This is a continuous set of numbers. every real number from the starting value to the ending value is included. it is called an ___.

The sequence alternates between letters and squares of integers. The letters seem to follow a particular positional increment pattern, and the numbers are squares of consecutive positive integers. The missing elements in the sequence are R and 36.

The given sequence is: A, 4, D, H, 16, M, 25, _, _. This sequence appears to have two separate patterns interleaved. One pattern is a sequence of letters and the other is a sequence of numbers. For the letters part, A (1st letter), D (4th letter), H (8th letter), M (13th letter), so the next letters might follow an increasing pattern with the position of the letters in the alphabet. For the numbers, we have 4, 16, 25 which are squares of 2, 4, and 5 respectively. To solve for the next elements in the pattern, we would have to decipher the rule that connects the letters with their positions and the next squares of numbers.

The numbers are squares of consecutive positive integers: 2², 4², 5². The next number is 6² which is 36. Following the pattern in letters, after M (the 13th letter), the next letter should be the letter that is five positions ahead because the interval between the previous letters increased by 3 each time (D is 3 letters after A, H is 4 letters after D, M is 5 letters after H), so the next letter should be R (the 18th letter, which is 5 letters after M).

Therefore, the sequence should continue with R, 36.

The first thing we are going to do for this case is define variables.

We have then:

w: width

l: length

The perimeter is given by:

[tex] 2w + 2l = 520
[/tex]

The area is given by:

[tex] A = w * l
[/tex]

The area as a function of a variable is:

[tex] A (w) = w * (260-w)
[/tex]

Rewriting we have:

[tex] A (w) = -w ^ 2 + 260w
[/tex]

To obtain the maximum area, we derive:

[tex] A '(w) = -2w + 260
[/tex]

We equal zero and clear the value of w:

[tex] -2w + 260 = 0

2w = 260
[/tex]

[tex] w = \frac{260}{2}

w = 130
[/tex]

Then, the length is given by:

[tex] l = 260 - w

l = 260 - 130

l = 130
[/tex]

Finally, the maximum area obtained is:

[tex] A = w * l

A = 130 * 130

A = 16900
[/tex]

Answer:

A retangle that maximizes the enclosed area has a length of 130 yards and a width of 130 yards.

The maxium area is 16900 square yards

To write an improper fraction as a mixed number, divide the denominator into the numerator.

Image is provided.

Therefore, the improper fraction 11/9 can be written as the mixed number 1 and 2/9.

The range of the function h(x) = -8x is all real numbers, as there are no restrictions on the output the function can produce. This is typical of a linear function.

The range of a function refers to the possible outputs it can produce. In the case of the function h(x) = -8x, it is a linear function, and there are no restrictions on the values that x can take, meaning x can be any real number between -∞ and +∞. The output, h(x), therefore, can be any real number, also between -∞ and +∞, given that it will be the result of -8 multiplied by x. Therefore, the range of the function h(x) = -8x is all real numbers from -∞ to +∞.

https://brainly.com/question/29145252

#SPJ12

Answer:

Always double check first but I am pretty sure that it is 6

Answer: The number of air conditioners sold per day in a city and the daily temperature

Step-by-step explanation:

We know that if there is a causal relationship between two variables then one variable is responsible for causing the other variable.

there is no causal relationship between the variables since both are independent variables.

there is no causal relationship between the variables since both are independent variables.

there is no causal relationship between the variables since both are independent variables.

there can be causal relationship between the variables since by increasing  or decreasing temperature the the number of air conditioners sold per day in a city can be increased or decreased respectively.

there is no causal relationship between the variables since both are independent variables.

Answer:

[tex]x=\frac{3}{16}[/tex]

Step-by-step explanation:

Given : Exponential function [tex]9^{8x}=27[/tex]

We have to solve the given exponential equation.

