = 8.36×10⁻³ W/m²

Answer:

[tex]1.06085\times 10^{-10}\ m[/tex]

Explanation:

h = Planck's constant = [tex]6.626\times 10^{-34}\ m^2kg/s[/tex]

m = Mass of electron = [tex]9.11\times 10^{-31}\ kg[/tex]

k = Coulomb constant = [tex]8.99\times 10^{9}\ Nm^2/C^2[/tex]

e = Charge of electron = [tex]1.6\times 10^{-19}\ C[/tex]

n = 1 (ground state)

Angular momentum is given by

[tex]L=mvr[/tex]

From Bohr's atomic model we have

[tex]L=\dfrac{nh}{2\pi}[/tex]

[tex]mvr=\dfrac{nh}{2\pi}\\\Rightarrow v=\dfrac{nh}{2\pi mr}[/tex]

The centripetal force will balance the electrostatic force

[tex]\dfrac{ke^2}{r^2}=\dfrac{mv^2}{r}\\\Rightarrow \dfrac{ke^2}{r}=mv^2\\\Rightarrow \dfrac{ke^2}{r}=m(\dfrac{nh}{2\pi mr})^2\\\Rightarrow r=\dfrac{n^2h^2}{4\pi^2mke^2}\\\Rightarrow r=\dfrac{1^2\times (6.626\times 10^{-34})^2}{4\pi^2 \times 9.11\times 10^{-31}\times 8.99\times 10^{9}\times (1.6\times 10^{-19})^2}\\\Rightarrow r=5.30426\times 10^{-11}\ m[/tex]

The diameter is [tex]2\times 5.30426\times 10^{-11}=1.06085\times 10^{-10}\ m[/tex]

Answer: 1/2

Explanation:

The total energy consumption in the United States of America has been estimated to be about 101.3quadrillion Btu( British thermal unit). The United States of America uses a mix energy source for energy Production which includes PRIMARY, SECONDARY, RENEWABLE,FOSSIL FUELS.

Five basic energy consumption sectors have been categorized in the United States,which includes ELECTRIC POWER, INDUSTRIAL, COMMERCIAL, RESIDENTIAL AND TRANSPORTATION. Of the estimated 101.3(quads) about 1/2 of 101.3(quads) are used for the production and manufacturing of materials by the manufacturing industry.

Answer:

The value of the angle theta = 135degree, which is option c.

Explanation :

These are the options given in the question

a) 45 degrees

b)120 degrees

c)135 degrees

d)150 degrees

e) it is impossible to deliver a negative power.

The concept of work done on an object is applied here.

work = Fd

F = ma

work = mad

Work is a form of energy transferred by an object after the application of a force that act on the object. A step by step explanation is as attached below.

Answer:

[tex]m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )[/tex]

Explanation:

Then the mass of the material required to make such a sphere would be calculated as:

Total volume of the spherical shell:

[tex]V_t=\frac{4}{3} \pi.r_2^3[/tex]

And the volume of the hollow space in the sphere:

[tex]V_h=\frac{4}{3} \pi.r_1^3[/tex]

Therefore the net volume of material required to make the sphere:

[tex]V=V_t-V_h[/tex]

[tex]V=\frac{4}{3} \pi(r_2^3-r_1^3)[/tex]

Then the mass of the material used is:

[tex]m=\rho.V[/tex]

[tex]m=\rho\times \frac{4}{3} \times \pi \times(r_2^3-r_1^3 )[/tex]

Answer:

[tex]f=571.67\ Hz[/tex]

Explanation:

Given:

Therefore we have the wavelength of the wave as the distance between the two consecutive maxima:

[tex]\lambda=1.2-0.6[/tex]

[tex]\lambda=0.6\ m[/tex]

We have the speed of sound in the air as:

[tex]v=343\ m.s^{-1}[/tex]

Therefore the frequency of sound:

[tex]f=\frac{v}{\lambda}[/tex]

[tex]f=\frac{343}{0.6}[/tex]

[tex]f=571.67\ Hz[/tex]

The frequency of the sound from the speaker is 571.67 Hz.

