Natural selection is the process of organisms adapting to their environments over time.
Explanation:
Natural selection refers the process to various survival and multiplication of organisms due to environmental properties. For example peacock, pepper moth, etc. These lead to evolutionary changes in which individual with specific traits has higher survival or reproduction than individuals in other populations and passes on these hereditary genetic traits to their offspring.
A process in which organisms are well suited to the surroundings than others generate more offspring. Due to this process, the percentage of organisms that adapt to the environment is increasing with each generation.
Part of the earth that goes around the core and is solid
Answer:
mantle
Explanation:
Answer:
The mantle. Its so hot it basically lava.
Explanation:
Hurricanes, thunderstorms, and blizzards are all meteorological disasters. What does "meteorological" mean?
AOcean-based incorrect answer
BCaused by meteors incorrect answer
CRelated to the weather incorrect answer
DUnpredictable
Meterological means related to the weather.
Option C
Explanation:
Meteorological phenomenon is defined as a process taking place on earth’s surface that is related to weather, its changes and modifications. Meteorology has nothing to do with meteorites. Both land and oceans contribute equally in meteorology.
Changes in atmosphere is basically responsible for the changes in weather. Thunderstorms, blizzards, hurricanes, tornados all are within this disaster. Earthquakes etc are actually not included in this meteorology as there’s nothing related to weather that can trigger an earthquake. So earthquakes are excluded.
The psychologist known for latent learning and cognitive maps is _________. A. Robert Rescorla B. Edward Tolman C. William James D. B. F. Skinner
Answer:
B
Explanation:
B. Edward Tolman
The psychologist known for latent learning and cognitive maps is B. Edward Tolman
Explanation:The psychologist known for latent learning and cognitive maps is Edward Tolman. Tolman's various experiments with rats demonstrated that organisms can learn even if they do not receive immediate reinforcement, suggesting a cognitive aspect to comprehensive learning.
In some specific experiments, hungry rats were placed in a maze with no reward for finding their way through it. As they explored the maze, they developed a cognitive map or a mental picture of the maze layout. This is known as latent learning, which is learning that occurs but is not observable in behavior until there is a reason to demonstrate it.
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Which of the following lines (of latitude or longitude) would be represent by 180
South Pole
Equator
Prime meridian
North Pole
International day lind
Prime meridian (lines of longitude) would be represent by 180 degree
Answer: Option C
Explanation:
The longitudes are vertical lines, and they intersect with latitudes to form grids. Sunlight takes about 4 minutes to pass from one grid to another. So, they are designated either West or East, besides their number in order to identify the location.
East longitudes cover 180 degrees and West ones cover west. So, totally there are 360 degree longitudes, having one standard one, called Prime Meridian. The Prime Meridian stays at the center of the earth, and hence termed as the center longitude and noble of all the verticals.
Final answer:
The 180-degree line of longitude represents the International Date Line, which is significant for timekeeping and not to be confused with the Prime Meridian or lines of latitude such as the Equator. The International Date Line does not strictly follow the 180-degree meridian due to political adjustments.
Explanation:
The line that is represented by 180° in terms of longitude is known as the International Date Line. This meridian is on the opposite side of the Earth from the Prime Meridian (0 degrees longitude) and serves a crucial role in timekeeping and calendar days. It is important not to confuse the International Date Line with lines of latitude such as the Equator, or with other notable longitudes like the Prime Meridian.
Lines of latitude are parallel to the Equator and include notable lines such as the Tropic of Cancer, the Tropic of Capricorn, Arctic Circle, and Antarctic Circle. In contrast, lines of longitude, or meridians, like the Prime Meridian and the International Date Line, span from the North Pole to the South Pole, converging at the poles. Latitude lines measure north-south positions, while longitude lines measure east-west positions on the Earth's surface.
The International Date Line roughly follows the 180-degree line of longitude but has been adjusted for political reasons to aid in keeping the same date within certain countries and islands. Crossing this line results in changes to the calendar date. Going westward across it leads to the day going forward, while traveling eastward causes the day to go backward by one.
