the volume of a box is 1344 cubic inches. how many cubic inches are in one cubic foot? what is the volume of the box in cubic feet?

Answers

Answer 1
there are 1728 cubic inches in one cubic foot.
A cubic foot is 12"
12* 12" * 12" = 1728 cu/inches
therefore
1344/1728 =. 78 cu ft

Related Questions

The area of a square garden is 98 meters squared. How long is the diagonal

Answers

Because it is square that means its equal on all sides 98 meters
No se jaja yo también tengo tarea que hacer

Ken watches a marching band. He sees 2 rows of flute players. Six people are in each row. He sees 8 trombone players. How many flute or trombone players does Ken see

Answers

Twelve flute players.

Eight trombone players.

20 total of flute and trombone players.

3x + 5x = 10 Which problem requires the same strategy (combining like terms)?

Answers

3x + 5x = 10 Which problem requires the same strategy (combining like terms)?
3x - 2x = 10


The answer is D. 3x - 2x = 10

What number is 49 less than 78

Answers

If you want to subtract the answer is -29.
The number that is 49 less than 78 is 29.

The equation of a line is y=3x+7. Change the equation so that it is proportional.

Answers

Answer:

y=3x

Step-by-step explanation:

For a line to be proportional it must have the form y=mx where the y-intercept is (0,0) through the origin. To change y=3x+7 to be proportional, write it as y=3x.

Determine the effective rate for $1 for 1 year at 5.9% compounded quarterly.

Answers

keeping in mind that the effective rate, is in effect the APY or Annual Percentage Yield, 

[tex]\bf \qquad \qquad \textit{Annual Yield Formula} \\\\ ~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1 \\\\ \begin{cases} r=rate\to 5.9\%\to \frac{5.9}{100}\to &0.059\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four times} \end{array}\to &4 \end{cases} \\\\\\ \left(1+\frac{0.059}{4}\right)^{4}-1\implies (1.01475)^4-1 \approx 0.0603 \\\\\\ 0.0603\cdot 100\implies \stackrel{\%}{6.03}[/tex]

In order to start a business, a student takes out a simple interest loan for $7000.00 for 6 months at a rate of 8.00 %

Answers

To find The interest owed the formula is
I=prt
I interest owed?
P principle 7000
R interest rate 0.08
T time 6/12
I=7,000×0.08×(6÷12)
I=280

To find the balance at the end of 6 months the formula
A=p+I
A=7,000+280
A=7,280

Hope it helps!

Solve: 5x - 7x + 6 = -2(x - 3).

A)
0


B)
3
4


C)
2


D)
infinitely many solutions

Answers

Answer:

  D)  infinitely many solutions

Step-by-step explanation:

The equation reduces to ...

  -2x +6 = -2x +6

This is true for all possible values of x, so there are infinitely many solutions.

what is the prime factorization for 37

Answers

The answer is 1x37 and there other way to times 37.

The prime factorization of 37 is 37

We have,

The prime factorization of a number involves expressing it as a product of prime numbers.

However, in the case of prime numbers themselves, their prime factorization is simply the number itself.

In this case,

The number 37 is a prime number because it is only divisible by 1 and itself.

Since it has no other factors, its prime factorization is simply 37.

Thus,

The prime factorization of 37 is 37.

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Let f(x,y)=x2 −y2. find the gradient of f at the point (√2,1). sketch the level curve of f through this point, together with the gradient at that point. g

Answers

Answer:

[tex]\displaystyle \nabla f(\sqrt{2}, 1) = 2\sqrt{2} \hat{\i} - 2 \hat{\j}[/tex]

General Formulas and Concepts:
Calculus

Differentiation

DerivativesDerivative Notation

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Multivariable Calculus

Differentiation

Partial DerivativesDerivative Notation

Gradient:                                                                                                               [tex]\displaystyle \nabla f(x, y, z) = \frac{\partial f}{\partial x} \hat{\i} + \frac{\partial f}{\partial y} \hat{\j} + \frac{\partial f}{\partial z} \hat{\text{k}}[/tex]

Gradient Property [Addition/Subtraction]:                                                           [tex]\displaystyle \nabla \big[ f(x) + g(x) \big] = \nabla f(x) + \nabla g(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify.

