The __________________ variable is the variable that the scientist changes in an experiment.

The linear speed of a bicycle wheel with a circumference of 2 meters rotating at 1 revolution per second is 2 meters per second.

The question seeks to find the linear speed of a bicycle wheel given its circumference and rotation rate. The circumference of the bicycle wheel is 2 meters, and it rotates at 1 revolution per second. To calculate the linear speed, we use the relationship that the linear speed (v) is the circumference (C) divided by the period of rotation (T). Since the wheel completes one revolution per second, the period T is 1 second.

Therefore, the linear speed v is given by:

v = C/T

v = 2 meters / 1 second

v = 2 meters per second (m/s).

This calculation shows that if a bicycle wheel with a circumference of 2 meters rotates at 1 revolution per second, its linear speed is 2 m/s.

Final answer:

To make the jump, Neo and Morpheus apply a 'force' to their respective launch points. By Newton's third law, this force results in an equal and opposite reaction force that propels them into the air. The same principle applies to a student jumping from a window, where thrust and mutual gravitational forces come into play.

Explanation:

To make the jump, Neo and Morpheus have pushed against their respective launch points with their legs applying a force to the launch points. When any object wants to jump or launch off the ground, it must exert a force against the ground to propel itself into the air. This concept is described by Newton's third law, which states that for every action, there's an equal and opposite reaction. Therefore, when jumping, our legs push down on the ground, and in response, the ground pushes our bodies upward with an equal force, allowing us to lift off.

This is related to the example of the astronomy student mentioned in the reference material, where the student's and the Earth's mutual forces of gravity result in a change of momentum for both; however, due to Earth's much larger mass, it moves imperceptibly compared to the student. When the student jumps, his acceleration is significantly greater. This can be further explored with the concept of thrust, which is a force that pushes an object forward - in this case, upwards against gravity when the student jumps from the window.

Final answer:

when the velocities of the particles match, their velocity is approximately 49.10 m/s.

Explanation:

For particle 1:

Given x = 9.00t² + 6.00t + 2.00 (in meters and seconds), we can find its velocity by taking the derivative of x with respect to t:

v₁(t) = dx/dt = 18.00t + 6.00

For particle 2:

Given a = -8.00t (in meters per seconds squared and seconds), we can find its velocity by integrating a with respect to t:

v₂(t) = ∫ a dt = -4.00t² + C

Given that at t = 0, v₂(0) = 23.0 m/s, we can solve for C:

v₂(0) = -4.00(0)² + C = C = 23.0

So, v₂(t) = -4.00t² + 23.0

Now, we need to find when their velocities match:

v₁(t) = v₂(t)

18.00t + 6.00 = -4.00t² + 23.0

Now, solve for t:

4.00t² + 18.00t - 17.0 = 0

Using the quadratic formula:

t = (-b ± √(b² - 4ac))/(2a)

Substituting a = 4.00, b = 18.00, and c = -17.0:

t = (-18.00 ± √(324 + 272))/(8.00)

t = (-18.00 ± √596)/(8.00)

t ≈ -1.70 or 2.45

Since time cannot be negative, we discard t = -1.70. Thus, t = 2.45 s.

Now, substitute t = 2.45 s into either v₁(t) or v₂(t) to find the velocity when their velocities match.

Let's use v₁(t):

v₁(2.45) = 18.00(2.45) + 6.00

v₁(2.45) ≈ 49.10 m/s

Final answer:

When the velocities of the particles match, their velocity is 23.0 m/s.

Explanation:

To find the velocity when the velocities of the particles match, we need to set their velocity functions equal to each other. The velocity of particle 1 is obtained by taking the derivative of its position function:

v1(t) = 18.00t + 6.00

The velocity of particle 2 is given to us as 23.0 m/s. So we set:

v1(t) = 18.00t + 6.00 = 23.0

Now, solve the equation for t:

18.00t + 6.00 = 23.0

18.00t = 17.0

t = 17.00/18.00 = 0.94 s

Therefore, when the velocities of the particles match, their velocity is 23.0 m/s.

Light pollution, caused by scattered light from outdoor artificial lighting, not only impacts astronomy but disrupts animal life cycles and contributes to unnecessary energy waste. New forms of light pollution like reflections from commercial satellites are additionally disrupting astronomical photography.

The brightening of the night sky by light scattered from artificial outdoor lighting is referred to as Light Pollution. This essentially is the wasted light that spills into our night sky, hindering the visibility of stars and planets - an issue of significant concern for astronomers. However, Light Pollution also disrupts life cycles of animals we share our urban and suburban environment with and leads to unnecessary operational costs for municipalities due to the excessive usage of fossil fuels.

