Answer:
Functional groups are group of atoms which are responsible for the reactivity of compound. In ethylene glycol, organic functional group is OH which is ALCOHOL.
Explanation:
Ethylene glycol, the starting material in the reaction, contains two reactive hydroxyl groups (-OH). These groups enable it to react with terephthalic acid, which has carboxylic acid functional groups, resulting in a polymerization reaction that forms a plastic named polyethylene terephthalate.
Explanation:Ethylene glycol, also known as 1,2-ethanediol, is an organic compound with two hydroxyl groups (-OH). These hydroxyl groups are the reactive functional groups in ethylene glycol, making it a type of alcohol. In the context of the reaction mentioned, ethylene glycol can react with terephthalic acid, another organic molecule with carboxylic acid (-COOH) as the functional group, which will yield a polymer called polyethylene terephthalate (PET).
PET is a type of plastic used commonly for making bottles, films, and fibers for clothing. The formation of plastics by reaction of alcohols (like ethylene glycol) and carboxylic acids (like terephthalic acid) is known as a polymerization reaction. In these reactions, many small monomer units (the alcohol and the acid, in this case) join together to form a large polymer molecule.
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Solutions of sodium acetate and acetic acid are combined in equal volume to produce a buffer. Identify the combination that will produce the buffer with the highest buffer capacity. Select one: a. 0.01 M CH3COOH , 0.1 M CH3COONa b. 0.1 M CH3COOH , 0.1 M CH3COONa c. 0.1 M CH3COOH , 0.01 M CH3COONa d. 0.01 M CH3COOH , 0.01 M CH3COONa
Answer:
Option b=> 0.1 M CH3COOH , 0.1 M CH3COONa.
Explanation:
In chemistry, when an acid or a base(alkali) is added to a solution and the solution pH does not change then we say that the solution is a BUFFER SOLUTION (that is a solution, upon the addition of acid or base will show resistance in pH value).
In order to be able to answer this question efficiently we have to consider the mathematical representation or Equation below;
pH = pKa + log ( [ A^-] / [HA] )--------------------------------------------------------------------(1).
What the mathematical representation or Equation (1) above is telling is is that if [A^-] or [HA] is high then there will be the production of buffer with higher buffer capacity.
What does STP mean? What are the values for an ideal gas? Are the values different for a real gas?
Answer: STP is a standard reference point of temperature and pressure, used when measuring gases. The universal value of STP is 1 atm (pressure) and 0o C. Note that this form specifically stated 0o C degree, not 273 Kelvin, even thought you will have to convert into Kelvin when plugging this value into the Ideal Gas equation or any of the simple gas equations. yes they are deal gases are those which follow ideal gas equation (which is PV=nRT).
Explanation:
Answer =
3) How many moles are there in 454 g of carbon? How many atoms is this?
1 mol =
-
8C
1 mol =
atoms C
Answer=
Answer:
37.83 moles
Explanation:
moles = grams / formula weight = 454 grams / 12g/mol = 37.83 moles
Do the following calculation and express the answer using correct scientific notation. (6.00x10^23)y(3.00)/284)
To calculate the given expression, multiply 6.00x10^23 by 3.00 and divide the result by 284 to get 6.33x10^21.
Explanation:To calculate the given expression and express the answer using scientific notation, we need to perform the following steps:
Multiply 6.00x10^23 by 3.00 to get 1.80x10^24.Divide the result by 284 to get 6.33x10^21.So, the answer is 6.33x10^21.
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Draw three resonance structures for CNO-. This species has its three atoms bonded sequentially in the following fashion: C-N-O. Draw your resonance structures so that the atoms in them are bonded together in this order. Select the most important resonance structure for this species based on the formal charges on the atoms of the three resonance structures you have drawn. Now select the statement from the multiple choices which is true about this most important resonance structure. In the most important resonance structure of CNO- : a) The leftmost bond (between C and N) is a double bond. b) The rightmost bond (between N and O) is a double bond. c) The formal charge on the leftmost (C) atom is -2. d) The number of nonbonding pairs (lone pairs) of electrons on the leftmost (C) atom is 2. e) The number of nonbonding (lone) pairs of electrons on the rightmost (O) atom is 3.