[tex]\displaystyle f(x, y) = x^2 - y^2[/tex]

[tex]\displaystyle P(\sqrt{2}, 1)[/tex]

Step 2: Find Gradient

[Function] Differentiate [Gradient]:                                                              [tex]\displaystyle \nabla f(x, y) = \frac{\partial f}{\partial x} \bigg[ x^2 - y^2 \bigg] \hat{\i} + \frac{\partial f}{\partial y} \bigg[ x^2 - y^2 \bigg] \hat{\j}[/tex][Gradient] Rewrite [Gradient Property - Addition/Subtraction]:                [tex]\displaystyle \nabla f(x, y) = \bigg[ \frac{\partial f}{\partial x}(x^2) - \frac{\partial f}{\partial x}(y^2) \bigg] \hat{\i} + \bigg[ \frac{\partial f}{\partial y}(x^2) - \frac{\partial f}{\partial y}(y^2) \bigg] \hat{\j}[/tex][Gradient] Differentiate [Derivative Rule - Basic Power Rule]:                  [tex]\displaystyle \nabla f(x, y) = 2x \hat{\i} - 2y \hat{\j}[/tex][Gradient] Substitute in point:                                                                     [tex]\displaystyle \nabla f(\sqrt{2}, 1) = 2\sqrt{2} \hat{\i} - 2(1) \hat{\j}[/tex][Gradient] Simplify:                                                                                       [tex]\displaystyle \nabla f(\sqrt{2}, 1) = 2\sqrt{2} \hat{\i} - 2 \hat{\j}[/tex]

∴ the gradient of the given f(x, y) function is equal to <2√2, -2>.

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Topic: Multivariable Calculus

Unit: Directional Derivatives

Find the distance between points M(6,16) and Z(-1,14) to the nearest tenth.

Answers

[tex]\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) M&({{ 6}}\quad ,&{{ 16}})\quad % (c,d) Z&({{ -1}}\quad ,&{{ 14}}) \end{array}\quad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ MZ=\sqrt{(-1-6)^2+(14-16)^2}\implies MZ=\sqrt{(-7)^2+(-2)^2} \\\\\\ MZ=\sqrt{49+4}\implies MZ=\sqrt{53}\implies MZ\approx 7.3[/tex]

what fraction 2/3 is found between which pair of fraction on the number line?

Answers

one third and three thirds,

The relationship between the number of $4 lunches you buy with a $100 school lunch card and the money remaining on the card

Answers

To set up an equation for this you must know what needs to be on the other side of the equals sign or what the answer is supposed to be. In this case, we know the answer should be the money remaining on the card. Since there is no number value for this, you must pick a variable to represent it. I am going to use variable R. So, since we know that you start with 100 dollars, and lose 4 dollars for each lunch, we can tell that there will be subtraction taking place. We also do not know how many lunches have been bought so we need a variable for that too. I will use variable x. That will leave you with an equation of:
R = 100 - 4x

x= number of lunches bought
R= remaining money on the lunch card

Hope this helps!

Compare methods of solving linear equations and methods of solving linear inequalities. what do they have in common? what is different?

Answers

hi hi hi jijhjhjhhjhjhjhjhh

The mailman delivered a $22 check and 3 - $14 bills today. He also took back 1- $5 bill. What is the total in the mailbox?

Answers

3 Times 14 is 42
42+22 is 64
64-5= 59

1.Find the coordinates of the midpoint of __ given that H (-1,3) and X (7,1).
HX

A.(3,1)
B (0,4)
C(-3,1)
D(-4,0)

2. Find the distance between the points R(0,5) and S(12,3). round the answer to the nearest tenth.

A 10.4
B 16
C 12.2
D 11.8

3. An airplane at T(80,20) needs to fly to both U(20,60) and V(110,85) what is the shortest possible distance for the trip?

A. 165 units
B. 170 units
C. 97 units
D. 169 units

Answers

1. B. 2.C 3.C.    these answers are all correct.

Answer:

1. (3, 2)

2. Option C. 12.2

3. Option A. 165 units

Step-by-step explanation:

1. The midpoint of two coordinates (x₁, x₂) and (y₁, y₂) is calculate by,

[tex](x, y) = (\frac{x_{1} + x_{2}}{2},\frac{y_{1} + y_{2}}{2})[/tex]

⇒[tex](x, y) = (\frac{-1 + 7}{2},\frac{3 + 1}{2})[/tex]

Thus (x, y) = (3, 2)

Hence, none of given options are true.