Moreover, recent developments have indicated a new threat in the form of multiple commercial companies planning and launching numerous satellites into low-Earth orbit. This is being done to provide internet access globally, but these satellites reflect sunlight, which has started to negatively impact astronomical photography.

There are initiatives channels that share comprehensive data on Light Pollution like the International Dark-Sky Association, and citizen science projects such as Globe at Night, aimed at inviting citizens to gauge the light levels in our communities.

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Diffraction or refraction

Answer: C) This is an example of refraction and not diffraction.

Explanation: The reason for the straw to appear bent at the water's surface is because of the process of refraction. Light travels at different speeds in different medium because of the varying densities.

The light travels from air to water and thus the difference in speed results in an apparent shift of the position of part of straw under water and thus the part appears broken.

Reflection is the the return of sound or light energy from the surface without absorbing it.

Diffraction is the phenomenon which occurs when the wave encounters an obstacle.

Bituminous coal has the highest heating value. Option (B) is correct.

The amount of heat produced by the combustion of fuel or another substance in a given unit quantity is known as the heating value. Two categories of heating values exist:

The elemental composition of the fuel burned influences the difference between the higher and lower heating value.

As in the given coke, bituminous coal, wood, lignite, bituminous coal has the greatest amount carbon. Hence, bituminous coal has the highest heating value. Hence, option (B) is correct.

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If the total trip took 2.2 secs, then it must took 1.1 secs to reach max height. 

We can then find the max height by realizing that the bag fell from rest and took 1.1 secs to come back to its launch point, we use formula:

hmax  = 1/2 gt^2 = 1/2 (9.8m/s/s)(1.1s)^2 
hmax =5.93m   (ANSWER)

To get the initial speed, we take that the vertical speed is zero at max height, and use 

vf^2=v0^2+2ad 

vf=final speed =0 
v0=intiial speed 
a=acceleration = -9.8m/s/s 
d=distance traveled =hmax= 5.93m 

0=v0^2+2(-9.8ms/s/)(5.93m) 
v0^2=2x9.8x5.93 
v0=10.8m/s  (ANSWER)

distortion is most likely to occur.

The average mass of an automobile in the United States is about 1.440x10^6 g, which is equivalent to 1440 kg.

The average mass of an automobile in the United States is about 1.440x106 g. To express this mass in kilograms, you can convert from grams to kilograms by dividing the mass by 1000. Therefore, 1.440x106 g is equal to 1440 kg.

The x and y scalar component of the displacement vector is 171.18 m and 55.62 m respectively

This question can be solved using the techneques of finding the x and y component of a vector

Vectors: These are quantity that can be measure both in magnitude and direction. E.g velocity, displement, acceleration, Force etc.

x = Rcos∅................ Equation 1

       x = 180cos18

        x = 180(0.951)

        x = 171.18 m

         y = Rsin∅............... Equation 2

        y = 180sin18

        y = 180(0.309)

       y = 55.62 m.

Hence, the x and y scalar component of the displacement vector is 171.18 m and 55.62 m respectively

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Time and Distance do not involve direction, as they are scalar quantities. Conversely, Velocity and Acceleration indicate both magnitude and direction, making them vector quantities.

In the context of physics, the terms listed have different implications with regards to direction. Specifically, options A (Time) and C (Distance) do not involve a direction.

Time is a scalar quantity, and it doesn't imply any specific direction. Similarly, Distance is a scalar measurement of the interval between two locations without concerning the direction of travel.

In contrast, both Velocity and Acceleration are vector quantities, meaning they have both magnitude and direction. Velocity is the displacement over time, indicating the rate at which an object changes its position, oriented towards the direction of displacement. Acceleration, on the other hand, depicts the rate of change of velocity, also factoring in the direction in which velocity is changing.

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Final answer:

When converting the price of a minivan from dollars to kilodollars and megadollars, it equals 33.2 kilodollars and 0.0332 megadollars respectively.

Explanation:

A minivan selling for $33,200 can be converted into kilodollars and megadollars as follows:

1 kilodollar = 1000 dollars, so in kilodollars, the minivan's price is 33.2 kilodollars.

1 megadollar = 1,000,000 dollars, so in megadollars, the minivan's price is 0.0332 megadollars.

its in july now too and we see a peek of ~WHITE DIAMOND~

When on hot pavement, car tire pressure and volume increase possibly leading to a blowout, hence the correct answer is option c.

When car tires are on hot pavement for too long, the pressure inside will increase and the volume within the tire will increase and possibly result in a blowout. This happens because as the temperature of the pavement increases, so does the temperature of the air inside the tire, causing the pressure to rise. If the pressure gets too high, it can lead to a blowout due to excessive pressure.