To calculate the charge of each atom.
Formal charge= Valence electrons-(non bonding electron+bonding electron/2)
The possible resonance of CNO- ( check attachment)
The second structure is the most stable because in this structure each atoms carry less formal charge than other.
(a) In the most stable resonance structure of CNO- leftmost bond is a triple bond.
Therefore the statement is False
(b) in the most stable resonance structure of CNO- rightmost bond is single.
Therefore the statement is true
(c) in the most stable resonance
structure of CNO- the formal charge on the leftmost is -1.
Therefore the statement is False
(d) in the most stable resonance structure of CNO-,the number of non bonding electron pairs on the leftmost carbon is 1.
Therefore the statement is False
(e) in the most stable resonance structure of CNO-the number of non bonding electron pairs on rightmost oxygen atom is 3.
Therefore the statement is False
A neutralization reaction between an acid and sodium hydroxide formed water and the salt named sodium sulfate. What was the formula of the acid that was neutralized? A neutralization reaction between an acid and sodium hydroxide formed water and the salt named sodium sulfate. What was the formula of the acid that was neutralized? H2SO4 Na2SO4 H2S HCl none of the above
Answer: The formula of the acid that was neutralized is [tex]H_2SO_4[/tex]
Explanation:
Neutralization is a chemical reaction in which acid and base combine to form salt and water. Acids donate [tex]H^+[/tex] and bases donate [tex]OH^-[/tex] in water which combine to form water molecules.
As the salt formed is [tex]Na_2SO_4[/tex] , the acid must contain [tex]SO_4[/tex] and thus the acid is [tex]H_2SO_4[/tex]
The balanced chemical reaction is ;
[tex]H_2SO_4+2NaOH\rightarrow Na_2SO_4+2H_2O[/tex]
The formula of the acid that was neutralized is [tex]H_2SO_4[/tex]
The formula of the acid that was neutralized is H₂SO₄.
The reaction is between an acid and a base sodium hydroxide.
The reaction between an acid and a base is called a neutralization reaction. The end product of neutralization reaction is salt and water.
An acid are substance which when dissolve in water produces hydrogen ion.
The acid involve in the neutralization reaction with sodium hydroxide to produce sodium sulphate is hydrogen sulphate( H₂SO₄).
The chemical reaction can be represented as follows:
H₂SO₄ + NaOH → Na₂SO₄ + H₂O
The balanced equation will be
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
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What of the following is true if the pH of a solution decreases?
[H+] increases
[OH-] increases
Kw increases
Kw decreases
None
Answer:
[H⁺] increases
Explanation:
What of the following is true if the pH of a solution decreases?
[H⁺] increases. TRUE.The pH and the [H⁺] are related through the following expression.
pH = -log [H⁺]
According to this, there is an inverse relation between the pH and the [H⁺]. When the pH decreases, the [H⁺] increases.
[OH⁻] increases. FALSE.The [H⁺] and the [OH⁻] are inversely related through the following expression.
[H⁺] × [OH⁻] = Kw
As we saw, when the pH decreases, the [H⁺] increases. Then, the [OH⁻] decreases.
Kw increases. FALSE. Kw is constant at a given temperature.Kw decreases. FALSE. Kw is constant at a given temperature.Cardiac muscle causes movement in the .
Answer:
organ
Explanation:
it causes movement in the heart and the heart is an organ
Complete the following sentences. Match the words in the left-hand column with the appropriate blank in the sentences in the right-hand column. View Available Hint(s) ResetHelp 1. A monosaccharide is a(n) glucose if the carbonyl group is on the end of the carbon chain. 2. If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) aldotriose. 3. Any carbohydrate with the carbonyl group on the second carbon is a(n) ketopentose. 4. With the carbonyl group on the end of a six-carbon chain, the carbohydrate would be classified as a(n) aldose. 5. The most common carbohydrate, ketose, has six carbon atoms. 6. Glyceraldehyde is an example of a(n) aldohexose, because it has three carbon atoms.
