Three students are arguing over who can run the fastest. Student A says that she can run 2/3 mile in six minutes. Student B says that he can run 1/2 mile in four minutes. Student C says that he can run 4/5 mile in eight minutes. What fraction of a mile can Student C run in one minute?

Answer: The required expression is,

$ 40(0.85)

Step-by-step explanation:

Given,

The original cost of the videogame = $ 40,

Discount percentage = 15%,

So, the amount of discount = 15% of 40

= (0.15)40                     ( ∵ 1% = 0.01 )

Hence, the cost of the videogame = original cost - discount

= 40 - (0.15)40

= 40 (1-0.15)

= 40(0.85)

Which is the required expression .

Answer:

the answer is $ 40(0.85)

Final answer:

Corey can make at most 4 batches of cookies with the 10 cups of flour available for cookie making, after reserving 6 cups for other purposes.

Explanation:

To determine how many batches of cookies Corey can make, we need to write and solve an inequality. Corey has 16 cups of flour and needs to save 6 cups for other baking, leaving him with 16 - 6 = 10 cups of flour to use for cookies. Each batch of cookies requires 2.5 cups of flour. Let the number of batches be represented by b. The inequality will then be:

2.5b ≤ 10

To solve for b, we divide both sides of the inequality by 2.5:

b ≤ 10 / 2.5

b ≤ 4

This means Corey can make at most 4 batches of cookies with the flour he has, after setting aside 6 cups for other baking purposes.

If U= -2.8

-6.4-4*-2.8=4.8

So the answer is B.

Hope this helps!

Final answer:

To find the number of old houses when the city has 3 new houses for every 9 old houses, set up a proportion. By cross-multiplying 3/9 = 21/x, we find that there are 63 old houses when there are 21 new houses.

Explanation:

The student asks how many old houses there would be if a city had 3 new houses for every 9 old houses, and there are 21 new houses. This is a problem of proportions that can be solved using a simple cross-multiplication method.

To solve for the number of old houses, set up a proportion with the numbers provided:

3 new houses / 9 old houses = 21 new houses / x old houses

Now, cross-multiply:

3x = 9 × 21

3x = 189

Divide both sides by 3 to find x:

x = 189 / 3

x = 63

So, there are 63 old houses in the city.

11-3x >= -4

subtract 11 from both sides

-3x >= -15

divide both sides by -3

-15 / -3 = 5

 so the answer would be x is less than or equal to 5

The question is asking about the relationship between the cost of crackers in dollars (c) and the number of boxes of crackers (be)

The subject of this question is Mathematics. The question is asking about the relationship between the cost of crackers in dollars (c) and the number of boxes of crackers (be). It seems that c represents the cost in dollars and be represents the number of boxes of crackers. The question is asking you to find out what the cost of 'be' boxes of crackers would be.

The required estimated value of the division of 4020 / 16 is 200.

The rounding of values is superseding a number with an inexact value that has a more ephemeral, more uncomplicated, or more direct representation.

here,
As of the given question,
rounding of the number 4020 is 4000, as the digit 20 in ten place is less than 50.

Rounding of the number 16 is 20

Now,
Division = 4000 / 20 = 200

Thus, the required estimated value of the division of 4020 / 16 is 200.

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Final answer:

To estimate 4020 divided by 16, round 4020 to 4000 and 16 to 20, then divide the rounded numbers to get an estimate of 200.

Explanation:

Estimating 4020/ 16 by Rounding

To estimate 4020/ 16 by first rounding each number so that it has only one non-zero digit, we'll start by rounding 4020 and 16 to their most significant figures. We round 4020 to 4000 since the first non-zero digit is a 4 with three following zeros, making it the most significant figure. Similarly, we round 16 to 20 because the leading digit is a 1 which we can round up to a 2 followed by a zero.

Next, we perform the division with our rounded numbers: 4000/ 20 = 200. This is our estimated result after rounding the original numbers to one non-zero digit and performing simple division.

The estimated division is simpler and can be done without a calculator, which is helpful for quick approximations.

36,000,000 gallons

Given:

The Canadian side of Niagara Falls has a flow rate of 600,000 gallons per second.

Question:

How many gallons of water flow over the falls in 1 minute?

The Process:

We will solve the problem of finding many gallons of water flow over the falls in one minute. This is related to unit conversions.

Let us look carefully.

[tex]\boxed{ \ = \frac{600,000 \ gallons}{1 \ second} \times 60 \ seconds \ }[/tex]

[tex]\boxed{ \ 600,000 \ gallons \times 60 = 36,000,000 \ gallons \ }[/tex]

Thus, the amount of water flowing in a waterfall is [tex]\boxed{\boxed{ \ 36,000,000 \ gallons \ }}[/tex]

Keywords: The Canadian side of Niagara Falls, a flow rate of 600,000 gallons per second, how many gallons of water flow, in 1 minute, unit conversions, the second unit is crossed out

The volume of a cube is given as 64 cubic mm then the side length of the cube is 4 mm.

The volume of a cube can be calculated as the cube of the sides of a given figure.

The volume of a cube =[tex]sides^3[/tex]

We have been given that the volume of a cube is 64 cubic mm. We need to find the side length of the cube.

The volume of a cube =[tex]sides^3[/tex]

                                 64  = [tex]sides^3[/tex]

Now we will take cube-root on both sides of the equation;

∛ 64 = ∛ [tex]sides^3[/tex]

∛ 4^3 = ∛ s^3

4 = s

Therefore, the side length of the cube is 4 mm.

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Answer:

A: y-9 =2(x-1)

Step-by-step explanation:

Answer:

  6x

Step-by-step explanation:

The rule of exponents that applies is ...

  (a^b)(a^c) = a^(b+c)

__

  (2x^3)(3x^-2) = (2)(3)(x^(3-2)) = 6x

_____

It can be confusing when you use x both for a variable and a math operator. There are other ways to indicate multiplication, and there are other letters you can use for a variable.

If your middle x is actually intended to be a variable, then the result is 6x².

Final answer:

To find the two integers, we looked for factors of 12 and tested them to find a pair that summed to -7. We discovered that -3 and -4 are the two integers that meet both the sum and product conditions.

Explanation:

To find two integers whose sum is -7 and whose product is 12, we need to find two numbers that add up to -7 and multiply to give 12.

Let's denote the two numbers we are looking for as x and y. We have two equations:

x + y = -7 (Equation 1)

xy = 12 (Equation 2)

We can use various methods to solve these equations, such as factors of 12, trial and error, or a systematic approach like substitution or elimination, but in this case, factoring is the easiest. We look for two numbers that multiply to 12 (1x12, 2x6, 3x4) and also add up to a sum of -7. We can see that the pair of numbers that satisfies both conditions is -3 and -4, because (-3)+(-4) = -7, and (-3)x(-4) = 12.

Thus, the two integers are -3 and -4.