Consider the given exponential function [tex]9^{8x}=27[/tex]

[tex]\mathrm{Convert\:}9^{8x}\mathrm{\:to\:base\:}3[/tex]

[tex]9^{8x}=\left(3^2\right)^{8x}[/tex]

Function becomes,

[tex]\left(3^2\right)^{8x}=27[/tex]

Convert 27 to base 3, we have,

[tex]\left(3^2\right)^{8x}=3^3[/tex]

Apply exponent rule, [tex]\left(a^b\right)^c=a^{bc}[/tex]

We have, [tex]3^{2\cdot \:8x}=3^3[/tex]

[tex]\mathrm{If\:}a^{f\left(x\right)}=a^{g\left(x\right)}\mathrm{,\:then\:}f\left(x\right)=g\left(x\right)[/tex]

We have,

[tex]2\cdot \:8x=3[/tex]

Simplify, we have,

[tex]16x=3[/tex]

Thus, [tex]x=\frac{3}{16}[/tex]

The annual loss of income due to missing one work day every two weeks at $9.29 per hour, working 8 hours per missed day, is $1,932.32.

To calculate the amount of pay being lost each year due to missing one work day every two weeks, we need to consider the weekly work schedule and hourly wage.

The annual loss of income due to missing one day of work every two weeks at an hourly wage of $9.29 is $1,932.32.

To solve the inequality -5r + 6 ≤ -5(r+2), the answer is that this inequality has no solution.

Solve the Inequality:

-5r + 6 ≤ -5(r+2)

Distribute the -5 on the right side: -5r + 6 ≤ -5r - 10

Combine like terms: 6 ≤ -10

Since 6 is not less than or equal to -10, the inequality has no solution.

Answer:

>

Step-by-step explanation:

Given : [tex]55?35[/tex]

To Find: Which of the symbols correctly relates the two numbers below?

Solution:

We are given that [tex]55?35[/tex]

Since we know that 55 is greater than 35 .

So, sign of greater than (>)should replace ?

So, [tex]55>35[/tex]

Hence Option F is correct.

So, [tex]55?35[/tex] = [tex]55>35[/tex]

Option F : >

The addition is:

      [tex]=\dfrac{513}{16}\ in.[/tex] or   [tex]32\frac{1}{16}\ in.[/tex]

We are asked to add the expression :

[tex]21\frac{1}{2}\ in.[/tex] and [tex]10\frac{9}{16}\ in.[/tex]

both the numbers are in mixed fraction .

We will first change both the numbers into simple fraction as follows:

[tex]21\frac{1}{2}=\dfrac{21\times 2+1}{2}\\\\\\21\frac{1}{2}=\dfrac{43}{2}\ in.[/tex]

and

[tex]10\frac{9}{16}=\dfrac{10\times 16+9}{16}\\\\10\frac{9}{16}=\dfrac{169}{16}\ in.[/tex]

Hence, the addition of the two numbers is calculated as follows:

[tex]\dfrac{43}{2}+\dfrac{169}{16}\\\\\\=\dfrac{43\times 8+169}{16}[/tex]

( Since, on taking lcm of 2 and 16)

Hence, we get:

[tex]=\dfrac{513}{16}\ in.[/tex]

which in mixed fraction is:

          [tex]32\frac{1}{16}\ in.[/tex]

Answer:

False.

Step-by-step explanation:

Given,

Chord AB Is 3 inches from the center and chord CD is 5 inches from the center of the same circle,

Since, the distance of a chord is inversely proportional to the length of the chord,

That is, the chord that has the smallest distance from the center is largest.

3 < 5

⇒ The distance of chord AB from center < The distance of Chord CD from center

By the above statement,

⇒ The length of chord AB > The length of chord CD.

Hence, the given statement is FALSE.

Answer:  The required ratio is 3 : 1.

Step-by-step explanation:  Given that Juanita is 15 years old and her brother is 5 years old.

We are to find the ratio of Juanita's age to her brother's age.

Let x and y represents the ages of Juanita and her brother respectively in years.

Then, according to the given information, we have

[tex]x=15,\\\\y=5.[/tex]

Therefore, the ratio of Juanita's age to her brother's age is given by

[tex]x:y\\\\=\dfrac{x}{y}\\\\\\=\dfrac{15}{5}\\\\\\=\dfrac{3}{1}\\\\=3:1.[/tex]

Thus, the required ratio is 3 : 1.