2. The distance between two coordinates is calculate by,

[tex]Distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2[/tex]

⇒ Distance = 12.16 ≈ 12.2 unit

Hence, option (C) is correct.

3. The distance between T(80, 20) and V(110, 85) is comparatively smaller than T(80, 20) and U(20, 60).

Using the Distance formula,

[tex]Distance=\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2[/tex]

Distance between T(80, 20) and V(110, 85) is 71.59 unit

and Distance between U(20, 60) and V(110, 85) is 93.41 unit

So, Airplane firstly go to point V from point T and then point U.

Total shortest distance = 71.60 + 93.40 = 165 unit.

Hence, option (A) is correct.

If a production line produces 50 mouse traps every 30 minutes over the course of a 10-hour work day with a half hour break for lunch how many mouse traps are made in a day

Answers

950 mouse traps

100 traps/ 1 hr times 9.5 hrs = 950
50 mouse traps every 30 minutes.....double that and u get 100 mouse traps per hr.

10 hrs - half hr break (30 minutes) = 9.5 hrs of work

so if it is 100 mousetraps per hr...and the hrs worked are 9.5 hrs.....then the number of mousetraps produced are : 9.5 * 100 = 950 mouse traps <==

When mary began her trip from san jose to la, she filled her car's tank with gas and reset its trip meter to zero. after traveling 324 miles, she stopped at a gas station to refuel; the gas tank required 17 gallons. mary wants a program that calculates and displays her car's gas mileage at any time during the trip. the gas mileage is the number of miles her car was driven per gallon of gas?

Answers

Yes.  The average  gas mileage for the trip was 324 / 17  =   19.06 miles per gallon
Final answer:

To calculate Mary's car's gas mileage, divide the number of miles driven by the number of gallons of gas used. In this scenario, her car's gas mileage is approximately 19.06 miles per gallon.

Explanation:

To calculate Mary's car's gas mileage, we need to divide the number of miles driven by the number of gallons of gas used. In this scenario, Mary traveled 324 miles and used 17 gallons of gas. Therefore, her car's gas mileage can be calculated as:

Gas mileage = Miles driven / Gallons of gas used

Substituting the values:

Gas mileage = 324 miles / 17 gallons

Simplifying the equation:

Gas mileage = 19.06 miles per gallon (rounded to two decimal places)

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if y varies directly as x and y=6 when x =-7, find y when x is 4

Answers

Final answer:

When x is 4, y is approximately -3.43.

Explanation:

To find y when x is 4, we can use the given information that y varies directly as x. This means that the ratio of y to x remains constant. We can set up a proportion using the initial values of y and x and solve for the unknown value:

6 / -7 = y / 4

By cross-multiplying, we get y = -24 / 7. Therefore, when x is 4, y is approximately -3.43.

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This number represents the number of times the base is used as a factor

Answers

It is the exponent.

The exponent is the number used in a power to represent the number of times the base is used as a power.

For example: 7^2. The number 2 is the exponent and it indicates that the number 7 (which is the base) is used two times as a factor, this is, 7^2 = 7 * 7.

Othe example: 4^6. The exponent 6 indicates that the base 4 is used 6 times as a factor => 4^6 = 4 * 4 * 4 * 4 * 4 * 4.


if tanx=-4/3 and x is in quadrant 2 then cos2x=?
A. 7/25
b. -3/5
c. -7/25
d. 3/5

Answers

Trigonometric Identities are equalities that utilize trigonometry functions and hold true for all variables in the equation. The correct option is C, -7/25.

What are Trigonometric Identities?

Trigonometric Identities are equalities that utilize trigonometry functions and hold true for all variables in the equation. There are several trigonometric identities relating to the side length and angle of a triangle.

Given that the value of tan(x) = -4/3 and x is in quadrant 2.