Two cars start a race with initial velocity 7ms-1 and 4ms-1 respectively.Their acceleration are 0.4ms-2 and 0.5ms-2 respectively.If the two cars finish the race at the same time,what is the distance of the track?
The distance of the track is 600 m
Explanation:
The two cars move by uniformly accelerated motion, so we the distance they cover after a time t is described by the following suvat equation
[tex]d=ut+\frac{1}{2}at^2[/tex]
where
u is the initial velocity
a is the acceleration
For car 1, we have
[tex]d_1 = u_1 t + \frac{1}{2}a_1 t^2[/tex]
where
[tex]u_1 = 7 m/s[/tex] is the initial velocity of car 1
[tex]a_1 = 0.4 m/s^2[/tex] is the acceleration of car 1
So the equation can be rewritten as
[tex]d_1 = 7t + 0.2t^2[/tex]
For car 2, we have
[tex]d_2 = u_2 t + \frac{1}{2}a_2 t^2[/tex]
where
[tex]u_2 = 4 m/s[/tex] is the initial velocity of car 2
[tex]a_2 = 0.5 m/s^2[/tex] is the acceleration of car 2
So the equation can be rewritten as
[tex]d_2= 5t + 0.25t^2[/tex]
The two cars finish the race at the same time: this means that they cover the same distance in the same time t, so we can write
[tex]d_1 = d_2\\7t + 0.2t^2=5t + 0.25t^2[/tex]
And solving for t, we find
[tex]2t - 0.05t^2= 0\\t(2-0.05t)=0[/tex]
Which gives two solutions:
t = 0 (initial instant)
t = 40 s
Therefore, the distance of the track is
[tex]d_1 = 7t +0.2t^2 = 7\cdot 40+0.2\cdot 40^2=600 m[/tex]
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In your own words, and using scientific vocabulary, answer the following question.
What is a wave?
Definition - Wave:
The wave is a type of vibration (disorder) that moves in space and matter. Wave motions pass energy from one point to other.
Explanation:
A wave is a disorder or change that gradually transfers energy from one point to another in a medium and can take the form of a flexible distortion or change in pressure, electric or magnetic current, electric potentials or temperature.
A medium passing through a wave may experience local vibrations when it passes through a wave, but the particle in the medium does not move with the waves. The disorder can take many forms, from a limited wide pulse to an infinitely long sinusoidal wave.
A weight of 20.0 N hangs motionless from a spring, with a spring constant of 65.0 N/m. How far is the spring stretched from its original length?
0.130 m
0.308 m
0.769 m
3.25 m
Answer:
0.308 m
Explanation:
Force = spring constant * change in length
F = k * Δx
F = 20 N
k = 65 N/m
Δx = ? m
20 = 65 * Δx
20/65 = Δx
Δx = 0.308 m
According to the question,
Spring constant, k = 65 N/mForce, F = 20 NThe force will be:
→ [tex]Force =Spring \ constant\times Change \ in \ length[/tex]
or,
→ [tex]F = k\times \Delta x[/tex]
then,
→ [tex]\Delta x = \frac{F}{k}[/tex]
By putting the values,
[tex]= \frac{20}{65}[/tex]
[tex]= 0.308 \ m[/tex]
Thus the above answer is right.
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a 1 m length of string is wrapped around a solid disk, of mass .25 kg and a radius of .30m, mounted on a frictionless axle. the string is pulled with a tension force of 20 N. what is the angular velocity of the disk after the string is pulled off
Answer:
60 rad/s
Explanation:
∑τ = Iα
Fr = Iα
For a solid disc, I = ½ mr².
Fr = ½ mr² α
α = 2F / (mr)
α = 2 (20 N) / (0.25 kg × 0.30 m)
α = 533.33 rad/s²
The arc length is 1 m, so the angle is:
s = rθ
1 m = 0.30 m θ
θ = 3.33 rad
Use constant acceleration equation to find ω.