1. If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n) ketopentose.
2. Any carbohydrate with the carbonyl group on the second carbon is a(n) ketose.
3. The most common carbohydrate, glucose, has six carbon atoms.
4. A monosaccharide is a(n) aldose if the carbonyl group is on the end of the carbon chain.
5. Glyceraldehyde is an example of a(n) triose, because it has three carbon atoms.
6. With the carbonyl group on the end of a six-carbon chain, the carbohydrate would be classified as a(n) aldohexose.
1. The term "ketopentose" refers to a five-carbon carbohydrate with a carbonyl group on the second carbon.
2. A "ketose" is a carbohydrate with a carbonyl group (ketone group) on an internal carbon atom.
3. "Glucose" is a common hexose sugar with six carbon atoms.
4. An "aldose" is a monosaccharide with a carbonyl group at the end of the carbon chain.
5. "Triose" denotes a three-carbon sugar, and glyceraldehyde is an example.
6. An "aldohexose" is a six-carbon sugar with the carbonyl group at the end of the carbon chain.
In summary, Carbohydrates are classified based on carbon atom count and carbonyl group placement. Xylulose is a ketopentose. Glucose is a common hexose. An aldose has the carbonyl group at the chain end, while glyceraldehyde is a triose. An aldohexose has a six-carbon chain with the carbonyl group at the end.
The question probable may be:
Complete the following sentences. Match the words in the left-hand column with the appropriate blank in the sentences in the right-hand column.
aldose, ketose, ketopentose, aldohexose, triose, glucose
1. 1. If a carbohydrate, like xylulose, has five carbon atoms and a carbonyl group on the second carbon, it is called a(n)
2. 2. Any carbohydrate with the carbonyl group on the second carbon is a(n)
3. The most common carbohydrate,_________, has six carbon atoms.
4. A monosaccharide is a(n)______ if the carbonyl group is on the end of the carbon chain.
5. Glyceraldehyde is an example of a(n) _________ , because it has three carbon atoms.
6. With the carbonyl group on the end of a six-carbon chain, the carbohydrate would be classified as a(n)____________.
. Solve: Turn off Show summary. Use the Choose reaction drop down menu to see other
equations, and balance them. Check your answers and then write the balanced equations.
2
6
2
Alt
HCI->
AlCl3 +
Hz
NaCl →
Na +
Cl₂
Na2S +
HCI →
NaCl +
H₂S
CHA +
O₂ →
CO2 +
НО
Practice Balance the following chemical equations. (These equations are not in the Gizmo.) help plz
Balancing chemical equations involves adjusting the coefficients of the reactants and products in order to ensure adherence to the Law of Conservation of Mass. An example of a balanced chemical equation is 2NaOH(aq) + H₂(g) + Cl₂(g) which can also be written in complete ionic form and net ionic form. Always remember to first balance individual atoms, then oxygen, and lastly hydrogen.
Explanation:The subject of your question pertains to balancing chemical equations, which is a key concept in the field of Chemistry. Balancing chemical equations is the process of adjusting the coefficients of reactants and products in a chemical reaction to ensure that the law of conservation of mass is adhered to. This law states that matter cannot be created nor destroyed, meaning every atom we start with, we must end with and in the same quantity.
For example, let's look at the equation 2NaOH(aq) + H₂(g) + Cl₂(g). In its balanced form, this equation would look like this:
An important tip to remember while balancing equations is to first check individual atom balances (aside from O and H), then balance O, and finally, H.
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Which molecular formula is also an empirical formula?
A. PCl3
B. C2H4
C. H2O2
D. C6H12O6
Answer:
The molecular formula [tex]PCl_{3}[/tex] is also an empirical formula.
Explanation:
Empirical formula of a compound represents the simplest positive integer ratio of constituting atoms.
Molecular formula may or may not be equal to empirical formula.