In order to find the value of cos(2x), we can use the trigonometric identity of cos(2x), therefore, for cos(2x) we can write,

[tex]\cos(2x) = \dfrac{1-\tan^2(x)}{1+\tan^2(x)}[/tex]

Since the value of tan(x) is known, substitute the value in the identity,

[tex]\cos(2x) = \dfrac{1-(-\frac{4}{3})^2}{1+(-\frac{4}{3})^2}\\\\\cos(2x) = \dfrac{1-(\frac{16}{9})}{1+(\frac{16}{9})}\\\\[/tex]

cos(2x) = (-7/9) × (9/25)

Cancelling 9 from the numerator and the denominator,

cos(2x) = -7/25

Hence, if tanx=-4/3 and x are in quadrant 2 then cos2x=-7/25.

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The correct answer is c. [tex]$\cos(2x) = -\frac{7}{25}$[/tex].

First, we find [tex]$\sin(x)$[/tex] and [tex]$\cos(x)$[/tex] using the given value of [tex]$\tan(x)$[/tex]:

[tex]$\tan(x) = \frac{\sin(x)}{\cos(x)} = -\frac{4}{3}$.[/tex]

We can use the Pythagorean identity [tex]$\sin^2(x) + \cos^2(x) = 1$[/tex] to find [tex]$\sin(x)$[/tex] and [tex]$\cos(x)$[/tex]. Let's assume [tex]$\sin(x) = \frac{4}{5}$[/tex] (since [tex]$\tan(x) = -\frac{4}{3}$[/tex], and we are looking for a positive value of [tex]$\sin(x)$[/tex] in quadrant 2). Using the Pythagorean identity:

[tex]$\left(\frac{4}{5}\right)^2 + \cos^2(x) = 1$ \\ $\frac{16}{25} + \cos^2(x) = 1$ \\ $\cos^2(x) = 1 - \frac{16}{25}$ \\ $\cos^2(x) = \frac{25}{25} - \frac{16}{25}$ \\ $\cos^2(x) = \frac{9}{25}$. \\[/tex]

Since [tex]$\cos(x)$[/tex] is negative in quadrant 2, we have [tex]$\cos(x) = -\frac{3}{5}$[/tex].

 Now, we can use the double-angle formula for cosine:

[tex]$\cos(2x) = 2\cos^2(x) - 1$ \\ $\cos(2x) = 2\left(-\frac{3}{5}\right)^2 - 1$ \\ $\cos(2x) = 2\left(\frac{9}{25}\right) - 1$ \\ $\cos(2x) = \frac{18}{25} - 1$ \\ $\cos(2x) = \frac{18}{25} - \frac{25}{25}$ \\ $\cos(2x) = -\frac{7}{25}$.[/tex]

Therefore, the value of [tex]$\cos(2x)$[/tex] = [tex]$ -\frac{7}{25}$[/tex].

Tim bought a pen for $2.25, a pencil for $0.59, a notebook for $6.49, and a highlighter for $1.49. He used a coupon that gave him $5.25 off his entire purchase. How much did he spend in total?

Answers

Add together the prices: $10.82. This is reduced by the value of the coupon: 10.82-5.25=$5.57.

the 4th and 13th terms of an AP are 5 and -1, find the 8th term of an AP

Answers

now, we know the 4th term is 5.... ok... now, what's the common difference?  well, we dunno, but notice, from the 4th to the 13th term, you do have to use it 9 times to hop over to the 13th term, let's say is "d", then

[tex]\bf \begin{array}{llll} term&value\\ ------&------\\ a_4&5\\ a_5&5+d\\ a_6&(5+d)+d\\ a_7&(5+d+d)+d\\ a_8&(5+d+d+d)+d\\ a_9&(5+d+d+d+d)+d\\ a_{10}&(5+d+d+d+d+d)+d\\ a_{11}&(5+d+d+d+d+d+d)+d\\ a_{12}&(5+d+d+d+d+d+d+d)+d\\ a_{13}&(5+d+d+d+d+d+d+d+d)+d\\ &5+9d \end{array}[/tex]

we also know that the 13th term is -1

[tex]\bf \stackrel{a_{13}}{5+9d}=-1\implies 9d=-6\implies d=\cfrac{-6}{9}\implies \boxed{d=-\cfrac{2}{3}}[/tex]

now, recall above what the 8th term is 

[tex]\bf a_8=5+4d\implies a_8=5+4\left(-\frac{2}{3} \right)\implies a_8=5-\cfrac{8}{3}\implies a_8=\cfrac{7}{3}[/tex]

Find the roc of the volume of a cube with respect to the length of its side s

Answers

If the length of one side of a cube is s, then the derivative of the formula for the volume of the cube is

dV/ds = 3s^2.