ω² = ω₀² + 2αΔθ
ω² = (0 rad/s)² + 2 (533.33 rad/s²) (3.33 rad)
ω = 59.6 rad/s
Rounding to one significant figure, the angular velocity is 60 rad/s.
A kettle heats 1.75 kg of water. The specific latent heat of vaporisation of water is 3.34 x 106 J/kg. How much energy would be needed to boil off the water? Write the answer out in full (i.e. not in standard form).
The amount of energy needed to boil off the water is 5,845,000 J
Explanation:
The amount of thermal energy needed to completely boil a certain amount of a liquid substance already at boiling temperature is given by
[tex]Q=m\lambda_v[/tex]
where
m is the amount of the substance
[tex]\lambda_v[/tex] is the specific latent heat of vaporization of the substance
In this problem, the substance is water, and its mass is
m = 1.75 kg
Its specific latent heat of vaporization is
[tex]\lambda_v = 3.34\cdot 10^6 J/kg[/tex]
Assuming that the water is already at boiling temperature, therefore, the thermal energy needed to boil off the water is
[tex]Q=(1.75)(3.34\cdot 10^6)=5,845,000 J[/tex]
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A 2498 kg car is moving at 17.1 m/s slams on its brakes and slows to 2.6 m/s. What is the magnitude (absolute value) of the impulse the car experiences during this time?
Answer:
J=36221 Kg.m/s
Explanation:
Impulse-Momentum Theorem
These two magnitudes are related in the following way. Suppose an object is moving at a certain speed [tex]v_1[/tex] and changes it to [tex]v_2[/tex]. The impulse is numerically equivalent to the change of linear momentum. Let's recall the momentum is given by
[tex]p=mv[/tex]
The initial and final momentums are, respectively
[tex]p_1=mv_1,\ p_2=mv_2[/tex]
The change of momentum is
[tex]\Delta p=p_2-p_1=m(v_2-v_1)[/tex]
It is numerically equal to the Impulse J
[tex]J=\Delta p[/tex]
[tex]J=m(v_2-v_1)[/tex]
We are given
[tex]m=2498\ kg,\ v_1=17.1\ m/s,\ v_2=2.6\ m/s[/tex]
The impulse the car experiences during that time is
[tex]J=2498(2.6-17.1)=2498(-14.5)[/tex]
J=-36221 Kg.m/s
The magnitude of J is
J=36221 Kg.m/s
bubba approach billie and gives him a swift shove.timid little billie keeps his hands in his pocket during this interaction.subsequently, while bubba places a force upon billie,billie does not place a force upon bubba
Answer:
Bubba like Billie :)
Final answer:
Newton's Third Law of Motion dictates that a force exerted on Billie by Bubba results in an equal and opposite force exerted back on Bubba, regardless of Billie's actions.
Explanation:
The scenario described involves Newton's Third Law of Motion, which states that for every action, there is an equal and opposite reaction. Despite Billie keeping his hands in his pockets, when Bubba pushes Billie, there is a force exerted back on Bubba, even if Billie does not actively push back. This interaction is involuntary and happens naturally due to the laws of physics.
A ball with 100 J of PE is released from a height of 10 m. What will be the KE of the ball at 5
m?
Answer:
The kinetic energy is: 50[J]
Explanation:
The ball is having a potential energy of 100 [J], therefore
PE = [J]
The elevation is 10 [m], and at this point the ball is having only potential energy, the kinetic energy is zero.
[tex]E_{p} =m*g*h\\where:\\g= gravity[m/s^{2} ]\\m = mass [kg]\\m= \frac{E_{p} }{g*h}\\ m= \frac{100}{9.81*10}\\\\m= 1.01[kg]\\\\[/tex]
In the moment when the ball starts to fall, it will lose potential energy and the potential energy will be transforme in kinetic energy.