Given that the phase constant of speakers is the same, the position of one speaker is at origin, the position of another speaker from the origin is 10 m.

The position of maxima interference is at 0.6 m and 1.2 m. Hence the wavelength of the wave is equivalent to the difference between the two consecutive maxima interference.

[tex]\lambda = 1.2 - 0.6[/tex]

[tex]\lambda = 0.6 \;\rm m[/tex]

We know that the speed v of the sound in the air is 343 m/s. Hence the frequency of the sound is calculated as given below.

[tex]f = \dfrac {v}{\lambda}[/tex]

[tex]f = \dfrac { 343}{0.6}[/tex]

[tex]f = 571.67\;\rm Hz[/tex]

Hence we can conclude that the frequency of the sound from the speaker is 571.67 Hz.

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Answer:

b. It deflects the electron to the right.

Explanation:

Since the sphere is positively charged and electron has negative charge, it will be attracted toward the sphere and hence,

The electron is deflected to the right as the positively charged sphere on its right

So, the 2nd option is correct.

Answer:

The work done by the force is 109.5 Joules.

Explanation:

It is given that,

Mass of the object, m = 3 kg                                

Speed of the object, v = 5 m/s

Force applied on the object, F = 12 N

Distance covered by the object, d = 6 m

The work done by this force is given by the sum of kinetic energy and potential energy as per work energy theorem as :

[tex]W=K+P[/tex]

[tex]W= \dfrac{1}{2}mv^2+Fd[/tex]

[tex]W=\dfrac{1}{2}\times 3\times (5)^2+12\times 6[/tex]

W = 109.5 Joules

So, the work done by the force is 109.5 Joules. Hence, this is the required solution.

Explanation:

This difference is because of the difference in arrangement of carbon atoms both graphite and Diamond.

Carbon atoms in graphite are arranged in layered form in an infinite array of layers. These layers are held together by a weaker force of attraction called vander waal's force of attraction such that layer's can slip over one another. Whereas in diamond carbon atoms are arranged tetrahedrally. Each carbon atom is attached to four carbon atoms with a bond angle of 109.5°. It is strong rigid three dimensional structure that results in infinite array atoms. This accounts for hardness of the diamond.

Final answer:

Diamond and graphite exhibit vastly different physical properties due to their respective carbon atom structures: diamond's strong three-dimensional covalent bonds make it extremely hard, while graphite's layered structure with weak interlayer forces makes it soft and slippery.

Explanation:

Diamond and graphite are two forms of the same element, carbon, but they have vastly different physical properties due to the way their atoms are bonded together. In diamond, each carbon atom is tetrahedrally bonded to four other carbon atoms in a strong three-dimensional network, which is what makes diamonds so hard and durable. This covalent bonding extends throughout the crystal, making it an excellent insulator but very hard to break.

Conversely, graphite is composed of layers of carbon atoms bonded in a hexagonal pattern, with weaker interlayer attractions known as London dispersion forces. This allows the layers to slide past each other easily, which is why graphite can be used as a lubricant and as the 'lead' in pencils – rubbing off onto paper with ease. The strong covalent bonds within the layers give graphite its high melting point, but the weak interactions between layers contribute to its softness.

Furthermore, graphite's structure enables it to conduct electricity parallel to the planes due to delocalized π (pi) bonds, while diamond does not conduct electricity. Graphite's black color results from the absorption of light by its delocalized electrons, whereas pure diamond is colorless.

Answer: D. all of the above

Explanation:

The speed is important in tennis, so you can win easily, speed is important in soccer to collect the ball quickly and reach the goal, speed is necessary for swimming as the first person wins the game so, option D is correct.

A moving object's rate of change in distance traveled is measured as speed. Speed is a scalar, which implies it is a measurement with a magnitude but no direction.

A thing that moves quickly and with high speed, covering a lot of ground in a short time. On the other hand, a slow-moving object traveling at a low speed covers a comparatively small distance in the same amount of time. An object with zero speed does not move at all.

Speed shortens the time needed to complete a task or travel between two locations. The spare time can then be applied to other tasks. The Earth's orbit around the Sun is maintained by speed.

Thus, speed is important in all the games mentioned here.

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