The roc of the volume of a cube with respect to the length of its side s is 3s².

What is rate of change?

The rate of change of a function is the rate at which the output values change over the input value.

The rate of change of a function is one degree less than the actual function.

The volume of a cube is :

V = s³

The rate of change of volume V with respect to length a will be :

dV/ds = d(s³ )/ds

          = 3s²

This means that, a cubic function will have a quadratic rate of change

Hence, The roc of the volume of a cube with respect to the length of its side s is 3s².

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Kurt and Maria’s high school is having a newspaper drive.The goal is to collect 3,585 pounds of newspapers. So far, 21% of the goal has been reached. Kurt estimated the number of pounds of newspapers collected by finding 10% of 3,600 and then multiplying the result by 2. Maria estimated the number of pounds of newspapers collected by finding mc006-1.jpg of 3,600. Who is right, and why?

Answers

Both Kurt and Maria are right, because 3585 will be rounded up to 3600 durning intermediate calculations and 21% of this amount can be approximated by either finding 10% of 3600 and multiplying the result by 2 or by finding [tex]\frac{1}{5}[/tex] of 3600.
Kurt and Maria were both right

Order the fraction from least to greatest.
2/3, 4/9, 5/6, 7/12

Answers

Ok so the first thing we need to do is find the least common denominator. The LCD is 36.

Now we must make all the denominators 36.
(2/3)=(24/36)
(4/9)=(16/36)
(5/6)=(30/36)
(7/12)=(21/36)

So we have the numbers (24/36),(16/36),(30/36), and (21/36).

Since they all have the same denominator, we can compare all the numerators and order hem from least to greatest.

(16/36)<(21/36)<(24/36)<(30/36)

Now that we have the order, we must simplify the numbers back to their original forms.

(4/9)<(7/12)<(2/3)<(5/6)

And that is your answer
1. 4/9 
2. 7/12
3. 2/3
4. 5/6

Solve the equation using the Zero-Product Property. –8n(10n – 1) = 0

Answers

The answer to your question is n=0 or n=1/10

Answer: The solution is,

[tex]n = 0\text{ or }n = \frac{1}{10}[/tex]

Step-by-step explanation:

Since, Zero product property states that if the product of two numbers or expression is equal to zero then either of the numbers or expressions must be equal to zero.

That is, If a.b = 0 ⇒ a = 0 or b = 0

Here, the given expression is,

[tex]-8n(10n-1)=0[/tex]

[tex]\implies (-8n)(10n-1)=0[/tex]

Thus, by the above property,

[tex]-8n = 0\text{ or }(10n-1)=0[/tex]

[tex]\implies n = \frac{0}{-8}\text{ or }10n= 1[/tex]

[tex]\implies n = 0\text{ or }n = \frac{1}{10}[/tex]

One tablet contains 575 grams of muscle relaxing medication. How many grams are in 3 1/2 tablets

Answers

3.5*575=2,012.5 grams
the answer is 2012.5 grams of medicine 

what is the value of the 7 equal to (7×1/100)

Answers

Hey there (again)

[tex]7 ( \frac{1}{100} )[/tex]

Solve the division/fraction

[tex] \frac{1}{100} = 0.01[/tex]

Problem becomes: [tex]7(0.01) = 0.07[/tex]

[tex]Answer: 0.07[/tex]

Good luck on your assignment and enjoy your day!

~[tex]MeIsKaitlyn:)[/tex]

All of the following expressions represent the sum of n and itself, except _____.

n + n
2n

Answers

n^2 because 2n is the same as n+n, but n^2 is the same as the product of n and n

Answer: [tex]n^{2}[/tex]

Step-by-step explanation:

(n + n) represents the definition of the sum of n and itself.

(2n) means two times n, wich is the same as adding n + n.

[tex]n^{2}[/tex] actually represents the multiplication of n two times: [tex]n*n[/tex]

For example, if n=3:

[tex]n+n=3+3=6[/tex]

[tex]2n=2(3)=6[/tex]

[tex]n^{2}=3^{2} =9[/tex]

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