When the elevation is 5 [m], we have a potential energy of
[tex]P_{e} =m*g*h\\P_{e} =1.01*9.81*5\\\\P_{e} = 50 [J]\\[/tex]
This energy is equal to the kinetic energy, therefore
Ke= 50 [J]
ANSWER 5 AND 8!!!!!;$$4$;$;
Answer:
5 ) The mass, 6) with lubrication and using surfaces that are not rough
Explanation:
5) If two bodies are held regardless of their densities and can be combined by some chemical or physical process, the only physical property to be modified will be the mass of the resulting body.
8)
Friction depends on the contact between two surfaces and when a body has a relative motion with respect to a contact surface. In order to reduce friction the contact surface must be lubricated, also the friction depends on the coefficient of friction between surfaces and the normal force exerted by the surface parallel to the area of contact with the body. Mathematically it can be expressed with the following equation.
[tex]F_{f} = u*N\\where:\\u = friction coefficient\\N = normal force [Newtons]\\F_{f}= friction force [Newtons][/tex]
why do many species that existed 35 million years ago no longer exist
Answer:
There are several reasons for the extinction of species. Some of these can include climate change, natural disasters, environmental destruction, or over-hunting. All of these factors can contribute to the deaths of various animals which ultimately leads to extinction if left unchecked.
Explanation:
How does an atom of sulfur-36 become a sulfide ion with a -2 charge?
O
A. The atom gains 2 protons to have a total of 38.
O
B. The atom loses 2 protons to have a total of 14.
O
O
O
C. The atom gains 2 electrons to have a total of 18
O
D. The atom loses 2 electrons to have a total of 14.
Answer:
C. The atom gains 2 electrons to have a total of 18.
Explanation:
Step by step explanation:
A neutral Sulfur-36 atom has 16 electrons and the 16 protons (as the Sulfur atom is neutral, it should have same number of electrons as that of protons). The number of neutrons in Sulfur-36 is equal to total mass of sulfur (which is 36) minus the number of protons (which is 16), resulting in 20 (36-16=20). If sulfur-36 becomes -2 charged ion, it needs to gain a negatively charged particles (i.e. electrons). An electron has a negative charge of -1. So sulfur-36 atom needs to gain 2 electrons to become -2 charged ion. Therefore the correct answer choice is C.
1. An object with a mass of m is thrown straight up near the surface of the earth. While the object is going up, the net force on it is
A) Zero.
B) Less than mg. C) Equal to mg. D) More than mg.
Answer:
C: equal to mg
Explanation:
in free-fall, gravity is always the net force on an object
The net force on an object that is thrown upward is less than mg (the object's mass times gravity). This is because the force of gravity is working against the motion of the object, making the net upward force less than the downward force of gravity.
Explanation:The question is related to Physics, more specifically the concepts of forces and gravity. When an object is thrown upward, it experiences a downward force due to gravity which is equal to its mass (m) times the acceleration due to gravity (g), written as mg. Nevertheless, there is also an upward force exerted on the object, which is why it can ascend.
In the scenario described in the question, where an object is thrown straight up, the net force on an object while the object is going up is less than mg. This is because the force of gravity (mg) is effectively acting downwards, while a smaller net force is acting upwards, making the net force on the object less than mg during ascent.
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A 2 kg book sits in the same room as a 5 kg vase. If the force of gravity between them is 7.41 x 10^-11 N, how far apart are they
The distance between the two objects is 3.0 m
Explanation:
The magnitude of the gravitational force between two objects is given by the following equation:
[tex]F=G\frac{m_1 m_2}{r^2}[/tex]
where :
[tex]G=6.67\cdot 10^{-11} m^3 kg^{-1}s^{-2}[/tex] is the gravitational constant
[tex]m_1,m_2[/tex] are the masses of the two objects
r is the separation between the objects
In this problem, we have:
[tex]m_1 = 2 kg[/tex] is the mass of the book
[tex]m_2 = 5 kg[/tex] is the mass of the vase
[tex]F=7.41\cdot 10^{-11}N[/tex] is the force between the two objects
Re-arranging the equation and solving for r, we find the distance between the two objects:
[tex]r=\sqr{\frac{Gm_1 m_2}{F}}=\sqrt{\frac{(6.67\cdot 10^{-11})(2)(5)}{7.41\cdot 10^{-11}}}=3.0 m[/tex]
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Answer:
3.00 m
Explanation:
Justin drives his unicycle 7.0 m/s northward. How long will it take him (in seconds) to travel 12 km?