In general, if [tex]A_{x}B_{y}[/tex] is the empirical formula then molecular formula is [tex]A_{nx}B_{ny}[/tex] where n = 1, 2, 3......
Empirical formula Molecular formula
[tex]PCl_{3}[/tex] [tex]PCl_{3}[/tex]
[tex]CH_{2}[/tex] [tex](CH_{2})_{2}[/tex] or [tex]C_{2}H_{4}[/tex]
OH [tex](OH)_{2}[/tex] or [tex]H_{2}O_{2}[/tex]
[tex]CH_{2}O[/tex] [tex](CH_{2}O)_{6}[/tex] or [tex]C_{6}H_{12}O_{6}[/tex]
Hence the molecular formula [tex]PCl_{3}[/tex] is also an empirical formula.
A molecular formula which also represents the empirical formula has its atoms in the simplest whole number ratio. For the given options, PCl3 is an example of this as its phosphorus to chlorine ratio is 1:3.
Explanation:The empirical formula represents the simplest whole number ratio of its atoms while the molecular formula represents the actual number of atoms in a molecule. A molecular formula will also represent the empirical formula if the ratio of its atoms are in their simplest form. Considering the options, we can say that A. PCl3 is also an empirical formula because the ratio of phosphorus to chlorine atoms is in its simplest form, 1:3.
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What are the possible phenotypes of the offspring?
freckles with curly hair
freckles with straight hair
no freckles with curly hair
no freckles with straight hair
SHIRTS
TUNG
W
WORD
CLE
COLE
ROUTE
G
LOBREGA
Savo
WORLD
BAL
What’s the answer
Answer:freckles with straight hair
Explanation:
Answer:
The Answer is B Freckles with Straight Hair
Explanation:
Early Merry Christmas Everyone
Use the observation in the first column to answer the question in the second column. observation question The enthalpy of vaporization of Substance C is bigger than that of Substance D. Which has the higher boiling point? Substance C Substance D Neither, C and D have the same boiling point. It's impossible to know without more information. At 1atm pressure, Substance E boils at 89.°C and Substance F boils at 128.°C. Which has a higher enthalpy of vaporization? Substance E Substance F Neither, E and F have the same enthalpy of vaporization. It's impossible to know without more information. At −3°C, Substance A has a vapor pressure of 147.torr and Substance B has a vapor pressure of 177.torr. Which has a higher boiling point? Substance A Substance B Neither, A and B have the same boiling point. It's impossible to know without more information.
Answer:
See explaination
Explanation:
1. Substance C
With Vapor pressure (VP) of C = 136 torr and VP of D = 186 torr. Since VP (C) < VP (D), this entaills that one needs to supply more energy to get C into the vapor phase. Hence, enthalpy of vaporization of C will be higher.
2. Substance A
B.pt (A) = 109 C
B,pt (B) = 125 C
Having A boils at a lower temperature than B, this automatically will make A to have a higher vapor pressure.
3. Substance E
Since E has a lower enthalpy of vaporization, it can be brought into the vapor phase with lower energy as compared to F. Hence, E will have a higher vapor pressure.
Substance C has a higher boiling point than Substance D, Substance F has a higher boiling point (and thereby a higher enthalpy of vaporization) than Substance E, and Substance A has a higher boiling point than Substance B due to its lower vapor pressure.
Explanation:The boiling point of a substance is directly related to its enthalpy of vaporization. In other words, a substance with a higher enthalpy of vaporization requires more heat to transform from a liquid to a gaseous state, making it have a higher boiling point.
So, based on the given observations:
Substance C has a higher enthalpy of vaporization than Substance D, therefore Substance C has a higher boiling point.Substance E boils at 89°C and Substance F boils at 128°C, therefore Substance F has a higher boiling point and consequently a higher enthalpy of vaporization.Substance A has a lower vapor pressure than Substance B at the same temperature (-3°C). Therefore, Substance A would require more energy to convert to the gaseous phase and so between Substance A and Substance B, Substance A has a higher boiling point.Learn more about Enthalpy of Vaporization here:https://brainly.com/question/32361849
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