Answer:
The time required is 28.5 [min]
Explanation:
We can find the time using the kinematic equation, but first, we must convert the distance to travel in meters.
x = distance = 12 [km] = 12000 [m]
velocity = 7 [m/s]
T[tex]t = \frac{x}{v} \\t=\frac{12000}{7} \\t=1714 [s] = 28.5 [min][/tex]
There are two planets. Planet 1 is three times the mass of Planet 2. However, a person standing on the surface of Planet 2 experiences a force that is 12 times stronger than on Planet 1. How is this possible? Explain in terms of physics phenomena and terminology.
The radius of planet 1 is [tex]\sqrt{3}[/tex] the radius of planet 2.
Explanation:
The gravitational force experienced by a person standing on the surface planet is given by
[tex]F=\frac{GMm}{R^2}[/tex]
where
G is the gravitational constant
M is the mass of the planet
m is the mass of the person
R is the radius of the planet
In this problem, we know that:
The mass of planet 1 is 3 times the mass of planet 2, so [tex]M_1 = 3 M_2[/tex] (1), where [tex]M_1[/tex] is the mass of the first planet and [tex]M_2[/tex] the mass of the second planetThe force experienced by the person on the two planets is the same, [tex]F_1 = F_2[/tex]Expliciting the two forces, we can write
[tex]F_1 = F_2\\\frac{GM_1 m}{R_1^2}=\frac{GM_2 m}{R_2^2}[/tex]
where [tex]R_1, R_2[/tex] are the radii of the two planets.
Substituting eq.(1) and re-arranging, we find:
[tex]\frac{G(3M_2) m}{R_1^2}=\frac{GM_2 m}{R_2^2}\\R_1^2 = 3R_2^2\\R_1 = \sqrt{3} R_2[/tex]
Which means that the radius of planet 1 is [tex]\sqrt{3}[/tex] the radius of planet 2.
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forces of 3.0 N (west) and 4.0 N (33° S of E) act on an object. What is the net force of the object? Calculate both magnitude and direction
The net force is 2.2 N at 80.9 degrees south of east
Explanation:
In order to find the net force, we have to resolve each force along the x-y direction, and then add the components in each direction.
Taking east as positive x-direction and north as positive y-direction, we have:
- First force:
[tex]F_{1x} = -3.0 N\\F_{1y} = 0[/tex]
- Second force:
[tex]F_{2x} = (4.0)(cos (-33^{\circ})=3.35 N\\F_{2y} = (4.0)(sin (-33^{\circ})=-2.18 N[/tex]
Therefore, the components of the net force are
[tex]F_x = F_{1x}+F_{2x}=-3.0+3.35=+0.35 N\\F_y = F_{1y}+F_{2y}=0+(-2.18)=-2.18 N[/tex]
And so, the magnitude of the net force is
[tex]F=\sqrt{F_x^2+F_y^2}=\sqrt{(0.35)^2+(-2.18)^2}=2.2 N[/tex]
And the direction is
[tex]\theta=tan^{-1}(\frac{F_y}{F_x})=tan^{-1}(\frac{-2.18}{0.35})=-80.9^{\circ}[/tex]
which means 80.9 degrees south of east.
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1. A projectile is launched into the air with an initial speed of vi = 40 m/s at a launch
angle of 20° above the horizontal. The projectile lands on the ground 5.0 seconds
later.
Neglecting air resistance, calculate the projectile's range and draw projectile
path
Answer:
range = x = 188 [m]
Explanation:
First we must find the velocity component on the horizontal axis or x-axis
[tex](v_{x})_{0} = 40*cos(20) \\(v_{x})_{0} = 37.58[m/s]\\[/tex]
Then using the kinematic expression that relates velocity with time, we can find the range of the projectile or the distance x.
[tex]x=(v_{x} )_{0}*t\\ x=37.58*5\\x=188[m][/tex]
How does direct current differ from alternating current?
Answer:
a direct current goes in one direction at all times whereas an alternating current goes back and forth in a circuit
How is force defined?
Answer:
In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity (which includes to begin moving from a state of rest), i.e., to accelerate. Force can also be described intuitively as a push or a pull.
what is the maximum weight a boat can hold if a boat can displace 60.5ml?
a. 60.5 kg
b. 30.25 grams
c. 60.5 grams
d. 30.25 kg
Answer:
a. 60.5 kg
Explanation:
Given data,
The maximum water a boat can displace is, 60.5 ml
According to the principle of buoyancy, the weight of the floating body is equal to the weight of the liquid displaced.
Under standard temperature and pressure, a unit mass of water equals one liter.
If a boat can displace a maximum of 60.5 ml of water, then it can hold a mass of a maximum of 60.5 kg of mass.
If a car goes from 20 miles per hour in 5 seconds, find its acceleration
Answer:
The acceleration of the car, is a = 4 m/s²
Explanation:
Given data,
The final velocity of the car, u = 0
The final velocity of the car, v = 20 miles/h
The time period of travel, t = 5 s
The acceleration of an object is defined as the rate of change of velocity.
From first equation of motion,
a = (v-u)/t
= (20 - 0)/5
= 4 m/s²
Hence, the acceleration of the car, is a = 4 m/s²
Carbon-12
Carbon-13
Carbon-14
Which BEST describes the difference between
carbon-12 and carbon-14?
A. Carbon-12 has one more neutron than carbon-14.
B. Carbon-12 has two less protons than carbon-14.
C. Carbon-14 has one less proton than carbon-12.
D. Carbon has two more neutrons than carbon-12.
Answer:
A.Carbon-13
B.Yes of course
C.No
D.Not sure
Answer:
B. Carbon-12 has two less protons than carbon-14.OAmalOHopeO
The potential energy of a 40-kg cannon ball is 14000 J. How high was the cannon ball to have this much potential energy?
Pe = mgh.
14000 J = (40kg)(10m/s^2)(h)
h = 35 meters
The cannon ball was at a height of 35.71 meters to have the given potential energy.
Explanation:To calculate the height of the cannonball, we can use the formula for gravitational potential energy: PE = mgh, where PE is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height.
Rearranging the formula, we have h = PE / (mg).
Plugging in the given values, we get h = 14000 J / (40 kg * 9.8 m/s^2) = 35.71 m.
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ABO blood group is a classification of blood depending on the presence of 4 different antigens.
A.
True
B.
False
Answer:
A
Explanation:
i feel it is correct
in the sense that it dwpends on the presence of 4different antigens
What determines how the plates interact at their boundaries
Answer:
Tectonic plate interactions are of three different basic types: Divergent boundaries are areas where plates move away from each other, forming either mid-oceanic ridges or rift valleys. These are also known as constructive boundaries. Convergent boundaries are areas where plates move toward each other and collide.
Explanation:
Meaning the answer to your question is depending on what type of tectonic plate interaction is occurring will depend on how the plates interact.
A sailboat accelerates from rest to a speed of 2 m/s east. Discuss direction and relative strength of the forces on the boat
Answer:
The direction of the force is towards the east.
The relative strength of the force acting on the boat is proportional to the acceleration acting on the boat.
Explanation:
Given data,
The initial velocity of the sailboat, u = 0 m/s
The final velocity of the sailboat, v = 2 m/s
Let, the time period of the sailboat to reach 2 m/s is, t = 4 s
The acceleration of the sailboat is given by the formula,
a = (v-u)/t
a = (2 - 0)/ 4
a = 0.5 m/s²
The direction of the force is towards the east.
The relative strength of the force acting on the boat is proportional to the acceleration acting on the boat.